Find the missing segment in the image below.

Answer: x-6, x+3, x-3

Step-by-step explanation;

Split the equation into two.

x2(x-6)-9(x-6)

(x-6) is seen as one of the tiles. Now work on x2-9

x2-9 is a difference of squares meaning the last two are (x+3) and (x-3).

The inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

Linear inequalities are inequalities that involves at least one linear algebraic expression, that is, a polynomial of degree 1.Linear inequalities are the expressions where any two values are compared by the inequality symbols such as, '<', '>', '≤' or '≥'. These values could be numerical or algebraic or a combination of both.

Hence, the inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

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Answer:

C

Step-by-step explanation:

answer is C

Step-by-step explanation:

for TEXAS using permutation formula

we have:5!/1!1!1!1!1!=5!=120

for MEXICO using permutation formula

we have:6!/1!1!1!1!1!1!=6!=720

Answer: Line D

Step-by-step explanation:

The points in the scatterplot are closest to line D.

Rotating 90 degrees counterclockwise: [tex](x,y) \longrightarrow (-y,x)[/tex]

[tex]A(-4,4) \longrightarrow A'(-4, -4)\\\\B(-3, 4) \longrightarrow B'(-4, -3)\\\\C(-3, 1) \longrightarrow C'(-1, -3)\\\\D(-4, 1) \longrightarrow D'(-1, -4)[/tex]

Translate along [tex]\langle 3, 4 \rangle[/tex]: [tex](x,y) \longrightarrow (x+3, y+4)[/tex]

[tex]A'(-4, -4) \longrightarrow A''(-1, 0)\\\\B'(-4, -3) \longrightarrow B''(-1, 1)\\\\C'(-1, -3) \longrightarrow C''(2, 1)\\\\D'(-1, -4) \longrightarrow D''(2, 0)[/tex]

Using the arrangements formula, it is found that there are 20,160 different groups of players of 2 players that the coach can make.

The number of possible arrangements of n elements is given by the factorial of n, that is:

[tex]A_n = n![/tex]

In this problem, all 8 players will play, hence considering the order, the number of ways is:

[tex]A_8 = 8! = 40320[/tex]

However, the position does not matter, as for example, João and Elisa would form the same pair as Elisa and João, hence the removing the order, the number of groups is:

40,320/2 = 20,160.

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Answer:

The answer is 28!!!

Step-by-step explanation:

Use the combinations formula:

[tex]C = \frac{n!}{r!(n-r)!}[/tex]

n = 8

r = 2

[tex]C = \frac{8!}{2!~*~6! } = 28\\[/tex]

I got it right! Look at the pic for proof.

Hope this helps!! :)

The mean of the sample from number of patients treated at Dr. Frank's dentist office each day for ten days is 8.2

Given data:

13, 9, 7, 8, 2, 4, 22, 12, 5, 0.

Mean of the sample = Total number of patients treated / number of days

= (13 + 9 + 7 + 8 + 2 + 4 + 22 + 12 + 5 + 0) / 10

= 82/10

= 8.2

Therefore, the mean of the sample is 8.2

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Answer:

12.5< × < 18.9

Step-by-step explanation:

because you would use the pythagoras theorem which a² + b² = c² in this case c is the third side the unknown so to work this out do square root of ( 10² + 16²) which is 100 + 256 = 356 and the square root of 356 is 18.86 which rounds to 18.9 so the second answer is correct :)

i hope this helps pls ask if you need any more help :)

Answer:

There is no answer

Step-by-step explanation:

82 can not equal $14.00, however if you mean 82x=14.00, the answer will be 0.17 (7/41), and if you mean 82=14x, the answer will be 5.86 (41/7)

Answer:

.06

Step-by-step explanation:

add all the 4 values listed, plus the .06

divide by 5

you get -.01

:)

Answer:

52º, 128º

Step-by-step explanation:

8. Because ∠6 is an opposite angle to ∠5, ∠6=∠5=52º;

9. Because line a//line b, ∠6=∠4=52º, so ∠7=180º–52º=128º

Hello and Good Morning/Afternoon

Let's take this problem step-by-step:

What does this problem give us:

What does this problem want us to find:

Let's solve:

           ⇒ by the vertical angle theorem is equal in measure to ∠5

               ⇒ ∠6 = 52°

           ⇒ lines a and b are parallel

               ⇒ the corresponding angles on both lines formed by the

                    transversal are equal

                         i.e. m∠2 = m∠3, m∠7 = m∠8

           ⇒ ∠8 is on a straight line with ∠6

                      [tex]\hookrightarrow angle8 +angle6 = 180\\\hookrightarrow angle8 + 52 = 180\\\hookrightarrow angle8 =128[/tex]

           ⇒ since m∠8 is equal to m∠7

              ⇒ m∠7 = 128

Definitions

Answer:

Hope that helps!

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The equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

The expression is given as:

21√(3)(15) - 9√(3)(15)

Express 15 as 3 * 5

21√(3)(15) - 9√(3)(15) = 21√(3)(3 * 5) - 9√(3)(3 * 5)

Evaluate the product of 3 and 3

21√(3)(15) - 9√(3)(15) = 21√(9 * 5) - 9√(9 * 5)

Take the square root of 9

21√(3)(15) - 9√(3)(15) = 21*3√(5) - 9*3√5)

Evaluate the product

21√(3)(15) - 9√(3)(15) = 63√(5) - 27√5)

Evaluate the difference

21√(3)(15) - 9√(3)(15) = 36√5

Hence, the equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

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Using the combination formula, it is found that he can make 4 different stacks.

The order in which the balls are selected is not important, as stated in the problem. hence the combination formula is used to solve this question. If the order was important, then the permutation formula would be used.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, he has four flavors, and will choose three of them for the stacks, hence the number of different stacks is given as follows:

[tex]C_{4,3} = \frac{4!}{3!1!} = 4[/tex]

He can make 4 different stacks.

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[tex](\stackrel{x_1}{-10}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{-9}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-9}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-10)}}} \implies \cfrac{-9 +7}{-5 +10} \implies \cfrac{ -2 }{ 5 }\implies -\cfrac{2}{5}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{(-10)}) \\\\\\ y+7=-\cfrac{2}{5}(x+10)\implies y+7=-\cfrac{2}{5}x-4\implies y=-\cfrac{2}{5}x-11[/tex]

60 ÷ 30 = 2

and

90 ÷ 30 = 3

---> 60/90 = 2/3

❄ Hi there,

the way 60/90 becomes 2/3 is this:

[tex]\sf{\dfrac{60\div30}{90\div30}=\dfrac{2}{3}}[/tex]

That's it!

❄

The number of people who must be included in the survey, that is, the sample size should be 340.

We assume the sample size to be n.

The confidence interval required is 99%.

The Z-score corresponding to the 99% confidence interval is (Z) 2.58.

The true proportion (p) of the sample is not given, so we assume it to be 50% or 0.5.

The margin of error for the sample (E) is given to be 7% or 0.07.

By the formula of margin of error, we know that:

E = Z√[{p(1 - p)}/n].

Putting in the values, we have, we get:

0.07 = 2.58√[{0.5*0.5}/n],

or, (0.07/2.58)² = 0.25/n,

or, n = 0.25/{(0.07/2.58)²} = 339.6122449 ≈ 340.

Thus, the number of people who must be included in the survey, that is, the sample size should be 340.

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She walks 540 yards for 3 full laps around the park per day.

From the information given;

The longest part of the triangular park = 75 yards

The shortest part = 45 yards

Let's find the other part, using Pythagorean theorem;

a² = b² + c²

75² = 45² + c²

c² = 75² - 45²

Find the squares

c² = 5625 - 2025

c² = 3600

Make 'c' the subject

c = √3600

c = 60 yards

If she walks

75 + 60 + 45 yards per lap

180 yards per lap

For three laps, she walks

= 3 × 180

= 540 yards

Thus, she walks 540 yards for 3 full laps around the park per day.

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Answer: [tex]x=-5, -3[/tex]

Step-by-step explanation:

[tex]x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3[/tex]

The perimeter of quadrilateral ABCD will be 26 units.

It should be noted that we want to measure the length of each side of ABC, and use those lengths to calculate the perimeter of ABC.

This will be 10, 5, 5, and 6. Therefore the perimeter will be the addition. This will be:

= 10 + 5 + 5 + 6

= 26 units.

This also was identical to the result gotten. This is attached below.

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The cost of new product on the website is $309.375.

Given that, the cost of product = $412.50 and discount percentage = 25%.

A discount is the reduction of either the monetary amount or a percentage of the normal selling price of a product or service.

Discount = 25% of 412.50

= 25/100 × 412.50

= 0.25 × 412.50

= 103.125

So, cost = 412.50-103.125

= $309.375

Therefore, the cost of new product on the website is $309.375.

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What this has to signify would be the fact that there is a the spread of a stimulus through the ventricles.

This is used to refer to the term that has to do with the combination of the different types of waves. These are the Q wave, the R wave as well as the S wave. This is used in ECG measurement. It has to do with the measurement of the chambers of a person heart to check its normal function.

When the ECG are in this category, it can be regarded as a high. This may put a person to have the more likelihood of having a death that is caused by coronary diseases.

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Condition (A) P(B/A) = y is true.

To find the true condition:

If two events are independent, then:

Use formulas for conditional probabilities:

For independent events these formulas will be:

Now in your case, Pr(A) = x and Pr(B) = y.

Therefore, condition (A) P(B/A) = y is true.

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The complete question is given below:

The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditions must be true?

a. P(B|A) = y

b. P(A|B) = y

c. P(B|A) = x

d. P(A and B) = x + y

e. P(A and B) = x/y

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

We have to evaluate [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex]

By using partial fractions, evaluate the integral

Let [tex]\frac{1}{s^{2}(s-1)^{2} } =\frac{A}{s} +\frac{B}{s^{2}} +\frac{c}{s-1} +\frac{D}{(s-1)^{2} }[/tex]

[tex]1=As(s-1)^{2} +B(s-1)^{2} +Cs^{2}(s-1)+Ds^{2}[/tex]

Put s = 0, 1 = B.1 ⇒ B = 1

Put s= 1, 1 = D ⇒ D = 1

Put s = -1, [tex]1=A(-1)(-2)^{2} +B(-2)^{2} +C(-1)^{2} (-2)+D(-1)^{2}[/tex]

1 = -4A + 4B -2C + D

1 = -4A + 4 -2C + 1

-4 = -4A -2C

2 = 2A + C----------------(1)

Put s = 2, 1 = A(2) + B +C(4) +D(4)

1 = 2A + 1 + 4C +4

-4 = 2A + 4C

-2 = A + 2C---------------(2)

From(1),

C = 2 -2A ---------------(3)

From (2),

⇒ -2 = A + 4 -4A

⇒ -6 = -3A ⇒ A = 2

From (3)

C = 2 - 2(2)

⇒ C = -2

Thus [tex]\int \frac{ds}{s^{2}(s-1)^{2} }= \int (\frac{2}{s} +\frac{1}{s^{2} }- \frac{2}{s-1} +\frac{1}{(s-1)^{2} } )ds[/tex]

= [tex]2 ln|s|-\frac{1}{s} -2ln|s-1|-\frac{1}{s-1}+c[/tex]

= [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex]

Thus,

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

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Answer:

B

Step-by-step explanation:

- 6x + 3 ≥ 21 ( subtract 3 from both sides )

- 6x ≥ 18

divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.

x ≤ - 3

Answer:

a

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (4, - 1 ) and (x₂, y₂ ) = (- 2, 3 )

m = [tex]\frac{3-(-1)}{-2-4}[/tex] = [tex]\frac{3+1}{-6}[/tex] = [tex]\frac{4}{-6}[/tex] = - [tex]\frac{2}{3}[/tex] , then

y = - [tex]\frac{2}{3}[/tex] x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 2, 3 ) , then

3 = [tex]\frac{4}{3}[/tex] + c ⇒ c = 3 - [tex]\frac{4}{3}[/tex] = [tex]\frac{5}{3}[/tex]

y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{5}{3}[/tex] ← in slope- intercept form

multiply through by 3 to clear the fractions

3y = - 2x + 5 ( subtract - 2x + 5 from both sides )

2x + 3y - 5 = 0 ← in general form

Considering the situation described, the classification of the elections is given as follows:

We take the situation that is described, and build the classification from it. The classification has the following format:

P1 - P2 - P3 - P4 - P5

With P1 being the first placed candidate, P2 being the second placed candidate, and so on until P5 which is the fifth placed candidate.

From the text given in this problem, we have that:

Hence the places of each candidate are given as follows:

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Answer: [tex]\Large\boxed{First~Choice.~-28}[/tex]

Step-by-step explanation:

Given function expression

f(x) = -5x² - x + 20

Requirement of the question

Find the value of f(3)

Substitute the values into the function

f(x) = -5x² - x + 20

f(3) = -5(3)² - (3) + 20

Simplify the exponents

f(3) = -5(9) - 3 + 20

Simplify by multiplication

f(3) = -45 - 3 + 20

Simplify by subtraction and addition

f(3) = -48 + 20

[tex]\Large\boxed{f(3)=-28}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

What is an algebraic expression?

An expression that is made up of variables and constants, along with algebraic operations like addition, subtraction, etc.

What is the substitution method?

The substitution method is generally used to solve the system of equations. In this method, first, solve the equation for one variable, and substitute the value of the variable in the other equation

5th question :

⇒ x(2y-x)²+2x²(x-2y)

let (x-2y) = A

⇒we can also write (2y-x)² as (x-2y)² as both have the same value

x(x-2y)²+2x²(x-2y)

x(A)²+2x²(A)

By taking xA common

⇒ xA(A+2x)

On putting the value of A=(x-2y)

⇒ x(x-2y) (x-2y+2x)

⇒x(x-2y) (3x-2y)

6th question :

2(x-y)-(y-x)²

let (x-y) = B

⇒we can also write (y-x)² as (x-y)² as both have the same value

2(x-y)-(x-y)²

2B-(B)²

By taking B common

⇒ B(2-B)

On putting the value of B=(x-y)

⇒(x-y) (2-{x-y})

⇒(x-y) (2-x+y)

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