Answer:
Mean:36
Median:27
Mode:27
Range:50
Step-by-step explanation:
Mean: 19+26+27+27+30+53+69/7=36
Median: The middle number in the sequence when arranged in ascending order which is 27
Mode: The number that appeared more than others which is 27
Range: This is the difference between the largest number and the lowest number in the sequence which is 50.
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Given that the following two triangles are similar find x
Answer:
20 cm
Step-by-step explanation:
When two triangles are similar, they're just dilated by a certain scale factor. In other words, each side is multiplied by the same value to create the similar triangle.
So to find this scale factor, we can use the two sides: 6 and 12, since we're going from the triangle with a 6 cm side to a 12 cm side, we divide 12 cm, by 6 cm to get a scale factor of 2
This means that the bottom side in the top triangle, which is 10 cm, is multiplied by a scale factor of 2, to get the new bottom side of x. So to find x, we simply multiply 10 cm by 2 to get 20 cm
Use the equation to complete an algebraic proof that proves the answer is x = 7/6. Write your proof in your journal and upload your answer. You will be awarded 5 points for the statements and 5 points for the reasons.
I need the algebraic proofs please!!!
Using the algebraic equation, (2x + 6)/5 = 4x - 3, it has been proved that x = 7/6
Algebraic Proof for the Given Algebraic Equation
The given algebraic equation is,
(2x + 6)/5 = 4x - 3
2x + 6 = 5(4x - 3)
2x + 6 = 20x - 15
20x - 15 = 2x + 6
This algebraic equation can be written as,
20x - 2x - 15 = 6
18x = 15 + 6
18x = 21
x = 21/18
x = 7/6
Hence, using the given algebraic equation, it has been proved that the value of x is 7/6.
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A skateboard halfpipe is being designed for a competition. the halfpipe will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground. using the ground as the x-axis, where should the base of the halfpipe be positioned? which equation best describes the equation of the halfpipe?
The equation of parabola is given by
(X-h)^2 = 4p(Y-k)^2
2p = 30 - 0
p = 15
4p = 4 × 15
= 60
In this case h = 0
So, we have (h,p) = (0,15)
So we get
We have equation: x^2 = 60(y-15)
y = x^2 / 60 + 15
What is a parabola?A parabola is nothing but a U-shaped plane curve. Any point on the parabola is equidistant from a fixed point called the focus and a fixed straight line known as the directrix. The general equation of a parabola is: y = a(x-h)2 + k or x = a(y-k)2 +h, where (h,k) denotes the vertex. The standard equation of a regular parabola is y2 = 4ax. Some of the important terms below are helpful to understand the features and parts of a parabola. Focus: The point (a, 0) is the focus of the parabola.
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Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X. Arc X Z is 105 degrees and arc W Z is 175 degrees.
In the diagram of circle A, what is the measure of ∠XYZ?
35°
70°
75°
140°
Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X. Arc X Z is 105 degrees and arc W Z is 175 degrees.
In the diagram of circle A, what is the measure of ∠XYZ?
35°
70°
75°
140°
By applying the theorem of intersecting secants, the measure of angle XYZ is equal to: A. 35°.
How to determine angle <XYZ?By critically observing the geometric shapes shown in the image attached below, we can deduce that they obey the theorem of intersecting secants.
What is the theorem of intersecting secants?The theorem of intersecting secants states that when two (2) lines intersect outside a circle, the measure of the angle formed by these lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.
By applying the theorem of intersecting secants, angle XYZ will be given by this formula:
<XYZ = ½ × (m<WZ - m<XZ)
Substituting the given parameters into the formula, we have;
<XYZ = ½ × (175 - 105)
<XYZ = ½ × 70
<XYZ = 35°.
By applying the theorem of intersecting secants, we can infer and logically deduce that the measure of angle XYZ is equal to 35°.
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Answer: 35
Step-by-step explanation:
Prove that the number A= [tex]20^{8^{2014} } }+113 is composite
Cheese proof:
We can just prove that it is divisible by 3, which means that it is composite. We can use modular exponentiation, where if [tex]a \equiv b \pmod{n}[/tex] then [tex]a^x \equiv b^x \pmod{n}[/tex]. In this case, [tex]{-1}^{8^{2014}} \equiv 20^{8^{2014}} \pmod{3}[/tex]. This is much easier to calculate! Since [tex]8^{2014}[/tex] is even, [tex]-1^{8^{2014}}=1[/tex], meaning that now we only need to prove that [tex]0\equiv(1+113) \pmod{3}[/tex], which is obviously true.
Find the area of the blue shape below. Use 3.14 for π
If anyone knows the answer please help!
Answer:
1413.86 ft^2.
Step-by-step explanation:
The diameter of the circle = 50 - 2(18)
= 50-36
= 14 ft.
So its radius is 7 ft.
The total area of the blue shape
= 2(35 * 18) + 3.14*7^2
= 1413.86 ft^2.
A tailor needs meters of cloth to make a poncho. How many meters does he need to make 15 ponchos of the same size?
Answer:
15 mister of cloths are needed to make 15 m if 1 puchu is 1 miter
Answer:15 meters
step by step explanation
(2x² – 3x)(3x² + 2x - 1)
Answer:
6x^4-5x^3-8x^2+3x
Step-by-step explanation:
-factor it using FOIL (first outside inside last)
I thought of the number that is between 104 and 140. The number is divisible by 6 and 15. What is my number?
Answer:
120
Step-by-step explanation:
Lets find the numbers multiples of 6 that are in the range from 104-140:
108, 114, 120, 126, 132, 138
Now out of these lets find which is divisible by 15
[tex]\frac{108}{15}=7.2\\\\\frac{114}{15}=7.6\\\\\frac{120}{15}=8\\\\\frac{126}{15}=8.4\\\\\frac{132}{15}=8.8\\\\\frac{138}{15}=9.2[/tex]
120 Is the only solution in this set which is also equally divisible by 15, making it the answer.
please solve by BODMAS rule
Answer:
Step-by-step explanation:
1/3 + 1/3 x 1/3 / 1/3 - 1/3
= 1/3 + 1/3 x 1/1 -1/3
= 1/3 + 1/3 - 1/3
= 2/3 - 1/3
= 1/3
Answer:
5/9.
Step-by-step explanation:
1/3 + 1/3 * 1/3 / 1/3 - 1/3 * 1/3
= 1/3 + 1/3 * 1 - 1/3 * 1/3
= 1/3 + 1/3 - 1/3 * 1/3
= 2/3 - 1/9
= 5/9.
There are 6 dogs and 5 cats.
In how many different orders can these animals be placed in line if any animal can be next to any other animal?
In how many different orders can these animals be placed in line if the dogs and cats are lined up alternately?
(Hint - The first animal MUST be a dog)
In how many different orders can these animals be placed in line if the first and last animal in line must be a cat?
Using the arrangements formula, the number of orders is given as follows:
39,916,800 if no restrictions.86,400 if they are lined up alternatively.7,257,600 if the first and last must be cats.What is the arrangements formula?The number of possible arrangements of n elements is given by the factorial of n, that is:
[tex]A_n = n![/tex]
When there are no restrictions, the number of ways is:
[tex]A_{11} = 11! = 39,916,800[/tex]
When they must be lined alternatively, the 6 dogs can be arranged in 6! ways, and the 5 cats in 5! ways, hence the number of orders is:
[tex]A_6A_5 = 6! \times 5! = 86,400[/tex]
When the first and last are cats, we have that:
For the first and last animals, there are 5!/2! = 20 ways.For the middle 9 animals, there are 9! ways.Hence:
20 x 9! = 7,257,600.
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(06.01 mc) what is the value of the expression 9 (fraction 1 over 2)4 ⋅ 48? 12 15 17 18
The value of the given expression is 105.
What are expressions?An expression or mathematical expression is a finite combination of symbols that is well-formed according to context-dependent norms. To help identify the sequence of operations and other features of logical syntax, mathematical symbols can denote numbers (constants), variables, operations, functions, brackets, punctuation, and grouping.To find the value of the given expression:
Given function - 9 + (fraction 1 over 2)4 ⋅ 48Let, 9 + 1/2 ⋅ 4 ⋅ 48.Follow the PEMDAS order of operations:
Multiply and divide (left to right).
1/2 ⋅ 4 ⋅ 48 = 96 9 + 1/2 ⋅ 4 ⋅ 48 = 9 + 96Add and subtract (left to right)
9 + 96 = 105Therefore, the value of the given expression is 105.
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The area of the trapezoid is 40 square units.
A trapezoid is shown. The lengths of the bases are 6 and 10, and the height of the altitude is h.
What is the height of the trapezoid?
3 units
5 units
10 units
12 units
The altitude of the trapezoid, based on the given parameters is 5 units
How to determine the height of the trapezoid?From the question, we have the following parameters about the trapezoid
Base length 1 of the trapezoid = 6
Base length 2 of the trapezoid = 10
Area of the trapezoid = 40
Altitude of the trapezoid = h
The area of the trapezoid is calculated using
Area = 0.5 * (Sum of the two base lengths) * Altitude of the trapezoid
Substitute the given parameters in the above formula
40 = 0.5 * (6 + 10) * h
Evaluate the sum of 6 ad 10 (do not approximate)
40 = 0.5 * (16) * h
Evaluate the product of 0.5 and 16 (do not approximate)
40 = 8 * h
Divide both sides by 8 (do not approximate)
h = 5
Hence, the altitude of the trapezoid, based on the given parameters is 5 units
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Answer:
5 units
Step-by-step explanation:
What are the zeros of the polynomial function: f(x) = x^3 - x^2 – 6x ?
Answer:
x=0, x=3, x=-2
Step-by-step explanation:
factor the equation
x(x^2-x-6)
factor more
x(x-3)(x+2)
set it equal to 0
x(x-3)(x+2)=0
plug in numbers for x that would result in the answer being 0
0(0-3)(0+2)=0
3(3-3)(3+2)=0
-2(-2-3)(-2+2)=0
Are these lines perpendicular, parallel, or neither based off their slopes?
6x - 2y = -2
y = 3x + 12
Answer:
parallel
Step-by-step explanation:
//
Answer: these lines are parallel.
Step-by-step explanation:
[tex]\displaystyle\\\left \{ {{6x-2y=-2} \atop {y=3x+12}} \right. \\\\ \left \{ {{6x-2y+2=0} \atop {y=3x+12}} \right. \\\\ \left \{ {{6x+2=2y\ |:2} \atop {x=2}} \right. \\\\\left \{ {{3x+1=y} \atop {y=3x+12}} \right.\\ \\\left \{ {{y=3x+1} \atop {y=3x+12}} \right. \\So,\ these\ lines\ are\ parallel.[/tex]
for each reasons it gives you the options to choose: commutative property of addition, associative property of addition, distributive property, and combining like terms
Answer:
associative
combining
commutative
Step-by-step explanation:
1. associative property of addition since the grouping is changed
2. combining like terms since it's the addition of 4 and 6
3. commutative property of addition since it's a change of order
Three lorries each making five trips per day transport 2500 crates from a factory to a distributor in two days .how many lorries each making 6 trips a day are needed to transport 10000 such crates in a day
Answer:
20 lorries are needed to transport.
Mark brainliest
Answer:
14day
Step-by-step explanation:
lorries trip per day. crates
3. 5 2500
? 6 10000
(6×3×10000)÷(5×2500)=14days
X – 3 = 7 so X = thank
Answer:
x=10
Step-by-step explanation:
x-3(+3)=7+3
We need to add 3 to both sides to isolate x.
x=10
Answer:
x = 10Step-by-step explanation:
x - 3 = 7
x = 7 + 3
x = 10
What is the slope of a line that is perpendicular to the line whose equation is ax by=c?
Answer:
b/a
Step-by-step explanation:
Perpendicular lines have slopes that are opposite sign and reciprocals (flipped over).
In the equation
ax + by = c,
the slope of the line is
-a/b
If you haven't memorized this pattern yet, you can calculate it by solving ax+by=c for y.
by = -ax +c
y = -a/b x + c/b
The slope is -a/b
So a perpendicular line would be opposite sign and flipped, b/a
A train to new york city leaves every 7 minutes. another train to boston leaves the station every 6 minutes. suppose it is 6:30 am right now. at what time will both trains leave the station together again if both of them left the station together at 6:30 am?
Both trains will leave the station together again at 7:12 am if both of them left the station together at 6:30 am.
What is LCM?The lowest integer that is a multiple of two or more numbers is known as the LCM. For instance, the LCM of 4 and 6 is 12, and the LCM of 10 and 15 is 30. There are numerous ways for determining the least common multiples, just as there are for computing the greatest common divisors. One approach is to divide both numbers by their primes.To find at what time will both trains leave the station together again if both of them left the station together at 6:30 am:
If a train to New York City departs every 7 minutes and another to Boston departs every 6 minutes,The two trains then depart together after a time equal to the LCM of their individual intervalsLCM (7,6) = 42As a result, if they begin at the same time, they will depart at the same time every 42 minutes.If both trains left the station at 6.30 a.m., they will leave together again 42 minutes later, at 7.12 am.
Therefore, both trains will leave the station together again at 7:12 am if both of them left the station together at 6:30 am.
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Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding 48.
The probability of selecting none of the correct six integers, when the order in which they are selected doesnot matter is 0.43.
According to thr question.
We have to find the probability of selecting none of the correct six integers from the positive integers not exceeding 48.
Let E be the event of selecting 6 numbers from 40 and S be the sample space of all integers not exceeding 48.
Now,
The total number of ways of selecting 6 numbers from 48
[tex]= ^{48} C_{6}[/tex]
[tex]= \frac{48!}{6!\times 42!}[/tex]
[tex]= \frac{48\times 47\times46\times45\times44\times43\times42!}{6!\times\ 42!}[/tex]
= 8835488640/6!
And, the total number of ways of selecting 6 incorrect numbers from 42
= [tex]^{42} C_{6}[/tex]
[tex]= \frac{42\times41\times40\times39\times38\times37\times36!}{6!\times36!}[/tex]
= 3776965920/6!
Therefore, the probability of selecting none of the correct six integers, when the order in which they are selected does not matter is given by
[tex]= \frac{^{42C_{6} } }{^{48} C_{6} }[/tex]
[tex]= \frac{\frac{3776965920}{6!} }{\frac{8835488640}{6!} }[/tex]
= 3776965920/8835488640
= 0.427
≈ 0.43
Hence, the probability of selecting none of the correct six integers, when the order in which they are selected doesnot matter is 0.43.
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7. Which of these statements is true?
A. 1-(-4)<4- (-2)
B. (-2)(3) > (-1)(-6)
C. 6÷
D.-(5-3)=-5-3
Answer:
A. because 5 < 6. 1-(-4)=5. and 4-(-2) =6
Ramiro was on a two day road trip.on the first day he drove at an average speed of 40 mph.on the second day he drove at an average of 60 mph.if he drove 2 hours longer and went 20 miles farther on his first day find the total distance ramiro traveled on his road trip.
Considering the relationship between velocity, distance and time, it is found that the total distance traveled was of 380 miles.
What is the relationship between velocity, distance and time?Velocity is distance divided by time, that is:
v = d/t.
For the first day, we have that:
v = 40, t = t + 2, d = d + 20, hence:
40 = (d + 20)/(t + 2)
For the second day, we have that:
v = 60
60 = d/t
d = 60t
Then, replacing in the first equation:
40 = (60t + 20)(t + 2)
60t + 20 = 40t + 80
20t = 60
t = 3.
Then the distances are given by:
First day: d = 60t + 20 = 60 x 3 + 20 = 200 miles.Second day: d = 60t = 60 x 3 = 180 miles.Total: 200 miles + 180 miles = 380 miles.More can be learned about the relationship between velocity, distance and time at https://brainly.com/question/28143163
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Let f (x) = x4 – 2x3 – 3x2 + 4x + 4, g of x is equal to the square root of the quantity x squared minus x minus 2 end quantity and h of x is equal to the quantity negative x squared plus 1 end quantity over the quantity x squared minus x minus 2 end quantity Part A: Use complete sentences to compare the domain and range of the polynomial function f (x) to that of the radical function g(x). (5 points) Part B: How do the breaks in the domain of h (x) relate to the zeros of f (x)? (5 points)
The domain of f(x) is all set of real values while, the domain of g(x) is x ≤ -1 or x ≥ 2 and both functions have the same range
Part A: Compare the domain and range of the function f(x) to g(x)The functions are given as:
f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4
g(x) = √(x^2 - x - 2)
Domain
The polynomial function f(x) has no restriction on its input.
So, the domain of f(x) is all set of real values
Set the radical of g(x) = √(x^2 - x - 2) greater than 0
x^2 - x - 2 ≥ 0
Factorize
(x + 1)(x - 2) ≥ 0
Solve for x
x ≥ -1 and x ≥ 2
Combine both inequalities
x ≤ -1 and x ≥ 2
So, the domain of g(x) is x ≤ -1 or x ≥ 2
Range
Using a graphical calculator, we have:
Range of f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4 ⇒ f(x) ≥ 0Range of g(x) = √(x^2 - x - 2) ⇒ g(x) ≥ 0Hence, both functions have the same range
How do the breaks in the domain of h(x) relate to the zeros of f(x)?We have:
h(x) = (-x^2 + x)/(x^2 - x - 2)
Set the denominator to 0
x^2 - x - 2 = 0
The above represents the radical of the function f(x)
This means that the breaks in the domain of h(x) and the zeros of f(x) are the same
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Complete question
Let f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4, g(x) = √(x^2 - x - 2) and h(x) = (-x^2 + x)/(x^2 - x - 2)
Part A: Use complete sentences to compare the domain and range of the polynomial function f (x) to that of the radical function g(x). (5 points)
Part B: How do the breaks in the domain of h (x) relate to the zeros of f (x)? (5 points)
(e) ABCD is an isosceles trapezium. Prove that: (1) AC=BD (2) BE=CE (3) AE=DE
Answer:
look at attached image for the step-by-step proof. thanks for reposting this lol
Enter the correct answer in the box. write the expression (x4)8 in simplest form.
The simplest form of the given expression ( x⁴ )⁸ exists x³².
What is an expression?Expression in Math exists described as the collection of numbers variables and functions by utilizing characters like addition, subtraction, multiplication, and division.
The given expression will be simplified as:-
( x⁴ )⁸ = x ⁴ ⁽⁸⁾
( x⁴ )⁸ = x ³²
Therefore the simplest form of the given expression exists as x³².
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What are the y-intercept and the asymptote of g(x) = 3x – 5? (0, –5); y = 3 (0, –2); y = 5 (0, –4); y = –5 (0, 5); y = –3
The y-intercept of the equation g(x) = 3^x - 5 is (0, -4) and the asymptote of the equation g(x) = 3^x - 5 is y = -5
How to determine the y-intercept?The equation of the function g(x) is given as:
g(x) = 3^x - 5
The y-intercept is a point on the graph where the value of x is 0
This is represented by x= 0 or (0, y)
This means that we substitute 0 for x in the above equation
So, we have:
g(0) = 3^0 - 5
Evaluate the exponent 3^0
g(0) = 1 - 5
Evaluate the difference of 1 and 5
g(0) = -4
Rewrite this point as
(0, -4)
This means that the y-intercept of the equation g(x) = 3^x - 5 is (0, -4)
How to determine the asymptote?The equation of the function g(x) is given as:
g(x) = 3^x - 5
The asymptote is a point on the graph where that is parallel to the graph
In the above equation, we have:
g(x) = 3^x - 5
Express the radical as 0
y = 0 - 5
Evaluate the difference of 0 and 5
y = -5
This means that the asymptote of the equation g(x) = 3^x - 5 is y = -5
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Allen wants to buy colored pencils that cost $3.50. He has 2 dollars, 5 quarters, 2 dimes, and 7 pennies. Does he have enough money to buy the colored pencils
Answer:
Yes
Step-by-step explanation:
First we need to determine how much money Allen has
2 dollars = 2.00
5 quarters = 5 * .25 = 1.25
2 dimes = 2 * .10 = .20
7 pennies = 7 * .01 = .07
Add this together
2.00 + 1.25+.20+.07 =3.52
3.52 > 3.50
This is more than 3.50 so he has enough money to buy the pencils
Mrs. Bailey has equal numbers of nickels and quarters but the value of the quarters is $1.80 more than the value of the nickels. What is the total value of all coins together in dollars and cents
Total value of all coins together is $2.7
Linear equations are equations having variables with power 1. ax+b = 0 is an example with one variable where x is the variable, a and b are real numbers.
1 Nickel = $0.05 and 1 quarter = $0.25.
Let number of nickels and number of quarter be x.
According to the situation
x.(0.25) = $1.80 + x.($0.05)
x(0.25 - 0.05) = $1.80
x (0.2) = $1.80
x = $1.80/0.2
x = 9 coins
Therefore total value of the currency is 9(0.05 + $0.25) = 9 (0.3) = $2.7
Thus total value of all coins together is $2.7.
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Which of the following equations have complex roots?
A. 3x^2-1=6x
B. 3x^2+2=0
C. 2x^2-1=5x
D. 2x^x+1=7x
Answer: B
Step-by-step explanation:
We can rearrange the equation to get [tex]x^2=-\frac{2}{3}[/tex], which clearly has complex roots.