Explain the impact that changing the temperature has on a system in a state of dynamic equilibrium. what will happen when the temperature of an exothermic reaction mixture at equilibrium is increased?

Answers

Answer 1

An endothermic reaction is favored by raising the temperature of a system in dynamic equilibrium. The mechanism absorbs the increased heat to offset the alteration you made. An exothermic reaction is favored by a system's temperature falling while it is in dynamic equilibrium.

Which of these reactions is endothermic?

Any chemical process that takes heat from its surroundings is said to be endothermic. The reaction's activation energy comes from the energy that was absorbed. This kind of reaction is characterized by its icy sensation.

How does an exothermic reaction work?

An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.

What kind of reaction is an exothermic reaction?

Materials like hydrocarbons reacting with oxygen to produce combustion products like water and carbon dioxide is an example of an exothermic process.

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Related Questions

Which main intermolecular force must be overcome to convert liquid nh3 to nh3 vapor?

Answers

Intermolecular hydrogen force must be overcome to convert liquid NH3 to NH3 vapour.

Sublimation is the phase transition of a substance directly from the solid to the gaseous phase without passing through the liquid phase.

There are the 3 forces that exist between the 2 molecules of NH3

1. Dispersion force: these forces exist between any 2 molecules regardless of anything else.

2. Hydrogen bonding: H is directly bonded to the extremely electronegative atom N, O and F, hence is nearly stripped off electron due to the large electronegativity difference. Hydrogen being small atom further reduces in size even allowing it to approach other molecules very closely. Here, N, O, and F gathers more partial negative charge.

Due to the closure approach between the molecule and strong partial charge, hydrogen bonding is generally more important than dipole bond.

3. dipole dipole interaction: NH3 is a polar molecule with a permanent separation of charge. Each molecules behaves like a tiny magnet and has positive and negative poles so 2 NH3 molecules attract each other. Dipole dipole interactions are stronger than dispersion force in the small molecules.

Thus we concluded that the hydrogen bond should overcome to convert NH3 to vapours.

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Select the correct answer.
Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
A. The charge on B will decrease.
B. The charge on B will increase.
C. The electric force between A and B will decrease.
D. The electric force between A and B will increase.

Answers

According to Coulomb's law of  electrostatic forces, as the charge of a body  increases, the force exerted also increases. Hence, The electric force between A and  B increases as the charge of A increases.

What is Coulomb's law ?

Coulomb's law states that, the electrostatic force between two charges is directly proportional to the magnitude of their charges and inversely proportional to the distance between them.

The mathematical expression for Coulomb's law is written as follows:

F = k q1 q2/r²

where, q1 and q2 be the charges r be the distance between them, k is the proportionality constant.

Therefore, as the charge of A increases, irrespective whether the force is attractive or repelling, the electric force between them A and B increases.

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How many milliliters of 10. 5 m hcl(aq) are needed to prepare 225. 0 ml of 1. 00 m hcl(aq)?

Answers

There are  21.42 milliliters of a 10. 5 M HCl(aq) are needed to prepare 225. 0 ml of 1. 00  M HCl(aq)

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1} =M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =   10. 5 M

[tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 1. 00 M

[tex]V_{2}[/tex] = 225. 0 ml

10. 5 M × [tex]V_{1}[/tex] = 1. 00 M×225. 0 ml  

[tex]V_{1}[/tex]  in milliliters = 1. 00 M×225. 0 ml / 10. 5 M = 21.42 ml

Volume in milliliters is  21.42 ml .

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Which type of nuclear decay is the radioactive isotope fe2659 likely to undergo?

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Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

Whenever there are too many protons or even neutrons in a nucleus, one of the protons and neutrons will turn into the other, which is known as beta decay. During beta minus decay, a neutron transforms into a proton, electron, as well as antineutrino.

[tex]Fe_{26} ^{59}[/tex] → [tex]Co_{27} ^{59} +\beta_{1} ^{0}[/tex]

It can be seen that after the beta minus decay Fe changes into Co.

In beta decay , decrease in atomic number by one unit Fe atom get converted into Co atom.

Neutron-rich nuclei often decay by producing both an electron and an antineutrino.

Therefore, Beta minus decay will be obtain in the radio-active isotope of Fe-26 power 59.

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Now, using your periodic table as a reference, type the symbols for the known elements into their appropriate groups and periods in the modified table below. Note that we’re using the international group numbers (1-18), followed by the American scheme for the A-group elements in parentheses.

Answers

The symbols for some known elements using the periodic table are given below

Groups/Period

H

He

Li

Be

B

C

N

O

F

Ne

Na

Mg

Al

SI

P

S

Cl

Ar

K

CA

What is an element?

An element is a substance which cannot be split into simpler units by any ordinary chemical process

So therefore, the elements in the periodic table are classified based on their increasing atomic numbers.

The group is vertical representation of the elements

The periods is horizontal arrangements of elements in the periodic table

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Answer:

see attachment

Explanation:

plato users!!

If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 8.00 g of O2?

Answers

Taking into account definition of percent yield, 31.42 grams of KClO₃ are needed to produce 8.00 g of O₂.

Reaction stoichiometry

In first place, the balanced reaction is:

2 KClO₃ → 2 KCl + 3 O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

KClO₃: 2 moles KCl: 2 molesO₂: 3 moles

The molar mass of the compounds is:

KClO₃: 122.55 g/moleKCl: 74.55 g/moleO₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

KClO₃: 2 moles× 122.55 g/mole= 245.1 gramsKCl: 2 moles× 74.55 g/mole= 149.1 gramsO₂: 3 moles× 32 g/mole= 96 grams

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theorical yield)×100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

actual yield= 8 gramstheorical yield= ?percent yield= 65%

Replacing in the definition of percent yields:

65= (8 grams÷ theorical yield)×100

Solving:

theorical yield= (8 grams÷ 65)×100

theorical yield= 12.31 grams

Then, this means that you need to find the mass of KClO₃ would theoretically produce 12.31 g of O₂.

Mass of KClO₃ required

The following rule of three can be applied: If by reaction stoichiometry 96 grams of O₂ are produced by 245.1 grams of KClO₃, 12.31 grams of O₂ are produced by how much mass of KClO₃?

[tex]mass of KClO_{3} =\frac{12.31 grams of O_{2}x245.1 gramsof KClO_{3} }{96 grams of O_{2}}[/tex]

mass of KClO₃= 31.43 grams

Finally, 31.42 grams of KClO₃ are needed to produce 8.00 g of O₂.

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An aerosol mixture of particulates and sulfur compounds form a grayish colored substance that is called ________. inversion smog industrial smog photochemical fog sulfuric aerosols industrial fog

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An aerosol mixture of particulates and sulfur compounds form a grayish-colored substance that is called industrial smog.

What is Particulate Matter?

Airborne particulate matter (PM) is a composite of several chemical species rather than a single contaminant. It consists of a complex mixture of solids and aerosols, including dry solid particles, liquid-coated solid cores, and minute liquid droplets. Particles can contain inorganic ions, metallic compounds, elemental carbon, organic compounds, and chemicals from the earth's crust. They can vary greatly in size, shape, and chemical makeup. For the goal of regulating air quality, the particle diameter is used.

Those that have a diameter of 10 microns or below (PM10) are inhalable and can have a negative impact on health. Particles with a diameter of 2.5 microns or less are considered to be fine particulate matter (PM2.5). Consequently, a percentage of PM10 is made up of PM2.5.

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Reactants are the____________ substances in a chemical change and products are the ______substances.

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Answer:

What is the name of the substances that are used at the beginning of a chemical reaction?

The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

Explanation:   :)

Which events would likely lead to a reduction in the sea level of Earth’s oceans?

Answers

Answer:

A shift in the global hydrologic cycle

Explanation:

During cold-climate intervals, known as glacial epochs or ice ages, sea level falls because of a shift in the global hydrologic cycle: water is evaporated from the oceans and stored on the continents as large ice sheets and expanded ice caps, ice fields, and mountain glaciers.

The hydrological cycle of the earth is the sum total of all processes in which water moves from the land and ocean surface to the atmosphere and back in form of precipitation. The hydrological cycle is dependent on various factors and is equally affected by oceans and land surfaces.

As water freezes, ________. its hydrogen bonds break apartit loses its polarityit cools the surrounding environmentits molecules move farther apart.

Answers

The molecules of water move farther apart upon freezing.

Molecules are the compounds formed by the combination of  one or more atoms by certain chemical bonds. Each molecule has distinctive physical and chemical properties.  

Water is also a molecule consisting of two H atoms and one O atom. Its physical state in nature is liquid. The atoms present inside water are joined together by the hydrogen bonding. Upon freezing, water molecules start forming more hydrogen bonds with the molecules present in their neighborhood. This makes them to move farther and spread apart. This also marks the reason for ice being denser than water.

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Determine the name for aqueous H2CO3. carbonous acid dihydrogen carbonate carbonic acid hydrocarbonic acid hydrocarbide acid

Answers

The name for aqueous [tex]H_{2} CO_{3}[/tex] is carbonic acid.

So, option C is correct one.

Binary hydrogen compounds with non metals may form H+ (proton) and an anion dissolved in water. The acidic solutions are named as if they were molecular acids , using the usual name for the compound itself , replacing hydrogen with hydro- and suffix -ide with ic. The word acid is then use.

The inorganic acid is an acid drive from one or more inorganic compounds. All inorganic acids form hydrogen ions and the conjugate base ions when dissolved in water.

Example: carbonic acid ( [tex]H_{2} CO_{3}[/tex] )

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Consider the gibbs energies at 25 ∘ c. substance δ∘f (kj·mol−1) ag (aq) 77. 1 cl−(aq) −131. 2 agcl(s) −109. 8 br−(aq) −104. 0 agbr(s) −96. 9 (a) calculate δ∘rxn for the dissolution of agcl(s)

Answers

The ∆G° for the dissolution of AgCl solid is 55.7 kJ/mol.

What is gibbs free energy?

The gibbs free energy is termed as thermodynamic quantity which is equal to the enthalpy (of a system or process) subtracted by the product of the entropy and the absolute temperature.

The gibbs free energy of the reaction is given by:

∆G°(rxn) =sum of ([∆G°] products)- sum of ( [∆ G°] reactants)

Reaction can be given as:

AgCl(S) » Ag+ (aq) + Cl- (aq)

Gibbs free energy of silver ions = ∆G°f, (Ag+) = 77.1kJ/mol

Gibbs free energy of formation of chloride ions = ∆G°f, (Cl-)= -131. 2kJ/mol

Gibbs free energy of formation of silver chloride solid = ∆ G°f, (AgCl) = - 109.8kJ/mol

The gibbs free energy of the reaction of dissolution of AgCl) :∆ G°rxn:

∆G°rxn = (77.1kJ/mol) – (- 109.8kJ/mol)

55.7kJ/mol

Thus, we found that the ∆G° for the dissolution of AgCL solid is 55.7 kJ/mol.

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In a titration experiment, 31. 4 ml of 1. 120 m hcooh is neutralized by 16. 3 ml of ba(oh)2. what is the concentration of the ba(oh)2 solution?

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In a titration experiment, 31. 4 ml of 1. 120 M HCOOH is neutralized by 16. 3 ml of [tex]Ba(OH)_{2}[/tex]. So, the concentration of the [tex]Ba(OH)_{2}[/tex]  solution is 23.16 M

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =  120  M

[tex]V_{1}[/tex] =31. 4 ml

[tex]M_{2}[/tex] = ?

[tex]V_{2}[/tex] = 16. 3 ml

120  M ×31. 4 ml  =  [tex]M_{2}[/tex]  ×  16. 3 ml

[tex]M_{2}[/tex]  = 120  M ×31. 4 ml / 16. 3 ml =23.16 M

In a titration experiment, the concentration of the [tex]Ba(OH)_{2}[/tex]  solution is 23.16 M

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The angle between the hydrogen atoms in water (h2o) is slightly less than expected for a tetrahedral shape. this is because of the:_______.

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The angle between the hydrogen atoms in water (h2o) is slightly less than expected for a tetrahedral shape. this is because of the extra electron repulsion from the lone pairs.

A water molecule consists of two hydrogen atoms and one oxygen atom. The three atoms make an angle; the H-O-H angle is approximately 104.5 degrees. The centre of each hydrogen atom is approximately 0.0957 nm from the centre of the oxygen atom.

In water, each hydrogen nucleus is covalently bound to the central oxygen atom by a pair of electrons that are shared between them. In H2O, only two of the six outer-shell electrons of oxygen are used for this purpose, leaving four electrons which are organized into two non-bonding pairs. The four electron pairs surrounding the oxygen tend to arrange themselves as far from each other as possible in order to minimize repulsions between these clouds of negative charge. This would ordinarily result in a tetrahedral geometry in which the angle between electron pairs (and therefore the H-O-H bond angle) is 109.5°. However, because the two non-bonding pairs remain closer to the oxygen atom, these exert a stronger repulsion against the two covalent bonding pairs, effectively pushing the two hydrogen atoms closer together. The result is a distorted tetrahedral arrangement in which the H—O—H angle is 104.5°.

About tetrahedral shape :

In geometry, a tetrahedron (plural: tetrahedra or tetrahedrons), also known as a triangular pyramid, is a polyhedron composed of four triangular faces, six straight edges, and four vertex corners. The tetrahedron is the simplest of all the ordinary convex polyhedra and the only one that has fewer than 5 faces.

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A vessel with a volume of 32. 5 l contains 2. 80 g of n2 gas, 0. 403 g of h2 gas, and 79. 9 g of ar gas. at 25°c, what is the total pressure in the vessel? show the set up and answer with unit

Answers

The total pressure of the gases in the vessel is found out by using the partial pressures of individual gases and adding them up. The total pressure of the gases in the vessel is 1.72 atm.

The Partial pressure of the gases is the individual pressure of the gases present in a vessel containing a mixture of gases. The total pressure can be found out by adding partial pressure of all gases.

Given:

Volume of vessel, V= 32.5L

Mass of Nitrogen gas = 2.8g

Mass of Hydrogen gas = 0.403g

Mass of Argon gas = 79.9g

We know that:

             Molar Mass of Nitrogen gas = 28g

             Molar Mass of Hydrogen gas = 2g

             Molar Mass of Argon gas = 40g

∴ Moles of gas = Given mass / Molar mass

∴ Using the Ideal Gas Equation:

PV = nRT

where, P is the Pressure of gas

V is the volume of gas

n is the moles of gas

R is the Universal Gas constant

T is the temperature

Applying the above equation of all three gases indivudually,

∴ For Nitrogen,

P₁V = n₁RT                    

⇒ P₁ × 32.5 = 2.8/28 × 0.082 × 298

⇒ P₁ = 0.07atm

∴ For Hydrogen,

P₂V = n₂RT                    

⇒ P₂ × 32.5 = 0.4/2 × 0.082 × 298

⇒ P₂ = 0.15 atm

∴ For Argon,

P₃V = n₃RT                    

⇒ P₃ × 32.5 = 79.9/40 × 0.082 × 298

⇒ P₃ = 1.5 atm

∴ Total pressure of vessel, P = P₁ + P₂ + P₃

                                         P = 1.72 atm

The total pressure of the gases in the vessel is 1.72 atm.

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Which acid or base (along with its corresponding salt) should be used to generate a buffer solution with ph around 3. 5?

Answers

Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.

It must consider the acid whose pKa = pH in order to choose the base or acid that can produce a buffer solution with such a pH of about 3.5.

However, it also need to consider buffer capacity, which is a factor that can alter the pH of a solution by one unit in a liter.

The connection between the components' concentrations and their concentrations themselves affects buffer capacity in addition to their individual concentrations.

Therefore, Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.

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While working in a pharmaceutical laboratory, you need to prepare 1.50 L of a 2.20-M NaCl solution. What mass of NaCl would be required to prepare this solution

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193 grams of NaCl are needed to make 1.50 L of a 2.20-M NaCl solution.

Calculation of the mass of NaCl required:

The only thing we need to know is that a solution's molarity informs us of the exact amount of moles of solute that are contained in 1 L of a solution.

In this situation, a NaCl (sodium chloride) solution with a 2.20-M concentration will have 2.20 moles of the solute (sodium chloride) in every 1 L of the solution.

The solution's molarity of 2.20 M requires that every 1 L of this solution include 2.20 moles of sodium chloride, which implies that every 1.50 L of this solution needs to contain

[tex]1.5 L solution .\frac{2.20 moles NaCl}{1L solution} = 3.30 moles NaCl[/tex]

Utilize the compound's molar mass to translate the amount of NaCl (sodium chloride) in moles to grams.

[tex]3.30 moles NaCl . \frac{58.4 gm}{1 mole NaCl} = 192.7 gm[/tex] ≈ 193 gm

Therefore it is concluded that the final answer is 193 gm.

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48. Which of the following (a) KCI (b) NaCl is called Sylvine? (c) CaCl₂ (d) MgCl₂​

Answers

Answer:

(a) KCI

sylvine, is potassium chloride (KCl) in natural mineral form

Draw the alkane formed when 4,5,5‑trimethyl‑1‑hexyne or 4,5,5‑trimethylhex‑1‑yne is treated with two equivalents of hbr.

Answers

Answer:

2,2 - dibromo - 4,5,5 - trimethylhexane

Explanation:

When 2 equivalents of HBr are added to 4,5,5‑trimethyl‑1‑hexyne, the alkane (at the top right of the image) is formed. The bromine branches are added to the second carbon because the intermediate carbocations are the most stable on the secondary carbon. Below I have drawn the mechanism.

If 36. 0 ml of 0. 20 m hcl is added to 30. 0 ml of 0. 40 m naoh, what will be the ph of the resulting solution?

Answers

The pH of the resulting solution is 2.05

Sodium hydroxide and hydrochloric acid neutralize each other in a 1:1 mole ratio as described by the balanced chemical equation

           [tex]NaOH_{(aq)} + HCL_{(aq)}[/tex] →  [tex]NaCl_{(aq)} + H_2O_{(aq)}[/tex]

This means that a complete neutralization, which would result in a neutral solution, i.e. a solution that has pH=7 at room temperature, requires equal numbers of moles of sodium hydroxide and hydrochloric acid.

Notice that your two solutions have equal molarities, but that the volume of the hydrochloric acid solution is 1.2 times larger than the volume of the sodium hydroxide solution. This implies that the number of moles of hydrochloric acid is 1.2 times bigger than the number of moles of sodium hydroxide.

This means that after the reaction is complete, you will be left with excess hydrochloric acid → the pH of the resulting solution will be <7.

Now, the number of moles of hydrochloric acid that will not take part in the reaction is given by

= moles of HCL added - moles of NaOH added

= 36 × [tex]\frac{0.100 moles HCL}{10^3 ml}[/tex] - 30 × [tex]\frac{0.100 moles HCL}{10^3 ml}[/tex]

= [tex]\frac{6* 0.100 moles}{10^3}[/tex]

The total volume of the resulting solution will be = ( 30 + 36 ) mL

                                                                            = 66 mL

Since hydrochloric acid is a strong acid that ionizes in a 1:1 mole ratio to produce hydronium cations, you can say that the concentration of hydronium cations in the resulting solution will be

[tex][ H_3O^+] = \frac{\frac{6*0.100}{10^3} }{66*10^3}[/tex]

[tex][ H_3O^+] = \frac{6*0.100}{66}[/tex]

pH = - log [tex](\frac{6*0.100}{66} )[/tex]

pH =  2.05

Therefore, the pH of the resulting solution is 2.05.

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How many moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride?

Answers

299.7 moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride.

Calculation,

The production of aluminium metal is given as,

[tex]Al^{+3} + 3e^{-}[/tex]→ [tex]Al[/tex]

The 3 moles of electrons require to produce 1 gm of atom of aluminium ( weight = 27 ) solution fluoride.

The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 3mol×99.9g/1g

The number of moles of electrons are required to produce 99. 9 g of aluminum metal from a sample of molten aluminum fluoride = 299.7 moles

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How many electrons are present in the nonbonding π molecular orbital of the allyl anion? a. 2 b. 1 c. 3 d. 0

Answers

The number of electrons, which are present in the nonbonding π molecular orbital of the allyl anion is "0".

Anions, cations, but also allylic radicals have always been frequently mentioned as reaction intermediates. Each one has three adjacent [tex]sp^{2}[/tex]-hybridized carbon centers, and they all rely on resonance for stability. Two resonance structures would be used to present each species, with the charge as well as unpaired electron scattered across both the 1,3 and 0 positions.

The Aufbau principle states that these orbitals would fill up based on the order of stability, therefore a typical pi bond, will have 2 electrons in the Pi orbital as well as zero in the Pi* orbital.

Therefore, the correct answer will be option (d)

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Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

Answers

Answer:

Fe(CN)₂,  FeCO₃,  Pb(CN)₄,  Pb(CO₃)₂

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CN)₂
-----> Fe²⁺ and CN⁻

-----> +2 + (-1) + (-1) = 0

2.) FeCO

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

3.)  Pb(CN)₄

-----> Pb⁴⁺ and CN⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) Pb(CO)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 +(-2) + (-2) = 0

What volume (to the nearest 0. 1 ml) of 4. 70-m naoh must be added to 0. 700 l of 0. 250-m hno2 to prepare a ph = 3. 20 buffer?

Answers

log1.429V=3.20  volume (to the nearest 0. 1 ml) of 4. 70-m NaOH must be added to 0. 700 l of 0. 250-m HNO2 to prepare a ph = 3. 20 buffer

Solution ;

pH= pKa +log {[ NaOH ] / [ HNO2 ]​}

3.20=3.80+log{(V×4.70)/ ( 0.700×0.250)}

3.20=log1.429V

Volume will be 3.20=log1.429V

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Based on your experience, which reactions are likely to be self-sustaining? check all that apply. an engine with pistons rising and falling. burning gasoline in a car engine a pan full of eggs floating in water. hard-boiling an egg a space ship launch. thrusting a rocket into space

Answers

The reactions which are likely to be self-sustaining from my experience among the choices above is burning gasoline in a car engine a pan full of eggs floating in water

What is self sustaining?

Self sustaining simply means a condition in which one is able to continue in a healthy state without an external support outside assistance.

So therefore, the reaction which are likely to be self-sustaining from my experience among the choices above is burning gasoline in a car engine a pan full of eggs floating in water

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Explain why doesn’t the total pressure increase when more gas is added to the chamber?

Answers

Pressure is inversely proportional to volume. Therefore, the effect of pressure change is opposite to the effect of volume change. So when more gas is added to the chamber the total pressure of the chamber doesn't increase.

What are the different relations between pressure and volume?As the volume changes, the concentrations and partial pressures of both reactants and products change. As the volume decreases, the reaction shifts to the reaction side with fewer gas particles.As the volume increases, the reaction shifts to the side of the reaction containing more gas particles. As the pressure increases, the equilibrium shifts towards reactions with fewer moles of gas. As the pressure decreases, the equilibrium shifts to the side of the reaction with higher moles of gas.Moreover, the pressure change in the system due to the addition of the inert gas is not limited to this.

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Maya prepared 0.50 liters of a solution by dissolving 2.0 moles of an unknown compound in water. What is the molarity of the solution Maya prepared

Answers

Answer:

4 M

Explanation:

Molarity can be represented by the following ratio:

Molarity = moles / volume (L)

Since you have been given both the mass and volume, you can plug the values into the equation and solve for molarity.

Molarity = moles / volumes

Molarity = 2.0 moles / 0.50 L

Molarity = 4 M

Compared to a solution with a ph value of 7, a solution with a thousand times greater hydronium ion concentration has a ph value of.

Answers

Answer:

pH of 4

Explanation:

Upon comparing a solution with a pH value of 4 and that having a pH of 7, you will realize that it has a pH difference of 3 although the concentration of ions of hydrogen having a pH of 7 is 1000 times greater than being at a pH of 4.

How many grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide?

Answers

10.55 grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide.

What is stoichiometric law?

The laws which deals with the composition of substance by mass or his volume are called the laws of stoichiometry.

The laws of stoichiometry are:

  Law of conservation of mass   Law of definite/constant proportion   Law of multiple proportion   Law of reciprocal proportions   Law of gaseous volume

Reaction:

3CuO + 2NH₃ → N₂ + 3 Cu + 3 H₂O

n(CuO) = m(CuO) / 64 + 16 = 90.4 / 80 = 1.13 mol   (molar mass of CuO = 90.4)

n(NH₃) = m(NH₃) / 14+3 = 18.1 / 17= 1.065mol   (molar mass of NH₃ = 18)

For 1.065 mol of NH3 undergoing the reaction, 3/2  times larger amount of CuO is needed.

CuO is 1.6 mol but it's only 1.13 of it so CuO is a limiting reactant, we must count stoichiometry by amount of this reactant.

n(CuO) = 1.13 mol,

n(N₂) = n(CuO) / 3 = 1.13 / 3 = 0.376 mol

m(N₂) = 0.376 x 28 = 10.55 grams

10.55 grams of nitrogen gas are formed when 18. 1 g of ammonia is reacted with 90. 4 g of copper(ii) oxide.

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Could someone explain this sentence for me ?​

Answers

Answer:

Explanation:

to put this plainly after putting strong electrolytes in water they dissolve to nothing but ions they give you an example and definition of a strong electrolyte I suggest you read those and see if you come up with what I gave you they also tell you that not all strong electrolytes dissolve as strongly as others that are in the example.

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