(1) If the ship moves upward with a constant velocity, the period increases, false.
(2) If the length of the pendulum is doubled, the new period will be: square root of 2 times T₀. true.
(3) If the ship accelerates upward, the period increases, true.
(4) If the ship accelerates downward at 9.81 m/s² , the pendulum will no longer oscillate, false.
(5) If the mass of the pendulum is halved, the period decreases, false.
Period of a simple pendulum
The period of a simple pendulum is given as;
T = 2π√(L/g) ------- (1)
where;
L is length of the pendulumg is acceleration due to gravityWhen the ship moves upward with a constant velocity, the period will not change.
When the length of the pendulum is doubledT ∝√L
when, L = 2L₀
T = T₀√2
Thus, if the length of the pendulum is doubled, the new period will be: square root of 2 times T₀.
when ship accelerates upwardt = √2h/g
when the height increases, time or period increaseswhen mass of the pendulum is halvedT = √I/mgd
where;
m is mass of the pendulumwhen the mass is halved, the period increases.
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Solve this question please A.S.A.P ⁉️
No spamming ❗
Answer:
Here given is :-Velocity (u) = 10m/sGravity (g) = 10 m/s²Height (h) = ?Explanation:
v² - u² = 2gh0² - 10² = 2 × (-10) × h-100 = -20 h[tex]h = \frac{ - 100}{ - 20} = 5m[/tex]V = u + gt0 = 10 - 10t10t = 10[tex]t = \frac{10}{10} = 1 \: sec[/tex]Total time = 2 secAnswer:
See below
Explanation:
vf = vo + at when it reaches top vf = 0 vo = 10m/s a = -9.81 m/s^2
0 = 10 + (-9.81) t
t = 1.02 seconds to reach max
time up = time down so roundtrip = 2.04 seconds
what does personal mission statement?
Answer:
A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.
Explanation:
It explains how you aim to pursue that purpose, and why it matters so much to you.
Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).
The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.
Force necessary to support the objectApply Pascal principle to calculated the force needed to support the mass as shown below;
F₁/A₁ = F₂/A₂
F₁/d₁² = F₂/d₂²
F₁ = F₂d₁²/d₂²
where;
F₂ is the force on piston 2, determined from, F = mgd₂ is the diameter of piston 2, given as 9.46 cmd₁ is diameter of piston 1, given as 1.87 cmF₁ is force on piston 1 = ?Substitute the given parameters and solve for the force needed to support the mass given.
F₁ = (991 x 9.8 x 0.0187²)/(0.0946)²
F₁ = 379.5 N
Thus, the force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.
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a guage is connected to tank in which the pressure of the fluid is 305kpa above atmospheric. if the absolute presssure of the fluid remains unchanged but the gage is in chamber where the air pressure is reduce to a vaccum of 648mmHg what reading in psi will then be observed
The pressure reading in psi observed after the gauge is placed in the chamber with a vacuum of 648 mmHg will be approximately 31.67 psi.
When the gauge is placed in a chamber with a vacuum of 648 mmHg we need to convert the pressure reading to a compatible unit to determine the pressure measurement in PSI.
First, convert the initial pressure of the fluid from kPa to mmHg.
7.5 mmHg is equal to about 1 kPa. So, 305 kPa * 7.5 mmHg/kPa = 2287.5 mmHg is the initial pressure of the fluid in mmHg.
Reducing the original pressure by vacuum pressure.
1639.5 mmHg = new pressure = 2287.5 mmHg - 648 mmHg
Converting the mmHg of the new pressure to the psi unit.
0.01934 psi is equal to approximately 1 mmHg. As a result, the new pressure in psi is equal to 31.67 psi: 1639.5 mmHg * 0.01934 psi/mmHg
Therefore, the pressure reading in psi observed after the gauge is placed in the chamber with a vacuum of 648 mmHg will be approximately 31.67 psi.
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You are writing a short report to a familiar audience and plan to use an informal
writing style. What can you do to make your writing informal?
Use contractions such as won't, it's, let's, and we're.
Include second-person pronouns such as you.
Use passive-voice verbs.
Incorporate longer sentences.
The thing that the presenter can do to make the presentation to appear informal is to use contractions such as won't, it's, let's, and we're.
What is a report?The term report refers to any formal presentation. It is usually made as part of an academic course or as part of professional development. It could be given while a person is hoping for promotion at a job that he or she is doing.
We have to bear in mind that the audience to whom the report is being presented is a familiar audience hence the presentation can be quite informal and devoid of the formality of presentation of reports as we know it to be.
Now, the focus is to make the presentation to look informal. The thing that the presenter can do to make the presentation to appear informal is to use contractions such as won't, it's, let's, and we're.
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At the top of a hill a roller coaster has gravitational potential energy due to its position. What happend to this potential energy as the roller coaster speeds up on the way down the hill?
As the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy is neither created nor destroy, they can only be transformed from one form to another. Energy of and object can transform from Potential energy to kinetic energy and vice versa
Given that at the top of a hill a roller coaster has gravitational potential energy due to its position. What will happen to this potential energy as the roller coaster speeds up on the way down the hill is that the potential energy to the roller coaster will start decreasing while the kinetic energy will start to increase.
The total energy of the roller coaster will be constant because of conservation of energy. As the roller coaster speeds up on the way down the hill, the potential energy will eventually reduce to zero where the total energy of the as the roller coaster will be equal to maximum kinetic energy.
Therefore, as the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
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A converging lens with a focal length of 4.0 cm is to the left of a second identical lens. When a feather is placed 12 cm to the left of the first lens, the final image is the same size and orientation as the feather itself. What is the separation between the lenses?
The distance of separation between the lenses is determined as 12 cm.
Distance of image formed by the first lens
The distance of the image formed by the first lens is calculated as follows;
1/d₁ = 1/f - 1/di₀
1/di₁ = 1/4 - 1/12
1/di₁ = 2/12
1/di₁ = 1/6
di₁ = 6 cm
Find the final position of the imageUse magnification formula as shown below;
M = (di₁di₂)/(d₀₁d₀₂)
1 = (di₁di₂)/(d₀₁d₀₂)
di₂ = (d₀₁d₀₂)/(di₁)
di₂ = (12 x d₀₂)/(6)
di₂ = 2d₀₂
1/f = 1/ d₀₂ + 1/di₂
1/f = 1/ d₀₂ + 1/2d₀₂
1/f = 1.5/d₀₂
d₀₂ = 1.5f
d₀₂ = 1.5(4 cm) = 6 cm
Distance between the two converging lensD = di₁ + d₀₂
D = 6 cm + 6 cm
D = 12 cm
Thus, the distance of separation between the lenses is determined as 12 cm.
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ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A. If the acceleration of the system is 5.88m/s2, what is the Tension T on Box A?
The tension on box A is 117.6 N
What is Equilibrium of Forces ?Equilibrium is a state of an object with respect to a given observable quantity during the time for which there is no change in that quantity.
A body is said to be in equilibrium when:
the body as a whole either remains at rest or moves in a straight line with constant speed.the body is either not rotating at all or is rotating at a constant angular velocity.Given that box A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A.
The tension in the rope will be the same.
Given that Box A is placed on a horizontal surface that is frictionless, that is,
T = ma .... (1)
Also, Box B is hanging from a pulley by a rope connected to Box A. That is,
W - T = ma ...... (2)
Where W = mg
Since the acceleration of the system is 5.88m/s² which will be the same for the two equations, then the Tension T on Box A can be calculated by substituting acceleration and mass into equation (1)
T = 20 x 5.88
T = 117.6 N
Therefore, the tension on box A is 117.6 N
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What phase of matter is pictured below? Image of particles that are spread out, many are not touching, high energy. A. Gas B. Bose-Einstein condensate C. Fermionic condensate D. Plasma
Option(d)i.e, Plasma is the Image of particles that are spread out, many are not touching, high energy.
Along with solid, liquid, and gas, plasma is frequently referred to as the "fourth state of matter." Heating a gas will result in the formation of plasma, which is a soup of positively and negatively charged particles (ions), similar to how adding energy causes a liquid to boil and transform into a gas (electrons).
Plasmas are less dense than solids or liquids and, like gases, have no set structure or volume. However, in contrast to regular gases, plasmas are composed of atoms in which part or all of the electrons have been removed and positively charged nuclei, known as ions, are free to move around.
Solids, liquids, gases, ionized plasma, quark-gluon plasma, bose-einstein condensate, and fermionic condensate are the seven states of matter.
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h) Find the inverse Laplace transforms of the equation. When the X(s) =1 /(s²+9s+20)
Answer:
e^-4t e^-5t
Explanation:
solving s²+9s+20 quadratically we have (s+4)(s+5)
x(s) can be written as x(s) =(1/s+4)(1/s+5)
if we take the laplace inversve
L-¹ (s)=L-1(1/s+4) L-1(1/s+5)
we have e^-4t e^-5t
the earth orbits is oval in shape.explain how the mangnitude of gravitational between the earth and sun changes as the eart moves from position a to b
As the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.
What is gravitational force?
Gravitational force is a force that attracts any two objects with mass.
According to Newton's law of universal gravitation, the force of attraction between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.
F = Gm₁m₂/R²
where;
m₁ is mass of Earthm₂ is mass of sunR is the distance between the Earth and SunThus, as the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.
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what the answer???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Only using dimensional analysis, answer the following question:
Convert 65 miles per hour to kilometers per second. Show your work and explain how you got it please!
Brainliest goes to most detailed response
Answer:
[tex]2.9055\times 10^-2 km/s \approx 0.03 km/s[/tex]
Explanation:
One (statute) mile is defined as [tex]1\ 609.344 m = 1.609\ 334 km[/tex] or, cutting the last significant digits, [tex]1.6 km[/tex]. An annoying European would drop some kind of remark here like "but what about nautical miles?", but let's assume it's a statute mile.
One hour is 3600 seconds (60 minutes in a hour, times 60 seconds in a minute), no complains across the pond here.
Now we're ready to crunch numbers.
[tex]65\frac{mi}h = 65\frac{1.6km}{3600s} \approx 0.03 \frac {km}s[/tex]
You can use the exact definition of mile and you will get the exact value of [tex]0.029055 \frac{km}s = 2.9055\times10^-^2 km/s[/tex] with an error of about a meter.
Answer:
See below
Explanation:
Since you want detailed dimensional analysis here is a lot of details:
mile / hr / (60 min / hr * 60 sec / min) * 1760 yds/mile * 36 in/yd * 1m /39.37 in * 1 km / 1000 m
After cancelling everything out (dimensional analysis) , you are left with:
= mile/ hr * 1/3600 * 1760 * 36 /39.37 * 1/1000
= mile /hr * .00044704089 km -hr/ sec-mile = km/s
the underlined portion is the conversion factor for miles/hr to km/s
65 * .00044704089 = .029057 km / sec
Assume that a car with a full tank of gasoline is closed system. Which two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same? The car's engine makes sounds as it runs. The car's engine gets hot as it burns gasoline. The car remains full of gasoline if its engine stays off. The car uses more gasoline as it goes faster.
The two evidence are the car's engine gets hot as it burns gasoline are the car remains full of gasoline if its engine stays off.
Which two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same?The car's engine gets hot as it burns gasoline and the car remains full of gasoline if its engine stays off are the two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same because when the gasoline burns, the engine gets hotter and when the car remains full of gasoline if its engine stays off which means no energy leaves the system.
So we can conclude that The two evidence are the car's engine gets hot as it burns gasoline are the car remains full of gasoline if its engine stays off.
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Why do batteries discharge more quickly in cold weather?
give me answer
who will give me answer in easy language i will give him 5 star ⭐⭐⭐
Answer:
lowering the ambient temperature causes chemical reaction to proceed more slowly,so a battery used in a low temperature produces less current than that at high temperature . As cold batteries run down they quickly reach the point where they cannot deliver enough current to keep up the demand.. hence discharge more quickly in cold weather..
How does the suns energy affect the climate of an area
There wouldn't be any life on Earth and no climate if it weren't for the Sun.
The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.
The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.
Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.
In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.
Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).
Thank you,
Eddie
A cell connected to two bulbs in series lasts longer than a cell connected to the same bulbs in parallel.Explain why?
Because the voltage stays the same while the amps grow, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps quadruple to 100ah, the batteries will last longer. Charges are spread among the bulbs in a parallel circuit because they are flowing in several directions over multiple paths. As a result, each bulb will have less charge since the charge is travelling in multiple directions, and the lights will shine less brightly. On the other hand, in a series circuit, there is only one channel and only one location for the charge to travel, meaning that all of the charge is directed at a single lightbulb. As a result, the lightbulb will shine more brilliantly since there is no need to spread the energy. The rule of conservation of energy is not broken because of the difference in power; instead, smaller resistance causes bigger current, which results in brighter lights. The energy traveling from the source to the bulbs remains constant. Because higher power means that more energy in a given time goes quicker from the source to the bulb, brighter lights require more power rather than energy. Because the energy traveling from the source to the bulbs remains constant, the rule of conservation of energy is not being broken; rather, there is merely a difference in power as a result of smaller resistance leading to bigger current, which will result in brighter lights. This means that brighter lights require more power rather than energy since higher power enables more energy to go from the source to the bulb more quickly.
Thank you,
Eddie
Most towns use a water tower to store water and provide pressure in the pipes that deliver water to customers. The figure below shows a spherical water tank that holds 5.80 105 kg of water when full. Note that the tank is vented to the atmosphere at the top and that the pipe delivering water to customer Smith is a height h = 3.75 m above the level of the pipe delivering water to customer Jones. Determine the gauge pressure of the water at the faucet of each house when the tank if full.
There is a spherical water-filled chamber with a vent on top and underneath it is a pipe 18 m long that leads down to the ground. At ground level a horizontal pipe connects the faucet in the Jones house to the water supply. The faucet in the Smith house is connected to the water supply with a pipe at a height h above ground level.
(a) Jones house
Pa
(b) Smith house
Pa
The effective height of the water for Smith's house will be 24.61m.
How to calculate the height?Based on the information given, the volume of the water in sphere will be:
= 4/3πr³ = (5.80 × 10^5)/1000
= 4.18r³ = 580
r³ = 138.7
r = 5.18m
The effective height of the water will be:
= 18.0 + 2(5.18)
= 28.36
The gauge pressure at Faucet of Jones house will be:
= pgh
= 1000(9.8)(28.36)
= 277.9kPa
The effective height of the water for Smith's house will be:
= 18.0 + 2(5.18) - 3.75
= 24.61m
The gauge pressure at Faucet of Jones house will be:
= 1000 × 9.8 × 24.61
= 241.2kPa
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The amplitude of a standing sound wave in a long pipe closed at the left end is sketched below.
1. The vertical axis is the maximum displacement of the air, and the horizontal axis is along the length of the pipe. What is the harmonic number for the mode of oscillation illustrated?
2. The length of the pipe is 0.440 m. What is the pitch (frequency) of the sound? Use 340 m/s for the speed of sound in air.
3. The pipe is now held vertically, and a small amount of water is poured inside the pipe. The first harmonic frequency is then measured to be 251.1 Hz. Measuring from the bottom of the pipe, what is the level of the water?
(1) The harmonic number for the mode of oscillation is 3.
(2) The pitch (frequency) of the sound is 579.55 Hz
(3) The level of the water inside the vertical pipe is 0.1 m.
The harmonic number
The harmonic number for the mode of oscillation illustrated for the closed pipe is 3.
Frequency of the waveThe pitch (frequency) of the sound is calculated from third harmonic formula;
f = 3v/4L
where;
v is speed of soundL is length of the pipef = (3 x 340) / (4 x 0.44)
f = 579.55 Hz
level of the waterwave equation for first harmonic of a closed pipe is given as
f = v/(4L)
251.1 = 340/(4L)
4L = 340/251.1
4L = 1.35
L = 1.35/4
L = 0.34 m
level of water = 0.44 m - 0.34 m = 0.1 m
Thus, the level of the water inside the vertical pipe is 0.1 m.
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A container with 3 kg of pure water at a temperature of 12 degrees Celsius is placed in a refrigerator where the air temperature is kept at 4 degrees Celsius. how much heat (in joules) is gained by the air when the water cools to 4 degrees Celsius?
Answer:
100 368 J
Explanation:
Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)
specific heat for water ( in joules) : 4182 J / kg-C
3 kg * 4182 J / kg-C * (12-4 C) = 100 368 J
the highest theoretical efficiency of a certain engine is 30% if the engine uses the atmosphere which has a temperature of 300k as its cold reservoir what is temperature of its hot reservoir
The temperature of its hot reservoir would be = 210k
Calculation of reservoir temperatureThe highest theoretical engine efficiency (η)= 30% =0.3
The temperature of the engine cold reservoir (T1)= 300k
Therefore the temperature of the engine hot reservoir (T2) = ?
Using this formula:
η=1- T2/T1
Make T2 the subject formula:
T2= T1 (1 - η)
T2 = 300 ( 1-0.3)
T2 = 300 × 0.7
T2 = 210k
Therefore, the temperature of its hot reservoir would be = 210K.
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Find the center of mass of the three-mass system shown in the figure relative to the mass m = 1.03 kg . (Figure 1)
Express your answer to two significant figures and include the appropriate units.
The center of mass of the three-mass system is 0.433m.
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. In a collection of unconnected items, the center of mass can also be established.
Given:Mass of the object, m₁ = 1.03kg
Mass of the object, m₂= 1.50kg
Mass of the object, m₃= 1.10
Taking the location of m as the origin and towards right as positive X-axis.
x₁=0
x₂=0.50m
x₃=0.25+0.50 = 0.75m
The X-coordinate of the center of mass [tex]x_c[/tex] of a system of three masses m₁, m₂ and m₃ located at the positions x₁, x₂ and x₃ on X-axis is given by,
[tex]x_c=\frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}[/tex]
[tex]x_c=\frac{0+1.50*0.50+1.10*0.75}{1.03+1.50+1.10}\\x_c= 0.433 m[/tex]
Therefore, the center of mass of the three-mass system is 0.433m.
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Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).
The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 373.8 N.
What is the force required to support the weight on piston 2?The force, F required to support the weight on piston 2 is calculated as follows:
F = F₂ * A₁/A₂f = 991 * 9.81 = 9721.71 N
A₂ = (9.46/2)² = 22.373
A₁ = (1.87/2)² = 0.874
F = 9721.71 * 0.874/22.373
F = 373.8 N
Inc conclusion, a smaller force is applied to lift the larger force at Piston 2.
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a simle arrangement by means of which emf are compared is known as
A simple arrangement by means of which EMF are compared is known as a voltmeter.
Discussion about Voltmeter :
A voltmeter is a straightforward device used to compare electromagnetic fields.When there is no current flowing through a cell, its terminal voltage equals its electromotive force (emf). The difference in potential between a cell's electrodes is what determines its terminal voltage. Since voltmeters use the cell's current to draw voltage, they are unable to measure a cell's emf.Using a voltmeter, one may determine the voltage generated in an electric circuit. Volts are the emf's SI unit (V). Volts are the voltage's SI unit (V). Non-coulomb force, also known as non-electric force operation, defines emf.Learn more about voltmeter here:
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how to calculate the half time
The formular for calculating half life is:
T1/2=0.693/Π
Let's begin with a simple calculation of the weight of air using density. Find the mass of air and its weight in a living room that has a 4.3m×5.4m floor and a ceiling 2.9 m high. What are the mass and weight of an equal volume of water?
a. What volume of water would have a mass equal to the mass of air in the room?
1. The mass of the air, given the data is 85.88 Kg
2. The weight of the air is 841.624 N
3. The mass of an equal volume of water is 67338 Kg
4. The weight of an equal volume of water is 659912.4 Kg
5. The volume of water that would have a mass equal to the mass of air in the room is 8.588×10⁻² m³
How to determine the volume of the airWe shall determine the volume of the air in the room by finding the volume of the room.
Volume of air = volume of room
Volume of air = 4.3 × 5.4 × 2.9
Volume of air = 67.338 m³
1. How to determine the mass of the airVolume of air = 67.338 m³Density of air = 1.2754 kg/m³Mass of air = ?Density = mass / volume
Cross multiply
Mass = Density × volume
Mass of air = 1.2754 × 67.338
Mass of air = 85.88 Kg
2. How to determine the weight of the airMass of air (m) = 85.88 KgAcceleration due to gravity (g) = 9.8 m/s²Weight of air (W) = ?W = mg
W = 85.88 × 9.8
Weight of air = 841.624 N
3. How to determine the mass of equal volume of waterVolume of air = 67.338 m³Volume of water = Volume of air = 67.338 m³Density of water = 1000 kg/m³Mass of water = ?Density = mass / volume
Cross multiply
Mass = Density × volume
Mass of water = 1000 × 67.338
Mass of water = 67338 Kg
4. How to determine the weight of equal volume of waterMass of water = 67338 KgAcceleration due to gravity (g) = 9.8 m/s²Weight of water (W) = ?W = mg
W = 67338 × 9.8
Weight of air = 659912.4 Kg
5. How to determine the volume of water with equal mass of air Mass of air = 85.88 KgMass of water = Mass of air = 85.88 KgDensity of water = 1000 kg/m³Volume of water = ?Volume = mass / density
Volume of water = 85.88 / 1000
Volume of water = 8.588×10⁻² m³
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If the internal energy of a system is decreased, which of the following is impossible?
a
Work done by the system is larger than heat
released.
b
Work done on the system is smaller than
heat released.
C
Work done by the system is larger than heat
absorbed.
d
Work done on the system is smaller than
heat absorbed.
Work done on the system is smaller than heat absorbed.
What happens when internal energy decreases?A cell's internal energy drops when it does work or expels heat. There won't be a net change in internal energy if the work performed by a cell matches the energy transferred in by heat or if the work performed on a cell matches the energy transported out by the heat.The energy within remains constant. The ideal gas law states that the temperature decreases according to the volume when a gas is compressed while maintaining a constant pressure. In this instance, more energy is lost as heat from the system is gained through work. Internal energy levels drop.Ideal gases' internal energy and enthalpy depend solely on temperature; neither volume nor pressure play a role. Using property relations, we may demonstrate these characteristics of ideal gases.
If the internal energy of a system is decreased, which of the following is impossible:
C) Work done on the system is smaller than heat absorbed.
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Your car rides on springs, so it will have a natural frequency of oscillation. (Figure 1) shows data for the amplitude of motion of a car driven at different frequencies. The car is driven at 29 mph over a washboard road with bumps spaced 12 feet apart; the resulting ride is quite bouncy.
1)Determine the frequency of the oscillation, caused by the bumps. 1 mile is 5280 feet.
2)Should the driver speed up or slow down for a smoother ride?
Answer:
See below
Explanation:
29 mile/hr * 5280 f/mile / 3600 s/hr = 42.53 ft/ sec
42.53 ft / sec / 12 feet = 3.54 cycles / sec = 3.54 Hz
for frequency I suppose....where is the referred to figure?
QUESTION 1 (a) State the seven (7) fundamental S.I units.
Hello and Good Morning/Afternoon:
What makes a unit a fundamental SI unit:
They are units determined to have played an essential role in today's world specifically in the technological and scientific communityThus the seven fundamental S.I. units are:
meters (m) ⇒ is the unit for the length of somethingseconds (s) ⇒ is the unit for time mol (mol) ⇒ is the base unit of the amount of a substanceampere (A) ⇒ is the base unit of electrical currentsKelvin (K) ⇒ is the unit for temperatureCandela (cd) ⇒ is the base unit for luminosity intensityKilograms (kg) ⇒ is the unit for weightHope that helps!
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4. Four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m, a 3.00kg object is at +2.50m, a 2.50kg object is at the origin, and a 4.00kg object is at -0.500m. Where is the center of mass of these objects?
Answer: 1.348 meters
Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point c . Adding the four moments together, we get:
(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0
6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0
11.5c=15.50
c= 1.348 metres
The center of mass is on the y axis at y = 1.348 metres.
A ball of mass 0.200 kg has a velocity of 150m/s; a ball of mass 0.300 kg has a velocity of - 0.4m/s. They meet in a head-on elastic collision. (a) Find their velocities after the collision. (b) Find the velocity of their center of mass before and after the collision.
(a) The velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.
(b) The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.
Velocity of the balls after collision
Apply the principle of conservation of linear momentum to determine the velocity of the balls;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.2(150) + (0.3)(-0.4) = 0.2v₁ + 0.3v₂
29.88 = 0.2v₁ + 0.3v₂
Apply one directional linear velocity
u₁ + v₁ = u₂ + v₂
v₁ = u₂ + v₂ - u₁
v₁ = -0.4 + v₂ - 150
v₁ = v₂ - 150.4
Substitute the value of v₁ into the first equation;
29.88 = 0.2(v₂ - 150.4) + 0.3v₂
29.88 = 0.2v₂ - 30.08 + 0.3v₂
59.96 = 0.5v₂
v₂ = 59.96/0.5
v₂ = 119.92 m/s
v₁ = 119.92 - 150.4
v₁ = -30.48 m/s
Velocity of their center mass before collisionV(cm) = (0.2 x 150 + 0.3 x 0.4) / (0.2 + 0.3)
V(cm) = 60.24 m/s
Velocity of their center mass after collisionV(cm) = (0.2 x 30.48 + 0.3 x 119.92) / (0.2 + 0.3)
V(cm) = 84.14 m/s
Thus, the velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.
The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.
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