A store is having a sale on trail mix and jelly beans. For 3 pounds of trail mix and 8 pounds of jelly beans, the total cost is $29. For 5 pounds of trail mix and 2 pounds of jelly beans, the total cost is $20. Find the cost for each pound of trail mix and each pound of jelly beans.

Answer:

9

Step-by-step explanation:

6 ÷ 2/3   =    6 /  (2/3 )   =  (6/1) / (2/3)  = 6/1  x  3/2 = 18/2 = 9

Question 13

Part (a)

[tex]\frac{3840-3905}{110}=\boxed{0.5\overline{90}}[/tex]

By similar logic, the other answers are

(b) 2.6818181....

(c) 3.5909090...

(d) 1.1363636...

Question 14

Part (a)

[tex]\frac{46800-41400}{4700} \approx \boxed{1.15}[/tex]

Part (b)

[tex]-2.57=\frac{x-41400}{4700} \\ \\ -2.57(4700)=x-41400 \\ \\ x=41400-2.57(4700) \\ \\ x \approx \boxed{29300}[/tex]

Step-by-step explanation:

1/4×48

=12

So if 12people are out of state

48-12=36,is the number of people living in the state

Based on the total number of people who want the steakhouse option, the probability that a student will not want the seafoodbuffet if they want the steakhouse option is 24%

The probability that a student does not want the seafood buffet given that they want the steakhouse option is:

= Number of people who want steakhouse but not seafood / Total surveyed

Solving gives:

= 9 / (16 + 8 + 9 + 4)

= 9 / 37

= 24%

Full question is:

If a student wants the steakhouse option, what is the probability that they will not want the seafoodbuffet?

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Answer:

8 ^-11

Step-by-step explanation:

It should be noted that in this case, since it's the product that we want to get, it's important to add the power together. This will be:

8^-2 × 8^-9

= 8^(-2 + -9)

= 8^-11

Considering the definition of mass volume percent, the percent composition of lactose in skim milk is 28%.

The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. In other words, the relationship between the amount of solute and the amount of solvent is called concentration.

Mass volume percent (% m/V) is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution.

In other words, mass-volume percent is an intensive property that is defined as the mass of solute (in grams) that there are in 100 mL of solution and it is calculated by applying the following equation:

[tex]Mass volume percent=\frac{mass solute (grams)}{volume solution (mL)}x100[/tex]

This is, mass volume percent is defined as the ratio of the mass of solute that is present in a solution, relative to the volume of the solution, as a whole.

In this case, you know:

Replacing in the definition of mass volume percent:

[tex]Mass volume percent=\frac{0.28 grams}{1 mL}x100[/tex]

Solving:

mass volume percent= 28 %

Finally, the percent composition of lactose in skim milk is 28%.

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Answer: [tex]y+2=2(x-3)[/tex]

Step-by-step explanation:

Parallel lines have the same slope, so substituting into point-slope form, the equation is

[tex]y+2=2(x-3)[/tex]

The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

The quadratic function is given as:

f(x) = x^2 - 3x

Differentiate the function

f'(x) = 2x - 3

Set the function to 0

2x - 3 = 0

Add 3 to both sides

2x = 3

Divide by 2

x = 3/2

Set x = 3/2 in f(x) = x^2 - 3x

f(x) = 3/2^2 - 3 * 3/2

Evaluate

f(x) = -9/5

So, we have:

(x, f(x)) = (3/2, -9/5)

The above represents the vertex of the quadratic function.

This is properly written as:

(h, k) = (3/2, -9/5)

The vertex form of a quadratic function is

f(x) = a(x - h)^2 + k

So, we have:

f(x) = a(x - 3/2)^2 - 9/5

In f(x) = x^2 - 3x,

a = 1

So, we have:

f(x) = (x - 3/2)^2 - 9/5

Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

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Answer:

The file contains the solution to the question

Answer:

1,680

Step-by-step explanation:

8 positions with basically 8 choices.

that is 8! arrangements.

but 2 is there 2 times.

8 is there 2 times.

5 is there 3 times.

only 3 is a single digit.

so, we need to eliminate every arrangement, where the 2s trade places, where the 5s trade places, and where the 8s trade places, because they are the same numbers.

that means we have to divide the 8! by 2!, then again by 2!, and again by 3!.

8! / (2! × 2! × 3!) = 8! / 24 = 1,680

A. No, AB and BC are not congruent

B. No, AC and BD are not congruent

From the question, we are to determine if the given pairs of segments are congruent

To do this, we will determine the length of the line segments

Consider the given number line,

AB = -2 - (-5) = -2 + 5 = 3

BC = 0 - (-2) = 0 + 2 = 2

AC = 0 - (-5) = 0 + 5 = 5

BD = 5 - (-2) = 5 + 2 = 7

Now,

A. AB and BC

AB = 3 and BC =2

∴ AB and BC are not congruent.

Thus, No

A. AC and BD

AC = 5 and BD = 7

∴ AC and BD are not congruent.

Thus, No

Hence,

A. No, AB and BC are not congruent

B. No, AC and BD are not congruent

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Answer:

d(t)=-10t-520

Step-by-step explanation:

First you have to find the gradient (m) using the formula [tex]m=\frac{d(t)2-d(t)1}{t2-t1}[/tex]

using the two points you have been given: 1(3,-550) and 2(8,-600)

so you substitute these points into the equation [tex]m=\frac{-600+500}{8-3}[/tex]

m=-10

Now that you have found the m-value you need to find the b-value by using one of the points you already have, I will use Point 2 (8,-600), and substitute it into the equation and solve

d(t)=-10t+b

-600=-10*8+b

-600=-80+b

-520=b

Therefore, the equation is d(t)=-10t-520

Answer:

x = - 4

Step-by-step explanation:

using the rule of indices

[tex]\frac{1}{a^{n} }[/tex] = [tex]a^{-n}[/tex] , then

[tex]3^{x}[/tex] = [tex]\frac{1}{81}[/tex] = [tex]\frac{1}{3^{4} }[/tex] = [tex]3^{-4}[/tex] , that is

[tex]3^{x}[/tex] = [tex]3^{-4}[/tex] , thus

x = - 4

Answer:

b

Step-by-step explanation:

b

The best conjecture for Charlie to develop is that an altitude drawn to the base of the isosceles triangle creates the smaller congruent triangles by the HL postulate.

It should be noted that conjecture simply means a conclusion that's proffered on a tentative basis without any proof.

From the information, Charlie used construction paper, scissors and a ruler to construct an isosceles triangle with a pair of sides each 3 inches long and an acute angle on top.

Here, the best conjecture for Charlie to develop is that an altitude drawn to the base of the isosceles triangle creates the smaller congruent triangles by the HL postulate.

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sinE is 0.5

What are similar triangles?

Two triangles will be similar if the angles are equal (corresponding angles), and sides are in the same ratio or proportion (corresponding sides). Similar triangles may have different individual lengths of the sides of triangles, but their angles must be equal and their corresponding ratio of the length of the sides must be the same.

Clearly, given triangle AFB and triangle DFE are similar.

We know that Similar Triangles have the same corresponding angle

We can find sinE as show below:

From diagram clearly

∠A=∠E

and ∠B=∠D

Since, ∠A=∠E

Taking sin on both sides

sinA=sinE

Give, sinA=0.5

sinA=sinE=0.5

⇒ sinE=0.5

Hence, sinE is 0.5

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Step-by-step explanation:

Answer:

W = (P -2L)/2

Step-by-step explanation:

P = 2(L + W)  Distribute the 2

P = 2L + 2W   Subtract 2L from both sides

P - 2L = 2W  Divide both sides by 2

(P-2L)/2 = W  

Answer: -1

Step-by-step explanation:

Evaluate 4x if x = -1/4

4(-1/4) = -1

Answer: -1

Step-by-step explanation:

4x and x = -1/4

plug x into the expression

[tex]4(-\frac{1}{4} )[/tex]

simplifies to:

[tex]-\frac{4}{4}[/tex]

4 divided by 4 is just 1, but it is negative so your final answer is

-1

Answer:

12 and 14

Step-by-step explanation:

12 * 14 = 168

Answer:

12 & 14

Step-by-step explanation:

the work: x = first even number, (x+2) = second even number

The equation

[tex]x(x+2)=168[/tex]

[tex]x^{2} +2x=168[/tex]

[tex]x^{2} +2x-168=0[/tex]

Factoring

[tex](x-12)(x+14)=0[/tex]

first factor

[tex]x-12=0\\x=12[/tex]

Second factor

[tex]x+14=0\\x=-14[/tex]

The solution is the positive number

x = 12     is the first even number

x + 2 = 12 + 2 = 14    is the second even number

Hope this helps

Answer:

39°

Step-by-step explanation:

Opposite angles of a parallelogram are congruent.

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

" The opposite angles of a Parallelogram are always equal to one another "

[tex] \qquad \large \sf {Conclusion} : [/tex][tex] \qquad \large \sf {Conclusion} : [/tex]

If we rewrite the expression 8v(v+3)(v+3) then we will get [tex]v^{3}+6v^{2} +9v[/tex]

Given an expression 8v(v+3)(v+3).

We are required to rewrite the given expression.

Expression is a combination of numbers, symbols, fraction , determinants,indeterminants, coefficients. They are not mostly found in equal to form. It expresses a relationship of a line or something else.

The expression is 8v(v+3)(v+3). There are three terms in which variable is v.

To rewrite the expression we have to multiply all the three terms with each other which can be done as under:

=8v(v+3)(v+3)

=[tex](8v^{2}+24v)(v+3)[/tex]

=[tex]8v^{3}+24v^{2}+24v^{2}+72v[/tex]

=[tex]8v^{3}+48v^{2} +72v[/tex]

Now divide it by 8.

=[tex]v^{3}+6v^{2} +9v[/tex]

Hence if we rewrite the expression 8v(v+3)(v+3) then we will get [tex]v^{3}+6v^{2} +9v[/tex] .

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The volume of the cylinder in discuss in which case, the radius of the cylinder is 3 inches and the height is inches is; V = 141.3in³.

The cylinder in discuss according to the task content has radius, 3 inches and height, 5 inches.

Since the volume of a cylinder by convention is given as; V = πr²h

Therefore, the volume of the cylinder in discuss is;

V = π (3²)×5

V = 3.14 × 45

V = 141.3in³

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex] \qquad❖ \: \sf \:6 = 2(y + 2)[/tex]

[tex] \qquad❖ \: \sf \:(y + 2) = \cfrac{6}{2} [/tex]

[tex] \qquad❖ \: \sf \:y + 2 = 3[/tex]

[tex] \qquad❖ \: \sf \:y = 3 - 2[/tex]

[tex] \qquad❖ \: \sf \:y = 1[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

The solution to the question is mathematically given as

1)

H0: M [tex]\geqslant[/tex] 300

H0: M [tex]\geqslant[/tex] 300

2)

Z distribution.

3)

z=-2.4

4)

P=0.0082

5)

"H0" is rejected as a hypothesis with a level of significance of 0.05.

Generally, the equation for is mathematically given as

Solutions

we have, [tex]$u=300$$$\begin{aligned}& \sigma=150 \text { dollars } \\N &=64 \text { individuals } \\\bar{x} &=255 \text { dollare. } \\a=& 0.05 .\end{aligned}[/tex]

(1):

H0: M [tex]\geqslant[/tex] 300 dollars;  customers save at least 300 dollars per year by switching to them.

H0: M [tex]\geqslant[/tex] 300 dollars:

(This is a left-tailed test)

(2):

when [tex]\sigma[/tex] is known, we use the Z test. we use Z distribution.

(3):

[tex]\begin{gathered}z=\frac{\bar{x}-\mu}{6 / \sqrt{n}}=\frac{255-300}{150 / \sqrt{64}}=\frac{-45}{18.75}=-2.4 \\z=-2.4\end{gathered}[/tex]

(4):

[tex]Pvalue $=P(z < -2 \cdot 4)$ $=0.0082 \quad\{$ wing $z$ tables $\}$ \\\\\text { Pvalue }=0.0082[/tex]

(5):

In conclusion, Since p-value = 0·0082 <0.05

This is statistically significant at the 0.05 level.

We thus "Refect H0" using a threshold of significance of 0.05.

"H0" is rejected as a hypothesis with a level of significance of 0.05.

There is not enough data to support the assertion that consumers may save at least $300 annually by switching insurance providers.

Therefore, we would not consider making the transition to this firm.

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The length of the missing side is 9.92 ft given that the base of the following pyramid is a square, base side length(s) is 11 ft and the volume of the square pyramid is 400 ft³. This can be obtained using the formula of finding the volume of the pyramid with base as square.

The formula of finding the volume of the pyramid with base as square is,

⇒ V = s²h/3

where V is the volume of the square pyramid, s is the side length of the base and h is the height of the square pyramid.

Here in the question it is given that,

that is, s = 11 ft, V = 400 ft³

By using the formula of finding the volume of the pyramid with base as square we get,

V = s²h/3

400 = (11)²h/3

By rearranging the equation we get,

h = 400 × 3/11²

h = 9.92 ft

Hence the length of the missing side is 9.92 ft given that the base of the following pyramid is a square, base side length(s) is 11 ft and the volume of the square pyramid is 400 ft³.

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The limit of f(x) as x goes to 1 will not exist for function III.

A limit is given by the value of function f(x) as x tends to a value. For a function with different lateral limits at a point x = a, the limit will not exist at the point x = a. Additionally, the limit may not exist at a point if there is a non-removeable discontinuity.

Factoring the function 1, the limit will be given as follows:

[tex]\lim_{x \rightarrow 1} \frac{1 - x^2}{x - 1} = \lim_{x \rightarrow 1} \frac{(1 - x)(1 + x)}{x - 1} = \lim_{x \rightarrow 1} -(1 +x) = -2[/tex]

Hence the limit exists.

Factoring the function 2, the limit will be given as follows:

[tex]\lim_{x \rightarrow 1} \frac{x^2 - x^3}{x^2 - 1} = \lim_{x \rightarrow 1} \frac{x^2(1 - x)}{(x - 1)(x + 1)} = \lim_{x \rightarrow 1} -\frac{x^2}{x + 1} = -\frac{1}{2}[/tex]

Hence the limit exists.

Factoring the function 3, the limit will be given as follows:

[tex]\lim_{x \rightarrow 1} \frac{x + 1}{x^2 - 1} = \lim_{x \rightarrow 1} \frac{x + 1}{(x - 1)(x + 1)} = \lim_{x \rightarrow 1} \frac{1}{x - 1}[/tex]

Non-revemoveable discontinuity, as we can't remove x - 1 for the denominator, ence the limit does not exist for function III.

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