Answer:
8
Step-by-step explanation:
let the number=x
8(x-2)=16(x-5)
divide by 8
x-2=2(x-5)
x-2=2x-10
2x-x=-2+10
x=8
three hens lay 3 eggs any 3 days. in how many days will 3n hens lay at this rate 9nk eggs? please i need answer fast!!! will give brainliest!
If three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
Number of days that three hens lay 9 eggsGiven:
3 hens lay 3 eggs in 3 days
First step is to determine the number of egg one hen lay in 3 days
1 hen in 3 days lays 3/3
1 hen in 3 days lays=1 egg
Second step is to determine the number of egg 3 hens lay 1 day
1 hen in 1 day lays 1/3 egg
3 hens in 1day lay=(1×3)/3
3 hens in 1day lay=1 egg
Third step is to determine the number of eggs 3 hens lay in 9 days
3 hens in 9 days lay=(1×9)
3 hens in 9 days lay=9 eggs
Therefore assuming three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
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us
Find a formula for the nth term in this
arithmetic sequence:
a₁ = 7, a2 = 4, a3 = 1, a4 = -2, ...
an = [? ]n +
The formula for the nth term of the arithmetic sequence is [-3]n+10
What is the nth term of an arithmetic sequence?
⇒ The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
Calculation:
It is given that the given sequence is an arithmetic sequence.
First term a1 = 7
Second term a2 = 4
Common difference d = 4-7
⇒ d=3
From the general formula,
an = a1 + (n - 1)d
On substituting,
an = 7+ (n-1)(-3)
an = 7-3n+3
an = -3n+10
⇒ Thus the general formula for the nth term of the arithmetic sequence is -3n+10
an= [-3]n+10
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Find the range of y=7x-34/x-5
Answer:
Option A
Here you go.
Hope this help!!
Good luck!!
Horizontal asymptote
y=7x/x=7The range is
(-oo,oo)-{7}Or
R-{7}Option A
divide 5 by 6 and 5/6 into a repeating decimal
_
Answer: 0.83
Step-by-step explanation:
5/6 = 0.8333...
_
0.8333... = 0.83
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals DE and DG.
Check the picture below.
[tex]sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}[/tex]
What is the measure of this line?
Answer:
2 and 1/16th inch
Step-by-step explanation:
the half inch mark would be 2 and 1/2 and you know half of half is 1/4 so the best answer is A.
Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.
f(x)= (3x-4)(-6x-5)
quadratic function
quadratic term: −18x2
linear term: 39x
constant term: –20
quadratic function
quadratic term: −12x2
linear term: −42x
constant term: –20
linear function
linear term: 39x
constant term: –20
linear function
linear term: −18x2
constant term: –20
The given function is quadratic. The quadratic term is -18x², the linear term is 39x, and the constant term is -20. So, first option is correct.
What is a quadratic function?A function in which the highest degree of the variable is 2, then that function is said to be a quadratic function.
The general form of a quadratic function is ax² + bx + c. Where the terms are:
ax² - quadratic term;
bx - linear term;
c - constant term;
What is a linear function?A function in which the highest degree of the variable is 1, then that function is said to be a linear function.
The general form of a linear function is ax + c. Where the terms are:
ax - linear term;
c - constant term;
Expanding the given function:The given function is f(x) = (3x - 4)(-6x + 5)
Expanding the given function,
f(x) = (3x)(-6x) + (3x)(5) + (-4)(-6x) + (-4)(5)
= -18x² + 15x + 24x - 20
= -18x² + 39x - 20
Since the highest degree of the variable x in the obtained function is 2, it is a quadratic function.
The terms in the obtained quadratic function are:
quadratic term: -18x²
linear term: 39x
constant term: -20
Therefore, the first option is correct.
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Disclaimer: The question has a mistake in the function. The corrected question is here.
Question: Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.
f(x)= (3x - 4)(-6x + 5)
6. Find the mean, median, and mode of the set of
numbers: 6, 7, 11, 5, 8, 7, 4, 13, 11, 2.
Answer:
Mean 7.4
Median 7
Mode 7, 11
Step-by-step explanation:
Let me know if this is correct!
Answer: 7.4, 7, 7 and 11
Step-by-step explanation:
The mean is the sum of all the numbers divided by the number of numbers. In this case, there are 10 numbers.
[tex]Mean=\frac{6+7+11+5+8+7+4+13+11+2}{10}=\frac{74}{10}=7.4[/tex]
The median is the number (or the average of the two numbers) in the middle of the set when it is ordered in ascending order. Let's first order it from least to greatest.
[tex]2,4,5,6,7,7,8,11,11,13[/tex]
The two middle numbers are 7 and 7. The median is the mean of these two numbers.
[tex]Median=\frac{7+7}{2}=\frac{14}{2}=7[/tex]
The mode is the number that is most repeated number in the set. The numbers 7 and 11 are repeated twice. Hence, the modes are 7 and 11.
what is 11- 2 to the 3rd power
Answer:
See below
Step-by-step explanation:
Question is unclear
could be (11-2)^3 = 9^3 = 729
could be 11 - 2^3 = 11 - 8 = 3 Pick the one you want !
Write an equation that expresses the following relationship.
varies directly with the square of and inversely with
In your equation, use as the constant of proportionality.
The equation become u = k p^2 / d.
According to the statement
we have given that some conditions for the equations and we have t make the equation from the given equations.
So, For this purpose, we have given that
The equation in which u is varies directly with the square of p and inversely with d and use the k as the constant of proportionality.
So, From all these above the equation will become is
u = k p^2 / d
In latex form the equation write as :
[tex]u = \frac{kp^{2}}{d}[/tex]
In this equation all the given conditions are applicable.
So, The equation become u = k p^2 / d
Disclaimer: This question was incomplete. Please find the full content below.
Question:
Write an equation that expresses the following relationship. u varies directly with the square of p and inversely with d In your equation, use k as the constant of proportionality.
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Figure ABCD Is a kite. Find x
Answer:
x = 8
Step-by-step explanation:
Diagonals of a kite cross at right angles. That gives us a relation that can be solved for x.
SetupThe measure shown is equal to the angle measure of 90°.
14x -22 = 90
SolutionWe can solve this 2-step linear equation in the usual way.
14x = 112 . . . . . . step 1, add the opposite of the constant to get x alone
x = 112/14 = 8 . . . step 2, divide by the coefficient of x
The value of x is 8.
Use the fact 0.09=1/11 to write 0.27 as a fraction
Someone please help with this question asap!
Answer:
Side b is the longest because the longer side always lie opposite the bigger angle. Angle B is the biggest angle, and since side b is opposite angle B, side b is the longest.
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
The side opposite to the largest angle is the longest side of a triangle.
[tex] \qquad \large \sf {Conclusion} : [/tex]
hence, we can conclude that the longest side is b
( since it's opposite angle is the largest, i.e 91° )
An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet above the ground. The position of the object can be modeled using the function f(t)=−16t2+64t+16, where t is the time in seconds and f(t) is the height, in feet, of the object. What is the maximum height, in feet, that the object will reach?
Considering the vertex of the quadratic equation, the maximum height that the object will reach is of 80 feet.
What is the vertex of a quadratic equation?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex][tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]Considering the coefficient a, we have that:
If a < 0, the vertex is a maximum point.If a > 0, the vertex is a minimum point.In this problem, the equation is:
f(t) = -16t² + 64t + 16.
Hence the coefficients are:
a = -16, b = 64, c = 16.
The maximum value is found as follows:
[tex]y_v = -\frac{64^2 - 4(-16)(16)}{4(-16)} = 80[/tex]
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You are on the Arithmetic Reasoning section.
Q: If the following series continues the same pattern. What is the next
number in the series 1, 10, 7, 16?
Answer:
13
Step-by-step explanation:
This problem is a type of puzzle called a Number Pattern. Number patterns always follow a specific pattern. In this case, its +9, -3.
The first number in this pattern is 1.
The second number in this pattern is 10.
That is an increase of +9.
The third number in this pattern is 7
That is a decrease of -3.
The fourth number in this pattern is 16.
That is an increase of +9.
Therefore, we can conclude that the next number will have to be a decrease of -3.
16 - 3 = 13
That is your answer. I hope I helped. If you feel like this is the best answer, please rate brainliest.
Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true.
P(-0.78≤Z≤c)=0.7657
For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
How to find the p-value from 2 z-scores?We want to find the p-value between 2 z-scores expressed as;
P(-0.78 < z < c) = 0.7657
To solve this, we will solve it as;
0/7657= 1 - [P(z < -0.78) + P(z > c)]
From normal distribution table, we have that;
P(z < -0.78) = 0.217695
Thus;
0.7657 = 1 - (0.217695 + c)
c = 1 - 0.7657 - 0.217695
c = 0.0166
Thus, For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166
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The area of a rectangular cocktail table is x^2-18x+32 If the width is x-16 what is its length?
Answer: (x-2)
Step-by-step explanation:
This problem is a middle-term factorization, or factoring by splitting the middle term.
We have the equation
x^2 - 18x + 32
This equation represents the area, and area = length x width for all rectangles. We also know the width, x-16, which makes it easier for us. The length must also be in the same format.
x^2 - 18x + 32
= x^2 - 16x - 2x + 32
= x(x-16) - 2(x - 16)
= (x-16) (x-2) -------> we get this through taking (x-16) common
We could also pretend that the length is x - y, where y is the number we need to finish the equation.
x^2 - 18x + 32
= (x-16) (x-y)
= x^2 -16x - xy + 16y
-16 minus 2 is -18, which is our middle term.
Therefore, y = 2. This is also verified because is 16y = 32, the constant term, then through transposing we get y = 2.
Our answer is that the length is (x-2).
The following information is available for Brownstone Products Company for the month of July:
Actual Master Budget
Units 3,500 4,000
Sales revenue $ 54,300 $ 60,000
Variable manufacturing costs 10,000 16,000
Fixed manufacturing costs 13,000 14,000
Variable selling and administrative expenses 6,500 8,000
Fixed selling and administrative expenses 8,000 9,100
Required:
1. What was the master budget variance for July? Was this variance favorable or unfavorable?
2. Compute the July sales volume variance and the flexible-budget variance for the month, both in terms of contribution margin and in terms of operating income.
4. Prepare pro-forma budgets for activities within its relevant range of operations. Prepare a flexible budget for each of the following two output levels:
a. 3,560 units.
b. 3,980 units.
1. The master budget variance for July was $3,900, and this variance was favorable.
2. The July sales volume variances in terms of contribution margin and operating income are $2,800 F and $3,900 F, respectively.
3. The July flexible-budget variances in terms of contribution margin and operating income are $5,550 F and $6,650 F, respectively.
4. Flexible budgets for the following output levels are:
3,560 units 3,980 units
Sales revenue $53,400 $59,700
Variable manufacturing costs 14,240 15,920
Fixed manufacturing costs 12,460 13,930
Variable selling and
administrative expenses 7,120 7,960
Fixed selling and
administrative expenses 9,100 9,100
Operating Income $10,480 $12,790
Data and Calculations:Actual Master Budget Per Unit Variance
Units 3,500 4,000 500 U
Sales revenue $ 54,300 $ 60,000 $15.00 $ 5,700 U
Variable manufacturing costs 10,000 16,000 4.00 6,000 F
Fixed manufacturing costs 13,000 14,000 3.50 1,000 F
Variable selling and
administrative expenses 6,500 8,000 2.00 1,500 F
Contribution margin $24,800 $22,000 $2,800 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Total costs $37,500 $47,100
Operating income $16,800 $12,900 $3,900 F
Sales volume variance:
Revenue per unit $15.51 $15.00 $0.51 F
Flexible-budget:Actual Master Budget Variance
Units 3,500 3,500 U
Sales revenue $ 54,300 $ 52,500 $ 1,800 F
Variable manufacturing costs 10,000 14,000 4,000 F
Fixed manufacturing costs 13,000 12,250 750 U
Variable selling and
administrative expenses 6,500 7,000 500 F
Contribution margin $24,800 $19,250 $5,550 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Operating income $16,800 $10,150 $6,650 F
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How many three-digit positive integers have at least one prime digit?
Answer:
210
Step-by-step explanation:
[tex]512=2^9 \\[/tex] has 9 prime factors
Now, if you want to maximize the number of different prime factor, apply the following method: let [tex]p(n)[/tex] be the nth prime number, in increasing order. Let [tex]v[/tex] define as follow : [tex]v(0)=1,v(n+1)=v(n)p(n+1)[/tex] , and find n such that [tex]v(n) < 1000,v(n+1) > 1000[/tex]. n will be the number of factors and v(n) your integer.
[tex]v(1)=2v(0)=2v(2)=3v(1)=6v(3)=5v(2)=30v(4)=7v(3)=210v(5)=11v(4)=2310[/tex]
There you are, 210 , with only 4 different prime factors.
→Credits: Xavier Dectot←
The composite figure is made up of a parallelogram and a rectangle. Find the
area.
A. 88 sq. units
B. 64 sq. units
C. 24 sq. units
D. 120 sq. units
Answer:
A
Step-by-step explanation:
The parallelogram is the length times the height. The height is 8 and the length is 12 - 2 - 2 or 8.
8x8 = 64
The small rectangle is 12 x 2 or 24
64 + 24 = 88
Service Department Charges and Activity Bases
Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.
CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:
• The sector has 5,200 employees, of whom 25% are office employees.
• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.
• One hundred percent of the employees with a computer also have an e-mail account.
• The average number of help desk calls for October was 1.5 calls per individual with a computer.
• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.
a. Determine the service charge rate for the four CCS service categories for October.
CCS Service Category Service Charge Rate
Help desk $fill in the blank 1
Per call
Network center $fill in the blank 3
Per device monitored
Electronic mail $fill in the blank 5
Per user or e-mail account
Smartphone support $fill in the blank 7
Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.
October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a
The answers to the question are:
50751014a. How to determine the service charge rate for the month of OctoberThis is the number of calls for the help desk
160000/3200 = 50per call
network center
735000/9800
= 75 per device that was monitored
Electronic mail
100000/10000 =
10 for the mail account
For smart phone support
124600/8900
= 14 per phone extension
b. Charges to the COMM sectorfor helpdesk
5200 * 0.25 * 0.96 *1.5 calls * $50
= 93600
For network center
(5200 * 0.25 * 0.96) + 600] x 75
= 138600
For Electronic mail
5200 * 0.25 * 0.96 * 10 per email account
= 12480
Smart support charge
5200 * 0.25 * 14 = 18200
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Need all 3 done, please help (:
(8) The algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.
(9) The minimum number of shares needed to achieve the required profit is 1223, using the algebraic expression 2.25x ≥ 2750, where x is the number of shares.
(10) The number of books needed to be sold for the novelist to make a profit of $10,000 is 4350, using the algebraic expression 5000 + 1.1495x ≥ 10000, where x is the number of books sold,
(8) Weekly target for Ms. Reed is $350.
The cost of each unit she sells is $22.
We assume the number of units she sold to be x.
Thus, the total sales done by Ms. Reed is $22x.
For her to remain employed, her total sales should exceed her target, which can be shown as an algebraic expression: 22x ≥ 350.
Thus, the algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.
(9) Profit on each share is $2.
The additional profit is $0.25.
Thus, the total profit on each share is $2 + $0.25 = $2.25.
The required profit by the customer is $2750.
We assume the number of shares needed to be x.
Thus, the total profit made by the customer is $2.25x.
For the customer to make the required profit, we can write the algebraic expression, 2.25x ≥ 2750.
To solve this, we divide both sides by 2.25 to get:
2.25x/2.25 ≥ 2750/2.25,
or, x ≥ 1222.22.
Thus, the minimum number of shares needed to achieve the required profit is 1223.
(10) Default contract of Book Maker publisher is $5000 and 5% royalty.
The cost of the book, for which the novelist has got the contract is $22.99.
We assume the number of books sold to be x.
The royalty share on each book given to the novelist is 5% of $22.99, or, $ 5/100 * 2299/100 = $ 11495/10000 = $1.1495.
Thus, the royalty received on x number of books = $1.1495*x = $1.1495x.
Thus, the total profit to the novelist = (5000 + 1.1495x).
Since the novelist wants to make a minimum profit of $10000, we can show it as the algebraic expression:
5000 + 1.1495x ≥ 10000.
To solve this, we go as follows:
5000 + 1.1495 ≥ 10000,
or, 1.1495x ≥ 10000 - 5000,
or, 1.1495x ≥ 5000,
or, x ≥ 5000/1.1495,
or, x ≥ 4349.717.
Approximating, we get x ≥ 4350.
Thus, 4350 books need to be sold to achieve the wanted profit.
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Use the grouping method to factor the polynomial below completely.
x³ + 2x² + 4x+8
The polynomial equation x³ + 2x² + 4x+8 can be expressed as the method of factor polynomial exists (x² + 4)(x + 2).
What is a factoring method?The factoring process concerns removing factors from an experiment and then using them in the analytical method of factor analysis.
Polynomials exist as expressions with one or more terms with a non-zero coefficient. A polynomial can contain more than one term.
A mathematical expression of one or more additional algebraic terms each of which consists of a constant multiplied by one or more variables presented to a nonnegative integral power.
Given: x³ + 2x² + 4x+8
x³ + 2x² + 4x+8 = 0
simplifying the equation, we get
(x³+2x²)+(4x+8 )= 0
x²(x+2)+4(x+2)= 0
factorizing the above equation, we get
(x+2)(x²+4) = 0
Therefore, the polynomial equation x³ + 2x² + 4x+8 can be expressed as the method of factor polynomial exists (x² + 4)(x + 2).
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Donna has a $300 loan through the bank she is charged a simple rate The total interest she paid on the loan was $63 As a percentage what was the annual interest rate on her loan
Answer:
21%
Step-by-step explanation:
($63*100%) / $300 = 21%
Please help me quick. I don’t understand please give me the answer
Answer:
m = -2
Step-by-step explanation:
to find the answer you must put rise over run
rise is (y2 - y1) and run is (x2 - x1)
lets use the bottom two points for thisd
y2 is 0 and y1 is 2
x2 is 1 and x1 is 0
0 - 2 = -2
1 - 0 = 1
-2/1 = -2
that is the slope
One circle has a circumference of 12x cm. Another circle has a circumference of 32x cm. What is the ratio of the
radius of the smaller circle to the radius of the larger circle?
O 3:8
O 8:3
O 1:3
O 3:1
Answer:
3 :8
Step-by-step explanation:
12 : 32 = 3:8
I believe that is right.
WILL GIVE BRAINLIEST
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
1) 50 mph
2) 70 mph
3) x mph
4) (x+10)mph
5) (x-5)mph
The length of the trip at a distance of 300 miles and the given times are
6 hours30/7 hours300/x hours300/x + 10 hours300/x - 5 hoursHow to determine the length of the trip?The distance is given as:
d = 300
The formula is represented as:
d = r * t
Make t the subject
t = d/r
Substitute 300 for d
t = 300/r
When r = 50 mph,
t = 300/50
Evaluate
t = 60
When r= 70 mph, we have
t = 300/70
Evaluate
t = 30/7
When r = x, we have
t = 300/x
When r = x + 10, we have
t = 300/x + 10
When r = x - 5, we have
t = 300/x - 5
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Complete question
A train traveled 300 miles. How long did the trip take if the train was traveling at a rate of:
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
For a certain company, the cost function for producing x items is C(x)=50x+100 and the revenue function for selling x items is R(x)=−0.5(x−100)2+5,000 . The maximum capacity of the company is 120 items.
The profit function P(x) is the revenue function R(x) (how much it takes in) minus the cost function C(x) (how much it spends). In economic models, one typically assumes that a company wants to maximize its profit, or at least make a profit!
Answers to some of the questions are given below so that you can check your work.
Assuming that the company sells all that it produces, what is the profit function?
P(x)=
Assuming that the company sells all that it produces, The profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.
Profit functionProfit = R-C = -(x-100)^2/2 +5000 - 50x -100 =
-(x^2 -200x +10000)/2 -50x +4900 =
-x^2/2 +100x -5000 +5000 -50x +4900
Collect like terms
-x^/2+50x -100
Hence,
Profit function = P(x)=-0.5x²+50x -100
Maximum profit generating output can be determine by taking the derivative and setting it equal to zero
R-C = -x^2/2 + 50x -100
R'-C' = -x + 50 =0
P(0)x = 50
Maximum profit can be determine by substituting x=50 into the original profit equation, R-C
P(50) =-(1/2)(50)^2 +50(50) -100
P(50)= -1250 + 2500 -100
P(50) = $1150 profit
P(120) =-(1/2)(120)^2 +50(120) -100
P(120)= -3600 + 6000 -100
P(120) = $2300 profit
Therefore the profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.
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Question 19 (5 points) ✔ Saved
Order the following temperatures from coolest to warmest.
1
>
>
>
>
3°C
-7°℃
2°F
262 K
Question 20 (5 points)
The order of temperature values become -16.7°C > -11.15°C > -7°C > 3°C And -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.
According to the statement
we have given that the some values of the temperatures and we have to write it in the order from the coolest to the warmest means in increasing order.
So, For this purpose,
The given values of temperatures are:
3°C , -7°C , 2°F, 262 K
Firstly convert into one form
So, convert all values in Celsius form,
3°C = 3°C
-7°C = -7°C
2°F = -16.7°C
262 K = -11.15°C
Now arrange into the order from coolest to warmest
So, it will become
-16.7°C > -11.15°C > -7°C > 3°C
So, -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.
The order of temperature values become -16.7°C > -11.15°C > -7°C > 3°C And -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.
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A rectangular box is designed to have a square base and an open top. The volume is to be 500in.3 What is the minimum surface area that such a box can have?
The minimum surface area that such a box can have is 380 square
How to determine the minimum surface area such a box can have?Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
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