The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
Dilution formulaM₁V₁ = M₂V₂
Where
M₁ is the molarity of stock solution V₁ is the volume of stock solution M₂ is the molarity of diluted solution V₂ is the volume of diluted solution Data obtained from the question Molarity of stock solution (M₁) = 24.7 mol/LVolume of diluted solution (V₂) = 8 LMolarity of diluted solution (M₂) = 10 mol/L Volume of stock solution needed (V₁) = ?How to determine the volume neededThe volume of the methanol necessary to prepare the solution can be obtained as illustrated below:
M₁V₁ = M₂V₂
24.7 × V₁ = 10 × 8
24.7 × V₁= 80
Divide both side by 24.7
V₁ = 80 / 24.7
V₁ = 3.2 L
Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
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When an electron in a quantum system drops from a higher energy level to a lower one, the system __
When an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.
The energy of the electron drops when it transitions levels, as well as the atom releases photons. The emission of the photon occurs as the electron transitions from an energy state to a lower state. The photon energy represents precisely the energy that would be lost when an electron moves to a level with less energy.
When such an excited electron transitions from one energy level to another, this could emit a photon. The energy drop would be equivalent to the power of the photon that is released. In electron volts, the energy of an electron, as well as its associated photon (emitted or absorbed) has been stated.
Therefore, when an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.
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the graph below shows a reaction with a catalyst. How did the addition of the cataalyst change the graph
Answer:
Section 2 will decrease.
Explanation:
A catalyst is a substance that increases the rate of the chemical reaction without taking part in the overall reaction. Catalysts speed up a reaction by lowering the activation energy needed for a reaction to take place. The activation energy is the minimum energy necessary for a reaction to take place. As such, when a catalyst is added, the activation energy (or the potential energy) needed to start the reaction decreases. This shows itself in the graph by decreasing the "hump" in Section 2.
It should be noted that Sections 1 and 3 will remain the same. This is because the energy of the reactants and products does not change regardless of a catalyst being present.
How many moles of iron iii oxide can be prepared from 6 moles of oxygen?
Answer:
6molO2 3/2O22Fe=4,5024molFe .
Explanation:
You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.
2Fe(s)+3/2O2(g) Fe2O3(s)
If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.
Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.
6molO2 3/2O22Fe=4.5024molFe .
These coefficients can be used as conversion factors when it comes to substance moles.
Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.
But, just for the argument, let’s rebalance the equation for integer coefficients only.
4Fe(s)+3O2(g) 2Fe2O3(s)
We are now using the coefficients as conversion factors, as we have done before.
Draw the mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute hcl
The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.
What is Proton Transfer ?In the first step oxygen donates its lone pair of electron to hydrogen of HCl. There is removal of water molecule from the substance α-d-glucose.
What is Nucleophilic Substitution ?The organic reaction where one nucleophile replaces another is called nucleophilic substitution reaction. These reaction takes place in aromatic compounds, acyl compounds and aliphatic compounds. SN¹ reactions are nucleophilic substitution reaction.
Thus from the above conclusion we can say that The mechanism for the interconversion of α-d-glucose and β-d-glucose in dilute HCl include the proton transfer in first step and nucleophilic attack in second step.
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Explain how the rate of diffusion of a gas is related to its molar mass.
carbon dioxide gas (co2) effuses 3.2 times faster than an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.
The molar mass of the other gas is 450.56 g.
Calculation:
Relation between rate of diffusion and molar mass of two gases is given by:
r₁/r₂ = (√m₂)/(√m₁)
Given,
r₁ = 3.2r₂
(r₁ is the diffusion rate of CO₂ and r₂ is the diffusion rate of the other gas)
We know
m₁ = molar mass of CO₂ = 44 g
To find,
m₂ = molar mass of the other gas =?
Put the values in the above equation,
r₁/r₂ = (√m₂)/(√m₁)
3.2r₂/r₂ = (√m₂)/(√44)
3.2 = (√m₂)/(√44)
Squaring both the sides,
10.24 = m₂/44
m₂ = 10.24 (44)
m₂ = 450.56 g
Hence, the molar mass of the other gas is 450.56 g.
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If a buffer is composed of 34. 63 ml of 0. 139 m acetic acid and 36. 50 ml of 0. 182 m sodium acetate, how many ml of 0. 100 m hcl can be added before the buffer capacity is reached?
The volume is the product of the molar concentration and the moles of the substance. The volume of hydrochloric acid that can be added to the buffer is 0.066 L.
What is a buffer?A buffer is a constant solution with a proton or hydrogen ion concentration with an acid, base, or salt dissolved in them.
The chemical reaction between hydrochloric acid and sodium acetate is given as,
HCl + CH₃Coo-Na → CH₃CooH + NaCl
From above the initials moles of acetic acid are given as,
Moles = molarity × volume
= 0.139 M × 0.0346 L
= 0.0048 moles
The initials moles of sodium acetate are given as,
M = 0.182 M × 0.0365 L
= 0.0066 moles
As it is known that the ratio of the buffer capacity is 10 for sodium acetate and acetic acid so,
Moles sodium acetate ÷ Moles Acetic acid = 10
(0.0066 moles + X) ÷ (0.0048 moles - X) = 10
Here, X is the moles of HCl and is calculated as,
0.0066 moles + X = 0.048 moles - 10X
11 X = 0.048 ÷ 0.0066
11 X = 7.27
X = 0.66 moles
The volume of 0.100 HCl with 0.66 moles is:
Volume = moles × molarity
= 0.100 × 0.66
= 0.066 L
Therefore, 0.066 L of 0.100 M HCl is required to reach the buffer capacity.
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Isotopes have question 2 options: a) a different number of neutrons in their nuclei. b) a different number of protons in their nuclei. c) a different number of electrons. d) different numbers of both protons and neutrons in their nuclei.
Answer:
A
Explanation:
Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.
Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.
Write the formula for: strontium carbonate
what is metallic conductivity ?
Explanation:
metallic conduction:the movement of electrons through a metal, with no changes in the metal and no movement of the metal atoms.
I hope this help uuhh............
What is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided?
Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.
What is Empirical Formula ?The Empirical formula is the simplest whole number ratio of atoms present in given compound.
What is Molecular formula of Compound ?Molecular Formula = Empirical Formula × n
n = [tex]\frac{\text{Molar Mass}}{\text{Empirical Formula weight}}[/tex]
Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.
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A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.
Molarity of the solution is 0.0527 M.
What is Molarity?The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.
Calculation of Molarity of the solutionAssume there is 1 kg of solvent present in the beginning.
Thus, the mole of solute is 0.0480 moles of LiF.
Molar mass of LiF = 25.939 grams/mole
0.0480 mol LiF x 25.939 g/1 mol LiF = 1.245 g LiF
Mass of the solution = 1001.245 g
The molarity of the solution can be determined as illustrated using the supplied density and moles of solute.
[LiF] = mol LiF/ volume of solution
[LiF] = 0.0480 mol/1001.245 g x 1ml/1.10g x 1L/1000mL
Hence, the molarity of LiF = 0.0527 M
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If 0. 5371 g of zn was plated onto an electrode, how much charge (in coulombs) was used to reduce the zn2+ to zn(s)?
The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.
What is electrolysis?The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.
The reaction of reduction of Zn can be given as:
Zn²⁺ + 2e⁻ → Zn (s)
Molar mass of Zn = 65.39 g
The equivalent of Zn²⁺ has been:
Equivalent = atomic mass/equivalent weight
Equivalent Zn²⁺ = 65.39/32.69
Equivalent Zn²⁺ = 2 mol
1 equivalent = 1 F charge used
2 mol equivalent = 2 F charge used
Charge in coulomb can be given as:
1 Faraday = 96500 coulomb
2 F = 96500 * 2 coulomb
2 F = 1,93,000 coulomb
The moles of Zn to be deposited is:
Moles = weight /molar weight
Moles = 0.5371 g/ 65.39 g/mol
Moles = 0.00821 mol
Therefore, the charge used for the deposition of 0.00821 mol is:
Charge = 0.00821 * 1,93,000 coulomb
Charge = 1585.26 coulomb
1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.
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Compute the theoretical density of zns given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively? The atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol.
Density of ZnS given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively if the atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol. is 4.1109 g/cm³
For density In the crystal structure, we determine the angle's value for one set of ZnS bonds. θ θ + ∅ + 90° = 180° θ = 90° - ∅ θ = 90° - (109.5° / 2) After determining that = 35.25°, we derive the value of x from the geometry: distance angle d = 0.234 x = dsin = 0.234 sin35.25°) = 0.135 nm = 0.135 107 cm; following this, we get the length of the unit cell: a = 4x a = 4(0.135) a = 0.54 nm = 0.54 107 cm; and The formula for n' is (number of corner atoms in unit ell contribution of each corner atom in unit cell) + (number of face center atoms in unit cell contribution of each face center atom in unit cell). n' = 8 × 1/8) + (6 × 1/2) = 1 + 3 = 4
Density = P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)] = 389.88 / 94.84 = 4.1109 g/cm³
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The process where a substance goes directly from a solid state to a gaseous form is known as:____.
Answer:
sublimation because it's has changed from solid to gaseous
Ulfuric acid is found in some types of batteries. What volume of 3.50 m h2so4 is required to prepare 250.0 ml of 1.25 m h2so4?
The volume sulfuric acid will be 89.3mL.
Volume will be determined by the molarity relation. The quantity of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a component per liter of a solution would be known as molarity. The molar concentration of any solution would be another name for molarity.
The volume can be calculated by using molarity formula:
[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]
Given data:
[tex]M_{1}[/tex] = 3.50 m
[tex]M_{2}[/tex] = 1.25 m
[tex]V_{1}[/tex]= 250.0 ml
Put the value of given data in above formula:
[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]
( 3.50 m) ( 250 mL) = ( 1.25 m) [tex]V_{2}[/tex]
[tex]V_{2}[/tex] = 89.3mL
Therefore, the volume sulfuric acid will be 89.3mL.
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Compared with the energy it takes to separate oxygen and hydrogen from water, how much energy is released when they recombine?.
The same amount of energy released when they recombine
Yes, the energy required to separate water into O2 and H2 is at least equal to the energy released when these gases come together to form water.
What is the process for separating water into it's constituents ?The process of separating water into hydrogen and oxygen is known as electrolysis. This reaction occurs in a device known as an electrolyzer.
This is around 260 kJ per mole of water, or just under 5 eV per water molecule (4 electrons times 1.23 V). One litre of water would require at least 16 MJ (4.4 kWh) in order to be split, which is more energy than would be required to send one litre of water into deep space.Learn more about Electrolysis here:
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If 30. 0 ml of 0. 150 m CaCl2 is added to 15. 0 ml of 0. 100 m AgNo3, what is the mass in grams of AgCl precipitate?
The mass of AgCl precipitated is 0.215g.
What do you mean by precipitation?Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.
To calculate mass of AgCl precipitate -
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01g/mol
AgCl= 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
mole CaCl2 = 30/1000 x 0.2 =0.006
mole AgNO3 =15/1000 x 0.1 = 0.0015
CaCl2 is in excess so 0.0015 mole AgCl will form
0.0015 x 143.5 = 0.215g
The 0.215 mass in grams of AgCl will precipitate.
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In a combustion chamber, ethane (c2h6) is burned at a rate of 9 kg/h with air that enters the combustion chamber at a rate of 176 kg/h. determine the percentage of excess air used during this process
The percentage of excess air used during combustion process of ethane will be 37 %.
Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.
Calculation of percentage of air .
[tex]C_{2} H_{6} + (1-x)+a(O_{2} +3.76N_{2} )=bCO_{2} + cH_{2} O + axO_{2} + 3.76dN_{2} .[/tex]
Mair=Mair/Rin
[tex]( MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex]÷ [tex](MN)O_{2}[/tex] + [tex](MN)N_{2}[/tex] +[tex](MN)C_{2} H_{6} .[/tex]
33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1
= 176/176+8
X= 0.37
0.37 × 100
X= 37%
Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.
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Draw the highest energy transition state in the solvolysis of (ch3)3c-i in ch3oh
The highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given as ,
The mechanism of solvolysis of tert-butyl iodide follow nucleophilic substitution reaction . The nucleophilc substitution reaction are two types one unimolecular and second bimolecular nucleophilc substitution .
The mechanism of solvolysis of tert-butyl iodide follows unimolecular nucleophilic substitution reaction in which carbocation is the intermediate which as a transition state of it. The carbocation formed by solvolysis of tert-butyl iodide is 3° carbocation or tertiary carbocation which is most stable. The methanol as neutral nucleophile and oxygen of methanol attack at carbocation intermediate.
Therefore , the highest energy transition state in the solvolysis of [tex](CH_{3} )_{3} CI[/tex] in [tex]CH_{3} OH[/tex] is given .
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8.0 liters I2 forms at STP. How many moles of KI were required for the reaction?
Answer:
0.71 moles KI
Explanation:
At STP, there should be 1.0 moles at 22.4 L. However, there are only 8.0 L of I₂. Therefore, we must set up a proportion to find the correct moles of I₂.
[tex]\frac{1 mole}{22.4 L} =\frac{? moles}{8.0 L}[/tex] <----- Proportion
[tex]8.0 = 22.4(? moles)[/tex] <----- Cross multiply
[tex]0.36 = ? moles[/tex] <----- Divide both sides by 22.4
To find the moles of KI, you can use the mole-to-mole ratio from the balanced equation coefficients. The final answer should have 2 sig figs.
2 KI(aq) + Cl₂(g) ---> 2KCl(aq) + 1 I₂(g)
^ ^
0.36 moles I₂ 2 moles KI
---------------------- x -------------------- = 0.71 moles KI
1 mole I₂
Answer: 0.71 moles KI
Explanation:
16. If the velocity of hydrogen molecule is 5 x 10^4cm sec-¹, then its de Broglie wavelength is
(1)2 A
(2) 4 A
(3)8 A
(4) 100 A
Answer:
Correct option is B)
According to de-Broglie,
λ=mvh=6.023×10232×5×104cm/sec6.62×10−27ergsec=4×10−8cm=4Ao
Which of the given ions have the same ground state electron configuration: s2-, n3-, mg2 , and br-? a. s2-, n3-, mg2 , and br- b. s2-, n3-, and br- c. n3- and mg2 d. s2- and br- e. mg2 and br-
N3- and Mg2 ions have the same ground-state electron configuration.
Ground-state electron configuration:Understanding molecule bonding, characteristics, and structures begin with understanding ground state electron configurations. The ground state electron configuration provides insight into a wide range of atomic properties, including the electrons in an atom, distinct orbitals, and hybridization.
The ground state of an atom's electrons is the lowest energy state that is feasible for that atom since, throughout the cosmos, a system's natural state is to use the least amount of energy.
Aufbau-Principle: If you have a lot of luggage, you'll probably choose the room that is closest to the ground floor in a hotel without an elevator. The Aufbau principle demonstrates the identical behavior of electrons in the ground state. According to the Aufbau principle, electrons first occupy lower energy orbitals before moving on to higher energy orbitals.
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How much energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°c and completely vaporize the sample?
The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.
Calculation,
Given data,
Mass of the ice = 10 g
Temperature of ice = 0. 0°C
The ice at 0. 0°C is to be converted into water at 0. 0°CHeat required at this stage = mas of the ice ×latent heat of fusion of ice
Heat required at this stage = 10 g×80 = 800 cal
The temperature of the water is to be increased from 0. 0°C to 100. 0°CHeat required for this = mass of the ice×rise in temperature×specific heat of water
Heat required for this = 10 g×100× 1 = 1000 cal
This water at 100. 0°C is to be converted into vapor.Heat required for this = Mass of water× latent heat
Heat required for this = 10g ×536 =5360 cal
Total energy or heat required = sum of all heat = 800 +1000+ 5360 = 7160 cal
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Identify the classification of milk. group of answer choices aerosol solid aerosol foam emulsion solid emulsion
Milk is an example of solid emulsion. Hence, option D is correct.
What is emulsion?An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.
Emulsion consist of a dispersion of two liquids that are immiscible with each other.
One of the liquids act as the dispersion medium and the other will act as the dispersed phase.
Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.
Types of Emulsion:
Oil in water (O/W)In this type of emulsion, the oil will be the dispersed phase and water will be the dispersion medium. Example of o/w emulsion is milk.2. Water in oil (W/O)
In this type, water will be the dispersed phase and oil will be the dispersion medium. Margarine is an example of water in oil emulsion.Milk is an example of solid emulsion. Hence, option D is correct.
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An aqueous solution of hso−3 is created at 25∘c. is the solution acidic, basic, or neutral?
An aqueous solution of hso−3 is created at 25∘c. is the solution basic in nature.
An aqueous solution is a solution wherein the solvent is water. Its miles are primarily shown in chemical equations by appending them to the relevant chemical formula.
An aqueous solution is a water that carries one or more dissolved materials. The dissolved substances in an aqueous answer can be solids, gases, or different beverages.
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At 25°C, an aqueous solution of hso3 is formed. This is the solution basic in nature.
Aqueous solutions are those in which the solvent is water. Its miles are often represented in chemical equations by attaching them to the appropriate chemical formula.
An aqueous solution is a mixture of water and one or more dissolved components. Solids, gases, or various beverages can be dissolved in an aqueous solution.
Aqueous solutions contain liquid water as the solvent. Solute (dissolved) ions and molecules are surrounded by water molecules and absorbed into the water's network of bonds. After then, the dissolved species diffused throughout the water.
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A gas sample at stp contains 1. 20 g oxygen and 1. 43 g nitrogen. what is the volume of the gas sample?
The volume of the gas sample will be 1.79 L.
A liquid, solid, or gas's volume represents the amount of three-dimensional space it occupies. Although there are many additional units that can be used to indicate volume, the most used ones are liters, cubic meters, gallons, milliliters, teaspoons, as well as ounces.
Given data :
Mass of [tex]O_{2}[/tex] = 1.20 g
Mass of [tex]N_{2}[/tex] = 1.43 g
Number of moles can be calculated by suing the formula:
Number of moles of [tex]O_{2}[/tex] = Mass / molar mass = 1.20 / 32 = 0.03 mol
Number of moles of [tex]N_{2}[/tex] = Mass / molar mass = 1.43 / 28 = 0.05 mol
So, the total count of moles can be calculated by :
Total moles = moles of [tex]O_{2}[/tex] + moles of [tex]N_{2}[/tex]
Total moles = 0.03 + 0.05 = 0.08 mol
The volume of the gas at STP can be calculated as:
Volume = 0.08 mol × 22.4 mol/L
Volume = 1.79 L
Therefore, the volume of the gas sample will be 1.79 L.
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The iodine test is used to test for the presence of starch which is a type of ___________ treated with an iodine solution, the starch reacts with the iodine solution and produces a ___________ color.
A. protein, blue-purple
B. protein, yellow
C. carbohydrate, yellow
D carbohydrate, blue-purple
When
Answer:
D. carbohydrate, blue-purple
Explanation:
Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.
When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.
Place the following in order of increasing dipole moment. I. Bcl3 ii. Bif2 iii. Bclf2.
The correct order of increasing dipole moment is BCl3 < BIF2 < BClF2.
What is dipole moment?
The mathematical product of the separation of the ends of a dipole and the magnitude of the charges.More is the electronegativity of an atom more it will have pull of electrons towards itself. For example, in BCl3 electrons will be pulled towards chlorine atom as it is more electronegative than boron.Hence, the dipole moment is cancelled out. So, it will have zero dipole moment. In BIF2 and BClF2 , fluorine is more electronegative in nature and it is present in both the molecules.But chlorine is more electronegative that iodine atom. So, the dipole moment of BClF2 is more than the dipole moment of BIF2.To learn more about dipole moments: https://brainly.com/question/14355450
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When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about ____ above the nail wraps.
When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about fully covered above the nail wraps.
What is nail wraps?Nail wraps, often known as nail paint strips, are nail improvements with printed patterns, glitter, or solid colors. Without the use of glue, they are attached to the nail in a flexible strip. There may be 12 to 22 various sized strips per box, depending on the manufacturer, which takes into account the range in size of each person's fingernail.
Nail wraps have a long history that dates back to the 1980s. The popularity of nail polish and the rise in salon visits gave rise to the demand for a better at-home manicure. Although several companies produced nail wraps and polish strips, it wasn't until the 2000s that they truly started to catch popularity. Since then, their appeal has increased.
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What is the total pressure exerted by a mixture of 48.0 grams of CH4 and 56.0 grams of
hydrogen gas when confined in a volume of 15.0 liters at 13°C.
The pressure of the gas is obtained as 48 atm.
What is the total pressure?Now we know that;
Number of moles of CH4 = 48.0 grams /16 g/mol = 3 moles
Number of moles of H2 = 56.0 grams/2 g/mol = 28 moles
Total number of moles present = 3 moles + 28 moles = 31 moles
Using;
PV =nRT
P = total pressure
V = total volume
n = total number of moles
R = gas constant
T = temperature
P = nRT/V
P = 31 * 0.082 * 286/15
P = 48 atm
Learn more about pressure of a gas:https://brainly.com/question/18124975
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