a) The polynomial f(x) in expanded form is f(x) = x³ + 10 · x² - 20 · x - 24.
b) The rational function g(x) in factored form is g(x) = [(x - 6) · (x + 3)] / (x - 2). there is no slant asymptotes.
c) There is one evitable discontinuity at x = - 1, and one definitive discontinuity at x = 2, where there is a vertical asymptote.
How to analyze polynomial and rational functions
a) In the first part of this question we need to determine the equation of a polynomial in expanded form, derived from its factor form defined below:
f(x) = Π (x - rₐ), for a ∈ {1, 2, 3, 4, ..., n} (1)
Where rₐ is the a-th root of the polynomial.
If we know that r₁ = 6, r₂ = - 1 and r₃ = - 3, then the polynomial in factor form is:
f(x) = (x - 6) · (x + 1) · (x + 3)
f(x) = (x - 6) · (x² + 4 · x + 4)
f(x) = (x - 6) · x² + (x - 6) · (4 · x) + (x - 6) · 4
f(x) = x³ - 6 · x² + 4 · x² - 24 · x + 4 · x - 24
f(x) = x³ + 10 · x² - 20 · x - 24
The polynomial f(x) in expanded form is f(x) = x³ + 10 · x² - 20 · x - 24.
b) The rational function is introduced below:
g(x) = (x³ + 10 · x² - 20 · x - 24) / (x² - x - 2)
g(x) = [(x - 6) · (x + 1) · (x + 3)] / [(x - 2) · (x + 1)]
g(x) = [(x - 6) · (x + 3)] / (x - 2)
The slope of the slant asymptote is:
m = lim [g(x) / x] for x → ± ∞
m = [(x - 6) · (x + 3)] / [x · (x - 2)]
m = 1
And the intercept of the slant asymptote is:
n = lim [g(x) - m · x] for x → ± ∞
n = Non-existent
Hence, there is no slant asymptotes.
c) There is vertical asymptote at a x-point if the denominator is equal to zero. There is one evitable discontinuity at x = - 1, and one definitive discontinuity at x = 2, where there is a vertical asymptote.
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Maricopa's Success scholarship fund receives a gift of $ 215000. The money is invested in stocks, bonds, and CDs. CDs pay 2.25 % interest, bonds pay 2 % interest, and stocks pay 9.2 % interest. Maricopa Success invests $ 15000 more in bonds than in CDs. If the annual income from the investments is $ 8087.5 , how much was invested in each account?
The amount of money invested in stocks was $50000, $90000 was invested in bonds and $75000 was invested in CDs
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.
Let x represent the amount of money invested in stocks, y represent bonds and z represent CDs, hence:
x + y + z = 215000 (1)
Also:
0.0225z + 0.02y + 0.092x = 8087.5 (2)
And:
y = 15000 + z (3)
The solution of the equation is:
x = 50000, y = 90000 and z = 75000
The amount of money invested in stocks was $50000, $90000 was invested in bonds and $75000 was invested in CDs
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If the lengths of two sides of a triangle measure 8 and 13, the length of the third side is:
Answer:
A
Step-by-step explanation:
Triangle side length rule says any two sides added together must be greater than third side .... '6' is the only side length that will work
Identify the lateral area and the surface area of a cube with edge length 15 in.
The Lateral area of the cube = 900 in.²
The Surface area of the cube = 1,350 in.².
What is the Lateral Area of a Cube?A cube's lateral area is the area covered by the lateral surfaces of the cube shape. The formula for the lateral area of a cube is given as: LA = 4a², where:
a = edge length of cube.
What is the Surface Area of a Cube?The surface area of a cube is the total area of all its 6 surfaces. The formula for finding the surface area of a cube is: 6a², where:
a = edge length of cube.
Edge length of cube (a) = 15 in.
Lateral area = 4a² = 4(15²)
Lateral area = 4(225)
Lateral area of the cube = 900 in.²
Surface area = 6a² = 6(15²)
Surface area = 6(225)
Surface area of the cube = 1,350 in.².
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Which geometric sequence has a common ratio of -9? (only one is correct)
a) {-1, -9, 81, 729, …}
b) {-9; -81; -729; -6,561; …}
c) {1, -9, 81, -729, …}
d) {81; 729; 6,561; 59,049; …}
C
1, -9 , 81 , -729 .....
ratio :-
R1 = -9/1 = -9
R2 = 81/-9 = -9
R3 = -729 / 81 =-9
so ,. R1= R2= R3
Question 25: [1 + 2 + 2 + 2 + 2 + 1= 10 points]
Given student of classified as belonging to three colleges and gender males and Females in the following table.
Eng (E) Life (L) Sci (S) sum F 60 40 30 130
M 40 20 10 70 sum 100 60 40 200
a) [1 points] Find the probabilities whole events. () , (), (), () , and ()
b) [2 points] Find the probabilities of Intersection (AND) Events:
( ∩ ) = ( ∩ ) ( ∩ ) = ( ∩ ) ( ∩ ) = ( ∩ )
( ∩ ) = ( ∩ ) ( ∩ ) = ( ∩ ) ( ∩ ) = ( ∩ )
c) [2 points] Find the probabilities of Union (OR) disjoint Events:
( ∪ ) = ( ∪ ) ( ∪ ) = ( ∪ )
( ∪ ∪ ) = ( ∪ ∪ ) ( ∪ ) = ( ∪ )
d) [2 points] Find the probabilities of Union (OR) joint events: ( ∪ )
( ∪ )
e) [2 points] Find the probabilities of Conditional Probabilities
(/) (/)
(/) (/)
(/) (/)
(/) (/)
f) [1 points] Use The multiplication low for dependent events to find the Conditional probability. ( ∩ ) = () (/)
See below for the values of the probabilities
How to determine the probabilities?The probabilities of the whole events
For event A, the probability of the whole event is calculated using
P(A) = n(A)/Total
Using the table of values, we have:
P(F) = 130/200 = 0.65
P(M) = 70/200 = 0.35
P(L) = 60/200 = 0.30
P(S) = 40/200 = 0.20
The probabilities of the intersection events
For events A and B, the probability of the intersection events is calculated using
P(A n B) = n(A n B)/Total
Using the table of values, we have:
P(F n E) = P(E n F) = 60/200 = 0.30
P(F n L) = P(L n F) = 40/200 = 0.20
P(F n S) = P(S n F) = 30/200 = 0.15
P(M n E) = P(E n M) = 40/200 = 0.20
P(M n L) = P(L n M) = 20/200 = 0.10
P(M n S) = P(S n M) = 10/200 = 0.05
The probabilities of the Union (OR) disjoint events
For events A and B, the probability of the union (OR) disjoint events is calculated using
P(A u B) = P(A) + P(B)
Using the table of values, we have:
P(E u S) = P(E) + P(S) = 100/200 + 40/200 = 0.70
P(E u L) = P(E) + P(L) = 100/200 + 60/200 = 0.80
P(E u L u S) = P(E) + P(L) + P(S) = 100/200 + 60/200 + 40/100 = 1
P(F u M) = P(F) + P(M) = 130/200 + 70/200 = 1
The probabilities of the Union (OR) joint events
For events A and B, the probability of the union (OR) joint events is calculated using
P(A u B) = P(A) + P(B) - P(A n B)
Using the table of values, we have:
P(E u F) = P(E) + P(F) - P(E n F) = 100/200 + 130/200 - 60/100 = 0.85
P(L u M) = P(L) + P(M) - P(L n M) = 60/200 + 70/200 - 20/100 = 0.55
The probabilities of the conditional probabilities
For events A and B, the conditional probability is calculated using
P(A/B) = P(A n B)/P(B)
Using the table of values, we have:
P(F/S) = P(F n S)/P(S) = 0.15/0.20 = 0.75
P(F/E) = P(F n E)/P(E) = 0.30/0.50 = 0.60
P(M/S) = P(M n S)/P(S) = 0.05/0.20 = 0.25
P(M/L) = P(M n L)/P(L) = 0.10/0.30 = 0.33
P(S/F) = P(F n S)/P(F) = 0.15/0.65 = 0.23
P(E/F) = P(F n E)/P(F) = 0.30/0.65 = 0.46
P(S/M) = P(M n S)/P(M) = 0.05/0.35 = 0.14
P(L/M) = P(M n L)/P(M) = 0.10/0.35 = 0.29
The multiplication of dependent events
For events A and B, the conditional probability is calculated using
P(A n B) = P(A) * P(B/A)
Using the table of values, we have:
P(F n L) = P(F) * P(L/F)
This gives
P(F n L) = 0.65 * (0.20/0.30)
Evaluate
P(F n L) = 0.43
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Target Costing
Instant Image Inc. manufactures color laser printers. Model J20 presently sells for $460 and has a product cost of $230, as follows:
Direct materials $175
Direct labor 40
Factory overhead 15
Total $230
It is estimated that the competitive selling price for color laser printers of this type will drop to $400 next year. Instant Image has established a target cost to maintain its historical markup percentage on product cost. Engineers have provided the following cost-reduction ideas:
Purchase a plastic printer cover with snap-on assembly, rather than with screws. This will reduce the amount of direct labor by 15 minutes per unit.
Add an inspection step that will add six minutes per unit of direct labor but reduce the materials cost by $20 per unit.
Decrease the cycle time of the injection molding machine from four minutes to three minutes per part. Forty percent of the direct labor and 48% of the factory overhead are related to running injection molding machines.
The direct labor rate is $30 per hour.
a. Determine the target cost for Model J20, assuming that the historical markup on product cost and selling price are maintained.
$fill in the blank 1
per unit
b. Determine the required cost reduction.
$fill in the blank 2
per unit
c. Evaluate the three engineering improvements together to determine if the required cost reduction (drift) can be achieved. Do not round interim calculations but round your final answers to two decimal places.
1. Direct labor reduction $fill in the blank 3
per unit
2. Additional inspection $fill in the blank 4
per unit
3. Injection molding productivity improvement $fill in the blank 5
per unit
Total savings $fill in the blank 6
per unit
The target cost for Model J20 is $2000.
The required cost reduction is $30.
The total saving will be $30.3.
How to compute the cost?The target cost will be:
= Sales price - (100% × Target cost)
= 400 - (100% × Y)
Y + Y = 400
2Y = 400
Y = 400/2 = 200
Target cost = $200
Therefore, the target cost is $200.
The required cost reduction will be:
= $230 - $200
= $30
The required cost reduction is $30.
The three engineering improvements together will be:
Direct labor reduction = 7.5
Additional inspection = 17
Injection molding = 5.8
Total savings = 30.3
The total savings is $30.3.
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Multiply -2x^-3 y(5yx^5+8xy-4y^2x^2).
Answer:
[tex]\textsf{Option 3}: \quad -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]
Step-by-step explanation:
Given expression:
[tex]-2x^{-3}y(5yx^5+8xy-4y^2x^2)[/tex]
Distribute:
[tex]\implies -2x^{-3}y(5yx^5) -2x^{-3}y(8xy)-2x^{-3}y(-4y^2x^2)[/tex]
Multiply the constants and collect like terms:
[tex]\implies -10 x^{-3}x^5yy-16x^{-3}xyy+8x^{-3}x^2yy^2[/tex]
Remember that a = a¹.
[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]
[tex]\implies -10 x^{(-3+5)}y^{(1+1)}-16x^{(-3+1)}y^{(1+1)}+8x^{(-3+2)}y^{(1+2)}[/tex]
[tex]\implies -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]
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Given 3x^2+x-4/x-1 what are the domain and range
Answer:
doman: x ≠ 1range: y ≠ 7Step-by-step explanation:
The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.
SimplifiedThe given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...
[tex]\dfrac{3x^2+x-4}{x-1}=\dfrac{(x-1)(3x+4)}{(x-1)}=3x+4\quad x\ne 1[/tex]
DomainThe simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...
x ≠ 1
In interval notation, this is ...
(-∞, 1) ∪ (1, ∞)
Range
The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...
y ≠ 7
In interval notation, this is ...
(-∞, 7) ∪ (7, ∞)
A movie theater has a seating capacity of 331. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. There are half as many adults as there are children. If the total ticket sales was $ 2404, How many children, students, and adults attended?
Answer:
87 adults
174 children
70 students
Step-by-step explanation:
The answer to this problem please and thank you
Answer:
C
Step-by-step explanation:
The red dotted line we see is the asymptote, which is a line that the functions will never cross.
The asymptotes we see currently is:
x = -3
and
x = 2
We can find the vertical asymptotes using the denominator of the function since the x value that makes the denominator 0 is the asymptote. Since -3 and 2 is the asymptote, the denominator of the function will be:
(x-2) (x+3)
If we look at the answer choices, we can see that C is the only option with a denominator of (x-2)(x+3), so that is our answer.
Answer:
C
Step-by-step explanation:
there are 2 vertical asymptotes at x = - 3 and x = 2
then the factors on the denominator will be (x + 3) and (x - 2)
then
f(x) = [tex]\frac{1}{(x-2)(x+3)}[/tex]
Sports clubs have increasingly been acknowledged as important settings for health promotion. The term sport club is synonymous with organized sport and both are considered to consist of environments that support the healthy behaviors of its athletic members. One of the member Sanjaya pays rupees 500 in advance on his account at a sports club ,each time he visits the club 10 rupees is deducted from his account. Q6. Which of the following equation represent the left balance of sanjaya’s y after visiting x number of days? * A) y=500+10x B) y=10+500x C) x=500-10y D) y=500-10x NO RESPONSE
The linear equation that represent the left balance of sanjaya’s y after visiting x number of days is:
y = 10x + 500.
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.From the data given, we have that:
The y-intercept is of 500.The slope is of 10.Hence the balance is given as follows:
y = 10x + 500.
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Maytag Company earns $2.60 per share. Today the stock is trading at $46. The company pays an annual dividend of $1.60 a. Calculate the price-earnings ratio (Round your answer to the nearest whole number.) Price-earings natio b. Calculate the stock yield. (Round your answer to the nearest tenth percent.) Stock yield
a. The price-earnings ratio of Maytag Company's stock is 17.
b. The stock yield of Maytag Company's stock is 3.48%.
What are the price-earnings ratio and stock yield?The price-earnings ratio is a financial measurement of the worth of Maytag Company.
The price-earnings (P/E) ratio is computed as the current stock price divided by the company's earnings per share.
The P/E ratio shows the potential investor how much to pay per share for each $1 of earnings.
The stock yield is a financial measurement that shows the dividends paid relative to the market value per share.
Data and Calculations:Earnings per share = $2.60
Current share price = $46
Annual dividend = $1.60
a. Price-earnings ratio = Price per share/earnings per share
= 17 ($46/$2.60).
b. Stock yield = Annual dividend per share/Current stock price x 100
= 3.48% ($1.60/$46 x 100)
Thus, while the price-earnings ratio is 17, the stock yield is 3.48%.
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X is 30% of Y and Y is 45% of 600. What is the value of X?
Answer:
X = 81
Step-by-step explanation:
600 × 0.45 = 270
270 × 0.3 = 81
X = 81
Let f(x)=x^2 and g(x)=(x+3)^2. Describe the transformation from f(x) to g(x).
Select one:
Shift right 3
Shift up 3
Shift down 3
Shift left 3
Answer:
shift left 3
Step-by-step explanation:
(x+3)²
x = -3
therefore translation by (-3,0)
The negative number shows it move to the left
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0) B(6, 0) C(6, 7) D(2, 7)
What is the area of rectangle ABCD?
Check the picture below.
Answer: 28 [tex]units^{2}[/tex]
Step-by-step explanation:
A troupe of 12 dancers is going to line up on stage. Of these dancers, 6 are wearing green and 6 are wearing blue. A dancer wearing green must be in the first position and they must alternate between colors. In how many ways can the dancers line up?
The number of ways that the dancers can line up is; 518400 ways
What is the Fundamental Counting Theorem?The fundamental counting theorem is a theorem that states that if there are n things, each with ways to be done, each thing independent of the other, the number of ways they can be done is:
N = n1 * n2 * n3.....*nₙ
Total = 12
Dancers on Green = 6
Dancers on blue = 6
Number of ways for those wearing green = 6!
Dancers wearing green must be in the first position and so 6 places are left for the blue dancers.
Number of ways to arrange those wearing blue = 6!
Thus;
Number of ways that the dancers can line up = 6! * 6! = 518400 ways
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Find the value of u -8 given that -7u-5=2
Answer: u - 8 = -9
Step-by-step explanation:
Given equation
-7u - 5 = 2
Add 5 on both sides
-7u - 5 + 5 = 2 + 5
-7u = 7
Divide -7 on both sides
-7u / (-7) = 7 / (-7)
u = -1
Substitute values into the goal expression
u - 8 = (-1) - 8 = [tex]\Large\boxed{-9}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
The answer is -9.
First, let's find the value of u.
-7u - 5 = 2-7u = 7u = -1Now, substitute in the expression.
u - 8(-1) - 8-9Use identities to find the values of the sine and cosine functions for the following angle measure.
θ, given that cos 20 =12/13 and θ terminates in quadrant I. Find sin θ and cos θ. Can you explain how do it and what is the answer?
Using the cosine double angle formula,
[tex]\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}[/tex]
(Note I took the positive case since [tex]\theta[/tex] terminates in the first quadrant)
Using the Pythagorean identity,
[tex]\sin^2 \theta+\cos^2 \theta=1\\\\\sin^2 \theta+\frac{25}{26}=1\\\\sin^2 \theta=\frac{1}{26}\\\\\boxed{\sin \theta=\frac{1}{\sqrt{26}}}[/tex]
(Note I took the positive case since [tex]\theta[/tex] terminates in the first quadrant)
Using a number line, find both the intersection and the union of the following
intervals:
(-∞, 6) and (-∞, 9)
The intersection of the two intervals in the number line will be = 4, 5, 6,.......+∞ = (-∞,6).
The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞ = (-∞),9)
How to illustrate the information?The given intervals are;
First interval = (-∞, 6)
Second interval = (-∞, 9)
Using the number line, we therefore, the first interval includes, -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞
The second interval includes, 4, 5,.....,+∞
Which gives the intersection as 4, 5, 6,7, 8,9......+∞
The union is the interval that combines the two sets of intervals which is given as follows;
The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞
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The length of a rectangle is 3 m longer than its width.
If the perimeter of the rectangle is 34 m, find its area.
Step-by-step explanation:
With this question ,
The length of the rectangle is 3m longer than it's width=3 +w
then the width =w
therefore perimeter= 2L +2w
34= 2(3+w) +2w
34= 6+2w +2w
34-6 = 4w
28=4w
7= w
Area= Length x breadth
Area = (7+3) x7
Area= 10 x7
Area= 70cm square
Using a spreadsheet program, create an amortization schedule for a 30-year mortgage of $500,000 at an annual interest rate of 4.23%.
(a)
In which month does the amount of principal in a monthly payment first exceed the amount of interest?
(b)
How much interest is repaid for the term of the loan? (Round your answer to the nearest cent.)
$
(c)
If the loan amount was $750,000 instead of $500,000, would the month in which the amount of principal in a monthly payment first exceeded the amount of interest change?
Yes
No
This exercise requires the ability to create Amortization Schedules Using a Spreadsheet program. Based on the information given about the Amortization of the loan, the principal payable per month became greater than the interest payable per month on the 159th month (given that the loan amount is $500,000.
In which month does the amount of principal in a monthly payment first exceed the amount of interest?The amount of principal in a monthly payment first exceeds the interest payment In 159th Month. The interest on this month is $1, 248.39 while the principal on this month is $1, 205.46.
It is to be noted that when a loan is taken, the constituents of the amounts being paid back is the Principal and part of the interest on the loan.
How do you Calculate Amortization of Loans?The yearly interest rate must be divided by 12.
Your monthly interest rate, for instance, will be 0.3525 percent if your annual interest rate is 4.23 percent (0.0423 annual interest rate x 12 months).
Additionally, you'll add 12 to the number of years remaining on your loan term.
How much interest is repaid for the term of the loan?The total amount of interest that is paid for the term loan is $383,385.54
If the loan amount was $750,000 instead of $500,000, would the month in which the amount of principal in a monthly payment first exceeded the amount of interest change?Yes it would change. It would change to the 165th month. In this month, the interest paid is $1, 834.00 while the principal paid back is $1,846.77. See the attached image for answer C.
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A bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km away. Write a formula expressing the dependence of the variable s on t, where s is the distance between the bicyclist and the station in km, t - the duration (time) of his travel in hours. Using the formula, find: d for t=3.5
1. The formula expressing the dependence of the variable s on t is: s = 60 - 12t
2. the distance travelled at time t = 3.5 h is 18 Km
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
1. How to determine the formula expressing the dependence of the variable s on tFrom the question given, bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km.
Thus, we shall determine the distance travel in time t as follow
Speed = 12 Km/hTime = tDistance in time t = ?Speed = distance / time
12 = distance / t
Cross multiply
Distance = 12 × t
Distance in time t = 12t
But the total distance travelled is 60 Km. Thus, the remaining distance (s) from the bicyclist to the station at time (t) will be given as:
s = 60 - 12t
Thus, the formula expressing the dependence of the variable s on t is: s = 60 - 12t
2. How to determine the distance at t = 3.5 hoursThe distance at t = 3.5 hours can be obtained as illustrated below:
Time (t) = 3.5 hoursDistance (s) = ?s = 60 - 12t
s = 60 - (12 × 3.5)
s = 60 - 42
s = 18 Km
Thus, the distance travelled at t = 3.5 hours is 18 km
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MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE
BETWEEN 1.8 AND 1.1 WILL RECEIVE A B, THOSE BETWEEN 1.1 AND -1.2 WILL
RECEIVE A C, THOSE BETWEEN -1.2 AND -1.9 WILL RECEIVE A D, AND THOSE
UNDER -1.9 WILL RECEIVE AN F.
FIND THE PERCENT OF GRADES THAT WILL BE
A, B, C, D, AND F.
Using the normal distribution, it is found that the percentages are given as follows:
3.59% of the grades will be A.9.98% of the grades will be B.74.92% of the grades will be C.8.64% of the grades will be D.2.87% of the grades will be F.Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The prorportion of students who receive an A is one subtracted by the p-value of Z = 1.8.
Looking at the z-table, Z = 1.8 has a p-value of 0.9641.
1 - 0.9641 = 0.0359.
3.59% of the grades will be A.
For B, it is the p-value of Z = 1.8 subtracted by the p-value of Z = 1.1, hence:
0.9641 - 0.8643 = 0.0998.
9.98% of the grades will be B.
For C, it is the p-value of Z = 1.1 subtracted by the p-value of Z = -1.2, hence:
0.8643 - 0.1151 = 0.7492.
74.92% of the grades will be C.
For D, it is the p-value of Z = -1.2 subtracted by the p-value of Z = -1.9, hence:
0.1151 - 0.0287 = 0.0864.
8.64% of the grades will be D.
For F, it is the p-value of Z = -1.9, hence 2.87% of the grades will be F.
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If we draw lines to join each given point to the origin identify the points whose corresponding line has a slope that is an integer value
The slopes of OA, OB and OC are integer values.
According to the statement
we have given that the some points on the graph and we have to find that the slopes of these points have integer value or not.
So, For this we know that the
If a line passing through two points then the slope of the line is
So, [tex]m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
Then
The slope of line OA is 4 because 8/2 = 4.
And
The slope of line OB is 3 because 9/3 = 3.
And
The slope of line OC is 2 because 8/4 is 2.
And
The slope of line OD is 8/5 because it is 8/5.
And
The slope of line OE is 7/6 because it is 7/6.
And
The slope of line OE is 6/7 because it is 6/7.
From all this it is clear that
So,The slopes of OA, OB and OC are integer values.
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Find the total surface area.
answer choices
A. 731 cm²
B. 649 cm²
C. 900 cm²
D. 770 cm²
Find the difference. Enter your answer in lowest terms in the box below as a
fraction, using the slash mark (/) for the fraction bar. 8/11 - 4/15
Answer:
76/165
Step-by-step explanation:
The difference of fractions can be found using the formula ...
a/b -c/d = (ad -bc)/(bd)
DifferenceUsing the given values in the formula, we have ...
[tex]\dfrac{8}{11}-\dfrac{4}{15}=\dfrac{8(15)-11(4)}{11\cdot15}=\dfrac{120-44}{165}=\boxed{\dfrac{76}{165}}[/tex]
Here, the difference fraction does not need to be reduced. Many calculators and spreadsheets can do this arithmetic for you.
The above formula can also be used for sums of fractions. In that case, the sign changes from minus to plus.
Answer:
Step-by-step explanation:
76/165 is the answer
6. Dacă a + 2b = 18 şi b+3c=17, calculaţi 3a+8b+6c.
Answer:
Răspuns: 88=>rezultatul
Explicație pas cu pas:
a+2b =18/×3
b+3c=17/×2
3a+6b =54 ^
2b+6c=34 | +
3a+(6b+2b)+6c=54+34
3a+8b+6c=88
Step-by-step explanation:
The Mogul Runners ski club planned a trip to Park City. Of the total number of club members, 11 signed up to go. If this is 25% of the club, how many members does the ski club have?
Answer: 44
Step-by-step explanation: Since 11 members are equal to 25% of the club, 11 members is 1/4 of the club because 25% = 1/4. There are four-fourths in a whole so 11x4 = 44 members. The ski club has 44 members.
An account begins the year with a
$4000.00 balance. If the account
earns 3% simple interest, what is the
balance at the end of one year?
A. $4,120.00
C. $4,300.00
B. $4,003.00
D. $4,012.00
[tex]s = c(1 + in) \\ s = 4000(1 + 0.03 \times 1) [/tex]
[tex]s = 4120.00[/tex]
Option: AFind the critical value zα/2 that corresponds to the confidence level 84%.
The critical value z_α/2 that corresponds to the confidence level 84% is; 1.41
How to find the critical value?We want to find the two tail critical values.
This means that at an 84% confidence level, we want to get the probability of not rejecting the null value to be equal to a = 100% - 84% = 16%.
Now, z - scores refers to a numerical measurement that describes a value's relationship to the mean of a group of values and is gotten from normal distribution. Z-score is measured in terms of standard deviations from the mean.
However, under a normal distribution, we want a/2% = 16%/2 = 8% to be located right in the higher tail and lower tail.
From the above, it denotes that the critical value closest to 0.92 will give you the two tail 84% confidence interval. Utilizing a normal distribution table figure online to find the z score gives;
z = 1.41
Thus, we can conclude from this calculation that he critical value z_α/2 that corresponds to the confidence level 84% is; 1.41
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