16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2) A) 19.5 km/s B) 27.5 km/s *C) 11.2 km/s D) 20.5 km/. orbital speed?

Answers

Answer 1

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

What does Orbital speed depend on ?

The speed of an object travelling around a circle depends on two quantities namely;

Its angular velocity wIts distance from the center of the circle.

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

The mass of Saturn = 5.68 x 10^26 kgThe orbital radius = 3.00 x 105 kmG = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × [tex]10^{-11}[/tex] × 5.68 × [tex]10^{26}[/tex]) ÷ (300000 × 1000)²

g = 3.79 × [tex]10^{16}[/tex] ÷ 9 × [tex]10^{16}[/tex]

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

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Related Questions

A directional loudspeaker aims a sound wave of Frequency 200 H₂ at wall. At what distance from the wall would you stand and hear no sound at all? (v= 332 m/s).​

Answers

The distance from the wall you would stand and hear no sound at all is 0.83 m.

What is speed of wave?

The speed of a wave is the rate of change of distance traveled by a wave with time.

Distance of the wave

The distance at which the wave will have zero amplitude, there will be no sound at all since amplitude of a sound is proportional to intensity of the sound.

The point of zero amplitude, L = λ/₂

Where;

λ is wavelength of the wave

The wavelength of the wave is calculated as follows;

λ = V/f

where;

V is speed of sound wavef is frequency of the wave

λ = 332/200

λ = 1.66 m

Distance from the wall a zero sound

L = 1.66/2

L = 0.83 m

Thus, the distance from the wall you would stand and hear no sound at all is 0.83 m.

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A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases.
The new sphere has a density of ρ > ρ0 and a mass of m = m0.
The new sphere has a mass of m > m0 and a radius of r = r0.
The new sphere has a radius of r = r0 and a density of ρ > ρ0.

Answers

Based on the given data about, volume, mass, and density of the spheres;

the water level will fall; fthe water level may rise or fall; r or fthe water level will rise; r

What determines whether an object floats are sinks in water?

The density, mass, volume, and shape of an object determines whether it will float or sink in water.

Density = mass/volume

For an object to float, it will displace its own weight of the fluid in which it floats. This is according to Archimedes' principle which states that the upward force acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.

Considering the given scenarios:

1. The new sphere has a density of ρ > ρ0 and a mass of m = m0.

This means that the volume of new sphere is smaller than the volume of the original sphere, therefore, the water level will fall,

2. The new sphere has a mass of m > m0 and a radius of r = r0.

This means that the new sphere will have a greater volume and mass. However, the density may be greater or less.. Therefore, the water level may rise or fall.

3. The new sphere has a radius of r = r0 and a density of ρ > ρ0.

The new sphere has equal volume, greater density and mass than the original sphere. Therefore, the water level will rise.

In conclusion, the level of the water in the container depends on the volume, mass and density of the object placed in it.

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A ball of mass 0.200 kg has a velocity of 150m/s; a ball of mass 0.300 kg has a velocity of - 0.4m/s. They meet in a head-on elastic collision. (a) Find their velocities after the collision. (b) Find the velocity of their center of mass before and after the collision. ​

Answers

(a) The velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.

(b) The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.

Velocity of the balls after collision

Apply the principle of conservation of linear momentum to determine the velocity of the balls;

m₁u₁ + m₂u₂ = m₁v₁  + m₂v₂

0.2(150) + (0.3)(-0.4) = 0.2v₁ + 0.3v₂

29.88 = 0.2v₁ + 0.3v₂

Apply one directional linear velocity

u₁ + v₁ = u₂ + v₂

v₁ = u₂ + v₂ - u₁

v₁ = -0.4 + v₂ - 150

v₁ = v₂ - 150.4

Substitute the value of v₁ into the first equation;

29.88 = 0.2(v₂ - 150.4) + 0.3v₂

29.88 = 0.2v₂ - 30.08 + 0.3v₂

59.96 = 0.5v₂

v₂ = 59.96/0.5

v₂ = 119.92 m/s

v₁ = 119.92 - 150.4

v₁ = -30.48 m/s

Velocity of their center mass before collision

V(cm) = (0.2 x 150  +  0.3 x 0.4) / (0.2 + 0.3)

V(cm) = 60.24 m/s

Velocity of their center mass after collision

V(cm) = (0.2 x 30.48 +  0.3 x 119.92) / (0.2 + 0.3)

V(cm) = 84.14 m/s

Thus, the velocity of 0.2 kg after the collision is 30.48 m/s and the velocity of the 0.3 kg mass is 119.92 m/s.

The velocity of their center of mass before collision is 60.24 m/s and after the collision is 84.14 m/s.

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Consider the f(x) = Acos(x) function shown in the figure in blue color. What is the value of amplitude A for this function?
As a reference the g(x) = cos(x) function is shown in red color, and green tick marks are drawn at integer multiples of π.

Answers

The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

What is amplitude of a wave?

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

Amplitude of the red colored wave

From the graph, the amplitude of the red colored wave is 1 unit.

Amplitude of the blue colored wave

From the graph, the amplitude of the red colored wave is 2.1 unit.

Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

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Why do batteries discharge more quickly in cold weather?
give me answer
who will give me answer in easy language i will give him 5 star ⭐⭐⭐​

Answers

Answer:

lowering the ambient temperature causes chemical reaction to proceed more slowly,so a battery used in a low temperature produces less current than that at high temperature . As cold batteries run down they quickly reach the point where they cannot deliver enough current to keep up the demand.. hence discharge more quickly in cold weather..

4. Four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m, a 3.00kg object is at +2.50m, a 2.50kg object is at the origin, and a 4.00kg object is at -0.500m. Where is the center of mass of these objects?​

Answers

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

10. Complete each of the following radioactive decay equations.
235U → Th+a
92
90
87
37Rb Sr +
6C

F
e
1¹B ++ie

Answers

1. Alpha

Number next to Th is 231

(because 231 + 4 = 235)

The other number below the 4 is 2 - helium

(because 90 + 2 = 92)

2. Beta

Missing numbers are zero and one. Same as the one below it.

3. Beta

11 is the number above the C

(because 11 + 0 = 11)

5 is the number next to the B

(because 5 + 1 = 6)

Basically, the missing numbers must balance on both side of the equation; creating the elements you've started of with, meaning if you where to add the right side of the equation up - you should end up with the same protons and mass numbers you began with.

Hope this helps!

h) Find the inverse Laplace transforms of the equation. When the X(s) =1 /(s²+9s+20)​

Answers

Answer:

e^-4t e^-5t

Explanation:

solving s²+9s+20 quadratically we have (s+4)(s+5)

x(s) can be written as x(s) =(1/s+4)(1/s+5)

if we take the laplace inversve

L-¹ (s)=L-1(1/s+4) L-1(1/s+5)

we have e^-4t e^-5t

When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) of the loop?

Answers

Radius of the circular loop is 0.0091m.

What is magnetic field?

Magnetic field is the area around a magnet where the magnetism influence is felt .

What is the magnetic field at the centre of a circular loop?The formula for magnetic field at the centre of a loop is

B =(μ)I/2r

where B= Magnetic field at the centre of a circular loop

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))

=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

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Which one of the following statements concerning weight and energy balance is most accurate?

A. People generally need the same amount of physical activity to maintain weight stability.

B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.

C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.

D. The optimal amount of physical activity needed to maintain weight is unclear.

Answer: D. I took the test and got it right

Answers

The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

What is energy balance?

Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.

Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.

So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

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How much heat is required to raise the temperature of 0.210 g of water from 19.2 ∘C to 32.0 ∘C?

Answers

Data:

m = 0.210 g T₀ = 19.2 °C + 273 = 292. 2 KT = 32.0 °C  + 273 =  305 KCe = 4.18 J / GK

We apply the following formula

Q = mcₑΔT

    Q = mcₑ (T - T₀)

We substitute Our data in the formula and solve:

Q = 0.210 g * 4.18 J / g K (305 k - 292.2 k)

Q = 11.23 J

Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

Answers

The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.

Force necessary to support the object

Apply Pascal principle to calculated the force needed to support the mass as shown below;

F₁/A₁ = F₂/A₂

F₁/d₁² = F₂/d₂²

F₁ = F₂d₁²/d₂²

where;

F₂ is the force on piston 2, determined from, F = mgd₂ is the diameter of piston 2, given as 9.46 cmd₁ is diameter of piston 1, given as 1.87 cmF₁ is force on piston 1 = ?

Substitute the given parameters and solve for the  force needed to support the mass given.

F₁ = (991 x 9.8 x 0.0187²)/(0.0946)²

F₁ = 379.5 N

Thus, the force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 379.5 N.

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Why are enthalpy changes always lower than their expected values?
A. They aren't. They are always greater than expected.
B. Heat losses during the experiment
C. Heat gains during the experiment
D. Faulty measurements

Answers

Enthalpy changes are always lower than their expected values due to faulty measurements; option D.

What are enthalpy changes?

Enthalpy changes refers to the changes in the heat content of substances in the course of a reaction.

Enthalpy changes occurs as a result of bond breaking and bond formation in the reactant molecules and product molecules respectively.

Enthalpy change = Energy of bond formation - Energy of bond breakage.

Enthalpy changes are measured from the changes in temperature that are observed in the course of a given reaction.

Due to faulty measurements in a particular experiment measuring enthalpy changes, enthalpy changes are always lower than their expected values.

Therefore, accurate measurements are required if results as close as possible to the actual enthalpy changes are to be obtained.

In conclusion, enthalpy changes measure the heat changes that occur during a particular chemical reaction.

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Your car rides on springs, so it will have a natural frequency of oscillation. (Figure 1) shows data for the amplitude of motion of a car driven at different frequencies. The car is driven at 29 mph over a washboard road with bumps spaced 12 feet apart; the resulting ride is quite bouncy.
1)Determine the frequency of the oscillation, caused by the bumps. 1 mile is 5280 feet.
2)Should the driver speed up or slow down for a smoother ride?

Answers

Answer:

See below

Explanation:

29 mile/hr * 5280 f/mile / 3600  s/hr = 42.53  ft/ sec

   42.53 ft / sec    /   12 feet =  3.54  cycles / sec = 3.54 Hz

      for frequency I suppose....where is the referred to figure?

A 750 kg car is stalled on an icy road during a snowstorm. A 1000 kg car traveling eastbound at 13 m/s collides with the rear of the stalled car. After being hit, the 750 kg car slides on the ice at 4 m/s in a direction 30 ∘ north of east.
A) What is the magnitude of the velocity of the 1000 kg car after the collision?
B) What is the direction of the velocity of the 1000 kg car after the collision?
C) Calculate the ratio of the kinetic energy of the two cars just after the collision to that just before the collision. (You may ignore the effects of friction during the collision.)

Answers

(a) The magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

(b) The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

(c) The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

Velocity of the 1000 kg after the collision

Apply the principle of conservation of linear momentum as follows;

Final velocity in x direction

m₁u₁  +  m₂u₂ = m₁v₁x  +  m₂v₂x

where;

m₁ is mass of 750 kg caru₁ is initial velocity of 750 kg massm₂ is mass of 1000 kg caru₂ is initial velocity of 1000 kg massv₁ is final velocity of 750 kg massv₂ is final velocity of 1000 kg mass

750(0) + 1000(13) = 750(4 cos 30)   +   1000v₂x

13000 = 2,598.1  +   1000v₂x

10,401.9 = 1000v₂x

v₂x  =  10.4 m/s

Final velocity in y direction

m₁u₁  +  m₂u₂ = m₁v₁y  +  m₂v₂y

750(0) + 1000(0) = 750(4 sin 30)   +   1000v₂y

0 = 1500 +  1000v₂y

v₂y  = -1500/1000

v₂y  = -1.5 m/s

Resultant final velocity

v = √(v₂ₓ² + v₂y²)

v = √[(10.4)² + (-1.5)²]

v = 10.5 m/s

Direction of the final velocity of 1000 kg car

tanθ = v₂y/v₂ₓ

tanθ = -1.5/10.4

tanθ =  -0.144

θ = arc tan(-0.144)

θ = 8.2 ⁰ north west

Kinetic energy of the cars before the collision

K.Ei = 0.5m₁u₁²  +  0.5m₂u₂²

K.Ei = 0.5(750)(0)²  +  0.5(1000)(13)²

K.Ei = 84,500 J

Kinetic energy of the cars after the collision

K.Ef = 0.5(750)(4)²  +  0.5(1000)(10.5)²

K.Ef = 61,125 J

Ratio of the kinetic energy

K.Ef/K.Ei = 61,125/84,500

K.Ef/K.Ei = 0.72

Thus, the magnitude of the velocity of the 1000 kg car after the collision is 10.5 m/s.

The direction of the velocity of the 1000 kg car after the collision is 8.2 ⁰ north west.

The ratio of the kinetic energy of the two cars just after the collision to that just before the collision is 0.72.

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Compute your average velocity in the following two cases: (a) You
walk 73.2 m at a speed of 1.22 m/s and then run 13.2 m at a speed
of 3.02 m/s along a straight track. (b) You walk for 1.00 min at a
speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along a
straight track. (c) Graph x versus t for both cases and indicate how
the average velocity is found on the graph.

Answers

(a) Walking 73.2 m at 1.22 m/s would take

[tex]\dfrac{73.2\,\rm m}{1.22 \frac{\rm m}{\rm s}} = 60 \,\rm s[/tex]

and running 13.2 m at 3.02 m/s would take

[tex]\dfrac{13.2\,\rm m}{3.02\frac{\rm m}{\rm s}} \approx 4.37\,\rm s[/tex]

You've undergone a total displacement of 73.2 + 13.2 = 86.4 m in a matter of approximatly 64.37 s, so your average velocity is

[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{86.4\,\mathrm m}{64.37\,\rm s} \approx \boxed{1.34\dfrac{\rm m}{\rm s}}[/tex]

(b) In the first 1.00 min = 60 s, you undergo a displacement of

[tex](60\,\mathrm s) \left(1.22 \dfrac{\rm m}{\rm s}\right) = 73.2 \,\rm m[/tex]

and in the second minute, you undergo a displacement of

[tex](60\,\mathrm s) \left(3.05\dfrac{\rm m}{\rm s}\right) = 183 \,\rm m[/tex]

Your total displacement is then 73.2 + 183 = 256.2 m in a matter of 2.00 min = 120 s, so your average velocity is

[tex]\dfrac{\Delta x}{\Delta t} = \dfrac{256.2\,\mathrm m}{120\,\rm s} \approx \boxed{2.14\dfrac{\rm m}{\rm s}}[/tex]

(c) For part (a), your displacement [tex]x(t)[/tex] (in m) at time [tex]t[/tex] (in s) is given by

[tex]x(t) = \begin{cases}1.22t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.02 (t-60) & \text{for } t > 60\end{cases}[/tex]

and for part (b), your displacement is given by the very similar

[tex]x(t) = \begin{cases}1.22 t & \text{for } 0 \le t \le 60 \\ 73.2 + 3.05(t-60) & \text{for } t > 60 \end{cases}[/tex]

See the attached plots. The average velocity for the given situation is the slope of the dotted line.

What phase of matter is pictured below? Image of particles that are spread out, many are not touching, high energy. A. Gas B. Bose-Einstein condensate C. Fermionic condensate D. Plasma

Answers

Option(d)i.e, Plasma is the Image of particles that are spread out, many are not touching, high energy.

Along with solid, liquid, and gas, plasma is frequently referred to as the "fourth state of matter." Heating a gas will result in the formation of plasma, which is a soup of positively and negatively charged particles (ions), similar to how adding energy causes a liquid to boil and transform into a gas (electrons).

Plasmas are less dense than solids or liquids and, like gases, have no set structure or volume. However, in contrast to regular gases, plasmas are composed of atoms in which part or all of the electrons have been removed and positively charged nuclei, known as ions, are free to move around.

Solids, liquids, gases, ionized plasma, quark-gluon plasma, bose-einstein condensate, and fermionic condensate are the seven states of matter.

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A cell connected to two bulbs in series lasts longer than a cell connected to the same bulbs in parallel.Explain why?

Answers

Because the voltage stays the same while the amps grow, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps quadruple to 100ah, the batteries will last longer. Charges are spread among the bulbs in a parallel circuit because they are flowing in several directions over multiple paths. As a result, each bulb will have less charge since the charge is travelling in multiple directions, and the lights will shine less brightly. On the other hand, in a series circuit, there is only one channel and only one location for the charge to travel, meaning that all of the charge is directed at a single lightbulb. As a result, the lightbulb will shine more brilliantly since there is no need to spread the energy. The rule of conservation of energy is not broken because of the difference in power; instead, smaller resistance causes bigger current, which results in brighter lights. The energy traveling from the source to the bulbs remains constant. Because higher power means that more energy in a given time goes quicker from the source to the bulb, brighter lights require more power rather than energy. Because the energy traveling from the source to the bulbs remains constant, the rule of conservation of energy is not being broken; rather, there is merely a difference in power as a result of smaller resistance leading to bigger current, which will result in brighter lights. This means that brighter lights require more power rather than energy since higher power enables more energy to go from the source to the bulb more quickly.

Thank you,

Eddie

The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.70 m and 1.03 m, respectively. The respective rotational speeds are 449 rev/min and 4,150 rev/min. Calculate the speeds of the tips of both rotors.

main rotor ______m/s
tail rotor _______m/s

Compare these speeds with the speed of sound, 343 m/s.

vmain rotor = _______ vsound
vtail rotor = _______ vsound

Answers

(a) The speeds of the tips of both rotors; main rotor 181.02 m/s and  tail rotor 223.8 m/s.

(b) The speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.

Linear speed of main motor and tail rotor

v = ωr

where;

ω is the angular speed (rad/s)r is radius (m)

v(main rotor) = (449 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.7 m)

v(main rotor) = 181.02 m/s

v(tail rotor) = (4,150 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.03 m)

v(tail rotor) = 223.8 m/s

Speed of the rotors with respect to speed of sound

% speed (main motor) = 181.02/343 = 0.528 = 52.8 %

% speed (tail motor) = 223.8/343 = 0.652 = 65.2 %

Thus, the speed of the main rotor is 52.8 % speed of sound, and the speed of the tail rotor is 65.2 % speed of sound.

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[tex] \large{\rm{Question:}}[/tex]

Give one example where the displacement is zero but the distance traveled is not zero.

Answers

Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.

Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.

Example:

Imagine a person walks 10 meters forward and then turns around and walks 10 meters back to the starting point. In this case, the displacement is zero (starting point to ending point), but the distance traveled is 20 meters (10 meters forward + 10 meters backward).

If the gravitational potential energy of an object 10 m above the ground is 50 J, what is its Ep, if it moves to 30 m above the ground?​

Answers

Answer:

150 J

Explanation:

Moving 3 times higher will increase the   P E  x 3   = 150 J

ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A. If the acceleration of the system is 5.88m/s2, what is the Tension T on Box A?

Answers

The tension on box A is 117.6 N

What is Equilibrium of Forces ?

Equilibrium is a state of an object with respect to a given observable quantity during the time for which there is no change in that quantity.

A body is said to be in equilibrium when:

the body as a whole either remains at rest or moves in a straight line with constant speed.the body is either not rotating at all or is rotating at a constant angular velocity.

Given that box A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A.

The tension in the rope will be the same.

Given that Box A is placed on a horizontal surface that is frictionless, that is,

T = ma .... (1)

Also,  Box B is hanging from a pulley by a rope connected to Box A. That is,

W - T = ma ...... (2)

Where W = mg

Since the acceleration of the system is 5.88m/s² which will be the same for the two equations, then the Tension T on Box A can be calculated by substituting acceleration and mass into equation (1)

T = 20 x 5.88

T = 117.6 N

Therefore, the tension on box A is 117.6 N

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the earth orbits is oval in shape.explain how the mangnitude of gravitational between the earth and sun changes as the eart moves from position a to b

Answers

As the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.

What is gravitational force?

Gravitational force is a force that attracts any two objects with mass.

According to Newton's law of universal gravitation, the force of attraction between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.

F = Gm₁m₂/R²

where;

m₁ is mass of Earthm₂ is mass of sunR is the distance between the Earth and Sun

Thus, as the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.

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how to calculate the half time​

Answers

The formular for calculating half life is:

T1/2=0.693/Π

Solve this question please A.S.A.P ⁉️
No spamming ❗​

Answers

Answer:

Here given is :-

Velocity (u) = 10m/sGravity (g) = 10 m/s²Height (h) = ?

Explanation:

v² - u² = 2gh

0² - 10² = 2 × (-10) × h

-100 = -20 h

[tex]h = \frac{ - 100}{ - 20} = 5m[/tex]V = u + gt0 = 10 - 10t10t = 10[tex]t = \frac{10}{10} = 1 \: sec[/tex]Total time = 2 sec

Answer:

See below

Explanation:

vf = vo + at        when it reaches top vf = 0    vo = 10m/s      a = -9.81 m/s^2

0 =   10  + (-9.81) t  

t = 1.02 seconds to reach max

time up = time down   so    roundtrip =  2.04 seconds

A container with 3 kg of pure water at a temperature of 12 degrees Celsius is placed in a refrigerator where the air temperature is kept at 4 degrees Celsius. how much heat (in joules) is gained by the air when the water cools to 4 degrees Celsius?

Answers

Answer:

100 368 J

Explanation:

Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)

specific heat for water ( in joules) :  4182 J / kg-C

    3 kg *  4182 J / kg-C  * (12-4 C) = 100 368 J

How does the suns energy affect the climate of an area

Answers

There wouldn't be any life on Earth and no climate if it weren't for the Sun.

The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.

The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.

Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.

In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.

Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).

Thank you,

Eddie

The Sun is the only source of energy for the Earth's climate system. Important to earth's atmosphere is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

A tree limb is blown loose from a tree during a storm. As it falls, it gains
speed. Which type of energy is the tree limb gaining as it falls?
O A. Kinetic energy
B. Gravitational potential energy
O C. Nuclear energy
OD. Light energy

Answers

Answer:

B Gravitational potential energy

Explanation:

what does personal mission statement?

Answers

Answer:

A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.

Explanation:

It explains how you aim to pursue that purpose, and why it matters so much to you.

the highest theoretical efficiency of a certain engine is 30% if the engine uses the atmosphere which has a temperature of 300k as its cold reservoir what is temperature of its hot reservoir

Answers

The temperature of its hot reservoir would be = 210k

Calculation of reservoir temperature

The highest theoretical engine efficiency (η)= 30% =0.3

The temperature of the engine cold reservoir (T1)= 300k

Therefore the temperature of the engine hot reservoir (T2) = ?

Using this formula:

η=1- T2/T1

Make T2 the subject formula:

T2= T1 (1 - η)

T2 = 300 ( 1-0.3)

T2 = 300 × 0.7

T2 = 210k

Therefore, the temperature of its hot reservoir would be = 210K.

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