Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X. Arc X Z is 105 degrees and arc W Z is 175 degrees.

In the diagram of circle A, what is the measure of ∠XYZ?
35°
70°
75°
140°


Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X. Arc X Z is 105 degrees and arc W Z is 175 degrees.

In the diagram of circle A, what is the measure of ∠XYZ?
35°
70°
75°
140°

What this has to signify would be the fact that there is a the spread of a stimulus through the ventricles.

This is used to refer to the term that has to do with the combination of the different types of waves. These are the Q wave, the R wave as well as the S wave. This is used in ECG measurement. It has to do with the measurement of the chambers of a person heart to check its normal function.

When the ECG are in this category, it can be regarded as a high. This may put a person to have the more likelihood of having a death that is caused by coronary diseases.

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Answer:51 crates could have 12 oranges and one crate could hold 11 oranges.

Step-by-step explanation: 623 / 12 is 51.9... 51 x 12 is 612. 612 + 11 is 623 math checks out.

Answer:

Start with equation,

         y''(x) = f(x) = 6y/(10x-x²)               about point x₀ = 5

Then,

       y(x) = a₀ + a₁(x-5) + a₂(x-5)²+ a₃(x-5)³ + a₄(x-5)⁴...….

by inspection,

           y(5) = a₀      and       y'(5) = a₁

then,

y''(5) = 6a₀/(50-25) = 6a₀/25              

y'''(x) = 6y'/(10x-x2) - 6y(10-2x)/(10x-x2)2

then,                      

                              y'''(5) = 6a₁/25 - 0 = 6a₁/25                

y''''(x) = 6y''/(10x-x2) -12y'(10-2x)/(10x-x2)² + 12y/(10x-x2)² + 12y(10-2x)2/(10x-x2)³

then,

    y''''(5) = (6/25)(6a₀/25) + 0 + 12a₀/625 + 0

              = 48a₀/625

So,

y(x) = f(x) = f(5) + f'(5)(x-5) + f''(5)(x-5)2/2! + f'''(5)(x-5)3/3! + f''''(5)(x-5)4/4! …

                                                       or

y(x) = f(x) = a₀ + a₁(x-5) + (6ao/25)(x-5)2/2! + (6a1/25)(x-5)3/3! + (48a₀/625)(x-5)4/4!...

                                                         or

y(x) = f(x) = a₀ + a₁(x-5) + (3a₀/25)(x-5)²+ (a₁/25)(x-5)³+ (2a₀/625)(x-5)⁴.....

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Answer:

B

Step-by-step explanation:

- 6x + 3 ≥ 21 ( subtract 3 from both sides )

- 6x ≥ 18

divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.

x ≤ - 3

The surface area of the triangular prism is of 162 cm².

The surface area of a prism is given by the sum of all the areas of the prism.

This prism is composed by:

For a rectangle, the area is the multiplication of the dimensions, hence:

A1 = 10 x 15 = 150 cm².

For a right triangle, the area is half the multiplication of the sides, hence:

A2 = 0.5 x 6 x 4 = 12 cm².

Hence the surface area is:

A = A1 + A2 = 150 cm² + 12 cm² = 162 cm².

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Answer: [tex]g(x)=2^{x-3}[/tex]

Step-by-step explanation:

The graph of y=g(x) is the graph of y=f(x) shifted 3 units right.

Considering the situation described, the classification of the elections is given as follows:

We take the situation that is described, and build the classification from it. The classification has the following format:

P1 - P2 - P3 - P4 - P5

With P1 being the first placed candidate, P2 being the second placed candidate, and so on until P5 which is the fifth placed candidate.

From the text given in this problem, we have that:

Hence the places of each candidate are given as follows:

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The slope of the line is 8.5 and the y-intercept is at the origin as shown in the graph below.

A linear function is a function that has a leading degree of 1. The standard equation for a linear function is expressed as:

y = mx + b

where

m is the slope which is equal to the rate of change of y coordinate to x-coordinates.

b is the y-intercept

Given the following equation

y=8.5x

The slope of the line is 8.5 and the y-intercept is at the origin as shown in the graph below.

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Answer:

? = 4 units

Step-by-step explanation:

'2'  is to  ' 7+2 '     as  ?   is to   '14 + ? '

2/ 9 = ? / (14 + ?)      cross mutiply

28 + 2? = 9?

28 = 7?

? = 4

The approximate number of text messages sent in 2011 is 2 x 10^1.

Scientific notation is used in expressing large numbers in smaller numbers. To write a number in scientific notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.

118, 000, 000, 000 in scientific notation is 1,18 x 10^11

2,357, 000, 000, 000 in scientific notation is 2.357 x 10^12

Difference in messages sent in 2011 compared to 2005 : (2.357 / 1.18) x 10^(12 - 11)

2 x 10^1

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Answer:

Hey there!

Step-by-step explanation:

This is ur answer...

Hope it helps!

Brainliest pls!

Have a good day!^^

The equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

The expression is given as:

21√(3)(15) - 9√(3)(15)

Express 15 as 3 * 5

21√(3)(15) - 9√(3)(15) = 21√(3)(3 * 5) - 9√(3)(3 * 5)

Evaluate the product of 3 and 3

21√(3)(15) - 9√(3)(15) = 21√(9 * 5) - 9√(9 * 5)

Take the square root of 9

21√(3)(15) - 9√(3)(15) = 21*3√(5) - 9*3√5)

Evaluate the product

21√(3)(15) - 9√(3)(15) = 63√(5) - 27√5)

Evaluate the difference

21√(3)(15) - 9√(3)(15) = 36√5

Hence, the equivalent expression of 21√(3)(15) - 9√(3)(15) is 36√5

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Answer:

D

Step-by-step explanation:

If those two functions are the factors of a quadratic, then each of them can be equated to 0 to find the roots. Sometimes the roots are called the zeros.

2x - 5 = 0                       Add 5 to both sides

2x - 5 + 5 = 0 + 5           Combine

2x = 5                             Divide both sides by 2

2x/2 = 5/2

x = 5/2

You don't really have to find the other factor's 0 point. There is only 1 option that makes x = 5/2. On a test, it is important to take short cuts and save time.  I'll find the other root anyway because this is not a test.

3x + 4 = 0                           Subtract 4 from both sides

3x + 4-4 = 0 - 4                  Combine

3x = - 4                               Divide both sides by 3

3x/3 = - 4/3

x = - 4/3

Answer: 797.4 m²

Step-by-step explanation:

The surface area is just the total of the areas of each face of of a solid. In this solid, we have 2 triangles and 3 rectangles.

We know that the two triangles of this solid are congruent, so they will have the same area. Since the area of a triangle is [tex]\frac{1}{2}bh[/tex], two triangles would have an area of [tex]bh[/tex]. Hence, the total area is

[tex]A=9 * 15\\A=135[/tex]

The area of a rectangle is lw, where l is the length and w is the width. Let's find the total area of all of them.

[tex]A=9*16+15*16+17.4*16[/tex]

All of the areas are a product of some number and 16. This makes sense as the length of this prism is 16. We can un-distribute this 16 to make the calculation easier.

[tex]A=16(9+15+17.4)\\A=16(41.4)\\A=662.4[/tex]

We can add both totals to get the total surface area of the solid.

[tex]135+662.4\\=797.4[/tex]

The surface area of this right triangular prism is 797.4 m².

Answer:

Step-by-step explanation:

RM 280 = 40% of 8 months

RM 700= 100% of 8 months

RM 700/8= 8 months

RM 87.5 = 1 month

Answer = 87.5

Farid's monthly salary is approximately RM 87.5. He spends 40% of his total 8-month expenditure on house rent, which amounts to RM 280 per month.

Let's assume Farid's monthly salary is RM x.

Given that he spends 40% of his total 8 monthly expenditure on house rent, and the amount he spends on house rent is RM 280, we can set up the following equation:

0.40 × 8x = 280

Now, let's solve for x:

0.40 × 8x = 280

3.2 × x = 280

x = 280 / 3.2

x ≈ 87.5

So, Farid's monthly salary is approximately RM 87.5.

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Answer:

$6.07/hr. if I understand the question properly.  See below.

Step-by-step explanation:

I don't see the question, but will assume we want to find Larisa's base pay.  The $7/hr given is the average for the work sequence noted in the problem.  If this is incorrect, ignore the answer.

==================================

Let x be Larisa's base salary.  We are told, I think, that in one stretch of time Larisa earned an average of $7/hour.  That was composed of:

Hours  Rate($/hr)

  40           x

    3        1.5x

    6         2x

  49

Her total income over this period would be:

40x +3(1.5x) + 6(2x)  [The hours worked times the pay rate for each period]

Her average income per hour would be:

(40x +3(1.5x) + 6(2x))/49

which we are told is $7/hr.

(40x +3(1.5x) + 6(2x))/49 = 7

40x + 4.5x + 12x = 343

56.5x = 343

x = $6.07/hr

Answer:

I would use equation d

Step-by-step explanation:

because need to find out X which is the second section so you would do 60 subtract 35 which gives 25 so X would be 25 .

I hope this helped . if you need any more help pls ask :)

pls give brainliest if you like my answer :)

What is an algebraic expression?

An expression that is made up of variables and constants, along with algebraic operations like addition, subtraction, etc.

What is the substitution method?

The substitution method is generally used to solve the system of equations. In this method, first, solve the equation for one variable, and substitute the value of the variable in the other equation

5th question :

⇒ x(2y-x)²+2x²(x-2y)

let (x-2y) = A

⇒we can also write (2y-x)² as (x-2y)² as both have the same value

x(x-2y)²+2x²(x-2y)

x(A)²+2x²(A)

By taking xA common

⇒ xA(A+2x)

On putting the value of A=(x-2y)

⇒ x(x-2y) (x-2y+2x)

⇒x(x-2y) (3x-2y)

6th question :

2(x-y)-(y-x)²

let (x-y) = B

⇒we can also write (y-x)² as (x-y)² as both have the same value

2(x-y)-(x-y)²

2B-(B)²

By taking B common

⇒ B(2-B)

On putting the value of B=(x-y)

⇒(x-y) (2-{x-y})

⇒(x-y) (2-x+y)

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[tex](\stackrel{x_1}{-10}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{-9}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-9}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-10)}}} \implies \cfrac{-9 +7}{-5 +10} \implies \cfrac{ -2 }{ 5 }\implies -\cfrac{2}{5}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{(-10)}) \\\\\\ y+7=-\cfrac{2}{5}(x+10)\implies y+7=-\cfrac{2}{5}x-4\implies y=-\cfrac{2}{5}x-11[/tex]

60 ÷ 30 = 2

and

90 ÷ 30 = 3

---> 60/90 = 2/3

❄ Hi there,

the way 60/90 becomes 2/3 is this:

[tex]\sf{\dfrac{60\div30}{90\div30}=\dfrac{2}{3}}[/tex]

That's it!

❄

The measure of the angle <JKL is 56 degrees

The theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

Given the following parameters

m<IL = 112 degrees

Since the measure of the vertex is half the measure of its intercepted arc, hence;

<JKl = 1/2(m<IL)

Substitute the given parameters into the formula to have;

<JKl = 1/2(112)

<JKL = 56 degrees

Hence the measure of the angle <JKL is 56 degrees

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Answer: [tex]x=-5, -3[/tex]

Step-by-step explanation:

[tex]x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3[/tex]

The perimeter of quadrilateral ABCD will be 26 units.

It should be noted that we want to measure the length of each side of ABC, and use those lengths to calculate the perimeter of ABC.

This will be 10, 5, 5, and 6. Therefore the perimeter will be the addition. This will be:

= 10 + 5 + 5 + 6

= 26 units.

This also was identical to the result gotten. This is attached below.

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The bucket number 2 will contain 45 after sorting the data.

According to the statement

we have given that the a data list which is sorted into 4 buckets then we have to find he in which the umber 45 is sorted.

So, For this purpose,

The given data list is:

76, 56, 93, 24, 45, 88, 13, 7, 37

And the data is sorted into the buckets so,it is sorted in 4 buckets. and the data contain numbers from 0 to 100.

So, let the sorting.

We know that the 100 numbers are sorted in 4 buckets then it means each bucket contain 25 numbers.

So, let us consider a

BUCKET 1 : 0 to 25

it contains the data number 7, 13,24.

Now,

BUCKET 2 : 25 to 50

it contains the data number 37,45.

Now,

BUCKET 3 : 50 to 75

it contains the data number 56.

Now,

BUCKET 4 : 75 to 100

it contains the data number 76, 88, 93.

From sorting the 45 number sort in the bucket 2.

So,The bucket number 2 will contain 45 after sorting the data.

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Answer: Your answers are

A. 1, 287 ways

B. 154,440 ways

Hope this helped :D

Please mark me brainliest

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

We have to evaluate [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex]

By using partial fractions, evaluate the integral

Let [tex]\frac{1}{s^{2}(s-1)^{2} } =\frac{A}{s} +\frac{B}{s^{2}} +\frac{c}{s-1} +\frac{D}{(s-1)^{2} }[/tex]

[tex]1=As(s-1)^{2} +B(s-1)^{2} +Cs^{2}(s-1)+Ds^{2}[/tex]

Put s = 0, 1 = B.1 ⇒ B = 1

Put s= 1, 1 = D ⇒ D = 1

Put s = -1, [tex]1=A(-1)(-2)^{2} +B(-2)^{2} +C(-1)^{2} (-2)+D(-1)^{2}[/tex]

1 = -4A + 4B -2C + D

1 = -4A + 4 -2C + 1

-4 = -4A -2C

2 = 2A + C----------------(1)

Put s = 2, 1 = A(2) + B +C(4) +D(4)

1 = 2A + 1 + 4C +4

-4 = 2A + 4C

-2 = A + 2C---------------(2)

From(1),

C = 2 -2A ---------------(3)

From (2),

⇒ -2 = A + 4 -4A

⇒ -6 = -3A ⇒ A = 2

From (3)

C = 2 - 2(2)

⇒ C = -2

Thus [tex]\int \frac{ds}{s^{2}(s-1)^{2} }= \int (\frac{2}{s} +\frac{1}{s^{2} }- \frac{2}{s-1} +\frac{1}{(s-1)^{2} } )ds[/tex]

= [tex]2 ln|s|-\frac{1}{s} -2ln|s-1|-\frac{1}{s-1}+c[/tex]

= [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex]

Thus,

Solution of integral  [tex]\int \frac{ds}{s^{2}(s-1)^{2} }[/tex] is  [tex]2ln|\frac{s}{s-1}|-\frac{1}{s}-\frac{1}{s-1}+c[/tex].

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