An electron moving perpendicular to a magnetic field of 3. 2 × 10-2 t moves in a circle of radius 0. 40 cm. this electron is moving with 2.25 x 10⁷ m/s
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.
A magnetic field is defined as a location in space close to a magnet or an electric current where a physical field is formed by a moving electric charge acting as a force on another moving electric charge. The magnetic field of the Earth is an illustration of a magnetic field. The region around a magnet where the effects of magnetism are felt is known as the magnetic field.
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Among merge sort and quick sort, which algorithm takes more spaces? what strategy is used by the other algorithm to use less space and run slightly faster in average case?
Merge sort requires more space than quick sort. Bogo sort is used by the other algorithm to use less space and run slightly faster in average case.
To find the answer, we need to know more about the Maxillary space.
What is Maxillary space?Quicksort consumes less space and has better cache locality than merge sort, which uses more space. An in-place sorting algorithm is quick sort. No additional storage space is required for sorting when it is done in-place. Because Join Sort does not exist, Quick Sort has the advantage of space since Merge Sort needs a temporary array to merge the sorted arrays.Thus, we can conclude that, merge sort requires more space than quick sort. Bogo sort is used by the other algorithm to use less space and run slightly faster in average case.
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The cost of operating an electrical appliance is based upon its
Aage.
Bease of use.
Cwattage and time used.
D original purchase price.
Answer:
wattage and time used
Explanation:
Look
If a electrical appliance has more power or wattage it will use more energy and cost more
If a electrical appliance is used for more time the cost is more
Hence Option C is correct
Two objects of mass 3 kg and 2 kg are thrown with velocities 2 ms-1 and 3 ms-1 , respectively. Calculate the momentum of both. Which has a greater momentum?
Answer:
They have the SAME momentum ....see below
Explanation:
Momentum = m v
3 3kg * 2 m/s = 6 kg-m/s
2 2kg * 3 m/s = 6 kg - m/s
A clock on a moving spacecraft runs 1s slower per day relative to an identical clock on earth. What is the relative speed of the spacecraft?
The craft is moving at a speed of v = 0.024c or around 7 million metres per second or 16 million miles per hour.
The time dilation factor is equal to 3600/3599 if we only want 3599 seconds of the craft's time to pass for every hour (3600 seconds) of Earth time. However, there is a connection as well.
γ = [tex]\frac{3600}{3599}[/tex] = Dilation factor
Also, γ = 1/ √[tex]1-v^{2}[/tex]/[tex]c^{2}[/tex]
which we can solve algebrically to yield,
[tex]\frac{v}{c}[/tex] = √1-1/γ[tex]^{2}[/tex]
we get,
[tex]\frac{v}{c}[/tex] = 0.024
v= 0.024c
Accordingly, the craft is moving at a speed of v = 0.024c, or around 7 million metres per second or 16 million miles per hour.
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What quantities determine the resistance of a piece of material? choose all that apply
The resistance depends upon the length, area and material of the material.Option (a), (b) and (c) is correct.
Quantities that determine the resistance:
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. Resistance also depends on the material of the conductor.
A conductor's or circuit element's resistance typically rises as temperature rises. Some conductors exhibit negligible resistance at very low cooling rates. Even after the electromotive force is removed from these substances, known as superconductors, currents still flow through them.The conductance, 1/R, is the reciprocal of resistance and is measured in reciprocal ohm units, or mho.
The complete question is:
What quantities determine the resistance of a piece of material? Choose all that apply.
a)The length of the piece of material
b)The cross-sectional area of the piece of material
c)The type of material
d)The voltage across the material
e)The current flowing through the piece of material
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A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface charge density on the sphere?
The surface charge density on the sphere is 0.014C/[tex]m^{2}[/tex].
Given,
r=5.00cm=0.05m, q=7. 5 µc
We know surface charge density σ =q/V=[tex]\frac{7.5*10^{-6} }{\frac{4}{3}\pi 0.05^{3} }[/tex]=0.014C/[tex]m^{2}[/tex].
Surface charge densityIt is always important to know how charge is moving in an electric field. These fields will also build up electric charges. Therefore, estimation of the surface charge density is essential for a number of applications. It is also necessary to calculate the surface charge density of an electric object using its volume and surface area. The amount of electric charge that has collected in a given field is measured by the surface charge density. Using the dimensions provided, it determines the amount of electric charge. Dimensions of the electric body could be in the form of length, area, or volume. In one, two, or three dimensions, according to electromagnetism, surface charge density is a measurement of the amount of electric charge present in a given volume of space.
A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface surface charge density on the sphere?
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A 0.20-μf capacitor is connected to a 300-v battery. What potential energy is stored in the capacitor?
A 0.20-μf capacitor is connected to a 300-v battery, the potential energy is stored in the capacitor will be 9 * [tex]10^{-3}[/tex] J
The energy stored in a capacitor is nothing but the electric potential energy and is related to the voltage and charge on the capacitor. If the capacitance of a conductor is C, then it is initially uncharged and it acquires a potential difference V when connected to a battery.
Its two plates hold opposite charges and the separation between them creates an electric field. That's why a capacitor stores energy.
Capacitance = 0.20 * [tex]10^{-6}[/tex]
voltage = 300 V
Potential energy stored in a capacitor = 1/2 *C * [tex]V^{2}[/tex]
= 1/2 * 0.20 * [tex]10^{-6}[/tex] * [tex](300)^{2}[/tex]
= 9000 * [tex]10^{-6}[/tex]
= 9 * [tex]10^{-3}[/tex] J
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How would a small bar magnet be oriented when placed at position X?
Based on the document attached, the small bar magnet will be oriented when placed at position X is option d:
What is the magnet position about?The orientation of the magnets is known to be one that do affect its magnetic force. Atoms atoms, such as iron, are known to often gives a stronger magnetic force when compared to other atoms.
These atoms can be seen as tiny magnets, that has the north and south of each pole. If the poles is known to be oriented in all directions, the material will not bring about a net magnetic force.
Therefore, Based on the document attached, the small bar magnet will be oriented when placed at position X is option d because the shapes of the magnetic field lines in regards to the bar magnet are said to be closed.
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A person of weight 600 n is standing with one foot on each of two bathroom scales. The scales readings are?
The scales readings are 300 N for each of the scale.
What is weight?The weight of an object is the force acting on the object due to gravity.
Weight is a vector quantity because it varies from place to place due to difference in acceleration due to gravity and it is measured in Newton (N).
Reading of each scaleThe total weight of the person is supported by the two legs and if the person stand on a level ground, the weight will be evenly distributed and each scale will carry half of the person's weight.
The reading of each scale due to the weight of the person is calculated as follows;
Reading of each scale = total weight / 2
Reading of each scale = 600 N/2
Reading of each scale = 300 N
Thus, the scales readings are 300 N for each of the scale.
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Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Earth? Select ALL that apply.
A
Radio waves travel faster.
B
Radio waves take less energy to produce.
C
Radio waves transmit more types of information.
D
Radio waves have a lower frequency, which makes them safer for humans.
E
Radio waves have higher energy, which makes their signal easier to capture.
The correct options are:
D
"Radio waves have a lower frequency, which makes them safer for humans."
B
"Radio waves take less energy to produce."
Why do we radio waves over other electromagnetic waves to transmit information to Earth?
Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.
Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.
Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.
With that in mind, the correct options are.
D
"Radio waves have a lower frequency, which makes them safer for humans."
B
"Radio waves take less energy to produce."
These are the two main reasons of why we use radio waves.
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A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 kg/s, what is the terminal speed of the marble in m/s?.
The terminal speed of the marble is 0.588 m/s.
Given:
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
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450n 360n 710n 1400n 230n a block is placed in oscillation on a frictionless horizontal surface attached to a spring that is also attached to a wall. If, when stretched away from equilibrium by 15cm and released, it oscillates with a period of 0. 25s, and if the mass of the block is 15kg, what force was required to stretch the spring by the initial 15cm?.
Answer:
m = 15, P = .25, x = .15
F = -K x for spring
ω = (K/m)^1/2
ω^2 = K / m
K = m ω^2 = m (2 π f)^2 = m 4 π^2 / P^2
K = 4 π^2 m / P^2
F = K x = x * 4 π^2 m / P^2
F = .15 * 4 * π^2 * 15 / .25^2
F = 1420 N
Please Help!!!
Which statement best describes the types of bonds shown in the diagram?
an ionic bond; a hydrogen ion is bonding with a chlorine atom
a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom
a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom
an ionic bond; the hydrogen chloride molecule has an electrical charge
Answer: B
Explanation:
The statement that best describes the types of bonds shown in the diagram is a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom, therefore the correct answer is the option B
What is a covalent bond?When two similar or dissimilar atoms form bonds with each other by sharing their valence electron the bond is known as the covalent bond.
The ionic bond is the result of the transfer of the electrons
Ionic bonds are formed between the pair of one electronegative atom and an electropositive atom.
As shown in the diagram there is sharing of the electrons between the hydrogen and the chlorine atom, and we know that covalent bonds are formed by the sharing of the electrons
Since the diagram's covalent bonds are best described by the statement that the hydrogen atom's single electron is shared with the chlorine atom, option B is the right response.
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What is the volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m?
The volume of a solution, in milliliters, that contains 1. 5 g lino3 and has a concentration of 0. 40 m will be 54.35 m L.
Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
Molarity = n / V
where
n = number of moles
V = volume of solution in l
Molar mass of [tex]LiNO_{3}[/tex] = M of Li + M of N + 3 * M of O
= 7 + 14 + (3*16)
= 69 g/ mole
since , M = n / V
n = m / molar mass of [tex]LiNO_{3}[/tex]
substituting the value of n
Molarity = (m / molar mass of [tex]LiNO_{3}[/tex] ) / V
V = m / molar mass of [tex]LiNO_{3}[/tex] * Molarity
= 1.5 / 69 * 0.40
= 54.35 mL
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Please help! I need this due for homework.
Explanation:
I don't know the exact word which u have to put in the blank spaces.
But Newton's Third Law States:
If a force is exerted there will always be an equal and opposite reactive force.
Officials want to reduce the possibility of oil leaks into bodies of freshwater drinking sources. therefore, the government insists that oil refineries undergo monthly inspections. for what reason would the government regulate monthly inspections at oil refineries? save the refinery money increase domestic oil production protect the public from pollution encourage foreign oil imports to drive down prices
Answer:
protect public from pollution
Explanation: got it right
(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.
The time taken for the tiny saliva to travel is 0.55 second.
The horizontal distance traveled at speed of 4 m/s is 2.2 m.
The horizontal distance traveled at speed of 20 m/s is 11 m.
Time of motion of the tiny saliva
The time taken for the tiny saliva to travel is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0g is the acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
Substitute the given parameters and solve for time of motion;
t = √(2 x 1.5 / 10)
t = 0.55 second
Horizontal distance traveled at speed of 4 m/sX = Vx(t)
X = (4 m/s)(0.55)
X = 2.2 m
Horizontal distance traveled at speed of 20 m/sX = (20)(0.55)
X = 11 m
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Give one example of a thermodynamic cycle that does not account for the carnot efficiency.
Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.
The Carnot cycle is a hypothetical cycle that takes no account of entropy generation. It is assumed that the heat source and heat sink have perfect heat transfer. The working fluid also remains in the same phase, as opposed to the Rankine cycle, in which the fluid changes phase. A practical thermodynamic cycle, such as the Rankine cycle, would achieve at most 50% of the Carnot cycle efficiency under similar heat source and heat sink temperatures.
What is Thermo-Electrochemical converter?In a two-cell structure, a thermo-electrochemical converter converts potential energy difference during hydrogen oxidation and reduction to heat energy.
It employs the Ericsson cycle, which is less efficient than the Carnot cycle. In a closed system, it converts heat to electrical energy. There are no external input or output devices.
This means there will be no mechanical work to be done, as well as no exhaust. As a result, Carnot efficiency is not taken into account in this cycle. Carnot efficiency is accounted for by other options such as turbine and engine.
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When the atmosphere becomes loaded with particles, only the _____ wavelengths are able to penetrate the atmosphere.
Visible light are able to penetrate the atmosphere
What is Wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm).
The electromagnetic spectrum is made up of a variety of electromagnetic radiations, including radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays, and gamma rays. Because the earth's atmosphere blocks off the majority of the electromagnetic spectrum's wavelengths, most electromagnetic energy from space cannot reach the planet's surface.
. A portion of the electromagnetic spectrum that humans can see with our eyes is the visible light or spectrum. The electromagnetic spectrum's band that can most easily reach Earth's surface is also this one.
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If the current in an inductor is doubled, by what factor is the stored energy multiplied?
a. 4
b. 1/4
c. 2
d. 1/2
e. 1
_______________
[tex]I_2=2I_1[/tex]
[tex]L=\text{const}[/tex]
_______________
[tex]\displaystyle \frac{W_2}{W_1}\; - \;?[/tex]
_______________
[tex]\displaystyle \boldsymbol{\frac{W_2}{W_1}}=\frac{\dfrac{LI_2^2}{2} }{\dfrac{LI_1^2}{2} } =\frac{I_2^2}{I_1^2} =\bigg(\frac{I_2}{I_1} \bigg)^2=\bigg(\frac{2I_1}{I_1} \bigg)^2=2^2=\boldsymbol{4}[/tex]
A 0. 20-kg ball is attached to a vertical spring. the spring constant is 28 n/m. when released from rest, how far does the ball fall before being brought to a momentary stop by the spring?
A 0. 20-kg ball is attached to a vertical spring. The spring constant is 28 n/m. when released from rest, the ball will fall at a distance of x = 0.14 m before being brought to a momentary stop by the spring.
The spring constant is the force needed to stretch or compress a spring, divided by the distance that the spring gets longer or shorter. It's used to determine stability or instability in a spring
Elastic potential energy is Potential energy stored as a result of deformation of an elastic object, such as the stretching of a spring. It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched.
When ball is released from rest with spring , it will loose some potential energy . Hence , loss in potential energy of the ball = gain in potential energy of spring
m*g*x = 1/2 * k * [tex]x^{2}[/tex]
0.20 * 9.8 * x = 1/2 * 28 * [tex]x^{2}[/tex]
x = (2 * 0.20 * 9.8) / 28
x = 0.14 m
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Assume earth is approximately a uniform, solid sphere that has a mass of 5.98×1024 kg and a radius of 6.38×106 m. calculate the angular momentum ????z of earth as it spins on its central axis once each day.
The angular momentum of earth is
7×10^33 kgm^2/sec
Given:
mass of earth = 5.98×1024 kg
radius of earth = 6.38×10^6 m
To Find:
angular momentum
Solution:
For earth we have moment of inertia as
I = 2/5mR^2
and angular velocity as ω = 2π/T
Thus angular momentum is given as
L= 2/5mR^2*2π/T
L = 2/5*5.98×10^24*(6.38×10^6)^2*2*3.14/86400s
L = 7 × 10^33 kg/m^2/sec
So, angular momentum of earth is
So, angular momentum of earth is 7×10^33 kgm^2/sec
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What are the factors that cause land and water to heat and cool differently? choose all that apply.
The differential heating of Land and water depends on amount of solar energy reaching earth.
Land is a better conductor of heat than water, heating up and cooling down faster than water.
In summer, amount of solar radiation is highest hence difference of water and land temperature is highest. Air over land heats up and expands hence the air rises above. This rising air is replaced with the surrounding air rich in moisture content from over ocean surface. The degree of differential heating depends on amount of solar energy reaching earth's surface.
This results in Sea Breeze which is from a large body of water towards landmass due to difference in pressure created.
Land Breeze blows towards sea from land at night. It is due to difference in rate of cooling of land and ocean.
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A 1500-w heater is connected to a 120-v line for 2. 0 hours. how much heat energy is produced?
Answer:
10800 kJ
Explanation:
1 watt = 1 Joule /sec
1500 w = 1500 j/sec 2 hours = 7200 sec
1500 j/sec * 7200 sec = 10 800 000 j = 10 800 kJ
Metallic iron crystallizes in a body-centered cubic lattice, with one fe atom per lattice point. if the metallic radius of fe is 124 pm, what is the volume of the unit cell in pm3 and in cm3?
The volume of a unit cell is 4.3 × 10⁻¹⁰ pm³.
We need to start with the features of a face-centered cubic system in order to be able to determine the edge length of the unit cell.
As we know, a face-centered cubic system is characterized by a unit cell that has a total of 14 lattice points.
one lattice point for every one of the eight corners of the unit cell.one lattice point for every one of the six faces of the unit cell.Now, these lattice points will contain
1/8th of an atom in every corner lattice point.1/2 of an atom in every face lattice point.Assume that r is the edge length of the unit cell and that r is the radius of an iron atom. You'll see that we can represent x in terms of the cell's diagonal, d, using Pythagoras' Theorem.
[tex]d^2 = x^2+ x^2[/tex]
[tex]d^2=2x^2[/tex]
The cell's diagonal will be equal to one radius from the atom in the top corner, two from the atom in the face, and one from the atom in the lower corner.
[tex]d= r+2r+r = 4r[/tex]
This means that we have,
[tex](4r)^2=2x^2[/tex]
[tex]16.r^2 = 2x^2 \\x=\sqrt{8r^2}[/tex]
This is equivalent to
[tex]x=2\sqrt{2} r = 2\sqrt{2} .124= 350.7 pm[/tex]
So, the edge length of the unit cell is equal to 350.7 pm.
The volume of a unit cell. As we know, the volume of a cube is given by the formula
V = [tex]l[/tex] × [tex]l[/tex] × [tex]l[/tex]
[tex]l[/tex] = the edge length of the cube
Volume = (350.7)³ pm³
= 4.3 × 10⁻¹⁰ pm³
= 4.3e-30 cm³
Therefore, the volume of the unit cell is 4.3 × 10⁻¹⁰ pm³.
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What is the avergae percent increase in the count rate over the voltage range of the geiger tube plateau?
The average percent increase in the count rate over the voltage range of the Geiger tube plateau is less than 10 percent per 100 volts.
Geiger tubes are the sensing elements of Geiger counters, which are used to measure ionizing radiation. This tube is made of a thin-walled stainless steel and is filled with a mixture of Neon and Halogen gases at low-pressure
The Geiger–Müller tube is filled with an inert gas such as helium, neon, or argon at low pressure, to which a high voltage is applied. The tube briefly conducts electrical charge when a particle or photon of incident radiation makes the gas conductive by ionization.
After the quick rise, the counting rate levels off. This range of voltages is termed the ”plateau” region. Eventually, the voltage becomes too high and we have continuous discharge. The threshold voltage is the voltage where the plateau region begins.
For a good G-M tube, the plateau region should rise at a rate less than 10 percent per 100 volts. That is, for a change of 100 volts, should be less than 0.1.
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Light propagates from soda lime glass (n = 1.518) into pyrex glass (n = 1.473). determine the critical angle for this situation.
Light propogates from soda lime glass into pyrex glass of different refractive indices indicating a change in the medium which can be used to find out the critical angle.
The critical angle is the angle of incidence for which the angle of refraction comes out to be 90°. It is related to the refractive indices (Plural of refractive index) by the following relation:
Sini = 1/u, where u is the ratio of refractive index of medium 2 and medium 1
According to the question, Light propogates from soda lime glass (Medium 1, u1=1.518) into pyrex glass(Medium 2, u2=1.473), i.e. from a denser medium to rarer medium. So, the ratio of refractive index becomes u2/u1= 1.473/1.518=0.97
Putting the ratio in the above-mentioned formula,
∴ Sini = 1/0.97
i= 75.9°
Hence, the critical angle(i) for the given situation is 75.9°.
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The aeroplane then continues at a CONSTANT VELOCITY for a further 800 m before leaving the runway. The length of the runway is 2 000 m. 8 m-s-1 1 .2 1.3 → Define the term vector. Convert 67 m-s¹ to km.h¹. 67 m-s¹ Calculate the: .3.1 3.2 1.3.3 3.4 30 s 800 m Acceleration of the aeroplane during the first 30 seconds Distance travelled by the aeroplane during the first 30 seconds Time taken by the aeroplane to travel the 800 m Length of the runway NOT USED when the aeroplane leaves the runway (2) (1 (4 (4 (3
800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]
800 = 450a
a = 1.77m[tex]s^{-2}[/tex]
Distance = s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]s = 0+ [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]
s = [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]
s = 796.5m
Time taken = distance / velocityt = 800/8
t = 100 sec
Length of the runway not used = total length of runway-total length covered before leaving runway2000 -800
length = 1200m
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A disk rotates with constant angular acceleration of 5. 45~\text{rad/s}^25. 45 rad/s 2. starting from rest, it turns through 220 rad. how much time elapses while it turns through the 220 radians?
The time elapsed is 8.98 sec when it turns through the 220 radians.
given:
initial angular velocity (ω°) = 0 rad/secangular acceleration (α) =5.45 [tex]rad/sec^{2}[/tex]total angular displacement (Ф) = 220 radusing second equation of motion for rotation
we get ,
[tex]220=0.t + \frac{1}{2}.5.45.t^{2}[/tex]
t^2 =80.98
t=8.98sec
therefore time elapsed is 8.98sec .
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If the resistance in a circuit connected to a constant current is halved, how is the voltage in the circuit affected?.
Answer:
The voltage remains constant.
Answer:
The voltage in the circuit remains same. However the current drawn by the circuit will increase.
Explanation:
According to Ohm's Law:
V=IR
If we halved the resistance let:
R'=R/2
then
I'=2I in order to kept the Voltage same. Also the resistance is the opposition to the current. So, if resistance will halved then obviously current will double
So when we put these value in to Ohm's Law the results is:
V'=I'R'
V'=2I(R/2)
V'=IR which is equal to first voltage. Hence,
V'=V