Answer
B
explanation
3480ones = 3480x1=3480
You need to haul a load of patio bricks to a job site. Each brick weighs 4 pounds 14 ounces. Your truck can carry a 3/4 -ton load. How many bricks can your truck carry in a full load?
A.
300
B.
307
C.
362
D.
409
E.
483
Suppose f(x) = x2. What is the graph of g(x) = f(4x)?
[tex]g(x)=f(4x)=(4x)^2 = 16x^2[/tex]
The graph is shown in the attached image.
In a flower garden of rose and sunflower, 40% of flowers are rose. if there are 120 sunflower in the garden, total of how many flowers are there in the garden?
Answer:
200
Step-by-step explanation:
If 40% are roses than 60% must be sunflowers (40% + 60% = 100%)
We are trying to find 60% of some number is 120.
Let n = the total number of flowers
.6n = 120 Divide both sides by .6
n = 200
Triangle Congruency Theorems: Edge High School Geometry
Answer is below:
DE ≅ CE given that side AD and side BC are equal and angle ∠BCD and angle ∠ADC are equal. This can be obtained by using triangle congruency theorems.
Prove that side DE and side CE is equal:Triangle congruency theorems required in the question,
SAS triangle congruency theorem - SAS means Side-angle-side. If two sides and the included angle of a triangle is equal to two sides and the included angle of another triangle then the triangles are congruent.AAS triangle congruency theorem - AAS means Angle-angle-side. If two angles and one side of a triangle is equal to two angles and one side of another triangle then the triangles are congruent.
In the question it is given that,
⇒ Side DE and side CE are equal ⇒ AD ≅ BC
⇒ angle ∠BCD and angle ∠ADC are equal ⇒ ∠BCD ≅ ∠ADC
AD ≅ BC (given in the question)∠BCD ≅ ∠ADC (given in the question)DC ≅ DC (since DC is a common side; reflexive property)Therefore we can say that,
ΔADC ≅ ΔBCD according to the SAS triangle congruency theorem
∠DAE ≅ ∠CBE (corresponding parts of congruent triangles are congruent (CPCTC))AD ≅ BC (given in the question)∠DEA ≅ ∠CEB (since they are vertically opposite angles - vertical angles theorem)ΔAED ≅ ΔBEC according to the AAS triangle congruency theorem
Thus DE ≅ CE since corresponding parts of congruent triangles are congruent (CPCTC).
Hence DE ≅ CE given that side AD and side BC are equal and angle ∠BCD and angle ∠ADC are equal.
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The entire graph of the function g is shown in the figure below.
Write the domain and range of g using interval notation.
The domain of the function is [-4, 4) and the range of the function is [-5, 2)
How to determine the domain and the range of the function?The domain
As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.
This means that the domain is the set of x values
From the graph, we have the following intervals on the x-axis
x = -4 (closed circle)
x =4 (open circle)
This means that the domain of the function is [-4, 4)
The range
As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.
This means that the range is the set of y values
From the graph, we have the following intervals on the y-axis
y = -5 (closed circle)
y = 2 (open circle)
This means that the range of the function is [-5, 2)
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List the sides of triangle RST in acsending order (Shortest to longest.)
The sequence of angles from smallest to largest is m∠T,m∠S,m∠R.
Given three angles be m∠T=4x-52°,m∠S=x+38°,m∠R=2x+47°.
We are required to arrange the angles in ascending order.
Ascending order means values that are written in a way that smallest values come first and larger values comes last.
First we have to find the angles at one value of x.
The values will differ as the values of x differ so we have to choose point or value of x.
Suppose x=20.
Then the angles are:
m∠T=4x-52°
=4*20-52
=80-52
=28°
m∠S=x+38°
=20+38
=58°
m∠R=2x+47°
=2*20+47
=40+47
=87°
Hence the sequence of angles from smallest to largest is m∠T,m∠S,m∠R.
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What’s an Inequality?
Answer:
mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.
Answer:
The quality of being unequal or uneven is known as the inequality.Question 10 of 25
Which pair of functions are inverses of each other?
[tex]f(x) = \sqrt[3]{11x} \\ y = \sqrt[3]{11x} \\ x = \sqrt[3]{11y} \\ x {}^{3} = 11y \\ y = \frac{x {}^{3} }{11} [/tex]
Option A eliminated[tex]f(x) = \frac{x}{7} + 10 \\ y = \frac{x}{7} + 10 \\ x = \frac{y}{7} + 10 \\ x - 10 = \frac{y}{7} \\ y = \frac{x - 10}{7} [/tex]
Option B eliminated[tex]f(x) = \frac{7}{x} - 2 \\ y = \frac{7}{x} - 2 \\ x = \frac{7}{y} + 2 \\ x - 2 = \frac{7}{y} \\ y = \frac{7}{x - 2} [/tex]
Option C eliminatedBy elimination it's DConfirmation:[tex]f(x) = 9x - 6 \\ y = 9x - 6 \\ x = 9y - 6 \\ x + 6 = 9y \\ y = \frac{x + 6}{9} = g(x)[/tex]
A bank ATM system has a pad with 10 digits (0 to 9). Find the number of possible 4-digit pin codes
if digits can be repeated.
if digits cannot be repeated.
a.
1. 10 000 ; 2. 5 040.
b.
1. 5 040; 2. 10 080.
c.
1. 10 000; 2. 210.
d.
1. 3 125; 2. 15 120.
Answer:
A
Step-by-step explanation:
If digits can be repeated, that means there are 10 options for each place in the pin code. 10*10*10*10 = 10,000
If digits can not be repeated, there are 10 options for the first digit, 9 options for the second digit, 8 options for the third digit, and 7 options for the fourth digit. 10*9*8*7 = 5040
Find the mean for the amounts: $17,484, $14,978, $13,521, $14,500, $18,540, $14,978
Answer:
$15666.83 (2dp)
Step-by-step explanation:
Mean = Total of all values / Number of Values
= [tex]\frac{17484+14978+13521+14500+18540+14978}{6}[/tex]
=[tex]\frac{94001}{6}[/tex]
= $15666.83 (2dp)
What is the solution to 3/4 a>-16?
O a>-21/3
O a<-21
O a> 21-1/
O a <21/13
[tex] \frac{3a}{4} > - 16 \\ 3a > - 64 \\ a > \frac{ - 64}{3} \\ a > 21 \frac{1}{3} [/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation:}[/tex]
[tex]\mathsf{\dfrac{3}{4}a > -16}[/tex]
[tex]\huge\textbf{Simplifying it:}[/tex]
[tex]\mathsf{\dfrac{3}{4}a > -16}[/tex]
[tex]\mathsf{\dfrac{3}{4}a > - \dfrac{16}{1}}[/tex]
[tex]\huge\textbf{Divide \boxed{\dfrac{4}{3}} to both sides:}[/tex]
[tex]\mathsf{\dfrac{4}{3}\times\dfrac{3}{4}a > -16\times\dfrac{4}{3}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\mathsf{a > \dfrac{4}{3}\times -16}[/tex]
[tex]\mathsf{a > - \dfrac{16}{1} \times\dfrac{4}{3}}[/tex]
[tex]\mathsf{a > \dfrac{-16\times4}{1\times3}}[/tex]
[tex]\mathsf{a > \dfrac{-64}{3}}[/tex]
[tex]\mathsf{a > -\dfrac{64}{3}}[/tex]
[tex]\mathsf{a > -21 \dfrac{1}{3}}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{- \frak{21\dfrac{1}{3}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]Which equation represents a parabola with a vertex at (7,-3)
Answer:
See Below
Step-by-step explanation:
y = a (x-7)^2 -3 where 'a' is any number except 0
Which expression is equivalent to sec²x - 1?
O A. cot²x
OB. tan²x
OC. CsC²x
OD. cos²x
[tex]l = sec {}^{2} x - 1 \\ l = \frac{1}{cos {}^{2} x} - \frac{cos {}^{2} x}{cos {}^{2} x} \\ l = \frac{1 - cos {}^{2} x}{cos {}^{2}x } \\ l = \frac{sin {}^{2} x}{cos {}^{2} x} = ( \frac{sinx}{cosx} ) {}^{2} = tan {}^{2} x[/tex]
Bwhat is ordinary numbers
What is ordinary number?
1 : a number designating the place (such as first, second, or third) occupied by an item in an ordered sequence — see Table of Numbers. 2 : a number assigned to an ordered set that designates both the order of its elements and its cardinal number.
A textbook store sold a combined total of 204 math and psychology textbooks in a week. The number of math textbooks sold was three times the number of psychology textbooks sold. How many textbooks of each type were sold?
A total of 204 textbooks were sold with 153 math textbooks and 51 psychology textbooks being sold, as the number of math textbooks was three times the number of psychology textbooks.
Given that,
The combined total of math and psychology textbooks sold in a week is 204.
The number of math textbooks sold is three times the number of psychology textbooks sold.
To solve this problem,
Assign variables to represent the number of math and psychology textbooks sold.
Let's say "M" represents the number of math textbooks and "P" represents the number of psychology textbooks.
We know that the combined total of math and psychology textbooks sold is 204,
So the equation be:
M + P = 204 .....(i)
We are also given that the number of math textbooks sold was three times the number of psychology textbooks sold.
In equation form, this can be expressed as:
M = 3P
Now, we can substitute the value of M in terms of P into the equation (i):
3P + P = 204
Combining like terms, we get:
4P = 204
Dividing both sides by 4, we find:
P = 51
So, the number of psychology textbooks sold is 51.
To find the number of math textbooks sold,
Substitute this value back into the equation:
M = 3P
M = 3(51)
M = 153
Therefore, the number of math textbooks sold is 153.
Hence,
153 math textbooks and 51 psychology textbooks were sold.
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For what value of x is the rational expression below equal to zero?
X-4
(x+5)(x-1)
IOA. 4
OB. 1
O C. -4
OD. -5
Answer:
A
Step-by-step explanation:
x - 4 / (x + 5)(x - 1)
let's expand:
x - 4 / x² + 4x - 5
4 - 4 / 16 + 16 - 5 = 0 so answer is 4
A SINGLE CARD IS DRAWN AT RANDOM FROM A STANDARD DECK OF 52 CARDS. FIND THE PROBABILITY OF DRAWING THE FOLLOWING CARDS. PLEASE REDUCE TO LOWEST TERMS.
A) A DIAMOND OR A 5 __________
B) A HEART AND A JACK __________
C) A JACK OR AN 8 __________
D) A HEART OR A SPADE __________
E) A RED AND FACE CARD __________
F) A RED CARD OR A QUEEN __________
Answer:
A. [tex]\frac{17}{52}[/tex]
B. [tex]\frac{17}{52}[/tex]
C. [tex]\frac{2}{13}[/tex]
Step-by-step explanation:
A.
There are 52/4 diamonds in the deck and 4 '5's in the dech of cards
52/4 = 13 + 4 = 17
Therefore, you have a [tex]\frac{17}{52}[/tex] chance of drawing one of those cards.
B.
There are 13 hearts in the deck and 4 jacks. Therefore, your odds are the same : [tex]\frac{17}{52}[/tex]
C.
There are 4 jacks in a deck of cards and 4 '8's in a deck of cards
Therefore your probability is [tex]\frac{8}{52}[/tex] which simplifies to [tex]=\frac{2}{13}[/tex]
As per brainly guidelines I can only answer 3 questions in one answer
Help me with this equation, please. (Image Attached)
So, the equation is sin(x + y)/sin(x - y) = (1 + cotxstany)/(1 + cotxtany)
The question has to to with trigonometric identities?
What are trigonometric identities?Trigonometric identities are equations that show the relationship between the trigonometric ratios.
How to solve the equation?Given the equation sin(x + y)/sin(x - y)
Using the trigonometric identities.
sin(x + y) = sinxcosy + cosxsiny andsin(x - y) = sinxcosy - cosxsinySo, sin(x + y)/sin(x - y) = (sinxcosy + cosxsiny)/(sinxcosy + cosxsiny)
Dividing the rnumerator and denominator of ight hand side by sinx, we have
sin(x + y)/sin(x - y) = (sinxcosy + cosxsiny)/sinx/(sinxcosy + cosxsiny)/sinx
sin(x + y)/sin(x - y) = (sinxcosy/sinx + cosxsiny/sinx)/(sinxcosy/sinx + cosxsiny/sinx)
= (cosy + cotxsiny)/(cosy + cotxsiny) (since cosx/sinx = cotx)
Dividing the numerator and denominator of the right hand side by cosy, we have
= (cosy + cotxsiny)/cosy/(cosy + cotxsiny)/cosy
= (cosy/cosy + cotxsiny/cosy)/(cosy/cosy + cotxsiny/cosy)
= (1 + cotxstany)/(1 + cotxtany) [since siny/cosy = tany]
So, sin(x + y)/sin(x - y) = (1 + cotxstany)/(1 + cotxtany)
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The Tortoise and the Hare is a fable about a race with the
moral, “Slow and steady wins the race.” The Tortoise and the
Hare decide to “race” across the United States from
Washington D.C. to Los Angeles.
a. Charles Darwin studied the tortoises when he was on
the Galapagos in 1835. He thought they moved relatively quickly. “One large one, I found by pacing, walked at the rate of 60 yards in 10 minutes” he wrote in Zoology Notes.
i How many inches per minute does the Galapagos tortoise walk?
ii. How long would it take a Galapagos tortoise to walk across the U.S.? Use the most
appropriate unit for time.
b. The Hare can run up to 30mph.
i. How many inches per minute does the Hare run?
ii. How long would it take the Hare to complete the race across the U.S.? Use the
most appropriate unit for time.
c. In the fable, the Hare, confident that he is so far head, relaxes and takes a nap. How long would the Hare need to nap for the Tortoise to pass him and win the race?
a.i) The number of inches per minute that the Galapagos tortoise walks are 216 inches (6 x 36).
a.ii) The time it would take a Galapagos tortoise to walk across the U.S. in hours is 2,933 hours (1,056,000/(6 x 60).
b.i) The Hare runs 31,680 inches per minute (1,900,800/60).
b.ii) The time it would take the Hare to complete the race across the U.S. in hours is 20 hours (600/30).
c.) For the Tortoise to pass the Hare, the Hare needs to sleep for 2,913 hours (2,933 - 20) or 121.4 days (2,933/24).
What are the equivalent values for calculating distance?In this exercise, the following equivalent values are used for computing the distance and speed:
1 mile = 1,760 yards1 yard = 36 inches1 hour = 60 minutesDistance from Galapagos to the U.S. = 600 miles600 miles = 1,056,000 yards (600 x 1,760).Data and Calculations:Speed of Galapagos Tortoise per minute = 6 yards/ min (60 yards in 10 minutes)
Speed of Hare = 30mph
30 miles = 52,800 yards (30 x 1,760)
52,800 yards = 1,900,800 inches (52,800 x 36)
= 880 yards per minute (52,800/60)
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I need help please yall
use orders of operation and simplify
Answer: [tex]\large\boxed{12x^3-30x+3=0}[/tex]
Step-by-step explanation:
[tex]Solve:\\\ 6(2x^2-5)x=-3\\\\Use\ distributive\ property\ first\\\\(12x^2-30)x=-3\\\\Now\ multiply\ the\ terms\ in\ ()\ by\ 'x'\\\\12x^3-30x=-3\\\\\large\boxed{12x^3-30x+3=0}[/tex]
on the graph, sketch f(x)=x+3 as well as g(x)=x
Answer:
below
Step-by-step explanation:
2. What is the length of the hypotenuse k?
Answer:
k ≈ 50.77
Step-by-step explanation:
using the cosine ratio in the right triangle
cos19° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{48}{k}[/tex] ( multiply both sides by k )
k × cos19° = 48 ( divide both sides by cos19° )
k = [tex]\frac{48}{cos19}[/tex] ≈ 50.77 ( to 2 dec. places )
Hi :)
————————————————We'll use sohcahtoa to solve this problem
[tex]\Large\boxed{\begin{tabular}{c|1} \sf{Sohcahtoa} ~&~~~~~Formula~~~~~~~ \\ \cline{1-2} \ \sf{Soh} & Opp~\div \text{hyp}\\\sf{Cah} & Adj \div \text{hyp}\\\sf{Toa} & Opp \div \text{adj} \end{tabular}}[/tex]
Looking at our triangle, we can clearly see that we have :
adj. side = 48 (adjacent to the angle)hyp. k (the one we need)Set up the ratio
[tex]\longrightarrow\darkblue\sf{cos(19)=\dfrac{48}{k}}[/tex]
solve for k
[tex]\longrightarrow\darkblue\sf{k\cos(19)=48}[/tex] > multiply both sides by k to clear the fraction
[tex]\longrightarrow\darkblue\sf{k=\dfrac{48}{\cos(19)}}[/tex] > divide both sides by cos (19)
[tex]\star\longrightarrow\darkblue\sf{k\approx50.77}\star[/tex]
[tex]\tt{Learn~More ; Work\ Harder}[/tex]
:)
please help me with these calculus bc questions
4. Compute the derivative.
[tex]y = 2x^2 - x - 1 \implies \dfrac{dy}{dx} = 4x - 1[/tex]
Find when the gradient is 7.
[tex]4x - 1 = 7 \implies 4x = 8 \implies x = 2[/tex]
Evaluate [tex]y[/tex] at this point.
[tex]y = 2\cdot2^2-2-1 = 5[/tex]
The point we want is then (2, 5).
5. The curve crosses the [tex]x[/tex]-axis when [tex]y=0[/tex]. We have
[tex]y = \dfrac{x - 4}x = 1 - \dfrac4x = 0 \implies \dfrac4x = 1 \implies x = 4[/tex]
Compute the derivative.
[tex]y = 1 - \dfrac4x \implies \dfrac{dy}{dx} = -\dfrac4{x^2}[/tex]
At the point we want, the gradient is
[tex]\dfrac{dy}{dx}\bigg|_{x=4} = -\dfrac4{4^2} = \boxed{-\dfrac14}[/tex]
6. The curve crosses the [tex]y[/tex]-axis when [tex]x=0[/tex]. Compute the derivative.
[tex]\dfrac{dy}{dx} = 3x^2 - 4x + 5[/tex]
When [tex]x=0[/tex], the gradient is
[tex]\dfrac{dy}{dx}\bigg|_{x=0} = 3\cdot0^2 - 4\cdot0 + 5 = \boxed{5}[/tex]
7. Set [tex]y=5[/tex] and solve for [tex]x[/tex]. The curve and line meet when
[tex]5 = 2x^2 + 7x - 4 \implies 2x^2 + 7x - 9 = (x - 1)(2x+9) = 0 \implies x=1 \text{ or } x = -\dfrac92[/tex]
Compute the derivative (for the curve) and evaluate it at these [tex]x[/tex] values.
[tex]\dfrac{dy}{dx} = 4x + 7[/tex]
[tex]\dfrac{dy}{dx}\bigg|_{x=1} = 4\cdot1+7 = \boxed{11}[/tex]
[tex]\dfrac{dy}{dx}\bigg|_{x=-9/2} = 4\cdot\left(-\dfrac92\right)+7=\boxed{-11}[/tex]
8. Compute the derivative.
[tex]y = ax^2 + bx \implies \dfrac{dy}{dx} = 2ax + b[/tex]
The gradient is 8 when [tex]x=2[/tex], so
[tex]2a\cdot2 + b = 8 \implies 4a + b = 8[/tex]
and the gradient is -10 when [tex]x=-1[/tex], so
[tex]2a\cdot(-1) + b = -10 \implies -2a + b = -10[/tex]
Solve for [tex]a[/tex] and [tex]b[/tex]. Eliminating [tex]b[/tex], we have
[tex](4a + b) - (-2a + b) = 8 - (-10) \implies 6a = 18 \implies \boxed{a=3}[/tex]
so that
[tex]4\cdot3+b = 8 \implies 12 + b = 8 \implies \boxed{b = -4}[/tex].
The mean of a normally distributed data set is 110, and the standard deviation is 15.
a) Use the standard normal table to find the probability that a randomly-selected data value is greater than 95.
b) Use the standard normal table to find the probability that a randomly-selected data value is greater than 125.
From the standard normal table, the respective probabilities are; 0.908 and 0.841
How to find the probability from z-score?
Formula for calculating the standard score or z score is:
z = (x - μ)/σ
where:
z is the standard score
x is the raw score
μ is the population mean
σ is the population standard deviation
A) We are given;
x = 95
μ = 110
σ = 15
Thus;
z = (95 - 110)/15
z = 1.33
From the normal standard distribution table we can find the probability from the z-score as;
P(x > 95) = 1 - 0.091759.
P(x > 95) = 0.908
B) We are given;
x = 125
μ = 110
σ = 15
Thus;
z = (125 - 110)/15
z = 1
From the normal standard distribution table we can find the probability from the z-score as;
P(x > 95) = 1 - 0.158655.
P(x > 95) = 0.841
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One fifth increase over 400
Answer:
480
Step-by-step explanation:
1/5 of 400 = 1/5 * 400 = 80
increase 400 by 80 = 480
NO LINKS! Please help me with this problem
What is the standard form of the equation of the ellipse?
Answer:
[tex]\frac{x^2}{9}+\frac{y^2}{4}=1[/tex]
Step-by-step explanation:
So an ellipse can be expressed in two different but very similar forms:
Horizontal Major Axis:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]
Vertical Major Axis:
[tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex]
In both equations the length of the major axis is "2a" and the length of the minor axis is "2b"
In the equation you provided, the major axis is horizontal, and the minor axis is vertical.
So looking at the horizontal length, you can see that it's 6, and since this ellipse has a horizontal major axis, that means 2a=6, which means a=3
Looking at the vertical length, you can see that it's 4, and since the ellipse has a vertical minor axis, that means 2b=4, which means b=2
The last thing to note is that the center of an ellipse is (h, k) in the equation, and since here the center is (0, 0) it's (x-0)^2 and (y-0)^2 in the denominator which is just x^2 and y^2
So let's plug in the values into the equation:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]
(h, k) = (0, 0)
a = 3
b = 2
[tex]\frac{x^2}{3^2}+\frac{y^2}{2^2}=1\\\\\frac{x^2}{9}+\frac{y^2}{4}=1[/tex]
Here we go ~
The given figure is of a horizontal ellipse with :
Length of major axis = 2a = 6so, a = 3
Length of minor axis = 2b = 4hence, b = 2
And as it's shown in the figure, the ellipse has its centre at origin, so we can write it's equation as :
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{b {}^{2} } = 1[/tex]
[ now, plug in the values ]
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {x}^{2} }{ {3}^{2} } + \cfrac{ {y}^{2} }{2 {}^{2} } = 1[/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{ {x}^{2} }{ {9}^{} } + \cfrac{ {y}^{2} }{4 {}^{} } = 1[/tex]
That's all, ask me if you have any questions ~
Suppose you know that the distribution of sample proportions of fifth grade students in a large school district who read below grade level in samples of 100 students is normal with a mean of 0.30 and a standard deviation of 0.12. You select a sample of 100 fifth grade students from this district and find that the proportion who read below grade level in the sample is 0.54. This sample proportion lies 2.0 standard deviations above the mean of the sampling distribution. What is the probability that a second sample would be selected with a proportion greater than 0.54 ?
Based on the mean of the sample and the proportion who read below grade level, the probability that a second sample would have a proportion greater than 0.54 is 0.9772.
What is the probability of the second sample being greater than 0.54?The probability that the second sample would be selected with a proportion greater than 0.54 can be found as:
P (x > 0.54) = P ( z > (0.54 - 0.30) / 0.12))
Solving gives:
P (x > 0.54) = P (z > 2)
P (x > 0.54) = 0.9772
In conclusion, the probability that the second sample would be selected with a proportion greater than 0.54 is 0.9772.
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domain of f(x)=(1/4)^x
What is the domain of f(x)
O A. x>0
OB. All real numbers
O C. y>0
O D. x<0
? Need help asap
Answer: B. All real numbers
Step-by-step explanation:
See attached image.
A data set contains three points, and two of the residuals are -10 and 20.
What is the third residual?
If a data set contains three points, and two of the residuals are -10 and 20, the third residual is 10 (option B).
What is a residual?A residual is the difference between the observed value and the estimated value of the quantity of interest.
The residual of a data points should normally sum up to zero (0). This means the following applies:
-10 + 20 + x = 0
x = 10
Therefore, if data set contains three points, and two of the residuals are -10 and 20, the third residual is 10.
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Write a quadratic function fwhose zeros are 2 and 8.
f(x) = 0