A light wave moves from diamond (n= 2.4) into water (n= 1.33) at an angleof 24°. what angle does it have in water?

Answers

Answer 1

Answer:

n1 sin θ1 = n2 sin θ2      Snell's Law       (θ1 is the angle of incidence)

sin θ2 = n1 / n2 * sin θ1

sin θ2 = 2.4 / 1.33 * sin θ1

sin θ2 = 1.80 * .407 = .734

θ2 = 47.2 deg


Related Questions

The air supplied to a diaphragm is 20 psig, and the diaphragm has a diameter of 6 in. how much pressure can this diaphragm apply to a plunger?

Answers

565.2 lbs pressure can apply to a plunger.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. symbol: p or P.

It is given that,

The air supplied to a diaphragm is 20 psig.

Diameter is 6

Then r=3

We know that,

Area=

πr²

=(3.14×3²)

= 28.26

The formula is (3.14 ×radius of diaphragm squared) ×psig.

=( 28.26 ×20)

= 565.2 lbs of pressure.

Hence, the pressure is  565.2 lbs.

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What is the separation in meters between two slits for which 617 nm orange light has its first maximum at an angle of 29. 8°?

Answers

The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.

For ease of calculations we take 29.8° = 30°

Using the relation :

[tex]\frac{m * λ }{sin\theta}[/tex]

where :

d = distance between the slits

θ = 30°

λ = wavelength of light = 617 nm = 6.17 x 10⁻⁷ m

m = 1

Substituting the values into the equation :

d = 1 x 6.17 x 10⁻⁷ / 0.5 = 0.00000122 = 1.22 x 10⁻⁶ m

Therefore, the seperation between the two slits is 1.22 x 10⁻⁶ m.

The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.

This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.

With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.

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Which element of the security policy framework offers suggestions rather than mandatory actions?

Answers

The element Guideline of the security policy framework offers suggestions rather than mandatory actions.

To find the answer, we have to know more about the security policy framework.

What is security policy framework?Any rule or policy's guidelines refer to some crucial details that help people understand the regulations. If there are no rules for something, nobody will be aware of that specific thing. The answer to the inquiry regarding the term that is the framework and capable of providing the details for any policy is guideline.

Thus, we can conclude that, the element Guideline of the security policy framework offers suggestions rather than mandatory actions.

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A force of 100 N to the east and a force or 100 N to the west both act on an object of 10 kg. What is the acceleration of the object?

A. 10 m/s2 to the east

B. 100 m/s2 to the west

C. 0 m/s2, it does not accelerate

D. 100 m/s2 to the east

Answers

Answer:

C, it doesnt accelerate

Explanation:

F=ma

F = 100 east + 100 west

F = 100 east + (-100 east)

F = 0

0 = ma

in order to isolate acceleration, we would be dividing 0 by mass, which would equal 0

For a reaction that follows the rate law of, rate = k[b]2 when [a] = 0.15 m, [b] = 0.12 m, the rate is 3.4 10−3 m s−1. what is the value and unit of rate constant k?

Answers

The value and unit of rate constant k are 1.61[tex]M^{-1} S^{-1}[/tex]

The rate law of a reaction correlates the concentration of reactants with the rate of the reaction. The rate of a reaction is always proportional to the concentration of reactants. Hence, a proportionality constant (called as the rate constant) is always present in the rate law.

Rate = k [tex][A][B]^{2}[/tex]

Rate = k [tex][0.15][0.12]^{2}[/tex]

3.4×[tex]10^{-3}[/tex] = k 0.0021

k = 1.61[tex]M^{-1} S^{-1}[/tex]

Therefore, the value and unit of rate constant k are 1.61[tex]M^{-1} S^{-1}[/tex]

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Identify the saturation pressure corresponding to 32 degrees fahrenheit for r - 123

Answers

Hg vacuum at 20 inches is the saturation pressure that corresponds to 32 degrees Fahrenheit of R-123.

To find the answer, we need to know more about the saturation pressure.

What is saturation pressure?The saturation pressure is the pressure at which a vapor is in equilibrium with its liquid (such as steam with water).It is the highest pressure that water vapor can get at a particular temperature.R-123 refrigerant is probably hard to find these days. It was discovered that chlorine-containing refrigerants have the potential to actively harm the Ozone layer if they are released into the atmosphere.The saturation pressure that corresponds to 32 degrees Fahrenheit of R-123 is 20 inches Hg vacuum.

Thus, we can conclude that, Hg vacuum at 20 inches is the saturation pressure that corresponds to 32 degrees Fahrenheit of R-123.

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In the model from the lesson, what did the moped riders represent?
A. Angry customers
B. Battery
C. Resistance
D. Flow of charge

Answers

Moped riding represent angry customers in the model from the lesson.

What is moped riding?

Moped riding refers to the riding of a special type of small motorcycle, generally having a less stringent licensing requirement than full motorcycles or automobiles.

Generally, the word "moped riding" describes any two-wheeledth with a step-through chassis and footrest platform. These two-wheeled vehicle are usually equipped with bicycle-like pedals that the rider uses to propel the vehicles.

Although motorcycles are usually very harder to learn to ride

The following are other types of riders:

Climber.Puncheur.Breakaway specialist, or baroudeur.Time trialist.Rouleur.Sprinter.Domestique.All-rounder.

So therefore, moped riding represent angry customers in the model from the lesson.

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An ultrasound tech is trying to identify an object, but the machine is broken and is not sending out the sound wave. Which statement best describes this situation?

The generated sound wave will not be able to reflect off of the object.
The sound wave will not be generated, so there will be no echoes received.
The echoes will be made but will be unable to be received by the machine.
The machine will not be able to process the received echoes into images.

Answers

B. The sound wave will not be generated, so there will be no echoes received

What is ultrasound?

An ultrasound is the process of sending high-frequency sound waves to make an image of an  internal structures of an object.

If the machine is broken and it is not sending out the sound wave, then it simply means that the sound wave will not be generated, so there will be no echoes received.

Thus, for an ultrasound tech that is trying to identify an object, but the machine is broken and is not sending out the sound wave.

The statement that best describes this situation is "The sound wave will not be generated, so there will be no echoes received".

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Answer:

B

Explanation:

A 3. 5-a current is maintained in a simple circuit with a total resistance of 1500 ω. What net charge passes through any point in the circuit during a thirty second interval?.

Answers

Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

            1A = 1 C/ s

Recall that the coulomb (C) is the unit for charge while the second (s) is the unit for time

Given: I = 3.5

A is the current

Δt =30 s is the time interval

                     A =ΔQ/ΔT

Net charge = 100C

Electricity is produced when an electric current runs through a circuit.

How does electric current work?

A current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.

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An object having a fixed emissivity of 0. 725 radiates heat at a rate of 10 w when it is at an absolute temperature t. If its temperature is doubled to 2t, at what rate will it now radiate?.

Answers

It now radiates at a rate of 160 W.

Emissivity: What is it?

The ratio of the energy emitted from a material's surface to the energy emitted from a blackbody, a perfect emitter with the same temperature, wavelength, and viewing conditions. It is a dimensionless number between 0 (for the ideal reflector) and 1. (for a perfect emitter).

What is emissivity and why is it significant?

Emissivity, which measures a material's capacity to emit infrared energy from its surface, is a crucial component of the ability to accurately measure temperature using either an infrared temperature sensor or a thermal imaging camera.

What materials have a high emissivity?

In addition to the material, a surface's emissivity also depends on the type of surface. In contrast to a roughened and oxidized metal surface, which will have a high emissivity, a clean and polished metal surface will have a low emissivity.

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The magnetic flux through a certain coil is given by phim = (1/50pi) cos( 100pi t) where the units are si. the coil has 100 turns. The magnitude of the induced emf (in volts) when t = 1/200 s is?

Answers

The magnetic flux through a certain coil is given by phim = (1/50pi) cos( 100pi t) where the units are si. the coil has 100 turns. The magnitude of the induced EMF (in volts) when t = 1/200 s is 1 / 50 π

Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area.

An EMF is induced in the coil when a bar magnet is pushed in and out of it. EMF of opposite signs are produced by motion in opposite directions, and the EMF are also reversed by reversing poles.

EMF =   d Ф / d t

Given phi = Ф =  (1/50pi) cos100pi t  

hence ,

EMF = d ((1/50pi) cos 100pi t ) / d t

       = 1/50π * cos 100 pi

       substituting value of pi

       = 1 / 50 π * cos (100 * 180)

       = 1/ 50 π * cos ( 1800 )

EMF = 1 / 50 π

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Will a beam of light that is, at first, in air and oriented perpendicular to the surface of a body of water be deflected as a result of the transition into water?.

Answers

When a beam of light  that is, at first, in air and oriented perpendicular to the surface of a body of water be deflected as a result of transition into water--------It does not deflect , the light direction will not change.

What happens to light when it passes through air?

All materials have what is known as an index of refraction, which is linked to how fast light can travel through the material. As light passes through air and into another clear material (such as glass), it changes speed, and light is both reflected and refracted by the glass.

How does light travel through air and water?

When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.

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What is the total mass of the earth's atmosphere? (the radius of the earth is 6.4 ´ 106 m, and atmospheric pressure at the surface is 105 n/m2.)

Answers

The total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

How do you calculate the total mass of the earth's atmosphere ?

To calculate the total mass of the earth's atmosphere we use the expression

[tex]P=\frac{F}{A}[/tex]

or, [tex]F=P\times A[/tex]

or,[tex]M\times g=P\times A[/tex]

or,[tex]M=\frac{P\times 4\times \pi\times r^{2} }{g}[/tex]

Here, P= Atmospheric pressure at the surface = [tex]10^{5}[/tex] N/m2

F= Force at the earth surface.

A= Area of the earth.

r= Radius of the earth=6.4 × [tex]10^{6}[/tex] m

g= Acceleration due to gravity. = 9.8 m/s2 ≈ 10 m/s2

Let, M be the total mass of the earth's atmosphere.

Now, [tex]M=\frac{10^{5}\times4\times\pi\times(6.4\times10^{6} )^{2} }{10}[/tex]

M= 5×[tex]10^{8}[/tex] kg.

Thus from the above calculation we can show that, the total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.

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Compute the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min.

Answers

The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

Given

Power = 175kw = 17500 WAngular Speed(ω) = 4300 rev/min = 450 rad/s

Let Torque = т

P = т * ω

т = P/ ω

т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)

Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.

We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.

Angular speed is the speed of the object in rotational motion.

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When the current in the micro-robot’s circuit increases and the resistance of the circuit remains constant, the voltage of the circuit:________

Answers

When the current in the micro-robot’s circuit increases and the resistance of the circuit remains constant, the voltage of the circuit: increases

What is micro-robot's ?

With manual control, microrobots have demonstrated tremendous potential for carrying out microscale activities as drug delivery, cell manipulation, micro construction, and biosensing. Magnetotactic bacteria were used to illustrate the use of targeted delivery in the presence of DC magnetic field gradients. Microrobots for magnetic field-based delivery of target objects like cells and chemicals have also been investigated by other research teams. Micro-electro-mechanical systems have been used to create microgrippers for microrobots, a technique that can be used to increase the capability of microrobots in addition to targeted distribution. The kinematic models of produced microrobots have been researched in order to obtain motion control. Microrobots that are both biological and non-biological have been guided using autonomous motion planning. These devices utilize visual systems for feedback control.

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Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.

Answers

The resistance of the conductor is 0.07940 Ohms.

What is the relation between resistance and area of wire?

The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

[tex]R=p\frac{l}{s}[/tex]

where,

p - resistivity of the conductor (0.0214-ohm mm²/m)

R - resistance

l- length of conductor (50 feet) (15.24 m)

s - the area of the wire

Thus the resistance can be calculated as

R = 0.07940 Ohms.

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If the angular speed of a 1. 1-m baseball bat is 2. 0 rad/s, what is the tangential speed of the tip of the bat?.

Answers

The tangential speed of the tip of the bat is 2.2 m/sec.

What is tangential speed?

Any item travelling in a circular direction has a tangential velocity, which is its linear speed. In one full round of a turntable, a point at the outside edge travels further than a point close to the center.

The formula for tangential velocity is given by-

[tex]V_{r}[/tex] = rω

r = radius of the circular path (m)

ω = angular speed

According to the question;

The angular speed of bat is  2. 0 rad/s.

The length of the bat is equal to radius of circular path = 1.1 m.

Angular speed = angular displacement/time

ω = Ф/t

2 = Ф/t

(∵ Ф = s/r); s is the actual distance travelled.

2 = s/(r×t)

s/t = r×2

    = 1.1×2

s/t = 2.2

v = 2.2 (∵ s/t = v)

Therefore, the tangential speed of the tip of the bat is v = 2.2 m/sec.

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If the distance between two objects is 15.00 m and the distance is tripled, then what is the new distance?

Answers

Answer:

so the answer is 45

Explanation:

you 15x3=45

5x3=15

this is a  another way to do it add 15+15+15=45

15+15=30

then you add 15

then you get 45

When a Celsius thermometer is inserted in a boiling liquid, the mercury thread
rises above the lower fixed point by 19.5cm. Find the temperature of boiling
liquid if the fundamental interval is 25cm.

Answers

The temperature of boiling liquid will be 78°C.

To find the correct answer, we need to know about the upper and lower fixed points of the thermometer.

How to find the temperature of boiling liquid?The lower fixed point is measured by the melting temperature of pure water.Given that, the fundamental interval is 25cm, which is the separation between the upper and lower fixed points.We have the equation for the temperature as,

                           [tex]T=\frac{x-x_0}{x_{100}-x_0} *100[/tex]

where,

[tex]x=[/tex] length of liquid at T temperature = 19.5cm.

[tex]x_0=[/tex] length of liquid thread at ice point = 0°C

[tex]x_{100}=[/tex] length of liquid thread at steam point = 25 cm.

Substituting values, we get,

                            [tex]T=\frac{19.5-0}{25-0}*100\\ T=0.78*100=78^0C[/tex]

Thus, we can conclude that, the temperature of boiling liquid will be 78°C.

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In a similar rolling race (no slipping), the two objects are a bowling ball and a circular hoop of unknown masses and radii. which reaches the bottom first?

Answers

The  bowling ball reaches the bottom first.

Bowling ball

In the game of bowling, a bowling ball is a tough, spherical ball used to knock down bowling pins. The customary holes in ten-pin bowling and American nine-pin bowling balls are for the thumb and two other fingers. Five-pin bowling, candlepin bowling, duckpin bowling, and European nine-pin bowling all use balls with no holes that can fit comfortably in the palm of the hand. Ball motion and how it affects scoring are influenced by a complicated interplay of many different factors. The delivery of the bowler, the construction of the bowling ball, and the state of the lane can all be considered as contributing variables.

In a similar rolling race (no slipping), the two objects are a bowling ball and a circular hoop of unknown masses and radii. which reaches the bottom first?

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A 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. Calculate the car’s momentum after 4.21 s.

Answers

The car’s momentum after 4.21s is 24617.4 kgm/s

Newton's Second Law of Motion.

Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.

Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.

Velocity u = 10.2 m/sAcceleration a =  2.45 m/s²Mass m = 1200KgTime t = 4.21 s

From Newton's second law,

F = (mv - mu) / t

ma = (mv - mu) / t

Substitute all the parameters into the formula above.

1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21

2940 = ( mv - 12240 ) / 4.21

Cross multiply

12377.4 = mv - 12240

Make mv the subject of the formula

mv = 12377.4 + 12240

mv = 24617.4 kgm/s

Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s

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A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive reactance of the inductor?.

Answers

The capacitive reactance is reduced by a factor of 2.

Calculation:

We know the capacitive reactance is given as,

[tex]Xc = \frac{1}{2\pi fC}[/tex]

where,

[tex]Xc[/tex] = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

[tex]Xc'[/tex] =?

[tex]Xc' = \frac{1}{2\pi f'C}[/tex]

      [tex]= \frac{1}{2\pi 2f C}[/tex]

      [tex]= \frac{1}{2} (\frac{1}{2\pi fC} )[/tex]

[tex]Xc'[/tex]  [tex]= \frac{1}{2} Xc[/tex]

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

The capacitive reactance is doubled.The capacitive reactance is traduced by a factor of 4.The capacitive reactance remains constant.The capacitive reactance is quadrupled.The capacitive reactance is reduced by a factor of 2.

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If the pressure on a gas is increased, then its volume will decrease because the gas molecules will be pushed closer together. did the data support the hypothesis (above)? justify your answer.

Answers

Boyle's Law

As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.

What is Boyle's law ?

As the pressure on a gas increases, the volume of the gas decreases because the gas particles are forced closer together. Conversely, as the pressure on a gas decreases, the gas volume increases because the gas particles can now move farther apart

A contained gas's pressure will rise when its volume is reduced, and fall when its volume is increased. In actuality, the pressure reduces by the same factor as the volume increases, and vice versa.

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Answer:yes

Explanation:

Sample Justification: As weight was added to the top of a syringe, the volume of the air trapped in the syringe decreased. The weight and the surface area of the plunger were used to calculate pressure. As more weight was added, the pressure increased. The volume decreased in response.

then

yes and yes

Mercury at 25°c flows over a 3-m-long and 2-m-wide flat plate maintained at 75°c with a velocity of 0. 01 m/s. Determine the rate of heat transfer from the entire plate?

Answers

The rate of heat transfer from the entire plate is 710.8 kW

The properties of mercury at the film temperature of (75+25)/2= 50°C

k = 8.83632 W/m °C

v = 1.056 × [tex]10^-^7[/tex] m²/s

Pr = 0.0223

The local Nusselt number relation for liquid metals is given by

 [tex]N_u =\frac{h_sx}{k} = 0.565 9Re_x Pr)^\frac{1}{2}[/tex]

The average heat transfer coefficient for the entire surface can be determined from

[tex]h = \frac{1}{L} \int\limits^1_0 {h_x} \, dx[/tex]

Substituting the local Nusselt number relation into the above equation and performing the integration we obtain

[tex]N_u = 1.13 (Re_s Pr)^\frac{1}{2}[/tex]

The Reynolds number is

[tex]Re_L = \frac{VL}{v} = \frac{(0.01)(3m)}{1.056 * 10^-^7 m^2/s} = 0.028 * 10^7[/tex]

Using the relation for the Nusselt number, the average heat transfer coefficient and the heat transfer rate are determined to be

                       Q = 710.8 kW

Therefore, the rate of heat transfer from the entire plate is 710.8 kW

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Light of wavelength 635.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 38.0∘ from the normal. how many slits per millimeter are marked on the grating?

Answers

Number of rulings per centimeter for the grating 4.5 x 10^3 grooves/cm

Given:

wavelength of light = 635.00 nm

angle of first order = 38.0∘

To Find:

Length of slits marked on grafting

Solution: Grafting and budding are horticultural techniques used to join parts from two or more plants so that they appear to grow as a single plant

We use the grating equation dsinθ = mλ

d = mλ/sinθ

d = 1 x 635x10^-7 m/sin 38.0∘

d = 2189.6 x 10^-7 m

Thus the grating gauge is

1/d = 0.00045 x 10^7 = 4.5 x 10^3 grooves/cm

So, number of rulings per centimeter for the grating 4.5 x 10^3 grooves/cm

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450n 360n 710n 1400n 230n a block is placed in oscillation on a frictionless horizontal surface attached to a spring that is also attached to a wall. If, when stretched away from equilibrium by 15cm and released, it oscillates with a period of 0. 25s, and if the mass of the block is 15kg, what force was required to stretch the spring by the initial 15cm?.

Answers

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

What is oscillation?

The motion between two positions back and forth, or swinging back and forth like a pendulum exists comprehended as oscillation.

What is equilibrium?

A condition where competing forces or activities exist in balance exists named equilibrium.

What is the stretching force?

Tensional force exists as the force exerted by a stretched item.

It could be a rope, string, elastic band, or wire that exists being extended.

The object's tensional force exists used to the object stretching it.

The stretched object exists subject to tensile force.

Force stood needed to stretch the spring by the initial 15cm exists 1420 N.

Let, m = 15, P = 0.25, x = 0.15

F = -K x for spring

where, F is the force

K be the constant

ω [tex]= (K/m)^{1/2[/tex]

where, ω be the angular frequency

m b the mass of the block

[tex]$\omega^2 = K / m[/tex]

[tex]K = m \omega^2[/tex] [tex]= m (2 \pi f)^2[/tex]  [tex]= m 4 \pi ^2 / P^2[/tex]

K = 4[tex]\pi ^2[/tex] m / [tex]P^2[/tex]

[tex]F = K x = x * 4 \pi ^2 m / P^2[/tex]

[tex]F = 0.15 * 4 * \pi ^2 * 15 / 0.25^2[/tex]

F = 1420 N

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

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For a body to be in SHM, the restoring force must be __________ to displacement from equilibrium.

Answers

Answer:

Proportional

Explanation:

The conditions that must be met to produce SHM are;

-The restoring force must be proportional to the displacement and act opposite to the direction of motion with no drag forces or friction.

- The frequency of oscillation does not depend on the amplitude.

For a particular transverse wave, there are 1.10 meters between two sequential troughs and nine troughs pass a fixed point along the direction of travel every 14.5 s. Find the wave speed (in m/s).

Answers

The speed of the wave is 0.68 m/s.

What is wave speed?

Wave speed is the distance the wave travels in a given amount of time, such as the number of meters it travels per second.

V = Fλ

where;

V is the speed of the waveF is frequency of the waveλ is wavelength

What is the wavelength?

This is the distance between two sequential troughs = 1.1 m

What is the frequency of the wave?

The frequency is number of complete oscillation per second.

f = n/t

where;

n is number of complete oscillation

f = (9)/(14.5)

f = 0.62 Hz

V = 0.62 x 1.1

V = 0.68 m/s

Thus, the speed of the wave is 0.68 m/s.

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Two point charges of 20. 0 μc and -8. 00 μc are separated by a distance of 20. 0 cm. what is the intensity of electric field e midway between these two charges? group of answer choices

Answers

The intensity of electric field E midway between these two charges is 2.52*10^7N/C.

To find the answer, we have to know more about the electric field.

How to find the electric field?We have the expression for net electric field as,

                      [tex]E=\frac{kQ}{r^2}[/tex]

where, k is the constant equal to 8.99*10^9.

Thus, we can write the electric field created by 20micro coulomb charge at the midway between two charges is,

                [tex]E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C[/tex]

We can write the electric field created by -8micro coulomb charge at the midway between two charges is,

                 [tex]E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C[/tex]

Thus, the net field at the midway due to two charges will be,

                [tex]E=1.79*10^7+7.19*10^6=2.52*10^7N/C[/tex]

Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.

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Please help, I don't understand lol

Answers

The resulting velocity of marble B after the collision is 2.4 m/s.

The object with the faster velocity, and thus larger momentum, will impart more energy to the slower object during the collision than vice versa. Following the collision, the object with the lower beginning velocity will travel away from the other object with a higher speed and momentum.
Marble A's mass, marble B's mass, marble B's initial velocity, marble A's final velocity, marble B's final velocity, and marbles A and B's combined mass and initial velocity

Applying the mass-conservation principle
Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

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