A company's sales equal $60,000 and cost of goods sold equals $20,000. Its beginning inventory was $1,600 and its ending inventory is $2,400. The company's inventory turnover ratio equals:

Answer:

  f(x) = x³ -4x² +9x +164

Step-by-step explanation:

When a function has a zero at x=p, it has a factor (x-p). When a polynomial function with real coefficients has a complex zero, its conjugate is also a zero.

Given the two zeros and the one we can infer, we can factor our 3rd-degree polynomial function as ...

  f(x) = a(x -(-4))·(x -(4+5i))·(x -(4-5i))

Using the factoring of the difference of squares, we can combine the complex factors to make a real factor.

  f(x) = a(x +4)((x -4)² -(5i)²) = a(x +4)(x² -8x +16 +25)

The value of this at x=1 is ...

  f(1) = a(1 +4)(1 -8 +41) = 170a

We want f(1) = 170, so ...

  170 = 170a   ⇒   a=1

The factored polynomial function is ...

  f(x) = (x +4)(x² -8x +41)

Expanding this expression, we have ...

  f(x) = x(x² -8x +41) +4(x² -8x +41) = x³ -8x² +41x +4x² -32x +164

  f(x) = x³ -4x² +9x +164

The attached graph verifies the real zero (x=-4) and the value at x=1. It also shows that the factor with complex roots has vertex form (x -4)² +25, exactly as it should be.

Answer:

[tex]f(x) = (x+4)(x^2-8x+41)[/tex]

Step-by-step explanation:

Ok, so there are a couple of things to note here. The first thing is that there is a complex solution

Complex Conjugate Root Theorem:

    if [tex]a-bi[/tex] is a solution then [tex]a+bi[/tex] is a solution and vice versa

Fundamental Theorem Of Algebra:

   Any polynomial with a degree "n", will have "n" solutions. Those solutions can be real and imaginary numbers

So since we're given the root: [tex]4+5i[/tex], we can use the Complex Conjugate Root Theorem to assert that: [tex]4-5i[/tex] is also a solution.

So now we know 3 solutions/zeroes, and since n=3 (the degree), we can know for a fact that we have all the solutions due to the Fundamental Theorem of Algebra.

So using these roots, we can express the polynomial as it's factors. When you express a polynomial as factors it'll look something like so: [tex]f(x) = a(x-b)(x-c)(x-d)...[/tex] where a, b, and d are zeroes of the polynomial. Also notice the "a" value? This will affect the stretch/compression of the polynomial.

So let's express the polynomial in factored form:

[tex]f(x) = a(x-(-4))(x-(4+5i))(x-(4-5i))[/tex]

Simplify the x-(-4)

[tex]f(x) = a(x+4)(x-(4+5i))(x-(4-5i))[/tex]

Now let's distribute the negative sign to the complex roots

[tex]f(x) = a(x+4)(x-4-5i)(x-4+5i))[/tex]

Now let's rewrite the two factors (x-4-5i) and (x-4+5i) so the (x-4) is grouped together

[tex]f(x) = a(x+4)((x-4)-5i)((x-4)+5i))[/tex]

If you look at the two complex factors, this looks very similar to the difference of squares: [tex](a-b)(a+b) = a^2-b^2[/tex]

In this case a=(x-4) and b=5i. So let's use this identity to rewrite the two factors

[tex]f(x) = a(x+4)((x-4)^2-(5i)^2)[/tex]

Let's expand out the (x-4)^2

[tex]f(x) = a(x+4)(x^2+2(-4)(x)+(-4)^2-(5i)^2)[/tex]

Simplify

[tex]f(x) = a(x+4)(x^2-8x+16-(5i)^2)[/tex]

Now simplify the (5i)^2 = 5^2 * i^2

[tex]f(x) = a(x+4)(x^2-8x+16-(-25))[/tex]

Simplify the subtraction (cancels out to addition)

[tex]f(x) = a(x+4)(x^2-8x+41)[/tex]

So just to check for the value of "a", we can substitute 1 as x, and set the equation equal to 170

[tex]170 = a(1+4)(1^2-8(1)+41)\\170 = a(5)(1-8+41)\\170 = a(5)(34)\\170 = 170a\\a=1[/tex]

In this case it's just 1, so the polynomial can just be expressed as:
[tex]f(x) = (x+4)(x^2-8x+41)[/tex]

Solve the second equation for [tex]t[/tex], then substitute it into the first equation.

[tex]y = t + 2 \implies t = y-2[/tex]

[tex]x = t^2 - 3 \implies \boxed{x = (y-2)^2 - 3}[/tex]

Answer:

250.

Step-by-step explanation:

if one coin covers 1.14 cm, then the required number can be calculated according the equality:

required_number=(given_length/given_diameter);

Then:

[tex]number=\frac{2.85*100}{1.14} =\frac{285}{1.14} =250[coins].[/tex]

P.S. note, the given length is in [meter], the diameter is in [cm].

Answer:

Domain: All Real Numbers

Range: All Real Numbers

Step-by-step explanation:

So the domain of a function can be defined as an interval of x-values, which you can input into the function and get real numbers as an output. Since we have a cube root here, or more specifically an odd nth root, the domain is all real numbers, since cbrt(negative number) will just be a negative number since (negative number * negative number * negative number) = negative number, so there does exist a solution, unlike even nth roots like square root, which is restricted to only positive values inside the radical, otherwise you get non-real solutions.

Now let's look at the range of the function, which can be defined as an interval of y-values which can possibly be outputted by the function.

Since as mentioned before, the cube root isn't limited to a certain interval, and rather all real numbers, the range is also similar, since whenever you have a negative number in the radical, the output will be a negative number, so the range is all real numbers

The answer is A.

As any number can be inputted in place of x and the result, y, will be directly proportional to the inputting value, the domain and range of the function is All Real Numbers.

The pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

The complete question is added as an attachment

Function 1

f(x) = 5x - 11 and g(x) = (x + 11)/5

Represent 5x - 11 with y in f(x) = 5x - 11

y = 5x - 11

Swap x and y

x = 5y - 11

Add 11 to both sides

x + 11 = 5y

Divide by 5

y = (x + 11)/5

Express as a function

g(x) = (x + 11)/5

From the question, we have:

f(x) = 5x - 11 and g(x) = (x + 11)/5

This means that the function g(x) is an inverse of the function f(x)

Hence, the pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

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In conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

In relation to the statistical model, the test tells how well it fits a set of observations.

The measures of the goodness of fit summarize the discrepancy between observed values and the values expected under the model in question.

Also, when conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

Therefore, the Option B is correct,

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For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:

The sum of all the probabilities must be of 1, hence:

P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.

Then, considering the table:

P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1

P(X = 0) + P(X = 1) + 0.56 = 1

P(X = 0) + P(X = 1) = 0.44.

Hence one possible example is:

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Answer:

-1

Step-by-step explanation:

0.35 - 0.8 = -0.45

-0.1 - 0.35 = -0.45

-0.55 - 0.45 = -1

Answer:

Step-by-step explanation:

speed = 50 km / hr.

distance = 20 km

time = distance / speed.

time = ( / 50) hr.

speed =  2 km/hrs

Answer:

  A.  (-1, -4)

Step-by-step explanation:

The vertex can be found by converting the equation from standard form to vertex form.

Considering the x-terms, we have ...

  y = (x^2 +2x) -3

where the coefficient of x is 2. Adding (and subtracting) the square of half that, we get ...

  y = (x^2 +2x +(2/2)^2) -3 -(2/2)^2

  y = (x +1)^2 -4

Compare this to the vertex form equation ...

  y = a(x -h)^2 +k

which has vertex (h, k).

We see that h=-1 and k=-4. The vertex is (h, k) = (-1, -4).

On the attached graph, the vertex is the turning point, the minimum.

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

The two triangles are right angled Triangles and they have one common angle. so the two triangles are similar to each other.

By using similarity, ratio of their corresponding sides must be equal as well~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{2 + 1} = \cfrac{3}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{1}{3} = \cfrac{3}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 3 \times 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 9 \: \: units[/tex]

Answer:

84,08964 [gr.].

Step-by-step explanation:

for more details see in the attachment.

The number of tickets sold are:

From the question, we have the following parameters:

Represent the children tickets with x and adults ticket with y.

So, we have the following system of equations

x + y = 63

6x + 8y = 444

Express the equations as a matrix

x      y

1       1       63

6      8       444

Apply the following transformation

R2 = R2 - 6R1

This gives

x      y

1       1       63

0      2       66

Apply the following transformation

R2 = 1/2R2

x      y

1       1       63

0      1       33

From the above matrix, we have the following system of equations

x + y = 63

y = 33

Substitute y = 33 in x + y = 63

x + 33 = 63

Subtract 33 from both sides of the above equation

x = 30

Hence, 30 children tickets were sold and 33 adult tickets were sold

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The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

The zeros of a polynomial f(x) are really the values of x that answer the equation f(x) = 0. Thus, f(x) is a function of x, and the polynomial zeros refer to the values of x, which makes the f(x) value equal to zero. The digit of zeros in a polynomial is decided by the degree of equation f(x) = 0.

For a polynomial, there may be specific values of the variable for which the polynomial is zero. These are known as polynomial zeros. They are also known as polynomial roots. In essence, we look for the zeros of quadratic equations to discover the solutions to the given equation.

From the given equation, the zeros of x^4-2x^3-44x^2-88x-32 can be computed as follows:

Using the rational root theorem:

[tex]\mathbf{= (x+2)\dfrac{x^4-2x^3-44x^2-88x-32}{x+2} }[/tex]

[tex]\mathbf{=(x+2) (x^3-4x^2-36x-32) }[/tex]

By factorization, we have:

= (x + 2) (x + 4) (x² - 8x - 4)

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

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If the price of 1 cubic foot of hay is $10 then the money needed is $15.

Given the price of 1 cubic foot of hay be $10 and the amount of hay be $1.50.

We are required to find the amount of money needed to buy the hay.

We know that the amount of money that can be spend on something is the product of price of one unit and number of units.

Product is the result when two numbers are multiplied with each other.

Total money =Price of 1 cubic foot*$1.50

=10*1.50

=$15

Hence if the price of 1 cubic foot of hay is $10 then the money needed is $15.

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Question is incomplete, the right question is as under:

1.5 cubic foot hay is required to fill a room completely. Calculate the amount we have to pay to fill the room completely if the price of 1 cubic foot is $10?

Answer:

28/57

Step-by-step explanation:

odds in favor of event occurring = (probability event occurs)/(probability event does not occur)

Let p = probability event occurs.

Then the probability the event does not occur is 1 - p.

Let the odds = a/b.

a/b = p/(1 - p)

a(1 - p) = bp

a - ap = bp

bp + ap = a

p(a + b) = a

p = a/(a + b)

p = 28/(28 + 29)

p = 28/57

As per the given scenario, the probability of event E is 28/57 or approximately 0.4912.

Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to occur.

If the odds in favor of an event E are "a to b," then the probability of E is given by:

P(E) = a / (a + b)

In this case, the odds in favor of E are 28 to 29, which means that there are 28 favorable outcomes for E and 29 unfavorable outcomes against E.

So, using the formula above, we can compute the probability of E as:

P(E) = 28 / (28 + 29)

P(E) = 28 / 57

Therefore, the probability of event E is 28/57 or approximately 0.4912.

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Answer:

x = 159; y = 140

Step-by-step explanation:

a = 40

a + y = 180

y = 180 - 40

y = 140

b = 61

b = (180 - x) + a

61 = 180 - x + 40

x = 159

Answer:

m∠x = 159°

m∠y = 140°

Step-by-step explanation:

Given information

∠a = 40°

Given formula

∠a + ∠y = 180° (Supplementary angles)

Substitute values into the formula

40 + ∠y = 180

∠y = 180 - 40

[tex]\Large\boxed{\angle y=140^\circ}[/tex]

Given information

∠b = 61°

∠c = Supplementary angle of ∠b

Given formula

∠b + ∠c = 180°

Substitute values into the formula

61 + ∠c = 180

∠c = 180 - 61

∠c = 119°

Determine the value of ∠x

∠x = ∠a + ∠c (Exterior angle theorem)

∠x = (40) + (119)

[tex]\Large\boxed{\angle x=159^\circ}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

53 mph   and  71 mph

Step-by-step explanation:

bus 1 rate = x

bus 2 rate = x + 18

rate times time = distance

( x    +    x+18) * 6 = 744

(2x+18) * 6 = 744

2x + 18 = 124

2x = 106

x = 53       the other bus is  53 + 18 =  71  mph

Using the binomial distribution, there is a 0.0874 = 8.74% probability that not enough seats will be available.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

For this problem, the values of the parameters are given by:

n = 15, p = 0.85.

The probability that not enough seats will be available is P(X = 15), as the only outcome in which not enough seats will be available is when all 15 people who bought the ticket show up, hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 15) = C_{15,15}.(0.85)^{15}.(0.15)^{0} = 0.0874[/tex]

0.0874 = 8.74% probability that not enough seats will be available.

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The exponential model for the data is: [tex]y = 693(1.5)^x[/tex]

When the cost is of $6000, the weight is of approximately 5.3 carats.

An exponential function is modeled by:

[tex]y = ab^x[/tex]

In which:

From the table, the rate of change is given by:

b = 4980/3210 = 3210/2140 = 2140/1430 = 1.5.

When x = 1, y = 1040, hence the initial value is found as follows:

1.5a = 1040.

a = 1040/1.5

a = 693.

So the model is:

[tex]y = 693(1.5)^x[/tex]

When the cost is of $6000, the weight is found as follows:

[tex]693(1.5)^x = 6000[/tex]

[tex](1.5)^x = \frac{6000}{693}[/tex]

[tex]1.5^x = 8.658[/tex]

[tex]\log{1.5^x} = \log{8.658}[/tex]

x log(1.5) = log(8.658)

x = log(8.658)/log(1.5)

x = 5.3

When the cost is of $6000, the weight is of approximately 5.3 carats.

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Applying the definition of the median of a triangle: x = 9; CD = 28; DB = 28.

The median of a triangle can be defined as a line segment in a triangle that joins the vertex of a triangle to the midpoint of the side of the triangle that is opposite the vertex.

Given triangle ABC, where AD is the median and D is the midpoint of side AB, therefore:

Side CD equals side DB.

Side CD = 5x - 17

Side DB = 3x + 1

Make both segments equal to each other. Therefore, we would have the equation:

5x - 17 = 3x + 1

Solve for x

Add both sides by 17

5x - 17 + 17 = 3x + 1 + 17

5x = 3x + 18

Subtract 3x from both sides

5x - 3x = 3x + 18 - 3x

2x = 18

Divide both sides by 2

2x/2 = 18/2

x = 9

CD = 5x - 17

Plug in the value of x

CD = 5(9) - 17

CD = 45 - 17

CD = 28 units.

DB = 3x + 1

Plug in the value of x

DB = 3(9) + 1

DB = 27 + 1

DB = 28 units.

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! is shorthand for the factorial function. If [tex]n[/tex] is a non-negative integer, then

[tex]n! = n\times(n-1)\times(n-2)\times\cdots3\times2\times1[/tex]

with [tex]0! = 1[/tex].

So how to compute [tex]n![/tex] ?

Multiply each number in sequence from that number to 1.

Answer: -1

Step-by-step explanation:

Here, we are subtracting two fractions; therefore, we must make the denominators the same by finding the least common multiple. Since we have x - 3 for one denominator and x + 2 for the other, we don't have any common factors. Hence, the least common multiple would be their product.

[tex](x-3)(x+2)\\x(x-3)+2(x-3)\\x^2-3x+2x-6\\x^2-x-6[/tex]

The question is looking for the coefficient of the second term. Since there is just a negative sign in front of the x, the "?" can be filled with either a negative sign or a -1.

Answer:

True

Step-by-step explanation:

This is true in an equilateral triangle.

Answer:

a = -6

b = -8

c = 12

Step-by-step explanation:

Quadratic equations follow the general structure:

ax² + bx + c = 0

In this equation, "a" and "b" serve as coefficients which modify the variables and "c" represents the y-intercept. Since the given equation is in the quadratic form, you can easily identify which values match the variables.

-6x² - 8x + 12 = 0

a = -6

b = -8

c = 12

The amount received net of expenses is $397865 and the percentage of the sale price was 10%.

Given that Bourassas decides to sell a house for $ 440,000. You will be charged a real estate fee of 8% of the sale price, property insurance of 1.4% of the sale price, and an escrow fee of $ 775.

The declared retail price is $ 440,000.

Real estate commission = 8% of the sale price

Real Estate Fee = (8/100) × 440000

Real Estate Fee = 8 × 4400

Real Estate Fee = $ 35,200

Security insurance costs of the title = 1.4% of the sale price

Cost of title insurance = (1.4 / 100) × 440 000

Cost of title insurance = 1.4 × 4400

Title Insurance Cost = $ 6160

The escrow fee assigned is $ 775.

(a) In determining the amount received after deducting the sale price of the property commission, title insurance and escrow fees, we receive

Amount received after fees = sale price - real estate commission - title insurance - escrow fees

Amount received after fees = 440000-35200-6160-775

The amount received after fees = $397865

(b) To find the percentage of sale price, add together all the terms real estate commission, title insurance and escrow fees and divide by the sale price we get

Percentage of selling price=((35200+6160+775)/440000)×100

Percentage of sale price = (42135/440000) × 100

Percentage of sale price = 9.57

Percentage of sale price = 10% (rounded down)

Hence Bourassas decides to sell a house for $440,000, then the amount Bourassas will receive after expenses is $397,865 and the percentage of the sale price of expenses is 10%.

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Answer: If they worked together, it would take 31.5 minutes

Step-by-step explanation:

There's a certain formula for equations like this:

[tex]\frac{1}{t1} +\frac{1}{t2}=\frac{1}{tb}[/tex]

t1= the time it took for the first person to complete the task.

t2= the time it took for the second person to complete the task.

tb= the time it took for both of them to complete the task.

We have the values for both t1 and t2, but not for tb.

t1= 45

t2= 105

tb= x

[tex]\frac{1}{45} +\frac{1}{105} = \frac{1}{x}[/tex]

Now it's simple algebra, and all we need to do is solve for x

The LCM for both fractions is 315, so now we multiply BOTH sides of the equation by 315.

[tex]\frac{315}{45} + \frac{315}{105} = \frac{315}{x}[/tex]

This will simplify nicely, so now we just need to get x on the other side.[tex]7 + 3 = \frac{315}{x} \\\\\ 10*x = \frac{315}{x} * x[/tex]

[tex]10x = 315 \\\\x = 31.5[/tex]