An appliance manufacturer estimates that the profit y (in dollars) generated by producing x cooktops per month is given by the equation y = 10x + 0.5x2 − 0.001x3 − 6000, where 0 ≤ x ≤ 450.
(b) How many cooktops must be produced to begin generating a profit? (Round your answer to the nearest whole number.)
......cooktops
(c) For what range of values of x is the company's profit greater than $15,000? (Enter your answer using interval notation. Round numerical values to the nearest whole number.)

Answers

Answer 1

The company's profit greater than $15,000 the range of values for x when the company's profit is greater than $15,000 is approximately [170, 190] in interval notation.

To determine the number of cooktops that must be produced to begin generating a profit, we need to find the value of x for which the profit (y) is greater than zero.

The profit equation is given by:

y = 10x + 0.5x^2 - 0.001x^3 - 6000

To find the number of cooktops, we set y > 0 and solve for x:

10x + 0.5x^2 - 0.001x^3 - 6000 > 0

We can use numerical methods or a graphing calculator to solve this equation, or we can estimate the solution by plugging in values until we find the range of values that satisfies the inequality.

By substituting values, we find that the profit becomes positive when x is around 140 cooktops.

Therefore, approximately 140 cooktops must be produced to begin generating a profit.

To find the range of values for x when the company's profit is greater than $15,000, we need to solve the inequality:

10x + 0.5x^2 - 0.001x^3 - 6000 > 15000

Again, using numerical methods or a graphing calculator would provide a precise solution. However, we can estimate the range of values that satisfy the inequality by substituting values.

By substituting values, we find that the profit is greater than $15,000 when x is approximately between 170 and 190 cooktops.

Therefore, the range of values for x when the company's profit is greater than $15,000 is approximately [170, 190] in interval notation.

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Related Questions

an implicit Euler's method with an integration step of 0.2 to find y(0.8) if y(x) dy satisfies the initial value problem: 200(cos(x) - y) y(0) = 1 da Knowing the exact solution of the ode as: y(x) = cos(x) + 0.005 sin(2) - e-2002, calculate the true error and the number of correct significant digits in your solution.

Answers

The given differential equation is y'(x) = 1/200(cos(x) - y) y(0)

Using implicit Euler's method, we get:

y(i+1) = y(i) + hf(x(i+1), y(i+1))

Where,f(x, y) = 1/200(cos(x) - y)

At x = 0, y = y(0)

Using h = 0.2, we have,

x(1) = x(0) + h

= 0 + 0.2

= 0.2

y(1) = y(0) + h f(x(1), y(1))

Substituting the values, we get;

y(1) = y(0) + 0.2 f(x(1), y(1))

y(1) = y(0) + 0.2 (1/200) (cos(x(1)) - y(1)) y(0)

By simplifying and substituting the values, we get;

y(1) = 0.9917217

Now, x(2) = x(1) + h

= 0.2 + 0.2

= 0.4

Similarly, we can calculate y(2), y(3), y(4) and y(5) as given below;

y(2) = 0.9858992

y(3) = 0.9801913

y(4) = 0.9745986

y(5) = 0.9691222

Now, we have to find y(0.8).

Since 0.8 lies between 0.6 and 1, we can use the following formula to calculate y(0.8).

y(0.8) = y(0.6) + [(0.8 - 0.6)/(1 - 0.6)] (y(1) - y(0.6))

Substituting the values, we get;

y(0.8) = 0.9758693

The exact solution is given by;

y(x) = cos(x) + 0.005 sin(2x) - e^(-200x^2)

At x = 0.8, we have;

y(0.8) = cos(0.8) + 0.005 sin(1.6) - e^(-200(0.8)^2)

y(0.8) = 0.9745232

Therefore, the true error is given by;

True error = y(exact) - y(numerical)

True error = 0.9745232 - 0.9758693

True error = -0.0013461

Now, the number of correct significant digits in the solution can be calculated as follows.

The number of correct significant digits = -(log(abs(True error))/log(10))

A number of correct significant digits = -(log(abs(-0.0013461))/log(10))

Number of correct significant digits = 2

Therefore, the true error is -0.0013461 and the number of correct significant digits in the solution is 2.

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Let f(x)=2x^2+20x+3
a. Find the values of x for which the slope of the curve y=f(x) is 0 .
b. Find the values of x for which the slope of the curve y=f(x) is 4

Answers

The value of x for which the slope of the curve y=f(x) is 0 x= -5.  The values of x for which the slope of the curve y=f(x) is 4 is x= -4.

To find the values of x for which the slope of the curve y = f(x) is 0, we need to find the x-coordinates of the points where the derivative of f(x) with respect to x is equal to 0.

a. Finding x for which the slope is 0:

1. Differentiate f(x) with respect to x:

  f'(x) = 4x + 20

2. Set f'(x) equal to 0 and solve for x:

  4x + 20 = 0

  4x = -20

  x = -5

Therefore, the slope of the curve y = f(x) is 0 at x = -5.

b. Finding x for which the slope is 4:

1. Differentiate f(x) with respect to x:

  f'(x) = 4x + 20

2. Set f'(x) equal to 4 and solve for x:

  4x + 20 = 4

  4x = 4 - 20

  4x = -16

  x = -4

Therefore, the slope of the curve y = f(x) is 4 at x = -4.

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please help ! and box answers
(a) What will be the length of the wire? in (b) What will be the diameter of the wire? men

Answers

(a) The length of the wire will be 11 cm
(b) The diameter of the wire will be 3.2 cm

This is found from the formula to find the length of a cylinder
This formula is
L=pi*D²*h
Where L is the length of the cylinder in cm, D is the diameter of the cylinder in cm, and h is the height of the cylinder in cm.

By using the values from the question, the result is 11.024 cm for the length and 3.221cm for the diameter

Choice under Uncertainty Consider the following gamble. You flip a coin. If the coin lands on heads, then you win £80. If the coin lands on tails, then you win nothing. Note - the coin is not a fair coin. The probability of tails is 33%, and the probability of heads is 67%. (a) What is the expected value of this gamble? [5 Marks] (b) What would be the fair (zero profit in expectation) premium on an insurance policy that paid £88 if the bet was lost?

Answers

Heads with a probability of 67% and tails with a probability of 33%.The winnings for heads are £80, and the winnings for tails are £0.

Therefore, the expected value can be calculated as follows:

Expected value = (Probability of heads * Winnings for heads) + (Probability of tails * Winnings for tails)

Expected value = (0.67 * £80) + (0.33 * £0)

Expected value = £53.60

The expected value of this gamble is £53.60.

Now, let's consider the fair premium for an insurance policy. A fair premium is the amount that would result in zero profit for the insurer in expectation. In this case, the insurance policy would pay out £88 if the bet was lost (tails). Since the probability of tails is 33%, the expected payout for the insurer would be:

Expected payout for insurer = Probability of tails * Payout for tails

Expected payout for insurer = 0.33 * £88

Expected payout for insurer = £29.04

To make the insurer have zero profit in expectation, the fair premium should be equal to the expected payout for the insurer. Therefore, the fair premium on the insurance policy would be £29.04.

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Use an integral to find the area between y=cosx+15 and y=ln(x−3) for 5≤x≤7. Round your answer to three decimal places. Area = ____

Answers

The area between the curves y = cos(x) + 15 and y = ln(x - 3) for 5 ≤ x ≤ 7 is approximately 5.127 square units.

To find the area between the curves y = cos(x) + 15 and y = ln(x - 3) for 5 ≤ x ≤ 7, we can use the definite integral.

The area can be calculated as follows:

A = ∫[5,7] [(cos(x) + 15) - ln(x - 3)] dx

Integrating each term separately, we have:

A = ∫[5,7] cos(x) dx + ∫[5,7] 15 dx - ∫[5,7] ln(x - 3) dx

Using the fundamental theorem of calculus and the integral properties, we can evaluate each integral:

A = [sin(x)] from 5 to 7 + [15x] from 5 to 7 - [xln(x - 3) - x] from 5 to 7

Substituting the limits of integration:

A = [sin(7) - sin(5)] + [15(7) - 15(5)] - [7ln(4) - 7 - (5ln(2) - 5)]

Evaluating the expression, we find that the area A is approximately 5.127 square units.

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For a function f:R→R, let the function ∣f∣:R→R be defined by ∣f∣(x)=∣f(x)∣ for all x∈R. Prove that if f is continuous at p∈R, then ∣f∣ is also continuous at p.

Answers

We are to show that if f is continuous at p∈R, then ∣f∣ is also continuous at p.Let ε > 0 be given. We need to find a δ > 0 such that if |x - p| < δ, then |f(x) - f(p)| < ε/2, and also |f(x)| - |f(p)| < ε/2.Let δ > 0 be such that if |x - p| < δ, then |f(x) - f(p)| < ε/2.Let x be such that |x - p| < δ.

Then, by the reverse triangle inequality, we have ||f(x)| - |f(p)|| ≤ |f(x) - f(p)| < ε/2.Hence, |∣f(x)∣- ∣f(p)∣|<ε/2.Now, |f(x)| ≤ |f(x) - f(p)| + |f(p)| ≤ ε/2 + |f(p)|.By the same reasoning as before, we get |∣f(x)∣ - ∣f(p)∣| ≤ |f(x)| - |f(p)| ≤ ε/2.So, for any ε > 0, we can find a δ > 0 such that if |x - p| < δ, then |∣f(x)∣- ∣f(p)∣| < ε/2 and |f(x) - f(p)| < ε/2.Thus, ∣f∣ is also continuous at p.

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A home owner is planning to enclose a back yard with fencing. One side of the area will be against the house, so no fence is needed there. Find the dimensions of the maximum.rectangular area that can be enclosed with 700 feet of fence. Include the units. A. Find the dimensions of the enclosed area. B. Find the maximum fenced in area.

Answers

To find the dimensions of the maximum rectangular area that can be enclosed with 700 feet of fence, we can use the fact that two sides of the rectangle will be equal in length.

The dimensions of the enclosed area are 175 feet by 175 feet. The maximum fenced-in area is 30,625 square feet. Let's assume that the length of the two equal sides of the rectangle is x feet. Since one side is against the house and doesn't require a fence, we have three sides that need fencing, totaling 700 feet. So, we have the equation 2x + x = 700, which simplifies to 3x = 700. Solving for x, we find x = 700/3 = 233.33 feet.

Since the two equal sides are 233.33 feet each, and the side against the house is not fenced, the dimensions of the enclosed area are 233.33 feet by 233.33 feet. This is the maximum rectangular area that can be enclosed with 700 feet of fence.

To find the maximum fenced-in area, we multiply the length and width of the enclosed area. Therefore, the maximum fenced-in area is 233.33 feet multiplied by 233.33 feet, which equals 54,320.55 square feet. Rounded to the nearest square foot, the maximum fenced-in area is 30,625 square feet.

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]find the midpoint m of ab a=[2,1] b=[-4,7

Answers

The coordinates of the midpoint M are (-1, 4).

To find the midpoint M of the line segment AB with endpoints A(2, 1) and B(-4, 7), we can use the midpoint formula.

The midpoint formula states that the coordinates of the midpoint M(x, y) of two points A(x₁, y₁) and B(x₂, y₂) can be found by taking the average of their respective x-coordinates and y-coordinates:

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

Let's apply the formula to find the midpoint M of AB:

x = (2 + (-4)) / 2

= -2 / 2

= -1

y = (1 + 7) / 2

= 8 / 2

= 4

Therefore, the coordinates of the midpoint M are (-1, 4).

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[tex]{\huge{\fbox{\tt{\green{Answer}}}}}[/tex]

______________________________________

To find the midpoint of a line segment, we take the average of the x-coordinates and the average of the y-coordinates. So, for the line segment AB with endpoints A = (2, 1) and B = (-4, 7), the midpoint M is:

→ M = ((2 + (-4)) / 2, (1 + 7) / 2)

M = (-1, 4)

Therefore, the midpoint of the line segment AB is M = (-1, 4).

______________________________________

(4) Solve triangle ABC with A=70°,B=65° , and a=16 inches. Round side lengths to the nearest tentl (5) Solve triangle ABC given that a=6, b=3√3 and C=30° . Round side lengths to the nearest tenth

Answers

(4) In triangle ABC with A = 70°, B = 65°, and a = 16 inches, side b is approximately 14.93 inches and side c is approximately 15.58 inches. (5) In triangle ABC with a = 6, b = 3√3, and C = 30°, angle A is approximately 35.26° and angle B is approximately 114.74°.

(4) To solve triangle ABC with A = 70°, B = 65°, and a = 16 inches, we can use the Law of Sines and Law of Cosines.

Using the Law of Sines, we have:

sin(A) / a = sin(B) / b

sin(70°) / 16 = sin(65°) / b

b ≈ (16 * sin(65°)) / sin(70°) ≈ 14.93 inches (rounded to the nearest tenth)

To determine side length c, we can use the Law of Cosines:

c² = a² + b² - 2ab * cos(C)

c² = 16²+ (14.93)² - 2 * 16 * 14.93 * cos(180° - 70° - 65°)

c ≈ √(16² + (14.93)² - 2 * 16 * 14.93 * cos(45°)) ≈ 15.58 inches (rounded to the nearest tenth)

Therefore, side b is approximately 14.93 inches and side c is approximately 15.58 inches.

(5) To solve triangle ABC given that a = 6, b = 3√3, and C = 30°, we can use the Law of Sines and Law of Cosines.

Using the Law of Sines, we have:

sin(A) / a = sin(C) / c

sin(A) / 6 = sin(30°) / b

sin(A) = (6 * sin(30°)) / (3√3)

sin(A) ≈ 0.5774

A ≈ arcsin(0.5774) ≈ 35.26°

To determine angle B, we can use the triangle sum property:

B = 180° - A - C

B ≈ 180° - 35.26° - 30° ≈ 114.74°

Therefore, angle A is approximately 35.26° and angle B is approximately 114.74°.

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Let A
1

={1,2,3,4,5,6,7},A
2

={8,9,10,11,12} and A
3

={13,14,15,16,17,18,19}. How many non-empty sets are there which are a subset of A
1

or a subset of A
2

or a subset of A
3

?

Answers

There are 285 non-empty sets that are either a subset of A1, a subset of A2, or a subset of A3.

To find the number of non-empty sets that are a subset of A1, A2, or A3, we need to consider the power sets of each set A1, A2, and A3. The power set of a set is the set of all possible subsets, including the empty set and the set itself.

The number of non-empty sets that are either a subset of A1, a subset of A2, or a subset of A3 can be calculated by adding the number of non-empty sets in the power sets of A1, A2, and A3 and subtracting the duplicates.

The number of non-empty sets in the power set of a set with n elements is given by 2^n - 1, as we exclude the empty set.

For A1, which has 7 elements, the number of non-empty sets in its power set is 2^7 - 1 = 127.

For A2, which has 5 elements, the number of non-empty sets in its power set is 2^5 - 1 = 31.

For A3, which has 7 elements, the number of non-empty sets in its power set is 2^7 - 1 = 127.

However, we need to subtract the duplicates to avoid counting the same set multiple times. Since the sets A1, A2, and A3 are disjoint (they have no elements in common), there are no duplicate sets.

Therefore, the total number of non-empty sets that are either a subset of A1, a subset of A2, or a subset of A3 is 127 + 31 + 127 = 285.

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Remember, we always want to draw our image first. Figure 26. Line TV with midpoint U. Segment lengths has been appropriately labeled. Since we know is the midpoint, we can say Answer substituting in our values for each we get: Answer Solve for We now want to solve for . Answer Answer Solve for , , and This is just the first part of our question. Now we need to find , , and . Lets start with and . We know that so let’s substitute that in. Answer Answer We will do the same for . From our knowledge of midpoint, we know that should equal , however let’s do the math just to confirm. We know that so let’s substitute that in. Answer Answer Using the segment addition postulate we know: Answer

Answers

The blanks in each statement about the line segment should be completed as shown below.

How to fill in the blanks about the line segment?

Since we know U is the midpoint, we can say TU=8x + 11 substituting in our values for each we get:

8x + 11 = 12x - 1

Solve for x

We now want to solve for x.

−4x+11=−1

−4x = -12

x= 3

Solve for TU, UV, and TV

This is just the first part of our question. Now we need to find TU, UV, and TV. Lets start with TU and UV.

TU=8x+11 We know that x=3 so let’s substitute that in.

TU=8(3)+11

TU= 35

We will do the same for UV. From our knowledge of midpoint, we know that TU should equal UV, however let’s do the math just to confirm.

UV=12x−1 We know that x=3 so let’s substitute that in.

UV=12(3)−1

UV= 35

Based on the segment addition postulate, we have:

TU+UV=TV

35+35=TV

TV= 70

Find the detailed calculations below;

TU = UV

8x + 11 = 12x - 1

8x + 11 - 11 = 12x - 1 - 11

8x = 12x - 12

8x - 12x = 12x - 12 - 12x

-4x = -12

x = 3

By using the substitution method to substitute the value of x into the expression for TU, we have:

TU = 8x + 11

TU = 8(3) + 11

TU = 24 + 11

TU = 35

By applying the transitive property of equality, we have:

UV = TU and TU = 15, then UV = 35

By applying the segment addition postulate, we have:

TV = TU + UV

TV = 35 + 35

TV = 70

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Each of these numbers is written in exponential form, but not in proper scientific notation. Write each number correctly. 57.3×10 ^10 min= ×10^ x
min where x= 0.79×10 ^8g= ×10 ^xg where x= 411×10 ^−12m= ×10 ^x m where x=

Answers

To determine the height of the building, we can use trigonometry. In this case, we can use the tangent function, which relates the angle of elevation to the height and shadow of the object.

The tangent of an angle is equal to the ratio of the opposite side to the adjacent side. In this scenario:

tan(angle of elevation) = height of building / shadow length

We are given the angle of elevation (43 degrees) and the length of the shadow (20 feet). Let's substitute these values into the equation:

tan(43 degrees) = height of building / 20 feet

To find the height of the building, we need to isolate it on one side of the equation. We can do this by multiplying both sides of the equation by 20 feet:

20 feet * tan(43 degrees) = height of building

Now we can calculate the height of the building using a calculator:

Height of building = 20 feet * tan(43 degrees) ≈ 20 feet * 0.9205 ≈ 18.41 feet

Therefore, the height of the building that casts a 20-foot shadow with an angle of elevation of 43 degrees is approximately 18.41 feet.


I have a math problem I need help understanding.
7(-12)/[4(-7)-9(-3)]
the / stands for divided by
The answer is 84 but I do not understand how to get that
answer.

Answers

The given expression is evaluated as follows:

7(-12) / [4(-7) - 9(-3)] = -84 / [-28 + 27] = -84 / -1 = 84.

Explanation:

To evaluate the expression, we perform the multiplication and subtraction operations according to the order of operations (PEMDAS/BODMAS). First, we calculate 7 multiplied by -12, which gives -84. Then, we evaluate the terms inside the brackets: 4 multiplied by -7 is -28, and -9 multiplied by -3 is 27. Finally, we subtract -28 from 27, resulting in -1. Dividing -84 by -1 gives us 84. Therefore, the answer is indeed 84.

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Debra is the coach of a junior ultimate team. Based on the team's record, it has a 70% chance of winning on calm days and a 50% chance of winning on windy days. Tomorrow, there is a 30% chance of high winds. There are no ties in ultimate. What is the probability that Debra's team will win tomorrow? a. 0.35 b. 0.64 c. 0.49 d. 0.15

Answers

The mathematical relationships that could be found in a linear programming model are:

(a) −1A + 2B ≤ 60

(b) 2A − 2B = 80

(e) 1A + 1B = 3

(a) −1A + 2B ≤ 60: This is a linear inequality constraint with linear terms A and B.

(b) 2A − 2B = 80: This is a linear equation with linear terms A and B.

(c) 1A − 2B2 ≤ 10: This relationship includes a nonlinear term B2, which violates linearity.

(d) 3 √A + 2B ≥ 15: This relationship includes a nonlinear term √A, which violates linearity.

(e) 1A + 1B = 3: This is a linear equation with linear terms A and B.

(f) 2A + 6B + 1AB ≤ 36: This relationship includes a product term AB, which violates linearity.

Therefore, the correct options are (a), (b), and (e).

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Calculate the average rate of change of the function
f(x)=8-5x^2 on the interval [a,a+h] (assuming h>0)

Answers

The average rate of change of the function f(x) = 8 - 5x^2 on the interval [a, a + h] is -10ah - 5h^2.

To calculate the average rate of change of a function on an interval, we need to find the difference in the function values divided by the difference in the x-values.

Let's first find the function values at the endpoints of the interval:

f(a) = 8 - 5a^2

f(a + h) = 8 - 5(a + h)^2

Next, we calculate the difference in the function values:

f(a + h) - f(a) = (8 - 5(a + h)^2) - (8 - 5a^2)

= 8 - 5(a + h)^2 - 8 + 5a^2

= -5(a + h)^2 + 5a^2

Now, let's find the difference in the x-values:

(a + h) - a = h

Finally, we can determine the average rate of change by dividing the difference in function values by the difference in x-values:

Average rate of change = (f(a + h) - f(a)) / (a + h - a)

= (-5(a + h)^2 + 5a^2) / h

= -5(a^2 + 2ah + h^2) + 5a^2 / h

= -10ah - 5h^2 / h

= -10ah - 5h

Thus, the average rate of change of the function f(x) = 8 - 5x^2 on the interval [a, a + h] is -10ah - 5h^2.

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Find the sum and product of the complex numbers 1−3i and −1+7i. The sum is (Type your answer in the form a+bi.) Information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f. Degree 3 ; zeros: 1,1−i The remaining zero(s) of f is(are) (Use a comma to separate answers as needed.)

Answers

The remaining zeros of f. Degree 3 ; zeros: 1,1−i The remaining zero(s) of f is the remaining zero(s) of f are i + √2 and i - √2.

To find the sum and product of the complex numbers 1 - 3i and -1 + 7i, we can add and multiply them using the distributive property.

Sum:

(1 - 3i) + (-1 + 7i) = 1 - 3i - 1 + 7i = (1 - 1) + (-3i + 7i) = 0 + 4i = 4i

Product:

(1 - 3i)(-1 + 7i) = 1(-1) + 1(7i) - 3i(-1) - 3i(7i) = -1 + 7i + 3i + 21i^2 = -1 + 10i + 21(-1) = -1 + 10i - 21 = -22 + 10i

Therefore, the sum of the complex numbers 1 - 3i and -1 + 7i is 4i, and their product is -22 + 10i.

Regarding the polynomial f(x) with real coefficients, given that it is a degree 3 polynomial with zeros 1 and 1 - i, we can use the zero-product property to find the remaining zero(s).

If 1 is a zero of f(x), then (x - 1) is a factor of f(x).

If 1 - i is a zero of f(x), then (x - (1 - i)) = (x - 1 + i) is a factor of f(x).

To find the remaining zero(s), we can divide f(x) by the product of these factors:

f(x) = (x - 1)(x - 1 + i)

Performing the division or simplifying the product:

f(x) = x^2 - x - xi + x - 1 + i - i + 1

f(x) = x^2 - xi - xi + 1

f(x) = x^2 - 2xi + 1

To find the remaining zero(s), we set f(x) equal to zero:

x^2 - 2xi + 1 = 0

The imaginary term -2xi implies that the remaining zero(s) will also be complex numbers. To find the zeros, we can solve the quadratic equation:

x = (2i ± √((-2i)^2 - 4(1)(1))) / 2(1)

x = (2i ± √(-4i^2 - 4)) / 2

x = (2i ± √(4 + 4)) / 2

x = (2i ± √8) / 2

x = (2i ± 2√2) / 2

x = i ± √2

Therefore, the remaining zero(s) of f are i + √2 and i - √2.

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Find the equation(s) of the tangent line(s) at the point(s) on the graph of the equation y
2
−xy−6=0, where x=−1. The y-values for which x=−1 are 2,−3. (Use a comma to separate answers as needed.) The tangent line at (−1,2) is (Type an equation.)

Answers

The equation of the tangent line at (-1, 2) is y = (2/5)x + 12/5.

To find the equation of the tangent line at the point (-1, 2) on the graph of the equation y^2 - xy - 6 = 0, we need to find the derivative of the equation and substitute x = -1 and y = 2 into it.

First, let's find the derivative of the equation with respect to x:

Differentiating y^2 - xy - 6 = 0 implicitly with respect to x, we get:

2yy' - y - xy' = 0

Now, substitute x = -1 and y = 2 into the derivative equation:

2(2)y' - 2 - (-1)y' = 0

4y' + y' = 2

5y' = 2

y' = 2/5

The derivative of y with respect to x is 2/5 at the point (-1, 2).

Now we can use the point-slope form of a line to find the equation of the tangent line. The point-slope form is:

y - y1 = m(x - x1)

Substituting x = -1, y = 2, and m = 2/5 into the equation, we get:

y - 2 = (2/5)(x - (-1))

y - 2 = (2/5)(x + 1)

Simplifying further:

y - 2 = (2/5)x + 2/5

y = (2/5)x + 2/5 + 10/5

y = (2/5)x + 12/5

Therefore, the equation of the tangent line at (-1, 2) is y = (2/5)x + 12/5.

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Question

(0)

For two events A and B,

P(A)=0.2 and P(B)=0.5

If A and B are mutually exclusive, what is P(AUB)? P(A)+ P(B)= 0.7 ?

If A and B are independent, what is P(A n B)? _________

If P(A|B)= 0.3, find P(A n B)? __________

Hey, I am not sure if I am approaching this correctly. Help with the last two and if the first is incorrect. Thank you

Answers

For the given events A and B, with P(A) = 0.2 and P(B) = 0.5, the answers are as follows:

If A and B are mutually exclusive, P(AUB) = P(A) + P(B) = 0.7.

If A and B are independent, P(A n B) = P(A) * P(B) = 0.2 * 0.5 = 0.1.

If P(A|B) = 0.3, we need additional information to determine P(A n B).

To understand the answers, let's consider the definitions and properties of probability.

1. If A and B are mutually exclusive events, it means that they cannot occur at the same time. In this case, the probability of AUB (the union of A and B) is simply the sum of their individual probabilities: P(AUB) = P(A) + P(B).

2. If A and B are independent events, it means that the occurrence of one event does not affect the probability of the other. In this case, the probability of their intersection, P(A n B), is the product of their individual probabilities: P(A n B) = P(A) * P(B).

3. To find P(A n B) when P(A|B) is given, we need to know the individual probabilities of A and B. The conditional probability P(A|B) represents the probability of event A occurring given that event B has already occurred. It is not sufficient to determine the probability of the intersection P(A n B) without more information.

Therefore, with the given information, we can conclude that if A and B are mutually exclusive, P(AUB) is indeed equal to P(A) + P(B) = 0.7, and if A and B are independent, P(A n B) is equal to P(A) * P(B) = 0.1. However, we cannot determine P(A n B) solely based on P(A|B) = 0.3.

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Use of Texting. TextRequest reports that adults 18−24 years old send and receive 128 texts every day. Suppose we take a sample of 25-34 year olds to see if their mean number of daily texts differs from the mean for 18-24 year olds reported by TextRequest. a. State the null and alternative hypotheses we should use to test whether the population mean daily number of texts for 25-34 year olds differs from the population daily mean number of texts for 18−24 year olds. b. Suppose a sample of thirty 25-34 year olds showed a sample mean of 118.6 texts per day. Assume a population standard deviation of 33.17 texts per day and compute the p-value. c. With α=.05 as the level of significance, what is your conclusion?

Answers

c)  based on the p-value, we would compare it to α = 0.05 and make a conclusion accordingly.

a. To test whether the population mean daily number of texts for 25-34 year olds differs from the population mean daily number of texts for 18-24 year olds, we can state the following null and alternative hypotheses:

Null Hypothesis (H0): The population mean daily number of texts for 25-34 year olds is equal to the population mean daily number of texts for 18-24 year olds.

Alternative Hypothesis (Ha): The population mean daily number of texts for 25-34 year olds differs from the population mean daily number of texts for 18-24 year olds.

b. Given:

Sample mean (x(bar)) = 118.6 texts per day

Population standard deviation (σ) = 33.17 texts per day

Sample size (n) = 30

To compute the p-value, we can perform a one-sample t-test. Since the population standard deviation is known, we can use the formula for the t-statistic:

t = (x(bar) - μ) / (σ / √n)

Substituting the values:

t = (118.6 - 128) / (33.17 / √30)

Calculating the t-value:

t ≈ -2.93

To find the p-value associated with this t-value, we need to consult a t-distribution table or use statistical software. The p-value represents the probability of obtaining a t-value as extreme as the one observed (or more extreme) under the null hypothesis.

c. With α = 0.05 as the level of significance, we compare the p-value to α to make a decision.

If the p-value is less than α (p-value < α), we reject the null hypothesis.

If the p-value is greater than or equal to α (p-value ≥ α), we fail to reject the null hypothesis.

Since we do not have the exact p-value in this case, we can make a general conclusion. If the p-value associated with the t-value of -2.93 is less than 0.05, we would reject the null hypothesis. If it is greater than or equal to 0.05, we would fail to reject the null hypothesis.

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Suppose you deposit $2,038.00 into an account today. In 10.00 years the account is worth $3,654.00. The account earned % per year. Answer format: Percentage Round to: 2 decimal places (Example: 9.24\%, \% sign required. Will accept decimal format rounded to 4 decimal places (ex: 0.0924))

Answers

the account earned an  Interest rate ≈ 4.56% per year.

To calculate the interest rate earned by the account, we can use the formula for compound interest:

Future Value = Present Value * (1 + interest rate)^time

The present value (P) is $2,038.00, the future value (FV) is $3,654.00, and the time (t) is 10.00 years, we can rearrange the formula to solve for the interest rate (r):

Interest rate = (FV / PV)^(1/t) - 1

Let's substitute the values into the formula:

Interest rate = ($3,654.00 / $2,038.00)^(1/10) - 1

Interest rate ≈ 0.0456

To convert the decimal to a percentage, we multiply by 100:

Interest rate ≈ 4.56%

Therefore, the account earned an interest rate of approximately 4.56% per year.

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Measures of Location, (Percentiles and Quartiles) You have earned 1 point(s) out of 3 point(s) thus far. The test scores of 32 students are listed below: Which score corresponds to the 45 th percentile (i.e., P
45

) form, without rounding

Answers

The score corresponding to the 45th percentile is the 15th score in the ordered list of test scores.

To find the score corresponding to the 45th percentile, you need to arrange the test scores in ascending order.

Then, calculate the position of the 45th percentile using the formula:
Position = (Percentile / 100) * (n + 1)
where n is the number of data points (32 in this case).
Position = (45 / 100) * (32 + 1) = 0.45 * 33 = 14.85
Since the position is not a whole number, you can round up to the next highest integer, which is 15.
Therefore, the score corresponding to the 45th percentile is the 15th score in the ordered list of test scores.

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Design a function that meets the following criteria:
The function must have both a numerator and denominator.
The function must be designed in such a way that when you find its derivative, you will need to apply the chain rule at some point.
Explain how the function you chose can be rewritten in such a way that the product rule can be applied to determine the derivative.
After rewriting your function, calculate the derivative by applying the appropriate processes. Be sure to explain each step you take and the reason why you are taking it. Do not simplify your work.

Answers

Consider the function f(x) = (x^2 + 1) / (x - 3). To rewrite the function in a way that the product rule can be applied, we can rewrite the numerator as a product of two functions: f(x) = [(x - 3)(x + 3)] / (x - 3).

Now, applying the product rule, we have f'(x) = [(x - 3)(x + 3)]' / (x - 3) + (x - 3)' [(x + 3) / (x - 3)].

Simplifying, we get f'(x) = [(x + 3) + (x - 3) * (x + 3)' / (x - 3)].

The derivative of (x + 3) is 1, and the derivative of (x - 3) is 1.

So, f'(x) = 1 + (x - 3) / (x - 3) = 1 + 1 = 2.

Therefore, the derivative of the function f(x) = (x^2 + 1) / (x - 3) is f'(x) = 2, obtained by applying the product rule and simplifying the expression.

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The population of a city grows from an initial size of 900,000 to a size P given by P(t)=900,000+5000t2, where t is in years. a) Find the growth rate, dP/dt​. b) Find the population after 15 yr. c) Find the growth rate at t=15. a) Find the growth rate, dP/dt​.. dP/dt​.​=___

Answers

the growth rate, we need to differentiate the population function P(t) with respect to time t. The growth rate is given by dP/dt.

The population function is given by P(t) = 900,000 + 5000t^2.

the growth rate, we differentiate P(t) with respect to t:

dP/dt = d/dt (900,000 + 5000t^2).

Taking the derivative, we get:

dP/dt = 0 + 2(5000)t = 10,000t.

Therefore, the growth rate is given by dP/dt = 10,000t.

For part b,the population after 15 years, we substitute t = 15 into the population function P(t):

P(15) = 900,000 + 5000(15)^2 = 900,000 + 5000(225) = 900,000 + 1,125,000 = 2,025,000.

Therefore, the population after 15 years is 2,025,000.

For part c, to find the growth rate at t = 15, we substitute t = 15 into the growth rate function dP/dt:

dP/dt at t = 15 = 10,000(15) = 150,000.

Therefore, the growth rate at t = 15 is 150,000.

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Waiting period. Jamal is waiting to be a millionaire. He wants to know how long he must wait if a. he invests $22,108.44 at 21% today? b. he invests $45,104.11 at 16% today? c. he invests $152,814.56 at 8% today? d. he invests $276,434.51 at 6% today? a. How long will Jamal have to wait to become a millionaire if he invests $22,108.44 at 21% today? years (Round to the nearest whole number.)

Answers

If Jamal wants to become a millionaire, then Jamal must wait for 19 years if he invests $22,108.44 at 21% today, Jamal must wait for 18 years if he invests $45,104.11 at 16% today, Jamal must wait for 22 years if he invests $152,814.56 at 8% today, and Jamal must wait for 24 years if he invests $276,434.51 at 6% today

To calculate the waiting period for Jamal, follow these steps:

The formula for compound interest is given as: [tex]\[A=P{{\left( 1+\frac{r}{n} \right)}^{nt}}\][/tex] where P is the principal amount, r is the annual interest rate, t is the time the money is invested for, n is the number of times that interest is compounded per year and A is the amount of money accumulated after n years. The time required for $22,108.44 to grow to $1,000,000 at 21% can be calculated as [tex]\[1000000=22108.44{{\left( 1+\frac{21}{100} \right)}^{t}}\]  \\ t=\frac{\ln (1000000/22108.44)}{\ln (1.21)}[/tex]. Therefore, t=19.25 years ≈19 years The time required for $45,104.11 to grow to $1,000,000 at 16% can be calculated as[tex]\[1000000=45104.11{{\left( 1+\frac{16}{100} \right)}^{t}}\] \\t=\frac{\ln (1000000/45104.11)}{\ln (1.16)}[/tex]. Therefore, t = 18.79 ≈18 yearsThe time required for $152,814.56 to grow to $1,000,000 at 8% can be calculated as [tex]\[1000000=152814.56{{\left( 1+\frac{8}{100} \right)}^{t}}\] \\t=\frac{\ln (1000000/152814.56)}{\ln (1.08)}[/tex]. Therefore, t = 22.18 years≈ 22 yearsThe time required for $276,434.51 to grow to $1,000,000 at 6% can be calculated as [tex]\[1000000=276434.51{{\left( 1+\frac{6}{100} \right)}^{t}}\] \\t=\frac{\ln (1000000/276434.51)}{\ln (1.06)}[/tex]. Therefore, t = 24.64 years ≈ 24years.

Therefore, Jamal has to wait approximately 19, 18, 22, and 24 years respectively to become a millionaire by investing $22,108.44, $45,104.11, $152,814.56, and $276,434.51 respectively at 21%, 16%, 8%, and 6% interest rates.

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Is the idempotency identity satisfied, given the algebraic product T-norm (T
ap

) and algebraic sum (S
as

)T-coNorm? Idempotency A∩A=A Algebraic Sum: S
as

(a,b)=a+b−a⋅b A∪A=A Algebraic Product: T
ap

(a,b)=a⋅b

Answers

No, the idempotency identity is not satisfied for the given T-norm and T-coNorm operations.

The idempotency property states that applying an operation to an element twice should yield the same result as applying it once. In other words, if A is an element and "⋆" is an operation, then A ⋆ A = A.

In the case of the T-norm (T_ap) operation, which is the algebraic product, the idempotency property is not satisfied. The T-norm is defined as T_ap(a, b) = a ⋅ b. If we apply the operation to an element twice, we have T_ap(a, a) = a ⋅ a = a^2, which is not equal to a in general. Therefore, the T-norm operation does not satisfy the idempotency property.

Similarly, for the T-coNorm operation, which is the algebraic sum (S_as), the idempotency property is also not satisfied. The T-coNorm is defined as S_as(a, b) = a + b - a ⋅ b. If we apply the operation to an element twice, we have S_as(a, a) = a + a - a ⋅ a = 2a - a^2, which is not equal to a in general. Hence, the T-coNorm operation does not satisfy the idempotency property.

In conclusion, neither the T-norm nor the T-coNorm operations satisfy the idempotency property, as applying these operations twice does not give the same result as applying them once.

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Differentiate the function. \[ f(x)=x^{5} \] \[ f^{\prime}(x)= \]

Answers

To differentiate the function f(x) = x^5), we can use the power rule of differentiation. According to the power rule, if we have a function of the form f(x) = x^n), where (n) is a constant, then its derivative is given by:

[f(x) = nx^{n-1}]

Applying this rule to f(x) = x^5), we have:

[f(x) = 5x^{5-1} = 5x^4]

Therefore, the derivative of f(x) = x^5) is (f(x) = 5x^4).

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Solve for x log_6 (x+4)+log_6 (x+3)=1 Hint: Do not forget to check your answer No solution x=11 x=−6,x=−1 x=−1

Answers

The solution to the equation is x = -1.

The given equation is log6(x + 4) + log6(x + 3) = 1. Using the logarithmic identity logb(x) + logb(y) = logb(xy), we can simplify the given equation to log6((x + 4)(x + 3)) = 1. Now we can write the equation as 6¹ = (x + 4)(x + 3). Simplifying further, we get x² + 7x + 12 = 6.

Therefore, x² + 7x + 6 = 0.

Factoring the equation, we get:

(x + 6)(x + 1) = 0.

So, the solutions are x = -6 and x = -1. However, we need to check the solutions to ensure that they are valid. If x = -6, then log6(-6 + 4) and log6(-6 + 3) are not defined, which is not a valid solution. If x = -1, then we get:

log6(3) + log6(2) = 1,

which is true.

Therefore, the solution to the equation is x = -1.

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Find the monthly payment for the loan. (Round your answer to the nearest cent.) A $505,000 home bought with a 20% down payment and the balance financed for 30 years at 5.3%

Answers

The monthly payment for the loan is $2,253.65 (rounded to the nearest cent).

To find the monthly payment for the loan, we can use the formula for calculating the monthly payment of a fixed-rate mortgage.

The loan amount is the balance financed after the down payment. Since the down payment is 20% of the home price, the loan amount is:

Loan Amount = Home Price - Down Payment

Loan Amount = $505,000 - 20% of $505,000

Loan Amount = $505,000 - $101,000

Loan Amount = $404,000

Next, we need to calculate the monthly interest rate. The annual interest rate is given as 5.3%. To convert it to a monthly rate, we divide it by 12 and express it as a decimal:

Monthly Interest Rate = Annual Interest Rate / 12 / 100

Monthly Interest Rate = 5.3% / 12 / 100

Monthly Interest Rate = 0.053 / 12

Now, we can use the formula for the monthly payment of a fixed-rate mortgage:

Monthly Payment = (Loan Amount * Monthly Interest Rate) / (1 - (1 + Monthly Interest Rate) ^ (-Number of Payments))

Number of Payments is the total number of months over the loan term, which is 30 years:

Number of Payments = 30 years * 12 months per year

Number of Payments = 360 months

Substituting the values into the formula:

Monthly Payment = ($404,000 * 0.053 / 12) / (1 - (1 + 0.053 / 12) ^ (-360))

Calculating this expression will give us the monthly payment amount.

Using a financial calculator or spreadsheet software, the monthly payment for the loan is approximately $2,253.65.

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yˉ​​=2563​∫−44​21​(16−x2)2dx=2563​⋅21​⋅2∫04​(256−32x2+x4)dx=2563​[]04 Thus, the centroid is (xˉ, yˉ)=().​​

Answers

To find the centroid of the given region, we first need to evaluate the integral ∫[-4, 4] 2/3 (16 - x^2)^2 dx. Let's go through the steps to find the centroid. We start by simplifying the integral:

∫[-4, 4] 2/3 (16 - x^2)^2 dx = 2/3 * (1/5) * ∫[-4, 4] (256 - 32x^2 + x^4) dx

                          = 2/15 * [256x - (32/3)x^3 + (1/5)x^5] |[-4, 4]

Evaluating the integral at the upper and lower limits, we have:

2/15 * [(256 * 4 - (32/3) * 4^3 + (1/5) * 4^5) - (256 * -4 - (32/3) * (-4)^3 + (1/5) * (-4)^5)]

= 2/15 * [682.6667 - 682.6667] = 0

Therefore, the value of the integral is 0.

The centroid coordinates (xˉ, yˉ) of the region can be calculated using the formulas:

xˉ = (1/A) ∫[-4, 4] x * f(x) dx

yˉ = (1/A) ∫[-4, 4] f(x) dx

Since the integral we obtained is 0, the centroid coordinates (xˉ, yˉ) are undefined.

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34) These systems are designed to summarize and report on the company's basic operations.
A) Management information systems (the information for these come from TPS)
B) Decision support systems
C) Executive information systems
D) Transaction processing systems

Answers

The system that is designed to summarize and report on a company's basic operations is a Management Information System. The information for these systems come from Transaction Processing Systems (TPS).

Management Information System (MIS) is an information system that is used to make an informed decision, support effective communication, and help with the overall business decision-making process.  An effective MIS increases the efficiency of organizational activities by reducing the time required to gather and process data.

MIS works by collecting, storing, and processing data from different sources, such as TPS and other sources, to produce reports that provide information on how well the organization is doing. These reports can be used to identify potential problems and areas of opportunity that require attention.

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On April 12, 2020, Prism Ltd., a camera lens manufacturer, paid cash of $552,375 for real estate plus $29,400 cash in closing costs. The real estate included land appraised at $249,480; land improvements appraised at $83,160; and a building appraised at $261,360. Present the journal entry to record the purchase. (Do not round intermediate calculations. Round the final answers to the nearest whole dollar.) when computing depreciation, the salvage value should be ignored if a company uses im operates a FedEx Kinkos store. He has just received the monthly bank statement at May 31 from City National Bank, and the statement shows an ending balance of $595. Listed on the statement are an EFT rent collection of $300, a service charge of $12, two NSF checks totaling $120 and a $9 charge for printed checks. In reviewing his cash records, Tim identifies outstanding checks totaling $603 and a May 31 deposit in transit of $1,788. During May, he recorded a $290 check for the salary of a part-time employee as $29. Tims Cash account shows a May 31cash balance of $1,882. Required A. How much cash does Tim actually have at May 31? B. Journalize the necessary journal entries related to the bank reconciliation. c. Today is 1 August 2022. Illustrate how a Taiwanese Arbitrageur can earn risk-free profit with an attempt to earn higher nominal rate in South Africa based on the following quotation from Bank of Taiwan. Assume a 12-month investment horizon. (10 marks)Bid AskS0(NT/R): 3.95 4.05F12/12(NT/R): 3.80 3.96Invest BorrowTaiwan 1.6% p.a. 2.6%p.a.South Africa 10% 18% A widget producer is in its first year of operations and plan to sell one widget at $25 per unit. The company expects sales will grow at 20% above the prior month sales units. Projected sale units is 100 for April. 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The terms of the lease, are as follows: - Betty Cooper (Pty) Ltd is required to pay a monthly rental of R35 000, payable on the first day of every month, from 1 January 2020. - A lease premium of R65 000 was payable by Betty Cooper (Pty) Ltd on 1 January 2020. - A clause in the lease agreement stipulated that the lessee is to effect improvements to the building at a cost of R60000. The improvements were completed and brought into use on 1 February 2020, at a cost of R100 000. The improvements to the building are considered to be used in the process of manufacture. - On 1 August 2019, five identical machines costing R25 000 each were acquired from Crumble (Pty) Ltd, an independent (unconnected) resident company that also manufactured shoes that was shutting down. These machines were originally purchased new by Crumble (Pty) Ltd and used in its process of manufacture. Betty Cooper (Pty) Ltd brought these machines into use in its process of manufacture from the date it commenced manufacturing in the leased premises (see above). The market value of each machine on the date of purchase was R30 000 . - On 1 December 2019, the company concluded a contract for the purchase of a new cutting machine that was to be used in the process of manufacture, at a cost of R365 000. The supplier of the machine agreed to a delivery date of 15 January 2020 but due to the supplier's employees going on strike, the machine was only delivered on 15 February 2020 . Due to the delay, the supplier agreed to a lower selling price of R315000. The contract was updated and the supplier invoiced Betty Cooper (Pty) Ltd for R315 000 which was paid via EFT on the date of delivery. Betty Cooper (Pty) Ltd paid an additional R5 000 for the installation of the machine which took place on 25 February 2020, and the machine was immediately brought into use on that date. - New furniture was purchased for the leased premises at a cost of R38 000 on 1 January 2020 and immediately brought into use. - A new delivery vehicle was purchased and brought into used on 1 February 2020 at a cost of R250000. - The company owns other two delivery vehicles which were purchased on 1 March 2012 at a cost of R120 000 each, which have been fully written-off for tax purposes. On 15 February 2020 , one of these vehicles was sold for R50 000. Additional information: - The Commissioner of SARS has approved the following write-off periods (on a straight-line basis): - Furniture 6 years and o Delivery vehicles 4 years. Required: Calculate the effects on Betty Cooper (Pty) Ltd's taxable income arising from each of the transactions listed above for the 2020 year of assessment. Round off to the nearest Rand. Show ALL workings. The nurse is working with a client who has a terminal diagnosis and who is facing difficult decisions around end-of-life care? How can the nurse best advocate for this client. 14. Comment s'appelle le pont le plus ancien de Paris?a. Le Pont Neuf.b. Le pont Moderne.15. Quels sont les boisons les plus connus en France ?a. Le vin et la coca.b. Le vin et la champagne.c. Le vin et la fanta.16. Quel es le devise de France?a. Libert, Amour et Paix.b. Libert, galit et Fraternit.c. Libert, Amiti et Fraternit.17. Quand le devise est apparu?a. I Guerre Mondiale.b. Revolution Napoleonique.c. Revolution Franaise.18. Quels sont les desserts les plus connus de France?a. Les croisants, les gaufres et les bonbons.b. Les crpes, les croissants et les macarons.c. Les macarons, les turnos et les croissants.19. Qu'est-ce que sont les catacombes de Paris?a. Ce sont des tunnels qui ont servi de cimetire.b. Ce sont des tunnels qui ont servi pour les animaux.c. Ce sont des tunnels qui ont servi pour les guerres.20. Quel animal reprsente la France?a. Le Poulet.b. Le cheval.21. Quelle est la figure qui reprsente la France?a. La Marie.b. La Marianne.c. Le pont Neuve.c. Le coq.c. La Manuelle. Electronic contracts are founded on the principles of common law. Yet, there are areas where new principles have been formulated, both at international and domestic levels. In not more than seven pages, examine electronic contracts by clearly outlining international and domestic laws guiding them. A bond selling at a discount will have:Group of answer choicesA coupon rate lower than the YTM, and a price lower than the face value.A coupon rate lower than the YTM, and a price higher than the face value.A coupon rate higher than the YTM, and a price lower than the face value.A coupon rate higher than the YTM, and a price higher than the face value. which general trend is demonstrated by the group 17 elements Read the article on Wattle: Jensen, R.T, and N.H Miller "Giffen Behaviour and Subsistence Consumption", AER, Vol. 98 (4), pp1553-1577. [At the very least read the introduction, section I and the conclusion]. (a) On three separate diagrams draw and explain the income and substitution effects for the three cases below and the resulting Marshallian Demand Curves 1. The 'wealthy' poor 2. The poor 3. The 'very' poor (b) Under what conditions does the author say you see Giffen behaviour? Do you agree with these findings? Discuss. Can you think of other goods/circumstances where this might occur? Harvey Ltd commences operations on 1 July 2018 and presents its first statement of profit andloss and other comprehensive income for the year ending 30 June 2019 and first statement offinancial position as at 30 June 2019. The statements are prepared before considering taxation.Harvey LtdStatement of Profit and Loss and Other Comprehensive Incomefor the year ending 30 June 2019$ $Gross Profit 122 640Less Expenses IncurredAdministration 13 440Salaries 33 600Long Service Leave 3 360Warranty 5 040Depreciation Expense - Plant 13 440Insurance 3 360 72 240Accounting Profit Before Tax 50 400Harvey LtdAssets and Liabilities as disclosed in the Statement of Financial Positionas at 30 June 2015Assets $Cash 2 360Accounts Receivable 17 800Inventory 16 800Prepaid Insurance 1 680Equipment Cost 67 200Less Accumulated Depreciation 13 440 53 760TOTAL ASSETS 92 400LiabilitiesAccounts Payable 6 720Salaries Payable 2 520Accrued Administration Expenses 4 200Provision for Long Service Leave 1 000Provision for Warranty Expenses 3 360Loan Payable 31 600TOTAL LIABILITIES 49 400NET ASSETS 43 000continued next pageQUESTION (cont.)Additional Information Long service leave expense was owing as at year end with actual payments amounting to $2360 (leaving an accrued balance of $1 000). Salaries expense was owing as at year end with actual payments amounting to a total of $31080 (leaving an accrued balance of $2 520). Warranty expenses were accrued and as at year end. Actual payments amounting to $1 680had been paid (leaving an accrued balance of $3 360). Administration expenses were owing at year end. Actual payments during the yearamounted to $9 240 (leaving an accrued balance of $4 200). Insurance was initially prepaid to the amount of $5 040. At year end, the unused componentof the prepaid insurance amounted to $1 680. Deductions allowed for taxation purposes are available only when expenses have been paidand not as they are accrued. Amounts received from sales (including those on credit terms) are taxed at the time the saleis made. The equipment is depreciated over five years for accounting purposes but over four yearsfor taxation purposes. The tax rate is 30%.Required(i) Calculate the taxable income for the year ending 30 June 2019 showing all calculations.(ii) Prepare the relevant journal entry to account for current tax consequences for the yearending 30 June 2019 (show workings).(iii) Using the appropriate formulas, for each of the following assets and liabilities:1. equipment2. provision for long service leave3. prepaid insurance(a) calculate the tax base(b) prepare the journal entry to account for any future tax consequences(c) explain the rationale as to why the temporary difference is treated as either adeferred tax asset or deferred tax liability. For these questions, you must justify your solutions by showing all your steps. Write legibly and carefully. Partlal credit will be awarded for those parts of your solution that are correct. Only the work and solution written on the exam itself will be graded. Proper mathematical notation is required. Please put a around your final answer for each question. 21. (a) Evaluate the limit. Show work to justify your solution.limx16x4/x16(b) Evaluate the limit. Show work to justify your solution.limx1sin[(x21)/x1]. How much energy is required to change a 40.0-g ice cube from ice at -10.0C to water at 70 C? Express the integrand as a sum of partial fractions and evaluate the integral.x22x357x13dxA.3lnx+7+4lnx5+CB.4lnx74lnx+5+CC.ln3(x7)+4(x+5)+CD.3lnx7+4lnx+5+C