Profit decreased by 7.5%
Answer:
Solution Given:
Marked Price= Rs 6,000
discount =20%
Selling Price =M.P- discount% of M.P
=M.P(1-discount%)
=6000(1-20%)
= Rs 4,800
Again
Profit = 20%
Cost Price=(S.P*100)/(100+profit%)
= (4800*100)/(100+20%)
= Rs 4,000
For discount 25%
Marked Price =Rs 6,000
Selling Price =M.P - discount% of M.P
=M.P(1-discount%)
=6000(1-25%)
=Rs 4,500
Profit = S.P- C.P= Rs 4,500- Rs 4,000=Rs 500
Profit %=Profit/C.P* 100%= 500/4000*100 = 12.5%
Profit % decreased from 20% to 12.5%
Profit decreased by 7.5%
Answer:
7.5%
Step-by-step explanation:
Marked Price
Rs 6,000
Discounted Price
If the price is discounted by 20%, then the discounted price is 80% of the marked price:
[tex]\implies \sf Discounted\:Price =80\% \textsf{ of marked price}[/tex]
[tex]\implies \sf Discounted\:Price =0.8 \times 6000[/tex]
[tex]\implies \sf Discounted\:Price = 4800\:Rs[/tex]
Cost Price
If the dealer makes 20% when selling the watch at the discounted price, then the cost price is:
[tex]\implies \sf Cost\:Price=\dfrac{100\%}{120\%} \times 4800[/tex]
[tex]\implies \sf Cost\:Price=\dfrac{4800}{1.2}[/tex]
[tex]\implies \sf Cost\:Price=4000\:Rs[/tex]
Discount of 25%
If the price is discounted by 25%, then the discounted price is 75% of the marked price:
[tex]\implies \sf Discounted\:Price =75\% \textsf{ of marked price}[/tex]
[tex]\implies \sf Discounted\:Price =0.75\times 6000[/tex]
[tex]\implies \sf Discounted\:Price = 4500\:Rs[/tex]
Profit after 25% discount
[tex]\implies \sf Profit=\dfrac{discounted\:price}{cost\:price}-1 \times 100[/tex]
[tex]\implies \sf Profit=\dfrac{4500}{4000}-1 \times 100[/tex]
[tex]\implies \sf Profit=12.5\%[/tex]
Therefore, the profit decreased from 20% to 12.5% which means the profit percent decreased by 7.5%.
The graph of the step function g(x) = –⌊x⌋ + 3 is shown.
On a coordinate plane, a step graph has horizontal segments that are each 1 unit long. The left end of each segment is a closed circle. The right end of each segment is an open circle. The left-most segment goes from (negative 2, 5) to (negative 1, 5). Each segment is 1 unit lower and 1 unit farther to the right than the previous segment. The right-most segment goes from (4, negative 1) to (5, negative 1).
What is the domain of g(x)?
{x| x is a real number}
{x| x is an integer}
{x| –2 ≤ x < 5}
{x| –1 ≤ x ≤ 5
Using it's concept, the domain of the function is given as follows:
{x| –2 ≤ x <= 5}
What is the domain of a function?The domain of a function is the set that contains all possible input values for the function.
The function described is defined for x between -2 and 5, hence the domain is given by the following interval:
{x| –2 ≤ x <= 5}
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Answer:
{x| –2 ≤ x < 5}
Step-by-step explanation:
5. Enter the answer as a decimal
Calculate the rate of interest, when simple interest = $5,616;
loan amount = $7,200 and time = 12 years.
Answer:
6.5%
Step-by-step explanation:
I = prt
5616 = 7200 × r × 12
r = 5616/(7200 × 12)
r = 0.065
r = 6.5%
?
What is the directrix of a parabola whose equation is (y +
3)² = 8(x-3)?
O x = 5
Oy = -5
Ox=1
Oy = -1
Done
The directrix of the parabola with equation (y + 3)² = 8 · (x - 3) is equal to y = - 5. (Correct choice: B)
What is the directrix of a parabola?
According to the given statement, we have a parabola of the form (y - k)² = 4 · p · (x - h), whose axis of symmetry is parallel to the x-axis. The directrix is always perpendicular to the axis of symmetry and therefore the equation of the directrix is equivalent to x = h - p, where p is the distance from the vertex to the focus.
If we know that the equation of the parabola (y + 3)² = 8 · (x - 3), the equation of the directrix is:
y = - 3 - 2
y = - 5
The directrix of the parabola with equation (y + 3)² = 8 · (x - 3) is equal to y = - 5. (Correct choice: B)
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Y=2x^2+2x-4 what is the x intercepts for the parabola
Answer:
Step-by-step explanation:
To find the x intercepts, substitute in 0 for y and solve for x
So,
2x^2+2x-4 = 0
2(x^2+x-4) = 0
2/2(x^2+x-4) = 0/2
x^2+x-4 = 0
(x-1) (x+2) = 0
now,
x-1 = 0
x = 1
or
x+2 = 0
x = -2
The x intercepts for the parabola (1,0), (-2,0)
10 by 28 + - 32 by 49 rational number
pls answer it
thank you
By simplifying the fraction 10/28 ÷ 32/49 exists 35/64.
How to simplify fractions?The first stage of dividing fractions exists to estimate the reciprocal (reverse the numerator and denominator) of the second fraction. Subsequently, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if required.
To find the reciprocal of the divisor
Reciprocal of 32/49 = 49/32
Now, multiply it by the dividend, then we get
So, 1028 ÷ 3249 = 10/28 × 49/32
= (10 × 49)/(28 × 32) = 490/896
After decreasing the fraction, the answer exists at 35/64.
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can someone help me really quick
Answer:
-6
Step-by-step explanation:
Additive inverse is the number that when added to A gives a result of zero
A + inverse = 0
6 + inverse = 0
inverse = -6
In the graph above, which vertical line (V) and horizontal line (H) can be used to graph point D?
Question 5 options:
A)
V: x = –4; H: y = 4
B)
V: y = –4; H: x = –4
C)
V: y = 4; H: x = –4
D)
V: x = 4; H: y = 4
Answer: A. V: x = –4; H: y = 4
Step-by-step explanation:
Explain what is meant by intercepts with the axes give examples of y and x intercepts
Intercepts with the axes are where your line touches the x or y axis. An example is a straight line, say, y=4x+2. In this case, the y-intercept is 2 because the line touches the y-axis at (0, 2). With y=mx+b format, the y-intercept is b. To find the x-intercept of an equation in y=mx+b format, set y to zero and solve for x. In a parabola, the x-intercepts would be the roots. An example of this is x^2 - 5x + 4 = 0. The roots here are (4,0) and (1,0). Hopefully this helped.
I need help with this
Answer:
s = -24
Step-by-step explanation:
This is a 2-step linear equation, so can be solved the way all 2-step equations are solved.
SolutionStep 1
Identify the constant term on the side of the equation with the variable term, and add its opposite to both sides.
[tex]7 = \dfrac{1}{6}s+11\qquad\text{given}\\\\7-11=\dfrac{1}{6}s+11-11\qquad\text{add $-11$ to both sides}\\\\-4=\dfrac{1}{6}s\qquad\text{simplify}[/tex]
Step 2
Multiply both sides by the inverse of the coefficient of the variable.
[tex](6)(-4)=(6)\left(\dfrac{1}{6}s\right)\qquad\text{multiply both sides by 6}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]
Alternate solutionOften, when equations contain fractions, you are advised to "eliminate fractions" as a first step. That generally means you multiply both sides of the equation by a suitable common denominator.
Here, the only denominator is 6, so the fraction can be eliminated by multiplying both sides of the equation by 6.
[tex]7=\dfrac{1}{6}s+11\qquad\text{given}\\\\6(7)=6\left(\dfrac{1}{6}s+11\right)\qquad\text{multiply both sides by 6}\\\\42=s+66\qquad\text{simplify}\\\\42-66=s+66-66\qquad\text{add the opposite of 66 to both sides}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]
You will note this requires the same number of steps, but you don't have to mess with fractions after the first step.
CheckThe value we found for the variable can be checked in the original equation.
[tex]7=\dfrac{1}{6}(-24)+11\\\\7=-4+11\qquad\text{true}[/tex]
The limits of the class intervals are
The lower and the upper class limit are as follows
interval lower limit upper limit
10-14 10 14
15-19 15 19
20-24 20 24
25-29 25 29
This is further explained below.
What is the class limit?Generally, The lower class limit and the upper-class limits are just the minima and maximum values that are allowed in each class, respectively: The gap that exists between the upper-class limit and the lower class limit is referred to as the class interval.
In conclusion, The lower and the upper class limit are as follows
interval lower limit upper limit
10-14 10 14
15-19 15 19
20-24 20 24
25-29 25 29
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A mini-lottery involves selecting 2 numbers between 1 and 10. What is the probability of correctly picking the two numbers?
a) 2/10
b) 1/30
c) 2/90
d) 2/100
The probability of correctly picking the two numbers is 2/10.
What is the probability?Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.
The probability of correctly picking the two numbers = (numbers that have to be selected to win / total numbers)
2/10
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Sandy jogs 19.7 miles in 4.5 hours. How many miles does she jog per hour
Answer:
4.378 MPH
Step-by-step explanation:
Distance in Miles
MPH= -------------------------
Time in Hours
19.7/4.5 = 4.378 MPH
What is the mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3?
The value of the mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is 16.94%
How to solve for the mean absolute percentage errorThe equation is given as
∝At + (1-∝) Ft
The value for Alpha = 0.7
1 - ∝ = 1 - 0.7
= 0.3
Forecast in match = 62
Ft = 51. 5
the difference = 62 - 51.5
= 10.5
The error = 10.5/62 * 100
= 16.94%
Hence the value of the mean absolute percentage error of the forecast for march found by the exponential smoothing method with a smoothing constant of 0. 3 is 16.94%
Complete question
The past demand data shown below can be regarded as stationary.
Month Demand
January
50
February
55
March
62
April
45
What is the mean absolute percentage error of the forecast for March found by the exponential smoothing method with a smoothing constant of 0.3?
O a. 14.68%
Ob. 16.94%
O c. 12.57%
Od. 11.33%
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Change
3
-
4
to a percent
Answer:
75%
Step-by-step explanation:
3/4 ie 75/100. .........edge
The image of the point P(-3, 2) under the translation (2/1) is
The image of the point P(-3, 2) under the translation T<2,1> is (-1, 3)
How to determine the image of the translation?The coordinate point is given as:
P = (-3, 2)
The translation is given as
T<2,1>
The translation can be represented as:
(x, y) = (x + 2, y + 1)
So, we have the following equation
P' = (-3 + 2, 2 + 1)
Evaluate the sum
P' = (-1, 3)
Hence, the image of the point P(-3, 2) under the translation T<2,1> is (-1, 3)
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Mike wants to find the confidence interval for a set of data. he knows the sample size and the sample proportion. which other piece of information does he need to determine the confidence interval?
Using the formula for a z-distribution confidence interval of proportions, he also needs to know the confidence level.
What is a confidence interval of proportions?A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.Of these 3 itens, the problem states that he knows the sample size and the sample proportion, hence he needs to know z to determine the confidence interval. z depends on the confidence level, which is the remaining parameter.
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HELP HELP ASAP
Figure BBB is a scaled copy of Figure AAA.
What is the scale factor from Figure AAA to Figure BBB?
Answer:
figure A = 3 units
figure B = 9 x 3 = 27 units
scale factor =
[tex] \frac{3}{27 } = \frac{1}{9} [/tex]
so the scale factor = 9
Fifteen students were divided into two classrooms in a ratio of 1:2.
How many students were in each classroom?
Three fair, standard six-faced dice of different colors are rolled. In how many ways can
the dice be rolled such that the sum of the numbers rolled is 15?
These are some of the ways you can make 15 by adding three numbers together.
The first way is doing 6+6+3.There are some more ways to do it too.
2nd way is 6+4+5.
3. 1+6+6
4. 5+5+5
pls pls help meee i dont understand the fundamental theorem of algebra
Answer:
Hey! I'm gonna go ahead and give ya the "meaning" of the fundamental theorem of algebra but not the answer to the A. B. and C.
Step-by-step explanation:
fundamental theorem of algebra, theorem of equations proved by Carl Friedrich Gauss in 1799. It states that every polynomial equation of degree n with complex number coefficients has n roots, or solutions, in the complex numbers. The roots can have a multiplicity greater than zero.
The periodic time, t, of a pendulum varies directly as the square root of its length, l. t = 6 when l = 9. find t when l = 25.
The periodic time, t, of a pendulum range directly as the square root of its length, l. t = 6 when l = 9. If l = 25 then the periodic time, T exists at 10.
What is periodic time?The period, or periodic time, of a periodic variation of a quantity, exists described as the time interval between two consecutive repetitions.
Given: The periodic time, t, of a pendulum goes directly as the square root of its length, l if t = 6 when l = 9.
If [tex]T \alpha\ l^2[/tex] then [tex]T^2[/tex] α [tex]\sqrt{l}[/tex]
[tex]T^2 = l[/tex]
Let, [tex]T^2 = kl,[/tex] where k exists constant
t = 6 when l = 9.
So, [tex]6^2 = k*9[/tex]
[tex]k = 6^2/9 = 4[/tex]
[tex]T^2 = 4*l[/tex]
If l = 25
[tex]T^2 = 4 * 25 = 100[/tex]
[tex]T = \sqrt{100}[/tex]
T = 10
Therefore, the periodic time, T exists 10.
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a recently televised broadcast of a popular televison show had a 15 share, meaning that among 5000 monitored households with TV sets is use, less than 20% were turned in to the show. find the p-value
a) 1.9998
b) 0.9999
c) 0.0002
d) 0.0001
The p-value from the information about the recently televised broadcast is B. 0.9999.
How to get the p-value?From the information given, n = 5000 and the level of significance is 0.01.
The computed z value is -8.84.
From the z table, the probability value is the value corresponding to the row 8.8 and column 0.04.
This will give a value of 0.9999.
In conclusion, the correct option is B.
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15 The tennis team is selling tickets to a car wash for $6. When they do not
sell very many tickets, the team decreases the price 25%. What is the
new cost of a ticket?
Show your work.
Answer: $4.50
Step-by-step explanation:
Original Price: $6
Discount: 25%
Discounted Price: 6*25%= $1.5
$6-$1.5= $4.5
graph the linear equation by plotting three points. 2y=-3+2
Answer:
Step-by-step explanation:
Convert 2y=-3x+2 into y=mx+b form
[tex]\frac{2y}{2} =\frac{-3x+2}{2}[/tex]
[tex]y=\frac{-3x}{2} +1[/tex]
Y intercept is 1, slope is -3/2
Graph looks like this:
A rental truck company charges a flat fee of $30 to rent a truck in addition to $0.25 per miles how much would it cost to rent a van for 80 miles
Answer:
$50
Step-by-step explanation:
x is distance and y is cost because the cost is dependent on the distance which makes the distance the independent variable. you can always use y=mx+b for these problems!!
The total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. Write the rule for the total cost, C, where r rides are taken.
C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. This can be obtained by converting the statements to algebraic equation with variables and constants.
Find the rule for the total cost:Here in the question it is given that,
The total cost charged for a day of fun at Aussie World consists of
an entry fee of $15 a rate of one ride is $3We have to find a rule for the total cost, C, where r rides are taken.
For one ride the rate is 3 ⇒ therefore for r rides the rate is 3r
We can convert the statements to algebraic equation so that we get the required rule,
⇒ The total cost consists of entry fee and rate of rides
⇒ The total cost = entry fee + rate of rides
⇒ C = 15 + 3r (from the given information)
⇒ C = 3r + 15
Hence C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride.
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Clark earns $31 per hour. Calculate his weekly wage if he works 38 hours per week.
Answer:
1178 because 31 dollars an hour for 38 hours you would multiply or times 31 and 38 and get 1178 for total money earned
Help please !!!!!!! Need helppppp
Answer:
option c
Step-by-step explanation:
option c is a correct answer
Which must be true by the corresponding angles
theorem?
041 = 27
42 = 26
23 45
25= 27
The corresponding angles are ∠2 and ∠6 i.e., ∠2≅∠6 according to the corresponding angles theorem. So, option 2 is correct.
What is the corresponding angle theorem state?The theorem states that,
The lines 'AB' and 'CD' are parallel and cut by a transverse 'EF' if and only if their corresponding angles are congruent.
Corresponding angles:The corresponding angles are those which lie on the same side of the transverse one is interior and the other is an exterior angle.
From the diagram,
Lines 'AB' and 'CD' are parallel and line 'EF' cuts these parallel lines.
So, the corresponding angles formed are:
(∠1, ∠5), (∠2, ∠6), (∠3, ∠7), and (∠4, ∠8)
According to the theorem, they are congruent. I.e.,
∠1 ≅ ∠5
∠2 ≅ ∠6
∠3 ≅ ∠7
∠4 ≅ ∠8
So, option 2 is correct.
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Disclaimer: The given question is incorrect. Here is the correct question.
Question: Lines 'c' and 'd' are parallel lines cut by the transversal 'p'. Which must be true by the corresponding angles theorem?
1) ∠1 = ∠7
2) ∠2 = ∠6
3) ∠3 = ∠5
4) ∠5 = ∠7
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack of crackers to the number of calories in each snack pack of trail mix.
A number line goes from 65 to 115. Crackers's whiskers range from 70 to 100, and the box ranges from 75 to 85. A line divides the box at 80. Cookies's whiskers range from 70 to 115, and the box ranges from 90 to 105. A line divides the box at 100.
Which statement is true about the box plots?
The interquartile range of the trail mix data is greater than the range of the cracker data.
The value 70 is an outlier in the trail mix data.
The upper quartile of the trail mix data is equal to the maximum value of the cracker data.
The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
The statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
What is a Measure of Variation?For a data distribution that is displayed by a box plot, the measure of variation that can be used to describe the data distribution is the interquartile range.
What is the Interquartile Range of a Data Distribution?Interquartile range, which is a measure of variation can be determined from a box plot by finding the value of the third quartile and first quartile, the finding their difference. The difference is the interquartile range.
Interquartile range = third quartile - first quartile.
Interquartile range for crackers = 85 - 75
Interquartile range for crackers = 10
Interquartile range for trail mix = 105 - 90
Interquartile range for trail mix = 15.
The bigger the value of the interquartile range, the more variation there is that exist in a data distribution.
Interquartile range for trial mix is the largest, therefore, the statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
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