Find the indicated maximum or minimum value of f subject to the given constraint. maximum: f(x,y,z)=x2y2z2; x2 y2 z2=4

Using a linear function, the total charge from parking in the lot for 72 hours is of:

b. $146.

A linear function is modeled by:

y = mx + b

In which:

Both the basic fee, which is the y-intercept, and the hourly fee, which is the slope, are of $2, hence the cost of parking x hours is given by:

C(x) = 2x + 2

Hence the cost for parking 72 hours is:

C(72) = 2 x 72 + 2 = 2 x 73 = $146.

Which means that option b is correct.

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Work Shown:

m = (y2 - y1)/(x2 - x1)

-4/3 = (a - (-3))/(-3 - 3)

-4/3 = (a+3)/(-6)

-4*(-6) = 3(a+3)

24 = 3a+9

3a+9 = 24

3a = 24-9

3a = 15

a = 15/3

a = 5

The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.

According to the statement

we have to explain about the function in which cryptography takes a string of any length as input and returns a string of any requested variable length.

So, For this purpose,

we know that the

A sponge function or sponge construction is any of a class of algorithms with finite internal state that take an input bit stream of any length and produce an output bit stream of any desired length.

So from definition and its working process it is clear that for this purpose the sponge function is used.

this function returns the string of any variable length.

So, The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.

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Answer:

C

Step-by-step explanation:

[tex]-15x+60\leq 105 \\ \\ -15x \leq 45 \\ \\ x \geq -3[/tex]

[tex]14x+11 \leq -31 \\ \\ 14x \leq -42 \\ \\ x \leq -3[/tex]

The intersection is x = 3.

Answer:

a) horizontal compression with a factor of 0.5 and a horizontal reflection over the y-axis.

b) Pick one the two correct answers:

translation of 2 units right

translation of 2 units down

Step-by-step explanation:

If function f(x) is transformed into f(ax) then it is stretched or compressed horizontally.

If |a| > 1 it is compressed horizontally.

If 0 < |a| < 1, it is stretched horizontally.

If a is negative, then it is reflected over the y-axis.

a) Compare y = -2x with y = x.

The change is in that x became -2x.

Here, a = -2.

Since |-2| = 2, and 2 > 1, it has a compression of a factor of 2 horizontally.

Also, since -2 is a negative number, it is reflected over the y-axis.

Answer: horizontal compression with a factor of 0.5 and a horizontal reflection over the y-axis.

If function f(x) is transformed into f(x) + b then it is translated vertically b units. If b > 0, the translation is b units up. If b < 0, the translation is b units down.

b) y = x - 2

This can be thought of the function f(x) becoming f(x) - 2.

It is a translation of 2 units down.

Interestingly, in this case, this can also be thought of x being replaced by x - 2 which is a translation of 2 units to the right.

Answer:

There are two correct answers (use only one of the two below):

translation of 2 units right

translation of 2 units down

the volume of the hexagonal prism is 184. 75 cm^3

It is important to note that the volume of a hexagonal prism is given as;

V = (2/√3) × ap2 × h

Where

From the information given, we have the values of the following parameters;

height = 10cm

apothem = 4cm

base edge = 6cm

Now, let's  substitute the value of the parameters

Volume = (2/√3) × ap^2 × h

Volume = 2/√3 × 4^2 × 10

Multiply through

Volume = 1. 1547 × 16 × 10

Volume = 184. 75 cm^3

Thus, the volume of the hexagonal prism is 184. 75 cm^3

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Answer:

p.

Step-by-step explanation:

p is the independent variable.

The dependent one is h.

The value of h depends on the value of p.

Answer:

x = 30° and y = 52°

Step-by-step explanation:

angles on the circle subtended by the same arc are congruent

x and 30° are on the same arc, then x = 30°

y and 52° are on the same arc, then y = 52°

The total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We know the volume of the cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

The surface area of the

= surface area of half sphere + surface area of the cylinder - surface area

  of one circular base

The radius r = (64-50)/2 = 7 cm

= (1/2)[4π(7)²] + 2π(7)(50) + 2π(7)² - π(7)²

= (1/2)[615.75] + 2506.99 - 153.94

= 307.875 + 2506.99 - 153.94

= 2660.925 square cm

Thus, the total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.

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The minimum value of data is 24,lower quartile is 29,median is 41, upper quartile is 50 and maximum value is 56 and the interquartile range is 21.

Given a data about ages of 13 history teacher as under:

24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56.

We are required to find the minimum value, lower quartile,median,upper quartile,maximum value, interquartile range.

The minmum value is 24.

Lower quartile=(n+1)/4 th term

=(13+1)/4

=7/2

=3.5

Lower quartile=(29+29)/2

=29

Median=(n/2)th term

=13/2 th term

=6.5 th term

Median=(39+43)/2

=82/2

=41

Upper quartile=3(n+1)/4   th term

=3(13+1)/4

=3*14/4

=10.5 th term

Upper quartile=(49+51)/2=100/2=50

Inter quartile range=Upper quartile- lower quartile

=50-29

=21

Hence the minimum value of data is 24,lower quartile is 29,median is 41, upper quartile is 50 and maximum value is 56 and the interquartile range is 21.

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The terms of this series may be arranged without changing the value of the series. The sum of the reciprocals of the squares of the odd positive integers is [tex]\pi ^{2} /8[/tex].

In mathematics, a sequence is the cumulative sum of a given collection of terms. Usually, those phrases are actual or complicated numbers, but plenty of extra generalities are feasible.

A series is described as an arrangement of numbers in a specific order. then again, a chain is described as the sum of the factors of a sequence.

In mathematics, a series is, more or less speaking, a description of the operation of including infinitely many quantities, one after the alternative, to a given beginning quantity. The look at of series is a primary part of calculus and its generalization, mathematical analysis.

k=1

1/(1)2+1/(2)2+1/(3)2+1/(4)2+1/(5)2+1/(6)2+1/(7)2+.

up to ∞ terms = 2/6

[1/(1)2+1/(3)2+1/(5)2+1/(7)2+]+[1/(2)²+1/(4)²+1/(6)²+

..∞0] = T²/6

→ [1/(1)² + 1/(3)² + 1/(5)2+1/(7)2+......00] + [1/4 (1)² + 1/4(2)²+

1/4(3)²+....0] =²/6

[1/(1)²+1/(3)²+1/(5)2+1/(7)2+.......)] + 1/4[1/(1)² + 1/(2)²+

1/(3)²+....x] = 2/6

⇒ [1/(1)² + 1/(3)² + 1/(5)²+1/(7)²+..] + 1/4 [π²/6] = 2/6

⇒ [1/(1)² + 1/(3)² + 1/(5)²+1/(7)²+] = (1-1/4)/6

⇒ [1/(1)²+1/(3)2+1/(5)2+1/(7)2+..∞ = 3/4 x π²/6

=

↑

[1/(1)2+1/(3)2+1/(5)2+1/(7)²+] = 2/8

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Answer:

distance = 10

2/7 /(22) = 10

Answer: [tex]\Large\boxed{B.~\displaystyle 75~m^3}[/tex]

Step-by-step explanation:

Given information

Height = 2 m

Base = 5 m

Length = 15 m

Given the formula for Triangular Prism Volume

[tex]V~=~\displaystyle \frac{1}{2}\times ~b~\times~h~\times~l[/tex]

[tex]\to V=Volume\\\to b=base\\\to h = height\\\to l = length[/tex]

Substitute values into the formula

[tex]V~=~\displaystyle \frac{1}{2}\times ~(5)~\times~(2)~\times~(15)[/tex]

Simplify by multiplication

[tex]V~=~\displaystyle \frac{5}{2}~\times ~30[/tex]

[tex]\Large\boxed{V~=~\displaystyle 75~m^3}[/tex]

Hope this helps!! :)

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The distance the bird has flown by the time Alice and Bob meet is 40 feet.

Given that the distance between Alice and Bob is 1000 feet and their running speed is 10 feet per second and the speed of bird is 20 feet per second.

Distance equals speed multiplied by time.

Distance between Alice and Bob=1000 feet.

Distance between the bird and Bob=1000 feet.

Speed of Alice and Bob=10 feet per second.

The combined speed of Alice and Bob=20 feet per second.

Since the two are running directly toward each other the distance each will cover at the meeting point is 50 feet (1000/20)

The time covered at the meeting point=20 second (1000/50)

Speed of the bird=20 feet per second.

The distance covered by the bird towards Bob at their meeting point is 40 feet(20 feet*20 seconds).

Hence the distance the bird has flown by the time Alice and Bob meet is 40 feet.

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The "given series" should be for [tex]\cos(x)[/tex], not [tex]x[/tex], so that

[tex]\cos(x) = 1 - \dfrac{x^2}2 + \dfrac{x^4}{24} - \dfrac{x^6}{720} + \cdots[/tex]

In the limit (which should say [tex]x\to\infty[/tex], not [tex]n[/tex]), we have

[tex]\displaystyle \lim_{x\to\infty} \frac{\frac{x^2}{1+\cos(x)}}{x^4} = \lim_{x\to\infty} \frac{1}{x^2\left(2 - \frac{x^2}2 + \frac{x^4}{24} - \cdots\right)} = \boxed{0}[/tex]

3 ways of computing the sum on the number line are:

Here we have the sum:

8 + (-3) + (-2)

The first way of doing the sum in a number line is starting on the first number, which is 8.

Now, we also can think the sum as:

(-3) + 8 + (-2)

So now we can start at the value -3, then move 8 units to the right, and then 2 units to the left.

Or think the sum as:

(-2) + (-3) + 8

So we start at -2, then we move 3 units to the left, and finally 8 units to the right.

So the different ways of computing the sum on a number line depends on where we start.

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Answer:

answer is 3 ft

Step-by-step explanation:

area of circle= 3*(1)^2

The SEC routinely require public companies to include their review reports in their 10-Q filings because it is said to be made up of fewer details and the financial statements inclusive that are known to be unaudited.

Form 10-Q is known to be a type of a report  that is often needed by the Securities and Exchange Commission (SEC)  and it is one that all public company need to file on quarterly basis.

Note also that The SEC is known to have made and need the form in accord to the pursuant of  the Securities Exchange Act of 1934  and this form helps them to keep investors well  informed about the state of their financial health and all that is taking place at  the companies they have invest in or will choose to invest in.

Hence,  Form 10-Q is asked for because it is often used to make comparison of a company’s previous financial quarter to that of its current financial quarter.

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Answer:

x =  -1,  7,  3 + i,  3 - i.

Step-by-step explanation:

(x^2-6x+9)^2-15(x^2-6x+10)=1

(x^2 - 6x + 9)^2  - 15(x^2 - 6x + 9) - 15*1 = 1

(x^2 - 6x + 9)^2  - 15(x^2 - 6x + 9) - 16 = 0

Let Z = x^2 - 6x + 9, then we have:

Z^2 - 15Z - 16 = 0

(Z - 16)(Z + 1) = 0

Z = 16 or Z = -1

so  x^2 - 6x + 9 = -1 or x^2 - 6x + 9 = 16

x^2 - 6x + 9 = -1

---> x^2 - 6x + 10 = 0

Using the Quadratic Formula:

---> x = [6 +/- √((-6)^2 - 4* 1* 10) / 2

---> x = 6/2 +/- √-4/2

---> x = 3 + i , 3 - i.

x^2 - 6x + 9 = 16

---> x^2 - 6x - 7 = 0

---> (x - 7)(x + 1) = 0

---> x = 7, -1.

The initial-value is  x(t)=F0/2w^2 (sin wt-wt cos wt)

An initial-value hassle is a differential equation wherein is an open set of, together with a point within the domain called the initial situation. A technique to an initial cost hassle is a function that is a technique to the differential equation and satisfies.

Inside the discipline of differential equations, preliminary cost trouble (additionally called Cauchy trouble by using a few authors) is a normal differential equation collectively with a detailed fee, called the preliminary situation, of the unknown function at a given factor in the domain of the solution.

In multivariable calculus, an initial-value hassle is a normal differential equation collectively with a preliminary circumstance that specifies the fee of the unknown characteristic at a given factor in the area. Modeling a system in physics or different sciences often amounts to fixing an initial cost problem.

Consider a differential equation x+x=F, sin wt, x(0) = 0,X(0) = 0

Apply Laplace transformation on both sides, and we get

(s²L{x(t)}-sy(0)-y'(0)) + w²L {x(t)} =·

Fow

Fow

(s² + w² ) { x(t)} = 3 + w²

L{x(t)}=

Fow

(5²+w²)²

x(t)=FwL

[(s² + w²)²]

Fow

x(t)=(sin wt-wt coswt)

2w

x(t)=

Fo

wtcos

2w (sin wt-wt cos wt),

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The speed of the wind is 50 miles per hour.

The term speed is defined as the ratio of the distance to the time taken. Now we can see that the movement of the plane and the wind were once in the same direction and then in opposite direction. This could be used to obtain a pair of simultaneous equations that could be used to solve the problem.

Hence;

300 = (250+s)* t = 250t + st ----- (1)

200 = (250-s)* t = 250t   - st  ------- (2)

Adding equations (1) and (2)

500 = 500t

t = 1 hour

To obtain the speed of the wind;

300 =250t + st

300 = 250(1) + (s * 1)

300 = 250 + s

300 - 250 = s

s = 50 miles per hour

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Missing parts;

A plane has a cruising speed of 250 miles per hour when there is no wind. At this speed, the plane flew 300 miles with the wind in the same amount of time it flew 200 miles against the wind. Find the speed of the wind.

Answer:2x+y=8

3x-2y=5

Step-by-step explanation:multiply 1 st equation by 2

4x+2y=16

3x-2y=5

7x=21

x=21/7

x=3

2×3+y=8

6+y=8

y=8-6

y=2

Answer:

463833

expand

Medium

Solution

verified

Verified by Toppr

In △ABD and △ACD, we have

DB=DC ∣ Given

∠ADB=∠ADC ∣ since AD⊥BC

AD=AD ∣ Common

∴ by SAS criterion of congruence, we have.

△ABD≅△ACD

⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal

Hence, △ ABC is isosceles.

Answer:

A.

Step-by-step explanation:

With the given information, triangles ABD and ACD can be proved congruent, and by CPCTC, segments AB and AC are congruent.

[tex](k \circ p)(x)=k(p(x))=k(x-3) \\ \\ =2(x-3)^2-5 \\ \\ =2(x^2 - 6x+9)-5 \\ \\ =\boxed{2x^2 - 12x+13}[/tex]

For instance, f[g (x)] exists the composite function of f(x) and g(x). The composite function f[g (x)] exists read as “f of g of x”.

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

A composite function exists generally as a function that exists written inside another function. The composition of a function exists done by replacing one function with another function.

Given function exists, [tex]$k(x)=2 x^{2}-5[/tex] and p(x) = (x - 3)

To find composite function k(p(x)).

k(p(x)) = k(x-3)

[tex]$&k(p(x))=2(x-3)^{2}-5 \\[/tex]

simplifying the above equation, we get

[tex]$&k(p(x))=2\left(x^{2}+9-6 x\right)-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}+18-12 x-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}-12 x+13[/tex]

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

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Answer:

7

Step-by-step explanation:

The start this question by looking at two important things, how much money we have and how much money it costs per person. The friends have a total of $284.25 and we don't know how much it costs per person. To find this we must set up an equation and solve it!

Because each person must pay for parking and a ticket, we can find the cost for one person by adding the parking and ticket cost together.

$9.25 + $27.50 = $36.75

Now that we have solved this equation, we know that it costs $36.75 for one person. To find how many total people can go we dived the total amount of money we have by how much it costs per person. Let's call the number of people that can go 'p'.

p = [tex]\frac{284.25}{36.75}[/tex]

Once we simplify/solve this equation we get 7 [tex]\frac{36}{49}[/tex] so essentially, we get the whole number 7 and a long decimal, but the only important part is the 7. We take the whole number from our answer which is 7.

We now know the answer: 7.

Let's check our work!

7 * 36.75 = 257.75

284.25 - 257.75 = 26.5

26.5 < 36.75 so we are correct!

The final answer is 7!

Have an amazing day!

The population of the country will be 1051 million in 2014

The exponential model that describes the population of a country' in millions, t years after 2003 is given as:

A = 999.8 e0.002t

Rewrite the function properly as:

A = 999.8 * e^(0.002t)

When the population of the country is 1051 million, it means that:

A = 1051

Substitute the known values in the above equation

So, we have:

1051 =  999.8 * e^(0.002t)

Divide both sides by 999.8

1.0512 = e^(0.002t)

Take the natural logarithm of both sides of the equation

ln(1.0512) = ln(e^(0.002t)

Rewrite the equation as:

ln(e^(0.002t) = log(1.0512)

This gives

0.002t = log(1.0512)

Evaluate the logarithmic expression

0.002t = 0.0216

Divide both sides of the equation by 0.002

t = 0.0216/0.002

Evaluate the quotient

t = 10.8

Approximate 10.8 as 11

t = 11

11 years from 2003 is 2014

Hence, the population of the country will be 1051 million in 2014

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Orders of top-three finishers that are possible is given as follows:

[tex]n P_{r}=\frac{14 !}{11 !}=2184[/tex]

In a broad sense, a permutation of a set is the rearrangement of its elements inside an already ordered set, or the arrangement of its members into a sequence or linear order. The act or process of altering an ordered set's linear order is referred to as "permutation."

The number of possible permutations of x elements from a set of n elements is given by:

[tex]n P_{r}=\frac{n !}{(n-r) !}[/tex]

The order in which the cars finish is important, hence the permutation formula is used instead of the combination formula.

In this problem, 3 cars are taken from a set of 14, hence the number of different orders is given as follows:

Using the permutation formula, it is found that the number of different orders of top-three finishers that are possible is given as follows:

[tex]n P_{r}=\frac{14 !}{11 !}=2184[/tex]

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I understand that the question you are looking for is:

How many different orders of top-three finishers are possible? drag the tiles to the correct locations on the equation. not all tiles will be used.