The equation that will calculate the number of days after which there will be 256 bacterial cells in the dish is 2^(d/2) = 256
How to determine the equation of the number of days?The given parameters are:
Rate, r = doubles every two days
Initial number of strain, a = 1
This means that the function is an exponential function.
An exponential function is represented as:
A(d) = a * r^d
Since the strain doubles every two days, we have:
A(d) = a * r^(d/2)
Substitute the known values in the above equation
A(d) = 1 * 2^(d/2)
Evaluate the product
A(d) = 2^(d/2)
When there are 256 bacterial cells, the equation becomes
2^(d/2) = 256
Hence, the equation that will calculate the number of days after which there will be 256 bacterial cells in the dish is 2^(d/2) = 256
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what is 7/8 - 1/2 as a fraction
Answer: 3/8
Step-by-step explanation:
1/2 is also 4/8 so you subtract 4/8 from 7/8 to get 3/8
When it is Noon (12 pm) in London, it is 10pm in Sydney, Australia. Dan in London rings his friend Boski in Sydney at 15:30pm on Christmas Day. What time is it in Sydney?
A. 1am
B. 1:30am
C. 2am
S. 2:30am
The time at Sydney when Dan rings his friend is 1 : 30 am (option B).
What is the time at Sydney?The first step is determine the time difference between London and Sydney.
Time difference = time at Sydney - time at London
( 12 + 10pm) - 12pm
22pm - 12pm = 10 hours
The second step is to add the time difference to the time it was when Dan rang.
15 : 30 pm + 10pm = 25 : 30
We know that there are only 24 hours in day, so subtract 24 hours from 25 : 30
25 : 30 - 24 = 1 : 30 am
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Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250
Answer:
no mode
Step-by-step explanation:
no number appears more than once
therefore there is no mode
I need help… a lot of it im so confused
[tex] \sqrt[3]{b {}^{2} } = b {}^{ \frac{2}{3} } [/tex]
2)[tex]f(4) = 2(3) {}^{4} = 2 \times 81 = 162[/tex]
3)[tex]f( \frac{1}{2} ) = \frac{1}{3} (9) {}^{ \frac{1}{2} } + 5 = \frac{ \sqrt{9} }{ 3} + 5 = 6[/tex]
4)
[tex]f(5) = - 4(2) {}^{ - 5 + 1} = - 4(2) {}^{ -4} = \frac{2 {}^{2} }{2 {}^{4} } = \frac{1}{2 {}^{2} } = \frac{1}{4} [/tex]
5)[tex]f(10) = 2e {}^{0.15 \times 10} = 2e {}^{1.5} = 8.96[/tex]
6)[tex]y = 10(b) {}^{x} \: \: \\ 10 = 10(b) {}^{0} \: duh \\ 2 = 10b {}^{1} \\ b = \frac{2}{10} = \frac{1}{5} [/tex]
7)[tex]y = a(b) {}^{x} \\ 3 = a(b) {}^{0} \\ a = 3 \\ \\75 = 3(b) {}^{2} \\ b {}^{2} = 25 \\ b = + 5 \: \: \: or \: \: \: \: b = - 5[/tex]
8)[tex]s = 1000(1 + \frac{0.045}{4} ) {}^{4 \times 10} = 1564.38[/tex]
9)[tex]s = 2500.e {}^{0.07 \times 20} = 10138[/tex]
HELPP PLSSS I NEED HELP!!!
Answer:
(3+3) x (3+1)
Step-by-step explanation:
free
We have give 4 numbers that are 1,3,3,3. we have to apply operations on it to make it 24.
Solution :» (1 + 3) × (3 + 3)
» (4) × (6)
» 24
Here's our answer..!!
ASAP help me with this question
Answer:
SAS and SSA
Kindly award branliest
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Congruency refers to the criteria of making two identical shapes that can hide each other properly when overlapped.
The criterias that guarantee congruence are :
SSSSASASAAAS[tex] \qquad \large \sf {Conclusion} : [/tex]
Correct options are : b, c, d, eVolume oblate spheroid
The volume of the oblate spheroid is approximately equal to 75.398 cubic feet.
What is the volume of an oblate spheroid?
In this problem we have the shape of an ellipse centered at origin, whose vertex form is shown below:
x² / a² + y² / b² = 1 (1)
Where a, b are the lengths of the semiaxes, in feet.
An oblate spheroid is generated by revolving half of the ellipse about the y-axis. Oblate spheroids are a kind of ellipse:
x² / a² + y² / b² + z² / a² = 1 (2)
Where a, b, c are the lengths of the semiaxes, in feet.
And the volume of the oblate spheroid is:
V = (4 / 3) · π · a² · b (3)
If we know that a = 3 ft, b = 2 ft, then the volume of the oblate spheroid is:
V = (4 / 3) · π · (3 ft)² · (2 ft)
V ≈ 75.398 ft³
The volume of the oblate spheroid is approximately equal to 75.398 cubic feet.
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J(1)²,
x ≤ 0
x > 0
2²,
Complete the table of values for function f, and then plot the ordered pairs on the graph.
-2
-1
0
1
2
f(x)
=
X
f(x)
Drawing Tools
Select
Point
Open Point
>
O
Click on a tool to begin drawing.
-10
-8
-6
-4
-2
10
8
6
4-
2-
-2
पं
CC
f(x)
Delete
2
4
Undo
6
3
+00
8
Answer:
1/2 - 4, 1/2 2, 2 1/4,
Step-by-step explanation:
1/2, - 4 1/2 2,2,1/4
The table when completed looks like this:
x -2 -1 0 1 2
f(x) 4 2 1 2 4.
We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).
What is a function?A function exists as a relation between a dependent variable (f(x)) and an expression of an independent variable (x), utilized to define the value of a dependent variable from a provided value of an independent variable.
We have been given a function,
[tex]$f(x)=\left \{ {{(1/2)^{x},x\leq 0 } \atop {2^x > 0}} \right.[/tex]
We have to estimate the value of f(x) when x = {-2, -1, 0, 1, 2}
If the values of x ≤ 0, take f(x) = (1/2)ˣ then
f(-2) = (1/2)⁻² = 2² = 4
f(-1) = (1/2)⁻¹ = 2¹ = 2
f(0) = (1/2)⁰ = 1
If the values of x > 0, take f(x) = 2ˣ then
f(1) = 2¹ = 2
f(2) = 2² = 4
The table exists as follows
x -2 -1 0 1 2
f(x) 4 2 1 2 4.
We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).
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What is the slope of the line that passes through the points (8, 0) and (-4, -8)?
Write your answer in simplest form.
Answer:
Step-by-step explanation:
(-8 - 0)/(-4 - 8)= -8/-12 = 2/3
The slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.
How to estimate the slope of the line?The slope or gradient between two points in the Cartesian coordinate system. The slope exists the amount of slant a line retains and can maintain a positive, negative, zero, or undefined value.
Using the slope formula [tex](y_2 - y_1)/(x_2 - x_1)[/tex]
[tex]x_1 = 8, y_1 = 0[/tex] and [tex]x_2 = -4 , y_2= -8[/tex]
slope [tex]= (y_2 - y_1)/(x_2 - x_1)[/tex]
= ((-8) - 0) / ((-4) - (8))
= (-8) / (-12) = (-2) / (-3)
= 0.66667
Therefore, the slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.
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Find the surface area of the composite figur
2 cm
5 cm
4 cm
3 cm
5 cm
SA =
4 cm
3 cm
5 cm
[?] cm²
By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.
What is the surface area of a composite figure formed by two right prisms?
According to the image, we have a composite figure formed by two right prisms. The surface area of this figure is the sum of the areas of its faces, represented by squares and rectangles:
A = 2 · (4 cm) · (5 cm) + 2 · (2 cm) · (4 cm) + (2 cm) · (5 cm) + (3 cm) · (5 cm) + (5 cm)² + 4 · (3 cm) · (5 cm)
A = 166 cm²
By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.
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Someone please help me with this thank you!
Answer:
50°
Step-by-step explanation:
Note EFGH is an isosceles trapezoid.
∠HGF=77° (base angles of an isosceles trapezoid are congruent)
∠EGH=27° (angles in a triangle add to 180°)
∠FGE=50° (angle subtraction postulate)
1 Which is the greatest 4- digit number divisible by 6?......
As fast as when u are running to save ur mom life
Answer:
The greatest four-digit number that is divisible by 6 is 9996
Step-by-step explanation:
9,996 / 6 = 1,666
Which of the following is the solution to 8√3 + 7√3?
15√9
15√6
15√3
56√3
Which of the following is the solution to √15 * √45 simplified?
√675
8√3
15√15
15√3
Which of the following is the solution to 15√10 - 3√10?
12√10
5√10
12√100
45√10
Answer:
Q1: Third Choice. 15√3
Q2: Fourth Choice. 15√3
Q3: First Choice. 12√10
Step-by-step explanation:
Question 1: Which of the following is the solution to 8√3 + 7√3?Given expression
8√3 + 7√3
Simplify by addition
Remember that terms with the same radical part can add together directly
= (8 + 7) √3
[tex]\Large\boxed{=15\sqrt{3} }[/tex]
Question 2: Which of the following is the solution to √15 * √45 simplified?Given expression
√15 × √45
Factorize each radical
= √(3 × 5) × √(9 × 5)
= √3 × √5 × √9 × √5
Simplify necessary radicals
= √3 × √5 × 3 × √5
= 3 × √3 × √5 × √5
Simplify by multiplication
When radicals multiply, combine them under one radical sign
= 3√3 × √(5 × 5)
= 3√3 × 5
[tex]\Large\boxed{=15\sqrt{3} }[/tex]
Questions 3: Which of the following is the solution to 15√10 - 3√10?Given expression
15√10 - 3√10
Simplify by subtraction
Remember that terms with the same radical part can subtract each other directly
= (15 - 3) √10
[tex]\Large\boxed{=12\sqrt{10} }[/tex]
Hope this helps!! :)
Please let me know if you have any questions
On parallelogram ABC∧
mΔA=42 mΔB=___ mΔC___ mΔD=___
The measures of the remaining angles of the parallelogram are m ∠ B = 138°, m ∠ C = 42° and m ∠ D = 138°
How to determine the measure of missing angles in a parallelogram by geometric theorems
In this problem we know the measure of an angle and we should find the values of the three remaining angles. According to Euclidean geometry, the sum of internal angles in a parallelogram equals 360° and there exists the following property between each pair of angles:
m ∠ A = m ∠ Cm ∠ B = m ∠ Dm ∠ A + m ∠ B = m ∠ B + m ∠ C = m ∠ C + m ∠ D = m ∠ A + m ∠ D = 180°Then, the measures of the missing angles are, respectively:
m ∠ B = 180° - m ∠ A
m ∠ B = 180° - 42°
m ∠ B = 138°
m ∠ D = 138°
m ∠ C = 42°
Remark
The statement is poorly formatted, presents typing mistakes and image is missing, correct form is shown below:
On parallelogram ABCD, m ∠ A = 42, m ∠ B = ____, m ∠ C = _____, m ∠ D = _____
A representation of the parallelogram is shown in the image attached below.
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The scatter plot shows the relationship between the test scores of a group of students and the number of hours they exercise in a week:
On a grid, Label Hours of Exercise on x axis and Test Scores on y axis. The title of the graph is Test Scores and Exercise. The scale on the x axis shows the numbers from 0 to 10 at increments of 1, and the scale on the y axis shows numbers from 0 to 100 at increments of 10. Dots are made at the ordered pairs 1.1, 12 and 1, 30 and 2.1, 21 and 2.5, 42 and 3.5, 30 and 3.5, 45 and 4, 55 and 5, 45 and 5.5, 60 and 5.5, 70 and 6.5, 40 and 7, 50 and 7.5, 80 and 8, 75, and 8.5, 60 and 9, 75. The ordered pair 9, 15 is circled and labeled as T. All the other points are put in an oval and labeled as P.
Part A: What is the group of points labeled P called? What is the point labeled T called? Give a possible reason for the presence of point T. (5 points)
Part B: Describe the association between students' test scores and the number of hours they exercise. (5 points)
It should be noted that Group A is a cluster of points with similar property or relationship and Point B is an outlier. This is the point outside of the common relationship in the scatterplot
What is a scatterplot?It should be noted that scatter plots are the graphs that present the relationship between two variables in a data-set. It represents data points on a two-dimensional plane or on a Cartesian system.
In this case, the independent variable or attribute is plotted on the X-axis, while the dependent variable is plotted on the Y-axis.
The association between students' test scores and the number of hours they exercise is that there is a negative tendency. As number of hours spent on computer games increase, the test scores decrease.
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JOHN RICHARDS BORROWED $875 AGAINST HIS CHARGE ACCOUNT ON SEPTEMBER
12 AND REPAID THE LOAN ON OCTOBER 14 (32 DAYS LATER). IF THE INTEREST RATE
IS 0.04273% PER DAY, HOW MUCH INTEREST DID JOHN PAY ON THE LOAN AND WHAT
AMOUNT DID HE PAY THE BANK WHEN HE REPAID THE LOAN
Using simple interest, it is found that:
John paid $12 in interest for the loan.The total amount that he paid the bank was of $887.Simple InterestSimple interest is used when there is a single compounding per time period.
The amount of money after t units of time in is modeled by:
[tex]A(t) = A(0)(1 + rt)[/tex]
In which:
A(0) is the initial amount.r is the interest rate, as a decimal.For this problem, the parameters are given as follows:
A(0) = 875, r = 0.0004273, t = 32.
Hence the amount paid is given by:
A(32) = 875 x (1 + 0.0004273 x 32) = $887.
The amount of interest is given by:
I = 887 - 875 = $12.
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Find the magnitude and direction of each resultant for the given vectors. Round each side to the nearest tenth and round each angle to the nearest degree.
w = < 5, 6 >, x = < -1, 14 >
The magnitude of the resultant vectors is 20.4 units and the direction of the vectors is 79⁰.
Magnitude of the resultant vector
Sum of vectors in x direction, ∑X = 5 - 1 = 4
Sum of the vectors in y direction, ∑Y = 6 + 14 = 20
Resultant vector = √(∑X² + ∑Y²)
Resultant vector = √(4² + 20²) = 20.4 units
Direction of the vectorθ = arc tan (ΣY/ΣX)
θ = arc tan (20/4)
θ = arc tan (5)
θ = 78.7⁰
θ ≈ 79⁰
Thus, the magnitude of the resultant vectors is 20.4 units and the direction of the vectors is 79⁰.
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Item to ship 58 ,
items per case 6
Answer: 9 and 2/3 cases
Step-by-step explanation:
6 goes into 58 9 times to make 54 so makes 4 left over 4/6 simplified makes 2/3.
To ship 58 items with 6 items per case, you will need 9 complete cases and 1 additional case with the remaining 4 items, making a total of 10 cases.
We have,
To find the number of cases required to ship 58 items when there are 6 items per case, we can use division.
Number of cases = Total items / Items per case
Number of cases = 58 items / 6 items per case
Number of cases = 9 with a remainder of 4
When we divide 58 items by 6 items per case, we get 9 with a remainder of 4.
This means that 9 cases can be fully filled with 6 items each, and there will be 4 items left that won't fit in a complete case.
Therefore,
To ship 58 items with 6 items per case, you will need 9 complete cases and 1 additional case with the remaining 4 items, making a total of 10 cases.
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The complete question:
How many cases are required to ship 58 items if there are 6 items per case?
Answers for number 32 and 31
Answer:
32: X=54
31: Xx54+74
What is the perimeter of angle DEF to the nearest tenth of a unit?
helppppp
tysm
===========================================================
Explanation:
Let's use the distance formula to find the distance from D to E
[tex]D = (x_1,y_1) = (-7,2) \text{ and } E = (x_2, y_2) = (3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-7-3)^2 + (2-4)^2}\\\\d = \sqrt{(-10)^2 + (-2)^2}\\\\d = \sqrt{100 + 4}\\\\d = \sqrt{104}\\\\d = \sqrt{4*26}\\\\d = \sqrt{4}*\sqrt{26}\\\\d = 2\sqrt{26}\\\\d \approx 10.198\\\\[/tex]
Note: uppercase D refers to the point, while lowercase d is the distance from D to E.
The length of segment DE is roughly 10.198 units long.
----------------
Repeat for the distance from E to F.
[tex]E = (x_1,y_1) = (3,4) \text{ and } F = (x_2, y_2) = (5,-7)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (4-(-7))^2}\\\\d = \sqrt{(3-5)^2 + (4+7)^2}\\\\d = \sqrt{(-2)^2 + (11)^2}\\\\d = \sqrt{4 + 121}\\\\d = \sqrt{125}\\\\d = \sqrt{25*5}\\\\d = \sqrt{25}*\sqrt{5}\\\\d = 5\sqrt{5}\\\\d \approx 11.1803\\\\[/tex]
Segment EF is roughly 11.1803 units long.
----------------
Repeat for the distance from F to D.
[tex]F = (x_1,y_1) = (5,-7) \text{ and } D = (x_2, y_2) = (-7,2)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(5-(-7))^2 + (-7-2)^2}\\\\d = \sqrt{(5+7)^2 + (-7-2)^2}\\\\d = \sqrt{(12)^2 + (-9)^2}\\\\d = \sqrt{144 + 81}\\\\d = \sqrt{225}\\\\d = 15\\\\[/tex]
Unlike the others, this result is exact.
----------------
Add up the three segment lengths to get the perimeter
DE + EF + FD
10.198 + 11.1803 + 15
36.3783
The perimeter is approximately 36.3783 units which rounds to 36.4
The answer has been confirmed with GeoGebra.
Two sides of a triangle are 12cm and 8cm. Complete the inequality to show the possible lengths for the third side.
The inequalities that represents the third side of the triangle is c ≥ 4 or c ≤ 20
How to find the third side of a triangle?The triangle inequality theorem states that that the sum of any two sides of a triangle is greater than or equal to the third side.
Therefore, the two sides of the triangle are 12 cm and 8 cm.
A triangle with sides a, b and c follows the principle below;
a + b ≥ c.
Therefore,
let
c = third sides
12 + 8 ≥ c
20 ≥ c
c + 8 ≥ 12
c ≥ 4
c + 12 ≥ 8
Therefore, the third third should be greater than or equals to 4 or less than or equals to 20
c ≥ 4 or c ≤ 20
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Can someone please help me with this?
Answer: Option (2)
Step-by-step explanation:
When x=10,
The median-median line gives [tex]y=1.4(10)+2.6=16.6[/tex].The least-squares regression line gives [tex]y=0.9(10)+4.2=13.2[/tex].13.2 is closer to 14 than 16.6, so the least-squares regression line is a better prediction.
Merina is scheduled to make two loan payments to Bradford in the amount of $1,000 each, two months and nine months from now. Merina doesn't think she can make those payments and offers Bradford an alternative plan where she will pay two equal amounts seven months from now followed by another equal payment seven months later. Bradford determines that 8.5% is a fair interest rate. Using the second unknown equal payment as your focal date, what are the equal payments?
well, we're assuming all along that Merina owes Bradford $2000, because in the 1st scenario, she was going to pay twice $1000.
on the 2nd scenario, she'll be paying the same $2000 but split 7 months from now and then 7 months later, same 2000 bucks, at which point Bradford applied 8.5% interest.
using those assumptions, since the wording is not quite clear, we can say that Merina is simply paying 2000 bucks plus the 8.5%
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8.5\% of 2000}}{\left( \cfrac{8.5}{100} \right)2000}\implies 170 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\stackrel{principal}{2000}~~ + ~~\stackrel{interest}{170}}{2}\implies \stackrel{\textit{two equal payments of}}{1085}[/tex]
Find the surface area of the composite figure 4 cm 13 cm 3 cm 4 cm 12 cm SA = [?] cm² 5 cm 3 cm.
6
Select the correct answer.
A company polled a large group of people to assess the company's reputation in the surrounding communities. To save time, the survey was
mailed to the addresses of stockholders and former employees that the company already had on file and that were in the surrounding areas.
Which of the following statements is correct?
Answer:
a company powder large group of people to assess the company's reputation in the surrounding
Find one possible missing coordinate so that the point becomes a solution to the given inequality.
(x,6) is a solution to 6x−6>y .
Answer:
Step-by-step explanation:
6x-6>y
put y=6
6x-6>6
6x>12
x>12/6
x>2
(3,6) is one solution.
72 is 15% of what number?
Answer: 480
Step-by-step explanation:
72/3 is 5% of the number we are looking for.
72/3=24
24*20 will be 100%
480 is 100%
72 is 15% of what number?
Quantity %
72---------------15
x---------------100
We solve
[tex]\boldsymbol{\sf{x=\dfrac{72\times100 }{15}=\dfrac{7200}{15}=480 }}[/tex]
Answer: 72 is 15% of 480.
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A printer prints an average of 2001/2 pages per hour. Approximately how many pages did it print in a 8-hour period
Answer:
Step-by-step explanation:
Comment
I can't be sure what you mean by 2001/2. I will interpret it the way it is written.
1 hour produces 2001/2
8 hours produces x
What you have is a proportion.
Solution
1/8 = 2001/2 // x Cross multiply
1*x = 2001/2 * 8 Combine
x = 8004
Answer
The printer will produce 8004 printed pages.
a chef uses 5 2/5 pounds of ground beef to make a hamburger and 2 1/4 pounds of ground beef to make meatloaf. the ground beef comes in 1/2 pound packages. how many packages of ground beef are needed to make hamburgers and meatloaf?
Answer:
16 packages
Step-by-step explanation:
5 2/5 + 2 1/4 Use the common denominator of 20
5 8/20 + 2 5/20
7 13/20
I know that I will need 14 packages for the 7 pounds. For the fraction part, 10/20 would be half, so I would need to buy a half pound for that, but I need 13/20 which would be more than a half pound, so I will need to buy 2 more pounds for the fraction part.
14 + 2 = 16
P = √mx_ £x MX t make x the subject
[tex]p = \sqrt{ \frac{mx}{t} } - t {}^{2}x \: \: make \: x \: the \: subject [/tex]
So, making x subject of the formula, x = [m - 2pt³ ±√(m² - 4pt²m)]/{2t⁵}
How to make x subject of the formula?Since p = √(mx/t) - t²x
So, p + t²x = √(mx/t)
Squaring both sides, we have
(p + t²x)² = [√(mx/t)]²
p² + 2pt²x + t⁴x² = mx/t
Multiplying through by t,we have
(p² + 2pt²x + t⁴x²)t = mx/t × t
p²t + 2pt³x + t⁵x² = mx
p²t + 2pt³x + t⁵x² - mx = 0
t⁵x² + 2pt³x - mx + p²t = 0
t⁵x² + (2pt³ - m)x + p²t = 0
Using the quadratic formula, we find x.
[tex]x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}[/tex]
where
a = t⁵, b = (2pt³ - m) and c = p²tSubstituting the values of the variables into the equation, we have
[tex]x = \frac{-(2pt^{3} - m) +/-\sqrt{(2pt^{3} - m)^{2} - 4(t^{5})(p^{2}t) } }{2t^{5} }\\= \frac{-(2pt^{3} - m) +/-\sqrt{4p^{2} t^{6} - 4pt^{2}m + m^{2} - 4p^{2}t^{6} } }{2t^{5}}\\= \frac{-(2pt^{3} - m) +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}\\= \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}[/tex]
So, making x subject of the formula, [tex]x = \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}[/tex]
Learn more about subject of formula here:
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