QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
WILL GIVE BRAINLIEST FOR ACCURATE ANWSER
The Area of the shaded region of the circle = 60.75π m²
The Length of arc ADB = ∅/360 × 2πr = 13.5π m.
What is the Area of a Shaded Region?The area of the shaded region in the circle = area of the sector of a circle = ∅/360 × πr², where r is the radius of the circle and the central angle is ∅.
What is the Length of an Arc of a Circle?The length of the arc on a circle = ∅/360 × 2πr, where r is the radius of the circle and the central angle is ∅.
Given the following:
Central angle (∅) = 360 - 90 = 270°
Radius (r) = 9 m.
Area of the shaded region of the circle = ∅/360 × πr² = 270/360 × π(9²)
Area of the shaded region of the circle = 270/360 × π81
Area of the shaded region of the circle = 60.75π m²
Length of arc ADB = ∅/360 × 2πr = 270/360 × 2π(9)
Length of arc ADB = ∅/360 × 2πr = 270/360 × 18π
Length of arc ADB = ∅/360 × 2πr = 13.5π m.
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The length of a rectangular poster is 5 more inches than half its width. The area of the poster is 12 square inches. Solve for the dimensions (length and width) of the poster.
The dimensions (length and width) of the poster are 6 inches and 2 inches
How to determine the dimensions (length and width) of the poster?Represent the length with x and the width with y
From the question, we have the following parameters
x = 5 + 0.5y
Area, A = 12
The area of a rectangle is represented as:
A = xy
Substitute the known values in the above equation
(5 + 0.5y) * y = 12
Expand the bracket
5y + 0.5y^2 = 12
Multiply through by 2
10y + y^2 = 24
Rewrite as:
y^2 + 10y - 24 = 0
Expand
y^2 + 12y - 2y - 24 = 0
Factorize the expression
(y - 2)(y + 12) = 0
Solve for y
y = 2 or y = -12
The dimension cannot be negative.
So, we have
y = 2
Substitute y = 2 in x = 5 + 0.5y
x = 5 + 0.5 * 2
Evaluate
x = 6
Hence, the dimensions (length and width) of the poster are 6 inches and 2 inches
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Instructions: Identify the vertices of the feasible region and use them to find the maximum and/or minimum value for the given linear programming constraints.
System of Linear Programming:
z=−3x+5y
x+y≥−22
x−y≥−4
x−y≤2
Minimum value of z:
The minimum value of z is -38
How to identify the vertices of the feasible region for the given linear programming constraints?The optimization equation is given as
z=−3x+5y
The constraints are given as:
x+y≥−2
3x−y≤2
x−y≥−4
Next, we plot the constraints on a graph and determine the points of intersections
See attachment for the graph
From the attached graph, the points of intersections are
(-9, -13) and (-10, -12)
So, we have:
(-9, -13)
(-10, -12)
Substitute these values in the objective function
z=−3x+5y
This gives
z= −3 * -9 +5 * -13 = -38
z= −3 * -10 +5 * -12 = -30
-38 is less than -30
Hence, the minimum value of z is -38
So, the complete parameters are:
Optimization Equation:
z=−3x+5y
Constraints:
x+y≥−2
3x−y≤2
x−y≥−4
Vertices of the feasible region
(0, -2)
(-3, 1)
(3, 7)
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Database A contains 40 data items and is made up with an equal number of the values of 0 and 100 and has a mean of 50. Database B also has 40 entries made up equally of the values 49 and51 and also has a mean of 50. Which database will have the smaller value for its standard deviation?
If we compare the given values then we can find that the database B is more likely to have smaller standard deviation.
Given that the values in database A are 0 from 100 and has mean of 50 and Database B has entries from 49 to 51 and also has mean of 50.
We are required to find the database whose standard deviation is lower.
Standard deviation measures the variation of values. It is calculated after finding mean. The square of a standard deviation is known as variance.
Database A has values from 0 to 100 and has mean of 50. Because the values are somewhat very larger than 50 and in database B has values from 49 to 51,there are more chances that the standard deviation of database B will have smaller value than from standard deviation of database A.
Hence if we compare the given values then we can find that the database B is more likely to have smaller standard deviation.
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A TEACHER IS CONSTRUCTING A MATHEMATICS TEST
CONSISTING OF 10 QUESTIONS. SHE HAS A POOL OF 28 QUESTIONS, WHICH ARE
CLASSIFIED BY LEVEL OF DIFFICULTY AS FOLLOWS: 6 DIFFICULT QUESTIONS, 10
AVERAGE QUESTIONS, AND 12 EASY QUESTIONS. HOW MANY DIFFERENT 10
QUESTION TESTS CAN SHE CONSTRUCT FROM THE POOL OF 28 QUESTIONS IF
HER TEST IS TO HAVE 3 DIFFICULT, 4 AVERAGE, AND 3 EASY QUESTIONS?
The number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is 924, 000 ways
How to determine the combinationNote that the formula for combination is given as;
Combination = [tex]\frac{n!}{r!(n-r)!}[/tex]
From the information we have that;
There are 28 questions in the pool
The test should have a total of 10 questions;
6 difficult , 10 average and 12 easy questions
We are asked to determine the combination of;
3 difficult questions
4 average questions
3 easy questions
6C3 = [tex]\frac{6!}{3!(6-3)!}[/tex]
6C3 = [tex]\frac{720}{36}[/tex]
6C3 = 20
10C4 = [tex]\frac{10!}{4!(10-4)!}[/tex]
10C4 = [tex]\frac{3628800}{17280}[/tex]
10C4 = 210
12C4 = [tex]\frac{12!}{4!(12-4)!}[/tex]
12C4 = 220
The number of ways of constructing the questions is
= 20 × 210 × 220
= 924, 000 ways
Thus, the number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is 924, 000 ways
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The Department of Motor Vehicles reports that the proportion of all vehicles registered in
California that are imports is 0.22.
ords
1. Is the number 0.22?
a population proportion.
a.
b. a sample proportion.
2. Which of the following use of notation is correct?
a. p=0.22
b. p=0.22
The number 0.22 represents the population proportion and the correct way to represent it is p = 0.22.
What are statistics?Statistics is a mathematical tool defined as the study of collecting data, analysis, understanding, representation, and organization. Statistics is described as the procedure of collecting data, classifying it, displaying that in a way that makes it easy to understand, and analyzing it even further.
It is given that:
It is given that:
The Department of Motor Vehicles reports that the proportion of all vehicles registered in California that are imported is 0.22.
The number 0.22 represent the population proportion.
The population proportion can be represented by the letter p:
p = 0.22
Thus, the number 0.22 represents the population proportion, and the correct way to represent it is p = 0.22.
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A rectangle is 6x-4 feet long and 2x + 3 feet wide. What is the perimeter of the rectangle?
Answer:
Perimeter o the rectangle = 16x - 2
Step-by-step explanation:
Perimeter of a rectangle = 2(long+ wide)
Then:
Perimeter = 2((6x-4)+(2x+3))
Perimeter = 2(6x+ 2x + 3 - 4)
Perimeter = 2(8x - 1)
Perimeter = 2*8x + 2*-1
Perimeter = 16x - 2
what is (4x8) divided by (8+2)
Answer:
3.2
Step-by-step explanation:
4 x 8 / 8 + 2
32/10
=3.2
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Divide
8x⁴-6x³+2÷2x²+3
WhenWhen we divide 8x⁴ - 6x³ + 2 by 2x² + 3 The result obtained is 4x² - 3x - 6 remainder 9x + 20
What is quotient?Quotient is the result obtained when division operation is carried out.
For example when 6 is divided by 2, the result obtained is 3. Thus, the quotient is 3
How to divide 8x⁴ - 6x³ + 2 by 2x² + 3To divide 8x⁴ - 6x³ + 2 by 2x² + 3, we shall apply the long division method. This is illustrated below:
4x² - 3x - 6
2x² + 3 | 8x⁴ - 6x³ + 2
-(8x⁴ + 12x²)
-6x³ - 12x² + 2
-(-6x³ - 9x)
-12x² + 9x + 2
-(-12x² - 18)
9x + 20
Thus, the result obtained when we divide 8x⁴ - 6x³ + 2 by 2x² + 3 is 4x² - 3x - 6 remainder 9x + 20
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Solve the right triangle.
b= 1.26 c=4.58
Need answers for A,B,a
I keep getting it wrong.
Answer:
a=4.40
Step-by-step explanation:
To find value of a use pythagoras theorem:
c^2=b^2+a^2
Rearrange the equation:
a^2=c^2-b^2
Substitute the values:
a^2=(4.58)^2-(1.26)^2
After calculation:
a=4.40
The cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks. The property has 67 feet of frontage on one sidewalk, and 48 feet of frontage on another; these two sidewalks intersect at a 72° angle. What is the square footage of the cheetahs' habitat? Round to the nearest hundredth.
1529.3 square unit is the area of the cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks, given that the property has 67 feet of frontage on one sidewalk, and 48 feet of frontage on another; these two sidewalks intersect at a 72° angle. This can obtained by using the formula of Area of a Triangle with 2 Sides and Included Angle.
Find the area of the cheetah area at the zoo:Area of a triangle is obtained using the formula of Area of a Triangle with 2 Sides and Included Angle.
If in a triangle ΔABC,
1/2 × bc × sin(A), if b and c are two sides of a triangle and angle A is the included angle1/2 × ac × sin(B), if a and c are two sides of a triangle and angle B is the included angle1/2 × ab × sin(C), if a and b are two sides of a triangle and angle C is the included angleHere it is given that,
67 feet and 48 feet are the sides of the triangular space and angle 72° is the included angle.
By using the formula of Area of a Triangle with 2 Sides and Included Angle,
Area of the cheetah area = 1/2 × bc × sin(A)
Area of the cheetah area = 1/2 × (67)(48) × sin(72°)
sin(72°) = 0.951056516
Area of the cheetah area = 1608 × 0.951056516
Area of the cheetah area = 1529.29888 ≈ 1529.3 square unit
Hence 1529.3 square unit is the area of the cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks, given that the property has 67 feet of frontage on one sidewalk, and 48 feet of frontage on another; these two sidewalks intersect at a 72° angle.
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Remy obtains a 30-year mortgage in the amount of $625,000 for a co-op. She secures a 7/1 ARM at an initial interest rate of 3%. Her initial monthly payment is $2,635.03. After 7 years, the interest rate on her loan changes to 4.925%. Calculate her new monthly payment in year 8 of the loan. (Round your answer to the nearest cent.)
$
According to the adjustable-rate mortgage The new monthly payment in year 8 of the loan is $1292.
According o the statement
we have given that the
Remy obtains a 30-year mortgage in the amount of $625,000 And
She secures a 7/1 ARM at an initial interest rate of 3%. Her initial monthly payment is $2,635.03.
And we have to find the new monthly payment when its interest rate increased to the 4.925%.
So, For this purpose we know that the
An adjustable-rate mortgage (ARM) is a loan with an interest rate that changes.
The amount in which she bought mortgage = 625,000
Interest rate = 3%
Initial amount = 2635.03
From this it clear that the
The amount she pays in 7 years = 2635.03*7
The amount she pays in 7 years = 18445.21
The left amount = 625,000 - 18445.21
The left amount = 606554
It means the rate of interest increased on the amount 606554$
So, According to the 4.925% interest the monthly payment will become
amount on interest rate 4.925% = 4.925% *606554/23 years
amount on interest rate 4.925% = $1292.
So, According to the adjustable-rate mortgage The new monthly payment in year 8 of the loan is $1292.
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2 x 4 + 48000 / 8 - 1 x 30 x 2 + 40000
Answer:12002/9987
Step-by-step explanation:
A cyclist covers a distance of 900m in 4min 30sec. what is the speed in km/h of the cyclist?
Answer:
12km/h
Step-by-step explanation:
s=d/t
900m is 0.9km and 4min and 30sec is 0.075h
0.9/0.075=12 which gives us 12km/h
Answer:
Step-by-step explanation:
4 min 30 seconds = 270 seconds
900m = 270 seconds
100m = 30 seconds
1000m= 300 seconds (5min)
12,000m=3600seconds (60min)
Answer = 12km/h
can someone help me with all these questions?
1a. 98 cm ^2
1b. 76. 98 cm^2
2a. 42cm
2b. 7. 19 cm
3. a + b/2 (h)
4. 24 cm ^2
5. πr + 2r
6. 13. 2m
7. 45cm^2
8. 252 cm ^ 2
9. 450 cm^ 2
How to solve the area1a. The shape given is a rectangle
The formula for area of a rectangle is given as;
Area = length × width
Area = 7 × 14
Area = 98 cm ^2
1b The shape given is a semi circle
The formula for area of a semicircle is given as;
Area = 1/2 π r^2
radius = diameter/2 = 14/2 = 7cm
Area = 1/2 × 3.142 × 7 × 7
Area = 76. 98 cm^2
2a. The shape given is a rectangle
The formula for perimeter of a rectangle is given as;
Perimeter = 2 ( length + width)
Perimeter = 2 ( 14 + 7) = 2( 21)
Perimeter = 42cm
2b. The shape is a semicircle
Perimeter = π r + 2r
r= 1.4cm; diameter divided by 2
Perimeter = 3. 142(1.4) + 2(1.4)
Perimeter = 7. 19 cm
3. The formula for area of a trapezium is given as
Area = a + b/2 (h)
4. The area of the trapezium is given as;
Area = 9 + 7/2 (3)
Area = 16/2 (3)
Area = 8 × 3
Area = 24 cm ^2
5. Area of semicircle = 1/2 πr^2
Perimeter of a semicircle = πr + 2r
6. From the information given, we have the following
Area = 480 m^2
a = 20m
b = unknown
h = 13. 2m
Area = a+b/2 (h)
Substitute the values
480 = 20+b/2 (13. 2)
480 = 10+ b (13. 2)
480/13. 2 = 10 + b
10+ b = 480/ 13. 2
10 + b = 36. 36
b = 36.36 - 10
b = 26. 36m
7. The formula for area of a rhombus is given as
Area = p × q/2
Where p and q are the diagonals
Area = 7. 5 × 12/2
Area = 90/2
Area = 45cm^2
8. The formula for area for a quadrilateral is given as;
Area of quadrilateral = (½) × diagonal length × sum of the length of the perpendiculars
sum of the length = 13 + 8 = 21cm
Diagonal A= 24cm
Area = 1/2 × 24 × 21
Area = 252 cm ^ 2
9. Area of a pentagonal park = 1/2 × sum of parallel sides × height
Sum of parallel sides = 15 + 15 = 30 cm
height = 30cm
Area = 1/2 × 30 × 30
Area = 450 cm^ 2
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Can someone help me with Algebra 2?
1. Solving linear equations:
(a) x = 4.
(b) r = 2/3.
2. Proportion:
(a) When x = 40, y = 100.
(b) When x = 40, y = 4.
3. System of equations:
(a) r = 8, s = 3.
(b) p = 5, q = -2.
4. Graphing lines:
(a) The slope of the line through (3, 4) and (-1, 3) is 1/4.
(b) The slope of the line 3x - 4y = 7 is 3/4.
(c) The slope-intercept form of the line through (5, -2) and (-1, 6) is y = (-4/3)x + 14/3.
5. Introductory quadratics:
(a) The solutions to the equation 4x² = 81 are -9/2, and 9/2.
(b) The solutions to the equation x² + 8x + 12 are -6, and -2.
(c) The solutions to the equation x² - 3x - 88 are -8, and 11.
6. The weight of an orange is 1 unit, the weight of an apple is 5 units, and the weight of a banana is 2 units.
7. x = 3.
1. Solving linear equations:
(a) 3x - 7 = 9 - x,
or, 3x + x = 9 + 7,
or, 4x = 16,
or, x = 16/4 = 4.
Thus, x = 4.
(b) (7 - 2r)/3 = 4r,
or, 7 - 2r = 3*4r = 12r,
or, -2r - 12r = -7,
or, -14r = -7,
or, r = -7/-14 = 1/2.
Thus, r = 1/2.
2. Proportion:
(a) x and y directly proportion, means x/y = constant.
When x = 8, y = 20.
Thus, x/y = constant, or, 8/20 = constant, or, constant = 0.4.
When x = 40,
x/y = 0.4,
or, y = x/0.4 = 40/0.4 = 100.
Thus, when x = 40, y = 100.
(b) x and y indirectly proportion, means xy = constant.
When x = 8, y = 20.
Thus, xy = constant, or, 8*20 = constant, or, constant = 160.
When x = 40,
xy = 160,
or, 40y = 160,
or, y = 160/40 = 4.
Thus, when x = 40, y = 4.
3. System of equations:
(a) r - s = 5 ...(i)
3r - 5s = 9 ... (ii)
3*(i) - (ii) gives:
3r - 3s = 15
3r - 5s = 9
(-) (+) (-)
_________
2s = 6,
or, s = 3.
Substituting in (i), we get
r - s = 5,
or, r - 3 = 5,
or, r = 8.
Thus, r = 8, s = 3.
(b) 3p + 7q = 1 ...(i).
5p = 14q + 53,
or, 5p - 14q = 53 ...(ii).
2*(i) + (ii) gives:
6p + 14q = 2
5p - 14q = 53
____________
11p = 55,
or, p = 5.
Substituting in (i), we get:
3p + 7q = 1,
or, 3*5 + 7q = 1,
or, 7q = 1 - 15 = -14,
or, q = -14/7 = -2.
Thus, p = 5, q = -2.
4. Graphing lines:
(a) Slope of the line through (3, 4) and (-1, 3) is,
m = (4 - 3)/(3 - (-1)),
or, m = 1/4.
Thus, the slope of the line through (3, 4) and (-1, 3) is 1/4.
(b) The graph given: 3x - 4y = 7.
Representing in the slope-intercept form, y = mx + b, gives:
3x - 4y = 7,
or, 4y = 3x - 7,
or, y = (3/4)x + (-7/4).
Thus, the slope of the line 3x - 4y = 7 is 3/4.
(c) Slope of the line through (5, -2) and (-1, 6) is,
m = (6 - (-2))/(-1 - 5),
or, m = 8/(-6) = -4/3.
Substituting m = -4/3 in the slope-intercept form, y = mx + b, gives:
y = (-4/3)x + b.
Substituting y = 6, and x = -1 gives:
6 = (-4/3)(-1) + b,
or, b = 6 - 4/3 = 14/3.
Thus, the slope-intercept form of the line through (5, -2) and (-1, 6) is y = (-4/3)x + 14/3.
5. Introductory quadratics:
(a) 4x² = 81,
or, 4x² - 81 = 0,
or (2x)² - 9² = 0,
or, (2x + 9)(2x - 9) = 0.
Either, 2x + 9 = 0 ⇒ x = -9/2,
or, 2x - 9 = 0 ⇒ x = 9/2.
Thus, the solutions to the equation 4x² = 81 are -9/2, and 9/2.
(b) x² + 8x + 12 = 0,
or, x² + 2x + 6x + 12 = 0,
or, x(x + 2) + 6(x + 2) = 0,
or, (x + 6)(x + 2) = 0.
Either, x + 6 = 0 ⇒ x = -6,
or, x + 2 = 0 ⇒ x = -2.
Thus, the solutions to the equation x² + 8x + 12 are -6, and -2.
(c) x² - 3x - 88 = 0,
or, x² - 11x + 8x - 88 = 0,
or, x(x - 11) + 8(x - 11) = 0,
or, (x + 8)(x - 11) = 0.
Either, x + 8 = 0 ⇒ x = -8,
or, x - 11 = 0 ⇒ x = 11.
Thus, the solutions to the equation x² - 3x - 88 are -8, and 11.
6. We assume the weight of one orange, one apple, and one banana to be x, y, and z units respectively.
Thus, we have:
3x + 2y + z = 15 ... (i)
5x + 7y + 2z = 44 ... (ii)
x + 3y + 5z = 26 ... (iii)
2(i) - (ii) gives:
6x + 4y + 2z = 30
5x + 7y + 2z = 44
(-) (-) (-) (-)
______________
x - 3y = -14 ... (iv)
5(i) - (iii) gives:
15x + 10y + 5z = 75
x + 3y + 5z = 26
(-) (-) (-) (-)
________________
14x + 7y = 49 ... (v)
14(iv) - (v) gives:
14x - 42y = -196
14x + 7y = 49
(-) (-) (-)
_____________
-49y = -245,
or, y = 5.
Substituting in (v), we get:
14x + 7y = 49,
or, 14x + 35 = 49,
or, x = 14/14 = 1.
Substituting x = 1 and y = 5 in (i), we get:
3x + 2y + z = 15,
or, 3 + 10 + z = 15,
or, z = 2.
Thus, the weight of an orange is 1 unit, the weight of an apple is 5 units, and the weight of a banana is 2 units.
7. 3/(1 - (2/x)) = 3x,
or, 3/((x - 2)/x) = 3x,
or, 3x/(x - 2) = 3x,
or, 3x = 3x(x - 2),
or, 3x = 3x² - 6x,
or, 3x² - 9x = 0,
or, 3x(x - 3) = 0.
Either, 3x = 0 ⇒ x = 0,
or, x - 3 = 0 ⇒ x = 3.
Since we had a term 2/x, x cannot be 0.
Thus, x = 3.
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WILL GIVE BRAINLIEST
3. Add or subtract the following terms:
a. (10x) + (22x) =
b. (-6x) - (-6x) =
c. (-13t) + (14x) - (+13t) =
d. (-4t) + (+4t) - (-3t) =
The simplified forms of the given expressions are
a. 32x
b. 0
c. -26t + 14x
d. 3t
Simplifying an expressionFrom the question, we are to simplify the given expressions by adding or subtracting
a. (10x) + (22x)
= 32x
b. (-6x) - (-6x)
= -6x + 6x
= 0
c. (-13t) + (14x) - (+13t)
= -13t + 14x - 13t
Collect like terms
= -13t -13t + 14x
= -26t + 14x
d. (-4t) + (+4t) - (-3t)
= -4t + 4t + 3t
= 3t
Hence, the simplified forms of the given expressions are
a. 32x
b. 0
c. -26t + 14x
d. 3t
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please solve this question asap
Step-by-step explanation:
[tex]y = \sqrt{4x + 6} [/tex]
[tex] {y}^{2} = 4x + 6[/tex]
[tex] {y}^{2} - 6 = 4x[/tex]
[tex] \frac{1}{4} ( {y}^{2} - 6) = x[/tex]
Swap x and y
[tex] \frac{ {x}^{2} - 6 }{4} = y[/tex]
X+2y=5 and 4x-12y=-20 solve using elimination and substitution
Answer:
(1,2)
Step-by-step explanation:
Substitution:
x + 2y = 5 Solve for x
x = -2y + 5 Substitute -2y + 5 in for x in the second equation
4x - 12y = -20
4(-2y + 5) - 12y = -20 Distribute the 4
-8y + 20 - 12 y = -20 Combine the y term
-20y + 20 = -20 Subtract 20 from both sides
-20y = -40 Divide both sides by -20
y = 2
Plug y into either of the 2 original equations to get x.
x + 2y = 5
x + 2(2) = 5
x + 4 = 5
x = 1
The answer is (2,1).
Elimination:
x + 2y = 5 4x - 12y = -20. We want to eliminate with the x or the y. I am going to eliminate the x's that means that I have to multiply the first equation all the way through by -4
(-4)(x + 2y) = (5) (-4) That makes the equivalent expression
-4x - 8y = -20 I will add that to 4x - 12y = -20
4x - 12y = -20
0x -20y = -40
-20y = -40
y = 2. Plug 2 into either the 2 original equation to find x. This time I will select the second original equation to find x.
4x -12y = -20
4x - 12(2) = -20
4x - 24 = -20
4x = 4
x = 1
−5y2−3y−2, when y=2.
y=2
-5(2)²-3(2)-2
-5(4)-3(2)-2
-20-6-2
=12
An electrician plans to install solar panels on a rectangular section of roof with an area 180m2. This width of this section of roof is 7 1/5 m across. What is the length of this section of roof?
Answer: I believe the answer is 25.
Step-by-step explanation:
You convert 1/5 to a decimal.
1/5 = 0.2
then you divide
180 divided by 7.2 = 25
answer is 25.
Which of the following is a solution of x² + 5x = -2?
05± √/33
2
5+√17
2
-5± √√33
2
-5± √17
2
Answer:last option -5± √17
2
Step-by-step explanation:
Quadratic equations represent any equation that can be rearranged in standard forma (ax² + bx + c( =0(a, b & c) are known.
Quadratic equations can always be solved using the quadratic formula, but sometimes factoring or isolating the variable is also posible.
In the square equation ax² + bx + c = 0
a = 1 b = 5 c = 2[tex]\boldsymbol{\sf{x=\dfrac{-b\pm\sqrt{\Delta} }{2a} \ ,\Delta=b^{2}-4ac } }[/tex]
Let's calculate the discriminant of the quadratic equation:
∆ = b² - 4ac = 5² - 4 1 2 = 25 - 8 = 17Since the discriminant is greater than zero, then the quadratic equation has two real roots.
[tex]\boldsymbol{\sf{x_{1}=\dfrac{-b-\sqrt{\Delta} }{ 2\cdot a}=\dfrac{-5-\sqrt{17} }{2\cdot1} }}[/tex]
[tex]\boldsymbol{\sf{x_{2}=\dfrac{-b+\sqrt{\Delta} }{ 2\cdot a}=\dfrac{-5+\sqrt{17} }{2\cdot1} }}[/tex]
Solution:
[tex]\boldsymbol{\sf{x=\dfrac{-5\pm\sqrt{17} }{2} }}[/tex]
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2.6 km
Area = 20.8 km²
What is the height of Thai rectangle?
What are two ordered pairs that the midpoint is (4, -10)? Please show that your points work.
The two ordered pairs that the mid point is (4,-10) are (4,-20),(4,0) & (4,0),(4,-20).
Given the coordinates of mid point be (4,-10).
We are required to find the ordered pairs that the mid point is (4,-20).
Coordinates show positions of points or something else on a surface.
There are various combinations whose mid point is (4,-10).
First are (4,-20),(4,0).
Mid point =[(4+4)/2,(-20+0)/2]
=(4,-10)
Second are (4,0) , (4,-20)
Mid point=[(4+4)/2,(0-20)/2]
=(4,-10)
Third are (8,-20),(0,0)
Mid point=[(8+0)/2,(-20+0)/2]
=(4,-10)
Fourth are (0,-20),(8,0)
Mid point =[(0+8)/2,(-10+0)/2]
=(4,-10)
Hence the ordered pairs that the mid point is (4,-10) are (4,-20),(4,0) & (4,0),(4,-20)& (8,-20),(0,0)&(0,-20),(8,0)&(0,0),(8,-20).etc.
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Which of the following is the equation of the line that passes through the points (-3,4) and (6,7)?
The equation of the line that passes through the given points is
y = 1/3x + 5.
What is the formula for calculating the equation of a line passing through two points?The formula for the equation of a line passing through two points (x1, y1) and (x2, y2) is
[tex](y-y1) = \frac{(y2-y1)}{(x2-x1)} (x-x1)[/tex]
Where the fraction (y2 - y1)/(x2 - x1) is the slope of the line denoted by 'm'.
Calculation:It is given that, a line passes through the points (-3,4) and (6,7).
So, the equation of the line is
[tex](y-y1) = \frac{(y2-y1)}{(x2-x1)} (x-x1)[/tex]
On substituting x1 = -3, y1 = 4, x2 = 6, and y2 = 7
(y - 4) = [(7 - 4)/(6 + 3)](x + 3)
⇒ (y - 4) = (3/9)(x + 3)
⇒ (y - 4) = 1/3(x + 3)
⇒ y- 4 = 1/3x + 1
⇒ y = 1/3x + 1 + 4
∴ y = 1/3x + 5
Thus, the equation of the line passing through the points (-3,4) and (6,7) is y = 1/3x + 5. Where the slope m = 1/3.
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How to solve these questions?
(with work)
The angles and length of the triangle area as follows:
∠CBD = 61°∠A = 35°AD = 32.77 unitsBD = 22.94 unitsBC = 11.12 unitsCD = 9.73 unitsHow to find the sides and angle of a triangle?The sum of angles in a triangle is 180 degree.
Therefore,
∠DBC = 180 - 29 - 90 = 61°
Hence,
∠A = 180 - 29 - 61 - 55 = 35°
∠CBD = 61°
Using trigonometric ratios,
sin 55 = opposite / hypotenuse
sin 55 = AD / 40
AD = 40 sin 55
AD = 32.7660817716
AD = 32.77 units
cos 55 = adjacent / hypotenuse
cos 55 = BD / 40
BD = 40 cos 55
BD = 22.943057454
BD = 22.94 units
sin 29 = 22.94 / BC
BC = 22.94 sin 29
BC = 11.1215326885
BC = 11.12 units
cos 29 = CD / 11.12
CD = 11.12 cos 29
CD = 9.72577114339
CD = 9.73 units
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y=3x-4 and y= -x+2 to find the system of equations
Answer:
x=3/2 y=1/2
Step-by-step explanation:
Find the value of the combination. 10C0
Answer:
1.
Step-by-step explanation:
10C0 = 1.
Two angles of a quadrilateral are of measures 75° and 117° respectively and the other two angles are equal find the measure of each of the equal angles
Answer:
Step-by-step explanation:
The sum of interior angles of a quadrilateral is 360°.
If we consider the measure of one of the unknown angles to be [tex]x[/tex]°, we can set up the following equation:
[tex]x + x + 75^\circ + 117^\circ = 360^\circ[/tex]
Now we can solve for [tex]x[/tex]:
⇒ [tex]2x + 192^\circ = 360^\circ[/tex]
⇒ [tex]2x = 360^\circ - 192^\circ[/tex] [subtracting 192° from both sides]
⇒ [tex]2x = 168^\circ[/tex]
⇒ [tex]x = \frac{168^\circ}{2}[/tex] [dividing both sides by 2]
⇒ [tex]x = \bf84^\circ[/tex]
Therefore, the other two angles each have a measure of 84°.
1. Transform each blue piece so that the boat changes from blue to red. Try to use as few transformations as possible to complete the task! 2. TIP: Be sure to move the blue pieces so that the corresponding letters match at the same point. 3. Write down the specific stops you made to transform the shapes in your notebook.
a. What transformations would you use on the blue segments CD to get it to match with the red segments C2D2? Explain your movement using the coordinates of the vertices.
b. What transformations would you use on the blue triangle to get it to match with the red triangle? Explain your movement using the coordinates of the vertices.
c. Which line segments on the boat are parallel? Explain your answer.
d. Which line segments on the boat are perpendicular? Explain your answer.
e. Which line segments on the boat have a slope of 0? Explain your answer.
f. Which line segments on the boat have an undefined slope? Explain your answer.
7. What is the slope of ED? Explain your answer using the change in coordinates given that E is at (-11, 4) and D is at (-10, 5).
A) Rotate by 90° counterclockwise.
B) Reflection transformation about the line y = 5.
C) Parallel Lines are C₂D₂ and A₂B₂; EF and E₁F₁.
D) Perpendicular lines are; D₁F₁ and E₁F₁; DF and EF; DC and AB.
E) Line segments with slope of 0 are; AB, C₂D₂, A₂B₂, EF and E₁F₁
F) Line segments on the boat that have an undefined slope are; Lines A₁B₁, DF and DC.
G) Slope of Line ED = 1
How to carry out Transformations?A) The blue segment CD is seen on the graph as a perpendicular line with 2 units while the line segment C₂D₂ is seen as a horizontal line. Thus, to match CD with C₂D₂, we will rotate by 90° counterclockwise.
B) The transformations that would be used on the blue triangle to get it to match with the red triangle is a reflection transformation about the line y = 5.
C) The line segments that are parallel to each other are; C₂D₂ and A₂B₂; EF and E₁F₁.
D) The line segments that are perpendicular are; D₁F₁ and E₁F₁; DF and EF; DC and AB.
E) Horizontal lines that are parallel to the x-axis have zero slope. Thus, AB, C₂D₂, A₂B₂, EF and E₁F₁ all have zero slopes.
F) Undefined slope is the slope of a vertical line. Thus, Lines A₁B₁, DF and DC have undefined slopes.
G) Slope of ED = (5 - 4)/(-10 - (-11))
Slope of ED = 1/1
Slope = 1
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