A bag contains 4 blue marbles and 7 red marbles. Two marbles are randomly drawn without replacement. Find the probability of the event ""the first marble is red and the second marble is blue""?

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

A line plot can be defined as a type of graph that is used to graphically represent a data set above a number line, while using crosses, dots, or any other mathematical symbol.

A mean is also referred to as an arithmetic average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

Mathematically, the distance between the means of both classes A and B is given by:

Distance = Mean of class A - Mean of class B

Distance = 12 - 4

Distance = 8.

The mean absolute deviation (MAD) for class A is given by:

MAD A = 1/9[2(9 - 12) + (10 - 12) + (11 - 12) + (12 - 12) + (13 - 12) + (14 - 12) + 2(15 - 12)]

MAD A = 1/9[2(3) + (2) + (1) + 0 + (1) + (2) + (1) + 2(3)]

MAD A = 1/9[6 + 2 + 1 + 1 + 2 + 1 + 6]

MAD A = 1/9 × [18]

MAD A = 18/9

MAD A = 2.

Also, the mean absolute deviation (MAD) for class B is given by:

MAD B = 1/9[2(1 - 4) + (2 - 4) + (3 - 4) + (4 - 4) + (5 - 4) + (6 - 4) + 2(7 - 4)]

MAD B = 1/9[2(3) + 2(2) + (1) + (0) + (1) + (2) + 2(3)]

MAD B = 1/9[6 + 4 + 1 + 0 + 1 + 2 + 6]

MAD B = 1/9 × [18]

MAD B = 18/9

MAD B = 2.

Therefore, distance between the means = four (4) times the MAD.

Distance = Means × MAD

8 = 4 × 2.

In conclusion, we can infer and logically deduce that there is no overlap and the distance between the means of both players A and B is between one (1) times the MAD and five (5) times the MAD.

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Answer:

83in²

Step-by-step explanation:

This can also be expressed as;

Area of polygon=Area of ∆ABF +Area of rectangle BCDF + Area 0f ∆DEF

For ∆ABF;

Area of ∆ABO=∆AOF

Area of ∆ABF=2×Area of ∆ABO

Area of ∆ABO=1/2×Length×height

=1×4×7/2=28/2=14in

But area of ∆ABF=2×Area of ∆ABO

Area=2×14in=28in.

Area of rectangle;

Area=length×breadth

Area=5in×8in=40in.

Area of ∆DEF=2×Area of ∆EFG

Area=1/2× base× height

Area=1×2.5×6/2

Area=15/2=7.5in.

But area of ∆EFG=2×7.5in

=15in.

Area of polygon=28in+40in+15in=83in

Answer:

y=2x+12

Step-by-step explanation:

Answer:

n = 2

Step-by-step explanation:

cross multiply

-5 times -4 = 20

10n = 20

n = 2

[tex]\bf{Move \ the \ negative \ symbol \ to \ the \ left. }[/tex]

[tex]\boldsymbol{\sf{-\dfrac{10n}{5}=-4 \ \ \longmapsto \ \ [Split] }}[/tex]

[tex]\boldsymbol{\sf{-2n=-4 }}[/tex]

[tex]\bf{Divide \ both \ sides \ by \ -2. }[/tex]

[tex]\boldsymbol{\sf{n=\dfrac{-4}{-2} }}[/tex]

[tex]\bf{Two \ negatives \ make \ a \ positive. }[/tex]

[tex]\boldsymbol{\sf{n=\dfrac{4}{2} \ \ \longmapsto \ \ [Split] }}[/tex]

[tex]\blue{\boxed{\boldsymbol{\sf{Answer \ \ \longmapsto \ \underline{n=2}}}}}[/tex]

By definitions of volume and flow rate, it will take a time of 10 minutes to fill the tank to a height of 50 centimeters.

Herein we find the case of a rectangular tank being filled with water at constant flow are, which is dimensionally speaking, volume by time. We know that dimensions of the tank are described in centimeters, whereas flow rate is described in liters per minute. Please notice that a liter is equal to 1000 cubic centimeters:

t = [(80 cm) · (60 cm) · (50 cm) · (1 L / 1000 cm³)] / (24 L / min)

t = 10 min

By definitions of volume and flow rate, it will take a time of 10 minutes to fill the tank to a height of 50 centimeters.

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the equation that represents the new graph is:

g(x) = √(x - 3) - 2

Here we start with the function:

y = f(x) = √x

First, we shift it 2 units down, then the new equation will be:

g(x) = f(x) - 2

Now we apply a horizontal shift, this time we shift the graph 3 units to the left, then the new equation is:

g(x) = f(x - 3) - 2

Now we replace f(x) = √x to get:

g(x) = √(x - 3) - 2

That is the equation that represents the new graph.

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Answer:

1/36

Step-by-step explanation:

Assuming the dice has 6 sides in total, we can set up a probability for each scenario.

The chances of the dice landing on 1 will be 1/6, since there are 6 total faces. Same goes for the second die and landing on 4.

Now that we have our 2 probabilities, we multiply them to get the final probability. 1/6 x 1/6 = 1/36.

Answer:

x^2

Step-by-step explanation:

So there's very two obvious ones we can elimination immediately, that's f(x) = x, and f(x) = |x|. The reason for this is because we can just look at the first ordered pair of (-2, 4). If it was f(x) = x, then the ordered pair would be (-2, -2), but it isn't. Very similar reasoning for f(x) = |x|, except for this function each ordered pair should have the same magnitude or absolute value. So the f(-2) should output 2, since it's the absolute value, but of course this isn't the case since it's 4.

So let's look at 2^x

[tex]2^{-2} = \frac{1}{2^2} = \frac{1}{4}[/tex]

Since the y value is 4 and not 1/4, this is not the parent function

It should be the second option (x^2), and we can double check

(-2)^2 = 4

(-1)^2 = 1

(0)^2 = 0

(1)^2 = 1

(2)^2 = 4

It outputs the same y-values as the table so this is the parent function

Answer:

11/24 ths each

Step-by-step explanation:

Add the portions left...then divide by the five of them

3/4 + 5/8 + 11/12  = ?      must find common denominator (24) and convert

(18 + 15+22) / 24 = 55/24  now divide by 5 (which is the same as mult by 1/5)

55/24 * 1/5 = 55/120     now simplify to 11/24

We have:

√32x + 1 = 9x - 2

<=> √32x - 9x = -2 - 1

<=> (√32 - 9)x = -3

<=> x = -3/(√32 - 9) = (27+12√2)/49

ANSWER: x = (27+12√2)/49

P/s: i'm not pretty sure

Ok done. Thank to me :3

generally, tanA=opposite/adjacent

answer:tanC=36/15=12/5

Answer:

[tex]Tan \space\ \theta =\frac{\boxed{12}}{\boxed5}}[/tex]

Step-by-step explanation:

The tangent (Tan) of an angle is the ratio of the opposite side and the adjacent side, so that:

[tex]\boxed{Tan\space\ \theta = \frac{opposite}{adjacent}}[/tex].

In this case, with respect to angle C:

• opposite = AB =  36 units

• adjacent = CB = 15 units.

Substituting the values into the equation:

[tex]Tan \space\ C = \frac{36}{15}[/tex]

           = [tex]\bf \frac{12}{5}[/tex]   (simplified)

Answer: Reagan's pay was increased by 62%

Step-by-step explanation:

First, lets find the difference between the two pays:

$347,247 - $214,350 = $132,897

Let 214350 = 100%

Dividing 132,897 by 214350 to find the percent increase

[tex]\bold{\frac{132,897}{214,350} }=0.62\times100=62[/tex]

Therefore, Reagan's pay was increased by 62%

∠KJI≅ZJX is the additional information.

What are the AAS congruency criteria?

⇒ AAS stands for Angle-Angle-Side. When two angles and a non-included side of a triangle are equal to the corresponding angles and sides of another triangle, then the triangles are said to be congruent

We have been given that

⇒ kJ=ZJ

⇒∠KJI=∠ZJX (vertically opposite angle)

And we require one more angle which can't be on the non-included side

so we have only one angle that can satisfy this  

⇒∠JIK=∠JXZ

⇒ Now we can say that △KJI ≅ △ZJX is congruent with AAS congruency criteria

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[tex]-16=r^3\implies \sqrt[3]{-16}=\sqrt[3]{r^3}\implies \sqrt[3]{-16}=r\implies \sqrt[3]{-2^4}=r \\\\\\ \sqrt[3]{(-2)^3\cdot 2^1}=r\implies -2\sqrt[3]{2^1}=r\implies -2\sqrt[3]{2}=r[/tex]

Answer:

By definition, angles A and 1 are corresponding angles and angles B and 1 are consecutive angles. By the corresponding angles postulate, angles A and 1 are congruent, and by the consecutive angles theorem, angles B and 1 are supplementary. By the definition of supplementary angles, measures of angle B and 1 add up to 180 degrees (m<B + m<1 = 180). By definition of congruent angles, angles A and 1 have same measurement (m<A = m<1). By substitution property of equality, measures of angles A and B add up to 180 degrees (m<A + m<B = 180). By definition of supplementary angles, angles A and B are supplementary.

(i) The measures of the angles are m ∠ TCM = m ∠ TCQ = m ∠ CMQ = 90°.

(ii) The lengths of sides CM and CQ are 2 cm and 2√2 cm, respectively.

(iii) The angle between the side face and the base is equal to θ = cos⁻¹ (2 / MT) and the angle between the slant edge and the base is θ = cos⁻¹ [2√2 / √(4 + MT²)].

In this problem we have a right pyramid as line segment TC is perpendicular to the base PQRS, which means that any line coplanar with PQRS is perpendicular to line segment TC. i) the measures of the angles are m ∠ TCM = m ∠ TCQ = 90°.

Besides, the base PQRS is a square, which is equivalent to four right triangles with angles 45° - 45° - 90° and each triangle can be divided into two right triangles. Hence, the measure of the angle CMQ is 90°.

ii) The length of the sides can be found by the 45-45-90 theorem, which states that the length of the hypotenuse is √2 times the length of any of the legs:

CQ = (√2 / 2) · PQ

CQ = (√2 / 2) · (4 cm)

CQ = 2√2 cm

CM = (√2 / 2) · (2 √2 cm)

CM = 2 cm

iii)  The angle between the side face, one of them contains the line segment MT and the base can be found by the following inverse trigonometric relation: (value of the pyramid height is missing)

θ = cos⁻¹ (CM / MT)

θ = cos⁻¹ (2 / MT)            (1)

Similarly, the angle between the slant edge and the base is found by Pythagorean theorem and inverse trigonometric relation: (value of the pyramid height is missing)

θ = cos⁻¹ (CQ / TQ)

θ = cos⁻¹ [2√2 / √(QM² + MT²)]

θ = cos⁻¹ [2√2 / √(4 + MT²)]          (2)

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a) The coordinates of point A that meet the linear equation y = 2 · x + 7 are A(x, y) = (0, 7).

b) The equation of the line parallel to the line y = 2 · x + 7 is the line y = 2 · x + 3.

c) The coordinates of the midpoint of line segment BC is M(x, y) = (1, 7).

Herein we find three cases related to the linear equation y = 2 · x + 7. a) We need to determine the coordinates of point A, the y-coordinate can be determined by evaluating the function:

y = 2 · 0 + 7

y = 0 + 7

y = 7

The coordinates of point A that meet the linear equation y = 2 · x + 7 are A(x, y) = (0, 7).

b) Two lines are parallel to each other whether both have the same slope but different intercept. Then, the new line is of the form:

y = 2 · x + b

Now we proceed to find the intercept of the line:

b = y - 2 · x

b = 3 - 2 · 0

b = 3

The equation of the line parallel to the line y = 2 · x + 7 is the line y = 2 · x + 3.

c) The coordinates of point C is:

y = 2 · 2 + 7

y = 11

If we know that B(x, y) = (0, 3) and C(x, y) = (2, 11), then the coordinates of the midpoint of BC is:

M(x, y) = 0.5 · B(x, y) + 0.5 · C(x, y)

M(x, y) = 0.5 · (0, 3) + 0.5 · (2, 11)

M(x, y) = (1, 7)

The coordinates of the midpoint of line segment BC is M(x, y) = (1, 7).

The statement presents typing mistakes and omissions, complete form is shown below:

a) The line of y = 2x + 7 meets the y-axis at A, where x = 0. Write down the co-ordinates of A.

b) A line parralel to y = 2x + 7 passes through B(x, y) = (0,3) Find the equation of this line.

c) C is the point on the line y = 2x + 7 where x = 2. Find the the co-ordinates of the midpoint of BC.

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The graph of the linear equation can be seen in the image below.

Here we have a linear equation:

y = -x

To graph it, we just need to find two points and the line, and then connect the points with a line.

Evaluating in x = 0, we get:

y = -0 = 0

Then we have the point (0, 0).

Evaluating in x = 1 we get:

y = -1

So we have the point (1, -1)

Now we just need to graph these two points and connect them with a line, the graph can be seen below.

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The scale factor of the given dilation transformation is calculated as; 1/2

We know that from transformation that  a dilation is a non - rigid transformation that produces similar figures.

If two lines are similar, then the lines are parallel and parallel lines always have the same slope.

Thus;

Line A has the formula; 2y = x + 8

Writing it in slope intercept form gives us;

y = 0.5x + 4   ------(1)

Thus;

slope of the line A is m = 0.5

y-intercept of the line A is b = 4

Line B has the equation;

y - ¹/₂x = 2

Rearranging in Slope Intercept form gives us;

y = ¹/₂x + 2

Thus;

slope of the line B is m = 0.5

y-intercept of the line B is b = 2

Now, it should be noted that the y-intercept of line A multiplied by the scale factor k must be equal to the y-intercept of line B. Thus;

4k = 2

k = 2/4

k =  ¹/₂

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If the initial value problem is [tex]y^{11} -8y^{1} -15y=0[/tex] and [tex]y^{1}(0) =1[/tex],y(0)=0 then y(t)=[tex](e^{3t} -e^{5t} )/2[/tex].

Given the initial value problem be   [tex]y^{11} -8y^{1} -15y=0[/tex]and  [tex]y^{1}(0) =1[/tex],y(0)=0.

We are required to find the solution of the given initial value problem.

Laplace transform is an integral transformation that converts a function of a real variable to a function of a complex variable.

Take laplace on the DE, we get

[tex]s^{2}-sY(0)-y^{i}(0)-8[sY(s)-y(0)-15Y(s)]=0[/tex]

[tex]s^{2}Y(s)-s(0)-1-8{sY(s)-0)}+15Y(s)=0[/tex]

(Putting the values given in question)

Y(s)=([tex]s^{2} -8s+15)-1=0[/tex]

Y(s)=1/([tex]s^{2} -8s+15[/tex])

Simplifying the above:

=1/([tex]s^{2} -5s-3s+15)[/tex]

=1/[s(s-5)-3(s-5)]

=1/2 [1/(s-3)-1/(s-5)]

Taking inverse of the above we get,

y(t)=[tex](e^{3t} -e^{5t} )/2[/tex]

Hence if the initial value problem is [tex]y^{11} -8y^{1} -15y=0[/tex] and [tex]y^{1}(0) =1[/tex],y(0)=0 then y(t)=[tex](e^{3t} -e^{5t} )/2[/tex].

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Answer:

The frame will be 4 inches in width

Step-by-step explanation:

The length of the outside is 24+2x

The width of the outside is 20+2x

(24+2x)(20+2x) - 20(24) = 416

480 + 40x + 48x + 4x2 - 480 = 416

4x2 + 88x - 416 = 0

x2 + 22x - 104 = 0

(x+26)(x-4) = 0

x = -26 or x=4

The frame will be 4 inches in width

a3=9

assuming the pattern is constant, a3 is right in the middle of a1 and a5 so the answer would be right in the middle of 6 and 12. the average of 6 and 12 is 9, so a3=9.

hope this helps!

The total amount the recycler pays Olivia is $1000.

The weight of the copper is expressed as a fraction A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below.

There is a need to convert tons to pounds:

1 ton = 2000 pounds

1/8 x 2000 = 250 pounds

The total amount that the recycler pays can be determined by multiplying the total pounds by cost per pound.

Total cost = cost per pound x total pound

250 x $4 = $1000

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The least common multiple of two or more natural numbers is the least common multiple of all of them. This concept has historically been linked to natural numbers, but can be used for negative integers or complex numbers.

We calculate the least common multiple, by simultaneous decomposition, this method consists of extracting the common and non-common prime factors, therefore

L.c.m.(12,15,18)= 2² × 3² × 5 = 180 min

The least common multiple of 12, 15, and 18 is 180.

Convert the minutes to hours, for this we apply the rule of 3:

As the bells all together ring at 6 am, so we add

Answer: The bells are rung together again at 9 in the morning.

Carries two brothers each ate 4 pieces, the rest of carries family ate 14 pieces and there were 14 pieces remaining given that Carries family broke a package of graham crackers into 32 pieces. carries two brothers each ate 1/8 of the pieces and the rest of the family ate 7/16 of the pieces. This can be obtained by multiplying the fractions given with the total number.

From the question it is given that,

Carries family broke a package of graham crackers into 32 pieces.

Therefore total number of pieces will be 32 pieces.

carries two brothers each ate 1/8 of the pieces

This means that out of 32, 1/8 of the pieces were ate by the two brothers.

1/8 of 32 = 1/8 × 32 = 4 pieces

⇒ Carries two brothers each ate 4 pieces

the rest of the family ate 7/16 of the pieces

This means that out of 32, 7/16 of the pieces were ate by the rest of the family

7/16 of 32 = 7/16 × 32 = 14 pieces

⇒ the rest of carries family ate 14 pieces

remaining pieces = 32 - (4 + 14) = 32 - 18 = 14 pieces

⇒ there were 14 pieces remaining

Hence Carries two brothers each ate 4 pieces, the rest of carries family ate 14 pieces and there were 14 pieces remaining given that Carries family broke a package of graham crackers into 32 pieces.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Carries family broke a package of graham crackers into 32 pieces. carries two brothers each ate 1/8 of the pieces and the rest of the family ate 7/16 of the pieces.

carries two brothers each ate ____ pieces

the rest of carries family ate ____ pieces

there were ____ pieces remaining

It would be the bottom left graph

Initial production: 1050

so the graph will be started at 1050 which makes top right graph incorrect

Next, the money at the lowest was 250 which makes the top left and bottom right incorrect.

leaving only the bottom right graph to be correct

Answer:

Graph Y

Step-by-step explanation:

Given information:

The initial production cost is when the number of items is zero.

Therefore, the y-intercept of the graph will be (0, 1050).

The lowest production cost is the minimum point of the curve.

Therefore, the vertex of the graph will be (2, 250).

The only graph that satisfies these conditions is graph Y (attached).

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There are 20! number of ways for everyone to do this so that at the end of the move, each seat is taken by exactly one person.

People are seated in a 2 by 10 rectangle grid. All 20 persons stand up from their seats and relocate to an orthogonally neighboring one upon the blowing of a whistle.

Now, we have to find the number of possible ways in which each seat is taken up by exactly one person after the move.

As the number of people is 20 and 20 seats are to filled exactly once.

So, the number of ways = 20!

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Solving the quadratic equation we conclude that:

The height of the rocket is defined by the quadratic equation:

[tex]d = 90t - 5t^2[/tex]

The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:

[tex]t = -90/(2*-5) = 9[/tex]

So the maximum height is what we get when we evaluate in t = 9:

[tex]d = 90*9 - 5*9^2 = 45[/tex]

The maximum height is 45ft.

Now we need to solve the equation for the largest value of t:

[tex]d = 90*t - 5t^2 = 0[/tex]

Rewriting it, we get:

[tex]0 = 90*t - 5*t^2\\\\0 = t*(90 - t*5)[/tex]

The maximum solution is what we get when:

0 = 90 - t*5

t = 90/5 = 18

The rocket is 18 seconds in the air.

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Answer:

Option C: x = 6

Step-by-step explanation:

Hi There!

7 + 5 (x - 3) = 22

=> 7 + 5x - 15 = 22

=> 5x = 22 - 7 + 15

=> 5x = 30

=> x = 30/5

=> x = 6

x = 6 makes the statement true.

Thank you,

Eddie

The value of 'a' closest to hundredths is 41.41

A triangle could also be  a polygon with three sides and three angles. The three sides for a triangle DEF shown above, written symbolically as △DEF, are line segments DE, EF, and DF

If three sides of a triangle are adequate to three sides of another triangle, then the triangles are congruent. (2) If three angles of a triangle are respectively  adequate to three angles of another triangle, then the 2 triangles are congruent.

Since this is often a right triangle, we'll  use trig functions:

cos theta = adjacent / hypotenuse;

cos a=FD/DE;

cos a=45/60.

Taking the inverse of each side:

cos-1(cos a) =cos-1(3/4);

a=41.40962211.

After Rounding to the closest hundredth:

The value of a is 41.41.

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