Do companies that provide mobile wifi hotspots see your history?

Answer:

Step-by-step explanation:

If they all exist in proportion to one another (READ: ratio) then multiplying each of the angles by the same number (here, some unknown "x" value) will maintain the proportionality. Since all the angles of a quadrilateral have to add up to equal 360, then

2x + 4x + 5x + 7x = 360 and

18x = 360. Divide both sides by 18 to get that

x = 20. That means that

2x = 2(20) = 40 and

4x = 4(20) = 80 and

5x = 5(20) = 100 and

7x = 7(20) = 140. Adding all of those up:

40 + 80 + 100 + 140 = 360

Answer:

40,80,100,140

Step-by-step explanation:

Let the ratio 2:4:5:7 angles be 2x, 4x, 5x, 7x

Now

2x + 4x + 5x + 7x=360 degrees

18x = 360 degrees

x =360/18

x=20

2x=2 *20=40

4x=4 *20=80

5x=5 *20=100

7x=7* 20=140

Answer: 48 doghouses

Step-by-step explanation:

We will look at the details given, then we will perform the necessary operations to solve the problem.

     16 bundles of plywood * 12 sheets in a bundle = 192 sheets

     192 total sheets / 4 sheets to build a dog house = 48 doghouses

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Answer:

45.7 kilometers = 45,700 meters

Explanation:

Hi!
Okay, so basically, in one kilometer, there are 1000 meters.
Using this problem, all you have to do is multiply 45.7 by 1000, which is 45,700.

Whatever value is used for kilometers (ex. 2), just multiply by 1000, and you’ll get the value as meters (ex. 2 x 1000 = 2000 meters).

Hope this helps!

To convert kilometers to meters, multiply the kilometer value by 1000 meters which is equal to 1 km.

Convert 45.7 kilometers to meters:

               [tex]\boldsymbol{\sf{Therefore \ \ \longmapsto \ \ 45.7\not{km}*\left(\dfrac{1000 \ m}{1\not{km}}\right)=45700 \ m }}[/tex]

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Answer:

50/20

Step-by-step explanation:

Rate of money raised raises per jump is  

                          money raised / jumps

                                       $50/ 20 jumps

We can think that if we divide the $50 into 20 equal parts,

each part will represent 1 jump and will have 50/20 = $2.5  per 1 jump.

(i) The exponential growth model to predict the number of rabbits after 'x' years is [tex]A = 2e^{6.21460809842x}[/tex].

(ii) The number of rabbits at the end of 3 years will be 250000000.

A continuous exponential growth function is of the form [tex]A = Pe^{rt}[/tex], where A is the final amount, which was initially P, growing continuously at the rate of r, after a time of t years.

In the question, we are asked to construct an exponential model to predict the number of rabbits after 'x' years.

We assume the exponential growth model to be a continuous model, of the form [tex]A = Pe^{rt}[/tex], where A is the final amount of rabbits, which was initially P, growing continuously at the rate of r, after a time of t years.

The initial quantity of rabbits, P = 2.

Time, t = x years.

Substituting the values, we get:

[tex]A = 2e^{rx}[/tex] ... (i)

We have been told that after 1 year, the number of rabbits was 1000.

Thus, substituting A = 1000, and x = 1, we get:

[tex]1000 = 2e^{r*1}\\\Rightarrow 1000 = 2e^r\\\Rightarrow e^r = 1000/2 = 500[/tex]

Taking log on both sides, we get:

[tex]log_ee^r = log_e500\\\Rightarrow rlog_ee = log_e500\\\Rightarrow r = 6.21460809842[/tex]

Thus, the rate of growth, r = 6.21460809842.

Substituting r = 6.21460809842 in (i), we get:

[tex]A = 2e^{6.21460809842x}[/tex], which is the required model.

To find the number of rabbits at the end of 3 years, we put x = 3, in the above equation to get:

[tex]A = 2e^{6.21460809842*3}\\\Rightarrow A = 2e^{18.6438242953}\\\Rightarrow A = 2*125000000\\\Rightarrow A =250000000[/tex]

Thus, there would be 250000000 rabbits at the end of 3 years.

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Answer:

x = 6

Step-by-step explanation:

Answer:

■ Sales tax: $52.75

■ Cost/Price before ST: $540.99

■ Total Cost/Price including ST: $593.74

Step-by-step explanation:

540.99 x 0.0975

= 52.75

Total

= 540.99+52.75

=593.74

Answer: d

Step-by-step explanation:

The graph is increasing, so the base must be more than 1.

Also, the y-intercept is 2.

This leaves d.

The spread of the disease will take a time 100 days to reach 2,500 infected people.

In this problem we have a radical equation that represents the number of infected people as a function of time, we are suppose to find the time when that number will be 2,500 by algebra properties: (N = 2,500)

2,500 = 250 · √t

√t = 2,500 / 250

√t = 10

t = 10²

t = 100

The spread of the disease will take a time 100 days to reach 2,500 infected people.

The statement is poorly formatted and presents typing mistakes, correct form is shown below:

The spread of a disease can be modeled as N(t) = 250 · √t, where N is the number of infected people, and t is time (in days). How long will it take until the number of infected people reaches 2,500?

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Answer: 8/50 = 16%

Step-by-step explanation:

The number with the given properties is 17

Let the tens be x and the units be y.

So, the number is 10x + y

The relationship between the digits is

[tex]y = x + 6[/tex]

The relationship between the number and the reverse is

[tex]2(10x + y + 10y + x) = 6 + 10 * (10x + y)[/tex]

Simplify the second equation

[tex]2(11x + 11y) = 6 + 100x + 10y[/tex]

Open the brackets

[tex]22x + 22y = 6 + 100x + 10y[/tex]

Substitute y = x + 6

[tex]22x + 22(x + 6) = 6 + 100x + 10(x + 6)[/tex]

Expand

[tex]22x + 22x + 132 = 6 + 100x + 10x + 60[/tex]

Collect like terms

[tex]22x + 22x - 100x - 10x = 6 + 60 - 132[/tex]

Evaluate the like terms

[tex]-66x = -66[/tex]

Divide by -66

x = 1

Substitute x = 1 in y = x + 6

[tex]y = 1 + 6[/tex]

y = 7

Recall that the number is 10x + y

So, we have

Number = 10 * 1 + 7

Evaluate

Number = 17

Hence, the number is 17

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The Two sets, A and B, are said to be disjoint sets if A n B=ϕ

The Two sets, A and B, are said to be disjoint sets if A n B=ϕ

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The ratio of cos Z is cos Z = 3 / 5

A right triangle has one angle of the triangle as 90 degrees.

The sides of the right triangle can be found using trigonometric ratios.

Therefore,

sin ∅ = opposite / hypotenuse

sin Z = 3 / 5

Using Pythagoras theorem,

c² = a² + b²

5² - 3² = b²

b² = 25  - 9

b² = 16

b = √16

b = 4

Hence,

P + A = 90 degrees (complementary angles)

Therefore,

sin P = cos Z

cos Z = 3 / 5

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Answer:

1&2)

GH = 28

FH = 56

XY = 7

XZ = 14

3-6) Acute, Obtuse, Acute, Right

7) Perimeter: 40 in. Area: 84 in^2

8) Perimeter: 42 m.  Area: 84 m^2

9) Perimeter: 15.2 yd. Area: 14.44 yd^2

10) 1, 8, 27, 64, 125 These are the cubes of 1, 2, 3, 4, 5 so it's just the cube of the next number that was cubed before.

11) 128, 32, 8, 2, 1/2 Divide the previous number by 4.

12) 2, -6, 18, -54, 162 Multiply the previous number by -3

13-15) I'm sorry we didn't do those so I don't really know how that works sorry.

16) 3x - 14 = 34

3x = 48 Add 14 to each side (to isolate 3x)

x = 16 Divide by 3 both sides (to get x)

17) -4(x+3) = -28

x+3 = 7 divide by -4 on both sides (to get a step closer to solving for x and isolating x+3)

x = 4 subtract 3 from both sides (to get x (isolating x))

18) 43 - 9(x-7) = -x - 6

43 - 9x + 63 = -x - 6 distribute 9 to x and 7 (to expand)

106 - 9x = -x - 6 combine like terms (easier to deal with)

106 - 8x = -6 add x to both sides (so there's only x on one side)

112 - 8x = 0 add 6 to both sides (only one number left)

112 = 8x move -8x to the right side

x = 14 divide by 8 (to isolate x)

19) x = 29 degrees

20) x = 13 degrees

21) x = 9 degrees, y = 31 degrees

Step-by-step explanation:

4x = 5x-7

x = 7

GH = 5(7) - 7 = 35 - 7 = 28

FH = 4x + 5x - 7 = 4(7) + 28 = 28*2 = 56

3x - 5 = x + 3

x = 4

XY = 3(4) - 5 = 12 - 5 = 7

XZ = 7*2 = 14

Acute is < 90

Obtuse is > 90

Right is = 90

Straight is = 180

7) 2(6+14) = 2(20) = 40 in

6*14 = 84 in^2

8) 13+14+15 = 42 m

(12*14)/2 = 6*14 = 84 m^2

9) 3.8*4 = 15.2 yd

3.8^2 = 14.44 yd^2

19) 34 + 4x + 30 = 180

64 + 4x = 180

4x = 116

x = 29

20) 4x + 7x + 37 = 180

11x = 143

x = 13

21) 3y + 42 = 9x + 54

y + 14 = 3x + 18

y = 3x + 4

3y + 42 + 5x + 9x + 54 + 5x = 360

3y + 19x = 264

substitute y with 3x + 4

3(3x + 4) + 19x = 264

9x + 12 + 19x = 264

28x = 252

x = 9

so y = 3(9) + 4 = 27 + 4 = 31

Give f(x) a dotted boundary and shade it above.

Give g(x) a solid boundary and shade it above.

The solution set is the region that is in the shaded region of both graphs.

The FOIL method is a method of expanding two given brackets by following the required steps. Thus using the FOIL method, the required answer is: -7

Expansion of brackets may be done using different methods, but these methods would give the same answer. Some methods that can be used are the binomial expansion method, FOIL method, etc.

The FOIL method is a shortened form of the steps required for the process. These required steps are First, Outside, Inside, and last.

Thus to expand the given brackets in the question, we have;

(5+2)(4-5) = 5(4 - 5) + 2(4 - 5)

                = 20 - 25 + 8 - 10

                = 28 - 35

(5+2)(4-5) = -7

Thus using the FOIL method, the answer to the question is -7.

Quick check: (5+2)(4-5) = (7)(-1)

                             = -7

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The vector in component form is given by:

V = i - j.

A vector is given by the terminal point subtracted by the initial point, hence:

(3,-4) - (2, -3) = (3 - 2, -4 - (-3)) = (1, -1)

A vector (a,b) in component form is:

V = a i + bj.

Hence, for vector (1,-1), we have that:

V = i - j.

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The amount of George's income that is subject to withholding is $75,000, which excludes the alimony income.

Alimony income represents the amount received from a spouse or a former spouse under a divorce or separation instrument.

The incomes subject to withholding include the following:

Wages income = $50,000

Gambling winning = $20,000

Alimony income = $10,000

Dividend income = $5,000

Income subject to withholding = $75,000 ($20,000 + $20,000 + $5,000)

Thus, George's income that is subject to withholding is $75,000, excluding the alimony income.

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The probability that a randomly selected member did not volunteer for the recent activity is 19/43.

Probability determines the odds that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0. The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.

The probability that a randomly selected member did not volunteer for the recent activity = 1 - ratio of randomly selected members that volunteered

1 - 24/43

(43/43) - (24/43) = 19/43

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The probability that a truck drives between 150 and 156 miles in a day is 0.0247. Using the standard normal distribution table, the required probability is calculated.

The formula for calculating the probability distribution for a random variable X, Z-score is calculated. I.e.,

Z = (X - μ)/σ

Where X - random variable; μ - mean; σ - standard deviation;

Then the probability is calculated by P(Z < x), using the values from the distribution table.

The given data has the mean μ = 120 and the standard deviation σ = 18

Z- score for X =150:

Z = (150 - 120)/18

   = 1.67

Z - score for X = 156:

Z = (156 - 120)/18

  = 2

So, the probability distribution over these scores is

P(150 < X < 156) = P(1.67 < Z < 2)

⇒ P(Z < 2) - P(Z < 1.67)

From the standard distribution table,

P(Z < 2) = 0.97725 and P(Z < 1.67) = 0.95254

On substituting,

P(150 < X < 156) = 0.97725 - 0.95254 = 0.02471

Rounding off to four decimal places,

P(150 < X < 156) = 0.0247

Thus, the required probability is 0.0247.

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Compute the divergence of [tex]\vec F[/tex].

[tex]\mathrm{div}(\vec F) = \dfrac{\partial(2x^3+y^3)}{\partial x} + \dfrac{\partial (y^3+z^3)}{\partial y} + \dfrac{\partial(3y^2z)}{\partial z} = 6x^2 + 3y^2 + 3y^2 = 6(x^2+y^2)[/tex]

By the divergence theorem, the integral of [tex]\vec F[/tex] across [tex]S[/tex] is equivalent to the integral of [tex]\mathrm{div}(\vec F)[/tex] over the interior of [tex]S[/tex], so that

[tex]\displaystyle \iint_S \vec F\cdot d\vec S = \iiint_{\mathrm{int}(S)} \mathrm{div}(\vec F)\,dV[/tex]

The paraboloid meets the [tex]x,y[/tex]-plane in a circle with radius 3, so we have

[tex]\mathrm{int}(S) = \left\{(x,y,z) \mid x^2+y^2\le3 \text{ and } 0 \le z \le 9-x^2-y^2\right\}[/tex]

and

[tex]\displaystyle \iiint_{\mathrm{int}(S)} \mathrm{div}(\vec F) \,dV = \int_{-3}^3 \int_{-\sqrt{9-x^2}}^{\sqrt{9-x^2}} \int_0^{9-x^2-y^2} 6(x^2+y^2)\,dz\,dy\,dx[/tex]

Convert to cylindrical coordinates, with

[tex]\begin{cases}x = r\cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \\ dV = dx\,dy\,dz = r\,dr\,d\theta\,d\zeta\end{cases}[/tex]

so that [tex]x^2+y^2=r^2[/tex], and the domain of integration is the set

[tex]\left\{(r,\theta,\zeta) \mid 0 \le r \le 3\text{ and } 0 \le \theta\le2\pi \text{ and } 0 \le \zeta \le 9-r^2\right\}[/tex]

Now compute the integral.

[tex]\displaystyle \int_0^3 \int_0^{2\pi} \int_0^{9-r^2} 6r^2\cdot r\,d\zeta\,d\theta\,dr = 12\pi \int_0^3 \int_0^{9-r^2} r^3\, d\zeta \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \int_0^3 r^3 (9 - r^2) \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \int_0^3 (9r^3 - r^5) \, dr \\\\ ~~~~~~~~~~~~ = 12\pi \left(\frac94 r^4 - \frac16 r^6\right)\bigg|_0^3 = 12\pi \left(\frac94\cdot3^4-\frac16\cdot3^6\right) = \boxed{729\pi}[/tex]

Statistics exist in the analysis of collection, analysis, interpretation, and presentation of data or into discipline to collect and summarize the data.

Therefore, the correct answer is option A. The mean is less than the median.

Statistics exist in the analysis of collection, analysis, interpretation, and presentation of data or into discipline to collect and summarize the data.

Half the students scored 87.

The next highest score exists at 71.

Then the median will be (71+ 87) / 2 = 79

A few students scored 52, so the mean exists a little lower than the mean of 71 and 87.

Therefore, the correct answer is option A. The mean is less than the median.

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The complete question is:

In a mathematics class, half of the students scored 87 on an achievement test. With the exception of a few students who scored 52, the remaining students scored 71. Which of the following statements is true about the distribution of scores?

A. The mean is less than the median.

B. The mean and the median is the same.

C. The mean is greater than the mode.

D. The mean is greater than the median.

Answer:

the answer is 86,016

Step-by-step explanation:

i took the test

Answer:

The answer is 4.

Step-by-step explanation:

8(-1)^4 - 3(-1) - 7

    8 + 3 - 7

      11 - 7

         4

Total 8 triangles are formed in figure and 4 edges used to make triangles and The area of all triangle is 1 square unit.

According to the statement

we have given that a figure and we have to the number of triangle present in it and the area of each square and the number of edges used in all triangles.

So, For this purpose, we know that the

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry.

So,

A. The number of triangles present in figure:

There is a rectangle provided with two diagonals and due to this structure

Firstly 4 triangles are formed with 2 diagonals (big size).

And 4 triangles are formed in diagonals because diagonals cut each other (small size).

So, Total 8 triangles are formed in figure.

B. Edges used to form triangle :

there are 4 edges used to form triangles because of presence of overall shape of rectangle because triangles are formed in a rectangle shape.

So, 4 edges used to make triangles.

C. Area of the triangle:

If the area is 1 square unit and area of all triangles are same

So, The area of all triangle is 1 square unit.

So, Total 8 triangles are formed in figure and 4 edges used to make triangles and The area of all triangle is 1 square unit.

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Answer:

C looks most correct

Step-by-step explanation:

Based on the given current and the given resistance, the voltage of the current is 14 + j8

From the question, we have the following parameters

current of 4+j2 amps and a resistance of 2-j3 ohms.

This can be rewritten as:

Current (I) = 4+j2 amps

Resistance (R) = 2-j3 ohms.

The formula to calculate voltage is given as

Voltage=(current) × (resistance)

Rewrite as:

V = I * R

Substitute the known values in the above equation

V = (4 + j2) * (2 - j3)

Expand the brackets

V = 8 - j4 + j12 + 6

Collect the like ters

V = 8 + 6 - j4 + j12

Evaluate the like term

V = 14 + j8

Based on the given current and the given resistance, the voltage of the current is 14 + j8

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The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.

Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;

D = 6371 + (343)×2

Hence, we have; diameter, D = 7057 km.

Hence, the distance travelled after 8 revolutions is;

C = 8 × πd

C = 8 × 3.14 × 7057

C = 177,271.8 km.

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The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.

In this question we must determine the area generated by four functions: three linear functions and a radical function. First, we plot the four functions to determine the required combinations of definite integrals need for calculation:

[tex]A = \int\limits^{0.382}_0 {[f(x) - g(x)]} \, dx + \int\limits^2_{0.382} {[h(x) - g(x)]} \, dx[/tex], where f(x) = √x, g(x) = x - 3 and h(x) = - x + 1.

[tex]A = \int\limits^{0.382}_{0} {[\sqrt{x} - x + 3]} \, dx + \int\limits^{2}_{0.382} {[- 2 \cdot x + 4]} \, dx[/tex]

[tex]A = \int\limits^{0.382}_{0} {\sqrt{x}} \, dx - \int\limits^{0.382}_{0} {x} \, dx + 3 \int\limits^{0.382}_{0}\, dx - 2 \int\limits^{2}_{0.382} {x} \, dx + 4 \int\limits^{2}_{0.382}\, dx[/tex]

[tex]A= 2 \cdot x^{\frac{3}{2} }|_{0}^{0.382} - \frac{x^{2}}{2}|_{0}^{0.382} + 3\cdot x |_{0.382}^{2} - x^{2} |_{0.382}^{2}+4\cdot x |_{0.382}^{2}[/tex]

[tex]A = 2 \cdot (0.382^{\frac{3}{2} }-0^{\frac{3}{2} })-\left(\frac{1}{2} \right)\cdot (0.382^{2}-0^{2}) + 3 \cdot (2 - 0.382) - (2^{2}-0.382^{2})+4\cdot (2^{2}-0.382^{2})[/tex]

A = 16.815

The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.

The statement reports an inconsistency with at least one function and needs to be modified in order to apply definite integrals in a consistent manner. New form is shown below:

Sketch the region enclosed by the given curves and find its area: (i) x + y = 1, (ii) x - 3 = y, (iii) y = √x, (iv) x = 0.

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Triangle MNL and triangle QNL are congruent to each other based on by either ASA or AAS.

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles, equilateral, scalene and right angle triangle. Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent to each other.

From triangle MNL and triangle QNL, in triangle MNL:

∠M + ∠N + ∠L = 180° (sum of angles in a triangle)

90 + 58 + ∠L = 180

∠L = 32°

Hence Triangle MNL and triangle QNL are congruent to each other based on by either ASA or AAS.

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Answer: 22.5 inches

Step-by-step explanation:

[tex]p=s+s+s+s+s[/tex]

[tex]5(4.5 in)=p[/tex]

∴ 22.5 inches = perimeter of the pentagon