The earth's orbital angular velocity around the Sun is 0.986° per day, and its axial angular velocity is 15.041° per hour.
Calculation:
The speeds, not the velocities, are what we require in this case, therefore that is how I will approach it.
Regular speed is calculated by dividing the distance traveled by the travel time.
So, speed = [tex]\frac{distance -travelled}{time}[/tex]
The angular velocity is essentially the same.
Hence, it's divided by the amount of time it took to turn the angle.
(a) Calculation of Earth's orbit around the Sun :
The Earth orbits the Sun in a circle that is 2 radians in diameter (360 degrees). It also takes a year, as we are aware (approx 365 days)
360°/365.25636 days = 0.986°/day ≈ 1° per day
(b) Next, we have to calculate Earth's angular velocity on its axis:
determining the Earth's angular velocity as it fulfills a complete revolution on its axis (a solar day)-
This one requires more precision because a day does not always have 24 hours. Depending on how we define a day,If the day is defined as the time between the Sun's highest and lowest points in the sky, a year's worth of data equals an average of 24 hours.If we define a day as the duration of time it requires for a planet to get to the same location in the sky the following night, then it is 23 hours 56 minutes 4.09 seconds.According to this, the angular speed of rotation = 360°/ 23h 56min 4.09s = 15.041° / hour.
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A block and tackle pulley system has 3pulley wheels in the lower movable block. Determine the load that can be lifted by an effort of 350N if the efficiency of the system is 80%
A block and tackle pulley design has a velocity ratio 3. <br> Draw a labelled diagram of this system. In your diagram, indicate absolutely the points of application and the directions of the load and effort
How to calculate the load that can be lifted by an effort of 350N if the efficiency of the system is 80%?VR =3
VR = n=3
Efficiency of the system = 80%
Thus , Mechanical asvantage [tex]$=V R \times \eta=$[/tex]80/100×3 =2.4
Man can lift load with effort =350N
Thus,
Load= MA× effort = 2.4×350 = 840 N.
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Consider the f(x) = cos(x-C) function shown in the figure in blue color, where 0 ≤ C ≤ 2π. What is the value of parameter C for the function in the figure?
As a reference the g(x) = cos(x) function is shown in red color, and green tick marks are drawn at integer multiples of π.
The value of parameter C for the function in the figure is 2.
What is amplitude of a wave?The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.
f(x) = Acos(x - C)
where;
A is amplitude of the waveC is phase difference of the waveWhat is angular frequency of a wave?Angular frequency is the angular displacement of any element of the wave per unit time.
From the blue colored graph; at y = 1, x = -2 cm
1 = cos(2 - C)
(2 - C) = cos^(1)
(2 - C) = 0
C = 2
Thus, the value of parameter C for the function in the figure is 2.
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what is elecric field line
A vector field and a starting position inside the field define the locus as a "field line." We have electric field lines for the electric fields.
What do you mean by electric field line?In general, an electric field line is a curve drawn with each point's tangent pointing in the direction of that point's net field. An arrow on the curve is obviously required to designate the direction of the electric field from the two potential directions provided by a tangent to the curve. A field line is a space curve or a three-dimensional curve.The vector gets shorter as you move away from the origin and always points radially outward because the electric field varies as the inverse of the square of the distance that points from the charge.The density of the lines indicates the size of the field. This indicates that the location with a high density of field lines has a stronger electric field due to the charged substance. The electric field is weaker in the area where the density of these lines is low.The electric field can be depicted by joining these vectors to form a line.The direction of an imaginary line called an electric field line at any place must match the direction of the field there.In general, a field line is a curve drawn so that each point's tangent points in the direction of the net field.To learn more about the electric field, refer to:
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