A point is moving on the graph of xy=42. When the point is at (7,6), its x-coordinate is increasing by 7 units per second. How fast is the y-coordinate changing at that moment? The y-coordinate is at units per second. (Simplify your answer).

A. We would expect approximately 115 students to be members of the band in 2005.

B. We would expect the band to have 85 members in the year 2000.

a. To determine the number of students expected to be members of the band in 2005, we need to substitute the value of x = 2005 - 1990 = 15 into the equation y = 6x + 25:

y = 6(15) + 25

y = 90 + 25

y = 115

Therefore, we would expect approximately 115 students to be members of the band in 2005.

b. To find the year when the band is expected to have 85 members, we can rearrange the equation y = 6x + 25 to solve for x:

y = 6x + 25

85 = 6x + 25

Subtracting 25 from both sides:

60 = 6x

Dividing both sides by 6:

x = 10

This tells us that x = 10 represents the number of years since 1990. To find the year, we add 10 to 1990:

Year = 1990 + 10

Year = 2000

Therefore, we would expect the band to have 85 members in the year 2000.

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The third table is the table that shows a linear function in this problem.

A function is classified as linear when the input variable is changed by one, the output variable is increased/decreased by a constant.

For the third table in this problem, we have that when x is increased by 2, y is also increased by 2, hence the slope m is given as follows:

m = 2/2

m = 1.

This means that when x is increased by one, y is increased by one, hence the third table is the table that shows a linear function in this problem.

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The required probability is 0.9954 (rounded off to five decimal places)

According to a recent survey, 63% of all families in Canada participated in a Halloween party.

The probability that at least two families participated in a Halloween party is to be calculated.

Let A be the event that at least two families participated in a Halloween party.

Hence,

A' is the event that at most one family participated in a Halloween party.

P(A') = Probability that no family or only one family participated in a Halloween party

P(A') = (37/100)¹¹ + 11 × (37/100)¹⁰ × (63/100)

Now, P(A) = 1 - P(A')

P(A) = 1 - [(37/100)¹¹ + 11 × (37/100)¹⁰ × (63/100)]

Hence, the probability that at least two families participated in a Halloween party is

[1 - (37/100)¹¹ - 11 × (37/100)¹⁰ × (63/100)]

≈ 0.9954

Therefore, the required probability is 0.9954 (rounded off to five decimal places)

Note: The rule of subtraction is used here.

The formula is P(A') = 1 - P(A).

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In mathematics, sequences refer to a set of numbers or objects arranged in a definite order according to specific rules. The nth term of a sequence is a formula that enables us to determine the value of any term in the sequence using the position of that term within the sequence.In order to find the nth term rule for a sequence, we first need to understand the sequence's pattern. Here is how we can find the nth term rule for a sequence:

Step 1: Determine the sequence's first term and the common difference between terms.

Step 2: Subtract the first term from the second term to determine the common difference between terms. For example, if the first two terms are 3 and 7, the common difference is 7 - 3 = 4.

Step 3: Use the formula "nth term = a + (n-1)d" to find the nth term, where a is the first term and d is the common difference between terms. For example, if the first term is 3 and the common difference is 4, the nth term rule is given by "nth term = 3 + (n-1)4".

In conclusion, finding the nth term rule for a sequence requires identifying the pattern in the sequence and determining the first term and the common difference between terms. We can then use the formula "nth term = a + (n-1)d" to find the value of any term in the sequence using its position within the sequence.

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The betas and portfolio weights for 3 stocks are given as follows: Portfolio 1: Portfolio 2: Portfolio 3: Calculation:Part 1: Beta of portfolio 1.

Beta of portfolio 1 = (0.4 × 1.2) + (0.3 × 0.9) + (0.3 × 0.8)Beta of portfolio 1 = 0.48 + 0.27 + 0.24 Beta of portfolio 1 = 0.99 Therefore, the beta of portfolio 1 is 0.99.Part 2: Beta of portfolio 2 Beta of portfolio 2 = (0.2 × 1.2) + (0.5 × 0.9) + (0.3 × 0.8)Beta of portfolio 2 = 0.24 + 0.45 + 0.24.

Beta of portfolio 2 = 0.93 Therefore, the beta of portfolio 2 is 0.93 If you are more concerned about risk than return, you should pick portfolio 1 because it has the highest beta value of 0.99, which means it carries more risk than the other portfolios.

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To calculate the derivative of the given expression, we can apply the Fundamental Theorem of Calculus.

Let's denote the variable of integration as u and differentiate with respect to θ: d/dθ [1∫θ (2cot(u)) du].By the Fundamental Theorem of Calculus, we can differentiate under the integral sign, so we have: = 2cot(θ). Therefore, the derivative of the given expression is 2cot(θ). This means that the rate of change of the integral with respect to θ is given by 2cot(θ).

The cotangent function represents the ratio of the adjacent side to the opposite side in a right triangle, so the derivative tells us how the integral changes as θ varies.

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The limit of (35x^3 + x^2 + 2x + 4) / (20x^3 + 3x^2 - 3x) as x approaches infinity is 35/20, which simplifies to 7/4 or 1.75.

To determine the limit, we focus on the highest degree terms in the numerator and denominator, which are both x^3. Dividing each term by x^3, we get (35 + 1/x + 2/x^2 + 4/x^3) / (20 + 3/x - 3/x^2). As x approaches infinity, the terms with 1/x, 2/x^2, and 4/x^3 tend towards zero, leaving us with (35 + 0 + 0 + 0) / (20 + 0 - 0). This simplifies to 35/20 or 7/4, which is the final result.

In essence, as x becomes larger and larger, the lower degree terms become insignificant compared to the highest degree terms. Therefore, we can approximate the limit by considering only the leading terms and ignore the smaller ones.

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In economics, the theory of signalling is used to investigate the information conveyed by different actions of an individual. The two primary models of signaling are the pooling equilibrium and the separating equilibrium.

In a pooling equilibrium, an individual who is uninformed about another individual's quality acts in the same way towards both high-quality and low-quality individuals. In a separating equilibrium, individuals with different qualities behave in different ways. The theory of signalling assumes that the informed party and the uninformed party are aware of the type of the other party.The values of c for which both a pooling equilibrium and a separating equilibrium are possible are values such that the payoff to each type of worker is the same at the pooling equilibrium and the separating equilibrium, i.e., each type of worker is indifferent between the two equilibria.

The workers in the separating equilibrium earn more than the workers in the pooling equilibrium. In the separating equilibrium, the high-quality workers behave differently from the low-quality workers, and the informed party can distinguish between the two types. The uninformed party is willing to pay a premium for the high-quality worker, resulting in the high-quality worker receiving a higher wage than the low-quality worker. This premium compensates the high-quality worker for the cost of signalling.In the pooling equilibrium, the high-quality worker and the low-quality worker are indistinguishable, resulting in the same wage for both types of workers. Since the cost of signalling for the high-quality worker is greater than the cost of signalling for the low-quality worker, the high-quality worker will not signal their quality, resulting in a lower wage for both workers. Thus, workers in a separating equilibrium earn more than workers in a pooling equilibrium.

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The speed of the flea is √5 graph paper units per minute. The flea will be at (0, -4) after 3 minutes. It will take the flea 5 minutes to get to the point (−4,−12). The flea does not reach the point (−13,−27) since the required time is positive.

a) Speed of the flea is |v|=√(1²+2²)=√5. Therefore, speed of the flea is √5 graph paper units per minute

.b) After 3 minutes, the flea will be at (3-1(3), 2-2(3))= (0, -4). Therefore, the flea will be at (0, -4) after 3 minutes.

c) Let (x,y) be the position of the flea after t minutes. So, x= 3-1t, and y= 2-2t.

According to the Pythagorean theorem: (x - (-4))² + (y - (-12))² = √5t²

Hence,(3 + t)² + (2 - 2t - 12)² = 5td)¹³, -27 is on the line x+y=-15.

Therefore, we know the flea would have to travel along this line to reach (−13,−27).The equation of the line is x+y=-15. Substituting x= 3-1t, andy= 2-2t, we get;

3-1t + 2 - 2t = -15

t=5

As this is positive, the flea does not reach the point (−13,−27).

: The speed of the flea is √5 graph paper units per minute. The flea will be at (0, -4) after 3 minutes. It will take the flea 5 minutes to get to the point (−4,−12). The flea does not reach the point (−13,−27) since the required time is positive.

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The simplified fraction for 18/15 - (125/6 - 18/15 ÷ 24/14) is -71/15.

To simplify this expression, we can start by simplifying the fractions within the parentheses:

18/15 ÷ 24/14 can be simplified as (18/15) * (14/24) = (6/5) * (7/12) = 42/60 = 7/10.

Now we substitute this value back into the original expression:

18/15 - (125/6 - 7/10) = 18/15 - (125/6 - 7/10).

Next, we need to simplify the expression within the second set of parentheses:

125/6 - 7/10 can be simplified as (125/6) * (10/10) - (7/10) = (1250/60) - (7/10) = 1250/60 - 42/60 = 1208/60 = 302/15.

Now we substitute this value back into the expression:

18/15 - 302/15 = (18 - 302)/15 = -284/15.

Finally, we simplify this fraction:

-284/15 can be simplified as (-142/15) * (1/2) = -142/30 = -71/15.

Therefore, the simplified fraction is -71/15.

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Therefore, the 23rd Fibonacci number is 28,657.

The answer to the given problem is the Fibonacci number 28,657. The given numbers 46,368 and 75,025 are the 24th and 25th Fibonacci numbers.

The Fibonacci numbers are a series of numbers that start with 0 and 1, and each subsequent number is the sum of the two previous numbers in the sequence. The sequence goes like this:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, ...

Thus, to find the 23rd Fibonacci number, we need to go back two numbers in the sequence.

We know that the 24th number is 46368 and the 25th number is 75025.

To find the 23rd number, we can subtract the 24th number from the 25th number:75025 - 46368 = 28657

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For the function f(x) = (5x + 2) / (3x - 1), the horizontal asymptote is y = 5/3, and the vertical asymptote is x = 1/3. For the function f(x) = (x + 2) / (x^2 + 4x + 1), the oblique asymptote is given by the equation y = x + 2.

a) To find the horizontal and vertical asymptotes of the function f(x) = (5x + 2) / (3x - 1), we need to analyze the behavior of the function as x approaches positive or negative infinity.

Horizontal asymptote: As x approaches infinity or negative infinity, the highest power term in the numerator and the denominator dominates the function. In this case, the highest power terms are 5x and 3x. Thus, the horizontal asymptote is given by the ratio of the coefficients of these highest power terms, which is 5/3.

Vertical asymptote: To find the vertical asymptote, we set the denominator equal to zero and solve for x. In this case, we have 3x - 1 = 0, which gives x = 1/3. Therefore, the vertical asymptote is x = 1/3.

b) To find the oblique asymptote of the function f(x) = (x + 2) / (x^2 + 4x + 1), we need to divide the numerator by the denominator using long division or synthetic division. The quotient we obtain will be the equation of the oblique asymptote.

Performing long division, we get:

1

x^2 + 4x + 1 | x + 2

x + 2

x^2 + 4x + 1 | x + 2

- (x + 2)^2

-3x - 3

The remainder is -3x - 3. Therefore, the oblique asymptote is given by the equation y = x + 2.

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The number of elements in A′∩B is 2. This is because A′∩B is the set of elements that are in B but not in A. Since Shildon is the only element in both A and B, the number of elements in A′∩B is 2.

A′ is the complement of A, which is the set of elements that are not in A. B is the set of elements that are in B. Therefore, A′∩B is the set of elements that are in B but not in A. We can find the number of elements in A′∩B by first finding the number of elements in B. The set B has 3 elements: Barnsley, Manchester United, and Shildon.

We then subtract the number of elements in A that are also in B. The set A has 4 elements, but only 1 of those elements (Shildon) is also in B. Therefore, the number of elements in A′∩B is 3 - 1 = 2.

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After testing all the possible rational roots, we can see that x = 3 is an actual root of the equation.

a. To find all possible rational roots of the given equation x^4 - 2x^3 - 10x^2 + 18x + 9 = 0, we can use the Rational Zero Theorem. According to the theorem, the possible rational roots are all the factors of the constant term (9) divided by the factors of the leading coefficient (1).

The factors of 9 are ±1, ±3, and ±9.

The factors of 1 (leading coefficient) are ±1.

Combining these factors, the possible rational roots are:

±1, ±3, and ±9.

b. Now let's use synthetic division to test several possible rational roots to identify one actual root. We'll start with the first possible root, x = 1.

1 | 1 -2 -10 18 9

| 1 -1 -11 7

|------------------

1 -1 -11 7 16

The result after synthetic division is 1x^3 - 1x^2 - 11x + 7 with a remainder of 16.

Since the remainder is not zero, x = 1 is not a root

Let's try another possible root, x = -1.

-1 | 1 -2 -10 18 9

| -1 3 7 -25

|------------------

1 -3 -7 25 -16

The result after synthetic division is 1x^3 - 3x^2 - 7x + 25 with a remainder of -16.

Since the remainder is not zero, x = -1 is not a root.

We continue this process with the remaining possible rational roots: x = 3 and x = -3.

3 | 1 -2 -10 18 9

| 3 3 -21 57

|------------------

1 1 -7 39 66

-3 | 1 -2 -10 18 9

| -3 15 -15

|-----------------

1 -5 5 3 -6

After testing all the possible rational roots, we can see that x = 3 is an actual root of the equation.

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The probability that a randomly chosen yogurt shopper prefers Yogorlicious over their current brand is 0.25 or 25%.

1. Calculate the number of old people who preferred Yogorlicious: Out of the 36 old people, 12 preferred Yogorlicious.

2. Calculate the number of young people who preferred Yogorlicious: Out of the young people, 13 preferred Yogorlicious.

3. Add the number of old and young people who preferred Yogorlicious: 12 (old) + 13 (young) = 25.

4. Calculate the total number of shoppers: 36 (old) + 64 (young) = 100.

5. Divide the number of shoppers who preferred Yogorlicious by the total number of shoppers: 25 / 100 = 0.25.

The probability that a randomly chosen yogurt shopper prefers Yogorlicious over their current brand is 0.25 or 25%.

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In ICD-10-CM, only two code categories are used to report infectious arthropathies: M00 and M01.

The codes in these categories are used to describe the variety of arthropathies that can be caused by various bacterial, viral, fungal, and other infectious agents.

The M00 code group includes pyogenic arthritis, osteomyelitis, and other non-tuberculous infections of joints and bones. The M01 code category includes other types of arthritis and arthropathies caused by bacteria, viruses, fungi, and parasites, as well as other infectious agents.

Infectious arthropathies are diseases that cause joint inflammation and pain as a result of infection with a variety of infectious agents, such as bacteria, viruses, fungi, and parasites. Symptoms vary depending on the type of infection, but they usually include pain, swelling, redness, stiffness, and limited mobility.

The diagnosis of infectious arthropathies usually involves a combination of physical examination, laboratory testing, and imaging studies. Treatment usually involves antibiotics or antiviral medications, as well as pain management and physical therapy.

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The coefficient of volume expansion for ethyl alcohol is 110×10^(-6) K^(-1). The coefficient of volume expansion is a measure of how much a substance's volume changes with a change in temperature.

It represents the fractional change in volume per unit change in temperature. In the case of ethyl alcohol, the coefficient of volume expansion is given as 110×10^(-6) K^(-1). This means that for every 1 degree Celsius increase in temperature, the volume of ethyl alcohol will expand by 110×10^(-6) times its original volume.

To express the answer with appropriate units, we use the symbol K^(-1) to represent per Kelvin, indicating that the coefficient of volume expansion is expressed in terms of the change in temperature per unit change in volume.

Therefore, the coefficient of volume expansion for ethyl alcohol is 110×10^(-6) K^(-1).

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The half-life of the radioactive substance is approximately 47.16 years. It would take approximately 157.20 years for the sample to decay to 10% of its original amount.

(a) To find the half-life of the radioactive substance, we can use the formula for exponential decay:

N(t) = N₀ * (1/2)^(t / T)

where N(t) is the amount remaining after time t, N₀ is the initial amount, and T is the half-life.

Given that the substance decayed to 96.5% of its original amount after one year (t = 1), we can write the equation:

0.965 = (1/2)^(1 / T)

Taking the logarithm of both sides, we have:

log(0.965) = log((1/2)^(1 / T))

Using the logarithmic property, we can bring down the exponent:

log(0.965) = (1 / T) * log(1/2)

Solving for T, the half-life, we get:

T = -1 / (log(1/2) * log(0.965))

Evaluating this expression, we find that the half-life is approximately 47.16 years.

(b) To determine the time it would take for the sample to decay to 10% of its original amount, we can use the same formula for exponential decay:

0.1 = (1/2)^(t / T)

Taking the logarithm of both sides and solving for t, we have:

t = T * log(0.1) / log(1/2)

Substituting the previously calculated value of T, we can find that it would take approximately 157.20 years for the sample to decay to 10% of its original amount.

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(a) The amplitude of the model is 60 feet.

(b) The period of the model is 40 seconds.

(a) To find the amplitude of the model, we look at the coefficient in front of the cosine function. In this case, the coefficient is 60, so the amplitude is 60 feet.

(b) The period of the model can be determined by examining the argument of the cosine function. In this case, the argument is (π/20)t - (π/t). The period is given by the formula T = 2π/ω, where ω is the coefficient of t. In this case, ω = π/20, so the period is T = 2π/(π/20) = 40 seconds.

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A. The function has no inflection points.; B. The function has no inflection points.

To determine the intervals where the function is concave up or concave down and the x-values where the function has inflection points, we need to analyze the given derivative. The given derivative is f'(x) = 4(x + 2)/(x - 1)^3. To find where the function is concave up or concave down, we look for the points where the second derivative changes sign. Differentiating f'(x), we get: f''(x) = d/dx [4(x + 2)/(x - 1)^3] = 12(x - 1)^3 - 12(x + 2)(x - 1)^2 / (x - 1)^6 = 12(x - 1)[(x - 1)^2 - (x + 2)/(x - 1)^4] = 12(x - 1)[(x - 1)^2 - (x + 2)/(x - 1)^4]. To determine the concavity, we set f''(x) = 0 and find the critical points: 12(x - 1)[(x - 1)^2 - (x + 2)/(x - 1)^4] = 0. From this equation, we have two critical points: x = 1 and (x - 1)^2 - (x + 2)/(x - 1)^4 = 0. Now, we analyze the sign of f''(x) in different intervals: For x < 1: We choose x = 0 and substitute it into f''(x). We get f''(0) = -12. Since f''(0) is negative, the function is concave down for x < 1. For 1 < x < ∞: We choose x = 2 and substitute it into f''(x).

We get f''(2) = 12. Since f''(2) is positive, the function is concave up for 1 < x < ∞. Based on this analysis, we can conclude the following: A. The function is concave up on the interval (1, ∞). B. The function is never concave down. To determine the x-values where the function has inflection points, we need to consider the critical points. The only critical point is x = 1, but it does not satisfy the condition for an inflection point. Therefore: A. The function has no inflection points. B. The function has no inflection points.

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The probability that X is within two standard deviations of its mean is approximately 0.4232, or 42.32%.

Given Poisson distribution parameter, λ = 3Thus, Mean (μ) = λ = 3And, Standard deviation (σ) = √μ= √3Let X be a Poisson random variable.The probability that X is within two standard deviations of its mean is given by P(μ-2σ ≤ X ≤ μ+2σ)For a Poisson distribution, P(X = x) = (e^-λλ^x)/x!Where, e is a constant ≈ 2.71828The probability mass function is: f(x) = e^-λλ^x/x!Putting the given values, we get:f(x) = e^-3 3^x / x!

We know that, mean (μ) = λ = 3and standard deviation (σ) = √μ= √3Let us calculate the values of the lower and upper limits of x using the formula given below:μ-2σ ≤ X ≤ μ+2σWe have, μ = 3 and σ = √3μ-2σ = 3 - 2 √3μ+2σ = 3 + 2 √3Now, using Poisson formula:f(0) = e^-3 * 3^0 / 0! = e^-3 ≈ 0.0498f(1) = e^-3 * 3^1 / 1! = e^-3 * 3 ≈ 0.1494f(2) = e^-3 * 3^2 / 2! = e^-3 * 4.5 ≈ 0.2240P(μ-2σ ≤ X ≤ μ+2σ) = f(0) + f(1) + f(2)P(μ-2σ ≤ X ≤ μ+2σ) ≈ 0.0498 + 0.1494 + 0.2240 ≈ 0.4232The probability that X is within two standard deviations of its mean is approximately 0.4232, or 42.32%.Answer:Therefore, the probability that X is within two standard deviations of its mean is approximately 0.4232, or 42.32%.

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The loudness of the diesel truck traveling 40 miles per hour 50 feet away is 80 decibels.

To determine the loudness of the diesel truck, we need to compare its intensity to the reference intensity of 10^-12 watts per square meter. Given that the passenger car traveling at the same distance has a loudness of 70 decibels, which corresponds to an intensity 10 times lower than the reference intensity, we can calculate the intensity of the diesel truck as 10 times higher.

Using the formula L(x) = 10 log(x/I base), where x is the intensity of the sound, we substitute the intensity of the diesel truck and calculate the loudness, which turns out to be 80 decibels.

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Following the order of operations (PEMDAS/BODMAS), we first perform the addition inside the parentheses, which gives us 1.11. Then, we raise 1.11 to the power of 8, resulting in approximately 2.39749053. Finally, we multiply this result by 383, yielding approximately 917.67. When rounded to two decimal places, the final answer remains as 917.67.

To solve the expression [tex]383(1 + 0.11)^8[/tex], we first perform the addition inside the parentheses, then raise the result to the power of 8, and finally multiply it by 383.

Addition: 1 + 0.11 equals 1.11.

Exponentiation: 1.11 raised to the power of 8 equals approximately 2.39749053.

Multiplication: Multiplying 2.39749053 by 383 gives us approximately 917.67.

Rounding: Rounding 917.67 to two decimal places gives us 917.67.

Therefore, the result of the expression [tex]383(1 + 0.11)^8[/tex], rounded to two decimal places, is 917.67.

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The length of BC is 16.78 cm.

We can use the tangent function to solve for BC. The tangent function is defined as the ratio of the opposite side to the adjacent side in a right triangle. In this case, the opposite side is BC and the adjacent side is AC. Therefore, the tangent of <angle ABC> is equal to BC/AC.

We know that the tangent of <angle ABC> = 40 degrees = 0.839. We also know that AC = 20 cm.

tan(ABC) = BC/AC

tan(40 degrees) = BC/20 cm

0.839 = BC/20 cm

BC = 0.839 * 20 cm

BC = 16.78 cm

Therefore, the length of BC is 16.78 cm.

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The equation that is coincident with the curve C is y = f(x), where

f(x) = x^2 - 2x + 1. The graph of C is a parabola that opens upward.

To obtain the equation y = f(x), we substitute the given parametric equations into each other to eliminate the parameter t.

From x = t^2 - 1, we have t^2 = x + 1, which implies [tex]\(t = \sqrt{x + 1}\)[/tex] (taking the positive square root since [tex]\(t \geq 0\)[/tex].

Substituting this value of t into y = t + 2, we get [tex]\(y = \sqrt{x + 1} + 2\)[/tex].

Simplifying this equation gives us y = f(x) = x^2 - 2x + 1, which is the equation in x and y coincident with curve C.

The graph of y = f(x) is a parabola that opens upward, with its vertex at (1, 0). The coefficient of the x^2 term is positive, indicating an upward opening parabola. The curve starts at the vertex and extends infinitely to the right and left.

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When we sample from a population and n≥50, the sampling distribution of the sample mean would be Normal.In statistics, a sampling distribution is a theoretical probability distribution of the sample data's statistic. The sample data could be a subset of the data of a larger population of interest.

It's crucial to understand sampling distributions because they provide valuable information about the population when the population data cannot be collected.A sample mean is the average of the sample data set. This is calculated by adding up all the numbers in the data set and dividing by the number of observations. The sample mean is an example of a statistic that can be used to estimate a population parameter.

A sampling distribution of the sample mean is a probability distribution of all possible sample means of a particular size that can be taken from a given population. In general, when the sample size n is 30 or more, the sampling distribution is approximately normal.If n≥50, then the sample size is large enough for the central limit theorem to apply, which indicates that the sampling distribution of the sample mean is approximately normal, even if the underlying population distribution is not.

As a result, when we have a sample size of 50 or more, we can assume that the sampling distribution of the sample mean is approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

The other terms listed in the question are types of probability distributions that are used to model different types of data and are not related to the sampling distribution of the sample mean. The Poisson distribution is utilized to model count data. The Binomial distribution is utilized to model binary data. The Exponential distribution is used to model time-to-event data.

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The posterior probability P(H | D) is 0.5..The probability P(D | H) is 0.2.

Bayes' Theorem is a fundamental concept in probability and statistics that allows us to revise our probabilities of an event occurring based on new information that becomes available. It is a formula that relates the conditional probabilities of two events.

Here, we are given: P(H) = 0.5, P(D) = 0.2, P(H & D) = 0.1

The formula to find the posterior probability P(H | D) is given by:

P(H | D) = P(H & D) / P(D)

Substituting the given values, we get: P(H | D) = 0.1 / 0.2

P(H | D) = 0.5

Therefore, the posterior probability P(H | D) is 0.5. This means that given the evidence D, the probability of event H occurring is 0.5.

The formula to find the probability P(D | H) is given by:

P(D | H) = P(H & D) / P(H)

Substituting the given values, we get:P(D | H) = 0.1 / 0.5P(D | H) = 0.2

Therefore, the probability P(D | H) is 0.2.

This means that given the event H, the probability of evidence D occurring is 0.2.

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If P(B)=0.3, P(A|B)=0.5, P(B')=0.7and P(A|B')=0.8, then the value of the probability P(B|A)= 0.2113

To find the value of P(B|A), follow these steps:

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Using Cramer's rule, the solution to the system of equations is a = 2.1818.

To solve the system of equations using Cramer's rule, we first need to express the system in matrix form:

| 0.5 3 -1 | | a | | 5 |

| 1 -1 0 | * | x | = | 3 |

| 5 4 0 | | y | | 0 |

The determinant of the coefficient matrix is:

D = | 0.5 3 -1 |

      | 1 -1 0 |

      | 5 4 0 |

Expanding the determinant, we have:

D = 0.5(-1)(0) + 3(0)(5) + (-1)(1)(4) - (-1)(0)(5) - 3(1)(0.5) - (0)(4)(-1)

= 0 + 0 + (-4) - 0 - 1.5 - 0

= -5.5

Now, let's find the determinant of the matrix formed by replacing the coefficients of the 'a' variable with the constants:

Da = | 5 3 -1 |

       | 3 -1 0 |

      | 0 4 0 |

Expanding Da, we get:

Da = 5(-1)(0) + 3(0)(0) + (-1)(3)(4) - (-1)(0)(0) - 3(-1)(0) - (0)(4)(5)

= 0 + 0 + (-12) - 0 + 0 - 0

= -12

Finally, we can calculate the value of 'a' using Cramer's rule:

a = Da / D

= -12 / -5.5

= 2.1818

Therefore, the solution to the system of equations is a = 2.1818.

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1) The solution to the right triangle is:

Angle A ≈ 50°

Angle B = 40°

Angle C = 90°

Side a = 8

Side b ≈ 5.13

2)The solution to the oblique triangle is:

Angle A is determined by sin(A)/11 = sin(50°)/c

Angle B ≈ 40°

Angle C = 50°

Side a = 11

Side b = 5

Side c ≈ 10.95

1) To solve the right triangle, we are given that one angle is 40° and the length of one side, which is a = 8. We can find the remaining side lengths and angles using trigonometric ratios.

Using the sine function, we can find side b:

sin(B) = b/a

sin(40°) = b/8

b = 8 * sin(40°)

b ≈ 5.13

To find the third angle, we can use the fact that the sum of angles in a triangle is 180°:

m∠A = 180° - m∠B - m∠C

m∠A = 180° - 90° - 40°

m∠A ≈ 50°

So, the solution to the right triangle is:

Angle A ≈ 50°

Angle B = 40°

Angle C = 90°

Side a = 8

Side b ≈ 5.13

2) To solve the oblique triangle, we are given the measures of two angles, m∠C = 50° and side lengths a = 11 and b = 5. We can use the Law of Sines and Law of Cosines to find the remaining side lengths and angles.

Using the Law of Sines, we can find the third angle, m∠A:

sin(A)/a = sin(C)/c

sin(A)/11 = sin(50°)/c

c = (11 * sin(50°))/sin(A)

To find side c, we can use the Law of Cosines:

c² = a² + b² - 2ab * cos(C)

c² = 11² + 5² - 2 * 11 * 5 * cos(50°)

c ≈ 10.95

To find the remaining angle, m∠B, we can use the fact that the sum of angles in a triangle is 180°:

m∠B = 180° - m∠A - m∠C

m∠B ≈ 180° - 50° - 90°

m∠B ≈ 40°

So, the solution to the oblique triangle is:

Angle A is determined by sin(A)/11 = sin(50°)/c

Angle B ≈ 40°

Angle C = 50°

Side a = 11

Side b = 5

Side c ≈ 10.95

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