During the process of heat transfer, the heat transferred to or from a system's surroundings is always?

Answers

Answer 1

Answer:

During the process of heat transfer, the heat transferred to or from a system's surroundings is always equal in magnitude to the heat transferred to or from the system, but opposite in sign.

What is the 1st law of thermodynamics?

The total energy of an isolated system is said to stay constant according to the first rule of thermodynamics. Energy cannot be generated or destroyed, but it may be transformed from one form into another inside a closed system, which is known as the conservation of energy.

This rule states that when a system is exposed to a certain amount of heat, the amount of heat that the system absorbs is equal to the product of the increase in internal energy (change in internal energy) of the system and the external work that the system does. The relationship between a system's internal energy and work output and the heat given to it is demonstrated by the first law of thermodynamics. This equation provides the foundation for the majority of practical innovations like heat engines, freezers, and air conditioners.

The equation for the first law of thermodynamics is given as; ΔU = q + W

Where,

ΔU = change in internal energy of the system.q = algebraic sum of heat transfer between system and surroundings.W = work interaction of the system with its surroundings.

The heat transported to or from a system's surroundings during the process of heat transfer is always opposite in sign, but equal in size, to the heat transferred to or from the system.

What is heat transfer?

       The flow of thermal energy between physical systems is known as heat transfer. The temperatures of the systems and the characteristics of the medium used to transmit the heat affect how quickly it transfers. Conduction, convection, and radiation are the three basic ways that heat is transferred. It is crucial to employ heat transfer, or the movement of energy in the form of heat, in applications of the First Law of Thermodynamics since it is a mechanism through which a system changes its internal energy. Diffusion and conduction are two different concepts. Diffusion linked to fluid mixing is not the same as conduction.

    The Second Law of Thermodynamics controls the direction of heat transmission, which is from one area of high temperature to another area of lower temperature. The internal energy of the systems from and to which the energy is transmitted is altered during heat transfer. Heat transfer will take place in a way that makes the group of systems' entropy higher.

   In physics, heat is described as the flow of thermal energy over a boundary that is clearly defined surrounding a thermodynamic system. The amount of work that a thermodynamic system may accomplish is known as the thermodynamic free energy. Enthalpy is a thermodynamic potential with the letter "H" that is made up of the system's internal energy (U) plus the volumetric product of pressure (P) and temperature (T) (V). A joule is a unit used to measure energy, effort, or heat production.

  The quantity of heat transmitted in a thermodynamic process that modifies a system's state relies on how that process happens, not just the net difference between the process' beginning and ending states, since heat transfer is a process function (or route function), as opposed to a function of state.

 The heat transfer coefficient, which represents the relationship between the heat flux and the thermodynamic force that drives the flow of heat, is used to determine both thermodynamic and mechanical heat transfer. A quantitative, vectorial description of the movement of heat through a surface is called a heat flux.

     The term "heat" is sometimes used interchangeably with "thermal energy" in technical applications. This usage derives from the historical understanding of heat as a fluid (caloric) that may be transported by a variety of reasons, which is also prevalent in laypeople's language and daily life.

Thank you,

Eddie


Related Questions

How many grams are in 0. 743 mol of al?

Answers

There are 20.046 grams in 0.743 moles of Al.

Mole is the SI unit of measurement of the matter present inside any substance or element. It is denoted by the 'n'.

The formula of finding mole is

n = mass / molar mass

According to the question, to find the mass of Al the formula can be rewritten as mass = moles × molar mass.

Molar mass of Al = 26.98 g/mol.

Moles of Al = 0.743 moles

Therefore, mass of Al = 0.743 moles × 26.98 g/moles

Hence, mass = 20.046 grams

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In a combustion chamber, ethane (c2h6) is burned at a rate of 9 kg/h with air that enters the combustion chamber at a rate of 176 kg/h. determine the percentage of excess air used during this process

Answers

The percentage of excess air used during combustion process of ethane will be 37 %.

Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.

Calculation of percentage of air .

[tex]C_{2} H_{6} + (1-x)+a(O_{2} +3.76N_{2} )=bCO_{2} + cH_{2} O + axO_{2} + 3.76dN_{2} .[/tex]

Mair=Mair/Rin

[tex]( MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex]÷ [tex](MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex] +[tex](MN)C_{2} H_{6} .[/tex]

33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1

= 176/176+8

X= 0.37

0.37 × 100

X= 37%

Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.

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8.0 liters I2 forms at STP. How many moles of KI were required for the reaction?

Answers

Answer:

0.71 moles KI

Explanation:

At STP, there should be 1.0 moles at 22.4 L. However, there are only 8.0 L of I₂. Therefore, we must set up a proportion to find the correct moles of I₂.

[tex]\frac{1 mole}{22.4 L} =\frac{? moles}{8.0 L}[/tex]                                <----- Proportion

[tex]8.0 = 22.4(? moles)[/tex]                         <----- Cross multiply

[tex]0.36 = ? moles[/tex]                                 <----- Divide both sides by 22.4

To find the moles of KI, you can use the mole-to-mole ratio from the balanced equation coefficients. The final answer should have 2 sig figs.

2 KI(aq) + Cl₂(g) ---> 2KCl(aq) + 1 I₂(g)
^                                                   ^

0.36 moles I₂          2 moles KI
----------------------  x  --------------------  =  0.71 moles KI
                                   1 mole I₂

Answer: 0.71 moles KI

Explanation:

Draw the mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute hcl

Answers

The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.

What is Proton Transfer ?

In the first step oxygen donates its lone pair of electron to hydrogen of HCl. There is removal of water molecule from the substance α-d-glucose.

What is Nucleophilic Substitution ?

The organic reaction where one nucleophile replaces another is called nucleophilic substitution reaction. These reaction takes place in aromatic compounds, acyl compounds and aliphatic compounds. SN¹ reactions are nucleophilic substitution reaction.

Thus from the above conclusion we can say that The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.

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The process where a substance goes directly from a solid state to a gaseous form is known as:____.

Answers

Answer:

sublimation because it's has changed from solid to gaseous

A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.

Answers

Molarity of the solution is 0.0527 M.

What is Molarity?

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

Calculation of Molarity of the solution

Assume there is 1 kg of solvent present in the beginning.

Thus, the mole of solute is 0.0480 moles of LiF.

Molar mass of LiF = 25.939 grams/mole

0.0480 mol LiF x 25.939 g/1 mol LiF = 1.245 g LiF

Mass of the solution = 1001.245 g

The molarity of the solution can be determined as illustrated using the supplied density and moles of solute.

[LiF] = mol LiF/ volume of solution

[LiF] = 0.0480 mol/1001.245 g x 1ml/1.10g x 1L/1000mL

Hence, the molarity of LiF = 0.0527 M

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What is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided?

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Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

What is Empirical Formula ?

The Empirical formula is the simplest whole number ratio of atoms present in given compound.

What is Molecular formula of Compound ?

Molecular Formula = Empirical Formula × n

n =  [tex]\frac{\text{Molar Mass}}{\text{Empirical Formula weight}}[/tex]

Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

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the graph below shows a reaction with a catalyst. How did the addition of the cataalyst change the graph

Answers

Answer:

Section 2 will decrease.

Explanation:

A catalyst is a substance that increases the rate of the chemical reaction without taking part in the overall reaction. Catalysts speed up a reaction by lowering the activation energy needed for a reaction to take place. The activation energy is the minimum energy necessary for a reaction to take place. As such, when a catalyst is added, the activation energy (or the potential energy) needed to start the reaction decreases. This shows itself in the graph by decreasing the "hump" in Section 2.

It should be noted that Sections 1 and 3 will remain the same. This is because the energy of the reactants and products does not change regardless of a catalyst being present.

CH3OH ___ ions in an aqueous solution. A) forms B) does not form​

Answers

CH3OH doesn't form ions in an aqueous solution.

Water and one or more dissolved substances make up aqueous solutions. In an aqueous solution, solids, gases, or other liquids may dissolve. Examples of watery solutions include coke, seawater, rain, acid, base, and salt solutions. A solution that is not an aqueous solution is any liquid that does not contain water.

Solutions that contain water as the solvent are known as aqueous solutions. Water is a great solvent, but not everything will easily dissolve in it. The term "aqueous" in a chemical equation designates a material in water. For instance, adding sodium hydroxide solution to diluted hydrochloric acid results in the production of sodium chloride.

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Ulfuric acid is found in some types of batteries. What volume of 3.50 m h2so4 is required to prepare 250.0 ml of 1.25 m h2so4?

Answers

The volume sulfuric acid will be 89.3mL.

Volume will be determined by the molarity relation. The quantity of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a component per liter of a solution would be known as molarity. The molar concentration of any solution would be another name for molarity.

The volume can be calculated by using molarity formula:

[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]

Given data:

[tex]M_{1}[/tex] = 3.50 m

[tex]M_{2}[/tex] =  1.25 m

[tex]V_{1}[/tex]= 250.0 ml

Put the value of given data in above formula:

[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]

( 3.50 m) ( 250 mL) = ( 1.25 m) [tex]V_{2}[/tex]

[tex]V_{2}[/tex] = 89.3mL

Therefore, the volume sulfuric acid will be 89.3mL.

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When an electron in a quantum system drops from a higher energy level to a lower one, the system __

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When an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

The energy of the electron drops when it transitions levels, as well as the atom releases photons. The emission of the photon occurs as the electron transitions from an energy state to a lower state. The photon energy represents precisely the energy that would be lost when an electron moves to a level with less energy.

When such an excited electron transitions from one energy level to another, this could emit a photon. The energy drop would be equivalent to the power of the photon that is released. In electron volts, the energy of an electron, as well as its associated photon (emitted or absorbed) has been stated.

Therefore, when an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

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If a buffer is composed of 34. 63 ml of 0. 139 m acetic acid and 36. 50 ml of 0. 182 m sodium acetate, how many ml of 0. 100 m hcl can be added before the buffer capacity is reached?

Answers

The volume is the product of the molar concentration and the moles of the substance. The volume of hydrochloric acid that can be added to the buffer is 0.066 L.

What is a buffer?

A buffer is a constant solution with a proton or hydrogen ion concentration with an acid, base, or salt dissolved in them.

The chemical reaction between hydrochloric acid and sodium acetate is given as,

HCl + CH₃Coo-Na → CH₃CooH + NaCl

From above the initials moles of acetic acid are given as,

Moles = molarity × volume

= 0.139 M × 0.0346 L

=  0.0048 moles

The initials moles of sodium acetate are given as,

M = 0.182 M × 0.0365 L

= 0.0066 moles

As it is known that the ratio of the buffer capacity is 10 for sodium acetate and acetic acid so,

Moles sodium acetate ÷ Moles Acetic acid = 10

(0.0066 moles + X) ÷ (0.0048 moles - X)  = 10

Here, X is the moles of HCl and is calculated as,

0.0066 moles + X = 0.048 moles - 10X

11 X = 0.048 ÷ 0.0066

11 X = 7.27

X = 0.66 moles  

The volume of 0.100 HCl with 0.66 moles is:

Volume = moles × molarity

= 0.100 × 0.66

= 0.066 L

Therefore, 0.066 L of 0.100 M HCl is required to reach the buffer capacity.

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Place the following in order of increasing dipole moment. I. Bcl3 ii. Bif2 iii. Bclf2.

Answers

The correct order of increasing dipole moment is BCl3 < BIF2 < BClF2.

What is dipole moment?

The mathematical product of the separation of the ends of a dipole and the magnitude of the charges.More is the electronegativity of an atom more it will have pull of electrons towards itself. For example, in BCl3 electrons will be pulled towards chlorine atom as it is more electronegative than boron.Hence, the dipole moment is cancelled out. So, it will have zero dipole moment. In BIF2 and BClF2 , fluorine is more electronegative in nature and it is present in both the molecules.But chlorine is more electronegative that iodine atom. So, the dipole moment of BClF2 is more than the dipole moment of BIF2.

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Compared with the energy it takes to separate oxygen and hydrogen from water, how much energy is released when they recombine?.

Answers

The same amount of energy released when they recombine

Yes, the energy required to separate water into O2 and H2 is at least equal to the energy released when these gases come together to form water.

What is the process for separating water into it's constituents ?

The process of separating water into hydrogen and oxygen is known as electrolysis. This reaction occurs in a device known as an electrolyzer.

This is around 260 kJ per mole of water, or just under 5 eV per water molecule (4 electrons times 1.23 V). One litre of water would require at least 16 MJ (4.4 kWh) in order to be split, which is more energy than would be required to send one litre of water into deep space.

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Identify the classification of milk. group of answer choices aerosol solid aerosol foam emulsion solid emulsion

Answers

Milk is an example of solid emulsion. Hence, option D is correct.

What is emulsion?

An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.

Emulsion consist of a dispersion of two liquids that are immiscible with each other.

One of the liquids act as the dispersion medium and the other will act as the dispersed phase.

Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.

Types of Emulsion:

Oil in water (O/W)In this type of emulsion, the oil will be the dispersed phase and water will be the dispersion medium. Example of o/w emulsion is milk.

    2. Water in oil (W/O)

In this type, water will be the dispersed phase and oil will be the dispersion medium. Margarine is an example of water in oil emulsion.

Milk is an example of solid emulsion. Hence, option D is correct.

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Compute the theoretical density of zns given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively? The atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol.

Answers

Density of ZnS given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively if the atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol. is 4.1109 g/cm³

For density In the crystal structure, we determine the angle's value for one set of ZnS bonds. θ θ + ∅ + 90° = 180° θ = 90° - ∅ θ = 90° - (109.5° / 2) After determining that = 35.25°, we derive the value of x from the geometry: distance angle d = 0.234 x = dsin = 0.234 sin35.25°) = 0.135 nm = 0.135 107 cm; following this, we get the length of the unit cell: a = 4x a = 4(0.135) a = 0.54 nm = 0.54 107 cm; and The formula for n' is (number of corner atoms in unit ell contribution of each corner atom in unit cell) + (number of face center atoms in unit cell contribution of each face center atom in unit cell). n' = 8 × 1/8) + (6 × 1/2) = 1 + 3 = 4

Density = P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)] = 389.88 / 94.84 = 4.1109 g/cm³

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What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of
hydrogen gas when confined in a volume of 15.0 liters at 13°C.

Answers

The pressure of the gas is obtained as 48 atm.

What is the total pressure?

Now we know that;

Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles

Number of moles of H2 =  56.0 grams/2 g/mol = 28 moles

Total number of moles present = 3 moles + 28 moles = 31 moles

Using;

PV =nRT

P = total pressure

V = total volume

n = total number of moles

R = gas constant

T = temperature

P = nRT/V

P = 31 * 0.082 * 286/15

P = 48 atm

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An aqueous solution of hso−3 is created at 25∘c. is the solution acidic, basic, or neutral?

Answers

An aqueous solution of hso−3 is created at 25∘c. is the solution basic in nature.

An aqueous solution is a solution wherein the solvent is water. Its miles are primarily shown in chemical equations by appending them to the relevant chemical formula.

An aqueous solution is a water that carries one or more dissolved materials. The dissolved substances in an aqueous answer can be solids, gases, or different beverages.

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At 25°C, an aqueous solution of hso3 is formed. This is the solution basic in nature.

Aqueous solutions are those in which the solvent is water. Its miles are often represented in chemical equations by attaching them to the appropriate chemical formula.

An aqueous solution is a mixture of water and one or more dissolved components. Solids, gases, or various beverages can be dissolved in an aqueous solution.

Aqueous solutions contain liquid water as the solvent. Solute (dissolved) ions and molecules are surrounded by water molecules and absorbed into the water's network of bonds. After then, the dissolved species diffused throughout the water.

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The iodine test is used to test for the presence of starch which is a type of ___________ treated with an iodine solution, the starch reacts with the iodine solution and produces a ___________ color.

A. protein, blue-purple
B. protein, yellow
C. carbohydrate, yellow
D carbohydrate, blue-purple
When

Answers

Answer:

D. carbohydrate, blue-purple

Explanation:

Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.

When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.

16. If the velocity of hydrogen molecule is 5 x 10^4cm sec-¹, then its de Broglie wavelength is
(1)2 A
(2) 4 A
(3)8 A
(4) 100 A

Answers

Answer:

Correct option is B)

According to de-Broglie, 

λ=mvh=6.023×10232×5×104cm/sec6.62×10−27ergsec=4×10−8cm=4Ao

Write the formula for: strontium carbonate

Answers

SrCO3

Sr=2 charge
CO3=2 charge from polyatomic chart

What is chemical energy and how does it work ?
ty in advance ​

Answers

Answer:

Chemical energy is defined as. the energy which is stored in the bonds of chemical compounds (molecules and atoms).

Explanation:

Chemical energy may be released during a chemical reaction

Answer:

Chemical energy is the energy stored in the chemical bonds of Compound.

It's used during chemical Reactions.

Explain how the rate of diffusion of a gas is related to its molar mass.
carbon dioxide gas (co2) effuses 3.2 times faster than an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.

Answers

The molar mass of the other gas is 450.56 g.

Calculation:

Relation between rate of diffusion and molar mass of two gases is given by:

r₁/r₂ = (√m₂)/(√m₁)

Given,

r₁ = 3.2r₂                          

(r₁ is the diffusion rate of CO₂ and r₂ is the diffusion rate of the other gas)

We know

m₁ = molar mass of CO₂ = 44 g

To find,

m₂ = molar mass of the other gas =?

Put the values in the above equation,

r₁/r₂ = (√m₂)/(√m₁)

3.2r₂/r₂ = (√m₂)/(√44)

3.2 = (√m₂)/(√44)

Squaring both the sides,

10.24 = m₂/44

m₂ = 10.24 (44)

m₂ = 450.56 g

Hence, the molar mass of the other gas is 450.56 g.

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How many moles of iron iii oxide can be prepared from 6 moles of oxygen?

Answers

Answer:

6molO2 3/2O22Fe=4,5024molFe .

Explanation:

You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.

2Fe(s)+3/2O2(g) Fe2O3(s)

If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.

Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.

6molO2 3/2O22Fe=4.5024molFe .

These coefficients can be used as conversion factors when it comes to substance moles.

Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.

But, just for the argument, let’s rebalance the equation for integer coefficients only.

4Fe(s)+3O2(g) 2Fe2O3(s)

We are now using the coefficients as conversion factors, as we have done before.

If 30. 0 ml of 0. 150 m CaCl2 is added to 15. 0 ml of 0. 100 m AgNo3, what is the mass in grams of AgCl precipitate?

Answers

The mass of AgCl precipitated is 0.215g.

What do you mean by  precipitation?

Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.

To calculate mass of AgCl precipitate -

The first step is to make a balanced chemical equation.

2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2

Molecular Weights:

CaCl2 = 110.98 g/mol

AgNO3 =170.01g/mol

AgCl= 143.45 g/mol

Volume:

CaCl2: 30.0mL=0.03L

AgNO3: 15.0mL=0.015 L

mole  CaCl2 = 30/1000 x 0.2 =0.006

mole  AgNO3 =15/1000 x 0.1 = 0.0015

CaCl2 is in excess so 0.0015 mole AgCl  will form

0.0015 x 143.5 = 0.215g

The 0.215 mass in grams of AgCl will precipitate.

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Which of the given ions have the same ground state electron configuration: s2-, n3-, mg2 , and br-? a. s2-, n3-, mg2 , and br- b. s2-, n3-, and br- c. n3- and mg2 d. s2- and br- e. mg2 and br-

Answers

N3- and Mg2 ions have the same ground-state electron configuration.

Ground-state electron configuration:

Understanding molecule bonding, characteristics, and structures begin with understanding ground state electron configurations. The ground state electron configuration provides insight into a wide range of atomic properties, including the electrons in an atom, distinct orbitals, and hybridization.

The ground state of an atom's electrons is the lowest energy state that is feasible for that atom since, throughout the cosmos, a system's natural state is to use the least amount of energy.

Aufbau-Principle: If you have a lot of luggage, you'll probably choose the room that is closest to the ground floor in a hotel without an elevator. The Aufbau principle demonstrates the identical behavior of electrons in the ground state. According to the Aufbau principle, electrons first occupy lower energy orbitals before moving on to higher energy orbitals.

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What type of interaction occurs between the r groups of valine and isoleucine in a tertiary structure? hydrogen bond salt bridge disulfide bridge hydrophobic interaction

Answers

The type of interaction occurs between the r groups of valine and isoleucine in a tertiary structure will be "hydrophobic interaction".

The only factor responsible for the hydrophobic attraction connecting molecules or particles submerged in water would be the AB free energy of cohesiveness between both the water molecules. Regardless of whether the molecules as well as, particles are submerged in water or not, this interaction always exists.

The entire three-dimensional configuration of a protein's polypeptide chain in space is referred to as the protein's tertiary structure. It is typically stabilized through interactions between the side chains of nonpolar amino acids with externally polar hydrophilic hydrogen as well as ionic bonds.

Therefore, the type of interaction occurs between the r groups of valine and isoleucine in a tertiary structure will be "hydrophobic interaction".

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what is metallic conductivity ?

Answers

Explanation:

metallic conduction:the movement of electrons through a metal, with no changes in the metal and no movement of the metal atoms.

I hope this help uuhh............

A gas sample at stp contains 1. 20 g oxygen and 1. 43 g nitrogen. what is the volume of the gas sample?

Answers

The volume of the gas sample will be 1.79 L.

A liquid, solid, or gas's volume represents the amount of three-dimensional space it occupies. Although there are many additional units that can be used to indicate volume, the most used ones are liters, cubic meters, gallons, milliliters, teaspoons, as well as ounces.

Given data :

Mass of [tex]O_{2}[/tex] = 1.20 g

Mass of [tex]N_{2}[/tex] = 1.43 g

Number of moles can be calculated by suing the formula:

Number of moles of [tex]O_{2}[/tex] = Mass / molar mass = 1.20 / 32 = 0.03 mol

Number of moles of [tex]N_{2}[/tex] =  Mass / molar mass  = 1.43 / 28 = 0.05 mol

So, the total count of moles can be calculated by :

Total moles = moles of [tex]O_{2}[/tex]  +  moles of [tex]N_{2}[/tex]

Total moles = 0.03  + 0.05 = 0.08 mol

The volume of the gas at STP can be calculated as:

Volume = 0.08 mol × 22.4 mol/L

Volume = 1.79 L

Therefore, the volume of the gas sample will be 1.79 L.

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When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about ____ above the nail wraps.

Answers

When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about fully covered above the nail wraps.

What is nail wraps?

Nail wraps, often known as nail paint strips, are nail improvements with printed patterns, glitter, or solid colors. Without the use of glue, they are attached to the nail in a flexible strip. There may be 12 to 22 various sized strips per box, depending on the manufacturer, which takes into account the range in size of each person's fingernail.

Nail wraps have a long history that dates back to the 1980s. The popularity of nail polish and the rise in salon visits gave rise to the demand for a better at-home manicure. Although several companies produced nail wraps and polish strips, it wasn't until the 2000s that they truly started to catch popularity. Since then, their appeal has increased.

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