An experiment consists of drawing 1 card from a standard 52 card deck. let e be the event that the card drawn is a red card. find p(e)

Answer:

Step-by-step explanation:

assuming that he has an annual interest of 5% then his initial deposit would be rounded to $2,238.65

See below for the solution to the systems of equations

System of equations 1

Here, we have

y = -5x/3 + 3

y = x/3 -3

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, the point of intersection of the equations is (3, -2)

Hence, the solution to the system is (3, -2)

System of equations 2

Here, we have

y = 4x + 3

y = -x -2

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, the point of intersection of the equations is (-1, -1)

Hence, the solution to the system is (-1, -1)

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An equation which best represents the relationship between velocity and time is: B. v = 2.19x + 6.7.

A scatter plot can be defined as a type of graph which is used for the graphical representation of the values of two variables, with the resulting points showing any association (correlation) between the data set.

A linear function can be defined as a type of function whose equation is graphically represented by a straight line on the cartesian coordinate.

By critically observing the graph (see attachment) which models the data in the given table, we can infer and logically deduce that the linear function is given by:

v = 2.0852x + 6.3978

Therefore, an equation which best represents the relationship between velocity and time is:

v = 2.19x + 6.7.

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30 full cylindrical containers are required to completely fill the fish tank.

To find what is the least number of full cylindrical containers needed to completely fill the fish tank:

We know the volume of the cylinder is given by: [tex]V=\pi r^{2} h[/tex]

The volume of a cylinder:

[tex]V=\pi (\frac{6}{2} )^{2} (8)\\V=75\pi inches^{3}[/tex]

The volume of cube V = 24 × 24 × 12 = 6912 cubic inches

A number of full cylindrical containers are needed to completely fill the fish tank:

Therefore, 30 full cylindrical containers are required to completely fill the fish tank.

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To acquire 90000000 views on his channel, he has to upload 20 videos every month.

Every month, he  posts 3 videos to his  channel. An average number of people watch each video. = 1500000

In search of:

How many months must pass before he begins to receive 90,000,000 views on his channel?

Step 1

On his channel, he posts three videos each month.

The average number of views per video is.

3 Videos Receive Views

= 3 * 1500000

= 4,500,000 Views

Number of 4,500,000 views each month

Complete 90000000 Views

Step 2

Total Views/Months = Total Views/Total Views

Days in a month = 90000000/4500000

                             = 20

20 Monthly months in the number

To acquire 90000000 views on his channel, he has to upload 20 videos every month.

20  Months is the right response, so.

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Answer:

C: 1 Quart

Step-by-step explanation:

2 pints are the equivalent of 1 quart

Answer:1 Quart

Step-by-step explanation: Because 2 pints equals=1 quart

The ratio of bananas to fruit is 13 : 21

The given parameters are

Banana = 13

Apple = 8

The total number of fruits is

Fruit = Banana + Apple

Substitute the known values in the above equation

Fruit = 13 + 8

Evaluate the sum

Fruit = 21

The ratio of bananas to fruit is then represented as:

Ratio = Banana : Fruit

Substitute the known values in the above equation

Ratio = 13 : 21

Hence, the ratio of bananas to fruit is 13 : 21

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The probability that a student chose football given that they like watching sports is: c. 0.27.

Using this formula

P[Like (Football)/Like (Sport)]

Where:

P=Probability

Like (Football)=0.23

Like (Sport)=0.23+0.18+0.26+0.17=0.84

Let plug in the formula

P[Like (Football)/Like (Sport)]=0.23/0.84

P[Like (Football)/Like (Sport)]=0.27

Therefore the probability that a student chose football given that they like watching sports is: c. 0.27.

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Answer:

C.

Step-by-step explanation:

[tex]denote \: by \: s \: the \: cost \: of \: a \: sweatshirt \\ denote \: by \: t \: the \: cost \: of \: a \: t \: shirt[/tex]

[tex]3t + 7s = 240.5 \\ 6t + 5s = 220[/tex]

[tex] - 6t - 14s = - 481 \\ 6t + 5s = 220[/tex]

[tex] - 9s = - 261 \\ s = \frac{ - 261}{ - 9} = 29 \: dollars[/tex]

[tex]3t + 7(29) = 240.5 \\ [/tex]

3t + 203 = 240.5

3t = 37.5

t = 12.5 dollars

Answer:

Part 1) Option B. y = 10x + 45

Part 2) The score is 95

Step-by-step explanation:

Linear equation that best describes the given model

Let

x ---> number of hours students spent studying

y ---> their score on the test

Looking at the line that was fit to the data to model the relationship

The slope is positive

The y-intercept is the point (0,45)

For x=1, y=55 ----> point (1,55)

Find the slope

The formula to calculate the slope between two points is equal to

substitute the points (0,45) and (1,55)

Find the equation of the line in slope intercept form

we have

substitute

Part 2) Estimate the score for a student that spent 5 hours studying.

For x=5 hours

substitute in the linear equation and solve for y

The equivalent expression of the radical expression ∛1080 is 6∛5

The radical expression is given as

∛1080

Express 1080 as 216 * 5

∛1080 = ∛(216 * 5)

Split the factors

∛1080 = ∛216 * ∛5

Evaluate the cube root of 216

∛1080 = 6 * ∛5

Evaluate the product

∛1080 = 6∛5

Hence, the equivalent expression of the radical expression ∛1080 is 6∛5

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By the alternating series test, this series converges: for [tex]k\in\Bbb N[/tex],

[tex]\dfrac{k^5+1}{k^6+11}[/tex]

is a positive, decreasing sequence that converges to 0.

However,

[tex]\displaystyle \sum_{k=2}^\infty \left| (-1)^{k+1} \frac{k^5+1}{k^6+11} \right| = \sum_{k=2}^\infty \frac{k^5+1}{k^6+11} \approx \sum_{k=2}^\infty \frac1k[/tex]

is a divergent series by comparison to the harmonic series.

So the given series is conditionally convergent.

The given series is conditionally convergent. This can be obtained by using alternating series test first and then comparing the series to the harmonic series.

Initially we need to know what Absolute convergence and Conditional convergence,

If [tex]\sum|a_{n} |[/tex] → converges, and [tex]\sum a_{n}[/tex] → converges, then the series is Absolute convergence

If [tex]\sum|a_{n} |[/tex] → diverges, and [tex]\sum a_{n}[/tex] → converges, then the series is Conditional convergence

First use alternating series test,

[tex]\lim_{k \to \infty} \frac{k^{5} +1}{k^{6}+11 }[/tex] = [tex]\lim_{n \to \infty} \frac{5}{6k}[/tex] = 0,

The series is a positive, decreasing sequence that converges to 0.

Next by comparing the series to harmonic series,

[tex]\sum^{\infty} _{k=2}|(-1)^{k+1} \frac{k^{5} +1}{k^{6}+11 }|=\sum^{\infty} _{k=2}\frac{k^{5} +1}{k^{6}+11 }[/tex] ≈  [tex]\sum^{\infty} _{k=2}\frac{1}{k}[/tex] = 0

This implies that the series is divergent by comparison to the harmonic series.

First we got that the series is converging and then we got the series is divergent. Therefore the series is conditionally convergent.

[tex]\sum|a_{n} |[/tex] → diverges, and [tex]\sum a_{n}[/tex] → converges, then the series is Conditional convergence.

Hence the given series is conditionally convergent.

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Answer:144

Step-by-step explanation: a coin has 2 possibilities so 2 coins have 2x2 = 4 possibilities. A normal six-sided dice has 6x6 = 36 possibilities. 4 x 36 = 144 (this might be wrong)

Answer:

C

Step-by-step explanation:

You are dividing BOTH sides by 3.

"The division property of equality states that when we divide both sides of an equation by the same non-zero number, the two sides remain equal."

Answer:

Step-by-step explanation:

400*60% can be rewriten as 400×0.6 which is 240, so a is false.

the same steps can be repeated for b and c

b) 200*0.6=120, therefore is false

c) 120*0.6=72, therefore is false

2)

[tex]60 percent * x=87\\0.6x=87\\x=\frac{87}{0.6} \\\\x=145[/tex]

Now we check the answer by using the same steps in problems a,b,c

[tex]145*0.6=87\\87=87[/tex]

3)

[tex]0.6c=43.2\\c=\frac{43.2}{0.6} \\c=72[/tex]

and finally

[tex]0.38e=190\\e=\frac{190}{0.38} \\e=500[/tex]

Answer:
the answer to the question is answer C

Answer:

Step-by-step explanation:

B is your answer

Answer:

Step-by-step explanation:

To find:

Given:

[tex]\sf{7p+4=-p+9+2p+3p}[/tex]

Isolate the term of p, from one side of the equation.

Combine like terms.

[tex]\rightarrow \sf{7p+4=-p+2p+3p+9}[/tex]

Add the numbers from left to right.

-p+2p+3p=4p

7p+4=4p+9

Then, you subtract by 4 from both sides.

[tex]\sf{7p+4-4=4p+9-4}[/tex]

Solve.

7p=4p+5

Subtract by 4p from both sides.

7p-4p=4p+5-4p

Solve.

[tex]\boxed{\sf{3p=5}}[/tex]

Divide by 3 from both sides.

3p/3=5/3

Solve.

p=5/3

Divide is another option.

5/3=1.6666

So, the final answer is 3p=5.

I hope this helps, let me know if you have any questions.

The range of the function y = -x² - 3x when the domain is {-5,0,2} is:

{-10, 0}.

The range of a function is the set that contains the output values for the given domain of the function.

In this problem, the domain is:

{-5,0,2}.

Hence the output values are:

Hence the range is:

{-10, 0}.

-10 repeats, but goes only once on the range.

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The function y = 2sin has a phase shift of pi/2 to the right (2x - pi).

To find the function which has a phase shift to the right:

The function has a phase shift of pi/2 to the right.

By definition, you have the phase shift is:

When you substitute the values from the function [tex]y=2sin(2x-\pi )[/tex], where  [tex]c=-\pi[/tex]  and [tex]b=2[/tex], you obtain:

Therefore, the function y = 2sin has a phase shift of pi/2 to the right (2x-pi).

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The complete question is given below:
Which function has a phase shift of pi/2 to the right?

Step-by-step explanation:

a ∈ (0; π/2) here means that our angle, a must lie between 0 and pi/2, exclusive.

So this mean our angle must be in between 0 and pi/2, but can not be neither 0 and pi/2.

Here we have

[tex] \sin( \alpha ) = \frac{3 \sqrt{11} }{10} [/tex]

We must find cos.

Using the Pythagorean theorem

[tex]( \sin( \alpha ) ) {}^{2} + ( \cos( \alpha ) ) {}^{2} = 1[/tex]

It is mostly notated as this,

[tex] \sin {}^{2} ( \alpha ) + \cos {}^{2} ( \alpha ) = 1[/tex]

But they mean the same thing, we know

[tex] \sin( \alpha ) = \frac{3 \sqrt{11} }{10} [/tex]

So we plug that in for sin a.

[tex]( \frac{3 \sqrt{11} }{10} ) {}^{2} + \cos {}^{2} ( \alpha ) = 1[/tex]

[tex] \frac{99}{100} + \cos {}^{2} ( \alpha ) = 1[/tex]

[tex] \cos {}^{2} ( \alpha ) = \frac{100}{100} - \frac{99}{100} [/tex]

[tex] \cos {}^{2} ( \alpha ) = \frac{1}{100} [/tex]

Since cos is Positve over the interval (0; π/2), we take the positive or principal square root.

[tex] \cos( \alpha ) = \frac{1}{10} [/tex]

2. We would get the same work for the second part, the only difference is that cosine is negative over the interval

(π/2, π)

So the answer for 2 is

[tex] \cos( \alpha ) = - \frac{1}{10} [/tex]

Disclaimer: Your work you did was correct, just remember for fractions like

[tex]1 - \frac{99}{100} [/tex]

Convert 1 into a fraction that has a denominator of 100.

[tex] \frac{100}{100} - \frac{99}{100} = \frac{1}{100} [/tex]

The maximum area is achieved when the rectangle is a square of side 6 feet, with a domain, 0 < x < 12.

The perimeter available with Brayden is 24 feet.

The width of the rectangle is assumed to be x feet.

The length can be calculated using the formula:

2(length + width) = perimeter,

or, 2length + 2width = perimeter,

or, 2length = perimeter - 2width,

or, length = (1/2)(perimeter - 2 width).

Substituting the values, we get:

length = (1/2)(24 - 2x).

The area can be calculated using the formula:

Area = length*width.

Substituting the values, we get:

Area = (1/2)(24 - 2x)x = (1/2)x(24 - 2x).

Now, we need to maximize the area for the given perimeter.

For that, we differentiate the area function, with respect to its width x.

d(Area)/dx = (1/2)(24 - 2x) + (1/2)x(-2),

or, d(Area)/dx = 12 - x - x = 12 - 2x ... (i).

To check for the point of inflection, we equate this to zero, to get:

12 - 2x = 0,

or, 2x = 12,

or, x = 6.

To check whether this is maximum or  minimum, we differentiate (i) with respect to x to get:

d²(Area)/dx² = -2 which is less than 0, implying area is maximum at x = 6.

Thus, the maximum area is achieved when the width is 6 feet.

Length = (1/2)(24 - 2x) = (1/2)(24 - 2*6) = (1/2)12 = 6.

Thus, the maximum area is achieved when the length is 6 feet.

The area function is, area = (1/2)x(24 - 2x).

We know that the area is always greater than 0, thus, we can show that:

(1/2)x(24-2x) > 0,

or, x(24 - 2x) > 0,

or, x(12 - x) > 0, which is true when 0 < x < 12.

Thus, the domain of the area function is 0 < x < 12.

Thus, the maximum area is achieved when the rectangle is a square of side 6 feet, with a domain, 0 < x < 12.

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The height of the flag pole which is described as in the task content is; 8.2m.

The horizontal distance between the 6m house and the flagpole in discuss can be evaluated by means of the angle of depression and trigonometric identity, tan as follows;

tan 22° = 6/x

x = 6/tan 22 = 14.9m.

Consequently, the horizontal distance from the top of the house to the top of the flagpole is therefore;

tan 9° = y/14.9

y = 14.9 tan 9° = 2.2m

Ultimately, the height of the flagpole is; 6+2.2 = 8.2m.

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The volume of the triangular prism as described is; 20 cubic foot.

A triangular pyramid refers to pyramid which has a triangular base

It follows from the formula for calculating the volume of a triangular prism that;

Volume = (1/3) × base area × height.

Consequently,

volume of the prism = (1/3) ×5 × 12

Volume = 20 cubic foot

Therefore, volume of the triangular prism as described is; 20 cubic foot.

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Answer:

output = 9

Step-by-step explanation:

add 5 to the input to obtain output

output = 4 + 5 = 9

The function to represent the problem is f(x)=6x+24 and the range is 30[tex]\leq[/tex]y[tex]\leq[/tex]48.

If the terms of a sequence differ by a constant, we say the sequence is arithmetic. If the initial term ([tex]a_{0}[/tex]) of the sequence is a and the common difference is d, then we have,

[tex]a_{n}[/tex]=a+(n-1)d

Initial number of clients=30

Number increase per week= 6

So, we can make an arithmetic sequence fir six weeks

30,36,42,48

Here, first term, a=30

Common difference, d=6

Range is [30,48]

The explicit formula of an arithmetic sequence is

[tex]a_{n}[/tex]=a+(n-1)d

Put a=30, d=6, n=x

[tex]a_{x}[/tex]=30+(x-1)6

[tex]a_{x}[/tex]=30+6x-6

[tex]a_{x}[/tex]=6x+24

Therefore, The function to represent the problem is f(x)=6x+24 and the range is 30<=y<=48

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Answer:

4 degrees ( to nearest degree).

Step-by-step explanation:

The trig ratio you want is the tangent.

tan x = 10,000 / 160,000    where x is the angle of depression.

tan x = 0.0625

x = 3.576 degrees.

The probability that a randomly selected adult has an IQ less than 130 is 0.9332

For given question,

We have been given adults IQ scores that are normally distributed with a mean of μ = 100 and a standard deviation σ = 15.

We need to find the probability that a randomly selected adult has an IQ less than 130

Sketch the curve.

The probability that X < 130 is equal to the area under the curve which is less than X = 130

Since μ = 100 and σ = 15 we have:

⇒ P ( X < 130 ) = P ( X- μ < 130 - 100 )

⇒ P ( X < 130 ) = P((X− μ)/ σ < 130 - 100/20 )

Since (X-μ)/σ = Z and (130 - 100)/20 = 1.5 we have:

P (X < 130) = P (Z < 1.5)

Now, we use the standard normal table to conclude that:

P (Z < 1.5) = 0.9332

Therefore, the probability that a randomly selected adult has an IQ less than 130 is 0.9332

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Answer:

C

Step-by-step explanation:

C

Answer:

Step-by-step explanation:

its c