Determine the acid dissociation constant (Ka) for a 0.200 M solution of hydrogen sulfate ion with
the pH of 1.35 if the reaction for the dissociation of this acid is
HSO 4 →→ H+ + SO 4-²
(Hint: [H+] = 10-PH; Ka = [product]/[reactant])

Answers

Answer 1

The acid dissociation constant(Ka) is 0.0095

The reaction for this dissociation of acid is

HSO4 ⇄H+ + SO4 -2

The dissociation constant can be determined from the following expression

[tex]Ka= \frac{[H+] [SO4]-2}{[HSO4}[/tex]  

[H+] = 10-PH

       = 10-1.35

[H+]  = 0.0447

[H+] = 0.0447 mol / L

From equation, [H+] = [SO4-2] = 0.0447 mol / L

[SO4-2] = 0.0447 mol / L

From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,

Ka = 0.0447 * 0.0447 / 0.200

     = 0.0019 / 0.200

     = 0.0095

Hence the value of the acid dissociation constant (Ka) for the given reaction is  0.0095

                           

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Related Questions

How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) k2co3(aq) → 2 kcl(aq) caco3(aq)

Answers

Answer:

1.12 g CaCl₂

Explanation:

To find the mass of calcium chloride, you need to (1) convert grams KCl to moles KCl (via molar mass), then (2) convert moles KCl to moles CaCl₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CaCl₂ to grams CaCl₂ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (KCl): 39.098 g/mol + 35.453 g/mol

Molar Mass (KCl): 74.551 g/mol

Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)

Molar Mass (CaCl₂): 110.984 g/mol

1 CaCl₂(aq) + K₂CO₃(aq) -----> 2 KCl(aq) + CaCO₃(aq)

1.50 g KCl            1 mole              1 mole CaCl₂           110.984 g
-----------------  x  -----------------  x  -----------------------  x  ------------------  =
                           74.551  g           2 moles KCl              1 mole

=  1.12 g CaCl₂


What is the chemical symbol of the terminal atom in the lewis structure of OH- ?

Answers

Answer:

kindly refer to the picture attached

Explanation:

Have a great day . keep smiling

Why does an aerial require two explosions of black powder

Answers

Answer:

to launch aerials and also causes the explosions necessary for special effects like noise or colored light.

Explanation:

State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:

Fe 3+ (aq) + SO3 2- (aq) ---> Fe 2+ (aq) + SO4 2- (aq)

Answers

Fe is undergoing oxidation while S is undergoing reduction

What is oxidation-reduction reaction?

Oxidation-reduction reaction can simply be defined as a special type of chemical reaction in which the oxidation states of substrate change. Oxidation is the

So therefore, Fe is undergoing oxidation while S is undergoing reduction

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Which of the following is the name given to a carbohydrate containing one monomer?
Disaccharide
Decasaccharide
Monosaccharide
Polysaccharide

Answers

Answer:

Disaccharide

Explanation:

When two monomers combine, a disaccharide is formed. Also, the prefix "di" is two therefore the answer must be a disaccharide

↬ [tex]what \: is \: psi \:?[/tex]​

Answers

[tex] \large \underline{ \boxed{ \tt \red{Pounds \: per \: square \: inch}}}[/tex]

[tex] \: \: \: [/tex]

( PSI ) is a measurement of pressure in the Imperial system of measurement.

PSI is commonly used to measure the pressure of gasses (pneumatic pressure) or liquids (hydraulic pressure). PSI is also used as a measure of tensile strength, defined as resistance to pulling forces, and elastic modulus strength, defined as resistance to deformation, which controls the stiffness of materials.

[tex] \: \: \: [/tex]

hope helps ~


Give the answer the problem below to the correct number of significant figures. Explain your results.
(329.5/0.45)-23.2

Answers

The correct number of significant figures gotten from the result of (329.5/0.45)-23.2 is infinite because there is no uncertain digit as a result of the answer being 709.022222222 when calculated.

What is a Significant figure?

These refers to the digits which contributes to the degree of accuracy of a value and is usually counted starting from the non zero digits. In cases where the zero is between other numbers it is regarded as being significant such as 70.0111 in which the number of significant figures is six.

The result gotten from the expression (329.5/0.45)-23.2 is 709.022222222 which has a recurring decimal thereby making it difficult to calculate the number of recurring decimal.

Therefore it has infinitely many significant figures because there is no uncertain digit.

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Which of the following is a property of bases?

A. They are found in fruit.

B. They pollute the air.

C. They taste sour.

D. They are slippery.

A p e x

Answers

Answer: D. They are slippery.

Explanation:

         Only one of the following is a property of bases. This is option D, they are slippery. Bases usually feel slippery, which can also be described as "soapy." Many soaps, shampoos, detergents, etc contain bases.

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3. Calculate the molarity of the HCI solution if 0.074 mol of HCl is dissolved in water to

make 2000 mL of the solution. Also calculate the pH of this solution. Hint: In case of

strong acids the [H3O+] is same as the molarity of acid solution.

Answers

Answer:

Molarity = 0.037 M

pH = 1.43

Explanation:

First, you need to calculate the molarity. After converting mL to L, you can plug the values into the molarity equation and simplify.

2,000 mL / 1,000 = 2 L

Molarity (M) = moles / volume (L)

Molarity = 0.074 moles / 2 L

Molarity = 0.037 M

You can plug the molarity of the hydrogen ion into the pH equation to find the pH. Remember that H₃O⁺ and H⁺ can be considered the same thing. Since HCl dissociates into just one H⁺ and one Cl⁻, the molarity of the HCl solution is the same as the molarity of the H⁺.

pH = -log[H⁺]

pH = -log[0.037]

pH = 1.43

The theory of what an atom looks like has evolved over time. From the ancient Greeks, to Dalton, to Rutherford—no idea was exactly the same. However, as more information is gathered, new ideas can build on the old. Sometimes new ideas can completely replace the old ones. Even today, there may be new advances that have changed our understanding of the atom that are not reflected in this course.

Answer one of the following prompts to begin your discussion:

You claim that the atomic model should not be continually changed. What reasoning would you give someone to help them understand your claim?
You claim that a new atomic model should always build on an old one. What reasoning would you give someone to help them understand your claim?
You claim that a new atomic model should completely replace an old one. What reasoning would you give someone to help them understand your claim?
You claim that the continuous evolution of the atomic model is beneficial, but you think it should be a mix of the old and the new. What reasoning would you give someone to help them understand your claim?

Answers

To being my discussion, I claim that a new atomic model should always build on an old one with the following reasons of mine. That is option B.

What is an atomic model?

An atomic model is a model that describes how the interior of an atom looks like. This first atomic model was developed by William Thomson.

To start my discussion, I claim that a new atomic model should always build on an old one with the following reasons of mine:

The modern scientists exploited the ideas of the ancient scientists to arrive at a better atomic model.

This method is proven the the works of Bohr in the Bohr atomic model which relied on quantum mechanics, built upon the Rutherford model to explain the orbits of electrons.

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Find q when 22.0 g of water is heated from 29.0°C to 100.0°C.

Answers

Answer:

6530 J

Explanation:

To find the value of "Q", you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat capacity of water is 4.182 J/g°C. You can plug the given values into the equation and solve for "Q". The final answer should have 3 significant figures because the lowest number of sig figs among the given values is 3.

Q = ? J                             c = 4.182 J/g°C

m = 22.0 g                      ΔT = 100.0 °C - 29.0 °C = 71.0 °C

Q = mcΔT

Q = (22.0 g)(4.182 J/g°C)(71.0 °C)

Q = 6530 J

Approximately 6461.9 joules of heat are required to heat 22.0 g of water from 29.0°C to 100.0°C.

Given:

mass of water, m = 22.0 g

Specific heat capacity of water, c = 4.184 J/g°C

Change in temperature, ΔT= 100.0°C - 29.0°C = 71.0°C

The formula for the heat absorbed or released during a temperature change:

q = m × c ×ΔT

where:

q = heat (in joules, J)

m = mass of the substance (in grams, g)

c = specific heat capacity of the substance (in J/g°C)

ΔT = change in temperature (in °C)

For water, the specific heat capacity is approximately 4.184 J/g°C.

Putting the values into the formula and calculating q:

q = 22.0 g × 4.184 J/g°C ×71.0°C

q ≈ 6461.9 J

Thus, approximately 6461.928 joules of heat are required.

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The Haber process is a method to produce ammonia from hydrogen and nitrogen gases. The reaction is:
N2(g) + 3 H2(g) <--> 2 NH3(g)
If hydrogen gas is added after the reaction has reached equilibrium, the reaction will:
Group of answer choices

A. Need more information

B. Stop. All of the nitrogen gas has been used up.

C. Shift to the left to produce more reactants

D. Shift to the right to produce more product

Answers

Answer:

D.) Shift to the right to produce more product

Explanation:

When more reactants are added to a reaction, the equilibrium will shift to the product side to restore the balance.

As such, when H₂ (a reactant) is added, the reaction will shift to the product side, resulting in an increase of NH₃.

OMG PLEASE HELP!! THIS IS IMPORTANT!!

which statements describe the cell membrane? Check all that apply


A.) The cell membrane is very selective.

B.) The cell membrane lets anything enter the cell.

C.) The cell membrane lets anything leave the cell.

D.) The cell membrane is protective layer surrounding a cell.

E.) The cell membrane allows waste to leave the cell.

Answers

Answer:

The cell membrane is protective layer surrounding a cell.

Answer:

options D is correct

....hope it helps you

If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assume that volume is constant.

A. 0.6 atm

B. 1.3 atm

C. 1.0 atm

D. 2.6 atm

Answers

The new pressure of the gas would be = 2.1 atm.

Calculation of gas pressure

The initial temperature of the gas(T1) = 20°C

The final temperature of the gas(T2)= 35°C

The volume= constant

The Original pressure (P1) = 1.2atm

The new pressure (P2) =?

Using the gas law P1/T1 = P2/T2

Make P2 the subject of formula;

P2= P1×T2/T1

P2= 1.2 × 35/20

P2= 42/20

P2= 2.1 atm

Therefore, the new pressure of the gas would be = 2.1 atm.

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Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of water at 25°C is 23.76 torr. (Assume ideal behavior.)

Answers

The vapor pressure is obtained as 23.47 torr.

What is the vapor pressure?

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

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Question 6
How many mole of potassium hydroxide are in 27.5 mL of 0.250 M
potassium hydroxide solution?

Answers

Answer:

0.00688 moles

Explanation:

The molarity ratio looks like this:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the values into the equation and simplify to find moles.

27.5 mL / 1,000 = 0.0275 L

Molarity = moles / volume                         <----- Molarity ratio

0.250 M = moles / 0.0275 L                      <----- Insert values

0.00688 = moles                                       <----- Multiply both sides by 0.0275

Given the reaction: A + B <--> C + D
The concentrations at equilibrium are [A] = 1 M, [B] = 1 M, [C] = 2 M, and [D] = 2 M. What is the value of the equilibrium constant (K)?
Group of answer choices

A. 4.0

B. 2.0

C. 1.0

D. 0.25

Answers

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]                                       <----- Equilibrium expression

[tex]K = \frac{[2 M] [2 M]}{[1 M] [1 M] }[/tex]                                     <----- Insert molarities

[tex]K = \frac{4}{1 }[/tex]                                                <----- Multiply

[tex]K = 4[/tex]                                                <----- Divide

Calculate the molarity of a solution that has 18.0 g of glucose, C6H12O6, dissolved in 80.0 g of water.

Answers

Answer:

1.25 M

Explanation:

In this case, the solute is C₆H₁₂O₆ and the solvent is H₂O.To find the molarity, you need to (1) convert the mass C₆H₁₂O₆ to moles (via molar mass), then (2) convert grams H₂O to liters H₂O, and then (3) calculate the molarity.

(Step 1)

Molar Mass (C₆H₁₂O₆): 6(12.011 g/mol) + 12(1.008 g/mol) + 6(15.998 g/mol)

Molar Mass (C₆H₁₂O₆): 180.15 g/mol

18.0 g C₆H₁₂O₆           1 mole
------------------------  x  -----------------  =  0.0999 moles C₆H₁₂O₆
                                   180.15 g

(Step 2)

1,000 grams = 1 L

80.0 g H₂O                1 L
--------------------  x  -------------------  =  0.0800 L H₂O
                                 1,000 g

(Step 3)

Molarity = moles solute / volume solvent (L)

Molarity = 0.0999 moles / 0.0800 L

Molarity = 1.25 M

In a calorimetry experiment 2.50 g of methane is burnt in excess oxygen. 30% of the

energy released during the combustion is absorbed by 500 g of water, the temperature of

which rises from 25°C to 68°C. The specific heat capacity of water is 4.184 J/g°C. What

is the total energy released per gram of methane burnt?

Answers

The total energy released per gram of methane in the experiment is 119941.33 J/g

How to determine the change in the temperature of waterInitial temperature of water (T₁) = 25 °CFinal temperature of water (T₂) = 68 °CChange in temperature (ΔT) = ?

Change in temperature (ΔT) = T₂ – T₁

Change in temperature (ΔT) = 68 – 25

Change in temperature (ΔT) = 43 °C

How to determine the heat absorbed by the water

The absorbed by the water can be obtained as illustrated below:

Mass of water (M) = s00 gChange in temperature (ΔT) = 43 °C Specific heat capacity of the water (C) = 4.184 J/gºC Heat (Q) =?

Q = MCΔT

Q = 500 × 4.184 × 43

Q = 89956 J

How to determine the energy released by methane in the experimentHeat absorbed by water = 89956 JPercentage of heat absorbed by water = 30%Heat released by methane =?

Heat absorbed by water = 30% of heat released by methane

89956 = 30% × heat released by methane

89956 = 0.3 × heat released by methane

Divide both sides by 0.3

Heat released by methane = 89956 / 0.3

Heat released by methane = 299853.33 J

How to determine the heat released per gram of methaneHeat released by methane (Q) = 299853.33 JMass of methane (m) = 2.5 gHeat per gram (ΔH) =?

Q = m × ΔH

Divide both sides by m

ΔH = Q / m

ΔH = 299853.33 / 2.5

ΔH =119941.33 J/g

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Urgent

During an experiment, distilled water was placed in a sealed container and the container was heated gradually. Describe this system when it reaches phase equilibrium.

Answers

We can achieve equilibrium state, when the concentration of product and reactants are equal to each other.

Describe this system when it reaches phase equilibrium?

In this type of system, when the same amount of liquid water is converted into gaseous form of water and the gaseous form of water into liquid form of water. This phase is known as equilibrium phase or state because same amount of reactants and products are produced .

So we can conclude that we can achieve equilibrium state, when the concentration of product and reactants are equal to each other.

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You have a 473 mL glass of lemonade with a concentration of 2.37 M.

The lemonade sits out on your counter for a couple of days, and 150 mL of water evaporates from the glass.

What is the new concentration of the lemonade?

Answers

The new concentration of the lemonade solution, given the data from the question is 3.47 M

Data obtained from the question

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 2.37 MVolume of stock solution (V₁) = 473 mLVolume of water that evaporated = 150 mLVolume of new solution (V₂) = 473 - 150 = 323 mL Molarity of new solution (M₂) =?

How to determine the molarity of the new solution

The molarity of the new solution can be obtained by using the dilution formula as shown below:

M₁V₁ = M₂V₂

2.37 × 473 = M₂ × 323

1121.01 = M₂ × 323

Divide both side by 323

M₂ = 1121.01 / 323

M₂ = 3.47 M

Thus, the concentration of the new solution is 3.47 M

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How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?
Group of answer choices

A. +83.6 J

B. +3963 J

C. -3963 J

D. -83.6 J

Answers

Taking into account the definition of calorimetry, sensible heat and latent heat, the heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

In this case, the amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m. c is a specific heat substance.ΔT is the temperature variation.Latent heat

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

This case

First, you  have to get the ice from -10°C to 0 °C, which is the melting point.  Then you have to melt the ice into liquid water. Now, you have to get the water from 0°C to 10°C.

-10°C to 0 °C

In this case, you know:

c= specific heat capacity of ice= 2.108 [tex]\frac{J}{gK}[/tex]m= 10 gΔT= Tfinal - Tinitial= 0 °C - (-10 °C)= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Replacing in the definition of sensible heat:

Q1= 2.108 [tex]\frac{J}{gK}[/tex]× 10 g× 10 K

Solving:

Q1= 210.8 J

Heat needed to melt ice

In this case, you have to melt the ice into liquid water. Being the specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is calculated as:

Q2= 10 grams× 334 J/g

Solving:

Q2= 3,340 J

0°C to 10 °C

In this case, you know:

c= specific heat capacity of liquid water is 4.187 [tex]\frac{J}{gK}[/tex]m= 10 gΔT= Tfinal - Tinitial= 10 °C - 0 °C= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Replacing in the definition of sensible heat:

Q3= 4.187 [tex]\frac{J}{gK}[/tex]× 10 g× 10 K

Solving:

Q3= 418.7J

Total heat required

The total heat required is calculated as:  

Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

Total heat required= 3,969.5 J

In summary, the heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J.

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H2O Is water. H10O5 Is Monohydrate trihydrate. What Is the chemical compound name for H50O25?

Answers

Answer:

THERE IS NO  such compound

Explanation:

Which of the following best describes how an ionic compound dissolves in water?
Group of answer choices

A. It separates into individual molecules and is a non-electrolyte.

B. It breaks into its individual ions and is an electrolyte.

C. It separates into individual molecules and is an electrolyte.

D. It breaks into its individual ions and is a non-electrolyte.

Answers

The correct answer choice which best describes how an ionic compound dissolves in water is that It breaks into its individual ions and is an electrolyte.

Option B is the correct answer

What is ionic bonding?

This is type of chemical bonding which involves the transfer of valence electron from a metallic element to a non-metallic element

So therefore, The correct answer choice which best describes how an ionic compound dissolves in water is that It breaks into its individual ions and is an electrolyte.

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Please help me with this reaction

Answers

The major product from the above organic reaction is I

In this reaction, methoxy ethane undergoes addition reaction with hydrogen bromide, Markownikoff's rule being involved in the reaction.

What are organic compounds?

Organic compounds are the compounds which contains carbon and hydrogen.

Generally, organic compounds are characterized by the following:

All organic compounds contains carbon Organic compounds are also combustible in nature They are mostly covalent bonded molecules They are all soluble in non-polar solvents.They can be isolatedThey can also be prepared in the laboratory

Below are some classes of organic compounds:

AlkanesAlkenesAlkynesAlkanolsAlkanoic acidAlkanalsEstersKetonesAmines

So therefore, the major product from the the above organic reaction is IV

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What is the half life of sodium-24 if after 12 days the sample has a mass of 1.2 g from an initial mass of 9.6 g?
Group of answer choices

A. 36 days

B. 12 days

C. 24 days

D. 4 days

Answers

As well as I think the answer is 24 days

Give the IUPAC name of 2,2,3-trimethyl butane and draw it's corrosponding structure.​

Answers

I hope this helps you ...

how did the boiling point of plain water compare to that of water with salt? Compared to water with sugar?

Answers

The boiling point of plain water is less than the boiling point of both salt and sugar water.

What is boiling point?

Boiling point can be defined as the point when the pressure exerted by the surroundings upon a liquid is equal to the pressure exerted by the vapour of the liquid.

The boiling point of plain water is 100°C which increases upon addition of solute substances such as salt and sugar.

But salts are usually made up of ionic bonds while sugar are made up of covalent bonds. This means that more energy would be required to boil salt solution due to its ionic bonds.

Therefore, the boiling point of salt water is highest following sugar water before plain water which is the lowest.

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perform the following operation and express the answer in scientific notation 9.80x10^-3 + 1.60 x 10^-4

Answers

answer = 9.96x10^-3

I hope that help you

A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. After 25.0 mL of base is added, the pH of the solution is 3.52.

Estimate the pKa of the weak acid.
Express your answer using three significant figures.

Answers

pKa value =4.76Ka

=1.73×10 −5 !!    PH=4−PKa=14−4.76=9.24 for a weak monoprotic acid is titrated with 0.100 M NaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. After 25.0 mL of the base is added, the pH of the solution is 3.52.

One way to describe an acid's potency is by its pKa value. The acid dissociation constant, or pKa, is the negative log of the pKa value. A stronger acid is indicated by a lower pKa value. In other words, a lower value means that the acid dissociates in water more completely.

The logarithm of Ka's negative value is denoted as pKa. The logarithmic inverse of the H+ concentration is pH. Acidity indication. An acid's pKa value tells you if it's a strong acid or a weak acid. The pH scale shows how acidic or alkaline a system is.

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