The information is missing here but data that may support the existence of life in an exoplanet may include the discovery of atmospheric biological gases.
What is an exoplanet?An exoplanet is any planet that surrounds another star beyond the sun, and therefore they are discovered by analyzing other galaxies in the Universe.
The existence of life in these exoplanets can be indirectly supported by the presence of gases that are only produced by organisms, which are detected by suitable telescopes that analyze emission spectra.
In conclusion, the information is missing here but data that may support the existence of life in an exoplanet include biological gases.
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Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).
The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.
Force necessary to support the objectApply Pascal principle to calculated the force needed to support the mass as shown below;
F₁/A₁ = F₂/A₂
F₁/d₁² = F₂/d₂²
F₁ = F₂d₁²/d₂²
where;
F₂ is the force on piston 2, determined from, F = mgd₂ is the diameter of piston 2, given as 9.46 cmd₁ is diameter of piston 1, given as 1.87 cmF₁ is force on piston 1 = ?Substitute the given parameters and solve for the force needed to support the mass given.
F₁ = (991 x 9.8 x 0.0187²)/(0.0946)²
F₁ = 379.5 N
Thus, the force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.
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Your car rides on springs, so it will have a natural frequency of oscillation. (Figure 1) shows data for the amplitude of motion of a car driven at different frequencies. The car is driven at 29 mph over a washboard road with bumps spaced 12 feet apart; the resulting ride is quite bouncy.
1)Determine the frequency of the oscillation, caused by the bumps. 1 mile is 5280 feet.
2)Should the driver speed up or slow down for a smoother ride?
Answer:
See below
Explanation:
29 mile/hr * 5280 f/mile / 3600 s/hr = 42.53 ft/ sec
42.53 ft / sec / 12 feet = 3.54 cycles / sec = 3.54 Hz
for frequency I suppose....where is the referred to figure?
It has been suggested that rotating cylinders about 19.5 mi long and 5.66 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
_____rad/s
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
Angular speed of the cylinder
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;
a = v²/r
v² = ar
(ωr)² = ar
ω²r² = ar
ω²r = a
ω² = a/r
ω = √(a/r)
where;
a is centripetal acceleration = acceleration due to gravity, gr is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 mω is angular speedω = √(g/r)
ω = √(9.8/4554.4)
ω = 0.046 rad/s
Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
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What phase of matter is pictured below? Image of particles that are spread out, many are not touching, high energy. A. Gas B. Bose-Einstein condensate C. Fermionic condensate D. Plasma
Option(d)i.e, Plasma is the Image of particles that are spread out, many are not touching, high energy.
Along with solid, liquid, and gas, plasma is frequently referred to as the "fourth state of matter." Heating a gas will result in the formation of plasma, which is a soup of positively and negatively charged particles (ions), similar to how adding energy causes a liquid to boil and transform into a gas (electrons).
Plasmas are less dense than solids or liquids and, like gases, have no set structure or volume. However, in contrast to regular gases, plasmas are composed of atoms in which part or all of the electrons have been removed and positively charged nuclei, known as ions, are free to move around.
Solids, liquids, gases, ionized plasma, quark-gluon plasma, bose-einstein condensate, and fermionic condensate are the seven states of matter.
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(Please help 25 points)
Asteroids X, Y, and Z have equal mass of 6.0 kg each. They orbit around a planet with M=6.20E^24 kg. The orbits are in the plane of the paper and are drawn to scale.
In the statements below, TE is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.
The PE of X at r is .... that at s
The TE of Y is .... the TE of X
The PE of Y at u is .... the PE of Z at c
The speed of Y at i is .... that at u
The KE of Z at u is .... that at m
The PE of Y at s is .... the PE of X at c
The TE of Z is .... the TE of X
The PE of X at c is .... the PE of Z at c
(Options are: greater than, less than, equal to)
The potential energy (P.E) of X at r is less than P.E at s.
The total energy (T.E) of Y is less than total energy (T.E) of X.
The PE of Y at v is greater than the PE of Z at c.
The speed of Y at i is .greater than that at v.
The kinetic energy (KE) of z at u is less than that at n.
The PE of Y at s is less than the PE of X at c.
The PE of X at c is less than the PE of Z at c.
The PE of X at c is less than the PE of Z at c.
PE of X at r and at sThe potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.
TE of Y is .... the TE of XThe total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.
PE of Y at v is .... the PE of Z at cThe PE of Y at v is greater than the PE of Z at c due to greater displacement at v.
Speed of Y at i is .... that at uThe speed of Y at i is .greater than that at v because i is closer to the planet than v.
KE of Z at u is .... that at nThe kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.
PE of Y at s is .... the PE of X at cThe PE of Y at s is less than the PE of X at c, because position c has greater displacement.
The TE of Z is .... the TE of XThe TE of Z is greater than the TE of X due to greater displacement of Z from the planet.
The PE of X at c is .... the PE of Z at cThe PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.
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ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A. If the acceleration of the system is 5.88m/s2, what is the Tension T on Box A?
The tension on box A is 117.6 N
What is Equilibrium of Forces ?Equilibrium is a state of an object with respect to a given observable quantity during the time for which there is no change in that quantity.
A body is said to be in equilibrium when:
the body as a whole either remains at rest or moves in a straight line with constant speed.the body is either not rotating at all or is rotating at a constant angular velocity.Given that box A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A.
The tension in the rope will be the same.
Given that Box A is placed on a horizontal surface that is frictionless, that is,
T = ma .... (1)
Also, Box B is hanging from a pulley by a rope connected to Box A. That is,
W - T = ma ...... (2)
Where W = mg
Since the acceleration of the system is 5.88m/s² which will be the same for the two equations, then the Tension T on Box A can be calculated by substituting acceleration and mass into equation (1)
T = 20 x 5.88
T = 117.6 N
Therefore, the tension on box A is 117.6 N
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[tex] \large{\rm{Question:}}[/tex]
Give one example where the displacement is zero but the distance traveled is not zero.
Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.
Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.
Example:
Imagine a person walks 10 meters forward and then turns around and walks 10 meters back to the starting point. In this case, the displacement is zero (starting point to ending point), but the distance traveled is 20 meters (10 meters forward + 10 meters backward).
what does personal mission statement?
Answer:
A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.
Explanation:
It explains how you aim to pursue that purpose, and why it matters so much to you.
How much heat is required to raise the temperature of 0.210 g of water from 19.2 ∘C to 32.0 ∘C?
Data:
m = 0.210 g T₀ = 19.2 °C + 273 = 292. 2 KT = 32.0 °C + 273 = 305 KCe = 4.18 J / GKWe apply the following formula
Q = mcₑΔT
Q = mcₑ (T - T₀)
We substitute Our data in the formula and solve:
Q = 0.210 g * 4.18 J / g K (305 k - 292.2 k)
Q = 11.23 J
Why are enthalpy changes always lower than their expected values?
A. They aren't. They are always greater than expected.
B. Heat losses during the experiment
C. Heat gains during the experiment
D. Faulty measurements
Enthalpy changes are always lower than their expected values due to faulty measurements; option D.
What are enthalpy changes?Enthalpy changes refers to the changes in the heat content of substances in the course of a reaction.
Enthalpy changes occurs as a result of bond breaking and bond formation in the reactant molecules and product molecules respectively.
Enthalpy change = Energy of bond formation - Energy of bond breakage.Enthalpy changes are measured from the changes in temperature that are observed in the course of a given reaction.
Due to faulty measurements in a particular experiment measuring enthalpy changes, enthalpy changes are always lower than their expected values.
Therefore, accurate measurements are required if results as close as possible to the actual enthalpy changes are to be obtained.
In conclusion, enthalpy changes measure the heat changes that occur during a particular chemical reaction.
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4. Four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m, a 3.00kg object is at +2.50m, a 2.50kg object is at the origin, and a 4.00kg object is at -0.500m. Where is the center of mass of these objects?
Answer: 1.348 meters
Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point c . Adding the four moments together, we get:
(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0
6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0
11.5c=15.50
c= 1.348 metres
The center of mass is on the y axis at y = 1.348 metres.
A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases.
The new sphere has a density of ρ > ρ0 and a mass of m = m0.
The new sphere has a mass of m > m0 and a radius of r = r0.
The new sphere has a radius of r = r0 and a density of ρ > ρ0.
Based on the given data about, volume, mass, and density of the spheres;
the water level will fall; fthe water level may rise or fall; r or fthe water level will rise; rWhat determines whether an object floats are sinks in water?The density, mass, volume, and shape of an object determines whether it will float or sink in water.
Density = mass/volumeFor an object to float, it will displace its own weight of the fluid in which it floats. This is according to Archimedes' principle which states that the upward force acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.
Considering the given scenarios:
1. The new sphere has a density of ρ > ρ0 and a mass of m = m0.
This means that the volume of new sphere is smaller than the volume of the original sphere, therefore, the water level will fall,
2. The new sphere has a mass of m > m0 and a radius of r = r0.
This means that the new sphere will have a greater volume and mass. However, the density may be greater or less.. Therefore, the water level may rise or fall.
3. The new sphere has a radius of r = r0 and a density of ρ > ρ0.
The new sphere has equal volume, greater density and mass than the original sphere. Therefore, the water level will rise.
In conclusion, the level of the water in the container depends on the volume, mass and density of the object placed in it.
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define universal vibrations ?
Answer:
The second universal law, the law of vibration, posits that everything (every atom, object, and living thing) is in constant motion, vibrating at a specific frequency.
Explanation:
Please mark brainly
The second universal law defines this.
The second universal law, also known as the Law of Vibration, The Law of Vibration states that everything in the universe is in a constant state of movement. We refer to these movements as vibration, and the speed or rate at which something vibrates is called its frequency. The only difference between one object and another is its vibration rate.
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A cell connected to two bulbs in series lasts longer than a cell connected to the same bulbs in parallel.Explain why?
Because the voltage stays the same while the amps grow, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps quadruple to 100ah, the batteries will last longer. Charges are spread among the bulbs in a parallel circuit because they are flowing in several directions over multiple paths. As a result, each bulb will have less charge since the charge is travelling in multiple directions, and the lights will shine less brightly. On the other hand, in a series circuit, there is only one channel and only one location for the charge to travel, meaning that all of the charge is directed at a single lightbulb. As a result, the lightbulb will shine more brilliantly since there is no need to spread the energy. The rule of conservation of energy is not broken because of the difference in power; instead, smaller resistance causes bigger current, which results in brighter lights. The energy traveling from the source to the bulbs remains constant. Because higher power means that more energy in a given time goes quicker from the source to the bulb, brighter lights require more power rather than energy. Because the energy traveling from the source to the bulbs remains constant, the rule of conservation of energy is not being broken; rather, there is merely a difference in power as a result of smaller resistance leading to bigger current, which will result in brighter lights. This means that brighter lights require more power rather than energy since higher power enables more energy to go from the source to the bulb more quickly.
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Eddie
A ball of mass 0.200 kg has a velocity of 150m/s; a ball of mass 0.300 kg has a velocity of - 0.4m/s. They meet in a head-on elastic collision. (a) Find their velocities after the collision. (b) Find the velocity of their center of mass before and after the collision.
(a) The velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.
(b) The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.
Velocity of the balls after collision
Apply the principle of conservation of linear momentum to determine the velocity of the balls;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.2(150) + (0.3)(-0.4) = 0.2v₁ + 0.3v₂
29.88 = 0.2v₁ + 0.3v₂
Apply one directional linear velocity
u₁ + v₁ = u₂ + v₂
v₁ = u₂ + v₂ - u₁
v₁ = -0.4 + v₂ - 150
v₁ = v₂ - 150.4
Substitute the value of v₁ into the first equation;
29.88 = 0.2(v₂ - 150.4) + 0.3v₂
29.88 = 0.2v₂ - 30.08 + 0.3v₂
59.96 = 0.5v₂
v₂ = 59.96/0.5
v₂ = 119.92 m/s
v₁ = 119.92 - 150.4
v₁ = -30.48 m/s
Velocity of their center mass before collisionV(cm) = (0.2 x 150 + 0.3 x 0.4) / (0.2 + 0.3)
V(cm) = 60.24 m/s
Velocity of their center mass after collisionV(cm) = (0.2 x 30.48 + 0.3 x 119.92) / (0.2 + 0.3)
V(cm) = 84.14 m/s
Thus, the velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.
The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.
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Compute your average velocity in the following two cases: (a) You
walk 73.2 m at a speed of 1.22 m/s and then run 13.2 m at a speed
of 3.02 m/s along a straight track. (b) You walk for 1.00 min at a
speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along a
straight track. (c) Graph x versus t for both cases and indicate how
the average velocity is found on the graph.
(a) Walking 73.2 m at 1.22 m/s would take
[tex]\dfrac{73.2\,\rm m}{1.22 \frac{\rm m}{\rm s}} = 60 \,\rm s[/tex]
and running 13.2 m at 3.02 m/s would take
[tex]\dfrac{13.2\,\rm m}{3.02\frac{\rm m}{\rm s}} \approx 4.37\,\rm s[/tex]
You've undergone a total displacement of 73.2 + 13.2 = 86.4 m in a matter of approximatly 64.37 s, so your average velocity is
[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{86.4\,\mathrm m}{64.37\,\rm s} \approx \boxed{1.34\dfrac{\rm m}{\rm s}}[/tex]
(b) In the first 1.00 min = 60 s, you undergo a displacement of
[tex](60\,\mathrm s) \left(1.22 \dfrac{\rm m}{\rm s}\right) = 73.2 \,\rm m[/tex]
and in the second minute, you undergo a displacement of
[tex](60\,\mathrm s) \left(3.05\dfrac{\rm m}{\rm s}\right) = 183 \,\rm m[/tex]
Your total displacement is then 73.2 + 183 = 256.2 m in a matter of 2.00 min = 120 s, so your average velocity is
[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{256.2\,\mathrm m}{120\,\rm s} \approx \boxed{2.14\dfrac{\rm m}{\rm s}}[/tex]
(c) For part (a), your displacement [tex]x(t)[/tex] (in m) at time [tex]t[/tex] (in s) is given by
[tex]x(t) = \begin{cases}1.22t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.02 (t-60) & \text{for } t > 60\end{cases}[/tex]
and for part (b), your displacement is given by the very similar
[tex]x(t) = \begin{cases}1.22 t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.05(t-60) & \text{for } t > 60 \end{cases}[/tex]
See the attached plots. The average velocity for the given situation is the slope of the dotted line.
How does the suns energy affect the climate of an area
There wouldn't be any life on Earth and no climate if it weren't for the Sun.
The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.
The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.
Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.
In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.
Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).
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Solve this question please A.S.A.P ⁉️
No spamming ❗
Answer:
Here given is :-Velocity (u) = 10m/sGravity (g) = 10 m/s²Height (h) = ?Explanation:
v² - u² = 2gh0² - 10² = 2 × (-10) × h-100 = -20 h[tex]h = \frac{ - 100}{ - 20} = 5m[/tex]V = u + gt0 = 10 - 10t10t = 10[tex]t = \frac{10}{10} = 1 \: sec[/tex]Total time = 2 secAnswer:
See below
Explanation:
vf = vo + at when it reaches top vf = 0 vo = 10m/s a = -9.81 m/s^2
0 = 10 + (-9.81) t
t = 1.02 seconds to reach max
time up = time down so roundtrip = 2.04 seconds
Consider the f(x) = Acos(x) function shown in the figure in blue color. What is the value of amplitude A for this function?
As a reference the g(x) = cos(x) function is shown in red color, and green tick marks are drawn at integer multiples of π.
The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.
What is amplitude of a wave?
The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.
Amplitude of the red colored waveFrom the graph, the amplitude of the red colored wave is 1 unit.
Amplitude of the blue colored waveFrom the graph, the amplitude of the red colored wave is 2.1 unit.
Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.
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h) Find the inverse Laplace transforms of the equation. When the X(s) =1 /(s²+9s+20)
Answer:
e^-4t e^-5t
Explanation:
solving s²+9s+20 quadratically we have (s+4)(s+5)
x(s) can be written as x(s) =(1/s+4)(1/s+5)
if we take the laplace inversve
L-¹ (s)=L-1(1/s+4) L-1(1/s+5)
we have e^-4t e^-5t
When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) of the loop?
Radius of the circular loop is 0.0091m.
What is magnetic field?Magnetic field is the area around a magnet where the magnetism influence is felt .
What is the magnetic field at the centre of a circular loop?The formula for magnetic field at the centre of a loop isB =(μ)I/2r
where B= Magnetic field at the centre of a circular loopμ= Magnetic permeability =4(π)*10^(-7)
I= current flowing through the loop
r= radius of the loop
Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))=0.0091m
Thus, we can conclude that the radius of the loop is 0.0091m .
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10. Complete each of the following radioactive decay equations.
235U → Th+a
92
90
87
37Rb Sr +
6C
→
F
e
1¹B ++ie
1. Alpha
Number next to Th is 231
(because 231 + 4 = 235)
The other number below the 4 is 2 - helium
(because 90 + 2 = 92)
2. Beta
Missing numbers are zero and one. Same as the one below it.
3. Beta
11 is the number above the C
(because 11 + 0 = 11)
5 is the number next to the B
(because 5 + 1 = 6)
Basically, the missing numbers must balance on both side of the equation; creating the elements you've started of with, meaning if you where to add the right side of the equation up - you should end up with the same protons and mass numbers you began with.
Hope this helps!
If the gravitational potential energy of an object 10 m above the ground is 50 J, what is its Ep, if it moves to 30 m above the ground?
Answer:
150 J
Explanation:
Moving 3 times higher will increase the P E x 3 = 150 J
A directional loudspeaker aims a sound wave of Frequency 200 H₂ at wall. At what distance from the wall would you stand and hear no sound at all? (v= 332 m/s).
The distance from the wall you would stand and hear no sound at all is 0.83 m.
What is speed of wave?The speed of a wave is the rate of change of distance traveled by a wave with time.
Distance of the waveThe distance at which the wave will have zero amplitude, there will be no sound at all since amplitude of a sound is proportional to intensity of the sound.
The point of zero amplitude, L = λ/₂
Where;
λ is wavelength of the wave
The wavelength of the wave is calculated as follows;
λ = V/f
where;
V is speed of sound wavef is frequency of the waveλ = 332/200
λ = 1.66 m
Distance from the wall a zero soundL = 1.66/2
L = 0.83 m
Thus, the distance from the wall you would stand and hear no sound at all is 0.83 m.
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A tree limb is blown loose from a tree during a storm. As it falls, it gains
speed. Which type of energy is the tree limb gaining as it falls?
O A. Kinetic energy
B. Gravitational potential energy
O C. Nuclear energy
OD. Light energy
Answer:
B Gravitational potential energy
Explanation:
The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.70 m and 1.03 m, respectively. The respective rotational speeds are 449 rev/min and 4,150 rev/min. Calculate the speeds of the tips of both rotors.
main rotor ______m/s
tail rotor _______m/s
Compare these speeds with the speed of sound, 343 m/s.
vmain rotor = _______ vsound
vtail rotor = _______ vsound
(a) The speeds of the tips of both rotors; main rotor 181.02 m/s and tail rotor 223.8 m/s.
(b) The speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.
Linear speed of main motor and tail rotor
v = ωr
where;
ω is the angular speed (rad/s)r is radius (m)v(main rotor) = (449 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.7 m)
v(main rotor) = 181.02 m/s
v(tail rotor) = (4,150 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.03 m)
v(tail rotor) = 223.8 m/s
Speed of the rotors with respect to speed of sound% speed (main motor) = 181.02/343 = 0.528 = 52.8 %
% speed (tail motor) = 223.8/343 = 0.652 = 65.2 %
Thus, the speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.
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A container with 3 kg of pure water at a temperature of 12 degrees Celsius is placed in a refrigerator where the air temperature is kept at 4 degrees Celsius. how much heat (in joules) is gained by the air when the water cools to 4 degrees Celsius?
Answer:
100 368 J
Explanation:
Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)
specific heat for water ( in joules) : 4182 J / kg-C
3 kg * 4182 J / kg-C * (12-4 C) = 100 368 J
Which one of the following statements concerning weight and energy balance is most accurate?
A. People generally need the same amount of physical activity to maintain weight stability.
B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.
C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.
D. The optimal amount of physical activity needed to maintain weight is unclear.
Answer: D. I took the test and got it right
The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.
What is energy balance?Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.
Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.
So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.
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how to calculate the half time
The formular for calculating half life is:
T1/2=0.693/Π
A 750 kg car is stalled on an icy road during a snowstorm. A 1000 kg car traveling eastbound at 13 m/s collides with the rear of the stalled car. After being hit, the 750 kg car slides on the ice at 4 m/s in a direction 30 ∘ north of east.
A) What is the magnitude of the velocity of the 1000 kg car after the collision?
B) What is the direction of the velocity of the 1000 kg car after the collision?
C) Calculate the ratio of the kinetic energy of the two cars just after the collision to that just before the collision. (You may ignore the effects of friction during the collision.)
(a) The magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.
(b) The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.
(c) The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.
Velocity of the 1000 kg after the collisionApply the principle of conservation of linear momentum as follows;
Final velocity in x directionm₁u₁ + m₂u₂ = m₁v₁x + m₂v₂x
where;
m₁ is mass of 750 kg caru₁ is initial velocity of 750 kg massm₂ is mass of 1000 kg caru₂ is initial velocity of 1000 kg massv₁ is final velocity of 750 kg massv₂ is final velocity of 1000 kg mass750(0) + 1000(13) = 750(4 cos 30) + 1000v₂x
13000 = 2,598.1 + 1000v₂x
10,401.9 = 1000v₂x
v₂x = 10.4 m/s
Final velocity in y directionm₁u₁ + m₂u₂ = m₁v₁y + m₂v₂y
750(0) + 1000(0) = 750(4 sin 30) + 1000v₂y
0 = 1500 + 1000v₂y
v₂y = -1500/1000
v₂y = -1.5 m/s
Resultant final velocityv = √(v₂ₓ² + v₂y²)
v = √[(10.4)² + (-1.5)²]
v = 10.5 m/s
Direction of the final velocity of 1000 kg cartanθ = v₂y/v₂ₓ
tanθ = -1.5/10.4
tanθ = -0.144
θ = arc tan(-0.144)
θ = 8.2 ⁰ north west
Kinetic energy of the cars before the collisionK.Ei = 0.5m₁u₁² + 0.5m₂u₂²
K.Ei = 0.5(750)(0)² + 0.5(1000)(13)²
K.Ei = 84,500 J
Kinetic energy of the cars after the collisionK.Ef = 0.5(750)(4)² + 0.5(1000)(10.5)²
K.Ef = 61,125 J
Ratio of the kinetic energyK.Ef/K.Ei = 61,125/84,500
K.Ef/K.Ei = 0.72
Thus, the magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.
The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.
The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.
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