Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and plenty of light, which reactant would be the limiting reactant?

Answers

Answer 1

H₂O would be the limiting reactant.

Balanced chemical equation:

6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

No. of moles of H₂O = Given mass/ Molar mass

= 238 / 18 = 13.22 moles

Moles of H₂O = 13.22

According to the balanced chemical equation

6 moles of CO₂ react with 6 moles of H₂O

So the reactant that has less number of moles will be consumed first.

As the No. of moles of H₂O < No. of moles of CO₂

So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

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Related Questions

What is the oxidation number of nitrogen in nitrogen gas?
Group of answer choices

A. -2

B. -1

C. -3

D. 0

Answers

Ans: (D) 0
Hope my answer is correct:))

Oliver and Mike put some ice into a container and heat it .

Answers

Answer:

See below

Explanation:

From the graph: initial temp = -10 ° C

melting occurs at 0 ° C (constant temp process)

at '2' the ice is melting.....going from a solid to a liquid at a constant temperature

Given similar concentrations, the stronger acid corresponds to the lower pH. Comment on the relative strengths of the acids H3PO4, H2PO4^– and H2PO4^2–

Answers

Answer:

H3PO4 is stronger than H2PO4- because

H3PO4 dissociation constant is 6.9×10^-3

H2PO4^- dissociation constant is 6.2×10^-8

If the value for ΔS is postive, and the value for ΔH is negative, thr reaction will be
Group of answer choices

A. spontaneous at high temperatures.

B. spontaneous at all temperatures.

C. spontaneous at low temperatures.

D. Δnot spontaneous at all temperatures.

Answers

It follows that the reaction is spontaneous at high temperatures Option A.

What is ΔS ?

The term ΔS is referred to as the change in the entropy of the system. Now recall that entropy is defined as the degree of disorderliness in a system. If a system is highly disorderly then it means that it has a high entropy. Also, ΔH has to do with the heat change that accompanies a reaction.

We know that both the entropy and the heat change can both either be positive or negative. Now we know that the equation ΔG = ΔH - TΔS can be used to ascertain whether or not a reaction will be spontaneous. If the result is negative, then the reaction will be spontaneous.

As such, when then it follows that the reaction is spontaneous at high temperatures Option A.

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In the reaction between CO and Fe3O4 , the theoretical yield in an experiment is calculated to be 47.2 g Fe.

When a chemistry student carries out the experiment, their actual yield is 34.1 g Fe.

Calculate the percent yield (% yield) of Fe

Answers

Answer:

Explanation:

34.1 / 47.2 x 100% = 0.07%

The percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.

How to calculate percent yield?

The percent yield is the percent ratio of the weight of the product obtained to the theoretical yield.

The percent yield can be calculated by dividing the experimental yield by the theoretical yield and multiplying the result by 100 then express the final answer in %.

According to this question, the experimental yield is 34.1g and the theoretical yield is 47.2g. The percent yield can be calculated as follows:

Percent yield = 34.1/47.2 × 100

Percent yield = 72.25%

Therefore, the percent yield (% yield) of Fe in a reaction with CO if the theoretical yield in the experiment is calculated to be 47.2 g Fe is 72.25%.

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