Answer:
56.18 grams because you have to round it off
A student takes notes in class.
Sound Waves
I. Created by a vibration
A. Vibration: something that causes air molecules to move
back and forth quickly and steadily
II. Move through a medium
A. Solid
B. Liquid
C. Gas
Which line of her notes contains an error?
I
I A
II B
II C
The wrong statement is that sound waves created vibration Option A.
What are sound waves?Sound is a type of waves that moves in compressions and rare factions. This implies that sound is a mechanical wave. Recall that a mechanical wave is one that requires a material medium for propagation. Now we know that if we set the medium into vibration, that is when the sound waves begins to vibrate. That brings us to the idea that it is the vibration that causes the sound waves and not the sound waves that creates the vibration.
Thus, knowing that sound is a mechanical wave which moves through solids liquids and gas and that the vibration of the source of sound is what causes the air to vibrate, we conclude that the wrong statement is that sound waves created vibration Option A.
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Answer:
a
Explanation:
A sample of an ideal gas is heated, and its kelvin temperature doubles. What happens to the average speed of the molecules in the sample?
A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of [tex]\sqrt{2}[/tex]
The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.
Root mean square speed is a statistical measurement of speed.
The root mean square speed can be calculated as : V1 : [tex]\sqrt{3 R T / Mo}[/tex]
if temperature becomes double
let T1 is initial temperature
So , T2 = 2 * T1
now ,
Root mean square speed will be (V2) = [tex]\sqrt{(3 R (2T)) / Mo}[/tex]
= [tex]\sqrt{2}[/tex] * [tex]\sqrt{3 R T / Mo}[/tex]
= [tex]\sqrt{2}[/tex] V1
Thus when temperature becomes double, the root mean square speed increases by a factor of [tex]\sqrt{2}[/tex]
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A bus travelling at 30m/s along a straight road passes throu a stationary taxi cab.the can begins to move 5seconds later within a uniform acceleration of 2metres per seconds square in the same direction as the bus.1.calculate the time taken by the cab to meet the bus.2.distance the cab has travelled to catch-up with the bus
(1) The time taken by the cab to meet the bus is 18.96 seconds.
(2) The distance the cab has travelled to catch-up with the bus is 718.96 m.
Distance between the bus and the cab
The distance between the bus and the cab when the cab begins to move is calculated as follows;
D = speed x time
D = 30 m/s x 5 s
D = 150 m
Velocity of the cabThe velocity of the cab when it begins to move is calculated as follows;
v = at
(v - 30)t = D
(at - 30)t = 150
(2t - 30)t = 150
2t² - 30t = 150
2t² - 30t - 150 = 0
solve the quadratic equation using formula method
t = 18.96 seconds
Distance traveled by the cabD = vt
D = 2t²
D = 2(18.96²)
D = 718.96 m
Thus, the time taken by the cab to meet the bus is 18.96 seconds. The distance the cab has travelled to catch-up with the bus is 718.96 m.
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A cosmic-ray electron moves at perpendicular to earth’s magnetic field at an altitude where the field strength is. what is the radius of the circular path the electron follows?
4.266 m is the radius of the circular path the electron follows.
Given
Speed of electron (v) = 7.5 × 10⁶ m/s
Earth's Magnetic Field (B) = 1 × 10⁻⁵ T
We already know that
Mass of electron (m) = 9.1 × 10⁻³¹ kg
Charge on electron (q) = 1.6 × 10⁻¹⁹ C
According to the formula
Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field
Radius of circular path(r) = m × v/q × B
Put the values into the formula
r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵
On solving, we get
r = 4.266 m
Hence, 4.266 m is the radius of the circular path the electron follows.
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Two objects have the same velocity. These two objects have different masses. Which object will
have greater momentum? Why?
Answer:
The object with the greater mass will have the greater momentum
Explanation:
The momentum of an object with mass m, moving with velocity , is given by the formula
M = mv
Since both objects have the same velocity v, it is clear that the object with the bigger mass will have the greater momentum
A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. how fast is the car going at the finish line?
A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. At the finish line, the speed of the car is [tex]\mathbf{89}.\mathbf{6660}\ \mathbit{m}/\mathbit{s}[/tex].
The initial velocity of the car [tex]u = 0[/tex]
Constant acceleration [tex]a = 10~ m/s^2[/tex]
Distance of the Race [tex]d = 402~ m[/tex]
The car is accelerating with a constant acceleration [tex]a[/tex] , so the car's velocity will change with time as it approaches the finish point which is at a distance [tex]d[/tex] from the initial point.
Newton's equation is the backbone of Classical Mechanics. Let's say the velocity of the car at the finish line is [tex]v[/tex]. We know that displacement is the product of average velocity and time.
Or [tex]s=\frac{u+v}{2}\times t[/tex]
Using Newton’s first equation [tex]v\ =\ u\ +\ at[/tex]
Newton's equation of motion turns out to be,
[tex]v^2 = u^2+2ad[/tex]
[tex]v^2 = 2\times 10 \times 402[/tex]
so, [tex]v = \sqrt{8040} = 89.6667 ~m/s[/tex]
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Which two fundamental forces act within an atom’s nucleus? the gravitational force the electromagnetic force the strong nuclear force the weak nuclear force the electric force
The two fundamental forces act within an atom’s nucleus include the strong nuclear force and the weak nuclear force.
What are the fundamental forces of atoms nucleus?.The fundamental forces of atoms nucleus are the forces that act within the nucleus of an atom which include the following:
The strong nuclear forces: These are the forces that enhances the binding of the nucleus together.The weak nuclear forces:. These are the forces that are responsible for nuclear decay.Therefore, the two fundamental forces act within an atom’s nucleus include the strong nuclear force and the weak nuclear force.
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What is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1400 m/s?
The frequency of a photon is 1.06 * [tex]10^{18}[/tex] Hz.
The mass of a neutron is:
m = 1.67 * [tex]10^{-27}[/tex] kg
Since we know its speed, we can calculate the neutron's momentum:
p = mv = (1.67 * [tex]10^{-27}[/tex] kg)(1400 m/s) = 2.34 * [tex]10^{-24}[/tex] kg m /s
The problem says the photon has the same momentum of the neutron, p. The photon momentum is given by
p = h / λ
where h is the Planck constant, and λ is the photon wavelength. If we re-arrange the equation and we use the momentum we found before, we can calculate the photon's wavelength:
p = h / λ = [6.6 * [tex]10^{-34}[/tex] J/s] / [2.34 * [tex]10^{-24}[/tex] kg m /s ]
= 2.82 * [tex]10^{-10}[/tex] m
And since we know the photon travels at speed of light c, we can now calculate the photon frequency:
f = c / λ = [3 * [tex]10^{8}[/tex] m/s] / [ 2.82 * [tex]10^{-10}[/tex] m ]
= 1.06 * [tex]10^{18}[/tex] Hz.
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In a transformer, energy is carried from the primary coil to the secondary coil by:________
In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
To find the answer, we have to know more about the transformer.
How transformer works?An item utilized in the transfer of electric energy is a transformer. AC current is used for transmission. It is frequently used to modify the supply voltage between circuits without altering the AC frequency.The fundamentals of mutual and electromagnetic induction govern how the transformer operates. Magnetic field through the primary coil changes when primary coil current varies. the iron core of the secondary coil likewise has a magnetic field. EMF is therefore generated in the secondary coil.Thus, we can conclude that, in a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
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As additional resistors are connected in parallel to a constant voltage source, how is the power supplied by the source affected?.
As additional resistors are included lined up across a consistent voltage source, there are more ways for current to take.
So more current spills out of the source, and the all out current provided by the source increments.
The power supplied by the battery is (voltage) x (current). So if the voltage is constant and the current increases, the power being supplied must also increase.
What is a resistor?A resistor is an electrical part that cutoff points or manages the progression of electrical flow in an electronic circuit. Resistors can likewise be utilized to give a particular voltage to a functioning gadget like a semiconductor.
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Recall the word ""speed"". what is speed? what equation(s) do we have for calculating speed? how can we measure the speed of a moving object?
Answer:
Speed = distance traveled / time
Speed is a "scalar" quantity
Velocity = Vector Distance Traveled / time
Velocity is a vector quantity.
Example:
One can travel one lap around a track at some particular speed and his average speed will be (lap distance / time)
However, his vector velocity would be zero because he ended up where he started with zero displacement.
What term appears in total energy equation of a flowing fluid, that does no appear in the total energy equation for a non-flowing fluid?
The Kinetic energy per unit volume appears in total energy equation of a flowing fluid, that does not appear in the total energy equation for a non-flowing fluid.
Kinetic Energy per unit volume is defined as the Kinetic energy of the flowing fluid per unit volume.
Bernoulli Equation is a equation that remains constant for a given fluid which comprises of Potential energy per volume, Kinetic energy per volume and Pressure.
It is given by:
P + ρgh + ρv²/2 = constant
where, P is the Pressure
ρ is the density of fluid
g is acceleration due to gravity
h is the height
v is the velocity
∴ ρgh is called as Potential energy per volume
∴ ρv²/2 is called as Kinetic energy per volume
In a Flowing Fluid:
P is presentPotential energy per volume is presentKinetic energy per volume is present since velocity is presentIn a Non-Flowing Fluid:
P is presentPotential energy per volume is presentKinetic energy per volume is absent since velocity is absentHence, Kinetic Energy per unit volume does not appear in the total energy equation for a non-flowing fluid but appears in total energy equation for a flowing fluid.
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When marking the fixed points on a thermometer, it is observed that at 0oC,
the mercury thread is of length 1cm and 6cm at 100oC. What temperature would
correspond to a length of 4cm?
The temperature corresponds to a length of 4cm is 80°C.
To find the answer, we need to know about the thermometers.
How to find the temperature corresponds to 4cm?An instrument for measuring and indicating temperature, typically one that consists of a short, hermetically sealed glass tube with graduation markings and a mercury or alcohol-filled bulb at one end that expands along the tube as it measures temperature is called Thermometer.Given that the temperature coincides with the 1cm line is 0 degree Celsius, and that of 6cm is 100 degrees Celsius.Thus, the separation between these two temperatures will be,[tex]d=6cm-1cm=5cm[/tex]
This separation is 5cm, for 100-unit difference of temperature.Thus,[tex]1cm=\frac{100}{5}=20^0C[/tex]
Thus, 4cm corresponds to a temperature,[tex]T=4*20=80^0C[/tex]
Thus, we can conclude that the 4cm line corresponds to a temperature of 80°C.
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A particle (m = 3. 5 × 10-28 kg) starting from rest, experiences an acceleration of 2. 4 × 107 m/s2 for 5. 0 s. what is its de broglie wavelength λ at the end of this period?
The de Broglie wavelength of the particle is 1.578*10^-3nm.
To find the answer, we have to know about the de Broglie wavelength.
How to find the de Broglie wavelength?We have the expression for de Broglie wavelength as,[tex]wavelength=\frac{h}{P} =\frac{h}{mv}[/tex]
where, h is the plank's constant, m is the mass and v is the velocity.
It is given that,[tex]m=3.5*10^{-28}kg\\a=2.4*10^7m/s^2\\t=5s\\h=6.63*10^{-34}Js[/tex]
Substituting the values, we get,[tex]wavelength=\frac{6.63*10^{-34}}{3.5*10^{-28}*2.4*10^7*5}=1.578*10^{-14}m\\\\ wavelength=1.578*10^{-3}nm.[/tex]
Thus, we can conclude that, the de Broglie wavelength of the particle is 1.578*10^-3nm.
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The first time that astronomers observed both gravitational waves and electromagnetic waves from the same event, what they were observing was:_____
Higher frequencies are present in more dramatic events and have thus been the first to be noticed, but the frequencies of ordinary gravitational waves are relatively low and considerably more difficult to detect.
A gamma-ray burst (GRB), which was discovered by the orbiting Fermi gamma-ray burst monitor on 2017 August 17 at 12:41:06 UTC, triggered an automatic notice throughout the world in addition to a merger of black holes. Six minutes later, a gravitational-wave observatory in Hanford, Washington, detected a gravitational-wave candidate that occurred 2 seconds before the gamma-ray explosion.
This collection of data supports the merger of two neutron stars, as shown by a multi-messenger transient event that was detected by gravitational waves as well as electromagnetic (gamma-ray burst, optical, and infrared) spectrum observations.
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A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the?
A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the Haldane effect
The less saturated hemoglobin is and the lower the partial pressure of oxygen in the blood is, the more readily hemoglobin binds to carbon dioxide. This is an example of the Haldane effect.
The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.
The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.
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Mass m moves to the right with speed =v along a frictionless horizontal surface and crashes into an equal mass m initially at rest. upon colliding, the two masses stick together and move with speed v to the right. notice that v and v denote different speeds. after the collision the magnitude of the momentum of the system is:
After the collision the magnitude of the momentum of the system is Mv
Given:
mass of 1st object = M
speed of 1st object = v
mass of 2nd object = M
speed of 2nd object = 0
To Find:
magnitude of the momentum after collision
Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.
Applying conservation of linear momentum
Mv + M(0) = 2MV
Mv = 2MV
V = v/2
So, after collision momentum is
p = 2MV = 2xMxv/2 = Mv
So, after collision momentum is Mv
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Summarize the current state of knowledge about extrasolar planet masses and sizes. Based on the evidence, is it likely that smaller planets or larger planets are more common?
Extrasolar planet mass can be ten times as that of earth and it's size can be twice as that of earth.
GJ 504b is the planet having lowest mass detected around sun.
HAT-O-67b is the planet having the highest mass with diameter twice as that of Jupiter.
Results show that there are more small planets than the large ones which indicates that small planets are dominant in the galaxy.
Earth-sized planets are common in the galaxy.
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How many joules of energy will a stock tank heater rated at 1500 watts use in a 24 hour period?
A stock tank heater rated at 1500 watts will use 1,29,600 kJ of energy in a 24 hour period.
Given :
Power = 1500 WTime = 24 hours = 24 x 3600 sec = 86,400 secWe know that
Energy = Power x time
E = P * t
E = 1500 x 24 x 3600
E = 129600000 J ( or 129600 kJ)
Hence, a stock tank heater rated at 1500 watts will use 1,29,600 kJ of energy in a 24 hour period.
The formula that links energy and power is:
Energy = Power x Time.
The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.
If we know the power in watts of an appliance and how many seconds it is used we can calculate the number of joules of electrical energy which have been converted to sortie other form.
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Each of the gears a and b has a mass of 675 g and has a radius of gyration of 40 mm, while gear c has a mass of 3. 6 kg and a radius of gyration of 100 mm. Assume that kinetic friction in the bearings of gears a, b, and c produces couples of constant magnitude 0. 15 n·m, 0. 15 n·m, and 0. 3 n·m, respectively. Knowing that the initial angular velocity of gear c is 2000 rpm, determine the time required for the system to come to rest.
9.87 seconds
The time required for this system to come to rest is equal to 9.87 seconds.
We have the following data:
Mass of gear A = 675 g to kg = 0.675 kg.
Radius of gear A = 40 mm to m = 0.04 m.
Mass of gear C = 3.6 kg.
Radius of gear C = 100 mm to m = 0.1 m.
How can I calculate the time needed?
We would need to figure out the moment of inertia for gears A and C in order to compute the time needed for this system to come to rest.
Mathematically, the following formula can be used to determine the moment of inertia for a gear:
I = mr²
Where:
m is the mass.
r is the radius.
We have, For gear A:
I = mr²
I = 0.675 × 0.04²
I = 0.675 × 0.0016
I = 1.08 × 10⁻³ kg·m².
We have, For gear C:
I = mr²
I = 3.6 × 0.1²
I = 3.6 × 0.01
I = 0.036 kg·m².
The initial angular velocity of gear C would therefore be converted as follows from rotations per minute (rpm) to radians per second (rad/s):
ωc₁ = 2000 × 2π/60
ωc₁ = 4000π/60
ωc₁ = 209.44 rad/s.
Also, the initial angular velocity of gears A and B is given by:
ωA₁ = ωB₁ = rc/rA × (ωc₁)
ωA₁ = ωB₁ = 0.15/0.06 × (209.44)
ωA₁ = ωB₁ = 2.5 × (209.44)
ωA₁ = ωB₁ = 523.60 rad/s.
Taking the moment about A, we have:
I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0
On Substituting the given parameters into the formula, we have;
(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0
0.15t - 0.06∫F_{AC}dt = 0.56549 ----->equation 1.
Similarly, the moment about B is given by:
0.15t - 0.06∫F_{BC}dt = 0.56549 ------>equation 2.
Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt
Adding eqn. 1 & eqn. 2, we have:
0.3t - 0.06x = (0.56549) × 2
0.3t - 0.06x = 1.13098 ------>equation 3.
Taking the moment about A, we have:
Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0
0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0
0.3t + 0.15x = 7.5398 ------->equation 4.
Solving eqn. 3 and eqn. 4 simultaneously, we have:
x = 30.5 Ns.
Time, t = 9.87 seconds.
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Calculate the value of ∆g for these initial partial pressures. (the partial pressure of each gas is set a 5. 0 atm at 25°c) (use ∆g = rt ln (q/k), use the k at 25°c)
∆g for these initial partial pressures is 10,403.31 KJ.
ΔG gets increasingly positive as a product gas's partial pressure is raised. ΔG becomes more negative as the partial pressure of a reactant gas increases.
∆g = RT ln (q/k)
In this equation: R = 8.314 J mol⁻¹ K⁻¹ or 0.008314 kJ mol⁻¹ K⁻¹
K = 325
If ΔG < 0, then K > Q, and the reaction must proceed to the right to reach equilibrium.
∴∆g = RT ln (q/k)
= 8.314 × 298 ln ( 5 / 325)
= 2477.57 ln 0.015
= 2477.57 × (-4.199)
= 10,403.31 KJ
Products are preferred over reactants at equilibrium if G° 0 and both the products and reactants are in their standard states. When reactants are preferred above products in equilibrium, however, if G° > 0, K 1. At equilibrium, neither reactants nor products are preferred if G° = 0, hence K = 1.
Therefore, ∆g for these initial partial pressures is 10,403.31 KJ.
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What is the unit of the quotient of inductance and resistance?
The unit of the quotient of inductance and resistance will be Henry and ohm
Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.
Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.
unit of quotient of inductance = henry (H)
unit of resistance = ohm
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Suppose a consumption function is given as c = $500 0.75yd. the marginal propensity to consume is:______
In the the case above, if the consumption function is: C = $500 + 0.75 × YD, from the equation, the The marginal propensity to consume is option C) 0.75.
What is MPC?The marginal propensity to consume which is MPC is the aspect of each extra money that is dollar of a household's income that is said to be used, consumed or spent.
Note that Consumer behavior in regards to saving or spending has a very vital impact on the economy of a country.
From the formula given, the breakdown is:
YD = disposable income.
Autonomous consumption = $500.
The marginal propensity to consume = 0.75.
Therefore, In the the case above, if the consumption function is: C = $500 + 0.75 × YD, from the equation, the The marginal propensity to consume is option C) 0.75.
See full question below
Suppose that the consumption function is: C = $500 + 0.75 × YD
(Scenario: Consumption Spending) The marginal propensity to consume is:
A) $500.
B) 0.
C) 0.75
D) 0.2.
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Zinc metal (Zn) and sulfur powder (s) undergo a chemical reaction to form zinc sulfide (ZnS) which equation represents this chemical reaction? S → ZnS + Zn ZnS → Zn + S Zn + S → ZnS Zn → ZnS + S
Zinc metal (Zn) reacts with sulfur (S) to create zinc sulfide (ZnS), and the chemical reaction is: Zn (s) + S (s) = ZnS (s).
Importance of Zinc (Zn) and sulfur (S):
Zinc(Zn) is a vital element that our systems need to absorb food and nutrients as well as create healthy skin and bones. Zinc(Zn) ions play a crucial role in a number of the body's enzymes. Sulfur(S) is a pale yellow, tasteless, brittle solid that is also necessary for life. It is found in many proteins as well as the amino acids cysteine and methionine. It is a trace element found in bone minerals, bodily fluids, and lipids.Chemical reaction -
In this experiment, heating a zinc(Zn) and sulfur(S) combination causes an interesting chemical reaction. A blinding flash of light, hot sparks, a hissing sound, and a cloud of white smoke in the shape of a mushroom are produced.
Therefore, the following chemical processes are taking place in the reaction: Zn (s) + S (s) = ZnS (s).
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The air pressure normally ____ before a cold front passes and ____ after a cold front passes.
The air pressure normally drops before a cold front passes and rises after a cold front passes.
What is cold front?When a warm, lighter air mass pushes under a cold, dense air mass, the warm air is forced to rise, forming a cold front. The warm air at the surface is replaced by the cold air as it moves forward. As the moisture in the warm air mass rises, cools, and condenses, rain and even thunderstorms might develop. The winds will often change direction during a cold frontal passage from the south to the west or north. It is probable that cold, fair weather will continue when the front passes.
The sort of air mass going in affects the temperature behind a cold front. During the winter, a polar air mass will bring in frigid air, and during other seasons, cool air. Bitter air from the Arctic will be present.
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14. The cutaway diagram below shows the paths
of earthquake waves generated at point X.
P- and
S-waves
reach
seismograph
No waves
Crust
Mantle
Core
P-waves only
-
Focus
Only P-waves reach the side of Earth that
is opposite the focus because P-waves
(1) are stronger than S-waves
(2) travel faster than S-waves
(3) bend more than S-waves
(4) can travel through liquids
and S-waves cannot
14
S-Wave Travel Time Copyright © 2017
Topical Review Book Compars
Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4: can travel through liquids and S-waves cannot.
What are P waves?A P wave is known to be a compressional wave. This is seen as a kind of a seismic body wave that often moves or shakes the ground a lot in the same direction and also in its opposite direction as the wave moving direction.
Note that the P waves can be able to move via liquid and solids and gases, but the S waves can only move through solids.
Hence, Only P-waves reach the side of Earth that is opposite the focus because P-waves option 4: can travel through liquids and S-waves cannot.
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What is the maximum speed you can be traveling to stop before hitting a child that runs into the street 60-65 feet ahead of your car
The fastest you could slow down before hitting a youngster who rushed into the road 60 to 65 feet in front of your car is 20 mph.
(Perception/Reaction Distance)
Speed 30 mph 40 mph 50 mph 60 mph 70 mph 80 mph
Distance 44 feet 59 feet 73 feet 88 feet 103 feet 117 feet
Braking Distance 45 feet 80 feet 125 feet 180 feet 245 feet 320 feet
Overall Stopping Distance 89 feet 139 feet 198 feet 268 feet 348 feet 439 feet
Equal to Approximate Number of Car Lengths 6 9 14 18 23 29
Take note that your total stopping distance triples when you double your speed, say from 30 mph to 60 mph or 40 mph to 80 mph.
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You could only brake down to 20 mph before hitting a child who dashed into the road 60 to 65 feet in front of your vehicle.
(Perception/Reaction Distance)
Speed 30, 40, 50, 60, 70, and 80 mph
Distance Braking Distance: 45 feet 80 feet 125 feet 180 feet 245 feet 320 feet 44 feet 59 feet 73 feet 88 feet 103 feet 117 feet
The total stopping distance is about equal to the number of car lengths: 89 feet, 139 feet, 198 feet, 268 feet, 348 feet, and 439 feet. 6 9 14 18 23 29
Be aware that as you double your speed, such as from 30 mph to 60 mph or 40 mph to 80 mph, your total stopping distance triples.
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A spherical balloon is inflated so that its volume is increasing at the rate of 3.3 ft3/min. how rapidly is the radius of the balloon increasing when the radius is 0.65 feet?
The radius is increasing at a rate of 0.31cm/sec.
We know the volume of the balloon is increasing at a rate of 3.3 [tex]ft^{3} min[/tex]
This is expressed as:
[tex]\frac{dV}{dT}[/tex] = 3.3
The volume of a sphere is given by:
V = [tex]\frac{4}{3}[/tex]π[tex]r^{3}[/tex]
The question asks to find the rate of which the radius is increasing when the radius is 0.65 feet.
We need to find:
[tex]\frac{dr}{dt}[/tex]
Since we don't have t in our equation, we will be differentiating implicitly. We can use the chain rule for this:
[tex]\frac{dV}{dT}[/tex] = [tex]\frac{dV}{dR}[/tex].[tex]\frac{dr}{dt}[/tex]
We already know
[tex]\frac{dV}{dT}[/tex] = 3.3
∴
3.3 = [tex]\frac{dV}{dR}[/tex].[tex]\frac{dr}{dt}[/tex]
To find [tex]\frac{dV}{dR}[/tex] we differentiate V = [tex]\frac{4}{3}[/tex]π[tex]r^{3}[/tex]
∴
3.3 = 4[tex]\frac{3.3}{5.30}[/tex][tex]r^{2}[/tex].[tex]\frac{dr}{dt}[/tex]
Dividing ,
[tex]\frac{3.3}{5.30}[/tex] = [tex]\frac{dr}{dt}[/tex] = 0.622 ft/min = 0.31 cm/sec
The radius is increasing at a rate of 0.31cm/sec.
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Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3. 0×108m/s. what are the wavelengths of these signals?
The wavelengths of these signals is between 187.50m to 2.77 m.
Frequency describes the number of waves that skip a set region in a given quantity of time. There are two forms of frequency desk - Grouped Frequency Distribution and Ungrouped Frequency Distribution.
Wavelength is normally denoted with the aid of the Greek letter lambda (λ); it is identical to the velocity (v) of a wave train in a medium divided by means of its frequency (f)= λ = v/f.
Part A)
λ max = v / f
= 3 x 10^8 / 550x10^3 =545.45 m
λmin = 3 x 10^8 / 1600x10^3 = 187.50m
Part B)
λ max = v / f
= 3 x 10^8 / 88x10^6
= 3.41 meters
λmin = 3 x 10^8 / 108x10^6 = 2.77 m
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We see a full moon by reflected sunlight. How much earlier did the light that enters our eye leave the sun? the earth-moon and earth-sun distances are 3. 8 x 105 km and 1. 5 x 108 km
The time taken by the light reflected from sun to reach on earth will be 8.4 minutes.
To find the answer, we need to know about the distance travelled by light.
How to find the time taken by the light reflected from sun to reach on earth?So, in order to solve this problem, we must first know how far the moon is from Earth and how far the Sun is from the moon. These distances are given as 3.8×10^5 km (Earth-Moon) and 1.5×10^8 km (Sun- Earth). Since the Moon and Sun are on opposite sides of Earth during a full moon, the light's distance traveled equals,[tex]d=(1.5*10^8km)+2(3.8*10^5km)=1.51*10^8km=1.51*10^{11}m[/tex]
As we know that light travels at a speed of 300,000 km per second. then, the time taken by the light reflected from sun to reach on earth will be,[tex]t=\frac{1.51*10^{11}}{3*10^8}=503.33 s\\t=\frac{503.33}{60}=8.4min[/tex]
Thus, the time it takes for the light from the Sun to reach Earth and be recognized as 8.4 minutes.
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