find the value of n:
[tex]\frac{10}{n} = \frac{15}{6}[/tex]

Answers

Answer 1
Answer value of n=4

Step-by-step explanation:

Greetings !

Given expression

[tex] \frac{10}{n} = \frac{15}{6} [/tex]

cross multiply

apply fraction cross multiply

[tex]if \: \: \frac{a}{b} = \frac{c}{d} \: \: then \: \: a.d = b.c[/tex]

10.6=n.15

simplify:

10.6=60

Thus, 60=n.15

switch sides

[tex]n.15 = 60[/tex]

divide both sides by 15

[tex] \frac{n.15}{15} = \frac{60}{15} [/tex]

simplify

[tex]n = 4[/tex]

Hope it helps!


Related Questions

The price of a jacket is $500 and the price of a pair of jeans is $250.

(a) The price if the jacket is ____% if the pair of jeans.
(b) The price of the pair of jeans is ___% or the price of the jacket.

Answers

Answer:(a) 50% (b)5%

Step-by-step explanation:

For a, it's not really difficult  because the price of a jacket is 1/2 more than jeans. So it's 50%.

For b, it's similar to no. (a) because the price of the jean is 1/2 less than a jacket. So u need to divide 250 by 500 and u will get 0.5 so if u want to put in % u need to multiply with 10, so u will get 5%.

To calculate the height of a tower Mary measures the angle of elevation from a point A, to be
10. She then walks 100m directly towards the tower, and finds the angle of elevation from the
new point B to be 20°. What is the height of the tower to the nearest tenth of a metre?

Answers

If Mary measures the angle of elevation from a point A, to be 10°. She then walks 100m directly towards the tower, and finds the angle of elevation from the new point B to be 20°, the height of the tower comes out to be 37 meters.

Given Information and Formula Used:

The angle of elevation of the tower from point A (a in figure) = 10°

The angle of elevation of the tower from point B (b in figure) = 20°

The distance AB (ab n figure) = 100m

In right triangle adc, tan 10° = cd / ad ....... (1)

In right triangle bdc, tan 20° = cd / bd ......... (2)

Here, cd is the height of the tower.

Let the distance bd be x, then the ad = x + 100

Substituting this value of of ad in equation (1), we get,

tan 10° = cd / (x+100)

x+100 = cd / tan 10°

x+100 = cd / 0.18

x+100 = 5.6 cd ....... (3)

From equation (2),

tan 20° = cd / x

x = cd / tan 20°

x = cd / 0.34

x = 2.9 cd

Putting this value of x in equation (3), we obtain the height cd (or CD) as,

2.9 cd + 100 = 5.6 cd

(5.6 - 2.9)cd = 100

2.7cd = 100

cd = 100/2.7

cd ≈ 37m (To the nearest tenth of a meter)

Therefore, the height of the tower is calculated to be 37 meters.

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Which point lies on the line described by the equation below? y+4=4(x-3

Answers

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies \begin{array}{llll} y+4=4(x-3)\implies y-(\stackrel{y_1}{-4})=\stackrel{m}{4}(x-\stackrel{x_1}{3})\\\\ ~\hfill (\stackrel{x_1}{3}~~,~~\stackrel{y_1}{-4}) \end{array}[/tex]

Geometry: complete this proof (ASAP!!!!! It’s urgent)

Answers

Answer:

1. Given.

2. Alternate Interior Angles Theorem.

3. m<2 + m<7 = 180 by definition of supplementary angles. By definition of congruent angles, m<2 = m<4 and m<5 = m<7, therefore m<4 + m<5 = 180 by substitution property of equality. By definition of supplementary angles, <4 is supplementary to <5.

4. Converse of Consecutive Angles Theorem.

Match each quadratic equation with its solution set. 2x2 − 32 = 0 4x2 − 100 = 0 x2 − 55 = 9 x2 − 140 = -19 2x2 − 18 = 0

Answers

Correct match for the quadratic equation are:

A. {-4, 4}

B.  {-5, 5}

C.  {-8, 8}

D.  {-11, 11}

E.  {3,-3}

What is a quadratic equation ?

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

According to the given Information:First equation:

2x² - 32 = 0

Adding thirty-two to both sides of the equation:

2x² = 32

Dividing between two on both sides of the equation:

x² = 322

x² = 16

Applying square root to eliminate the exponent:

x =  ±√16

x =  ±4

Second equation:

4x² - 100 = 0

Adding hundred to both sides of the equation:

4x² = 100

Dividing between four on both sides of the equation:

x² = 100/4

x² = 25

Applying square root to eliminate the exponent:

x = ±√25

x = ±5

Third equation:

x² - 55 = 9

Adding fifty-five to both sides of the equation:

x² = 9 + 55

x² = 64

Applying square root to eliminate the exponent:

x = ±√64

x =  ±8

Fourth equation:

x² - 140 = -19

Adding one- fourty to both sides of the equation:

x² = -19 + 140

x² = 121

Applying square root to eliminate the exponent:

x = ±√121

x = ±11

Fifth equation:

2x² - 18 = 0

Adding eighteen to both sides of the equation:

2x² = 18

Dividing between two on both sides of the equation:

x² = 182

x² = 9

Applying square root to eliminate the exponent:

x = ±√9

x = ±3

Correct match for the quadratic equation are: A. {-4, 4},B.  {-5, 5},

C. {-8, 8},D.  {-11, 11},E.  {3,-3}

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I understand that the question you are looking for is:

Match each quadratic equation with its solution set.

A. 2x2 - 32 = 0  {-8, 8}

B. 4x2 - 100 = 0  {-4, 4}

C. x2 - 55 = 9          {-5, 5}

D. x2 - 140 = -19         {-11, 11}

E. 2x2 - 18 = 0  {3,-3}

A pygmy hippo and a regular hippo were recently born. The pygmy hippo had a mass of 5 1/2 kg at birth. The regular hippo had a mass of 24 1/2 kg at birth. Complete the comparison. At birth, the regular hippo massed ? times as much as the pygmy hippo.

Answers

The mass of the regular hippo at birth to that of the pygmy hippo is 49/11

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

The pygmy hippo had a mass of 5 1/2 kg at birth = 5.5 kg.

The regular hippo had a mass of 24 1/2 kg at birth = 24.5 kg

Hence:

Ratio of regular hippo to pygmy hippo = 24.5 / 5.5 = 49/11

The mass of the regular hippo at birth to that of the pygmy hippo is 49/11

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Answer:

49/11 or 4 5/11

Step-by-step explanation:

just did it on khan Academy.

A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet saturn. you could determine a 100–pound earthling's weight on saturn using the proportion: a. startfraction 15 over 4 endfraction = startfraction b over 100 endfraction c. startfraction 4 over 15 endfraction = startfraction 100 over b endfraction b. startfraction 15 over 4 endfraction = 100 over b endfraction d. either a or c

Answers

100–pound earthling's weight on Saturn using the proportion is (B)

15/4 = 100/x.

What is proportion?The size, number, or quantity of one object or group of things in comparison to another thing or group of things In our class, the ratio of guys to girls is two to one (2:1).

To find the 100–pound earthling's weight on Saturn using the proportion:

Weight of ball on Earth = 15 poundsWeight of ball on Saturn= 4 poundsLet 100 pounds of earthling weight on Saturn be x pounds.Thus, the proportion is 15:4 = 100:x15/4 = 100/x

Therefore, 100–a pound earthling's weight on Saturn using the proportion is (B) 15/4 = 100/x.

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The correct question is given below:
A bowling ball weighs 15 pounds on earth and weighs 4 pounds on the planet Saturn. you could determine a 100–pound earthling's weight on Saturn using the proportion:

a. start fraction 15 over 4 end fraction = start fraction x over 100 end fraction

b. startfraction 15 over 4 endfraction = 100 over x endfraction

c. startfraction 4 over 15 endfraction = startfraction 100 over x endfraction

d. either a or c

What are the domain and range of g of x equals the square root of the quantity x plus 4?

Answers

It is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

What are the domain and range of a function?The domain of a function is the set of values that can be plugged into it. This set contains the x values in a function like f(x). A function's range is the set of values that the function can take. This is the set of values that the function returns after we enter an x value.

To find the domain and range:

The given function in the problem is: [tex]g(x)=\sqrt{x+4}[/tex]Because the square root function does not exist for negative numbers, the domain is denoted by: [tex]x+4[/tex] ≥ [tex]0[/tex] → [tex]x[/tex] ≥ [tex]-4[/tex]Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).The range of the square root function is [tex]x[/tex] ≥ [tex]0[/tex], which remains the same as there are no vertical translations.

Therefore, it is discovered using its notion that the domain and range of the function are given by (C) D: [–4, ∞) and R: [0, ∞).

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The complete question is given below:

What are the domain and range of g of x equals the square root of the quantity x plus 4?

(A) D: [4, ∞) and R: [0, ∞)

(B) D: (–4, ∞) and R: (–∞, 0)

(C) D: [–4, ∞) and R: [0, ∞)

(D) D: (4, ∞) and R: (–∞, 0)

Find the value of x. Degrees in an arc!! pls help i need this to study for my test!! pls show work thank you so much :)

Answers

Considering the angle of the arc, it is found that the value of x is of x = 12º.

What is the angle of the arc?

It is twice the inside angle.

In this problem, the angle of the arc is of 102º, hence the inside angle is of 51º, which means that we can solve for x as follows:

4x + 3 = 51

4x = 48

x = 12º.

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Can someone help me with these two problems and show work please !!

Answers

work is attached to this post

Answer:

13. Two real solutions.

14. No real solutions.

Step-by-step explanation:

Given quadratic equations:

13. [tex]x^2+7x+10=0[/tex]

14. [tex]4x^2-3x+4=0[/tex]

[tex]{\large \textsf{Quadratic Formula: }} x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \Bigg{\|}\ \textsf{when }ax^2+bx+c=0[/tex]

What is the discriminant?

The discriminant (Δ) is b² - 4ac, which is under the square root in the quadratic formula. It is used to determine the number of real solutions (roots) of a quadratic:

When b² - 4ac > 0, the quadratic has two real solutions.When b² - 4ac = 0, the quadratic has one real solution.When b² - 4ac < 0, the quadratic has no real (complex) solutions.

13. x² + 7x + 10 = 0

[tex]\implies a=\textsf{1},b=\textsf{7},c=\textsf{10}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta=(7)^2 - 4(1)(10)[/tex]

[tex]\implies \Delta=49 - 40[/tex]

[tex]\implies \Delta=9[/tex]

As [tex]9[/tex] > 0, this quadratic has two real solutions.

14. 4x² - 3x + 4 = 0

[tex]\implies a=\textsf{4},b=\textsf{-3},c=\textsf{4}[/tex]

Find the discriminant value.

[tex]\implies \Delta = b^2 - 4ac[/tex]

[tex]\implies \Delta = (-3)^2 - 4(4)(4)[/tex]

[tex]\implies \Delta = 9 - 64[/tex]

[tex]\implies \Delta = -55[/tex]

As [tex]-55[/tex] < 0, this quadratic has no real solutions.

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In the expression (ax+b)*(cx^2+dx+e), find two set of values of a,b,c,d and e so that the coefficient of x^3and x terms after expansion are 4and 10 respectively.

Answers

Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

A gardener has 520 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it does not need any fencing.

garden bordered by a river

What dimensions would guarantee that the garden has the greatest possible area?

shorter side: _____ft (feet)

longer side: ____ft (feet)

greatest possible area: ___ft2 (square-feet)

Answers

The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

What dimensions would guarantee that the garden has the greatest possible area?

The given parameter is

Perimeter, P = 520 feet

Represent the shorter side with x and the longer side with y

One side of the garden is bordered by a river:

So the perimeter is:

P = 2x + y

Substitute P = 520

2x + y = 520

Make y the subject

y = 520 - 2x

The area is

A = xy

Substitute y = 520 - 2x in A = xy

A = x(520 - 2x)

Expand

A = 520x - 2x^2

Differentiate

A' = 520 - 4x

Set to 0

520 - 4x = 0

Rewrite as:

4x= 520

Divide by 4

x= 130

Substitute x= 130 in y = 520 - 2x

y = 520 - 2 *130

Evaluate

y = 260

The area is then calculated as:

A = xy

This gives

A = 130 * 260

Evaluate

A = 33800

Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

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The geometry of the hybrid orbitals about a central atom with sp3d hybridization is:________

Answers

For sp3d hybridized central atoms, the only possible molecular geometry is trigonal bipyramidal.

Hybridisation (or hybridization) is a process of mathematically combining two or more atomic orbitals from the same atom to form an entirely new orbital different from its components and hence being called as a hybrid orbital.

In this case, if all the bonds are in place, the shape is also trigonal bipyramidal.

In chemistry, a trigonal bipyramid formation is a molecular geometry with one atom at the center and 5 more atoms at the corners of a triangular bipyramid.

Bond angle(s): 90°, 120°

Coordination number: 5

Point group: D3h

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Assume that thermometer readings are normally distributed with a mean of 0 C and a standard deviation of 1.00 C. A thermometer is randomly selected and tested. For the case​ below, draw a​ sketch, and find the probability of the reading.​ (The given values are in Celsius​ degrees.)

Between 1.50 and 2.25

1. Choose the correct graph
2.the probability of getting a reading between 1.50 and 2.25

Answers

The probability of getting a reading between 1.50 and 2.25 is; 0.00546

How to find the probability from z-score?

We are given the following information in the question:

Mean; μ = 0 °C

Standard Deviation; σ = 1 °C

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula for z-score is;

z = (x' - μ)/σ

P(Between 1.50 degrees and 2.25 degrees) is expressed as;

P(1.5 ≤ x ≤ 2.25)

= P((1.5 - 0)/1 ≤ z ≤ (2.25 - 0)/1))

= P(z ≤ 2.25) -  P(z < 1.5)

= 0.0546 = 5.46%

The graph that correctly describes this is the first graph

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PLEASE HELP IM STUCK

Answers

Answer:

y=1

Step-by-step explanation:

Since you already found x,

We will only be needing one equation to find y..

I will take equation two: 3(2)+2y=8

Step Two: 6+2y=8 (then you minus 6 on each side)

Step Three: 2y=2 (divide)

y=1

math related pls help

Answers

Answer:

  (a)  (f +g)(x) = √(x-2) +√(x)

Step-by-step explanation:

The sum of two functions is the sum of their definitions.

Application

  (f +g)(x) = f(x) +g(x)

  (f +g)(x) = √(x -2) +√(x)

Note: the radicals can only be combined if they can be reduced to a form that has the same expression under the radical. Here, that is not the case, so there is no way to simplify the sum.

Force equals mass times acceleration.
F = ma
Solve the equation for the
acceleration, a.
-A

Answers

Answer:

m = F / a is the answer

Step-by-step explanation:

F = ma

m = F / a

Factor the polynomial completely
10³ -25r² - 12r + 30

Answers

ANSWER
(5r^2 - 6)(2r - 5)

EXPLANATION
Factor by grouping
(10r^3 - 25r^2) + (-12r + 30)

Factor a GCF
5r^2 (2r - 5) -6 (2r - 5)

Combine groups
(5r^2 - 6)(2r - 5)

CHECK
Use FOIL

First: 5r^2*2r = 10r^3
Outside: 5r^2*-5 = -25r^2
Inside: -6*2r = -12r
Last: -6*-5 = 30

The area of triangle ABC is 4√2 m².

Work out the value of x.
Give your answer correct
to 3 significant figures.
Note: Please make sure your final line says x =

Answers

Answer:

x=1.08 (3SF)

Step-by-step explanation:

hope it helps!!!!

Aakash has a fever. His body temperature during the day was 99.2°F. By evening, his body temperature has increased by 3.4°F.
His body temperature in the evening is
°F.

Answers

His body temperature in the evening is 102.6 °F

How to determine his body temperature?

The given parameters are:

Temperature in the morning = 99.2°F.

Temperature increase = 3.4°F.

His body temperature in the evening is calculated as:

New = Temperature in the morning + Temperature increase

So, we have

New = 99.2°F +  3.4°F

Evaluate the sum

New = 102.6 °F

Hence, his body temperature in the evening is 102.6 °F

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A data set contains three points, and two of the residuals are 7 and -3. What 7
is the third residual?

Answers

The data set in discuss which contains three points and two of the residuals are 7 and -3 would have its third residual as; -4.

What is the third residual if the data set characterized as having 2 of its three residuals to be; 7 and -3?

According.tinthe task content, the data set in discuss has three points and consequently should have three residuals.

Additionally, two of the three residuals have been given and on this note, it follows that the third residual must have a value such that the algebraic sum of all residuals is 0.

Hence, we have; -3 + 7 +x = 0;

x = 3-7 = 4.

Ultimately, the third residual is; -4.

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The real solutions to the quadratic -x² - 2x+5=0 are:
2± √√29
2
-1±-√6
No real solutions.
None of the choices are correct.

Answers

Answer:

No real solutions.

Step-by-step explanation:

To solve this, we need to use Quadratic Formula.

Quadratic Formula:

[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ [/tex]

in the form of:

[tex]a {x}^{2} + bx + c[/tex]

Given information from the question, we can deduce:

a = -1

b = -2

c = 5

Let's substitute these values into the formula.

[tex]x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4( - 1)( -5)} }{2( - 1)} \\ = no \: real \: solutions[/tex]

if you punch these into the calculator.

using point Q as the center of dilation.

Point Q is the center of dilation. Line segment A B is dilated to create line segment A prime B prime. The length of Q A is 1.25 and the length of A A prime is 1.25.

What is the scale factor?

1
1.25
2
2.5

Answers

Answer:

  (c)  2

Step-by-step explanation:

The dilation scale factor multiplies the distance from the center of dilation.

Distance from Q

We are given that QA = 1.25, and that AA' = 1.25. By the segment sum theorem, we have ...

  QA' = QA +AA'

  QA' = 1.25 +1.25 = 2.50

Scale factor

The scale factor multiplies the original distance:

  QA' = k·QA . . . . . . . . . . where k is the dilation scale factor

  2.50 = k·1.25 . . . . . . . . using the known lengths

  2.50/1.25 = k = 2 . . . . divide by the coefficient of k

The scale factor is 2.

If a card is drawn from a deck, find the probability of getting these results:
a. a 6 and a spade
b. a black king
c. a red card and a 7
d. a diamond or a heart
e. a black card

Answers

Answer:

Below in bold,

Step-by-step explanation:

a. There's is only one card that fits this description so

Probability = 1/52.

b. There are 2 black Kings so

Probability = 2/52 = 1/26.

c. There are 2 of these - 7 of diamonds and 7 of hearts

so

Probability = 2/52 = 1/26.

d.  There 13 diamonds and 13 hearts so

Probability = 26/52 = 1/2.

e.  There  26 black cards

Probability = 26/52 = 1/2.

S=1 - 1/4 + 1/6 - 1/9 + 1/11 - 1/14..........infinity. Find the sum of series.

Answers

[tex]1+\frac{1}{6}+\frac{1}{11}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-4} \\ \\ \frac{1}{4}+\frac{1}{9}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-1} \\ \\ S=\sum^{\infty}_{n=1} \left(\frac{1}{5n-4} -\frac{1}{5n-1} \right) \\ \\ =\frac{\pi}{5} \sqrt{\frac{1}{5} (5+2\sqrt{5})}[/tex]

The daily high temperature of Elk Creek drops by 1.2°C every day. What is the net change in the daily high temperature after two calendar weeks?

Answers

Answer:

Step-by-step explanation:

Answer: 16.8°C

The model of a trinomial is shown.

An algebra tile configuration. 0 tiles are in the Factor 1 spot and 0 tiles are in the Factor 2 spot. 24 tiles are in the Product spot: 1 is labeled + x squared, 7 are labeled negative x, the 2 tiles below + x squared are labeled + x, and the 14 tiles below the negative x tiles are labeled negative.
What are the factors of the trinomial? Select two options.

x – 14
x + 7
x – 7
x – 2
x + 2

Answers

The factors of the trinomial are:

x – 7x + 2

Options C and E

This is further explained below.

What is trinomial?

Generally, A trinomial is a kind of polynomial that is used in basic mathematics. It is composed of three components, also known as monomials.

In conclusion, The following expressions are the components of the trinomial: x - 7, x + 2

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The table represents an exponential function. what is the multiplicative rate of change of the function? a. 1/5 b. 2/5 c. 2 d. 5

Answers

Answer: a) 1/5




.......

1. 3k − 8 = 7
2. 8b + 9 = −15
3. 8 = 3x − 13
4. 6p + 22 = 4
5. 84 = 51 + 11c

Answers

===> Exercise 13k − 8 = 7

Add 8 to both sides.

3k = 7 + 8

Add 7 and 8 to get 15.

3k = 15

Divide both sides by 3.

k = 15 / 3

Divide 15 by 3 to get 5.

k=5 ===> Answer

===> Exercise 28b + 9 = −15

Subtract 9 from both sides.

8b= −15 − 9

Subtract 9 from −15 to get −24.

8b = −24

Divide both sides by 8.

b = -24 / 3

Divide −24 entre 8 para obtener −3.

b=−3 ===> Answer

===> Exercise 38 = 3x − 13

Swap the sides so that all the terms of the variables are on the left side.

3x −13 = 8

Add 13 to both sides.

3x = 8 + 13

Add 8 and 13 to get 21.

3x = 21

Divide both sides by 3.

x = 21 / 3

Divide 21 by 3 to get 7.

x = 7 ===> Answer

===> Exercise 46p + 22 = 4

Subtract 22 from both sides.

6p = 4 − 22

Subtract 22 from 4 to get −18.

6p = −18

Divide both sides by 6.

p = -18 / 6

Divide −18 entre 6 para obtener −3.

p = −3 ===> Answer

===> Excercise 584 = 51 + 11c

Swap the sides so that all the terms of the variables are on the left side.

51 + 11c = 84

Subtract 51 from both sides.

11c = 84 − 51

Subtract 51 from 84 to get 33.

11c = 33

Divide both sides by 11.

c = 33 / 11

Divide 33 by 11 to get 3.

c = 3 ===> Answer

Solution 1 :-

>> 3k - 8 = 7

>> 3k = 7 + 8

>> 3k = 15

>> k = 15 / 3

>> k = 5

Solution 2 :-

>> 8b + 9 = -15

>> 8b = -15 - 9

>> 8b = -24

>> b = -24 / 8

>> b = -3

Solution 3 :-

>> 8 = 3x - 13

>> 3x = 13 + 8

>> 3x = 21

>> x = 21 / 3

>> x = 7

Solution 4 :-

>> 6p + 22 = 4

>> 6p = 4 - 22

>> 6p = -18

>> p = -18 / 6

>> p = -3

Solution 5 :-

>> 84 = 51 + 11c

>> 11c = 84 - 51

>> 11c = 33

>> c = 33 / 11

>> c = 3

For a sample of n = 36 that has a sample variance of 1,296, what is the estimated standard error for the sample? 6 37 36 6. 9

Answers

The estimated standard error for the sample is 6

Given,

Sample size, n = 36

Sample variance, [tex]s^{2}[/tex] = 1296

Standard deviation, s = √1296

                                   = 36

Standard error, SE = [tex]\frac{s}{\sqrt{n} }[/tex]

                              = [tex]\frac{36}{\sqrt{36} }[/tex]

                              = [tex]\frac{36}{6}[/tex]

                              = 6

Concept

Sample size is the number of participants or observations included in a study. It is denoted by ‘n’Sample variance is a measure of the degree to which the numbers in a list are spread out. It is denoted by '[tex]s^{2}[/tex]'Standard deviation is a measure of how dispersed the data is in relation to the mean. It is denoted by ‘s’

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