Carbonyl chloride, also called phosgene, was used in World War 1 as a poisonous gas. The equilibrium concentrations for the reaction between carbon dioxide and molecular chlorine to form carbonyl chloride

CO(g) + Cl2(g) <--> CoCl2(g)

are [CO] = 1.2 x 10-2 M, [Cl2] = 0.054 M, and [CoCl2] = 0.14 M. Calculate the equilibrium constant (K).







Group of answer choices

A. K = 4.63 x 10-3

B. K = 216

C. K = 2.56

D. K = 6.23 x 102

Answers

Answer 1

From the calculations, the equilibrium constant is 216. Option B

What is the equilibrium constant?

The equilibrium constant can depict the amount of reactants that is converted into products at a given time. We know that if thus number is large and positive, then it means that the reaction would proceed to the right.

Thus, we have the equation of the reaction as; CO(g) + Cl2(g) <--> CoCl2(g) and we know that;

K = [CoCl2]/ [CO]  [Cl2]

[CoCl2] = concentration of CoCl2

[CO] = concentration of CO

[Cl2] concentration of Cl2

Substituting the values into the equation;

K = 0.14/  1.2 x 10-2 *  0.054

K = 216

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Related Questions

Heating up a reaction does which of the following:
Group of answer choices

A. Increases the number of collisions as well as the strength of the collision

B. Increases the strength of the collisions only.

C. Increases the number of collisions only.

D. No effect is found on the reaction by increasing the temperature.

Answers

Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

What is Collision Theory ?  

According to the collision theory, the reaction take place when the collision occur and molecules having sufficient energy or threshold energy for collision.

The collision of molecules depend on the kinetic energy of molecules. Greater the kinetic energy greater the number of molecules collide. Lesser the kinetic energy lesser will be collision.

How temperature affect the collision theory ?

With an increase in temperature, there is an increase in energy that can be converted into activation energy in a collision, and that will increase the reaction rate. A decrease in temperature would have the opposite effect. With an increase in temperature, there is an increase in the number of collision.

Thus from the above conclusion we can say that Heating up a reaction does increase the number of collision only.

Hence, Option C is correct answer.

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A sample of a gas (15.0 mol) at 2.0 atm is expanded at constant temperature from 5 L to 19.5 L. calculate the final pressure.​

Answers

Answer:

.512 ATM

Explanation:

P1V1 = P2V2

2 * 5   =  P2 * 19.5

P2 = .512 ATM

4 Fe(s) + 3 02(g)
--> 2 Fe₂O3(s)
1. What is the oxidation state of iron (Fe) in the reactant Fe(s)?
2. What is the oxidation state of oxygen (O) in the reactant O2(g)?
3. What is the oxidation state of iron (Fe) in the product Fe2O3(s)?
4. What is the oxidation state of oxygen (O) in the product Fe2O3(s)?
5. In this reaction, iron is... (oxidized or reduced?)
6. In this reaction, oxygen is... (oxidized or reduced?)
7. What was the oxidizing agent in this reaction: Fe(s) or O2(g)?

Answers

The oxidation number of reactant Fe is 0 while the  oxidation number of iron in the product is +3

What s a redox reaction?

The term redox reaction implies a reaction in which there is an increase in the oxidation number of a specie and the decrease in the oxidation number of another specie.

Now we have the answers as follows;

1) The oxidation number of reactant Fe is 0

2) The oxidation number of reactant oxygen is 0

3) The oxidation number of iron in the product is +3

4) The oxidation number of oxygen in the product is -2

5). Iron is oxidized in the reaction

6) Oxygen is reduced in the reaction

7) The oxidizing agent in this case is the oxygen atom

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In the reaction:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

How does the equilibrium shift if the HCl concentration is increased?

Group of answer choices

A. To the reactants

B. No change will occur

C. To the products

D. The equilibrium will initially shift but eventually be uneffected.

Answers

The equilibrium shift if the HCl concentration is increased to the product.

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

What is effect of concentration on equilibrium?

If the concentration of a substance is changed, then the equilibrium will shift in such a way that it minimise the effect of change which occur. If we increase the concentration of a reactant, then the equilibrium will shift to minimize the changes in the direction of the reaction which uses the reactants, so that the reactant concentration decreases.

Factor affecting concentration of reactionThe temperature: As we increasing the temperature, the average speed of the reactant molecules also increases. As many molecules move faster, the large number of molecules moving fast enough to react increases, make the faster formation of products.pressure and concentration of the system are the factors which affect equilibrium.

Thus, we concluded that with increase in the concentration of reactant equilibrium shift forward.

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What is the oxidation state of oxygen (O) in the reactant O2(g)?

Answers

Answer:0

Explanation:

Since oxygen gas i.e., diatomic oxygen exists in the atmosphere in the free state, hence the oxidation state of each atom will be 0

#44) Draw the complete chemical equation for the hydrohalogenation reaction of 1-
pentene by HBr. You must show the structures in your reaction; you may NOT use
molecular formulas!

Answers

Hydrohalogenation Reaction:

The substitution of hydrogen and halide levels across a double bond takes place. The halide group is connected to the carbon with more substituents. The product will affect by the presence of peroxide

What is the hydrohalogenation reply with example?

Ethene is a symmetrical alkene having two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon particles on either side of the double bond.

What is the hydrohalogenation reaction with example?

Ethene is a symmetrical alkene including two carbon atoms. It reacts with HBr in the presence of CCl4, producing bromoethane or ethyl bromide (CH3CH2Br). Propene is an unsaturated alkene consisting of a three-carbon chain with two carbon atoms on either flank of the double bond.

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what is the purpose of adding concentrated phosphoric acid to the reaction mixture in the synthesis of aspirin

Answers

Concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

What is the phosphoric acid?

Phosphoric acid is an inorganic acid with the molecular H₃PO₄.

Its a triprotic acid which means that one molecule of the acid produces 3 molecules of hydrogen ions.

Phosphoric acid is important for many laboratory as well as industrial uses. It can be serve as buffer in living organisms.

It also used in the synthesis of aspirin.

The synthesis of aspirin requires an acidic environment. Therefore, concentrated phosphoric acid is added to the reaction mixture in the synthesis of aspirin to maintain the acidic environment and to keep the reagents protonated.

In conclusion, Phosphoric acid ensures an acidic environment in the synthesis of aspirin.

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Urgent!!!


A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the calorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.

Answers

The specific heat of the metal, given the data from the question is 0.60 J/gºC

Data obtained from the question

The following data were obtained from the question:

Mass of metal (M) = 74 gTemperature of metal (T) = 94 °CMass of water (Mᵥᵥ) = 120 g Temperature of water (Tᵥᵥ) = 26.5 °C Equilibrium temperature (Tₑ) = 32 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of metal (C) =?

How to determine the specific heat capacity of the metal

The specific heat capacity of the sample of gold can be obtained as follow:

According to the law of conservation of energy, we have:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Thus, the specific heat capacity of the metal is 0.60 J/gºC

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In the chemical reaction:

Cu + 2AgNO3 → 2Ag + Cu(NO3)2

What is the limiting reactant if you start with 1.8 moles of copper and 2.0 moles of silver nitrate?

Group of answer choices

A. copper (II) nitrate

B. copper

C. silver

D. silver nitrate

Answers

Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.

Reaction stoichiometry

In first place, the balanced reaction is:

Cu + 2 AgNO₃  → 2 Ag + Cu(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 1 moleAgNO₃: 2 molesAg: 2 molesCu(NO₃)₂: 1 mole

Limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

Limiting reagent in this case

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?

[tex]amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}[/tex]

amount of moles of AgNO₃= 3.6 moles

But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.

Summary

In summary, AgNO₃ will be the limiting reagent.

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Convert the following measurement

Answers

The correct answer would be 0.034 g/L.

Unit conversion

What we are trying to do here is to convert from milligram to gram and from deciliter to liter.

First, let's do the milligram to gram conversion.

1 mg = 0.001 g

Therefore,

3.4 mg = 3.4 x 0.001 = 0.0034 g

In order to convert from deciliter to liter.

1 deciliter = 0.1 L

Thus, 3.4 mg/dL = 0.0034g/0.1 L = 0.034 g/L

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How many mL of a 0.193 M aqueous solution of ammonium bromide, , must be taken to obtain 8.42 grams of the salt?

Answers

Answer:

445 mL NH₄Br

Explanation:

(Step 1)

Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.

Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol

Molar Mass (NH₄Br): 97.943 g/mol

8.42 grams NH₄Br                1 mole
-----------------------------  x  ------------------------  =  0.0860 moles NH₄Br
                                         97.943 grams

(Step 2)

Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).

Molarity (M) = moles / volume (L)

0.193 M = 0.0860 moles / volume

(0.193 M) x volume = 0.0860 moles

volume = 0.445 L

1,000 mL = 1 L

0.445 L NH₄Br           1,000 mL
------------------------  x  ------------------  =  445 mL NH₄Br
                                        1 L

At STP, 1 mole of gas has a molar volume of 22.4 L. What is the density (g/L) of oxygen at STP?
(Hint: find mass using PV=nRT) and find Density using d=m/v

Answers

So the GFM of O2 is 32.00g/mol
If we have 1 mole of O2 we have 32.00g
32.00g/22.4L = 1.42857… aprox. 1.43g/L

Sorrr I’m not quite sure where PV=nRT comes in

URGENT

A chemical equilibrium between gaseous reactants and products is shown.


N2(g) + 3H2(g) ⇌ 2NH3(g)


How will the reaction be affected if the pressure on the system is increased?


It will shift toward the reactant side as there is lower pressure on the reactant side.

It will shift toward the product side as there is higher pressure on the product side.

It will shift toward the reactant side as there are a greater number of moles of gas on the reactant side.

It will shift toward the product side as there are a fewer number of moles of gas on the product side.

Answers

Answer:

Explanation:

Discussion

When Pressure increases  equilibrium shifts to the side with the smallest number of moles. But which side is that?

N2(g) + 3H2(g) ⇌ 2NH3(g)

The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols

on the left side.

The right side has 2 mols of NH3 = 2 mols on the right.

Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.

Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.

2NH3 is only two mols.

The equilibrium shifts Right

Answer

D

Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.

What mass, in grams, of NaCl do you need to use to make the solution?

Answers

Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl           58.443 g
------------------------------  x  -------------------  =  2.52 g NaCl
                                            1 mole

What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3

Answers

Answer:

44.8 grams

Explanation:

The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.

[tex]\frac{8.96 grams}{1.00 cm^3} =\frac{?grams}{5.00cm^3}[/tex]                                         <----- Proportion

[tex]44.8 = (1.00cm^3)(?grams)[/tex]                              <----- Cross-multiply

[tex]44.8= ?grams[/tex]                                                 <----- Divide both sides by 1.00

How to recover ballpoint ink washed off from a paper?

Answers

The first step in clearing a clogged ballpoint pen is to exert additional pressure when scrawling and drawing vertical lines on paper. If this approach doesn't work, dip the pen's tiny tip in rubbing alcohol. [Only the tidbit] Any dried-up or hardened ink on the tip will dissolve with this.

ClO(4)− Express your answer as a chemical formula.

Answers

ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

What is Perchlorate ion?

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has  32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

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A chemistry student needs 45.0mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is ·0.626gcm−3. Calculate the mass of pentane the student should weigh out. Round your answer to 3 significant digits.

Answers

The mass of pentane the student should weigh out is

The density of pentane is 0.626 gcm-3

To calculate the mass of pentane following expression is used,

(Density is defined as the mass divide by volume)

Density = mass / volume

mass of pentane = Density of pentane * Volume of pentane

mass of pentane = 0.626 gcm-3 * 45.0 mL

                             = 28.17 g

Here the unit of mass of pentane is g,

However the unit of density is gcm-3 and unit of volume is mL i.e. cm3

Hence,   Mass = gcm-3 * cm3

              Mass = g

The mass of pentane the student should weigh out is 28.17g

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28. What mass
0.120M HCI?
of Na₂CO3 (Molar Mass = 106.0 g/mol) is required to react completely with 21.6 mL of.

Answers

Mass of [tex]$\mathrm{Na}{2} \mathrm{CO} 3$[/tex] required [tex]$=0.55 \mathrm{~g}$[/tex]

What is meant by molar mass?The mass of one mole of a sample is its molar mass. Add the atomic masses (atomic weights) of all the atoms in the molecule to obtain the molar mass. Using the mass listed in the Periodic Table or atomic weights table, determine the atomic mass for each element.The total mass of all the atoms that make up a mole of a specific molecule, measured in grams, is known as the molar mass or molecular weight. The measurement is made in grams per mole.Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh on your scale if you are testing theories involving precise amounts of a substance. Take a look at an experiment that needs 2 moles of pure carbon as an illustration.

The mass 0.120M HCI:

Moles of [tex]$\mathrm{HCl}$[/tex]reacted [tex]$=0.120 \times 21.6 / 1000=0.00260$[/tex]

according to balanced reaction, [tex]$\mathrm{HCl}$ and $\mathrm{Na} 2 \mathrm{CO} 3$[/tex] reacts in [tex]$2: 1$[/tex] the ratio

moles of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.00260 \times 2=0.00520$[/tex]

convert moles to mass

mass [tex]$=$[/tex]moles [tex]$\times$[/tex]molar mass

mass [tex]$=0.00520 \times 106.0$[/tex]

mass [tex]$=0.55 \mathrm{~g}$[/tex]

mass of [tex]$\mathrm{Na} 2 \mathrm{CO} 3$[/tex]required [tex]$=0.55 \mathrm{~g}$[/tex]

Mass 0.120M HC is [tex]$=0.55 \mathrm{~g}$[/tex]

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Hydrogen gas has a density of 0.090/gL, and at normal pressure and 0.214°C one mole of it takes up 22.4L. How would you calculate the moles in 370.g of hydrogen gas?
Set the math up. But don't do any of it. Just leave your answer as a math expression.

Also, be sure your answer includes all the correct unit symbols.

how to set up this equation?
moles= ???

Answers

Answer:

See below

Explanation:

370 g  /  .090 g/l = _____?___   liters

take that answer    then :

  ? liters   /   22.4 liters / mole   = # moles     done!

There are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.

The number of moles in 370.g of hydrogen gas using the given information.

In the given example,

Density of hydrogen gas = 0.090 g/L

Molar volume at normal pressure and 0.214°C = 22.4 L/mol

So, we  calculate the volume of hydrogen gas (in L) using the given mass and density:

Volume (in L) = mass (in g) / density (in g/L)

Volume (in L) = 370.g / 0.090 g/L

Volume (in L) ≈ 4111.11 L

By using the molar volume, calculate the number of moles:

moles = Volume (in L) / Molar volume (in L/mol)

moles = 4111.11 L / 22.4 L/mol

moles ≈ 183.50 moles (rounded to two decimal places)

Hence, there are approximately 183.50 moles of hydrogen gas in 370.g of hydrogen gas.

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Given the reaction:
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution:
Group of answer choices

A. No changes in color occur

B. The solution turns darker red

C. The solution becomes colorless

D. The solution becomes more yellow

Answers

Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)

If Fe3+ is added to the solution the solution turns darker red

While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.

The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.

The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.

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Quick explanation please i'm having trouble

Two different atoms have nine protons each and the same mass. However, one is neutral while the other has a negative charge. Describe what each atomic structure could be, listing the possible number and location of all subatomic particles.

Answers

It’s asking what subatomic particles each could have where one would be negative and they’d have the same mass. Since one is neutral it will have an equal amount of electrons and protons, while the negative one will have more electrons since they are negatively charged. It would be possible for one atom to have 9 protons, 9 electrons, and 1 neutron while the other has 9 protons and 10 electrons. Or you could take out the neutron because electrons don’t really have mass

The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?

(What goes in the 6 empty spaces?)

Answers

Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

What is Iron (II) Oxide ?

The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.

What is Iron (III) Oxide ?

The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.

           

Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.

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Lab Data
Mass of magnesium (g)
Moles of magnesium (mol)
Temperature of water (°C)
Temperature of water (K)
Vapor pressure of water (mmHg)
Barometric pressure (mmHg)
Observations
Volume of hydrogen gas collected (mL)
Volume of hydrogen gas collected (L)
Pressure of hydrogen gas (mmHg)
Pressure of hydrogen gas (atm)
Moles of hydrogen gas produced (mol)
Ideal das constant (L-atm-mol-K)
0.218
-X
ES
V
LAB DATA SH
OLONCE

Answers

Answer:

okkkk zjjdjdjdjduxuxu

Solve this organic transformation....use - Br2,CCl4,KOH,CH3OH,Hg+2,diluted H2SO4, PCC,HBr,Mg,Dry ether,Na,H2,Pd,quinoline

Answers

Organic transformation sequential equation using catalysts will be as follows:

2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn

CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2

As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.

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us
Let's say that you were asked to find the
molecular formula for a compound given its
empirical formula, CH₂O, and the compound's
molar mass.
The first step in solving such a problem is to
calculate the molar mass for the empirical
formula. What is the molar mass of CH₂O?
(C=12.01 amu, H=1.008 amu, O=16.00 amu)
[?] g/mol CH₂0
1

Answers

Answer:

Molar mass = 30.026 g/mol

Explanation:

Let Molar mass be mm

mm of CH2O = 12.01 + 2(1.008) + 16.00

= 12.01 + 2.016 + 16.00 = 30.026 g/mol

Need the answer pretttty pleaseeeeee

Answers

Answer:

The answer would be D.

Explanation:

Whenever one has many of the same correlating numbers within in a pattern, the rest tend to follow. With the information I was given and not the actual plotting, that would be my answer.

The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that the reaction proceeds essentially to completion.
Group of answer choices

True

False

Answers

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

What is the equilibrium constant?

In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.

On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

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please answer the question so i can make sure I got them right! thank you :)

Answers

pH = pKa + log [conj.base]/[acid]

Let the concentration of the conjugate base = x

=> The concentration of the acid is also x (As the acid concentration is equivalent to that of the conjugate base)

for CH₃COOH=0.50 M and CH₃COO=0,25 M

pH = pKa + log [salt]/[acid]

pKa = -log Ka = -log 1.8x10-5 = 4.74

pH = 4.74 + log (0.50 M/1.0 M) = 4.74 + log 0.5 = 4.74 + (-0.3)

pH = 4.74 - 0.3

pH = 4.44

For0.20 M Na2CO3

pH=−log[H+]

    =−log (1.54×10−12)

   =11.8

for HNO₂

Kb = 2.17X10^-11 = x^2 / 0.148

x = [OH-] = 1.79X10^-6

pOH = 5.747

pH = 14.000 - pOH = 8.253

for HPO₄³⁻

= [HPO₄³⁻] [PO₄³⁻] [H +]/×10⁻³

=[PO₄³⁻]5.464×10⁻¹⁸

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what is s for silicon tetrachloride Sicl4?

Answers

S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon transmits its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency

What is silicon tetrachloride used for?

Silicon Tetrachloride is a transparent, colorless, fuming liquid with an irritating odor. It is used to create Silicon-containing chemicals and in chemical analysis. determine potentially hazardous frontages.

How is silicon tetrachloride produced?

Silicon tetrachloride is designed by the chlorination of various silicon compounds such as ferrosilicon, silicon carbide, or mixtures of silicon dioxide and carbon. The ferrosilicon route is most familiar. In the laboratory, SiCl 4 can be prepared by dining silicon with chlorine on 600 °C (1,112 °F): Si + 2 Cl 2 → SiCl.

 

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