Calculate the population density of 900 sheep in a plot of land that is 3.00 km by 2.00km

Answers

Answer 1

The population density of the 900 sheep in the given plot of land is 150 sheep per square kilometer.

The population density of 900 sheep in a plot of land that is 3.00 km by 2.00 km can be calculated by dividing the total number of sheep by the area of the land.

First, we need to calculate the area of the land. The area can be found by multiplying the length and width of the plot of land:

Area = length × width = 3.00 km × 2.00 km = 6.00 km²

Next, we divide the total number of sheep by the area to calculate the population density:

Population Density = Total number of sheep / Area = 900 sheep / 6.00 km²

Performing the calculation, we find:

Population Density = 150 sheep/km²

Therefore, the population density of the 900 sheep in the given plot of land is 150 sheep per square kilometer.

Population density is a measure of the number of individuals (in this case, sheep) per unit area. By dividing the total number of sheep by the area of the land, we obtain the population density in terms of sheep per square kilometer. In this case, the population density is 150 sheep/km², indicating that there are, on average, 150 sheep within each square kilometer of the land.

For more such answers on Population

https://brainly.com/question/29885712

#SPJ8


Related Questions

The above carbohydrate (cellobiose) is properly categorized as:
A. a heteropolysaccharide sugar
B. a homopolysaccharide sugar
C. a heterodisaccharide sugar
D. a homodisaccharide sugar
E. a monosaccharide sugar

Answers

Cellobiose is properly categorized as a heterodisaccharide sugar, as it consists of two glucose units linked together through a β-1,4-glycosidic bond.

The correct answer is option C.

The above carbohydrate, cellobiose, is properly categorized as a heterodisaccharide sugar. A heterodisaccharide is a type of carbohydrate composed of two different monosaccharide units joined together by a glycosidic bond. Cellobiose consists of two glucose molecules linked together through a β-1,4-glycosidic bond.

To understand why cellobiose is classified as a heterodisaccharide, let's break down the options provided:

A. Heteropolysaccharide sugar: Heteropolysaccharides are complex carbohydrates composed of different types of monosaccharides. However, cellobiose is a disaccharide, not a polysaccharide, and it consists of two identical glucose units, making it a homodisaccharide rather than a heteropolysaccharide.

B. Homopolysaccharide sugar: Homopolysaccharides are carbohydrates made up of repeating units of the same monosaccharide. Since cellobiose is composed of two glucose units, it is not a homopolysaccharide.

C. Heterodisaccharide sugar: Heterodisaccharides are carbohydrates formed by the combination of two different monosaccharide units. In the case of cellobiose, it is formed by the linkage of two glucose units, which are the same type of monosaccharide. Therefore, cellobiose is a heterodisaccharide sugar.

D. Homodisaccharide sugar: Homodisaccharides are carbohydrates composed of two identical monosaccharide units. Since cellobiose is formed by the linkage of two glucose units, it is not a homodisaccharide.

E. Monosaccharide sugar: Monosaccharides are single sugar units and cannot be further broken down into simpler sugars. Cellobiose is a disaccharide, consisting of two glucose molecules, and is therefore not classified as a monosaccharide.

Therefore, the carbohydrate (cellobiose) is properly categorized a:  C. a heterodisaccharide sugar

For more such information on: Cellobiose

https://brainly.com/question/31745001

#SPJ8

Summarize your results from your data tables. Compare the results from the respirometers containing germinating and dormant peas. Speculate about the cause(s) of any difference between the two pea samples, and explain your reasoning.

Answers

The data tables show that the respirometers containing germinating peas consumed more oxygen than the respirometers containing dormant peas. The difference between the two samples was most evident during the first 10-minute interval. After this time, the oxygen consumption of the two groups became more similar.

This difference can be explained by the fact that germinating peas are actively growing and require more energy than dormant peas. As a result, they consume more oxygen through cellular respiration. Dormant peas, on the other hand, are not actively growing and require less energy, so they consume less oxygen.

The difference in oxygen consumption between the two groups decreased over time because the germinating peas eventually used up their stored energy and slowed down their metabolic rate. The dormant peas, however, continued to consume oxygen at a relatively constant rate because they had less stored energy to begin with.

Overall, the data suggest that the metabolic rate of peas is influenced by their growth stage and energy needs. Germinating peas require more energy and therefore consume more oxygen than dormant peas.

Describe how instructional notes in both the Alphabetic Index and the Tabular List guide coders when selecting ICD-10-CM codes.

Answers

Instructional notes in the Alphabetic Index and Tabular List of ICD-10-CM provide essential guidance for coders in selecting accurate codes by clarifying coding conventions, rules, and specific instructions.

Instructional notes in both the Alphabetic Index and the Tabular List of ICD-10-CM provide guidance to coders when selecting appropriate codes. These notes serve as important references that clarify coding conventions, rules, and specific coding instructions.

In the Alphabetic Index, instructional notes can be found alongside the listed terms or conditions. They provide additional information on code selection, such as code inclusion or exclusion criteria, code sequencing rules, and any specific coding guidelines applicable to certain conditions or circumstances. For example, the index may indicate the need to refer to another term or provide cross-references to guide coders to the most appropriate code. These notes help coders navigate through the index and select the correct codes based on the documented diagnoses or conditions.

Similarly, the Tabular List contains instructional notes that further assist coders in code selection. These notes are typically located at the beginning of a chapter, section, or category and provide overarching guidelines and specific coding conventions. They may include instructions on the use of combination codes, manifestation codes, or codes for related conditions. Additionally, the Tabular List may contain additional instructions within code descriptions to guide coders in selecting the most precise and accurate code for a given diagnosis.

Overall, the instructional notes in both the Alphabetic Index and the Tabular List play a crucial role in guiding coders during the code selection process. They provide essential information on coding conventions, rules, and specific instructions, ensuring that the assigned codes accurately represent the documented diagnoses or conditions.

For more such information on: Alphabetic Index

https://brainly.com/question/11174890

#SPJ8

Final answer:

Instructional notes in both the Alphabetic Index and the Tabular List are essential for guiding coders in selecting ICD-10-CM codes.

Explanation:

In the ICD-10-CM coding system, both the Alphabetic Index and the Tabular List provide instructional notes to guide coders in selecting codes. These notes are important for ensuring accurate coding and adherence to coding guidelines.

In the Alphabetic Index, instructional notes can provide additional specificity or exclusions for certain code entries. For example, an instructional note may specify that a particular code should only be used for a certain condition or age group.

In the Tabular List, there are also instructional notes that provide guidance on code sequencing, combination codes, and other important coding rules. These notes help coders determine the correct code based on specific conditions or circumstances.

Learn more about ICD-10-CM coding here:

https://brainly.com/question/33722615

#SPJ11

Is the hypothesis a plant can show it is alive by growing testable

Answers

The statement "a plant can show it is alive by growing" is not a testable hypothesis as it lacks specificity, a measurable variable, and conditions that can be manipulated or controlled in an experiment.

The statement "a plant can show it is alive by growing" is not a hypothesis, but rather an observation or a general statement. A hypothesis is a proposed explanation or prediction that can be tested through experimentation or observation.

To form a testable hypothesis related to this statement, we would need to provide a specific and measurable variable to investigate. For example, a testable hypothesis could be: "Increasing the amount of sunlight exposure will result in faster growth rates of plants." This hypothesis can be tested by conducting an experiment where different groups of plants are exposed to varying levels of sunlight, and their growth rates are measured and compared.

In the given statement, "growing" is a general characteristic of plants and does not provide a specific variable that can be measured or manipulated. Additionally, the statement does not specify any conditions or factors that can be controlled or changed to test the hypothesis.

For more such information on: testable hypothesis

https://brainly.com/question/389988

#SPJ8

exaplian two situations on a pedigree that would allow you to determine the genotype of an induvudal with the dominant phenotype. Draw a pedigree with each explanation

Answers

Pedigrees frequently cover several generations as well as other family members to give a more thorough insight of inheritance patterns. In both situations, the dominant phenotype is expressed in multiple generations, providing clues about the genotype of the individual showing the dominant trait.

Two pedigree situations to explain genotype with dominant phenotype

Two scenarios can be seen in a pedigree to determine the genotype of a person with a dominant phenotype:

Affected parent and affected child: It is likely that the affected parent is heterozygous, carrying one copy of the dominant allele if they have a child who also displays the dominant phenotype.Two individuals with a dominant phenotype have an unaffected offspring: This shows that both of the affected individuals are heterozygous if the child does not have the dominant phenotype.

By taking into account the inheritance patterns shown in the pedigree, these scenarios offer hints regarding the genotype of people with dominant traits.

Learn more on genotype here https://brainly.com/question/30460326

#SPJ1

Other Questions
Kimberly bought a painting 35 years ago for$3400and it's currently worth$7400. She tripled her money on this investment: however. what is her annualized return on this investment?a. 4.01%b. 0.47%c. 2.63%d. 2.25% how many amino acids make up this portion of the oxytocin molecule? which of the following conditions may be affected by the chromium and nickel content of stainless steel cookware? The primany reason for developing a conceptual framework was to: O a. provide an alternative view to the accounting standards.O b. assist to revise the accounting standards. O c. reduce the number of accounting standards needed.O d. enable regulators to develop accounting standards that are consistent and logically formulated. (a) Explain the term "adverse selection" and illustrate it with an example involving a company that wishes to raise money via a bond issue. (5 marks) 9] Indicate proper type of waves - longitudinal "L" or transverse "T": a) Mechanical waves on surface of water L T b) Sound waves in steel L T c) Sound waves in air L T d) Electromagnetic waves in vacuum L T e) Electromagnetic waves in fiberglass L T f) Earthquake waves L T g) X-ray waves L T h) Light waves L T [10] Extension of the length of string of pendulum results in: a) Change of deflection b) Change of mass c) Increase of tension of the string d) Increase in period of oscillation e) Decrease in period of oscillations f) Increase of acceleration of pendulum g) Decrease in velocity of pendulum yooooooo zooooooo N state the vertebral level whose intactness is assessed when eliciting each of these reflexes-biceps reflex C5-C6-triceps reflex C7-C8-bachioradialis reflex C5-C6-quadricepts reflex L2-L4-achilles reflex L5-S2 At the beginning of 2020, Carla Vista Company, a small private company, acquired a mine for $1,790,000. Of this amount, $160,000 was allocated to the land value and the remaining portion to the minerals in the mine. Surveys conducted by geologists found that approximately 21 million units of ore appear to be in the mine. Carla Vista had $205,000 of development costs for this mine before any extraction of minerals. It also determined that the fair value of its obligation to prepare the land for an alternative use when all of the minerals have been removed was $55,000. During 2020, 2.7 million units of ore were extracted and 2.20 million of these units were sold.Calculate the depletion cost per unit for 2020. By rearranging al of the cards shown below, make the calculation with thelargest possible value.What is the value of this calculation?56 9( )+ the stanford linear accelerator (slac) accelerates electrons to A system consists of three identical particles (same mass), with positions and velocities as follows: T = 21, V = +, T = 1, T3 = -3 k V = 4, V3 = k a) Find the position of the center of mass. (2pts) b) Find the velocity of the center of mass. (2pts) c) Find the linear momentum of the system. (2pts) d) Find the kinetic energy of the system. Why might a CEO have an incentive to drive his company's stock price down? Is there evidence that CEOs might do this on any systematic basis? If so, describe it. in what type of song do vocalists sing different melodies at the same time? most people need ____ minutes of exercise per day for weight management. Which of the following does not describe the juxtaglomerular complex?A. Its granular cells produce renin.B. It helps control systemic blood pressure.C. It regulates the rate of filtrate formation.D. Its macula densa cells produce aldosterone. FILL THE BLANK.if a third party believes an agent is acting with actual or apparent authority, he or she may sue the principal for_____. please answer in 10 minutesI will upvoteCompare and contrast two different planform channel morphologies. Expatiate on systems theory, its relevance in industrial relationsand how it can be applied Explain different methods of radioactive decay.Know the processes involving alpha, beta, and gamma decay Do Not SpamHow would we justify digital content making according to ethics.Relate sustainability, environment safety,. green jobs, jobenlargement and explain in context to Globalization? 500words