Consider the spiral curves given parametrically by: (see picture and answer question)
Answers
a. The arc length is given by the integral
[tex]L(r) = \displaystyle \int_3^\infty \sqrt{x'(t)^2 + y'(t)^2} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \sqrt{\left(\frac{t\cos(t) - r\sin(t)}{t^{r+1}}\right)^2 + \left(-\frac{t\sin(t) + r\cos(t)}{t^{r+1}}\right)^2} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \sqrt{\frac{(t^2+r^2)\cos^2(t) + (t^2+r^2)\sin^2(t)}{\left(t^{r+1}\right)^2}} \, dt \\\\ ~~~~~~~~ = \boxed{\int_3^\infty \frac{\sqrt{t^2+r^2}}{t^{r+1}} \, dt}[/tex]
b. The integrand roughly behaves like
[tex]\dfrac t{t^{r+1}} = \dfrac1{t^r}[/tex]
so the arc length integral will converge for [tex]\boxed{r>1}[/tex].
c. When [tex]r=3[/tex], the integral becomes
[tex]L(3) = \displaystyle \int_3^\infty \frac{\sqrt{t^2+9}}{t^4} \, dt[/tex]
Pull out a factor of [tex]t^2[/tex] from under the square root, bearing in mind that [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex].
[tex]L(3) = \displaystyle \int_3^\infty \frac{\sqrt{t^2} \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{|t| \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{t \sqrt{1+\frac9{t^2}}}{t^4} \, dt \\\\ ~~~~~~~~ = \int_3^\infty \frac{\sqrt{1+\frac9{t^2}}}{t^3} \, dt[/tex]
since for [tex]3\le t<\infty[/tex], we have [tex]|t|=t[/tex].
Now substitute
[tex]s=1+\dfrac9{t^2} \text{ and } ds = -\dfrac{18}{t^3} \, dt[/tex]
Then the integral evaluates to
[tex]L(3) = \displaystyle -\frac1{18} \int_2^1 \sqrt{s} \, ds \\\\ ~~~~~~~~ = \frac1{18} \int_1^2 s^{1/2} \, ds \\\\ ~~~~~~~~ = \frac1{27} s^{3/2} \bigg|_1^2 \\\\ ~~~~~~~~ = \frac{2^{3/2} - 1^{3/2}}{27} = \boxed{\frac{2\sqrt2-1}{27}}[/tex]
a) The improper integral in simplified form is equal to [tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex].
b) r > 1 for a spiral with finite length.
c) The length of the spiral when r = 3 is (1 - 2√2) / 9 units.
How to characterize and analyze a group of parametric functions
a) The arc length formula for 2-dimension parametric functions is defined below:
L = ∫ √[(dx / dt)² + (dy / dt)²] dt, for [α, β] (1)
If we know that [tex]\dot x (t) = \frac{t \cdot \cos t - r \cdot \sin t}{t^{r+1}}[/tex], [tex]\dot y(t) = \frac{t\cdot \sin t + r\cdot \cos t}{t^{r + 1}}[/tex], α = 0 and β → + ∞ then their arc length formula is:
[tex]L = \int\limits^{\infty}_{3} {\sqrt{\left(\frac{t\cdot \cos t - r\cdot \sin t}{t^{r + 1}}\right)^{2}+\left(\frac{t\cdot \sin t + r\cdot \cos t}{t^{r+1}}\right)^{2}} } \, dt[/tex]
By algebraic handling and trigonometric formulae (cos ² t + sin² t = 1):
[tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex] (2)
The improper integral in simplified form is equal to [tex]L = \int\limits^{\infty}_{3} {\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}} } \, dt[/tex].
b) By ratio comparison criterion, we notice that √(t² + r²) is similar to √t² = t and [tex]\frac{\sqrt{t^{2}+r^{2}}}{t^{r + 1}}[/tex] is similar to [tex]\frac{t}{t^{r +1}} = \frac{1}{t^{r}}[/tex].
The integral found in part a) has a finite length if and only the governing grade of the denominator is greater that the governing grade of the numerator. and according to the ratio comparson criterion, the absolute value of the ratio is greater than 0 and less than 1. Therefore, r > 1 for a spiral with finite length.
c) Now we proceed to integrate the function:
L = ∫ [√(t² + 9) / t⁴] dt, for [3, + ∞].
L = ∫ [t · √(1 + 9 / t²) / t⁴] dt, for [3, + ∞].
By using the algebraic substitutions: u = 1 + 9 / t², du = - (18 / t³) dt → - (1 / 18) du.
L = ∫ √u du, for [3, + ∞].
L = - (1 / 9) · √(u³), for [3, + ∞].
L = - (1 / 9) · [√(1 + 9 / t²)³], for [3, + ∞].
L = - (1 / 9) · [√(2³) - √(1³)]
L = - (1 / 9) · (2√2 - 1)
L = (1 - 2√2) / 9
The length of the spiral when r = 3 is (1 - 2√2) / 9 units.
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Related Questions
Calcular el valor del ángulo que falta de dun triangulo rectangulo si uno de sus lados mide 25 grados.
Answers
Considerando la definición de triángulo rectángulo y sus propiedades, el valor del ángulo que falta de un triángulo rectángulo es 65°.
Definición de triánguloUn triángulo es un polígono que está determinado por tres segmentos de recta que se denominan lados, o por tres puntos no alineados llamados vértices.
En otras palabras, un triángulo es un polígono conformado por tres lados, así como por tres vértices y tres ángulos interiores.
Una de las propiedades de cualquier triángulo indica que la suma de los ángulos interiores es igual a 180°.
Definición de triángulo rectánguloEl triángulo rectángulo es una figura geométrica que se considera como un polígono formado por tres lados que forman un ángulo recto y dos ángulos agudos.
En otras palabras, el triángulo rectángulo es aquel que tiene un ángulo interior que es recto, es decir, mide 90º.
Valor del ángulo faltante en este casoEn este caso, sabes que:
Al ser un triángulo rectángulo, un ángulo interior mide 90°.Otro ángulo interior mide 25°. La suma de los ángulos interiores es igual a 180°.Entonces, el valor del ángulo faltante se puede calcular mediante:
90° + 25° + ángulo faltante= 180°
Resolviendo:
115° + ángulo faltante= 180°
ángulo faltante= 180° - 115°
ángulo faltante= 65°
Finalmente, el valor del ángulo que falta de un triángulo rectángulo es 65°.
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Multiply each of the following(2a-3b)and(a^2+2b^2)
Answers
Answer: [tex]\Large\boxed{2a^3+4ab^2-3a^2b-6b^3}[/tex]
Step-by-step explanation:
Given expression
(2a - 3b) (a² + 2b²)
Apply the FOIL method (First Outer Inner Last)
Please refer to the attachment below for a graphical understanding
= 2a · a² + 2a · 2b² - 3b · a² - 3b · 2b²
Simplify by multiplication
=2 (a · a²) + 4 (a · b²) - 3 (b · a²) - 6 (b · b²)
[tex]\Large\boxed{=2a^3+4ab^2-3a^2b-6b^3}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Answer:
Your answer is 2a³ + 4ab² - 3a²b - 6b³.
Step-by-step explanation:
(2a - 3b) (a² + 2b²)
=2a (a² + 2b²) -3b (a² + 2b²)
=2a.a² + 2a.2b² - 3b.a² - 3b.2b²
=2a³ + 4ab² - 3a²b - 6b³ ans.
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The diagonals of a rectangle enclose an angle of measure 78 degree
. If the perimeter of the rectangle is 36cm, what is its area?
Answers
The area of the rectangle with a perimeter of 36 cm is determined as: 80.1 cm².
What is the Area of a Rectangle?Area of a rectangle = (length)(width).
Given the following:Angle of measure 78 degree enclosed by the diagonals of the rectangle
Perimeter = 36 cm
To find the area, we need to find the length and width of the rectangle using the trigonometric ratios.
A side of the rectangle = x cm
The other side = (36 - 2x)/2 = (18 - x) cm
Angle of the diagonal base = (180 - 78)/2 = 51°
Apply the tangent ratio to find x:
Tangent ratio is tan ∅ = opposite/adjacent side of a right triangle. We have the following,
∅ = 51°
Opposite side = x cm
Adjacent side = (18 - x) cm
Tan 51° = x/(18 - x)
1.235 = x/(18 - x)
1.235(18 - x) = x
22.23 - 1.235x = x
22.23 = x + 1.235x
22.23 = 2.235x
22.23/2.235 = 2.235x/2.235
x = 9.946 cm (one side length)
The other side length = 18 - x = 18 - 9.946 = 8.054 cm
Area of the rectangle = (9.946)(8.054)
Area of the rectangle = 80.1 cm²
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what is the range of the function f (x) = lxl +5?
Answers
The range of the function f(x)= IxI+5 is x+5 for x>=0 and -x+5 for x<0.
Given that the function is f(x)=IxI+5.
We are required to find the range of the function.
Function is relationship between two or more variables expressed in equal to form. In a function each value of x must have a corresponding value of y. The value of x is known as domain of the function and the value of y is known as codomain of the function. Range of a function is a limit of values in which the values of function lies.
Function is f(x)= IxI+5
We know that IxI=x for x>=0 and -x<0.
We have to just put the value of IxI in f(x) to get the range of function.
f(x)=x+5 for x>=0 and -x+5 for x<0.
Hence the range of the function f(x)= IxI+5 is x+5 for x>=0 and -x+5 for x<0.
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How many three-digit positive integers have three different digits and at least one prime digit?
Answers
The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.
The only two components in prime numbers are 1 and the number itself.
Any whole number greater than one is a prime number.
It has exactly two factors—1 and the actual number.
There is just one 2-digit even prime number.
Every pair of prime numbers is always a co-prime.
The product of prime numbers can be used to represent any number.
Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960
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Simplify each expression. Select the correct answer from the drop-down menu.
−6(3i)(−2i) =
2(3 − i)(−2 + 4i) =
Answers
Answer:
Step-by-step explanation
-6(3i)(-2i)=-6(3i*-2i)=-6*-6i²=36i²
2(3-i)(-2+4i)=(6-2i)(-2+4i)=-12+24i+4i-8i²=-8i²+28i-12
Answer:
1. -36
2. -4+28i
3. 10+8i
Step-by-step explanation:
EDGE2022
How is a marketing -oriented firm different from a production-oriented firm or a sales-oriented firm?
Answers
Marketing-oriented firms focus more on what the market needs above every other aspects.
What is a Marketing-oriented Firm?Marketing-oriented firms can be described as firms that major in identifying the needs and wants of customers and then creating specific products that are designed to meet the wants of such customers. One of the important elements of marketing-oriented firms is to ensure there is a demand for whatever products or services they offer.
Some examples of marketing-oriented firms are:
AppleCoca-ColaAmazonWhat is a Product-oriented Firm or a Sales-oriented Firm?A product-oriented firm focus more resources on and focus on researching and developing quality products rather than focusing more on the market to discover the wants of customers.
Sales-oriented firm tend to focus more on developing its sales force that will promote their products and services.
How Marketing-Oriented Firms are Different from the Product-oriented or Sales-oriented Firms?Marketing-oriented firms stand out and are different from the other two types of firms because they focus more on what the market needs above every other aspects.
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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. It goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). Which graph represents g(x)? On a coordinate plane, a parabola opens up. It goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10). On a coordinate plane, a parabola opens up. It goes through (2, 8), has a vertex at (5, negative 11), and goes through (8, 8). On a coordinate plane, a parabola opens up. It goes through (negative 8, 10), has a vertex at (negative 5, 1), and goes through (negative 2, 10).
Answers
The graph is shown in the attached image.
Find (g*f)(3)
f(x)= 7x + 8
g(x)= -1/x
Answers
Answer:
-21-24/x
Step-by-step explanation:
f(x) is a function on his own which is f(x)=7x+8
we multiple it with another function which is g(x)=-1/x
that gives us (g*f)=-7-8/x
then multiple it by 3 we have -21-24x
please help this is affecting my grade pls help i beg of you <3
Answers
Answer:
C - On the number line, move 3 units to the left. End at -7. The dolphin was 7 feet below sea level.
Step-by-step explanation:
The dolphin's starting point was -4 (4 feet below sea level). If the dolphin if diving down by 3 feet, you add -3 to its starting point.
-4 + -3 = -7.
Can anyone please help me with this assignment
Answers
1. The sentences translated to equations looks like:
a) 4x = 32.
b) x + 6y = 43.
c) 3x + 7 = 9x - 4.
d) 76 - 2x = 8x.
2. The equations translated to sentences looks like:
a) The sum of 16 and 9 times x is 50.
b) The sum of the square of x and 6 times y is 4 times w.
c) Three times x is 52.
d) Five-sixth is equal to the product of -10 and x.
Practice Part 1: Translate sentence to equation
a)Four times a number is thirty-two.
Assuming the number to be x, we get the equation, 4x = 32.
b)The sum of and six times is equal to forty-three.
The sentence, when translated to an equation looks like, x + 6y = 43.
c)The sum of 7 and three times equals the difference of 9 times and 4.
The sentence, when translated to an equation looks like, 3x + 7 = 9x - 4.
d)Two times less than 76 is equal to the product of 8 and
The sentence, when translated to an equation looks like, 76 - 2x = 8x.
Practice Part 2: Translate equation into sentence
a) 9x + 16 = 50.
- The sentence for the given equation is, the sum of 16 and 9 times x is 50.
b) x² + 6y = 4w.
- The sentence for the given equation is, the sum of the square of x and 6 times y is 4 times w.
c) 3x = 52.
- The sentence for the given equation is, three times x is 52.
d) 5/6 = -10x.
- The sentence for the given equation is, five-sixth is equal to the product of -10 and x.
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Consider the line 3x - 4 y = 7.
What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?
Answers
Answer:
The slope of a line perpendicular to this line is -1/3. The slope of a line parallel to this line would be 3.
Step-by-step explanation:
Perpendicular lines have opposite(sign) and reciprocal slopes.
Parallel lines have the same slope.
En la final de un concurso escolar de
matemática participan 6 alumnos de los
cuales 3 son alumnos del colegio A. Si se
premia a los dos primeros con regalos
diferentes, entonces la probabilidad de que
los alumnos del colegio A obtengan los dos
premios (no hay empates), es:
Answers
Usando la distribución hipergeométrica, la probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es: 0.2 = 20%.
¿Qué es la fórmula de distribución hipergeométrica?La fórmula es:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Los parámetros son:
x es el número de éxitos.N es el tamaño de la población.n es el tamaño de la muestra.k es el número total de resultados deseados.Los valores de los parámetros son:
N = 6, k = 3, n = 2.
La probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es P(X = 2), por eso:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 2) = h(2,6,2,3) = \frac{C_{3,2}C_{3,0}}{C_{6,2}} = 0.2[/tex]
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thank you for helping
Answers
Explanation:
Step 1:
A triangle equals 180 and we already know two angles so we add 40 plus 45 which equals 85 then subtract 85 from 180 to find the missing angle which equals 95
Step 2: Now since we know the missing angle we use the straight line rule which states:Any straight line equals 180.and under close examination we see the 95 degree angle forms a straight line with the exterior angle so we subtract 95 from 180 and we get 85
50 POINTS PLEASE HELP I NEED ANWSER NOW what would the reflection look like
Answers
Answer:
Point C will be at (3,1), Point B will be at (7,1) and Point A will be at (7,5)
Step-by-step explanation:
Divide. write your answer in simplest form. 7/9 divided by 8/15
Answers
Explanation:
7/9 divided by 8/15 can also be written as 7/9 x 15/8. We multiply the top and the bottom. It would look like 7x15/9x8. That equals 105/72. Simplified it is 35/24
Answer:
Step-by-step explanation:
7/9 * 15/8 = 105/72 = 35/24
The formula for the perimeter of a rectangle is 2L + 2W = P (L = length, W = Width and P = Perimeter.) The perimeter of a rectangular garden is 400 feet. If the length of one side of the garden is 120 feet, what is the width of one side of the garden?
Answers
We conclude that the width of the rectangular garden is 80 feet.
How to get the dimensions of the garden?Let's define the variables:
L = length of the garden.W = width of the garden.The perimeter of a rectangle of length L and width W is given by the simple formula:
P = 2*(L + W)
The perimeter is equal to 400ft, then:
400ft = 2*(L + W)
And we know that the length is 120ft, then:
L = 120ft.
Replacing the length in the perimeter equation we get:
400ft = 2*(120ft + W)
Now we can solve this linear equation for W.
400ft/2 = 120ft + W
200ft = 120ft + W
200ft - 120ft = W
80ft = W
We conclude that the width of the rectangular garden is 80 feet.
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How many three-digit positive integers have three different digits and at least one prime digit?
Answers
Answer:
252
Step-by-step explanation:
using a brute force method in c++
#include <stdio.h>
int main(){
int a, b, c, n = 0;
for(a = 1; a <= 9; a++)
for(b = 0; b <= 9; b++)
for(c = 0; c <= 9; c++)
if((a==3 || b==3 || c==3)) n++;
printf("%d\n", n);
}
The points
(−1.2,2.9) and (2.9,9.46) are on the graph of a linear relationship between two variables, x and y
Write a formula that expresses
y in terms of x
What is the value of y when x=115
Answers
[tex](\stackrel{x_1}{-1.2}~,~\stackrel{y_1}{2.9})\qquad (\stackrel{x_2}{2.9}~,~\stackrel{y_2}{9.46}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9.46}-\stackrel{y1}{2.9}}}{\underset{run} {\underset{x_2}{2.9}-\underset{x_1}{(-1.2)}}}\implies \cfrac{6.56}{2.9+1.2}\implies \cfrac{6.56}{4.1}\implies 1.6[/tex]
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2.9}=\stackrel{m}{1.6}(x-\stackrel{x_1}{(-1.2)}) \\\\\\ y-2.9=1.6(x+1.2)\implies y-2.9=1.6x+1.92\implies \boxed{y=1.6x+4.82} \\\\\\ \textit{when x = 115, what is "y"?}\qquad y=1.6(115)+4.82\implies y=188.82[/tex]
David rented a truck for one day. There was a base fee of $17.99, and there was an additional charge of 84 cents for each mile driven. David had to pay $250.67 when he returned the truck. For how many miles did he drive the truck?
Answers
Answer:
277 miles
Step-by-step explanation:
This graph represents a quadratic function. An upward parabola on a coordinate plane vertex at (minus 2, 2) and passes through (minus 3, 5) and (minus 1, 5). What is the value of a in the function’s equation? A. -2 B. -3 C. 2 D. 3
Answers
Answer: 3
Step-by-step explanation:
Substituting into vertex form, the equation is
[tex]y=a(x+2)^2 +2[/tex]
Substituting in the coordinates (-3, 5),
[tex]5=a(-3+2)^2 +2\\\\5=a+2\\\\a=3[/tex]
Suppose that 5 workers can complete a certain task in 12 days. If there are 4 workers, how many days would it take for them to finish the same task
Answers
Answer:
15 days
Step-by-step explanation:
5 workers times 12 days is 60 days per worker which gets reduced based on how many workers there are. 60 divide by 4 workers now brings down to 15 days. 5 workers, 12 days. 10 workers 6 days etc.
Attached as an image. Please help.
Answers
The general solution of the logistic equation is y = 14 / [1 - C · tⁿ], where a = - 14² / 3 and C is an integration constant. The particular solution for y(0) = 10 is y = 14 / [1 - (4 / 10) · tⁿ], where n = - 14² / 3.
How to find the solution of an ordinary differential equation with separable variablesHerein we have a kind of ordinary differential equation with separable variables, that is, that variables t and y can be separated at each side of the expression prior solving the expression:
dy / dt = 3 · y · (1 - y / 14)
dy / [3 · y · (1 - y / 14)] = dt
dy / [- (3 / 14) · y · (y - 14)] = dt
By partial fractions we find the following expression:
- (1 / 14) ∫ dy / y + (1 / 14) ∫ dy / (y - 14) = - (14 / 3) ∫ dt
- (1 / 14) · ln |y| + (1 / 14) · ln |y - 14| = - (14 / 3) · ln |t| + C, where C is the integration constant.
y = 14 / [1 - C · tⁿ], where n = - 14² / 3.
If y(0) = 10, then the particular solution is:
y = 14 / [1 - (4 / 10) · tⁿ], where n = - 14² / 3.
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The following diagrams show six lines with equations of the form y =mx +c
I have the answers but I do not know how to FIND the right one. Please help!
Answers
Answer:
understand the meaning of m > 0 and c > 0.
Step-by-step explanation:
The slope-intercept form of the equation of a line tells you its slope and its y-intercept.
y = mx +c . . . . line with slope m and y-intercept c
Slope (m)The slope is the rate of increase moving from left to right. It is positive (m>0) when the line slants upward to the right. It is negative (m<0) when the line slants down to the right.
m > 0: lines 3, 5, 6m < 0: lines 1, 2, 4Y-intercept (c)The y-intercept is where the line crosses the (vertical) y-axis. It is positive (c>0) when the line crosses above the x-axis, where y-values are positive. It is negative (c<0) when the line crosses below the x-axis. If the line passes through the origin, then c=0.
c > 0: lines 4, 5c < 0: lines 1, 3c = 0: lines 2, 6Circle A has center of (6, 7) and a radius of 4, and circle B has a center of (2, 4) and a radius of 16. What steps will help show that circle A is similar to circle B? (5 points)
Answers
Circle A has center of (6, 7) and a radius of 4, and circle B has a center of (2, 4) and a radius of 16. Now, in order to show that circle A is similar to circle B, we will have to dilate circle A by a scale factor of 4. We can use transformations like dilation and translation to make two circles similar.
Given Information:
For circle A,
Center, C1(x, y) = (6, 7)
Radius, r1 = 4
For circle B,
Center, C2(x, y) = (2, 4)
Radius, r2 = 16
Showing the Two Circles Similar
Now, to make circles A and B similar, we will have to make their centers coincide. It can be done by following the steps listed below:
First, translate circle A using the rule (x + 4, y + 3).Then, rotate circle A by 45° about the center.In the third step, dilate circle A by a scale factor of 4 (r2/r1).Finally, Reflect circle A about the origin to make it similar to circle BHence, we can now see that circle A is similar to circle B.
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A company has two large computers. The slower computer can send all the company's email in 60 minutes. The faster computer can complete the same job in 15 minutes. If both computers are working together, how long will it take them to do the job?
Do not do any rounding
Minutes =
Answers
Answer:
15.25 given using both
Step-by-step explanation:
Slow com= 60 all mail
Fast clm= 15 all mail
Given both bejng used
60 min ÷ 15 min = intervall of 4 unbroken min
and
15min÷60min= 0.25
0.25mjn×60sec= 15sec
Sret =15min anfd 15 seconds/ 15.25min
Factor the common factor out of 8^3 + 12x
Answers
The factorized expression of 8^3 + 12x is 4(128+ 3x)
How to factor the common factor out?The expression is given as:
8^3 + 12x
Evaluate 8^3
8^3 + 12x = 512 + 12x
Factor out 2 from the expression
8^3 + 12x = 2(256+ 6x)
Factor out 2 from the expression
8^3 + 12x = 2 * 2(128+ 3x)
Evaluate the product
8^3 + 12x = 4(128+ 3x)
Hence, the factorized expression of 8^3 + 12x is 4(128+ 3x)
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$2,870 per month. He pays $574 a month for rent. What percent of his monthly pay goes to rent?
Answers
we know that 2870 is the 100%, what is 574 off of it in percentage?
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 2870 & 100\\ 574& x \end{array} \implies \cfrac{2870}{574}~~=~~\cfrac{100}{x} \\\\\\ 5=\cfrac{100}{x}\implies 5x=100\implies x=\cfrac{100}{5}\implies x=20[/tex]
The percent of his monthly pay which goes to rent if he earns a total of $2,870 per month is 20%.
What percent of his monthly pay goes to rent?Amount earned per month = $2,870
Amount paid for rent = $574
Let
The unknown percent = x
x% of $2,870 = $574
x/100 × 2,870 = 574
2,870x/100 = 574
cross product
2,870x = 57,400
divide both sides by 2,870
x = 57,400/2,870
x = 20%
Ultimately, 20% of the monthly pay goes to rent.
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polygon h is a scaled factor of polygon g using a scale factor of 1/4
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The fraction of the area of polygon H of polygon G's area would be: 1/16.
What are Similar Polygons?When a polygon is formed by enlarging or reducing an original polygon by a scale factor, the new polygon formed is similar to the original polygon.
What is a Scale Factor?The scale factor = new dimension/original dimension
Given that polygon H is the new polygon formed when polygon G is reduced by a scale factor of 1/4, thus, we would have the following:
Area of polygon H/Area of polygon G = square of the side of polygon H/square of the side of polygon G = square of the scale factor of dilation
Area of polygon H/Area of polygon G = 1²/4² = 1/16
This implies that the area of polygon G is 16 units² while the area of polygon H is 1 units².
Thus, the fraction of the area of polygon H of polygon G's area would be: 1/16.
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I need help solving this problem!
Answers
Answer: A
Step-by-step explanation:
The domain is the range of possible x that doesn't make y impossible to find, in this case, all real numbers work
The range is the range of possible y that doesn't make x impossible to find in the inverse function, in this case, all real numbers work
The answer is A.
As any number can be replaced in place of x for the function y, the domain of the function is All Real Numbers. Since any number can be inputted, the result will also vary accordingly. Hence, the range of the function is All Real Numbers.
This is true for the listed function :
[tex]\boxed {y = \sqrt[3]{x-2} - 5}[/tex]