A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 729 cubic feet. The concrete for the base cost $8 per square foot, The material for the roof costs $3 Per square foot, and the material for the sides costs $5.50 Per square foot. Find the dimensions of the most economical shed.

Answers

Answer 1

The dimensions of the most economical shed are 9 ft in length, 9 ft in width, and 9 ft in height if the storage shed is to be built in the shape of a box with a square base.

What is volume?

It is defined as a three-dimensional space enclosed by an object or thing.

It is given that:

A storage shed is to be built in the shape of a box with a square base.

It is to have a volume of 729 cubic feet.

Let x be the length of the base

Let y be the height of the box.

V = 729 cubic feet

The base is square:

l = w = x

V = x²y

y =  729/x²

Cost of the base = $8x²

Cost of the roof = 3x²

Cost of the sides = 4(5.50)xy

= 22xy

Total cost

C= 8x² + 3x² + 22xy

C = 11x² + 22x(729/x²)

C = 11x² + 16038/x

Find the first derivative:

dC/dx = 22x - 16038/x²

Equate; dC/dx = 0

22x - 16038/x² = 0

22x = 16038/x²

22x³ =16038

x³ = 729

x = 9

y = 729/(9)² = 9

Length of base = 9 ft

Width of base  = 9 ft

Height of box = 9 ft

Thus, the dimensions of the most economical shed are 9 ft in length, 9 ft in width, and 9 ft in height.

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Related Questions

Which of the following best reflects a theme of art influenced by the teachings of Sigmund Freud?
a.
images with antiwar themes
b.
a dream-like image
c.
ready-mades
d.
none of the above


Please select the best answer from the choices provided

A
B
C
D

Answers

Answer:

B

Step-by-step explanation:

a dream like imageeeeee

The next model of a sports car will cost 4.4% more than the current model. The current model costs $49,000. How much will the price increase in dollars? What will be the price of the next model?​

Answers

Answer: $51156

Step-by-step explanation:

a = b x p%

how much will the price increase

a = 49,000 x 4.4%

= 49,000 x 0.044

= $2156

price of next model

49,000 + 2156 = $51156

Kendra received a bonus that was 30% of her monthly earnings. If her monthly earnings were $930, how much was Kendra's bonus?

Answers

Answer:

$279

Step-by-step explanation:

100% = $930

30% = ???

(30/100) × 930

=$279

see attachment for question

Answers

The percentages for each outcome are given as follows:

a) 34.4%.

b) 29.4%.

What is a percentage?

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = a/b x 100%

For this problem, we already have the percentages, hence we just combine them.

For item a, he can be late in two ways, one that happens 24.4% of the time(waking up late), and the other 10%(stuck in traffic), hence the percentage is of 34.4%, as 24.4% + 10% = 34.4%.

For item b, the percentage stuck in traffic is of 5%, hence the percentage that he will be late is 24.4% + 5% = 29.4%.

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Let f= {(-5,-4),(6,-5),(2, -3)}.
Find f(-5).

Answers

Answer:

f(–5)=–4

Step-by-step explanation:

as it is defined

what is - 1/5 ( -2 1/4) ?

Answers

-1/5 (-2 1/4)=9/20

-1 x -9=9
5 4=20

Subtract: 3x to the power 2 - 6x - 4 from 5 + x - 2xto the power 2.

Answers

Answer:

[tex]-8x^2 - 4x + 29 \\[/tex]

Step-by-step explanation:

Second expression evaluates to:

[tex](5 + x -2x)^2 = (5 -x)^2 = (-x+5)^2 = x^2 + 2(-x)(5) +5^2 = x^2 -10x + 25[/tex]  (1)

For (1) We are using the rule [tex](a+b)^2 = a^2 +2ab + b^2\\\\[/tex]

Here [tex]a = -x, b = 5\\\\[/tex]

First expression evaluates to

[tex](3x)^2 -6x - 4 = 9x^2 -6x -4[/tex]    (2)

Subtract (2) from (1)

[tex]x^2 - 10x +25 - (9x^2 -6x -4) = x^2-9x^2 -10x - (-6x) +25 -(-4)\\\\= -8x^2 - 4x + 29 \\[/tex]

 

Directions: Find the missing angle in each of the following problems.

1. QR = 36 ; PR = 45 ; PQ = 21, Sin __?___ = 21 / 45

2. QR = 16 ; PR = 2 ; PQ = 8, tan __?__ = 8 / 16

3. QR = 15 ; PR = 28 ; PQ = 15, Cos __?__ = 15 / 28

4. QR = 47 ; PR = 64 ; PQ = 38, tan __?__ = 38 / 47

5. QR = 4 ; PR = 17 ; PQ = 12, Sin __?___ = 12 / 17

6. QR = 36 ; PR = 59 ; PQ = 20, Cos __?___ = 36 / 59

7. QR = 82 ; PR = 63 ; PQ = 29, tan __?__ = 29 / 82

8. QR = 10 ; PR = 28 ; PQ = 8, Sin __?___ = 8 / 28

9. QR = 51 ; PR = 42 ; PQ = 9, tan __?__ = 9 / 51

10. QR = 16 ; PR = 20 ; PQ = 17, Cos __?___ = 16 / 20

11. QR = 12 ; PR = 84 ; PQ = 60, Sin __?_ = 60 / 84

12. QR = 19 ; PR = 32 ; PQ = 45, Cos __? = 19 / 32

13. QR = 76 ; PR = 27 ; PQ = 64, tan __ ?_ = 64 / 76

14. QR = 26 ; PR = 48 ; PQ = 37, Cos __?_ = 37 / 48

15. QR = 19 ; PR = 66 ; PQ = 23, Cos __?__= 23 / 66

Answers

The missing angles are listed below:

sin 27.818° = 21 / 45

tan 26.565° = 8 / 16

cos 57.607° = 15 / 28

tan 38.956° = 38 / 47

sin 44.901° = 12 / 17

cos 52.398° = 36 / 59

tan 19.477° = 29 / 82

sin 16.601° = 8 / 28

tan 10.008° = 9 / 51

cos 36.870° = 16 / 20

sin 35.538° = 60 / 84

cos 53.576° = 19 / 32

tan 40.101° = 64 / 76

cos 39.571 = 37 / 48

cos 69.605° = 23 / 66

How to find the measure of missing angles by definition of inverse of trigonometric functions

In this question we must find the measure of the angle associated to the rational numbers seen in the statement. There are two methods to estimate such measures: (i) Drawing an equivalent right triangle and estimate the measure of the angle by definition of trigonometric functions, (ii) Using inverse trigonometric functions and numerical methods since they are trascendent variables.

Herein we decided to use the second method by reasons of rapidness and effectivity:

sin 27.818° = 21 / 45

tan 26.565° = 8 / 16

cos 57.607° = 15 / 28

tan 38.956° = 38 / 47

sin 44.901° = 12 / 17

cos 52.398° = 36 / 59

tan 19.477° = 29 / 82

sin 16.601° = 8 / 28

tan 10.008° = 9 / 51

cos 36.870° = 16 / 20

sin 35.538° = 60 / 84

cos 53.576° = 19 / 32

tan 40.101° = 64 / 76

cos 39.571 = 37 / 48

cos 69.605° = 23 / 66

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PLEASE HELP ME! I WILL AWARD BRAINLIEST TO WHOEVER ANSWERS THE QUESTION BEST!

Answers

Considering it's discriminant, it is found that:

A. The classmate is wrong, as the discriminant is of zero, hence the equation has one solution.

B. The quadratic equation has 1 x-intercept.

What is the discriminant of a quadratic equation and how does it influence the solutions?

A quadratic equation is modeled by:

y = ax^2 + bx + c

The discriminant is:

[tex]\Delta = b^2 - 4ac[/tex]

The solutions are as follows:

If [tex]\mathbf{\Delta > 0}[/tex], it has 2 real solutions.If [tex]\mathbf{\Delta = 0}[/tex], it has 1 real solutions.If [tex]\mathbf{\Delta < 0}[/tex], it has 2 complex solutions.

In this problem, the equation is:

y = 9x² - 6x + 1.

The coefficients are a = 9, b = -6 and c = 1, hence the discriminant is:

[tex]\Delta =(-6)^2 - 4(9)(1) = 36 - 36 = 0[/tex]

Since the discriminant is zero, the classmate is wrong, as it means that the equation has one solution = one x-intercept.

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Mathematics problem..

Answers

Answer:

a) x + 10 = 45

b) 3 = 6 - x

c) d = s * t

Step-by-step explanation: This is actually pretty simple. Let's put down one theorem.

SYMMETRIC THEOREM OF PROPERTIES: If a equals b, then b must equal a. Thus, a = b and b = a.

This is all we're really doing.

Take a) for example, 45 = x + 10. Let's label (45) as A, and (x + 10) as B. Thus we have A = B. Now we know by the Symmetric Property, we have B = A. Thus, substituting B and A again, we get x + 10 = 45.

Just keep doing this with all the equations.

Hope this helped!

PLEASE HELP!

Let f be the function given by f (x) = (create an original sinusoidal function with an amplitude not equal to 1, a period not equal to 2π, and non-zero phase and vertical shifts).

ex: F of x equals negative one half times sine of quantity 3 times x plus pi over 2 end quantity minus 2


Part A: State the amplitude and vertical shift.


Part B: Determine the period of f (x), showing all necessary calculations.


Part C: Calculate the phase shift of the sinusoidal function with proper mathematical justification.


Part D: Graph the sinusoidal function by hand, using your answers from parts A–C.


Choose an angle θ, in radians, such that 2π < θ < 4π . Let θ = (create an original angle measure).


ex: Theta equals 13 pi over 6


Part E: Determine the exact value of cos θ using the sum formula. Show all necessary mathematical work.


Part F: Determine the exact value of sin θ using the difference formula. Show all necessary mathematical work.


Part G: Calculate the exact value of tan 2θ, using your answers from parts E – F.

Answers

The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

How to create the sine function?

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

Amplitude not equal to 1Period not equal to 2πNon-zero phase and vertical shifts

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

The amplitude, vertical shift, period of f(x)and the phase shift

Using the representations in (a), we have:

Amplitude = 2Vertical shift = -3Period = 4Phase shift = 6

The graph of the function

See attachment for the graph of f(x)

The value of cos θ

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

The value of sin θ

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

The value of tan 2θ

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

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PLEASE HELP ALOT OF POINTS

Answers

Answer: B

Step-by-step explanation:

A recent food drive distributed 6,298 pounds of stoneground cornmeal to 1,007 people. Approximately how many pounds did each person receive? Round to the hundredths.

Answers

Answer: 6.25

Step-by-step explanation: Here, you want to find how much of 6,298 pounds of food each person got. You can do this by dividing. 6,298/1,007 should get you the answer because it shows how the 6,298 pounds were distributed amongst the 1,007 people.

Evaluate (f + g)(x) if f(x) = 2x and g(x) = 3X - 2
when x = 3

Answers

Answer:

13

Step-by-step explanation:

→ Substitute 3 into 2x

2 × 3

→ Evaluate

f ( x ) = 6

→ Substitute x = 3 into 3x - 2

3 × 3 - 2

→ Evaluate

7

→ Find the sum of the 2 results

13

When x = 3, the value of (f + g)(x) is 13.

To evaluate (f + g)(x) when f(x) = 2x and g(x) = 3x - 2, we substitute the given functions into the expression (f + g)(x).

(f + g)(x) = f(x) + g(x)

Substituting the given functions:

(f + g)(x) = 2x + (3x - 2)

Simplifying the expression:

(f + g)(x) = 2x + 3x - 2

Combining like terms:

(f + g)(x) = 5x - 2

Now, to find the value of (f + g)(x) when x = 3, we substitute x = 3 into the expression:

(f + g)(3) = 5(3) - 2

Simplifying further:

(f + g)(3) = 15 - 2

(f + g)(3) = 13

Therefore, when x = 3, the value of (f + g)(x) is 13.

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Find the slope of the line passing through the points (-4,-4) and (2, 5).

Answers

Answer:

the slope of the line passing through the points (-4,-4) and (2, 5) m=3/2.

Step-by-step explanation:

Hello!

To find the slope between two points use the formula

m=(y-y)/(x-x)... substitute valuesm=(5-(-4))/(2-(-4))m=9/6m=3/2

what is Z in the rhombus?​

Answers

Answer: 27°

Step-by-step explanation:

The easiest way to find the measure of angle Z is to know that in a rhombus, the diagonals are perpendicular bisectors of each other. This means that all the four angles in the center are 90°.

Since we know that all angles in a triangle add up to 180°, we can set the sum of z, 63, and 90 to be 180 and solve for z.

[tex]z+63+90=180\\z+153=180\\z=27[/tex]

Hence, z is 27°.

The mean of a normally distributed data set is 110, and the standard deviation is 15.

a) Use the Empirical Rule to find the probability that a randomly-selected data value is greater than 95.

b) Use the Empirical Rule to find the probability that a randomly-selected data value is greater than 125.

Answers

Step-by-step explanation:

68% of all values are within 1 SD (110 ± 15).

95% of all values are within 2SD (110 ± 2×15 = 30)

99.7% of all values are within 3 SD (110 ± 3×15 = 45)

a)

95 is 110 - 15, so exactly 1 SD apart from the mean value.

68% or 0.68 is the probability of all values between 95 and 125.

so, 34% or 0.34 is the probability of all values between 95 and 110. and 50% or 0.5 is the probability of all values larger than 110.

so, the probability of all values larger than 95 is

0.34 + 0.5 = 0.84

b)

125 is 110 + 15, so exactly 1 SD apart from the mean value.

so, as per a) 34% or 0.34 is the probability of all values between 110 and 125. and 50% or 0.5 is the probability of all values larger than 110.

so, the probability of all values larger than 125 is

0.5 - 0.34 = 0.16

The first five terms of a quadratic sequence are 3, 12, 25, 42, 63.
Find the nth term of this sequence.

Answers

Since we know the sequence is quadratic, we expect the [tex]n[/tex]-th term to have the general form

[tex]x_n = an^2 + bn + c[/tex]

Plug in the first 3 known values of the sequence to form a system of equations.

[tex]x_1 = 3 = a + b + c[/tex]

[tex]x_2 = 12 = 4a + 2b + c[/tex]

[tex]x_3 = 25 = 9a + 3b + c[/tex]

Eliminating [tex]c[/tex] gives

[tex](4a + 2b + c) - (a + b + c) = 12 - 3 \implies 3a + b = 9[/tex]

[tex](9a + 3b + c) - (a + b + c) = 25 - 3 \implies 8a + 2b = 22 \implies 4a + b = 11[/tex]

Eliminating [tex]b[/tex] gives

[tex](4a + b) - (3a + b) = 11 - 9 \implies a = 2[/tex]

Solving for [tex]b,c[/tex], we get

[tex]4a + b = 11 \implies b = 11-4\cdot2 = 3[/tex]

[tex]a+b+c=3 \implies c=3-2-3 = -2[/tex]

So, the [tex]n[/tex]-th term of the sequence is

[tex]x_n = \boxed{2n^2 + 3n - 2}[/tex]

What is the length of the apothem of the regular pentagon shown below? Round to one decimal place

Answers

The length of the apothem of the regular pentagon shown is 5.2 meters

How to determine the length of the apothem?

Represent the central angle of the regular pentagon using x

The value of the central angle of the regular pentagon is then calculated as:

x = 360/n

Where n represents the number of sides

i.e n = 5

So, we have:

x = 360/5

Evaluate the quotient

x = 72

Represents the apothem with y.

The apothem is then calculated as:

tan(x/2) = (Side length/2)/Apothem

This gives

tan(72/2) = (7.6/2)/y

Evaluate the quotient

tan(36) =3.8/y

Multiply both sides by y

y tan(36) = 3.8

Divide both sides by tan(36)

y = 3.8/tan(36)

Evaluate the quotient

y = 5.2

Hence, the length of the apothem of the regular pentagon shown is 5.2 meters

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sinx + siny=a
cosx + cosy=b
Find cos(x+y/2)

Answers

Using the addition rule of the Sine function and the Cosine function, we obtain [tex]\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}[/tex].

What are the formulas for (sin x + sin y) and (cos x + cos y)?The formula for the addition of two Sine functions ([tex]\sin x+\sin y[/tex]) is [tex]\sin x + \sin y = 2\sin\frac{x+y}{2}\cos\frac{x-y}{2}[/tex].The formula for the addition of two Cosine functions ([tex]\cos x+\cos y[/tex]) is [tex]\cos x + \cos y = 2\cos\frac{x+y}{2}\cos\frac{x-y}{2}[/tex].

Given that

[tex]\sin x + \sin y = a\\\cos x + \cos y = b[/tex]

Then using the above formulas, we get:

[tex]2\sin\frac{x+y}{2}\cos\frac{x-y}{2}=a[/tex]       (1)

[tex]2\cos\frac{x+y}{2}\cos\frac{x-y}{2}=b[/tex]       (2)

Dividing the equation (1) by (2), we get:

[tex]\dfrac{\sin\dfrac{x+y}{2}}{\cos\frac{x-y}{2}}=\dfrac{a}{b}\\\Longrightarrow \tan\dfrac{x+y}{2}=\dfrac{a}{b}[/tex]             (3)

Now, we know that  [tex]\cos\theta=\dfrac{1}{\sqrt{1+\tan^2\theta}}[/tex].

Thus, using the above formula, we get from (3):

[tex]\cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\tan^2\dfrac{x+y}{2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{1}{\sqrt{1+\dfrac{a^2}{b^2}}}\\\Longrightarrow \cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}[/tex]

Therefore, using the addition rule of the Sine function and the Cosine function, we obtain [tex]\cos\dfrac{x+y}{2}=\dfrac{b}{\sqrt{a^2+b^2}}[/tex].

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KI's net income for 2021 is _____.

a.
$188.2 million

b.
$118.5 million

c.
$149.3 million

d.
$162.8 million

Answers

The answer is d but I don’t for sure it might be a or c or b

Can someone please please help me

Answers

Answer:

  order: 2, 3, 1

Step-by-step explanation:

Reasonableness checks and your knowledge of integers and fractions will help you solve this. The offered questions are intended to help you think this through.

a.

For an output of -31, the machine (x -2)² cannot possibly be last. Its output can only be positive.

  machine 2, (x-2)², cannot be last

Also, machine 3 cannot be last. For the output to be -31, the input to machine 3 must be -1/31. Neither of the other machines can produce a fraction with the inputs they might receive.

b.

For an input of x=0, the machine 1/x cannot possibly be first. 1/0 is undefined.

The other two machines will give the following outputs for an input of 0:

  machine 1: 4(0) -32 = -32

  machine 2: (0 -2)² = 4

It is unlikely that machine 1 will be first, because the other two machines cannot do anything useful with -32 as an input.

  machine 3, 1/x, cannot be first

c.

The reasoning of part (a) tells you the last machine must be machine 1. The reasoning of part (b) tells you the first machine cannot be 3, so must be 2. The order of the machines must be ...

machine 2: (0 -2)² = 4 . . . . . . . using an input of 0machine 3: 1/4 = 1/4machine 1: 4(1/4) -32 = -31 . . . . desired output

What is ZT?
a. 7
b. 14
c. 28
d. 29

Answers

Answer:

B

Step-by-step explanation:

• the opposite sides of a parallelogram are congruent , then

ZY = WX , that is

5x - 6 = 4x + 1 ( subtract 4x from both sides )

x - 6 = 1 ( add 6 to both sides )

x = 7

• the diagonals bisect each other , then

ZT = TX = 2x = 2 × 7 = 14

Attached as picture. Please read fully

Answers

a. The velocity t = [tex]v = Ce_{n} (\frac{mo}{mo - kt} ) - gt[/tex]

b. v60 = 7164

How to solve for the velocity

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = [tex](\frac{ck}{Mo-Kt} -g)dv[/tex]

Integrate the two sides of the equation to get

v [tex]-\frac{ck}{k} e_{n} (Mo- kt)-gt+c[/tex]

[tex]v = Ce_{n} (\frac{mo}{mo - kt} ) - gt[/tex]

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

Complete question

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

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Hi,

Could anyone help with this please?

Many thanks,

Answers

Length: 2.6 meters

Width: 1.8 meters

Area: 4.68 meters

Since the scale is 1/40, we can multiply the centimeter measurements by 40 thus making it our scale factor.

Length

2.6 x 40 = 260

260 cm = 2.6 m

Width

4.5 x 40 = 180

180 cm= 1.8 m

Area

1.8 x 2.6 = 4.68 m

Length: 2.6 meters

Width: 1.8 meters

Area: 4.68 meters

graph the solution to the system of inequalities in the coordinate plane 3y>2x+122+y<-5

Answers

The graph is shown in the attached image.

Using the graph as your guide, complete the following statement.
The discriminant of the function is

Answers

Because the parabola intercepts the x-axis only once, we conclude that the discriminant is 0.

What can we say about the discriminant?

For a quadratic equation:

y = a*x^2 + b*x + c

The discriminant is:

D = b^2 - 4ac

If D = 0, there is only one real zero.If D > 0, there are two real zeros.If D < 0, there are two complex zeros.

In the graph we can see that the parabola intercepts the x-axis in its vertex, then the parabola has only one real zero, then we conclude that the discriminant is equal to zero.

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About 5% of the population has a particular genetic mutation. 300 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 300. Round your answer to two decimal places.

Answers

If the sample size is 300 and about 5% of the population has a particular genetic mutation then the standard deviation for the number of people with the genetic mutation in such groups of 300 is 3.77.

Given sample size be 300 and about 5% of the population has a particular genetic mutation.

We are required to find the standard deviation for the number of people with the genetic mutation in groups of 300.

Sample size=300

The standard deviation for the number of people with the genetic mutation is calculated as:

Standard deviation=[tex]\sqrt{np(1-p)}[/tex]

Use the known values in the above formula.

Standard deviation=[tex]\sqrt{300*0.05(1-0.05)}[/tex]

=[tex]\sqrt{14.25}[/tex]

=3.77

Hence if the sample size is 300 and about 5% of the population has a particular genetic mutation then the standard deviation for the number of people with the genetic mutation in such groups of 300 is 3.77.

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Grandma is making her grandson french toast. The pan can only fit two pieces of bread at a time. To cook each side of the bread it takes one minute( you have to cook both sides). Grandma made three slices of french toast in three minutes, how was she able to do this

Answers

Grandma should be able to make three slices of French toast by slicing one of the original slices into two.

How can grandma make three slices of French toast?Put two slices of bread in the pan and cook them for one minute (first minute)Turn both slices over and cook ( second minute)Remove both slices and slice one of this into two. This will mean the new slices will have one side cooked and another one that is not cooked.Cook these thinner slices  (third minute).The result would be three cooked slices, although two of them would be thinner.

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Solve rs + t = u for the variable s

Answers

Answer:

[tex]s=\frac{u}{r} -\frac{t}{r}[/tex]

Step-by-step explanation:

You have to move the variables (r and t) with u to isolate s.

[tex]rs+t=u[/tex]

   [tex]-t[/tex]       [tex]-t[/tex]

------------------------

[tex]rs=u-t[/tex]

÷ [tex]r[/tex]       ÷ [tex]r[/tex]

------------------------

[tex]s=\frac{u}{r} -\frac{t}{r}[/tex]

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