Answer:
4 m/s
Explanation:
Conservation of momentum , mv
Before collision 80 kg * 6 m/s = 480 kg-m/s
after the collision,
the momentum is the same but the mass is 80+40 kg =120 kg
mv = 480
120 * v = 480
v = 4 m/s
1. What type of waves can only travel through a medium?
Answer:
A mechanical wave can only travel through a medium.
progress of science has not caused any ill effect true or false?
A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of the wire from A to C is 250cm. How large an average friction force opposed the motion of the bead?
Answer:
.12 N
Explanation:
Velocity goes from 2 m/s to 0 m/s so average velocity = 1 m/s
.250 m / 1 m/s = .25 second to stop
change in velocity / change in time = accel
2 m/s / .25 sec = 8 m/s^2
F = ma
= .015 kg * 8 m/s^2 = .12 N
is a pot plant a closed system?
Answer:
No because a pot plant system must interact with its surroundings (air, water, etc) and these are not closed systems.
Only if the pot plant were completely enclosed, say in a large glass jar would the system be closed.
is power and voltage the same thing yes or no
What climate zone are you in temperatures are always very warm Where is this zone located on Earth
Answer:
Warm weather may be found in the tropical zone since the sun's heat is concentrated in regions close to the equator. At 23.5 degrees north of the equator and 23.5 degrees south of the equator, this area is nearly in the middle of the world. It has a monthly average temperature of 18 degrees Celsius or higher.
Explanation:
Is it possible for an object to be in equilibrium (no net force), if only one force is acting on it ?
Glucose solution is administered to a patient in a hospital. The density of the solution is 1.308 kg/l. If the blood pressure in the vein is 35.7 mmHg, then what is the minimum necessary height of the IV bag above the position of the needle?
The minimum necessary height of the IV bag above the position of the needle is 0.37 m.
Minimum necessary heightThe minimum necessary height of the IV bag above the position of the needle is calculated as follows;
P = ρgh
where;
ρ is density = 1.308 kg/L = 1308 kg/m³g is acceleration due to gravity = 9.8 m/s²p is pressure = 35.7 mmHg = 4759.609 Pah is height, (m) = ?Substitute the given parameters and solve for minimum height
h = P/ρg
h = (4759.609) / (9.8 x 1308)
h = 0.37 m
Thus, the minimum necessary height of the IV bag above the position of the needle is 0.37 m.
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Particles that are __________ can transfer heat energy as they vibrate.
A. The same size
B. The same color
C. Very close together
D. Very far apart
A car with a mass of 1000 kg accelerates from 0 to 90 km/h in 10 seconds. a) What is its acceleration? b) What is the net force on the car?
Answer:
v
f=90km/h=25m/s
v_{_{i}}=0v
i=0
t=10\;\mathrm{s}t=10s
m=1000\;\mathrm{kg}m=1000kg
The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are 2.5 m/s², 2500 Newtons (N).
Given:
Mass of the car (m) = 1000 kg
Acceleration (a) = 2.5 m/s²
a) The acceleration of the car is:
Acceleration (a) = Change in velocity / Time taken
Final velocity (v(f)) = 90 × 0.27778 = 25 m/s
Acceleration (a) = (Final velocity - Initial velocity) / Time taken
Acceleration (a) = (25 - 0 ) / 10
Acceleration (a) = 2.5 m/s²
Therefore, The acceleration of the car is 2.5 m/s².
b) Newton's second law of motion:
F = m × a
F = 1000 × 2.5
F = 2500 N
The net force acting on the car is 2500 Newtons (N).
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a ball bearing x is dropped vertically downwards,from the edge of a table and it takes 0.5seconds to hit the floor. Another bearing y leaves from the edge of the table horizontally with a velocity of 5m/s . Find:.
a)the time taken for bearing y to reach the table?
b)the horizontal distance traveled by y before hitting the floor
c)the height of the table top above the floor level
Answer:
See below
Explanation:
A) bearing y reaches the FLOOR in the same amount of time .5 seconds since there is no initial vertical velocity component
B. in .5 seconds y will travel 5 m/s * .5 s = 2.5 meters horizontally
C. d = 1/2 a t^2
= 1/2 (9.81)(.5^2) = 1.23 m table height
(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c) The height of the table top above the floor level is 1.225 meters.
a) Time is taken for bearing y to reach the table:
For a horizontal motion, the equation to calculate time is:
Time (t) = Distance (d) ÷ Velocity (v)
Time (t) = Width of the table / Velocity of y
t = 1 / 5
t = 0.2 sec
So, bearing y takes 0.2 seconds to reach the table.
b) Horizontal distance traveled by bearing y before hitting the floor:
Distance (d) = Velocity (v) × Time (t)
d = 5 × 0.2
d = 1 m
So, Bearing y travels 1 meter horizontally before hitting the floor.
c) The height of the table top above the floor level:
h = (1/2) × g × t²
h = (1/2) × 9.8 × (0.5)²
h = (1/2) × 9.8 × 0.25
h = 1.225 m
So, the height of the table top above the floor level is 1.225 meters.
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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?
The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
Time of motion of the girl
The time of motion of the girl is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0t is time of motiong is acceleration due to gravitySubstitute the given parameters and solve for time of motion;
50.8 = 0 + ¹/₂(9.8)t²
2(50.8) = 9.8t²
101.6 = 9.8t²
t² = 101.6/9.8
t² = 10.367
t = √10.367
t = 3.22 seconds
Final vertical velocity of the skydivervf = vi + gt
where;
vi is the initial vertical velocity = 0
vf = 0 + 9.8(3.22)
vf = 31.56 m/s
Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
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When a 6kg block is placed on a vertical spring, the spring is compressed by 20cm. How much work is required to compress the spring by an additional 10CM
Answer:
Mass of block = 6kg
wright = 6 × g = 60 N using g = 10 m/s^2 .
compression= 0.20m
spring constant =( weight / compression) =( 60/0.20) = 300 N/m .
Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.
Additional compression = 0.10 m
total compression = 0.20+ 0.10= 0.30 m.
Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.
Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.
Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .
Circle the anomalous result in the table below. An anomaly is a piece of data that doesn't
fit in with the rest of the data.
1. Concentration of
sucrose (M)
0.25
0.5
1
1.5
2
2. Change in mass of piece of potato (g)
Group B's
Group A's
measurements
0.02
0.05
0.12
0.17
0.21
3. measurements
0.03
0.05
2.3
0.14
0.2
Average?
Pls help I need to get this done really soon otherwise I will get a detention for two hours after school with my least fave teacher plss it’s for a test!!!!!!
Answer:
Explanation:
yes
I = 30A and R = 30; what is V?
A. 900v
B.90v
C.10v
D.0.1v
Answer:
[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].
Explanation:
By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].
Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].
Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:
[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].
what is barometer ???
Answer:
an instrument measuring atmospheric pressure, used especially in forecasting the weather and determining altitude.
Explanation:
hope it helps ya
4 Four objects are stiuated along the y axis as follow: a 20 kg object is at +3 m, a 3 kg object is at +2.5 m, a 2.5 kg object is at origin, and a 4 kg object is at -5 m. What is the center of mass of these objects?
Answer: 1.348 meters
Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point c . Adding the four moments together, we get:
(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0
6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0
11.5c=15.50
c= 1.348 metres
The center of mass is on the y axis at y = 1.348 metres.
An object is thrown upward with initial velocity of 30m/s at angle of 30 degree to the horizontal. calculate the components of the initial velocity.
Answer:
Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s
Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s
A certain force F has an c component of 46N and a y component of 80N. Find the magnitude of this force. A- 73.8N B- 103.8N C 92.3N D-67.6N E-none
Answer:
X component= 46 N
Y component= 80 N
Magnitude =( 46 ^2 + 80^2 )^0.5 = 92.3 N
A triangular plate with a non-uniform areal density has a mass M=0.500 kg. It is suspended by a pivot at P and can oscillate as indicated below. Its center of mass is a distance d=0.300 m from the pivot axis and its moment of inertia about an axis through the CM and parallel to the pivot axis is ICM=9.00×10-3 kg m2.
The plate is released from an angle θ=15°. Calculate the period of the oscillations.
The period of the oscillations.T = 1.2042s
Opposition is the process of any quantity or measure fluctuating repeatedly about its equilibrium value throughout time. This process is referred to as oscillation. Oscillation, a periodic fluctuation of a substance, can also be described as alternating between two values or rotating around a central value.
Typically, the mathematical formula for the moment of inertia is
T = 2 π √(I / mgd)
Therefore, a moment of inertia
I = 9.00×10-3 + md^2 ;
I=9.00*10^{-3}+ 0.5 * 0.3^2
I=0.054
T=2[tex]\pi \sqrt{0.5*9.8*0.3}[/tex]
T=1.2042s
The period of the oscillations.T = 1.2042s
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A simple pendulum suspended in a rocket ship has a period [tex]T_{0}[/tex]. Assume that the rocket ship is near the earth in a uniform gravitational field.
True or false:
1. If the ship moves upward with a constant velocity, the period increases.
2. If the length of the pendulum is doubled, the new period will be: square root of 2 times [tex]T_{0}[/tex].
3. If the ship accelerates upward, the period increases.
4. If the ship accelerates downward at 9.81 [tex]m/s^{2}[/tex], the pendulum will no longer oscillate.
5. If the mass of the pendulum is halved, the period decreases.
(1) If the ship moves upward with a constant velocity, the period increases, false.
(2) If the length of the pendulum is doubled, the new period will be: square root of 2 times T₀. true.
(3) If the ship accelerates upward, the period increases, true.
(4) If the ship accelerates downward at 9.81 m/s² , the pendulum will no longer oscillate, false.
(5) If the mass of the pendulum is halved, the period decreases, false.
Period of a simple pendulum
The period of a simple pendulum is given as;
T = 2π√(L/g) ------- (1)
where;
L is length of the pendulumg is acceleration due to gravityWhen the ship moves upward with a constant velocity, the period will not change.
When the length of the pendulum is doubledT ∝√L
when, L = 2L₀
T = T₀√2
Thus, if the length of the pendulum is doubled, the new period will be: square root of 2 times T₀.
when ship accelerates upwardt = √2h/g
when the height increases, time or period increaseswhen mass of the pendulum is halvedT = √I/mgd
where;
m is mass of the pendulumwhen the mass is halved, the period increases.
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Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back down to its initial temperature. If the circuit element can withstand a temperature change of 5.1 ∘C without being damaged, what is the maximum rate at which energy can be added to the circuit element?
The maximum rate at which energy can be added to the circuit element mathematically given as
[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]
What is the maximum rate at which energy can be added to the circuit element?Generally, the equation for P is mathematically given as
[tex]P=\ln s \frac{\Delta T}{\Delta t}[/tex]
Therefore
[tex]Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}[/tex]
[tex]\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}[/tex]
[tex]\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}[/tex]
Max temp Change
[tex]MaxT=5.6^{\circ} \mathrm{C}[/tex]
[tex]\text { time }=3 \times 60[/tex]
t=180s
In conclusion, Max Energy Rate
[tex]MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}[/tex]
[tex]MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}[/tex]
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The mass of a coin is measured to be 12.5±0.1 g. The diameter is 2.8±0.1 cm and the thickness 2.1 ±0.1 mm. Calculate the average density of the material from which the coin is made with its uncertainty. Give your answer in kg m-³.
with proper explanation
answer only if u know or else u know the consequences
The average density of the material from which the coin is made is 9.67 g/cm³.
Volume of the coinThe volume of the coin at the given diameter is calculated as follows;
V = Ah
where;
A is area of the coinh is the thickness of the coinV = πd²/4 x h
V = π(2.8)²/4 x (0.21 cm)
V = 1.293 cm³
average density of the coinThe average density of the material from which the coin is made is calculated as follows;
density = mass/volume
density = 12.5 g / (1.293 cm³)
density = 9.67 g/cm³
Thus, the average density of the material from which the coin is made is 9.67 g/cm³.
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Many astronomers have spent their entire career attempting to definitively answer the question "Are we alone?". To date, we have found no other life forms. Discuss the type of efforts made to date to answer this question and the results of those efforts. Within our solar system, what are the best candidates for harboring life? Aside from the scientific evidence, what are your views regarding life beyond Earth and the basis for why you feel that way?
Answer:
Astrobiologists have put in tremendous efforts till now in the search for extra-terrestrial life. They are searching not only for tremendously developed life forms like humans, but also for microbes that are found to inhabit even the harshest of environments on Earth. Due to the tremendous development in technology, the odds of finding life beyond Earth are increasing day by day. Nasa's Kepler mission was launched to hunt for Earth like planets beyond our Solar System, and till now this mission has established the presence of 2,337 exoplanets, along with 1,284 new planets. This hugely increases the chances of finding another Earth like planet outside the limits of our Solar system. NASA's Astrobiology researchers are presently studying the most severe environments on Earth for improved understanding of the kind of conditions that would be able to support life in every part of the universe. Moreover, programs for instance SETI are keeping an eye on the galaxy for electromagnetic communications occurring or situated between stars from the societies on new worlds.
There is still a tremendous possibility to find life in our solar system. By the discovery of life forms in the extreme environments here on Earth, scientists have realized that the presence of solar energy is not an absolute necessity for the subsistence of life. Energy from chemical reactions can also trigger the organic elements to interact and start the formation of life. In the Solar system, Jupiter's moons Io and Europa and Saturn's moons Enceladus and Titan have been realized to the very strong candidates for the presence of microscopic life forms.
Explanation:
I hold a very optimistic view on the presence of life beyond Earth. It is highly probable that life on Earth is not an exceptional case but it should be a general one in the Universe. While we are always excited to imagine that we might encounter species as much developed or more highly developed than us, there is very good chance that the Universe is teeming with microscopic life forms. Also, to discover another intelligent life form would also be highly welcome.
How does the suns energy affect the climate of an area
Answer:
the earth receives the suns energy as radiation which is able to travel without the need of matter from point A to point B and this radiation is also in the form of heat.
Explanation:
Sun's energy fall on the earth in form of radiation and heats up the atmosphere and produces unequal heating due to its spherical nature and impacts climate of different areas.
The Sun is the only source of energy for the Earth's climate system. Fundamental to atmospheric composition is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.
When the sun is at its maximum (peak in sunspots, prominences, and flares), it produces more ultraviolet (UV) radiation. More ozone is produced as a result of UV light, warming the stratosphere. The lower atmosphere and Earth's surface warm slightly as a result of the increased solar radiation.
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a ball rolls off a platform that is 12 m above ground. The ball's horizontal velocity as it leaves the platform is 5 m/s. How much time it takes for the ball to hit the ground
The time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.
Time of motion of the ball
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0t is time of motionh is height of fall of the ballh = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h/g)
t = √(2 x 12 / 9.8)
t = 1.56 seconds
Thus, the time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.
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Explain the mechanism by which an open fracture could result in shock.
Answer:
an open fracture contains some sort of water which if it comes in contact with electrons could result to a shock
Why does Usain bolt run?
Answer:
because he's fast and speedy
Explanation:
i. Which of the following formula gives definition of relative density? d d B. A. C. d water at 4°C d d mercury at 4°C D. d water at 40°C d d alcohol at 4°C
Answer:
water at 4°c that's abnormal stage of water
A 5 Ω and a 5 Ω resistor are in parallel. What is their total resistance?
A. 10 Ω
B. 2.5 Ω
C. 25 Ω
D. 5 Ω
Answer:
B. 2.5 Ω
Explanation:
[tex]\frac{1}{5} +\frac{1}{5}=0.4[/tex]
Put a one on top of the 0.4
[tex]\frac{1}{0.4} =2.5[/tex]