Enduro solved -4x > 120 by adding 4 to each side of the inequality. What mistake did he make?

Based on the logarithms given, the requirement to use one digit, and the figures to be produced, the right numbers are:

The log of a number gives 1 which is an integer so we can find numbers that when multiplied, produce a number that can be taken a log of. Those numbers are 2 and 4:

= 2 x 4

= 8

Log₈ = 1

Taking the log of a number to a decimal form leads to an irrational number. So, find numbers that when divided, will give a decimal:

= 6/5

= 1.2

Take a log of 7:
log₇ (1.2) will give an irrational number.

The remaining numbers ae 9, 3, and 1.

With the numbers 9,3 and 1, the log to produce a rational number is:
log₉3¹ = log₉9¹/² = 1/2

1/2 is a rational number.

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s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom. This can be obtained the same way of finding algebraic equation using variables ad constants.

From the question it is given that:

From the given statements we can say that sonic booms are created ONLY WHEN the speed of object (s) is greater than the speed of the sound.

This clearly means that sonic booms are produced when s is greater that s

There are three possible situations in the given scenario:

Since we are looking for the true equation of creation of sonic waves,

it would be only the last one (s > 1225 km/hr).

Hence s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom.

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s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom. This can be obtained the same way of finding algebraic equation using variables ad constants.

Find the required inequality:

From the question it is given that:

speed of sound is approximately 1225 km/hr

a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom

From the given statements we can say that sonic booms are created ONLY WHEN the speed of object (s) is greater than the speed of the sound.

This clearly means that sonic booms are produced when s is greater that s

There are three possible situations in the given scenario:

Speed of light can be less than 1225 km/hr ⇒  s < 1225 km/hr ⇒ no sonic boom is created (assumption is wrong)

s = 1225 km/hr  ⇒ no sonic boom is created (assumption is wrong)

s > 1225 km/hr  ⇒ sonic boom is created (assumption is correct)

Since we are looking for the true equation of creation of sonic waves,

it would be only the last one (s > 1225 km/hr).

Hence s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom.

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Answer:

x = 4

Step-by-step explanation:

These triangles are similar by the AA Similarity Postulate.

12 + 4 = 16

(5x - 2)/12 = 6x/16 (3x/8)

Cross multiply: 8(5x - 2) = 12(3x)

40x - 16 = 36x

4x - 16 = 0

4x = 16

x = 4

The linear function which represents the line given by the point-slope equation is (B) [tex]f(x)=\frac{1}{2} x+6[/tex].

To find the linear function which represents the line given by the point-slope equation:

Given: [tex]y-8=\frac{1}{2} (x-4)[/tex]

Distribute the right side:

[tex]y-8=\frac{1}{2} (x)-\frac{1}{2} 4\\y-8=\frac{1}{2} x-2[/tex]

Adds 8 on both sides:

[tex]y=\frac{1}{2}x-2+8\\y=\frac{1}{2}x+6[/tex]

Convert to function notation:

[tex]f(x)=y\\f(x)=\frac{1}{2} x+6[/tex]

Therefore, the linear function which represents the line given by the point-slope equation is (B) [tex]f(x)=\frac{1}{2} x+6[/tex].

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The complete question is given below:

Which linear function represents the line given by the point-slope equation y – 8 = y minus 8 equals start fraction one-half end fraction left-parenthesis x minus 4 right-parenthesis. (x – 4)?

A) F(x) = f(x) equals StartFraction one-half EndFraction x plus 4.X + 4

B) f(x) = f(x) equals StartFraction one-half EndFraction x plus 6.

C) X + 6 f(x) = f(x) equals StartFraction one-half EndFraction x minus 10.X –10

D) f(x) = f(x) equals StartFraction one-half EndFraction x minus 12.X – 12

Answer:

the answer is B

a 3d rectangle slided vertically can produce a 2d rectangle

The p-value that would be given as the evidence would be given as p-value = 0.00002 and also P value = 0.00003

The sample size of the first sample = 100

x1 = success 0f 86%

We have to find the proportion of this = 0.86

The sample size of the second sample n2 = 100

x12 = success 0f 60%

We have to find the proportion of this = 60/100

= 0.6

The difference = 0.86-0.6= 0.26

Next we have to find the pooled proportion. This is taken given as p = (x1+x2)/(n1+n2) this gives us 0.73

Next we have to find the standard error

= √(p*(1-p)*(1/n1+ 1/n2)= 0.06279

Z stat = (0.26-0)/0.0628= 4.1411

From here the p value would have to be

p-value = 0.00002 and also

P value = 0.00003

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The required probability of the coin landing tails up at least two times is 15/16.

Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
In the given question,
let's approach inverse operation,
The probability of all tails  = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
                                                                                     = 1 - 8 / 128
                                                                                     = 120 / 128
                                                                                     = 15 / 16

Thus, the required probability of the coin landing tails up at least two times is 15/16.

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Answer:

D

Step-by-step explanation:

Pq=opp/hyp

(135+12)=180

The difference between the mean times is about 2 times the absolute deviation of the data sets.

Given that the difference of the means is found.

The difference in the means is basically the absolute difference between the mean of two groups. It explains the mean of two groups. It explains how much difference that exists between the average between two groups.Calculating mean difference is significant during clinical trials where we have the experimental group and the control group. The mean absolute deviations is basically the variation of each data value from the mean. It tells us how much the values in a set of data differ from the mean value. It explains the reach of values in a data set. There is a relationship that exists between the difference of the mean absolute deviations.

Hence the difference between the mean times is about 2 times the absolute deviation of the data sets.

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The descriptive statistics for the above data is given as follows:
X = 12.5

A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.

For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]

= 300/24

= 12.5

For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]

= (1/(24-1) (4,900 - (300²/24)

= 50

Standard deviation s = √s²

= √50

= 7.0711

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Answer: 88°

Step-by-step explanation:

We know that the ratio of ∠DCB : ∠ACD is 3:1. In other words, ∠DCB is [tex]\frac{3}{3+1}[/tex], or [tex]\frac{3}{4}[/tex] of the whole angle (i.e., ∠ACB), while ∠ACD is [tex]\frac{1}{4}[/tex] of the whole angle.

To easily find ∠ACB, which is the sum of both angles, we can add up all the angles of [tex]\triangle ABC[/tex] and set it equal to 180°.

[tex]m\angle A + m\angle B + m\angle ACB = 180\\75+53+m\angle ACB=180\\128+m\angle ACB=180\\m\angle ACB=52[/tex]

From here, we can calculate ∠BCD by multiplying the value of ∠ACB by three-fourths.

[tex]m\angle BCD = \frac{3}{4}(m\angle ACB)\\m\angle BCD = \frac{3}{4}(52)\\m\angle BCD = 39[/tex]

Similar to what we did to get the measure of ∠ACB, we can add up all the angles measures of [tex]\triangle DBC[/tex] to get the measure of ∠BDC.

[tex]m\angle B + m\angle BDC + m\angle BCD = 180\\53+m\angle BDC + 39= 180\\92+ m\angle BDC=180\\m\angle BDC = 88[/tex]

The measure of ∠BDC is 88°.

The volume of a solid is  [tex]\frac{26}{3} \pi[/tex].

Given

The given curves about the specified line. y = x + 1, y = 0, x = 0, x = 2; about the x-axis

Curve is y = x + 1

Line is y = 0

We have to find out the volume v of the solid obtained by rotating the region bounded by these curves.

If the region bounded above by the graph of f, below by the x-axis, and on the sides by x=a and x=b is revolved about the x-axis, the volume V of the generated solid is given by [tex]V = \pi \int\limits^b_a {(f(x))^{2} } \, dx[/tex]. We can also obtain solids by revolving curves about the y-axis.

Volume of a solid:

According to washer method:

[tex]V = \pi \int\limits^b_a {(f(x))^{2} } \, dx[/tex]

Using washer method, where a=0 and b=2, we get

V = [tex]\pi \int\limits^2_0 {(x+1)^{2} } \, dx[/tex]

= [tex]\pi[ \frac{(x+1)^{3} }{3} ]0 \ to \ 2[/tex]

= [tex]\pi [\frac{(3+1)^{3} }{3} -\frac{(0+1)^{3} }{3}][/tex]

= [tex]\pi [\frac{27}{3} -\frac{1}{3} ][/tex]

= [tex]\pi [\frac{26}{3}][/tex]

= [tex]\frac{26}{3} \pi[/tex]

Therefore the volume of a solid is  [tex]\frac{26}{3} \pi[/tex].

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Using limits, the correct option regarding the end behavior of the function is given by:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

The end behavior is found calculating the limit of f(x) as x goes to infinity.

For this problem, the equation is given by:

[tex]f(x) = -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108[/tex]

Since x goes to infinity, we consider only the term with the highest exponent, hence the limits are given as follows:

[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow -\infty} -x^6 = -(-\infty)^6 = -\infty[/tex]

[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow \infty} -x^6 = -(\infty)^6 = -\infty[/tex]

Hence the correct option is:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

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The table of values for y=1/2x-1 is completed as follows:

x               y

-2             -2

-1            -3/2

0               -1

1             -1/2

2                0

3              1/2

Exactly one value from the set of second components of the ordered pair is connected with each value from the set of first components of the ordered pairs in a relation known as a function.

Given function:  y=1/2x-1

For x = -2

Value of y = -2

For x = -1

Value of y = 1/2(-1)-1 = -3/2

For x = 0

Value of y = 1/2(0)-1 =-1

For x = 1

Value of y = 1/2(1)-1 = -1/2

For x = 2

Value of y = 0

For x = 3

Value of y = 1/2(3)-1 = 1/2

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The equation of the graph, in slope-intercept form, is: C. y = 2/3x + 6.

The linear equation of a graph in slope-intercept form is expressed as y = mx + b. Where the variable in the equation are as follows:

Considering the graph given, to write the linear equation it represents, find the slope (m) and the y-intercept (b) of the line.

Slope (m) = rise/run = 2 units/3 units

Slope (m) = 2/3.

The line intercepts the y-axis at y = 6, thus, the y-intercept (b) would be 6. b = 6.

Substitute m = 2/3 and b = 6 into the slope-intercept form equation, y = mx + b:

y = 2/3x + 6

Thus, the equation, in slope-intercept form, that represents the linear graph as shown in the image given is: C. y = 2/3x + 6.

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The rate of change in the plant's height in terms of inches per week will be 1 2/3 inches.

Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable.

The calculation for the rate of change is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.

The change in y (y being the height of the plant) over 4 weeks was 6 2/3 inches and there are four weeks. Therefore, the average height will be:

= 6 2/3 ÷ 4

= 1 2/3 inches

The average rate of change of the plant growth per week was 1 2/3 inches.  

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Complete question:

Alan's bamboo plant adds some flair to his apartment. In four weeks, Alan has trimmed a total of 6 2/3 inches off the top of the plant. What is the rate of change in the plant's height in terms of inches per week? Ignore the growth rate of the plant.

a.+1 2/3B)-1 2/3C)+3/5D)-5/2

Answer:

336

Step-by-step explanation:

They can place 1 of 8 frags on the bottom.

Now they have 7 flags left.

They can place 1 of 7 flags in the middle.

Now they have 6 flags left.

The can place 1 of 6 flags on top.

8 × 7 × 6 = 336

The term that is not possible in the domain of a sequence is:

-5

The domain of a function is the set that contains all possible input values for the function. For a sequence, the domain is the set that contains all the indexed of the terms, starting at 0 and going until the nth term.

For example, suppose we have the following sequence: 3, 5, 7, ...

From what was explained above, which also can be visualized with the example, an index term of a sequence cannot be negative, hence the term that is not possible in the domain of a sequence is:

-5.

Which is the only negative number of the options.

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In the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).

In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.

The side opposite to angle J is KL, which has a value of 3 units.

The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.

Thus, sin J can be calculated as:

sin J = KL/JK = 3/7.8 = 5/13 = 0.39.

Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

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Answer:

  68 miles

Step-by-step explanation:

The total distance can be determined from the fractions.

Let d represent the total distance of the race.

The distance running is 1/2d. The distance swimming is 1/4d. The remaining distance is 17 miles.

  Remaining = total distance - distance running - distance swimming

  17 mi = d -1/2d -1/4d = 1/4d . . . . . . . . use known fractions

  68 mi = d . . . . . . . multiply by 4

The total distance of the race is 68 miles.

__

Additional comment

This would be a very difficult race. A typical "iron man" race has a swimming distance under 2.5 miles, less than 1/10 of the distance running. The biking distance is typically about 4 times the running distance of "only" 26 miles. An iron man race can take about 17 hours to complete.

This race has a 17-mile swimming segment, which would take a fast swimmer on the order of 8 hours, by itself. (This is 2.7 times the length of a "marathon" swim.) Here, the running distance is 34 miles, about 30% longer than a marathon.

The critical value is the z-score right at the edge of the rejection region option (A) is correct.

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

It is given that:

The z-score is right at the edge of the rejection region.

As we know, the rejection zone is the area in which we have sufficient data to reject the null hypothesis if our test statistic falls within it.

Thus, the critical value is the z-score right at the edge of the rejection region option (A) is correct.

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we are given x here, so we already know that our first coordinate is equal to -2.

in order to find the next coordinate, we have to substitute x for -2 in the y=mx+b equation.

the equation is

[tex]y = \frac{2}{3} x + 23[/tex]

so in substituting x for -2 we get

[tex]y = \frac{2}{3} ( - 2) + 23[/tex]

all we need to do is multiply ⅔ by -2, which gives us -1,3333.

we now have

[tex]y = - 1.3333 + 3[/tex]

so we add them together and get :

[tex]y = 1.666666[/tex]

hope this helps!!<3

Answer:

The second answer is correct.

Step-by-step explanation:

Answer:

23 is the answer

[tex]y = mx + n[/tex]

[tex]m = \frac{y - y}{x - x} = \frac{5 - ( - 1)}{ - 5 - ( - 3)} = \frac{6}{ - 2} = - 3[/tex]

[tex]y = - 3x + n \\ [/tex]

[tex]5 = - 3( - 5) + n \\ n = 5 - 15 = - 10[/tex]

[tex]y = - 3x - 10[/tex]

Answer:

Jamie is currently 15.

Step-by-step explanation:

The correct option is the thrid one, the first step is

-x+5= 6x-2

Here we have the system of equations:

y = -x + 5

y = 6x - 2

Now, the variable "y" should represent the same thing in both equations, then we can write:

-x + 5 = y = 6x - 2

If we remove the middle part, we get the equation that only depends on x:

-x + 5 = 6x - 2

This is the first step that we should use to solve the system of equations, which is the one in option 3.

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The first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.

In this question,

A sequence is a set of things (usually numbers) that are in order. A partial sum is the sum of part of the sequence.

The sequence is [tex]a_{n} =log(n^{n}+1 )[/tex]

The first four partial sum S₁, S₂, S₃, S₄ can be calculated by substituting n = 1,2,3,4 in the sequence.

S₁ can be calculated as

S₁ = a₁

⇒ [tex]a_{1} =log(1^{1}+1 )[/tex]

⇒ [tex]a_{1} =log(1+1 )[/tex]

⇒ [tex]a_{1} =log(2 )[/tex]

⇒ [tex]a_{1} =0.3010[/tex]

Now, S₁ = 0.3010

S₂ can be calculated as

S₂ = a₁ + a₂

⇒ [tex]a_{2} =log(2^{2}+1 )[/tex]

⇒ [tex]a_{2} =log(4+1 )[/tex]

⇒ [tex]a_{2} =log(5 )[/tex]

⇒ [tex]a_{2} =0.6989[/tex]

Now, S₂ = 0.3010 + 0.6989

⇒ S₂ = 0.9999

S₃ can be calculated as

S₃ = a₁ + a₂ + a₃

⇒ [tex]a_{3} =log(3^{3}+1 )[/tex]

⇒ [tex]a_{3} =log(27+1 )[/tex]

⇒ [tex]a_{3} =log(28)[/tex]

⇒ [tex]a_{3} =1.4471[/tex]

Now, S₃ = 0.3010 + 0.6989 + 1.4471

⇒ S₃ = 2.447

S₄ can be calculated as

S₄ = a₁ + a₂ + a₃ + a₄

⇒ [tex]a_{4} =log(4^{4}+1 )[/tex]

⇒ [tex]a_{4} =log(256+1 )[/tex]

⇒ [tex]a_{4} =log(257 )[/tex]

⇒ [tex]a_{4} =2.4099[/tex]

Now, S₄ = 0.3010 + 0.6989 + 1.4471 + 2.4099

⇒ S₄ = 4.8569

Hence we can conclude that the first four partial sums of the sequence are S₁ = 0.3010, S₂ = 0.9999, S₃ = 2.447, S₄ = 4.8569.

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Answer:

[tex]\textsf{A. } y=3x^2+10x-8[/tex]

Step-by-step explanation:

We are given the information that a function has zeros at x = ⅔ and x = -4. In order to find the function that has those zeros, we can substitute the value of the zeros into each function. If the value of a function equates to zero with both values, then that is the function we are looking for.

..................................................................................................................................................

Standard Form of a Quadratic: ax² + bx + c = 0.

..................................................................................................................................................

[tex]\large \text{$y = 3x^2+10x-8 \implies 0=3x^2+10x-8$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{24}{3}-8\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2+10(-4)-8\\\\\implies 0=3(16)-40-8\\\\\implies 0=48-48\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]

..................................................................................................................................................

[tex]\large \text{$y = 2x^2-5x-12 \implies 0=2x^2-5x-12$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2-5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=2\left(\dfrac{4}{9}\right)-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}-\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=-\dfrac{22}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{130}{9}\ \textsf{X}\end {minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2-5(-4)-12\\\\\implies 0=2(16)+20-12\\\\\implies 0=32+20-12\\\\\implies 0=40\ \textsf{X}\end{minipage}}[/tex]

..................................................................................................................................................

[tex]\large \text{$y = 2x^2+5x-12 \implies 0=2x^2+5x-12$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2+5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}+\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=\dfrac{38}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{70}{9}\ \textsf{X}\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2+5(-4)-12\\\\\implies 0=2(16)-20-12\\\\\implies 0=32-32\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]

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[tex]\large \text{$y = 3x^2-10x-8 \implies 0=3x^2-10x-8$}[/tex]

[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2-10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)-\dfrac{20}{3}-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)-\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}-\dfrac{20}{3}-\dfrac{8\times3}{3}\\\\\implies 0=-\dfrac{16}{3}-\dfrac{24}{3}\\\\\implies 0=-\dfrac{40}{3}\ \textsf{X}\end{minipage}}[/tex]    [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2-10(-4)-8\\\\\implies 0=3(16)+40-8\\\\\implies 0=48+40-8\\\\\implies 0=80\ \textsf{X}\end{minipage}}[/tex]

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Therefore, the function whose zeros are ⅔ and -4 is [tex]y=3x^2+10x-8[/tex].