Find the center of mass of the three-mass system shown in the figure relative to the mass m = 1.03 kg . (Figure 1)
Express your answer to two significant figures and include the appropriate units.

Find The Center Of Mass Of The Three-mass System Shown In The Figure Relative To The Mass M = 1.03 Kg

Answers

Answer 1

The center of mass of the three-mass system is 0.433m.

A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. In a collection of unconnected items, the center of mass can also be established.

Given:

Mass of the object, m₁ = 1.03kg

Mass of the object, m₂= 1.50kg

Mass of the object, m₃= 1.10

Taking the location of m as the origin and towards right as positive X-axis.

x₁=0

x₂=0.50m

x₃=0.25+0.50 = 0.75m

The X-coordinate of the center of mass [tex]x_c[/tex] of a system of three masses  m₁, m₂ and m₃ located at the positions x₁, x₂ and x₃ on X-axis is given by,

[tex]x_c=\frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}[/tex]

[tex]x_c=\frac{0+1.50*0.50+1.10*0.75}{1.03+1.50+1.10}\\x_c= 0.433 m[/tex]

Therefore,  the center of mass of the three-mass system is 0.433m.

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Related Questions

A cell connected to two bulbs in series lasts longer than a cell connected to the same bulbs in parallel.Explain why?

Answers

Because the voltage stays the same while the amps grow, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps quadruple to 100ah, the batteries will last longer. Charges are spread among the bulbs in a parallel circuit because they are flowing in several directions over multiple paths. As a result, each bulb will have less charge since the charge is travelling in multiple directions, and the lights will shine less brightly. On the other hand, in a series circuit, there is only one channel and only one location for the charge to travel, meaning that all of the charge is directed at a single lightbulb. As a result, the lightbulb will shine more brilliantly since there is no need to spread the energy. The rule of conservation of energy is not broken because of the difference in power; instead, smaller resistance causes bigger current, which results in brighter lights. The energy traveling from the source to the bulbs remains constant. Because higher power means that more energy in a given time goes quicker from the source to the bulb, brighter lights require more power rather than energy. Because the energy traveling from the source to the bulbs remains constant, the rule of conservation of energy is not being broken; rather, there is merely a difference in power as a result of smaller resistance leading to bigger current, which will result in brighter lights. This means that brighter lights require more power rather than energy since higher power enables more energy to go from the source to the bulb more quickly.

Thank you,

Eddie


[tex] \large{\rm{Question:}}[/tex]

Give one example where the displacement is zero but the distance traveled is not zero.

Answers

Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.

Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.

Example:

Imagine a person walks 10 meters forward and then turns around and walks 10 meters back to the starting point. In this case, the displacement is zero (starting point to ending point), but the distance traveled is 20 meters (10 meters forward + 10 meters backward).

How does the suns energy affect the climate of an area

Answers

There wouldn't be any life on Earth and no climate if it weren't for the Sun.

The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.

The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.

Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.

In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.

Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).

Thank you,

Eddie

The Sun is the only source of energy for the Earth's climate system. Important to earth's atmosphere is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) of the loop?

Answers

Radius of the circular loop is 0.0091m.

What is magnetic field?

Magnetic field is the area around a magnet where the magnetism influence is felt .

What is the magnetic field at the centre of a circular loop?The formula for magnetic field at the centre of a loop is

B =(μ)I/2r

where B= Magnetic field at the centre of a circular loop

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))

=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

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A container with 3 kg of pure water at a temperature of 12 degrees Celsius is placed in a refrigerator where the air temperature is kept at 4 degrees Celsius. how much heat (in joules) is gained by the air when the water cools to 4 degrees Celsius?

Answers

Answer:

100 368 J

Explanation:

Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)

specific heat for water ( in joules) :  4182 J / kg-C

    3 kg *  4182 J / kg-C  * (12-4 C) = 100 368 J

A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases.
The new sphere has a density of ρ > ρ0 and a mass of m = m0.
The new sphere has a mass of m > m0 and a radius of r = r0.
The new sphere has a radius of r = r0 and a density of ρ > ρ0.

Answers

Based on the given data about, volume, mass, and density of the spheres;

the water level will fall; fthe water level may rise or fall; r or fthe water level will rise; r

What determines whether an object floats are sinks in water?

The density, mass, volume, and shape of an object determines whether it will float or sink in water.

Density = mass/volume

For an object to float, it will displace its own weight of the fluid in which it floats. This is according to Archimedes' principle which states that the upward force acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.

Considering the given scenarios:

1. The new sphere has a density of ρ > ρ0 and a mass of m = m0.

This means that the volume of new sphere is smaller than the volume of the original sphere, therefore, the water level will fall,

2. The new sphere has a mass of m > m0 and a radius of r = r0.

This means that the new sphere will have a greater volume and mass. However, the density may be greater or less.. Therefore, the water level may rise or fall.

3. The new sphere has a radius of r = r0 and a density of ρ > ρ0.

The new sphere has equal volume, greater density and mass than the original sphere. Therefore, the water level will rise.

In conclusion, the level of the water in the container depends on the volume, mass and density of the object placed in it.

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10. Complete each of the following radioactive decay equations.
235U → Th+a
92
90
87
37Rb Sr +
6C

F
e
1¹B ++ie

Answers

1. Alpha

Number next to Th is 231

(because 231 + 4 = 235)

The other number below the 4 is 2 - helium

(because 90 + 2 = 92)

2. Beta

Missing numbers are zero and one. Same as the one below it.

3. Beta

11 is the number above the C

(because 11 + 0 = 11)

5 is the number next to the B

(because 5 + 1 = 6)

Basically, the missing numbers must balance on both side of the equation; creating the elements you've started of with, meaning if you where to add the right side of the equation up - you should end up with the same protons and mass numbers you began with.

Hope this helps!

Your car rides on springs, so it will have a natural frequency of oscillation. (Figure 1) shows data for the amplitude of motion of a car driven at different frequencies. The car is driven at 29 mph over a washboard road with bumps spaced 12 feet apart; the resulting ride is quite bouncy.
1)Determine the frequency of the oscillation, caused by the bumps. 1 mile is 5280 feet.
2)Should the driver speed up or slow down for a smoother ride?

Answers

Answer:

See below

Explanation:

29 mile/hr * 5280 f/mile / 3600  s/hr = 42.53  ft/ sec

   42.53 ft / sec    /   12 feet =  3.54  cycles / sec = 3.54 Hz

      for frequency I suppose....where is the referred to figure?

Solve this question please A.S.A.P ⁉️
No spamming ❗​

Answers

Answer:

Here given is :-

Velocity (u) = 10m/sGravity (g) = 10 m/s²Height (h) = ?

Explanation:

v² - u² = 2gh

0² - 10² = 2 × (-10) × h

-100 = -20 h

[tex]h = \frac{ - 100}{ - 20} = 5m[/tex]V = u + gt0 = 10 - 10t10t = 10[tex]t = \frac{10}{10} = 1 \: sec[/tex]Total time = 2 sec

Answer:

See below

Explanation:

vf = vo + at        when it reaches top vf = 0    vo = 10m/s      a = -9.81 m/s^2

0 =   10  + (-9.81) t  

t = 1.02 seconds to reach max

time up = time down   so    roundtrip =  2.04 seconds

define universal vibrations ?​

Answers

Answer:

The second universal law, the law of vibration, posits that everything (every atom, object, and living thing) is in constant motion, vibrating at a specific frequency.

Explanation:

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The second universal law defines this.

The second universal law, also known as the Law of Vibration, The Law of Vibration states that everything in the universe is in a constant state of movement. We refer to these movements as vibration, and the speed or rate at which something vibrates is called its frequency. The only difference between one object and another is its vibration rate.

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How much heat is required to raise the temperature of 0.210 g of water from 19.2 ∘C to 32.0 ∘C?

Answers

Data:

m = 0.210 g T₀ = 19.2 °C + 273 = 292. 2 KT = 32.0 °C  + 273 =  305 KCe = 4.18 J / GK

We apply the following formula

Q = mcₑΔT

    Q = mcₑ (T - T₀)

We substitute Our data in the formula and solve:

Q = 0.210 g * 4.18 J / g K (305 k - 292.2 k)

Q = 11.23 J

The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.70 m and 1.03 m, respectively. The respective rotational speeds are 449 rev/min and 4,150 rev/min. Calculate the speeds of the tips of both rotors.

main rotor ______m/s
tail rotor _______m/s

Compare these speeds with the speed of sound, 343 m/s.

vmain rotor = _______ vsound
vtail rotor = _______ vsound

Answers

(a) The speeds of the tips of both rotors; main rotor 181.02 m/s and  tail rotor 223.8 m/s.

(b) The speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.

Linear speed of main motor and tail rotor

v = ωr

where;

ω is the angular speed (rad/s)r is radius (m)

v(main rotor) = (449 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.7 m)

v(main rotor) = 181.02 m/s

v(tail rotor) = (4,150 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.03 m)

v(tail rotor) = 223.8 m/s

Speed of the rotors with respect to speed of sound

% speed (main motor) = 181.02/343 = 0.528 = 52.8 %

% speed (tail motor) = 223.8/343 = 0.652 = 65.2 %

Thus, the speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.

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Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

Answers

The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.

Force necessary to support the object

Apply Pascal principle to calculated the force needed to support the mass as shown below;

F₁/A₁ = F₂/A₂

F₁/d₁² = F₂/d₂²

F₁ = F₂d₁²/d₂²

where;

F₂ is the force on piston 2, determined from, F = mgd₂ is the diameter of piston 2, given as 9.46 cmd₁ is diameter of piston 1, given as 1.87 cmF₁ is force on piston 1 = ?

Substitute the given parameters and solve for the  force needed to support the mass given.

F₁ = (991 x 9.8 x 0.0187²)/(0.0946)²

F₁ = 379.5 N

Thus, the force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.

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Consider the f(x) = Acos(x) function shown in the figure in blue color. What is the value of amplitude A for this function?
As a reference the g(x) = cos(x) function is shown in red color, and green tick marks are drawn at integer multiples of π.

Answers

The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

What is amplitude of a wave?

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

Amplitude of the red colored wave

From the graph, the amplitude of the red colored wave is 1 unit.

Amplitude of the blue colored wave

From the graph, the amplitude of the red colored wave is 2.1 unit.

Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

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Compute your average velocity in the following two cases: (a) You
walk 73.2 m at a speed of 1.22 m/s and then run 13.2 m at a speed
of 3.02 m/s along a straight track. (b) You walk for 1.00 min at a
speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along a
straight track. (c) Graph x versus t for both cases and indicate how
the average velocity is found on the graph.

Answers

(a) Walking 73.2 m at 1.22 m/s would take

[tex]\dfrac{73.2\,\rm m}{1.22 \frac{\rm m}{\rm s}} = 60 \,\rm s[/tex]

and running 13.2 m at 3.02 m/s would take

[tex]\dfrac{13.2\,\rm m}{3.02\frac{\rm m}{\rm s}} \approx 4.37\,\rm s[/tex]

You've undergone a total displacement of 73.2 + 13.2 = 86.4 m in a matter of approximatly 64.37 s, so your average velocity is

[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{86.4\,\mathrm m}{64.37\,\rm s} \approx \boxed{1.34\dfrac{\rm m}{\rm s}}[/tex]

(b) In the first 1.00 min = 60 s, you undergo a displacement of

[tex](60\,\mathrm s) \left(1.22 \dfrac{\rm m}{\rm s}\right) = 73.2 \,\rm m[/tex]

and in the second minute, you undergo a displacement of

[tex](60\,\mathrm s) \left(3.05\dfrac{\rm m}{\rm s}\right) = 183 \,\rm m[/tex]

Your total displacement is then 73.2 + 183 = 256.2 m in a matter of 2.00 min = 120 s, so your average velocity is

[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{256.2\,\mathrm m}{120\,\rm s} \approx \boxed{2.14\dfrac{\rm m}{\rm s}}[/tex]

(c) For part (a), your displacement [tex]x(t)[/tex] (in m) at time [tex]t[/tex] (in s) is given by

[tex]x(t) = \begin{cases}1.22t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.02 (t-60) & \text{for } t > 60\end{cases}[/tex]

and for part (b), your displacement is given by the very similar

[tex]x(t) = \begin{cases}1.22 t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.05(t-60) & \text{for } t > 60 \end{cases}[/tex]

See the attached plots. The average velocity for the given situation is the slope of the dotted line.

A 750 kg car is stalled on an icy road during a snowstorm. A 1000 kg car traveling eastbound at 13 m/s collides with the rear of the stalled car. After being hit, the 750 kg car slides on the ice at 4 m/s in a direction 30 ∘ north of east.
A) What is the magnitude of the velocity of the 1000 kg car after the collision?
B) What is the direction of the velocity of the 1000 kg car after the collision?
C) Calculate the ratio of the kinetic energy of the two cars just after the collision to that just before the collision. (You may ignore the effects of friction during the collision.)

Answers

(a) The magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

(b) The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

(c) The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

Velocity of the 1000 kg after the collision

Apply the principle of conservation of linear momentum as follows;

Final velocity in x direction

m₁u₁  +  m₂u₂ = m₁v₁x  +  m₂v₂x

where;

m₁ is mass of 750 kg caru₁ is initial velocity of 750 kg massm₂ is mass of 1000 kg caru₂ is initial velocity of 1000 kg massv₁ is final velocity of 750 kg massv₂ is final velocity of 1000 kg mass

750(0) + 1000(13) = 750(4 cos 30)   +   1000v₂x

13000 = 2,598.1  +   1000v₂x

10,401.9 = 1000v₂x

v₂x  =  10.4 m/s

Final velocity in y direction

m₁u₁  +  m₂u₂ = m₁v₁y  +  m₂v₂y

750(0) + 1000(0) = 750(4 sin 30)   +   1000v₂y

0 = 1500 +  1000v₂y

v₂y  = -1500/1000

v₂y  = -1.5 m/s

Resultant final velocity

v = √(v₂ₓ² + v₂y²)

v = √[(10.4)² + (-1.5)²]

v = 10.5 m/s

Direction of the final velocity of 1000 kg car

tanθ = v₂y/v₂ₓ

tanθ = -1.5/10.4

tanθ =  -0.144

θ = arc tan(-0.144)

θ = 8.2 ⁰ north west

Kinetic energy of the cars before the collision

K.Ei = 0.5m₁u₁²  +  0.5m₂u₂²

K.Ei = 0.5(750)(0)²  +  0.5(1000)(13)²

K.Ei = 84,500 J

Kinetic energy of the cars after the collision

K.Ef = 0.5(750)(4)²  +  0.5(1000)(10.5)²

K.Ef = 61,125 J

Ratio of the kinetic energy

K.Ef/K.Ei = 61,125/84,500

K.Ef/K.Ei = 0.72

Thus, the magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

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A tree limb is blown loose from a tree during a storm. As it falls, it gains
speed. Which type of energy is the tree limb gaining as it falls?
O A. Kinetic energy
B. Gravitational potential energy
O C. Nuclear energy
OD. Light energy

Answers

Answer:

B Gravitational potential energy

Explanation:

If the gravitational potential energy of an object 10 m above the ground is 50 J, what is its Ep, if it moves to 30 m above the ground?​

Answers

Answer:

150 J

Explanation:

Moving 3 times higher will increase the   P E  x 3   = 150 J

ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A. If the acceleration of the system is 5.88m/s2, what is the Tension T on Box A?

Answers

The tension on box A is 117.6 N

What is Equilibrium of Forces ?

Equilibrium is a state of an object with respect to a given observable quantity during the time for which there is no change in that quantity.

A body is said to be in equilibrium when:

the body as a whole either remains at rest or moves in a straight line with constant speed.the body is either not rotating at all or is rotating at a constant angular velocity.

Given that box A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A.

The tension in the rope will be the same.

Given that Box A is placed on a horizontal surface that is frictionless, that is,

T = ma .... (1)

Also,  Box B is hanging from a pulley by a rope connected to Box A. That is,

W - T = ma ...... (2)

Where W = mg

Since the acceleration of the system is 5.88m/s² which will be the same for the two equations, then the Tension T on Box A can be calculated by substituting acceleration and mass into equation (1)

T = 20 x 5.88

T = 117.6 N

Therefore, the tension on box A is 117.6 N

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(Please help 25 points)

Asteroids X, Y, and Z have equal mass of 6.0 kg each. They orbit around a planet with M=6.20E^24 kg. The orbits are in the plane of the paper and are drawn to scale.

In the statements below, TE is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.

The PE of X at r is .... that at s

The TE of Y is .... the TE of X

The PE of Y at u is .... the PE of Z at c

The speed of Y at i is .... that at u

The KE of Z at u is .... that at m

The PE of Y at s is .... the PE of X at c

The TE of Z is .... the TE of X

The PE of X at c is .... the PE of Z at c

(Options are: greater than, less than, equal to)

Answers

The potential energy (P.E) of X at r is less than P.E at s.

The total energy (T.E) of Y is less than total energy (T.E) of X.

The PE of Y at v is greater than the PE of Z at c.

The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The PE of X at c is less than the PE of Z at c.

PE of X at r  and at s

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

TE of Y is .... the TE of X

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

PE of Y at v is .... the PE of Z at c

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

Speed of Y at i is .... that at u

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

KE of Z at u is .... that at n

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

PE of Y at s is .... the PE of X at c

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

The TE of Z is .... the TE of X

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

The PE of X at c is .... the PE of Z at c

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

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Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical
rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really
understand acceleration.
A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of
the car for a 16 second interval of time.

Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving?
You must answer using at least two complete sentences and vocabulary words from this lesson.

Answers

Q.1 Calculate the different accelerations from the graph

At initial point (let O) the velocity was 0 m/s to reach point A when the velocity was 5 m/s it took nearly 3 seconds as we all know that acceleration is nothing but the change in velocity per unit time

[tex]a \: = \frac{dv}{t} [/tex]

[tex]a = \frac{5 - 0}{3} = \frac{5}{3} \: m/ {s}^{2} [/tex]

Similarly from point A to point B the acceleration was

[tex]a = \frac{dv}{t} = \frac{7 - 5}{3} = \frac{2}{3} m/s²[/tex]

From Point B to C the velocity was constant so the acceleration at that point would be zero.

in the same way we can calculate acceleration for rest other points.

Q.2 Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving?

We all know that Velocity is nothing but the speed with direction. Merry Go Round and a Ferris Wheel has constant speed but dynamic direction due to which the magnitude of velocity at every point differs with different sign hence it have a constant acceleration.

what does personal mission statement?

Answers

Answer:

A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.

Explanation:

It explains how you aim to pursue that purpose, and why it matters so much to you.

A thin spherical shell of mass M and radius r is allowed to roll from the edge of a hemispherical bowl of radius R = 80.0 cm. It rolls down with no slipping.
1) Find the speed of the center of mass of the spherical shell when it is at the bottom of the bowl, if r is very small.
2) Repeat part 1) if r = 10.0 cm. Moment of inertia of a thing spherical shell if 2/3Mr^2.

Answers

(a) The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 3.1 m/s when the radius is 80 cm.

(b) The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 1.1 m/s when the radius is 10 cm.

Speed of the shell at the bottom of the bowl

The speed of the shell at the bottom of the bowl is calculated by applying the principle of conservation of energy.

K.E(rot) + K.E(trans) = P.E

where;

P.E is the potential energy of the ball at the initial positionK.E(rot) is rotational kinetic energyK.E(trans) is translation kinetic energy

¹/₂mv² + ¹/₂Iω² = mgh

where;

I is moment of inertia of the spherical shellh is the height of fallv is the speed at the bottomω is angular speed

¹/₂mv² + ¹/₂(²/₃Mr²)(v/r)² = mgh

¹/₂v² + ¹/₂(²/₃r²)(v²/r²) = gh

¹/₂v² + ¹/₂(²/₃)(v²) = gh

¹/₂v² + ¹/₃v² = gh

⁵/₆v² = gh

v² = 6gh/5

v = √(6gh/5)

Let the vertical height from the edge of bowl to the bottom , h = R = 80 cm

v = √(6 x 9.8 x 0.8 /5)

v = 3.1 m/s

When the radius = 10 cm

v = √(6gh/5)

v = √(6 x 9.8 x 0.1 /5)

v = 1.1 m/s

Thus, the speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 3.1 m/s when the radius is 80 cm.

The speed of the center of mass of the spherical shell when it is at the bottom of the bowl is 1.1 m/s when the radius is 10 cm.

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A ball of mass 0.200 kg has a velocity of 150m/s; a ball of mass 0.300 kg has a velocity of - 0.4m/s. They meet in a head-on elastic collision. (a) Find their velocities after the collision. (b) Find the velocity of their center of mass before and after the collision. ​

Answers

(a) The velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.

(b) The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.

Velocity of the balls after collision

Apply the principle of conservation of linear momentum to determine the velocity of the balls;

m₁u₁ + m₂u₂ = m₁v₁  + m₂v₂

0.2(150) + (0.3)(-0.4) = 0.2v₁ + 0.3v₂

29.88 = 0.2v₁ + 0.3v₂

Apply one directional linear velocity

u₁ + v₁ = u₂ + v₂

v₁ = u₂ + v₂ - u₁

v₁ = -0.4 + v₂ - 150

v₁ = v₂ - 150.4

Substitute the value of v₁ into the first equation;

29.88 = 0.2(v₂ - 150.4) + 0.3v₂

29.88 = 0.2v₂ - 30.08 + 0.3v₂

59.96 = 0.5v₂

v₂ = 59.96/0.5

v₂ = 119.92 m/s

v₁ = 119.92 - 150.4

v₁ = -30.48 m/s

Velocity of their center mass before collision

V(cm) = (0.2 x 150  +  0.3 x 0.4) / (0.2 + 0.3)

V(cm) = 60.24 m/s

Velocity of their center mass after collision

V(cm) = (0.2 x 30.48 +  0.3 x 119.92) / (0.2 + 0.3)

V(cm) = 84.14 m/s

Thus, the velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.

The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.

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If something is a good conductor, what type of insulator is it?

1. also a good insulator
2. a metal
3. it depends
4. a poor insulator

Answers

4. a poor insulator

If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.

Answer:

4 conductors and insulators are opposites of each other.

Explanation:

how to calculate the half time​

Answers

The formular for calculating half life is:

T1/2=0.693/Π

A directional loudspeaker aims a sound wave of Frequency 200 H₂ at wall. At what distance from the wall would you stand and hear no sound at all? (v= 332 m/s).​

Answers

The distance from the wall you would stand and hear no sound at all is 0.83 m.

What is speed of wave?

The speed of a wave is the rate of change of distance traveled by a wave with time.

Distance of the wave

The distance at which the wave will have zero amplitude, there will be no sound at all since amplitude of a sound is proportional to intensity of the sound.

The point of zero amplitude, L = λ/₂

Where;

λ is wavelength of the wave

The wavelength of the wave is calculated as follows;

λ = V/f

where;

V is speed of sound wavef is frequency of the wave

λ = 332/200

λ = 1.66 m

Distance from the wall a zero sound

L = 1.66/2

L = 0.83 m

Thus, the distance from the wall you would stand and hear no sound at all is 0.83 m.

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Which one of the following statements concerning weight and energy balance is most accurate?

A. People generally need the same amount of physical activity to maintain weight stability.

B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.

C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.

D. The optimal amount of physical activity needed to maintain weight is unclear.

Answer: D. I took the test and got it right

Answers

The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

What is energy balance?

Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.

Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.

So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

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It has been suggested that rotating cylinders about 19.5 mi long and 5.66 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?

_____rad/s

Answers

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

Angular speed of the cylinder

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;

a = v²/r

v² = ar

(ωr)² = ar

ω²r² = ar

ω²r = a

ω² = a/r

ω = √(a/r)

where;

a is centripetal acceleration = acceleration due to gravity, gr is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 mω is angular speed

ω = √(g/r)

ω =  √(9.8/4554.4)

ω = 0.046 rad/s

Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

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Why are enthalpy changes always lower than their expected values?
A. They aren't. They are always greater than expected.
B. Heat losses during the experiment
C. Heat gains during the experiment
D. Faulty measurements

Answers

Enthalpy changes are always lower than their expected values due to faulty measurements; option D.

What are enthalpy changes?

Enthalpy changes refers to the changes in the heat content of substances in the course of a reaction.

Enthalpy changes occurs as a result of bond breaking and bond formation in the reactant molecules and product molecules respectively.

Enthalpy change = Energy of bond formation - Energy of bond breakage.

Enthalpy changes are measured from the changes in temperature that are observed in the course of a given reaction.

Due to faulty measurements in a particular experiment measuring enthalpy changes, enthalpy changes are always lower than their expected values.

Therefore, accurate measurements are required if results as close as possible to the actual enthalpy changes are to be obtained.

In conclusion, enthalpy changes measure the heat changes that occur during a particular chemical reaction.

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