Aspirin is the common name for acetyl salicylic acid, C9H8O4. One tablet contains 0. 325 g of aspirin. How many moles of aspirin is this?

D.Acute Viral Hepatitis

inflammation of the liver caused by infection with one of the five hepatitis viruses

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Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization

Trigonal hybridization is another name for sp2 hybridization. It entails combining one's' orbital with two 'p' orbitals of equal energy to create a new hybrid orbital known as sp2. A trigonal symmetry combination of s and p orbitals that is kept at 120

One of the hybrid orbitals formed when one s orbital and two p orbitals are mathematically merged to form three new equivalent orbitals orientated toward the corners of a triangle is sp2 hybridization.

The only feasible molecule geometry for sp2 hybridized center atoms is trigonal planar. When all of the bonds are in place, the shape is trigonal planar as well.

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Here BA is benzoic acid and B- is conjugate base;

BA is weaker than B- because the Ka < Kb

--> BA is stronger than B- because the Ka > Kb

BA is stronger than B- because the Ka < Kb

BA is weaker than B- because the Ka > Kb

A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H+). When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created. Yuki Jung was the creator.

The power of an acid (or base) is inversely proportional to the power of its conjugate base (or conjugate acid): The conjugate base of an acid is weaker the stronger it is. The conjugate base of a weaker acid has a stronger base. A pair of chemical species known as conjugate acid and conjugate base exhibit opposing chemical behaviors.

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Hello its me Sanya yadav

The NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

A spectroscopic method for observing the local magnetic fields surrounding atomic nuclei seems to be nuclear magnetic resonance spectroscopy, also referred to as magnetic resonance spectroscopy as well as NMR spectroscopy.

The identification and study of organic molecules benefit greatly from nuclear magnetic resonance (NMR) spectroscopy. This type of spectroscopy has a straightforward underlying theory. Numerous atom types' nuclei behave like small magnets and frequently align themselves in magnetic fields.

Therefore, the NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

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1. The empirical formula of the compound is Ti₂O₃

2. The correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. The correct answer to the question is: orange-brown (Option A)

4. The empirical formula of the compound is KClO₂

5. The empirical formula of the compound is P₂O₅

Divide by their molar mass

Ti = 66.6 / 48 = 1.3875

O = 33.4 / 16 = 2.0875

Divide by the smallest

Ti = 1.3875 / 1.3875 = 1

O = 2.0875 / 1.3875 = 3/2

Multiply by 2 to express in whole number

Ti = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Ti₂O₃

This is the simplest formula of a compound which shows the smallest whole number ratio of the atoms present in the compound

With the above definition, we can conclude that the correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

In the tin oxide laboratory activity, the colour of the vapor emitted when nitric acid is added to the tin is: orange-brown

NOTE: This colour is visible when we carryout the practical experiment

Thus, the correct answer to the question is orange-brown (Option A)

Divide by their molar mass

K = 36.6 / 39 = 0.9385

Cl = 33.2 / 35.5 = 0.907

O = 29.9 / 16 = 1.8688

Divide by the smallest

K = 0.9385 / 0.907 = 1

Cl = 0.907 / 0.907 = 1

O = 1.8688 / 0.907 = 2

Thus, the empirical formula of the compound is KClO₂

Divide by their molar mass

P = 43.6 / 31 = 1.406

O = 56.4 / 16 = 3.525

Divide by the smallest

P = 1.406 / 1.406 = 1

O = 3.525 / 1.406 = 5/2

Multiply by 2 to express in whole number

P = 1 × 2 = 2

O = 5/2 × 2 = 5

Thus, the empirical formula of the compound is P₂O₅

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Answer: The process is diffusion.

Explanation:

a dark liquid will have the highest concentration of dark purple atoms/molecules so it gives a concentrated colour.

when water is added to it, the colourless water molecules fill up the gaps between the purple particles and so their colour fades and becomes lighter and lighter as we add more water. see the image attached where imagine the red particles are water and the blue particles are purple particles. thats why the colour fades.

When an electron in a hydrogen atom jumps from an orbital farther from the nucleus to an orbital closer to the nucleus, the energy is emitted.

The energy of electron decreases. When it goes, the electron release a photon of electromagnetic energy.

When an electron jumps from higher energy orbital to lower energy orbital, the difference in the energies of these two orbitals is radiated as quantum.

E = hc/wavelength

The photon is emitted with the electron moving from higher energy level to lower energy level.

The wavelength of emitted radiation would be (27/32) × wavelength.

Thus we concluded that the energy of photon is exact energy that is lost by the electron moving to its lower energy level.

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Selective serotonin reuptake inhibitors (SSRIs) are drugs that are antidepressants. These blocks the reuptake of a neurotransmitter leading to increases in their activity in the synaptic cells.

Neurotransmitters are defined as the signaling molecules that are secreted by the nerve cells and act as signal transporter between the neurons and the other cells of the body.

The SSRIs class of drugs affects this neurotransmitter and blocks the pathway to the presynaptic cell. This, in turn, affects synaptic communication by increasing the amount of those SSRIs in the body and acting as a stimulant to treat various diseases.

Therefore, the SSRIs block the neurotransmitter and result in their effects.

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Heya....

Here's your answer.....

PV = nRT... R is a constant...

so PV/nT = constant...

P1V1 / n1T1 = P2V2 / n2T2...P is constant.T is constant.. so

V1 / n1 = V2 / n2

since n = mass / mw

V1 / (mass 1 / mw) = V2 / (mass 2 / mw)

and since molecular mass = constant

V1 / mass 1 = V2 / mass 2

mass 2 = V2 x mass 1 / V1 = 2.90L x 2.00 g / 2.00 L = 2.9 g

mass 2 - mass 1 = 2.90 g - 2.00 g = 0.90 g

ie.. 0.90 g of He was added.

Thanks...!!!

The molality of phosphoric acid, h3po4, in a solution prepared from 376 g of phosphoric acid and 1. 70×103 g of ethylene glycol, c2h4(oh)2 is 2.25m.

Ethylene Glycol is known as C2H4 (OH)2.

It is used to prepare Antifreeze solution by adding water in it.

Given,

Mass of phosphoric acid = 376g

Mass of ethylene acid = 1.7 × 10 3g

Since ethylene glycol is in excess. So it is acts as a solvent and phosphoric acid acts as solute

As we know that,

Molar mass of phosphoric acid = 98g

Moles of phosphoric acid

= Given mass / Molar mass

=376 / 98

= 3.83

Molality is defined as the ratio of moles of solute to the mass of solvent.

Molality = Moles of solute / Mass of solvent

= 3.83 / 1.7 kg

= 2.25m.

Thus, we found that the molality of phosphoric acid is 2.25m.

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The concentration of [ Hy³] = 4.861 *28⁻²³

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.

Given,

 Molarity of VoSo4 ,M = 0.02M

     Vol of VoSo4 , V = 10 ml

Molarity of EDTA = 0.02 M

vol of EDTA = 9.10 ml = 0.0091 L

& 10 ml of buffer with pH =4

NOW,

     no. of moles of EDTA = molarity * Volume (L)

                                         =  0.02 M * 0.0091 L

                                        = 182 * 10^-6 moles

                                        = 1.82 * 10^-4 moles

Now,

       ∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]

         [ Y^3-] = ∝ Y^3- * moles of EDTA

Given,

at pH = 4,   ∝ Y^3- = 3*10^-9

    ∴ ∝ Y^3- =  3*10^-9

        [ Y^3-] = 3*10^-9 * 1.82 * 10^-4

                   = 5.46 * 10^-13

Now, K f = [H2Y^2-]/[vo^2+][y3-]

           [vo^2+] = 18.7

[H2Y2-] = K f * [ v o+][Y^2-]

    [H2Y2] = 3.762 * 10^-13

 [ HY^3-] = 4.8 * 10^-23

So, the concentration of the    [ HY^3-] is 4.8 * 10^-23

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In aqueous solutions, the hydrogen ion, also known as the hydronium ion, is a Bronsted-Lowry acid, while the hydroxide ion is a base as a result of the self-dissociation reaction.

        [tex]C_4H_5N(aq) + H_2O(l)[/tex] ⇄ [tex]C_4H_5NH (aq) + OH^-(aq)[/tex]

        [tex]Bronsted-\\Lowry Acid[/tex]                    [tex]Conjugate Acid[/tex]

Any species that may transfer a proton (H+) to another molecule is a Brnsted-Lowry acid. Any species that can take a proton from another molecule is a Brnsted-Lowry base. In essence, a Brnsted-Lowry base is a proton acceptor (PA) and an acid is a proton donor (PD).

According to the Arrhenius theory, acids are defined as chemicals that dissociate in an aqueous solution to produce hydrogen ions (H+), whereas bases are defined as substances that produce OH (hydroxide ions).

The hydrogen ion, or hydronium ion, is a Brønsted–Lowry acid in aqueous solutions, and the hydroxide ion is a base, by virtue of the self-dissociation reaction.

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Molar concentration of Sodium chloride (NaCl) means the number of moles of sodium chloride present in 1L of water.

Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5g

∴ 1L of water contains 55.55 moles of water. Hence,

Mass of ocean water = 55.55 × 18 = 999.9g

Since, 1L of ocean water has a mass of 999.9g of which 3.5% is the salt.

hence, (999.9) (0.035) = 34.99g

So, No. of moles of NaCl = Mass of NaCl / 58g NaCl per mol

No. of moles of NaCl = 34.99/58.5

No. of moles of NaCl = 0.59 moles

So, Molar concentration or Molarity would be 0.59 moles present in 1L of solution.

Hence, Molarity or Molar Concentration = Moles of NaCl/ Volume of solution (in L)

Molarity = 0.59/1L

⇒ Molarity = 0.59M

Hence, the molarity is 0.59M

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The solubility KI is 50 g in 100 g of H₂O at 20 °C. if 110 grams of ki are added to 200 grams of H₂O the solution will be saturated.

Solubility is a condition where the solute is fully dissolved in the solvent. When fully mixed with the solvent.

Given that 50 g of KI is added to 100 g of water at 20 °C it means 100 g of water can dissolve a maximum of 50 g of  KCl.

1 g of water will dissolve an quantity of 0.5 g of  KCl.

To assay for 200 g of water: 200 g of water can disintegrate a maximum of (0.5) x 200 g of  KCl.

The maximum amount of KCl that will dissolve is 100 g

Actualised amount dissolved = 110 g

when Amount dissolved > Maximum solubility limit

110 g > 100 g

Thus,  the solution is saturated.

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The pressure in atm is 6.8.

Calculation,

According to ideal gas law,

PV = nRT           ..(i)

Putting the value of all given data in equation (i) we get,

P×5.43 L =  1.82 moles ×247.50 K × 0.082 atm L/K mol

P =  1.82 moles ×247.50 K × 0.082 atm L/K mol /5.43 L = 6.8 atm

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99 140-10-3.

99 140-10-3 is the compound number for trans-cinnamic acid.

Phenolacrylic acid

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The standard free energy change ΔG° at 600 K is equal to  1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .

Calculation ,

ΔG° = - RT㏑Kp

Where ΔG° = standard free energy change =  1. 4×[tex]10^5[/tex]J/mol

R = universal gas constant  = 8.3 J / K mol

T = temperature = 600K

Kp  = equilibrium constant

Now putting the value of all data in equation (i) we get ,

1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp

- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K  = ㏑Kp

㏑Kp = - 6972×[tex]10^5[/tex]

Kp = 0

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The number of atps generated is 330 ATP

At the cellular level, energy is used and stored as adenosine triphosphate (ATP). Adenine, ribose, and three serially bound phosphate groups make up the structure of ATP, which is a nucleoside triphosphate.

Glycerol provided us with 2 ATP and 2 NADH. In b-oxidation, we obtained 8 NADH and 8 FADH from each fatty acid, but since there were 3 fatty acids, we also produced 24 NADH and 24 FADH. We used 24 acetyl-CoA molecules, which were converted into 24 ATP, 24 FADH, and 72 NADH molecules by the citric acid cycle. You should obtain the same figures after adding everything up.

80 NADH x 3 ATP/NADH = 240 ATP

32 FADH x 2 ATP/FADH = 64 ATP

102 + 64 + 26 ATP = 330 ATP.

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The moles of hydrogen in the talc sample are 5.67 moles.

Talc are the hydrous silicate minerals. The chemical formula of talc is Mg₃Si₄O₁₀(OH)₂.

From the formula it can be determined that there are: 3 moles of Mg, 4 moles of Si, 12 moles of O and 2 moles of H.

Moles are a type of SI unit of measurement of the amount of substance.

According to the question, magnesium = 8.5 moles

Also, 3 moles of Mg = 2 moles of H

Therefore, moles of H = 8.5 moles × (2 moles H / 3 moles Mg)

                 moles of H = 5.67 moles

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The mass of copper releases 112.4 kj of heat as it freezes is 549 gm.

The most typical illustration is when solid ice transforms into liquid water. The molecules within in the substance become less structured as a result of this process, which is also known as melting or heat of fusion.

Calculation for mass of copper;

The heat of fusion for copper is given as 13.0 kj/mol.

Hfus(Cu) = 13.0 kJ/mol

The heat released during the process is  112.4 kj.

Q = 112.4 kJ;

The formula for molar heat of substance is;

Q = n(Cu) · Hfus(Cu).

Where n(Cu) is the number of moles of copper present in the solution.

Write formula in terms of Number of moles.

n(Cu) = Q / Hfus(Cu)

Substitute the given values;

n(Cu) = 112.4 kJ / 13.0 kJ/mol.

n(Cu) = 8.65 mol (number of moles of copper present)

m(Cu) = n(Cu) · M(Cu).

Where, m(Cu) is the mass of copper.

M(Cu) is the molecular mass of the copper.

Substitute the values in the formula to get the mass.

m(Cu) = 8.65 mol × 63.546 g/mol.

m(Cu) = 549.428 g

Therefore, the mass of copper present in the solution was 549.428 g.

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Answer: C.) 549 g

Explanation:

Question:

If butane had a volume of 500 ml. at a pressure of 1.5 atm and a temperature of 20 °C, what would the new volume of the gas be at a temperature of 30 °C and a pressure of 500 Torr?

Solution Given:

Let P be the pressure V be volume and and T be temperature.

Volume of Butane [[tex]V_1[/tex]] = 500 ml

Pressure of Butane [[tex]P_1[/tex]] = 1.5 atm

Temperature [[tex]T_1[/tex]] =20°C=20+273=293K

New Volume of Butane [[tex]V_2[/tex]] = ?

New Pressure of Butane [[tex]V_2[/tex]] =500 Torr=500*0.00131579=0.657895 atm

Note: 1 Torr= 0.00131579 atm

New Temperature of Butane [[tex]V_2[/tex]] =30°C=30+273=303K

Now

By using combined gas law equation:

[tex]V_2=V_2*\frac{P_1*T_2}{P_2*T_1}[/tex]

[tex]V_2=500*\frac{1.5*303}{0.657895*293}=1178.9 ml[/tex]

The new volume of Butane is 1178.9 ml

True

The bare minimum required standard

The minimal necessary standard restricts uses, disclosures, and requests for PHI to the bare minimum amount required to fulfil the use's or disclosure's intended purposes.

Under the Privacy Rule's Minimum Necessary Standard, covered entities are required to take all necessary precautions to ensure that protected health information (PHI) is only accessed as much as is required to carry out the duties at hand.

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Answer:

Hi there. In this question, we are trying to classify this reaction type. What we see happening here is we're told that we have sulfur which is in its solid state and it is reacting with solid iron And they're going to produce solid Iron three sulfide. So that is going to be f. E two S. Three. And that is a solid. I know it was F. E two S. Three because the iron three tells us the charge on the iron is three plus and sulfur voice forms ions with a too negative charge. Therefore it has to be FE two S 3. We can balance this equation although that's not necessary for this problem. But it's kind of quick. So I'll go ahead and do that. Okay, but we want to know what type of reaction it is. So we're looking for a pattern here when we see an element sulfur, it's combining with another element iron and it's producing a compound. So only one product. Alright, so looking at this general reaction type, there's only one reaction type of those five listed there, there's only one reaction type that has just one product and that is a synthesis reaction. A synthesis reaction follows this pattern where we are taking two or more simpler substances and combining them to make more complex compounds. Alright, with the simplest synthesis being element plus element equals compound. So this would be a synthesis reaction. Thank you for asking a question. And I hope this was helpful

Answer:

It should be D) Combustion Reaction

We know that,

acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)

There is a total of three atoms present in the water (H₂O) molecule.

An atom is the smallest particle of an element that may or may not be capable of independent existence.

A molecule is the smallest particle of an element or compound that can exist freely.

Subscripts are the numbers that come below after a symbol. They tell you the number of atoms of an element. If there is no subscript then it is understood that the subscript is 1.

For calculating the number of atoms in a molecule, add the subscripts of that molecule, and you will get the total atoms of it.

For example, in molecule C₂H₅O, there are 2 carbon atoms, 5 hydrogen atoms, and 1 oxygen atom.

Add the subscripts

2 + 5 + 1 = 8

Hence, there is a total of 8 atoms in C₂H₅O.

For the H₂O molecule,

2 + 1 = 3

Hence, there is a total of 3 atoms present in one water molecule.

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Answer:

  3.0×10⁻¹³ M

Explanation:

The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.

The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.

  Ksp = [Al₃⁺³]×[OH⁻]³

The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.

This means the solubility product equation is ...

  Ksp = x(10⁻⁷ +3x)³

For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...

  3.0×10⁻³⁴ = x(10⁻⁷)³

Then x = [Al₃⁺³] will be ...

  [tex][\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}[/tex]

We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.

__

Additional comment

The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.

Equilibrium constant for the reaction is

[tex]\sf K_{sp}=[Al^{3+}][OH^-]^3[/tex]

So

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{(10^{-7})^3}[/tex[

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{10^{-21}}[/tex]

[tex]\\ \rm\Rrightarrow s=3.0\times 10^{-13}M[/tex]

Answer:

c )   16

Explanation:

C4 H10 O    +   6 O2  =====>  4  CO2  +   5  H2O

1 + 6 + 4 + 5 = 16

Answer:

C.) 16

Explanation:

An equation is balanced when there are equal amounts of each element on both sides of the reaction. These values can be modified by adding coefficients.

The unbalanced equation:

C₄H₁₀O + O₂ -----> CO₂ + H₂O

Reactants: 4 carbon, 10 hydrogen, 3 oxygen

Products: 1 carbon, 2 hydrogen, 3 oxygen

The balanced equation:

1 C₄H₁₀O +  6 O₂ -----> 4 CO₂ + 5 H₂O

Reactants: 4 carbon, 10 hydrogen, 13 oxygen

Products: 4 carbon, 10 hydrogen, 13 oxygen

Now, you can add the coefficients:

1 + 6 + 4 + 5 = 16