A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago, the age of the father was five times the age of the son. Six years from now the son’s age will be?

The expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

The local gym is offering this new promotion:

An enrollment fee of $40 and a monthly fee of $30.

Let m be the total number of months

Total monthly fee = 30m

Total cost(including the enrollment fee of $40) = 40 + 30m

Let the total cost is c:

c = 40 + 30m

If in the linear expression, one variable is present, then the bis known as the linear expression in one variable.

Thus, the expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.

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The solution to the following mathematical problems are;

Solve using

BODMAS

5² -3⁴ / (2³-5)(6² ÷ 9)

= 25-81 / (8-5)(36÷9)

= -56 / (3)(4)

= -56/12

= - 14/3

20² ÷ {3(5-9)² + 2}

= 400 ÷ {3(-4)² + 2}

= 400 ÷ {3(16) + 2}

= 400 ÷ (48+3)

= 400 ÷ 50

= 8

84/12 + (5-7)² -72 ÷ 6×2

= 7 + (-2)² - 12 × 2

= 7 + (4) - 24

= 11 - 24

= -13

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Answer:

627

267

276

762

726

and the no. itself, 672

Proved that the cofunction identity sec([tex]\frac{\pi }{2}[/tex]) - u = csc(u)

We have to prove that the cofunction identity using the addition and subtraction formulas.

sec([tex]\frac{\pi }{2}[/tex]) - u = csc(u)

We can prove this by using the identities given below:

[tex]sec(u)=\frac{1}{cos(u)}[/tex]

[tex]\frac{1}{sin(u)} =csc(u)[/tex]

cos(a-b) = cos a cos b + sin a sin b

Now the explanation,

[tex]sec(\frac{\pi }{2} -u) = csc(u)[/tex]

By using trignometric identities,

[tex]cos(u)=\frac{1}{sec(u)}[/tex]   ∴[tex]sec(u)=\frac{1}{cos(u)}[/tex]

So,

[tex]\frac{1}{cos(\frac{\pi }{2}-u) } =csc(u)[/tex]

By substituting the given identities we get,

  [tex]\frac{1}{cos(\frac{\pi }{2})cos(u)+sin(\frac{\pi }{2} )sin(u) }[/tex]

= [tex]\frac{1}{0.cos(u)+(1).sin(u)}[/tex]

=[tex]\frac{1}{sin(u)}[/tex]

= csc(u)

csc(u) = csc(u)

Here we proved that the cofunction identity sec([tex]\frac{\pi }{2}[/tex]-u) = csc(u)

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If the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

Given that the vertices of parallelogram ABCD is A(-6,-4),B(0,-4)

,C(3,4),D(-3,4).

We are required to find the area of parallelogram ABCD.

Let the point of intersection of height of parallelogram from point A is point E.

When we see the graph on which the parallelogram then we will be able to know that point E has coordinates of (-3,-4).

Area of parallelogram=Base*Height

=AB*DE

DE=[tex]\sqrt{(-4-4)^{2} +(-3+3)^{2} }[/tex]

=[tex]\sqrt{64}[/tex]

=8 units

AB=[tex]\sqrt{(-4+4)^{2} +(0+6)^{2} }[/tex]

=[tex]\sqrt{36}[/tex]

=6 units

Area=6*8

=48 square units.

Hence if the vertices of parallelogram ABCD is A(-6,-4),B(0,-4),C(3,4),D(-3,4) ,then the area of parallelogram ABCD will be 48 square units.

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Answer:

Step-by-step explanation:

[tex]We\ summarize\ (1) \ and\ (2),\ \ (2) \ and\ (3):\\\displaystyle\\\left \{ {{2x\geq -6\ |:2} \atop {-2x\geq -6\ |:(-2)}} \right. \ \ \ \ \ \left \{ {{x\geq -3} \atop {x\leq 3}} \right. \ \ \ \ \ \Rightarrow\ \ \ \ x\in[-3;3].\\[/tex]

[tex]2)\ We\ subtract\ equation\ (2) \ from \ equation (1),[/tex]

Answer:

A. 175 m

B. 20 cm

Step-by-step explanation:

[tex]\frac{1 cm}{25 m} =\frac{7 cm}{x m}[/tex]

x = 175 m

[tex]\frac{25 m}{1 cm} = \frac{500 m}{x cm}[/tex]

x = 20 cm

Answer:

No1. 175 m

no2. 20 cm

This is voluntary response bias. The result overestimates true support for firing the coach.

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Answer:

1 hour

Step-by-step explanation:

The correct graph is in the attached image.

Answer:

  B.  A linear graph of solid line intercepts X-axis at the point (2, 0) and Y-axis at the point (0, -4)

Step-by-step explanation:

The boundary line of an inequality is graphed as though the expression were an equality. The nature of the line used will depend on the nature of the inequality.

When the inequality includes the "or equal to" case (≤ or ≥), the boundary line is part of the solution set. It is drawn as a solid line.

When the inequality excludes the "or equal to" case (< or >), the boundary line is not part of the solution set. It is drawn as a dotted or dashed line.

The given inequality

  y ≤ 2x -4

includes the "or equal to" case, so the boundary line is solid.

The equation of the boundary line is written in slope-intercept form:

  y = mx +b . . . . . . . line with slope m and y-intercept b

  y = 2x -4 . . . . . . . boundary line with slope 2 and y-intercept -4.

This tells you that the boundary line intercepts the y-axis at the point (0, -4).

If they work together, they need 15/8 hours to assemble one shelving unit.

What does work mean in math?

According to tittle, we know worker A can  assemble a shelving unit in 5 hours , which means worker A can finish 1/5 of work in 1 hour . And worker B can finish 1/3 of work in 1 hour.

If A & B work together , they will spend the same time t to assemble only one shelving .

That means,                  1/5t + 1/3 t = 1                         (equation)

1/5 t is worker A's workload during time t , 1/3 t is worker B workload.

So,   1/5 t + 1/3t = 1  is the answer

     ⇒ 5t + 3t = 15

     ⇒ t = 15/8 hours

If they work together, they need 15/8 hours to assemble one shelving unit.

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Answer:

Letter C is the correct answer or  1/5 t + 1/3t = 1

Assuming that the variable h is the same for each figure, the figures from the least to the greatest is:

The value of h is the same for all the shape so assume the value of h is 2 units.

The volume of a cylinder is:

= πr²h

First cylinder area:

= 22/7 x 3 x 2

= 56.54867 units

The second cylinder area:

= 22/7 x 6 x 2

= 226.19467 units

The volume of a cone is:

= πr²h/3

First cone volume:

= 22/7 x 3 x 2/3

= 18.84956 units

Second cone volume:

= 22/7 x 6 x 2/3

= 75.39822 units

The order is therefore:

Cone with radius of 3 units < Cylinder with radius of 3 units < Cone with radius of 6 units < Cylinder with radius of 6 units

In conclusion, the shapes with the larger radius of 6 units will have more volume.

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Step-by-step explanation:

25 as binary number is

11001

1×2⁴ + 1×2³ + 0×2² + 0×2¹ + 1×2⁰ = 16 + 8 + 1 = 25

25×2 = 50 = 11001 × 2 = 110010

multiplying a binary number by 2 is the save effect as multiplying a normal decimal number by 10 : all digits move one position to the left, and a 0 is put into the empty right position.

and so, we see

110P = 110010

P = 010

FYI : you normally don't mix binary and decimal numbers. if one of the numbers is binary, then all the others have to be binary too.

so, the problem should have looked like

110P/10 = 11001

110P = 11001×10 = 110010

P = 010

Answer:

01

Step-by-step explanation:

From decimal to binary;

25/2==> 1 (remainder)

12/2===>0

6/2==>0

3/2===>1

1

=11001

Checking the answer;

11001

=1*2^4+1*2^3+0*2*2+0*1+1*2^0

=1*16+1*8+0+0+1*1

=16+8+0+0+2

=25

Answer:

J

Step-by-step explanation:

Answer:

Step-by-step Explanation:

The correct option is C.

The algebraic expression for "seven more than the product of three and some number = 3x + 7 = 0

An algebraic expression is one that is composed of variables, integer constants, and algebraic operations. An algebraic expression is, for instance, 3x² 2xy + c.

we can search for the product of 3 and "some number",

Let the number be x.

So, the product of x is 3 times = 3x

And now

7 more then the Product .

we add the 7 to the product .

3x + 7 = 0

So the equation will be 3x + 7 = 0

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I understand that question you are looking for is:

Which of these is the algebraic expression for "seven more than the product of three and some number?"

A. 7 + 3 + x

B. 3 + 10 ÷ x

C. 3x + 7

D. 3 + 7x

Answer:

330

Step-by-step explanation:

the change in hirght = 120 - 90 = 30

so 90 + (30 x 8)

= 90+240

= 330//

Answer:r=14°

Step-by-step explanation:

(5r-5)°+ (8r+3)°=180

(Sum of angles on a straight line =180°)

Collect like terms

5r+8r-5+3=180

13r-2=180

13r=180+2

13r=182

r=182/13

r=14°

Answer:[tex]x^3-x^2-17x+20[/tex]

Step-by-step explanation:

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z}^{2} - 14z + 48 }{ {z}^{2} + 6x - 27} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z}^{2} - 8z - 6z+ 48 }{ {z}^{2} + 9z- 3z- 27} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {z(}^{} z- 8) - 6(z - 8) }{ {z}^{} (z+ 9)- 3(z + 9)} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(}^{} z- 8) (z - 6) }{ {}^{} (z+ 9)(z - 3)} ÷ \cfrac{z -8}{z-3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ (z - 6) }{ {}^{} (z+ 9)}[/tex]

Break into two parts and simplify

[tex]\\ \rm\dashrightarrow \dfrac{z^2-14z+48}{z^2+6z-27}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{z^2-8z-6z+48}{z^2+9z-3z-27}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{(z-8)(z-6)}{(z+9)(z-3)}[/tex]

Now divide by the denominator

[tex]\\ \rm\dashrightarrow \dfrac{(z-8)(z-6)(z-3)}{(z+9)(z-3)(z-8)}[/tex]

[tex]\\ \rm\dashrightarrow \dfrac{z-6}{z+9}[/tex]

Answer:

50 ^^

Step-by-step explanation:

So first an easy way to solve this problem is by removing the zeros then you'll have 35 and
7x1=7

7x2=14

7x3=21

7x4=28

7x5=35

So 7x5 dont forget to add your zeros to 35 and 5 and boom your answer is 50

need more explaining tell me ^^

There are 105 numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

The number base is given as:

Base 3

To determine the count of numbers, we make use of the following Python program

count = 0

for n in range(1,1001):

   digits = []

   while n:

       digits.append(int(n % 3))

       n //= 3

   myStr = ''.join(map(str,digits[::-1]))

   if(myStr.count('0')+myStr.count('1') == len(myStr)):

       count+=1

print(count)

The above program counts the numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

The output of the program is 105

Hence, there are 105 numbers in the  the first 1000 positive integers contain only 0s and 1s when written in base 3

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For the given functions, the domains are:

1) All real numbers.

2) D: x≥ -3

3) D: set of all real numbers such that x ≠ 0

4) D: 7 ≥ x ≥-7

5)  All real numbers.

For any function, we assume that the domain is the set of all real numbers, and then we remove all the values of x that generate problems (like a denominator equal to zero or something like that).

1) f(x) = x^2 - 4

This is just a quadratic equation, the domain is the set of all real numbers.

2) f(x) = √(x + 3)

Remember that the argument of a square root must be equal to or larger than zero, so here the domain is defined by:

x + 3 ≥ 0

x≥ -3

The domain is:

D: x ≥ -3

3) f(x) = 1/x

We can assume that the domain is the set of all real numbers, but, we can see that when x = 0 the denominator becomes zero, then we need to remove that value from the domain.

Thus, we conclude that the domain is:

D: set of all real numbers such that x ≠ 0

4) f(x) = √(49 - x^2)

Here we must have:

49 - x^2 ≥ 0

49 ≥ x^2

√49  ≥ x ≥-√49

7 ≥ x ≥-7

The domain of this function is:

D:  7 ≥ x ≥-7

5) f(x) = √(x^2 + 1)

Notice that x^2 is always a positive number, then the argument of the above square root is always positive, then the domain of that function is the set of all real numbers.

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We can observe

Its a geometric progression having first term 9(3)=27 and common ratio as 1/3

So

The firmula is

Option C

Answer:

[tex]a_n=27\left(\dfrac{1}{3}\right)^{n-1}[/tex]

Step-by-step explanation:

From inspection of the graph, the given points are:

If we draw a line through the given points, the line is a curve rather than a straight line. If the line was a straight line, the graph would be modeled as an arithmetic sequence. Therefore, as the line is a curve, the given points are modeling a geometric sequence.

General form of a geometric sequence:

 [tex]a_n=ar^{n-1}[/tex]

where:

Rewrite the given points as terms of the sequence:

To find the common ratio r, divide consecutive terms:

[tex]\implies r=\dfrac{a_3}{a_2}=\dfrac{3}{9}=\dfrac{1}{3}[/tex]

Calculate the first term (a) by substituting the found value of r and the given values of one of the terms into the formula:

[tex]\implies a_2=9[/tex]

[tex]\implies a\left(\dfrac{1}{3}\right)^{2-1}=9[/tex]

[tex]\implies \dfrac{1}{3}a=9[/tex]

[tex]\implies a=27[/tex]

Substitute the found values of r and a into the general formula to create the sequence modeled by the graph:

[tex]a_n=27\left(\dfrac{1}{3}\right)^{n-1}[/tex]

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The step which contains the first error in calculation is: B. Step 2 - the sine ratio was applied incorrectly.

The law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

Mathematically, the law of sines is given by this equation:

[tex]\frac{sinA}{a} =\frac{sinB}{b}[/tex]

For any right-angled triangle, the ratio of the length of its opposite sides to the length of its hypotenuse is generally referred to as sine ratio. Thus, sine ratio is given by this formula:

cos(θ) = Opp/Hyp

Where:

In this context, we can infer and logically deduce that the step which contains the first error in calculation is step 2:

sin(W) = y/XZ; XZsin(W) = y.

In conclusion, the correct step should have been written as follows:

sin(W) = XZ/y; ysin(W) = XZ.

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Answer:

step 2 is incorrect

Step-by-step explanation:

B. Step 2 - the sine ratio was applied incorrectly

Answer:

the triangle is a right angle triangle. I can't see the correct explanation here so I will explain

Step-by-step explanation:

to work out whether triangles are right angle you do :

square root of (5² + 12²) so it would be 25 + 144 =169 and the square root of 169 is 13 . we do this because the square root of both of the side lengths squares should make ths longer side in this case it makes 13 so it is a right angled triangled

i hope this helps . if you need any more help pls ask :)

The rectangular pyramid rises 7 feet in height.

Pyramids are three-dimensional objects with triangle-shaped faces and an all-encompassing polygonal base. It is referred to as a rectangular pyramid if the base of the structure is rectangular. Although all pyramids have a rectangular foundation, they all have triangular edges.

How is the height of the rectangular pyramid determined?

First, we understand that a rectangular pyramid's volume is determined by:

                         [tex]V=B * H / 3[/tex]

The height H is determined by the base B.

When we know the volume is 56 [tex]ft^{3}[/tex] and the base is 24 [tex]ft^{2}[/tex], we can then swap out those two numbers in the volume calculation to get:

                          [tex]56 f t^{3}=24 f t^{2} * H / 3[/tex]

When we solve it for H, we get:

                          [tex]H=3 *\left(56 f t^{\circ} / 24 f t^{2}\right)=7 f t[/tex]

The rectangular pyramid rises 7 feet in height.

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