A salt solution contains ammonium cation (ka = 5.7 × 10^–10) and nitrite anion (kb = 1.4 × 10^–11) in equal proportions. The ph of the solution will be?

The correct option is (c) 101.55.

What is copper fluoride used for?

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The IUPAC names of the given compounds are 3-methylpentane, 1,3-butadiene, 1,3-dimethylcyclohexane, 2,3,5,5-tetramethyl-1,3-hexadiene, and 2,2-dimethylpentane respectively.

Thus, following the IUPAC nomenclature rules the name of the given compounds are as follows:

3-methylpentane

1,3-butadiene

1,3-dimethylcyclohexane

2,3,5,5-tetramethyl-1,3-hexadiene

and 2,2-dimethylpentane

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The 2.5 x 10²¹ molecules of CH₃OH have 0.00415 moles.

The number of moles is given by

[tex]n=\frac{m}{M}[/tex]

When given mass = molar mass of a substance, then no of moles is equal to 1 which is equivalent to 6.022 x 10²³.

We also know,

1 mole has 6.022 x 10²³ molecules of CH₃OH

According to the mole concept,

6.022 x 10²³ molecules of CH₃OH is equal to 1 mole

2.5 x 10²¹molecules of CH₃OH is equal to [tex]\frac{2.5\times10^2^1}{6.022 \times 10^2^3}[/tex] moles

Thus, 2.5 x 10²¹molecules of CH₃OH are equal to 4.15 x 10⁻³ moles or 0.00415 moles

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The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

It is expressed as:

pH = pKa + log([A-]/[HA].

where,

[A-] is molar concentration of conjugate base and

[HA] is molar concentration of weak acid.

Given,

pH = 5.30

Substitute the value in the Henderson Hasselbalch equation

5.30 = 4.874 + log[A-]/ [HA]

log[A-]/[HA] = 5.30 - 4.874

[A-]/[HA] = 10^ 0.426

[A-]/[HA] = 2.7

Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

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Answer:

Alkanes

Explanation:

Alkanes are hydrocarbons containing only single bonds between the parent chain carbons.

Alkenes are hydrocarbons containing at least one double bond between the parent chain carbons.

Alkynes are hydrocarbons containing at least one triple bond between the parent chain carbons.

Answer:

It’s sexual, and the offspring are genetically different from the parents

Explanation:

Since it is the same flower the bee is pollinating, the progeny will be genetically distinct if the bee were to transfer the pollen to the female part of the flower from the male part.

The sequence of atomic numbers 1, 2, 3, and 4 denotes the periodic table's ordering of following elements.

Series are significant because they offer a possible point of entry. It's possible for a user to merely be aware of the fact that a publication is part of a specific series or to be searching for all publications in that series without being aware of any of the individual titles. The series could potentially be used as a storage and control system.

There are two ways to recognize elements in a series: The elements are in series if there are two and only two connections between them and a single node. When two elements' currents are determined to be similar by KCL at a node, the elements are in series.

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The approximate molar mass of lauryl alcohol is 183 g/mol.

As per Raoult's law:

[tex]T_b - T_s =KC m[/tex]

Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.

[tex]m_{l}[/tex]/M[tex]m_{s}[/tex] = [tex]C_{m}[/tex] where ml is the mass of lauryl alcohol and ms is the mass of the solvent.

[tex]T_b - T_s =KC m[/tex]=K[tex]m_{l}[/tex]/M[tex]m_{s}[/tex]

Therefore, M=[tex]\frac{Km_{l} }{(T_b - T_s)m_{s} }[/tex]=[tex]5.12*5/0.1(5.5-4.1)[/tex]=183 g/mol.

An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers.  Lauryl alcohol is a kind of emollient used in cosmetics.  Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.

A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?

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Oxidation is "Increase in oxidation number" as well as loss of electrons.

A rise in oxidation number results from the loss of negative electrons, whereas a reduction in oxidation number results from the gain of electrons. As a consequence, the oxidized element or ion experiences a rise in oxidation number.

As a result of losing electrons in the process, a reactant oxidizes. When a reactant obtains electrons during a reaction, reduction takes place. This frequently happens when acid and metals react.

Therefore, Oxidation is "Increase in oxidation number" as well as loss of electrons.

Hence, the correct answer will be option (e)

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The two effects do impurities have on the melting point of an organic compound are given as ,

The impurities decreases the melting point of the substance of organic compounds . This is because there are unwanted  particles which weaken the lattice structure of the  solids crystal due to which it become less stable and melts before its original melting point.

Example : Let take a clay and add dirt hen it breaks easily from the points where there is dirt . This is essentially what happens with impurities

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Answer:

You can separate a mixture of sand, salt and water by decantation and evaporation. Decantation will separate sand from salt and water. Sand remains in the original vessel, whereas salt and water is transfered to new vessel. Evaporation will separate salt from water.

The main problem is the release of heat and thereby reducing yield of Ammonia.

Chemical equilibrium is defined as the state of a reversible chemical reaction where there is no change in net amount of products and reactants involved in it.

What is an exothermic reaction?

Exothermic reaction is one of the chemical reactions that will produces heat during the formation of products.

At the chemical equilibrium, the chemical reaction will be as follows:

[tex]N_{2}[/tex] + 3[tex]H_{2}[/tex] → 2[tex]NH_{3}[/tex] + energy

The above chemical equilibrium equation indicates that energy will be released due to the reaction of nitrogen and hydrogen. The energy release increases the surrounding temperature and thereby it will reduce the yield of the ammonia. Thus it can be indicated as the major problem.

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Leucine and methionine are the amino acids formed using the n-phthalimido malonic ester synthesis.

The steps involved in phthalimido malonic ester synthesis:

Step 1: Deprotonation To Give An Enolate

In the first step, a base (CH3O– in this case) removes the most acidic proton from the ester (on C2 here, with a pKa of about 13) to give an enolate. The resulting enolate can be drawn as one of two resonance forms.

Step 2: SN2 Reaction Of The Enolate Nucleophile With An Alkyl Halide Electrophile.

Enolates are great nucleophiles. In the second step, the enolate acts as a nucleophile in an SN2 reaction to form a new C-C bond.

Step 3: Acidic Ester Hydrolysis

Acid and water are added to perform the aqueous hydrolysis of the ester to a carboxylic acid.

Step 4: Decarboxylation To Give An Enol

When carboxylic acids have a carbonyl group (C=O) two bonds away, they can readily lose carbon dioxide, because the carbonyl can act as an electron “sink” for the pair of electrons coming from the breaking C–C bond, forming an enol. This is called “decarboxylation”. Note how this is also the case for carboxylic acids with a ketone two bonds away, so-called “β-keto acids”.

Step 5: Tautomerization Of The Enol Back To The Carboxylic Acid

The enol that is formed is not a stable species. It can undergo transformation into its constitutional isomer: in this case, a carboxylic acid. These two constitutional isomers are in equilibrium with each other, although the “keto” form (with the carbonyl group) is greatly favoured. This process is called "tautomerism".

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The balloon is filled with 0.5L of air at sea level and submerged to a depth. Since, there is no change in the Temperature, the process is Isothermal. It is a process in which the temperature T of the given system does not change and remains constant. Hence, ΔT=0

Any system in which the temperature is kept constant is stated as an Isothermal Process. Since, in the given question, Temperature is not changing, hence we can consider it to be an Isothermal Process.

Given:

Pressure at sea level, P₁= 1 atm

Volume at sea level, V₁= 0.5L

Pressure at depth, P₂= 3.25 atm

Volume at depth, V₂= ?

Since, the process is Isothermal, hence,

∴ P₁V₁ = P₂V₂

⇒ 1 × 0.5 = 3.25 × V₂

⇒ V₂ = 0.5/3.25

⇒ V₂ = 0.154L

So, the Volume of balloon at the depth is 0.154L.

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Yes, the objects made of the same metal.

The volume of the first object, which is a cube, is equal to the edge length cubed.

This volume is converted to mL as follows:

V1 = [tex](3 cm)^{3}[/tex] = 27 [tex]cm^{3}[/tex] = 27 mL

Based on its given mass, the density will be:

d1 = m1/V1

   = 140.4g/ 27.0 mL

   = 5.20g/mL

The following thing is a sphere. We calculate the volume of a sphere using the following formula, with the result expressed in  mL:

V1 = 4/3 *[tex]\pi[/tex]* [tex](1.42)^{2}[/tex]

= 12 [tex]cm^{3}[/tex]

= 12 mL

The density based on the following mass will be 

d2= m2/V2

= 61.6 g/12.0 mL

= 5.14 g/mL

These two computed densities are separated by about 1%. We can determine that these objects are made of the same metal based on the precision of +/- 1% provided.

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In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.

Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.

If hydroxide is not added, the NH₂ groups will get protonated by H⁺  ions present to give NH₃⁺ groups, which cannot react.

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Answer:

Sodium hydroxide and water will react at room temperature. What does this indicate about its activation energy? The activation energy is at exactly 600 kJ. C. The activation energy is very low.

Explanation:

Answer:

Water and Salts

Explanation:

Hope it helps u....

If you were given the the total # of grams of all three compounds with the % of each molecular compound - H2O, CO2 and sugar [you would need to know the type of sugar in the Pop such as C12H22O11 as to find its MM (molar mass)]

To begin take the % of each compound x the total grams of all the compounds. For illustrative purposes let's say it works out to be 50 grams of H2O in the POP. The same would be. done for CO2 and for the sugar.

Step 1) With the mass of each you could determine the # of moles of each:

Example if the number grams of water in the sample is 50g, to determine the # of moles of water you would do the following - 50g H20 x 1 mol/18g H20 = 2.8 mol H2O The same technique would be used for the other compounds to find the # of moles.

Step 2) To find the representative particles of each(molecules, atoms) you would do the following:

as the example given of above for H20 - 50 grams you calculated as shown above to be the number of mol of H20 = 2.8mol

From the number of mol of H20, to determine the # of molecules of water you would set up the following:

2.8 mol H20 x 6.02 x 10^23/1 mol H2O = 1.69 X 10^24 molecules of H20.

The same would be done for CO2 and the sugar.

Step 3) Now to find the number of atoms of element of the compound taking for example the H2O example above:

Take the # of molecules of H2O found above and set it up in the following manner:

1.69 X 10^24 molecules H2O x 2 atoms H/1 molecule H2O = 3.38 x 10^24 atoms H

1.69 x 10^24 molecules H2O x 1 atom O)/1 molecule H2O = 1.69 X 10^24 atoms O

The same would be done for CO2 and for the sugar compound.

The same amount of energy is released when they recombine.

Like energy components, electrolyzers comprise of an anode and a cathode isolated by an electrolyte. Different electrolyzers capability in various ways, fundamentally because of the different kind of electrolyte material included and the ionic species it conducts.

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Answer:

pH = 4

Explanation:

pH is a base 10 logarithmic scale

  1000 = 10^3

        7 -3  = pH = 4  

1.4406 × 10⁻⁶ is the Ka(dissociation constant) for the acid.

The equilibrium constant for the reaction of an acid with water is the acid dissociation constant, where the acid, HA separates into H⁺ and A⁻ ions.

The acid dissociation constant is represented by (Ka).

So let's first imagine that the given monoprotic acid is HA.

HA will dissociate into H⁺ and A⁻ ions.

HA ⇒ H⁺ and A⁻

The formula used for Ka is

Ka = [H⁺] [A⁻] / [HA]

Given

pH = 2.83

[HA] = 1.50 M

From the given pH, we can calculate [H⁺] and [A⁻]

[H⁺] = [A⁻] = 1 × [tex]10^{-2.83}[/tex] =  1.47 × 10⁻³ M

Ka = 1.47 × 10⁻³ × 1.47 × 10⁻³ / 1.50

Ka = 1.4406 × 10⁻⁶

Hence, 1.4406 × 10⁻⁶ is the Ka for the acid.

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The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.

However, the number of moles can be calculated using the following formula:

PV = nRT

Where;

0.92 × 1.6 = n × 0.0821 × 287

1.47 = 23.56n

n = 1.47/23.56

n = 0.624moles

Molar mass = 0.314g ÷ 0.624mol

Molar mass = 0.503g/mol

Therefore, the molar mass of a 0.314-gram sample of gas having a volume of 1.6L at 287K and 0.92 atm is 0.503g/mol.

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The covenant of further assurances requires the grantor to execute any necessary legal documents (within his power) necessary to fix title defects discovered after closing.

A warranty deed is typically signed by both parties when a seller transfers real estate to a buyer. According to Deed Claim, this document certifies that the seller is the legitimate owner of the property and is selling it free of any liens while transferring the legal title to the buyer. The assurances made by the seller are represented by the six covenants of title. Three covenants are regarded as existing covenants, and as such, they are applicable to the parties to the most recent transfer. The other three are future covenants, and if they are broken, any owner may bring a claim against any prior grantor.

Covenant of Seisin

The seller's rightful ownership of the property is guaranteed by the present covenant of seisin.

No Encumbrances

The seller guarantees that the property is possessed free and clear by making the current covenant against encumbrances.

Right to Convey

According to TheLaw.com, having the right to convey indicates that the seller is legally permitted to transfer the property to the buyer.

Quiet Enjoyment

The future covenant of quiet enjoyment guarantees that a third party's legal claim to title won't affect the buyer's right to possession.

Covenant of Warranty

The warranty covenant and the quiet pleasure covenant are extremely similar.

Further Assurances

This prospective covenant is a guarantee that, should the need ever arise, the grantor will take all reasonable steps to assist the grantee in perfecting the title.

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Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form proteins concentration mechanisms do not include Boiling Stones.

Amino acids organic compounds. Amino acids are building block of life these are the molecules which combine to form proteins. Amino acids contain the amino functional group that is -NH₂ and carboxyl functional group that is -COOH.

Example: Glycine, Alanine etc.

Thus from the above conclusion we can say that Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form proteins concentration mechanisms do not include Boiling Stones.

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The weighted average of a penny is = 67.9g

The sample of penny for pre 1982 is a total of = 18 pennies.

The mass of each penny for pre 1982 = 3.1

Therefore the total weight for penny for pre 1982

= 18×3.1

= 55.8

The sample of penny for post 1982 is a total of = 32 pennies.

The mass of each penny for post 1982 = 2.5

Therefore the total weight for penny for post 1982

=32×2.5

= 80

The weighted average

= 55.8+80/2

= 135.8/2

= 67.9g

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Answer:

a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change

a catalyst is a substance that increases the speed of reaction by lowering the activation energy or providing an alternative pathway of a lower activation energy(more likely for enzymes in bio).

it also doesnt take part in the reaction but in chemistry, there are homologous and homogenous catalysts where some may take part in the rxn BUT they are regenerated and are not used up

chem: more particles will have the energy to overcome the activation energy, resulting in a higher frequency of effective collision, so the rate of rxn ↑. (usually catalyst is transition metal)

bio: enzyme-substrate complex, where it is essentially what happens in the chemistry part above but the conclusion is that it takes lesser time for nutrients to be broken down and therefore digested.

The 4 major types of inhibition are  Competitive Inhibition, Non-competitive Reversible Inhibition,  Non-competitive Irreversible Inhibition, and  Uncompetitive Inhibition.

1. Competitive Inhibition: Competing inhibitors are substances that resemble an enzyme's natural substrate so closely that they vie for the active site. In order to stop additional reactions, the inhibitor binds to the active site and stays there.

The inhibitor and substrate fight for the enzyme's active site because the enzyme may react with the inhibitor and release the products as it normally would with its substrate

2. Non-competitive Inhibition:

And in the Michaelis equation, this kind of inhibition lowers V max but has no impact on Km.The rate at which the enzyme is fully saturated is given by V = V max [S] / Km + [S] (V max).

(Km): The substrate is the Michaelis constant, at which the reaction rate is halved, or at V maximum.

       Additionally, this kind of inhibition lowers Vmax but has no impact on Km.

3. Uncompetitive Inhibition: is the last type, where the inhibitor attaches to the [E-S] complex to create [E-S-I] even if it has no affinity for the enzyme.

However, this kind of inhibition lowers both Vmax and Km.

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The 6 M solution NaOH solution diluted before titrating the vinegar sample because pH at the equivalence point changes very rapidly . It is very useful to have dilution solution , so that number of moles that are transferred per drop of the solution is low . So, pH change smaller amount per drop. Having more dilute solution also allows the titration to use volume that is easier to work with.

If you used the 6 M solution was used then the volume required for titration would go down by a factor of 6/0.3 = 20

This means that if a titration took 20ml of the 0.3 M solution then it would take 1ml of the NaOH solution.

Titration consists of adding a controlled and known amount of standard solution with an unknown until the reaction to be complete.

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