Rejected masses x are those that weigh less than 9.02 oz or more than 9.48 oz.
What is the range?In mathematics, the range of a function can refer to one of two notions that are closely related.The function's codomain, the function's visual representation.A binary relation f between two sets X and Y is a function if for every x in X there is exactly one y in Y such that f relates x to y.To find the rejected masses:
If each pack of trail mixes is supposed to weigh 9.25 oz and must be within 0.23 oz of that weight to be accepted, then rejected masses x are those that weigh less than 9.02 oz or more than 9.48 oz.Therefore, rejected masses x are those that weigh less than 9.02 oz or more than 9.48 oz.
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The correct question is given below:
A company did a quality check on all the packs of trail mix it manufactured. each pack of trail mix is targeted to weigh 9.25 oz. a pack must weigh within 0.23 oz of the target weight to be accepted. what is the range of rejected masses, ×, for the manufactured trail mixes?
PLS HELP ASAP! Ty
Let g(x)= 2x^2+3x-9 and h(x)=x^2+2x-6
Find (h-g)(2.1)
The function can be solved as follows:
(h - g)(2.1) = 3.51
How to solve a function?g(x) = 2x² + 3x - 9
h(x) = x² + 2x - 6
(h - g)(x) = h(x) - g(x)
(h - g)(x) = 2x² + 3x - 9 - ( x² + 2x - 6)
(h - g)(x) = 2x² + 3x - 9 - x² - 2x + 6
(h - g)(x) = 2x² - x² + 3x - 2x - 9 + 6
(h - g)(x) = x² + x - 3
Therefore,
(h - g)(2.1) = (2.1)² + (2.1) - 3
(h - g)(2.1) = 4.41 + 2.1 - 3
(h - g)(2.1) = 6.51 - 3
(h - g)(2.1) = 3.51
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If you want to connect your home network to the internet, you will need a ________ in addition to a modem.
Answer:
landline
hshdjdh
dbbdhdhdh
bdbdhdhdhe
Answer:
Router
Step-by-step explanation:
Hope this helps
I’m gonna ask this question again can someone help me solve this and leave in terms of pi
The equation of the circumference of a circle in terms of [tex]\pi[/tex] is [tex]2\pi r[/tex] or [tex]\pi d[/tex].
The circumference for a circle with diameter 10 is [tex]10\pi[/tex].
The circumference for a circle with diameter 19 is [tex]19\pi[/tex].
The circumference for a circle with diameter 30 is [tex]30\pi[/tex].
The circumference for a circle with diameter 16 is [tex]16\pi[/tex].
Relatively easy, right?
The equation of the area of a circle in terms of [tex]\pi[/tex] is [tex]\pi r^2[/tex].
The area of a circle with radius 5 is [tex]25\pi[/tex].
The area of a circle with radius 9.5 is [tex]90.25\pi[/tex].
The area of a circle with radius 15 is [tex]225\pi[/tex].
The area of a circle with radius 8 is [tex]64\pi[/tex].
Hope this helped!
(By the way, I don't know why you're using hard formulas for trying to find the radius or diameter. The diameter is simply twice the radius, and the radius is simply half the diameter.)
Answer:
Circumference = 10[tex]\pi[/tex], 19[tex]\pi[/tex], 30[tex]\pi[/tex], 16[tex]\pi[/tex]
Area = 25[tex]\pi[/tex], 90.25[tex]\pi[/tex], 225[tex]\pi[/tex], 64[tex]\pi[/tex]
Step-by-step explanation:
For the first row we have the radius which is 5, the diameter is 10. The formula for circumference is 2[tex]\pi[/tex]r. So for this one its gonna be 2[tex]\pi[/tex]5 or 10[tex]\pi[/tex]
radius = 5
diameter = 10
circumference = 2[tex]\pi[/tex]5 or 10[tex]\pi[/tex]
area = [tex]\pi[/tex][tex]5^{2}[/tex] or 25[tex]\pi[/tex]
for the second row
radius = 9.5
diameter = 19
circumference = 2[tex]\pi[/tex]9.5 or 19[tex]\pi[/tex]
area = [tex]\pi[/tex][tex]9.5^{2}[/tex] or 90.25[tex]\pi[/tex]
for the third row
radius = 15
diameter = 30
circumference = 2[tex]\pi[/tex]15 or 30[tex]\pi[/tex]
area = [tex]\pi[/tex][tex]15^{2}[/tex] or 225[tex]\pi[/tex]
for the fourth row
radius = 8
diameter = 16
circumference = 2[tex]\pi[/tex]8 or 16[tex]\pi[/tex]
area = [tex]\pi[/tex][tex]8^{2}[/tex] or 64[tex]\pi[/tex]
Which graph represents the equation y2 = –4x?
On a coordinate plane, a parabola opens to the left. It has a vertex at (0, 0), a focus at (negative 1, 0), and a directrix at x = 1.
On a coordinate plane, a parabola opens down. It has a vertex at (0, 0), a focus at (0, negative 1), and a directrix at y = 1.
On a coordinate plane, a parabola opens to the left. It has a vertex at (0, 0), a focus at (negative 4, 0), and a directrix at x = 4.
On a coordinate plane, a parabola opens down. It has a vertex at (0, 0), a focus at (0, negative 4), and a directrix at y = 4.
Answer:
its A
Step-by-step explanation:
Answer: The first one (A)
Step-by-step explanation:
for each reasons it gives you the options to choose: commutative property of addition, associative property of addition, distributive property, and combining like terms
The distributive Property States that when a factor exists multiplied by the sum/addition of two terms, it exists critical to multiply each of the two numbers by the factor, and eventually complete the addition operation.
Let the expression be 4+(6+8u)
4 + (6 + 8u) = (4 + 6) + 8u
What is a distributive property?The distributive Property States that when a factor exists multiplied by the sum/addition of two terms, it exists critical to multiply each of the two numbers by the factor, and eventually complete the addition operation.
Adding (distributing) the first numbers of each set, outer numbers of each set, inner numbers of each set, and the last numbers of each set. Combine like terms. Solve the equation and simplify, if needed.
The expression be 4+(6+8u)
4+(6+8u) = (4 + 6)+8u
Therefore, the correct answer is distributive property.
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1. Part A. Graph the following coordinates on the grid below.
(4, 3), (4,-5), (-2, 3), and (-2,-5)
Answer:
Step-by-step explanation:
a) start at the origin (0,0) then go 4 boxes to the right, 3 up
b) start at the origin (0,0) then go 4 boxes to the right, 5 down
c) start at the origin (0,0) then go 2 boxes to the left, 3 up
d) start at the origin (0,0) then go 2 boxes to the left, 5 down
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Find the inverse of the given function.
The inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3 is f⁻¹(x) = 4x² - 3, for x ≤ - 1/2.
In the question, we are asked to find the inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3.
The domain for the given function is x ≥ -3.
Thus, its range is x ≤ - 1/2.
To find the inverse, we equate f(x) = y, to get:
(-1/2)√(x + 3) = y,
or, √(x + 3) = -2y.
Squaring both sides, we get:
x + 3 = (-2y)²,
or, x + 3 = 4y²,
or, x = 4y² - 3.
Thus, the inverse of the function f(x) = (-1/2)√(x + 3), is, f⁻¹(x) = 4x² - 3.
The inverse will have the domain equal to the range of the original function, that is, x ≤ - 1/2.
Thus, the inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3 is f⁻¹(x) = 4x² - 3, for x ≤ - 1/2.
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The provided question is incomplete. The complete question is:
"Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Find the inverse of the given function.
f(x) = (-1/2)√(x + 3), x ≥ -3
f⁻¹(x) = x² - , for x ≤ ."
The external and the internal radii of a hollow cylindrical metallic vessel 56 cm long are 10.5 cm and 10.1 cm respectively. Find the cost of the metal contained by the vessel at Rs 2 per cubic cm. Also, find the cost of polishing it's outer surface 20 paisa per square cm.
The total cost of polishing it's outer surface 20 paisa per square cm exists Rs. 738.58.
How to estimate the cost of polishing metallic vessel outer surface 20 paisa per square cm.?External radius of the hollow cylinder = 10.5 cm
Internal radius of the hollow cylinder = 10.1 cm
Height of the hollow cylinder = 56 cm
Cost to Polish Outer Surface: 20 paisa/sq. cm.
Surface Area of Hollow Cylinder = Circumference [tex]*[/tex] height
Surface area of hollow cylinder = 2 π r h
= 2 π (10.5 cm) 56 cm
= π (21)(56)
= 3692.64 [tex]cm^2[/tex] (Using π ≈ 3.14 rounding to 2 digits)
Total Cost of metallic cylinder [tex]$= 3692.64 cm^2 * 20 paisa/cm^2[/tex]
= 73,852.8 paisa
= Rs. 738.58
Therefore, the total cost of polishing it's outer surface 20 paisa per square cm exists Rs. 738.58.
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A grocery store sells a bag of 3 oranges for $1.23. If Latanya spent $3.28 on oranges, how many did she buy?
Answer: 8 Oranges
Step-by-step explanation:
Given information
3 Oranges = $1.23
Total cost = $3.28
Determine the unit price of an orange
Unit price = Cost ÷ Number of Oranges
Unit price = 1.23 ÷ 3
Unit price = $0.41 / orange
Determine the number of oranges bought
Number of orange × Unit price = Total cost
N × (0.41) = (3.28)
Divide 0.41 on both sides
N = 3.28 ÷ 0.41
[tex]\Large\boxed{Number~of~oranges=8}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Write the event as set of outcomes. when we roll two dice, the total showing is eight.
Given that and are supplementary angles and that , explain how to find the measure of the complement of .
The measure of the complement is 25°.
What is supplementary and complementary angles?If the sum of two angles is 180 degrees then they are said to be supplementary angles, which form a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.
Given that, [tex]A_{1}[/tex] = 115°
sum of two angles [tex]A_{1}+A_{2} = 180[/tex]°
[tex]A_{2} = 180- A_{1}[/tex]
[tex]A_{2} = 180- 115[/tex]
[tex]A_{2} = 65[/tex]°
Since, [tex]A_{1}[/tex] and [tex]A_{2}[/tex] are supplementary angles.
Now,
Complementary angles add to 90, so the complement of [tex]A_{2}[/tex] is 90 - [tex]A_{2}[/tex] .
Then,
90-65
= 25°
Hence, The measure of the complement is 25°.
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–4.9(–7.3 + 3.6n) =
Simplify the expression please :)
Which combination of shapes can be used to create the 3-D figure?
Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.
According to the statement
we have to tell and explain about the types of shapes which are required for the creations of 3-D figure.
For this purpose, Firstly we have to know about the 3-D figures.
So,
A shape is a graphical representation of an object or its external boundary and outline, as opposed to other properties such as color, texture, or material type.
A plane shape is constrained to lie on a plane, in contrast to solid 3-D shapes.
After that we know that the
When the all dimensions of a given shape can be observed at the same time, then its is said to be in a 3-D. However, polygons are shapes which has 3 or mores sides. Examples are: trigon, hexagon, octagon etc.
Thus, since the in the 3-D figure have 8 sides connected which is greater than their width.
This confirms that the sides of the figure made up of eight congruent rectangles, because the 3-D figure has eight regular sides. Then, the height of the figure would be the length of the rectangles.
After that all this condition, Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.
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help with equation points included
The logarithmic equation f(x) = log₈(x + 1) + 4 is shifted left by 1 unit and up by 4 units
How to determine the transformation?The logarithmic equation is given as:
f(x) = log₈(x + 1) + 4
The parent function of the logarithmic equation is
y = log₈(x)
When the logarithmic equation is translated 1 unit left, we have:
y = log₈(x + 1)
When the logarithmic equation is translated 4 units up, we have:
y = log₈(x + 1) + 4
This means that the logarithmic equation f(x) = log₈(x + 1) + 4 is shifted left by 1 unit and up by 4 units
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EEF has vertices D(1, 3), E(2, -4), and F(-3, 1). What are the vertices T<4, 1> (DEF).
The vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)
How to determine the vertices?The vertices of the triangle are given as:
D(1, 3), E(2, -4), and F(-3, 1).
The transformation represented by T<4, 1> (DEF) is:
(x,y) = (x + 4, y + 1)
So, we have;
D' = (1 + 4, 3 + 1)
D' = (5, 4)
E' = (2 + 4, -4 + 1)
E' = (6, -3)
F' = (-3 + 4, 1 + 1)
F' = (1, 2)
Hence, the vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)
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A class trip to a beach has been planned for your senior trip. the resort only allows swimming when the temperature is between 75 degrees and 110 degrees. there is room for 50 people on your trip. write the constraints to represent this real-world problem, where x is the temperature and y is the number of people on your trip. 0 < x ≤ 50 and 75 < y < 110 x > 75 and y < 110 75 < x < 110 and 0 < y ≤ 50 x < 110 and y > 75
This real-world problem has the limitations 75< x <110 and 0< y[tex]\leq[/tex] 50, hence:
option (C) is the best choice.
What is Inequality ?The term "inequality" refers to a mathematical expression in which both sides have mathematical signs that are either less than or greater than one another, and the expression is one where the two sides are not on equal footing.
We have:
Your senior vacation is scheduled to include a class trip to a beach. Only when it's between 75 and 110 degrees do guests at the resort get access to the pool. 50 passengers can go with you.
Let y be the number of passengers and x be the temperature
75 to 110 degrees are the range of the temperature.
75 < x < 110
50 passengers can go with you.
0 < y ≤ 50
In order to illustrate this real-world issue, the limitations are 75 <x <110 and 0< y [tex]\leq[/tex]50.
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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b to complete the solutions.
The roots of the given polynomials exist [tex]$x=8+\sqrt{10}$[/tex], and [tex]$x=8-\sqrt{10}$[/tex].
What is the formula of the quadratic equation?For a quadratic equation of the form [tex]$a x^{2}+b x+c=0$[/tex] the solutions are
[tex]$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$[/tex]
Therefore by using the formula we have
[tex]$x^{2}-16 x+54=0$$[/tex]
Let, a = 1, b = -16 and c = 54
Substitute the values in the above equation, and we get
[tex]$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$[/tex]
simplifying the equation, we get
[tex]$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\[/tex]
[tex]$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\[/tex]
[tex]$&x=8+\sqrt{10}, x=8-\sqrt{10}[/tex]
Therefore, the roots of the given polynomials are [tex]$x=8+\sqrt{10}$[/tex], and
[tex]$x=8-\sqrt{10}$[/tex].
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Answer:
x=8-[tex]\sqrt{10}[/tex] and x=8+[tex]\sqrt{10}[/tex]
Step-by-step explanation:
It was right for me
Simplify each exponential expression using the properties of exponents and match it to the correct answer.
The match of solutions with the exponential expressions is
1) [tex]\frac{(2(3^{-2}) )^{3} (5(3^{2}) )^{2} }{(3^{-2})((5)(2))^{2}}=2[/tex]
2) [tex](3^3) (4^0)^2 (3(2))^{-3} (2^2)=1/2[/tex]
3) [tex]\frac{(3^74^7) (2(5))^{-3} (5)^2}{(12^7) (5^{-1}) (2^{-4})} =2[/tex]
4) [tex]\frac{(2(3))^{-1} (2^0)}{(2(3))^{-1}}=1[/tex]
What are properties of exponents?The base will be multiplied by itself a certain number of times, as indicated by the exponent (also known as a power or degree).
What are the formulae/ properties for exponents?Formulae for solving exponents are referred to as exponents formulas. The exponent of a number is written as [tex]x^{n}[/tex], which means that x has been multiplied by itself n times.
[tex]x^{n}(x^{m})=x^{n+m} \\\frac{x^{n} }{x^{m} }=x^{n-m} \\(x^{n} )^{m} =x^{nm} \\((x)(y))^{n}=x^{n}(y^{n} \\x^{0}=1[/tex]
1) the solution of the first expression will be
[tex]\frac{(2(3^{-2}) )^{3} (5(3^{2}) )^{2} }{(3^{-2})((5)(2))^{2}}[/tex]
[tex](2^3) (3^{-6} ) (5^2) (3^4) / (3^{-2}) (10^2)= (2.2^2.5^2) (3^{-6}.3^4) / (3{^-2}) (10^2)= (2)(10^2) (3^{-2}) / (3^{-2}) (10^2)\\=2[/tex]
2)The solution of the second expression will be
[tex](3^3) (4^0)^2 (3(2))^{-3} (2^2)[/tex]
Any number with power zero is 1.
So,
[tex](3^3) (1^2) (3^{-3}) (2^{-3}) (2^2)= (2^{(-3+2)})=2^-1\\= 1/2[/tex]
3) The solution of third expression will be
[tex]\frac{(3^74^7) (2(5))^{-3} (5)^2}{(12^7) (5^{-1}) (2^{-4})} \\= \frac{(12^7) (2^{-3}) (5^{-3}) (5^2)}{(12^7) (5^{-1}) (2^{-4})} =\frac{(2^-3) (5^{(-3+2)})}{(5^{-1}) (2^{-4})} = \frac{(2^{-3}) (5^{-1})}{(5^{-1}) (2^{-}4)} = \frac{1}{(2^{-1})} = 2[/tex]
4) The solution to the forth expression will be
[tex]\frac{(2(3))^{-1} (2^0)}{(2(3))^{-1}}\\=2^{0}\\ =1[/tex]
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Answer:
The person above litteraly gave you the answer just reread the first equations and then you will figure it out
Step-by-step explanation:
I have 90% after about 75%
of the semester. What's the
lowest grade I could earn at
the end of the semester?
The lowest grade he could earn is 120% of the grade at the end of the semester.
The following statement is given:
I have 90% after about 75% of the semester.
We are asked to find the lowest grade by the end of this semester.
What is Percentage?A percentage is a number expressed as a fraction of 100.
- 50% = 50/100 = 1/2
- 25% = 25/100 = 1/4
- 20% = 20/100 = 1/5.
We can write this statement "I have a 90% grade after about 75% of the semester" as:
90% grade = 75% semester.............(1)
By the end of the semester means at 100% semester.
Multiplying equation (1) by 100/ 75 on both sides of the equation.
We get,
(100/75) x 90% grade = (100/75) x 75% semester
(100 x 90)/75 % grade = 100% semester
120% grade = 100%
Thus the lowest grade he could earn is 120% of the grade at the end of the semester.
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A gallon of Moo Milk costs 5.12$
What is the price, in dollars, of an 8 ounce glass of Moo Milk?
Answer:
$0.32
Step-by-step explanation:
8 ounces is 1/16 of a gallon so
5.12*(1/16) = 0.32
Answer:
32 cents (0.32 dollars)
Step-by-step explanation:
One gallon contains 128 ounces
Calculate the cost of each ounce:
[tex]\frac{5.12}{128} =0.04[/tex]
costs 4 cents an ounce
Calculate the cost of 8 ounces:
[tex](8)(4)=32[/tex]
Hope this helps
help math pls lots of points!!!!!
Answer:
(f ￮ g)(11) = - 1
Step-by-step explanation:
evaluate g(11) then substitute the result obtained into f(x)
g(11) = 11 - 7 = 4 , then
f(4) = [tex]\sqrt{4}[/tex] - 3 = 2 - 3 = - 1
Bond Valuation with Semiannual Payments
Renfro Rentals has issued bonds that have an 8% coupon rate, payable semiannually. The bonds mature in 12 years, have a face value of $1,000, and a yield to maturity of 7.5%. What is the price of the bonds? Round your answer to the nearest cent.
If Renfro Rentals has issued bonds that have an 8% coupon rate, payable semiannually. The price of the bonds is: $1,039.11.
Price of the bondsWe would be making use of financial calculator to find or determine the price of the bonds (Present value) by inputting the below data:
N represent Number of years = 12 x 2 = 24
I represent Interest rate= 7.5 % / 2 =3.75 %
PMT represent Periodic payment= (8% x 1000) / 2 = $40
FV represent Future value= $1,000
PV represent Present value=?
Hence;
PV (Present value) = $1,039.11
Therefore if Renfro Rentals has issued bonds that have an 8% coupon rate ,payable semiannually. The price of the bonds is: $1,039.11.
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pls help ill give brainliest
a=
x=
Answer:
a = 12
x = 5.714
Step-by-step explanation:
sf = 15 / 9
20 / (15 / 9) = 12
a = 12
sf = 21 / 6
20 / (21 / 6)
x = 5.714
Every year a man is paid $500 more than the previous year. If he receives $17800 over four years, what was he paid in the first year
The amount paid to the man in the first year given the total he received in four years is $3,700.
EquationAmount paid in the first year = xAmount paid in the second year = (x + 500)Amount paid in the third year = x + 500 + 500= (x + 1000)
Amount paid in the fourth year = x + 500 + 500 + 500= (x + 1500)
Total payment = $17800Total payment = first year + second year + third year + fourth year
x + (x + 500) + (x + 1000) + (x + 1500) = 17,800
open parenthesisx + x + 500 + x + 1000 + x + 1500 = 17800
collect like terms4x + 3000 = 17,800
4x = 17,800 - 3000
4x = 14,800
divide both sides by 4x = 14,800/4
x = $3,700
Therefore, $3,700 was paid to the man in the first year.
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By selling 20 oranges for#1.35 a trader makes a profit of 8% what is the percentage gain or loss if he sells the same 20 oranges for#1.10?
Answer:
12% loss
Step-by-step explanation:
The selling price is the sum of the cost price and the markup. Here, the markup (profit) is expressed as a percentage of the cost price.
Cost priceThe relation between selling price and cost price is ...
selling price = cost price + cost price × markup fraction
selling price = cost price × (1 + markup fraction)
Then the original cost price is ...
cost price = (selling price) / (1 + markup fraction)
cost price = #1.35 / (1 +8%) = #1.25
ProfitAfter the change in selling price, we can find the markup fraction (profit rate) to be ...
1 + markup fraction = (selling price)/(cost price)
markup fraction = (selling price)/(cost price) -1
markup fraction = #1.10/1.25 -1 = 0.88 -1 = -0.12
The trader has a 12% loss when selling the oranges at #1.10.
Please help im not the brightest with math
Answer:
12 square in
Step-by-step explanation:
In the diagram, the diameter is 4 in. Radius is half the length of diameter, so the radius of the yellow circle is 2 in. Using the given formula, A = pi*r*r, we can calculate the approximate area of the circle.
A = pi*r*r = 3*2*2 = 12 square in
Answer:
12 in^2
Step-by-step explanation:
Since the formula to find the area of a circle is already up, we can use that to solve the question.
In the image, we can see that the diameter of the circle is 4inches. Since two radii equal one diameter, one radius is 2 inches.
--> The reason why we found the radius is because the 'r' in the formula means radius. We need the value of the radius to find the area of the circle.
Now, we can just replace r with 2.
--> A = 4[tex]\pi[/tex]
Since the question told us to replace [tex]\pi[/tex] with 3, we can do that.
--> A = 4 x 3
--> A = 12
We can conclude that the area of the circle is 12 in^2.
Find all x-values in the interval for which the function is equal to its average value. (enter your answers as a comma-separated list. )
All the x-values in the interval for which the function is equal to its average value [tex]5-\sqrt{5}[/tex] .
An interval program language period accommodates the numbers mendacity between specific given numbers. for instance, the set of numbers x gratifying 0 ≤ x ≤ five is a c programming language that contains zero, five, and all numbers among 0 and five.
The interval program language period is the distinction between the higher class restriction and the lower magnificence restriction. As an example, the dimensions of the class c program language period for the first class is 30 – 21 = 9. further, the size of the class c programming language for the second magnificence is forty – 31 = nine.
In arithmetic, an interval language is fixed of actual numbers that carry all actual numbers mendacity among any numbers of the set. For example, the set of numbers x pleasurable zero ≤ x ≤ 1 is a language that includes zero, 1, and all numbers in between.
f(x)=(91-55 [0,1]
value of the function on the interval [0,1] is (9-0)
Let x-5=3
now, find the value of x, for which
f(x) =(2x-5) 2 =
5/X-5 =√5
24 X = 54√5 and 5. √5
Strs [ay] and 5- 5-√5 €0.4]
value of x is 5- sqrt15
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Assume the four intersecting lines are parallel. In this figure, A = 36, B = 24, and C = 60 . If D = 33,
what are the measurements of E and F?
Using the proportionality theorem, the measurements are: c. E = 22 and F = 55.
What is the Proportionality Theorem?If two transversals intersect three or more parallel lines, they divide the lines in such a way that the smaller segments are proportional to each other or have ratios that are equal to each other.
Given the following:
A = 36,
B = 24,
C = 60
D = 33.
Since all lines are parallel, then:
A/D = B/E = C/F
Find the measure of E using the ratio, A/D = B/E:
36/33 = 24/E
Cross multiply
E = (24 × 33)/36
E = 22
Find the measure of F using the ratio, A/D = C/F:
36/33 = 60/F
Cross multiply
F = (60 × 33)/36
F = 55
The answer is: c. E = 22 and F = 55.
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a. How many feet is [tex]\frac{1}{5}[/tex] of a mile? ______
b. How many feet is [tex]\frac{1}{100}[/tex] of a mile? ______
Answer:
a. 1056 ft
b. 52.8 ft
Step-by-step explanation:
1 mile = 5280 feet
a.
[tex]\frac{1}{5} *5280 = 1056[/tex]
Therefore 1/5 of a mile is 1056 feet.
b.
[tex]\frac{1}{100} *5280=52.8[/tex]
Therefore 1/100 of a mile is 52.8 feet
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
4
Step-by-step explanation:
The part of the function that is (2x - 1)² has a minimum value of 0. The reason is that any real number you for x will give you a positive, negative, or zero value for 2x - 1. When you square it, you must get a non-negative answer.
Then you add 4, and you get a value that is greater than or equal 4.